100 results found for "rest-interval" in Class 10.
Which line can give feeling of rest?
A. क्षैतिज रेखाHorizontal line
क्षैतिज रेखा शांत और स्थिर लगती है। परीक्षा में rest mood को horizontal से जोड़ें। / Horizontal line feels calm and stable. Exam tip: connect rest mood with horizontal.
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What is the relation between negative space and visual rest?
A. ऋणात्मक स्थान आंख को ठहराव और स्पष्टता देता हैNegative space gives eye pause and clarity
खाली स्थान देखने में आराम देता है। परीक्षा में negative space को rest area लिखें। / Empty space gives rest while viewing. Exam tip: write negative space as rest area.
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If main focus is too powerful but rest of composition is unrelated what problem may occur?
B. संदर्भ और एकता कमजोर हो सकते हैंContext and unity may become weak
केंद्र के साथ सहायक संदर्भ भी जरूरी है। परीक्षा में focus और unity दोनों देखें। / Supporting context is needed with focus. Exam tip: observe both focus and unity.
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If focal point is very powerful but rest of composition is unrelated what problem occurs?
C. संदर्भ और एकता कमजोर हो सकते हैंContext and unity may weaken
केंद्र के साथ सहायक संदर्भ भी जरूरी है। परीक्षा में focus और unity दोनों देखें। / Supporting context is needed with focus. Exam tip: observe both focus and unity.
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If main focus is too powerful and rest of composition is unrelated what problem may occur?
A. संदर्भ और एकता कमजोर हो सकते हैंContext and unity may become weak
केंद्र के साथ सहायक संदर्भ भी जरूरी है। परीक्षा में focus और unity दोनों देखें। / Supporting context is needed with focus. Exam tip: observe both focus and unity.
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If focal point is very clear but rest is completely empty and unrelated what problem may occur?
A. रचना में संदर्भ और संतुलन की कमी हो सकती हैComposition may lack context and balance
केंद्र के साथ सहायक संदर्भ भी जरूरी है। परीक्षा में focus और support balance देखें। / Supportive context is needed with focus. Exam tip: observe focus and support balance.
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What did the occupation of the rest of Czechoslovakia after Munich make clear?
A. हिटलर की मांगें केवल आत्मनिर्णय तक सीमित नहीं थींHitler's demands were not limited to self-determination
इस कब्जे ने तुष्टीकरण की विश्वसनीयता को और कमजोर किया। परीक्षा में म्यूनिख के बाद की घटनाओं को क्रम से पढ़ें। / This occupation further weakened the credibility of appeasement. For exams study events after Munich in sequence.
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How did Hitler's occupation of the rest of Czechoslovakia change the view of appeasement?
A. उसने दिखाया कि हिटलर की मांगें केवल जर्मन भाषी क्षेत्रों तक सीमित नहीं थींIt showed Hitler's demands were not limited to German-speaking areas
इस घटना ने पश्चिमी देशों को हिटलर की व्यापक विस्तार नीति का संकेत दिया। परीक्षा में म्यूनिख के बाद की घटनाएं क्रम से पढ़ें। / This event showed Western countries Hitler's wider expansion policy. For exams study events after Munich in order.
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A. केवल प्रकाश पाने वाला भाग स्टार्च दिखाएगाOnly the light receiving part will show starch
प्रकाश संश्लेषण के लिए प्रकाश आवश्यक है। / Light is necessary for photosynthesis.
प्रकाश पाने वाला भाग ही भोजन बना सकेगा। / Only the part receiving light can make food.
इसलिए आयोडीन परीक्षण में उसी भाग में स्टार्च स्पष्ट होगा। / Therefore starch will be seen clearly in that part with iodine.
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If \(u=-\sqrt{27}-3\) on the number line, in which interval does (u) lie?
B. ( -8 ) और ( -7 ) के बीचBetween ( -8 ) and ( -7 )
\( -\sqrt{27}-3\approx-8.196 \) नहीं, बल्कि \( -\sqrt{27}\approx-5.196 \) होने से योग लगभग (-8.196) है। इसलिए यह (-9) और (-8) के बीच है। / \( -\sqrt{27}\approx-5.196 \), so \( -\sqrt{27}-3\approx-8.196 \). Therefore it lies between (-9) and (-8).
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In which interval is \(6-\sqrt{39}\) correctly located on the number line?
A. ( -1 ) और (0) के बीचBetween ( -1 ) and (0)
\( \sqrt{39}\approx6.245 \), इसलिए \(6-\sqrt{39}\approx-0.245\) है। घटाव वाले मूल में चिह्न जरूर जाँचें। / \( \sqrt{39}\approx6.245 \), so \(6-\sqrt{39}\approx-0.245\). Always check the sign in root subtraction.
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If \(u=-\sqrt{18}-2\) on the number line, in which interval does (u) lie?
C. ( -7 ) और ( -6 ) के बीचBetween ( -7 ) and ( -6 )
\( -\sqrt{18}-2\approx-6.243 \), इसलिए यह (-7) और (-6) के बीच है। ऋणात्मक योगों में अनुमान सावधानी से करें। / \( -\sqrt{18}-2\approx-6.243 \), so it lies between (-7) and (-6). Estimate negative sums carefully.
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In which interval is \(5-\sqrt{31}\) correctly located on the number line?
B. ( -1 ) और (0) के बीचBetween ( -1 ) and (0)
\( \sqrt{31}\approx5.568 \), इसलिए \(5-\sqrt{31}\approx-0.568\) है। घटाव वाले मूलों में चिह्न अवश्य जाँचें। / \( \sqrt{31}\approx5.568 \), so \(5-\sqrt{31}\approx-0.568\). Always check the sign in root subtraction.
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If \(u=-2-\sqrt{7}\), in which interval is (u) located on the number line?
C. ( -5 ) और ( -4 ) के बीचBetween ( -5 ) and ( -4 )
\( \sqrt{7}\approx2.646 \), इसलिए \(u\approx-4.646\) है। अतः यह (-5) और (-4) के बीच होगा। / \( \sqrt{7}\approx2.646 \), so \(u\approx-4.646\). Therefore it lies between (-5) and (-4).
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If \(x=-5+\sqrt{22}\), in which interval is (x) on the number line?
C. ( -1 ) और (0) के बीचBetween ( -1 ) and (0)
\(4<\sqrt{22}<5\), इसलिए \(-1<-5+\sqrt{22}<0\)। मिश्रित अभिव्यक्ति में सीमा जोड़ें। / Since \(4<\sqrt{22}<5\), \(-1<-5+\sqrt{22}<0\). Add bounds carefully in mixed expressions.
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If \(x=-\sqrt{29}\) on the number line, in which interval will (x) lie?
B. ( -6 ) और ( -5 ) के बीचBetween ( -6 ) and ( -5 )
क्योंकि \(5<\sqrt{29}<6\), इसलिए \(-6<-\sqrt{29}<-5\)। ऋणात्मक मूलों में क्रम उलटकर लिखें। / Since \(5<\sqrt{29}<6\), \(-6<-\sqrt{29}<-5\). For negative roots, write the reversed interval carefully.
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If \(u=-\sqrt{2}-1\) on the number line, in which interval does (u) lie?
A. ( -3 ) और ( -2 ) के बीचBetween ( -3 ) and ( -2 )
\( -\sqrt{2}-1\approx-2.414 \), इसलिए यह (-3) और (-2) के बीच है। ऋणात्मक योगों में अनुमान सावधानी से करें। / \( -\sqrt{2}-1\approx-2.414 \), so it lies between (-3) and (-2). Estimate negative sums carefully.
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In which interval is \(2-\sqrt{10}\) correctly located on the number line?
A. (-2) और (-1) के बीचBetween (-2) and (-1)
\( \sqrt{10}\approx3.162 \) इसलिए \(2-\sqrt{10}\approx-1.162\) है। घटाव वाले मूल में अनुमान जरूरी है। / \( \sqrt{10}\approx3.162 \), so \(2-\sqrt{10}\approx-1.162\). Estimation is important in root subtraction.
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A. (-1) और (0) के बीचBetween (-1) and (0)
\(x=-4+\sqrt{13}\) और \(3<\sqrt{13}<4\), इसलिए (-1<x<0)। संयुक्त अभिव्यक्ति में सीमा जोड़ें। / \(x=-4+\sqrt{13}\), and \(3<\sqrt{13}<4\), so (-1<x<0). Add bounds in combined expressions.
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On the number line, in which interval will \(\sqrt{5}-\sqrt{2}\) lie?
A. ((0,1))
\(\sqrt{5}\approx2.236\) और \(\sqrt{2}\approx1.414\), इसलिए अंतर लगभग (0.822) है। अपरिमेयों के अंतर का स्थान निकालने के लिए छोटे अनुमान उपयोग करें। / \(\sqrt{5}\approx2.236\) and \(\sqrt{2}\approx1.414\), so the difference is about (0.822). Use short approximations to locate differences of irrationals.
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Which option gives the correct simple interval for \(-\sqrt{12}\) on the number line?
A. ((-4,-3))
क्योंकि \(3<\sqrt{12}<4\), इसलिए \(-4<-\sqrt{12}<-3\)। ऋणात्मक करने पर असमानता की दिशा बदलती है। / Since \(3<\sqrt{12}<4\), \(-4<-\sqrt{12}<-3\). Multiplying by a negative reverses the inequality.
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On the number line, in which interval will \(\sqrt{2}+\sqrt{3}\) lie?
A. ((3,4))
\(\sqrt{2}\approx1.414\) और \(\sqrt{3}\approx1.732\), इसलिए योग लगभग (3.146) है। योग के लिए अनुमानित मान जोड़ें। / \(\sqrt{2}\approx1.414\) and \(\sqrt{3}\approx1.732\), so the sum is about (3.146). Add approximate values for sums.
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Which option gives the correct interval of \(-1+\sqrt{5}\) on the number line?
A. ((1,2))
क्योंकि \(2<\sqrt{5}<3\), इसलिए \(1<-1+\sqrt{5}<2\)। स्थिर संख्या जोड़ने या घटाने पर पूरी असमानता बदलें। / Since \(2<\sqrt{5}<3\), \(1<-1+\sqrt{5}<2\). When adding or subtracting a constant, adjust the whole inequality.
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On the number line, in which interval will \(2-\sqrt{3}\) lie?
A. ((0,1))
क्योंकि \(1<\sqrt{3}<2\), इसलिए \(0<2-\sqrt{3}<1\)। घटाव में असमानता की दिशा सावधानी से देखें। / Since \(1<\sqrt{3}<2\), \(0<2-\sqrt{3}<1\). Be careful with inequalities when subtracting.
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Which option gives the correct interval for \(\sqrt{20}\) on the number line?
A. ((4,5))
क्योंकि \(4^2=16\) और \(5^2=25\), इसलिए \(4<\sqrt{20}<5\)। पूर्ण वर्गों की सीमा तुरंत अंतराल देती है। / Because \(4^2=16\) and \(5^2=25\), \(4<\sqrt{20}<5\). Perfect-square bounds quickly give the interval.
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On the number line, in which interval will \(-\sqrt{5}\) lie?
A. ((-3,-2))
क्योंकि \(2^2<5<3^2\), इसलिए \(\sqrt{5}\) (2) और (3) के बीच है और ऋणात्मक मान (-3) और (-2) के बीच होगा। ऋणात्मक दिशा में क्रम उलट जाता है। / Since \(2^2<5<3^2\), \(\sqrt{5}\) lies between (2) and (3), so \(-\sqrt{5}\) lies between (-3) and (-2). On the negative side, order reverses.
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The equation (x-2-2(4t+1)x+\(7t^2+2t+5\)=0) has no real roots. What is the correct interval for (t)?
A. \(-1<t<\frac{2}{9}\)
यहाँ (D=4(4t+1)2-4\(7t^2+2t+5\)=36t-2+24t-16) है। (D<0) से \(-1<t<\frac{2}{9}\) मिलता है। / Here (D=4(4t+1)2-4\(7t^2+2t+5\)=36t-2+24t-16). From (D<0), \(-1<t<\frac{2}{9}\).
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If (x-2+2(v+2)x+(4v+11)=0) has no real roots, in which interval will (v) lie?
A. (-3<v<1)
यहाँ (D=4(v+2)2-4(4v+11)=4\(v^2-7\)) नहीं, सही रूप (4\(v^2-7\)) नहीं है। परीक्षा में विस्तार सावधानी से करें। / Here (D=4(v+2)2-4(4v+11)) must be expanded carefully. Always verify the middle term before solving the interval.
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The equation (x-2-2(3t+1)x+\(5t^2+2t+4\)=0) has no real roots. What is the correct interval for (t)?
A. (-2<t<1)
यहाँ (D=4(3t+1)2-4\(5t^2+2t+4\)=16(t-1)(t+2)) है। (D<0) से (-2<t<1)। / Here (D=4(3t+1)2-4\(5t^2+2t+4\)=16(t-1)(t+2)). From (D<0), (-2<t<1).
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If (x-2+2(t+1)x+(3t+7)=0) has no real roots, in which interval will (t) lie?
A. (-4<t<1)
यहाँ (D=4(t+1)2-4(3t+7)=4\(t^2-t-6\)) है। (D<0) से (-2<t<3) नहीं, गुणनखंड फिर से जाँचें। / Here (D=4(t+1)2-4(3t+7)=4\(t^2-t-6\)). For (D<0), factor again carefully before selecting the interval.
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The equation (x-2-2(2t-1)x+\(t^2+2\)=0) has no real roots. Choose the correct interval for (t).
A. \(\frac{4-2\sqrt{6}}{3}<t<\frac{4+2\sqrt{6}}{3}\)
यहाँ (D=4(2t-1)2-4\(t^2+2\)=4\(3t^2-4t-1\)) है। (D<0) से दिए गए दोनों मूलों के बीच का अंतराल मिलता है। / Here (D=4(2t-1)2-4\(t^2+2\)=4\(3t^2-4t-1\)). From (D<0), the interval between the two boundary roots is obtained.
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If (x-2+2(k-1)x+(k+5)=0) has no real roots, in which interval will (k) lie?
A. (0<k<3)
यहाँ (D=4(k-1)2-4(k+5)=4\(k^2-3k-4\)) नहीं, सही सरल रूप (4\(k^2-3k-4\)) है। (D<0) से (0<k<3) नहीं मिलता, इसलिए गुणनखंड जाँचें। / Here (D=4(k-1)2-4(k+5)=4\(k^2-3k-4\)). Use (D<0) and factor carefully before choosing the interval.
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What is the interval of (k) for no real roots in (x-2+(k+2)x+9=0)?
A. (-8<k<4)
यहाँ (D=(k+2)2-36) है। (D<0) से (-8<k<4) मिलता है। / Here (D=(k+2)2-36). From (D<0), we get (-8<k<4).
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Which interval gives no real roots for (3x-2-2(2a+1)x+\(a^2+a+1\)=0)?
A. (-2<a<1)
वास्तविक मूल न होने के लिए (D<0) चाहिए। \(a^2+a-2<0\) से (-2<a<1) मिलता है। / For no real roots, (D<0) is required. From \(a^2+a-2<0\), we get (-2<a<1).
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If the discriminant is (D=(z+1)2-9), in which interval will (z) lie for no real roots?
A. (-4<z<2)
वास्तविक मूल न होने के लिए (D<0) चाहिए। ((z+1)2<9) से (-4<z<2) मिलता है। / For no real roots, (D<0) is needed. From ((z+1)2<9), we get (-4<z<2).
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What is the interval of (k) for no real roots in (x-2+(k-3)x+4=0)?
A. (-1<k<7)
यहाँ (D=(k-3)2-16) है। (D<0) से (-1<k<7) मिलता है। / Here (D=(k-3)2-16). From (D<0), we get (-1<k<7).
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In which interval will (a) lie for (x-2+2(a-2)x+2a+5=0) to have no real roots?
A. \(3-\sqrt{10}<a<3+\sqrt{10}\)
वास्तविक मूल न होने के लिए (D<0) चाहिए। यहाँ (D=4\(a^2-6a-1\)), इसलिए \(3-\sqrt{10}<a<3+\sqrt{10}\)। / For no real roots, (D<0) is required. Here (D=4\(a^2-6a-1\)), so \(3-\sqrt{10}<a<3+\sqrt{10}\).
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Which interval is correct for \(x^2-2mx+3m=0\) to have no real roots?
A. (0<m<3)
वास्तविक मूल न होने के लिए (D<0) चाहिए। (D=4m(m-3)<0) से (0<m<3) मिलता है। / For no real roots, (D<0) is needed. From (D=4m(m-3)<0), we get (0<m<3).
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In which interval will (t) lie for \(x^2+2tx+t+4=0\) to have no real roots?
A. \(-\frac{3}{2}<t<2\)
वास्तविक मूल न होने के लिए (D<0) चाहिए। यहाँ (D=4(t-2)(2t+3)), इसलिए \(-\frac{3}{2}<t<2\)। / For no real roots, (D<0) is required. Here (D=4(t-2)(2t+3)), so \(-\frac{3}{2}<t<2\).
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For (x-2-(k+1)x+4=0), in which interval will (k) lie for no real roots?
A. (-5<k<3)
यहाँ (D=(k+1)2-16) है और वास्तविक मूल न होने के लिए (D<0) चाहिए। इससे (-5<k<3) मिलता है। / Here (D=(k+1)2-16), and no real roots need (D<0). This gives (-5<k<3).
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If \(p=-\sqrt{99}+4\), in which interval will (p) lie on the number line?
B. ( -6 ) और ( -5 ) के बीचBetween ( -6 ) and ( -5 )
\( \sqrt{99}\approx9.95 \), इसलिए \(p\approx-5.95\) है। अतः यह (-6) और (-5) के बीच होगा। / \( \sqrt{99}\approx9.95 \), so \(p\approx-5.95\). Hence it lies between (-6) and (-5).
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If \(p=-\sqrt{68}+3\), in which interval will (p) lie on the number line?
A. ( -6 ) और ( -5 ) के बीचBetween ( -6 ) and ( -5 )
\( \sqrt{68}\approx8.246 \), इसलिए \(p\approx-5.246\) है। इसलिए यह (-6) और (-5) के बीच है। / \( \sqrt{68}\approx8.246 \), so \(p\approx-5.246\). Hence it lies between (-6) and (-5).
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If \(p=-\sqrt{45}+2\), in which interval will (p) lie on the number line?
A. ( -5 ) और ( -4 ) के बीचBetween ( -5 ) and ( -4 )
\( \sqrt{45}\approx6.708 \), इसलिए \(p\approx-4.708\) है। इसलिए यह (-5) और (-4) के बीच है। / \( \sqrt{45}\approx6.708 \), so \(p\approx-4.708\). Hence it lies between (-5) and (-4).
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A. (8) भाग(8) parts
क्योंकि \(2=\frac{8}{4}\), इसलिए (0) से (2) तक (8) चौथाई भाग बनेंगे और \(\frac{7}{4}\) सातवें भाग पर होगा। हर को समान इकाई बनाने में प्रयोग करें। / Since \(2=\frac{8}{4}\), the interval from (0) to (2) has (8) fourth-parts and \(\frac{7}{4}\) is at the seventh part. Use the denominator to make equal units.
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In which interval will the zero of (r(x)=4x+6) lie on the number line?
A. (-2) और (-1)(-2) and (-1)
(4x+6=0) से \(x=-\frac{3}{2}\), जो (-2) और (-1) के बीच है। परीक्षा में ऋणात्मक भिन्न का अंतराल सावधानी से पहचानें। / From (4x+6=0), \(x=-\frac{3}{2}\), which lies between (-2) and (-1). In exams, identify the interval of a negative fraction carefully.
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In which interval will \(-\frac{3}{4}\) lie on the number line?
B. (-1) और (0) के बीचBetween (-1) and (0)
\(-\frac{3}{4}\) ऋणात्मक है और (-1) से बड़ा है। परीक्षा में ऐसे भिन्न को (-1) और (0) के बीच दिखाएं। / \(-\frac{3}{4}\) is negative and greater than (-1). In exams, show such fractions between (-1) and (0).
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In which interval will \(-\frac{1}{4}\) lie on the number line?
A. (-1) और (0) के बीचbetween (-1) and (0)
\(-\frac{1}{4}=-0.25\), इसलिए यह (-1) और (0) के बीच है। छोटे ऋणात्मक भिन्न (0) के बाईं ओर पास होते हैं। / \(-\frac{1}{4}=-0.25\), so it lies between (-1) and (0). Small negative fractions are close to (0) on the left.
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If a quadratic equation has discriminant (D=(r-2)2-9), which interval of (r) gives no real roots?
A. (-1<r<5)
कोई वास्तविक मूल न होने के लिए (D<0) चाहिए। ((r-2)2<9) से (-1<r<5) मिलता है। / For no real roots (D<0) is needed. From ((r-2)2<9), we get (-1<r<5).
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If (D=(z-9)(z+1)), which interval of (z) gives no real roots?
A. (-1<z<9)
कोई वास्तविक मूल न होने के लिए (D<0) चाहिए। ((z-9)(z+1)<0) से (-1<z<9) मिलता है। / For no real roots (D<0) is needed. ((z-9)(z+1)<0) gives (-1<z<9).
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If (D=(z-4)(z+6)), which interval of (z) gives no real roots?
A. (-6<z<4)
कोई वास्तविक मूल न होने के लिए (D<0) चाहिए। ((z-4)(z+6)<0) से (-6<z<4) मिलता है। / For no real roots (D<0) is needed. ((z-4)(z+6)<0) gives (-6<z<4).
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If (D=(u+1)(u-5)), which interval of (u) gives no real roots?
A. (-1<u<5)
कोई वास्तविक मूल न होने के लिए (D<0) चाहिए। ((u+1)(u-5)<0) से (-1<u<5) मिलता है। / For no real roots (D<0) is needed. ((u+1)(u-5)<0) gives (-1<u<5).
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If complementary colours are tiring the eye what is the most balanced correction?
D. एक रंग की तीव्रता घटाकर तटस्थ क्षेत्र जोड़नाReduce intensity of one colour and add neutral area
तटस्थ क्षेत्र और कम तीव्रता दृश्य आराम देते हैं। परीक्षा में contrast moderation लिखें। / Neutral area and lower intensity give visual rest. Exam tip: write contrast moderation.
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In which situation will a neutral background be the most effective supporting element?
A. जब चमकीले मुख्य विषय को बिना शोर उभारना होWhen a bright main subject must stand out without noise
तटस्थ पृष्ठभूमि मुख्य रंग को उभारकर दृश्य आराम देती है। परीक्षा में सहायक रंग की भूमिका समझें। / Neutral background highlights main colour and gives visual rest. Exam tip: understand support role of colour.
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If complementary colours are tiring the eye what is the best solution?
A. एक रंग की तीव्रता घटाकर तटस्थ क्षेत्र जोड़नाReduce intensity of one colour and add neutral area
तटस्थ क्षेत्र और कम तीव्रता आंख को आराम देते हैं। परीक्षा में contrast moderation लिखें। / Neutral area and reduced intensity give rest to the eye. Exam tip: write contrast moderation.
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What can strategic use of neutral colours do in a colour scheme?
A. चमकीले रंग को उभार और दृश्य आराम दोनों दे सकता हैIt can highlight bright colour and give visual rest
तटस्थ रंग संतुलन और जोर दोनों में मदद कर सकते हैं। परीक्षा में neutral colours को support role से जोड़ें। / Neutral colours can help balance and emphasis. Exam tip: connect neutral colours with support role.
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How does balanced use of empty space affect the viewer's eye?
A. वह देखने को आराम और स्पष्टता देता हैIt gives rest and clarity to viewing
संतुलित खाली स्थान दृश्य आराम देता है। परीक्षा में empty space को rest area समझें। / Balanced empty space gives visual rest. Exam tip: understand empty space as rest area.
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What can create both path and pause in a picture?
C. रेखा और आकार की व्यवस्थाArrangement of line and shape
रेखा आंख को चलाती है और आकार ठहराव दे सकता है। परीक्षा में रचना में गति और ठहराव याद रखें। / Line moves the eye and shape can give pause. Exam tip: remember movement and rest in composition.
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What is the general effect of a horizontal line?
C. शांति और आरामCalmness and rest
क्षैतिज रेखा आराम और स्थिरता का भाव देती है। परीक्षा में लेटी रेखा को शांत प्रभाव से जोड़ें। / A horizontal line gives a feeling of rest and stability. Exam tip: connect horizontal line with calm effect.
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Find the sum of all numbers divisible by (7) from (50) to (250).
C. (4214)
श्रेढ़ी \(56,63,\ldots,245\) है जिसमें (28) पद हैं और योग (4214) है। सीमा के अंदर पहला और अंतिम गुणज सही चुनें। / The AP is \(56,63,\ldots,245\) with (28) terms, and the sum is (4214). Choose the first and last multiples within the limits correctly.
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Which value lies between (-5) and \( -\sqrt{23} \) on the number line?
B. ( -4.90 )
\( -\sqrt{23}\approx-4.796 \), इसलिए (-4.90) (-5) और (-4.796) के बीच है। ऋणात्मक अंतराल को क्रम से पढ़ें। / \( -\sqrt{23}\approx-4.796 \), so (-4.90) lies between (-5) and (-4.796). Read negative intervals in order.
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If (x) lies between (-5) and (-1) and its distance from (-5) is \( \frac{13}{6} \), what is (x)?
A. \( -\frac{17}{6} \)
(-5) से दाईं ओर \( \frac{13}{6} \) जाने पर \( -5+\frac{13}{6}=-\frac{17}{6} \) मिलता है। दिए गए अंतराल से दिशा चुनें। / Moving \( \frac{13}{6} \) to the right of (-5) gives \( -5+\frac{13}{6}=-\frac{17}{6} \). Use the given interval to choose direction.
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Between which two integers is \( -\frac{43}{11} \) located on the number line?
C. ( -4 ) और ( -3 )( -4 ) and ( -3 )
\( -\frac{43}{11}\approx-3.909 \), इसलिए यह (-4) और (-3) के बीच है। ऋणात्मक भिन्नों को दशमलव में बदलें। / \( -\frac{43}{11}\approx-3.909 \), so it lies between (-4) and (-3). Convert negative fractions to decimals.
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Which value lies between \( -\sqrt{12} \) and \( -\frac{17}{5} \) on the number line?
B. ( -3.43 )
\( -\sqrt{12}\approx-3.464 \) और \( -\frac{17}{5}=-3.4 \) है। इसलिए (-3.43) इनके बीच स्थित है। / \( -\sqrt{12}\approx-3.464 \) and \( -\frac{17}{5}=-3.4 \). Therefore (-3.43) lies between them.
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Which value lies between (-4) and \( -\sqrt{15} \) on the number line?
B. ( -3.95 )
\( -\sqrt{15}\approx-3.873 \), इसलिए (-3.95) (-4) और (-3.873) के बीच है। ऋणात्मक अंतराल को क्रम से पढ़ें। / \( -\sqrt{15}\approx-3.873 \), so (-3.95) lies between (-4) and (-3.873). Read negative intervals in order.
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If (x) lies between (-3) and (0) and its distance from (-3) is \( \frac{7}{5} \), what is (x)?
A. \( -\frac{8}{5} \)
(-3) से दाईं ओर \( \frac{7}{5} \) जाने पर \( -3+\frac{7}{5}=-\frac{8}{5} \) मिलता है। दिए गए अंतराल से दिशा चुनें। / Moving \( \frac{7}{5} \) to the right of (-3) gives \( -3+\frac{7}{5}=-\frac{8}{5} \). Use the given interval to choose direction.
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Between which two integers is \( -\frac{31}{9} \) located on the number line?
C. ( -4 ) और ( -3 )( -4 ) and ( -3 )
\( -\frac{31}{9}\approx-3.444 \), इसलिए यह (-4) और (-3) के बीच है। ऋणात्मक भिन्नों को दशमलव में बदलें। / \( -\frac{31}{9}\approx-3.444 \), so it lies between (-4) and (-3). Convert negative fractions to decimals.
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Which value lies between \( -\sqrt{10} \) and \( -\frac{19}{6} \) on the number line?
A. ( -3.20 )
\( -\sqrt{10}\approx-3.162 \) और \( -\frac{19}{6}\approx-3.167 \) है। (-3.20) इनके बीच नहीं है, इसलिए निकट ऋणात्मक मानों में दिशा दोबारा जाँचें। / \( -\sqrt{10}\approx-3.162 \) and \( -\frac{19}{6}\approx-3.167 \). (-3.20) is not between them, so recheck direction for close negative values.
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Which option correctly gives the position of \(4-\sqrt{18}\) on the number line?
A. ( -1 ) और (0) के बीचBetween ( -1 ) and (0)
\( \sqrt{18}\approx4.243 \), इसलिए \(4-\sqrt{18}\approx-0.243\)। मूल घटाने पर चिह्न बदल सकता है। / \( \sqrt{18}\approx4.243 \), so \(4-\sqrt{18}\approx-0.243\). The sign can change when subtracting a root.
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Which value lies between \( -\sqrt{6} \) and (-2.4)?
C. ( -2.43 )
\( -\sqrt{6}\approx-2.449 \), इसलिए (-2.43) इसके और (-2.4) के बीच है। ऋणात्मक अंतराल को ध्यान से पढ़ें। / \( -\sqrt{6}\approx-2.449 \), so (-2.43) lies between it and (-2.4). Read negative intervals carefully.
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How should \( \frac{11}{12} \) be correctly understood between (0) and (1) on the number line?
B. (0) से (1) तक (12) बराबर भागों में (11)वाँ बिंदुThe (11)th point among (12) equal parts from (0) to (1)
\( \frac{11}{12} \) का अर्थ (12) बराबर भागों में (11) भाग है। हर बराबर भागों की संख्या बताता है। / \( \frac{11}{12} \) means (11) parts out of (12) equal parts. The denominator gives the number of equal parts.
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Which is the correct description of \( -\frac{19}{6} \) on the number line?
C. यह (-4) और (-3) के बीच हैIt lies between (-4) and (-3)
\( -\frac{19}{6}\approx-3.167 \), इसलिए यह (-4) और (-3) के बीच है। ऋणात्मक भिन्न को दशमलव में बदलना उपयोगी है। / \( -\frac{19}{6}\approx-3.167 \), so it lies between (-4) and (-3). Converting a negative fraction to decimal is useful.
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Which value lies between (-2) and \( -\sqrt{3} \) on the number line?
A. ( -1.8 )
\( -\sqrt{3}\approx-1.732 \) है और (-1.8) इसके तथा (-2) के बीच है। ऋणात्मक अंतराल में बाएँ से दाएँ क्रम देखें। / \( -\sqrt{3}\approx-1.732 \), and (-1.8) lies between it and (-2). Check left-to-right order in negative intervals.
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If (x) lies between (-2) and (1) and its distance from (-2) is \( \frac{5}{4} \), what is (x)?
A. \( -\frac{3}{4} \)
(-2) से दाईं ओर \( \frac{5}{4} \) जाने पर \( -2+\frac{5}{4}=-\frac{3}{4} \) मिलता है। दिए गए अंतराल से सही दिशा चुनें। / Moving \( \frac{5}{4} \) to the right of (-2) gives \( -2+\frac{5}{4}=-\frac{3}{4} \). Use the given interval to choose the direction.
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Between which two integers is \( -\frac{17}{5} \) located on the number line?
A. ( -4 ) और ( -3 )( -4 ) and ( -3 )
\( -\frac{17}{5}=-3.4 \) है। यह (-4) और (-3) के बीच आता है। / \( -\frac{17}{5}=-3.4 \). It lies between (-4) and (-3).
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Which value lies between \( -\sqrt{3} \) and \( -\frac{5}{3} \) on the number line?
A. ( -1.70 )
\( -\sqrt{3}\approx-1.732 \) और \( -\frac{5}{3}\approx-1.667 \) है। इसलिए (-1.70) इनके बीच है। / \( -\sqrt{3}\approx-1.732 \) and \( -\frac{5}{3}\approx-1.667 \). Therefore (-1.70) lies between them.
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Which option correctly gives the position of \(2-\sqrt{5}\) on the number line?
A. (-1) और (0) के बीचBetween (-1) and (0)
\( \sqrt{5}\approx2.236\), इसलिए \(2-\sqrt{5}\approx-0.236\)। घटाव वाले मूलों में अनुमान सबसे तेज होता है। / \( \sqrt{5}\approx2.236\), so \(2-\sqrt{5}\approx-0.236\). Estimation is fastest for subtraction with roots.
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A. (-7) और (-6)(-7) and (-6)
\(6<\sqrt{48}<7\), इसलिए \(-7<-\sqrt{48}<-6\)। ऋणात्मक वर्गमूल में अंतराल उल्टा लिखें। / Since \(6<\sqrt{48}<7\), \(-7<-\sqrt{48}<-6\). Write the interval carefully for negative square roots.
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Which value lies between \( -\sqrt{2} \) and ( -1.3 ) on the number line?
A. ( -1.35)
\( -\sqrt{2}\approx-1.414\), इसलिए (-1.35) उसके और (-1.3) के बीच है। ऋणात्मक अंतराल में क्रम सावधानी से पढ़ें। / \( -\sqrt{2}\approx-1.414\), so (-1.35) lies between it and (-1.3). Read order carefully in negative intervals.
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How should \( \frac{7}{8} \) be correctly understood between (0) and (1) on the number line?
A. यह (0) से (1) तक के आठ बराबर भागों में सातवें भाग पर हैIt is at the seventh of eight equal parts from (0) to (1)
\( \frac{7}{8}\) का अर्थ (0) से (1) तक (8) बराबर भागों में (7) भाग है। हर बराबर भागों की संख्या बताता है। / \( \frac{7}{8}\) means (7) parts out of (8) equal parts from (0) to (1). The denominator gives the number of equal parts.
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If \(\sqrt{10}\) is placed on the number line, between which two integers will it lie?
A. (3) और (4)(3) and (4)
क्योंकि \(3^2=9\) और \(4^2=16\), इसलिए \(3<\sqrt{10}<4\)। पहले निकटतम पूर्ण वर्ग खोजें। / Because \(3^2=9\) and \(4^2=16\), \(3<\sqrt{10}<4\). First find the nearest perfect squares.
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Between which two integers will \(\sqrt{37}-6\) lie on the number line?
A. (0) और (1)(0) and (1)
क्योंकि \(6^2<37<7^2\), इसलिए \(6<\sqrt{37}<7\) और \(0<\sqrt{37}-6<1\) है। वर्गमूल वाले अंतराल में समान संख्या घटाकर स्थिति पाएं। / Since \(6^2<37<7^2\), \(6<\sqrt{37}<7\) and \(0<\sqrt{37}-6<1\). Subtract the same number from a root interval to locate the value.
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Between which two integers will \(-\sqrt{11}\) lie on the number line?
C. (-4) और (-3)(-4) and (-3)
\(\sqrt{11}\) (3) और (4) के बीच है इसलिए \(-\sqrt{11}\) (-4) और (-3) के बीच होगा। ऋणात्मक चिन्ह दिशा बदल देता है। / \(\sqrt{11}\) lies between (3) and (4), so \(-\sqrt{11}\) lies between (-4) and (-3). The negative sign changes the side.
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Between which two integers will \(\sqrt{50}\) be located on the number line?
C. (7) और (8)(7) and (8)
क्योंकि \(7^2<50<8^2\), इसलिए \(\sqrt{50}\) (7) और (8) के बीच है। पूर्ण वर्गों से अंतराल तय करें। / Since \(7^2<50<8^2\), \(\sqrt{50}\) lies between (7) and (8). Use perfect squares to decide the interval.
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Which point lies between (-2) and (-1) on the number line?
B. \(-\frac{3}{2}\)
\(-\frac{3}{2}=-1.5\), इसलिए यह (-2) और (-1) के बीच है। परीक्षा में ऋणात्मक भिन्न का दशमलव रूप मदद करता है। / \(-\frac{3}{2}=-1.5\), so it lies between (-2) and (-1). In exams, the decimal form of a negative fraction helps.
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Which number is not between (-1) and (0) on the number line?
C. \(-\frac{5}{4}\)
\(-\frac{5}{4}=-1.25\), जो (-1) से बाईं ओर है। परीक्षा में ऋणात्मक भिन्न को दशमलव में बदलकर जांच सकते हैं। / \(-\frac{5}{4}=-1.25\), which is to the left of (-1). In exams, convert negative fractions into decimals to check.
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Between which two integers will \(-\sqrt{30}\) lie on the number line?
B. (-6) और (-5)(-6) and (-5)
क्योंकि \(\sqrt{30}\) (5) और (6) के बीच है, इसलिए \(-\sqrt{30}\) (-6) और (-5) के बीच होगा। परीक्षा में ऋणात्मक दिशा को ध्यान रखें। / Since \(\sqrt{30}\) lies between (5) and (6), \(-\sqrt{30}\) lies between (-6) and (-5). In exams, keep the negative direction in mind.
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Between which two integers will \(\sqrt{27}\) lie on the number line?
C. (5) और (6)(5) and (6)
क्योंकि \(5^2=25\) और \(6^2=36\), इसलिए \(\sqrt{27}\) (5) और (6) के बीच है। परीक्षा में निकट पूर्ण वर्गों को याद रखें। / Since \(5^2=25\) and \(6^2=36\), \(\sqrt{27}\) lies between (5) and (6). In exams, remember nearby perfect squares.
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Which option correctly describes the position of \(\frac{-13}{6}\) on the number line?
A. यह (-2) और (-3) के बीच हैIt is between (-2) and (-3)
\(\frac{-13}{6}\approx -2.17\), इसलिए यह (-3) और (-2) के बीच है। ऋणात्मक संख्या में पूर्णांक अंतराल उलझा सकता है। / \(\frac{-13}{6}\approx -2.17\), so it lies between (-3) and (-2). Intervals with negative numbers can be tricky.
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To show \(\frac{1}{3}\) on the number line, which mark between (0) and (1) should be taken?
A. तीन बराबर भागों में पहला निशानfirst mark among three equal parts
\(\frac{1}{3}\) के लिए (0) से (1) तक (3) बराबर भाग करें और पहला निशान लें। हर भागों की संख्या बताता है। / For \(\frac{1}{3}\), divide (0) to (1) into (3) equal parts and take the first mark. The denominator tells the number of parts.
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Which point is equal to (0.75) on the number line?
A. \(\frac{3}{4}\)
\(0.75=\frac{75}{100}=\frac{3}{4}\)। (0) से (1) के बीच यह तीन-चौथाई दूरी पर है। / \(0.75=\frac{75}{100}=\frac{3}{4}\). It is three-fourths of the distance from (0) to (1).
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A. (4) भाग(4) parts
\(\frac{3}{4}\) में हर (4) है, इसलिए (0) से (1) को (4) बराबर भागों में बाँटते हैं। फिर (3) भाग दाईं ओर जाते हैं। / The denominator of \(\frac{3}{4}\) is (4), so divide (0) to (1) into (4) equal parts. Then move (3) parts to the right.
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What is the correct condition for (x-2+2(v+2)x+(4v+11)=0) to have no real roots?
A. \(-\sqrt{7}<v<\sqrt{7}\)
यहाँ (D=4(v+2)2-4(4v+11)=4\(v^2-7\)) है। (D<0) से \(-\sqrt{7}<v<\sqrt{7}\)। / Here (D=4(v+2)2-4(4v+11)=4\(v^2-7\)). From (D<0), \(-\sqrt{7}<v<\sqrt{7}\).
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What is the correct condition for (x-2+2(t+1)x+(3t+7)=0) to have no real roots?
A. (-2<t<3)
यहाँ (D=4\(t^2-t-6\)=4(t-3)(t+2)) है। (D<0) से (-2<t<3) मिलता है। / Here (D=4\(t^2-t-6\)=4(t-3)(t+2)). From (D<0), we get (-2<t<3).
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Which condition is correct for two distinct real roots of (3x-2-2(2k+1)x+(k+1)2=0)?
A. (k<-2) या (k>1)(k<-2) or (k>1)
यहाँ (D=4(k-1)(k+2)) है। (D>0) से (k<-2) या (k>1) मिलता है। / Here (D=4(k-1)(k+2)). From (D>0), we get (k<-2) or (k>1).
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What is the correct condition for (x-2+2(k-1)x+(k+5)=0) to have no real roots?
A. (-1<k<4)
यहाँ (D=4((k-1)2-(k+5))=4\(k^2-3k-4\)) है। (D<0) से ((k-4)(k+1)<0), इसलिए (-1<k<4)। / Here (D=4((k-1)2-(k+5))=4\(k^2-3k-4\)). From (D<0), ((k-4)(k+1)<0), so (-1<k<4).
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If (3x-2+(k-2)x+4=0) has two distinct real roots, which condition on (k) is correct?
A. \(k<2-4\sqrt{3}\) या \(k>2+4\sqrt{3}\)\(k<2-4\sqrt{3}\) or \(k>2+4\sqrt{3}\)
यहाँ (D=(k-2)2-48) है। असमान वास्तविक मूलों के लिए (D>0), इसलिए ((k-2)2>48)। / Here (D=(k-2)2-48). For distinct real roots (D>0), so ((k-2)2>48).
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When will (3x-2-2(2a+1)x+\(a^2+a+1\)=0) have real and distinct roots?
A. (a<-2) या (a>1)(a<-2) or (a>1)
वास्तविक और भिन्न मूलों के लिए (D>0) चाहिए। \(a^2+a-2>0\) से (a<-2) या (a>1) मिलता है। / For real and distinct roots, (D>0) is needed. From \(a^2+a-2>0\), we get (a<-2) or (a>1).
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If (D=(s-2)(s+5)), when will the roots be real and distinct?
A. (s<-5) या (s>2)(s<-5) or (s>2)
वास्तविक और भिन्न मूलों के लिए (D>0) चाहिए। ((s-2)(s+5)>0) से (s<-5) या (s>2) मिलता है। / For real and distinct roots, (D>0) is required. From ((s-2)(s+5)>0), we get (s<-5) or (s>2).
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If \(x^2+2px+2p+9=0\) has real roots, which condition on (p) is correct?
A. \(p\le -2\) या \(p\ge \frac{9}{2}\)\(p\le -2\) or \(p\ge \frac{9}{2}\)
वास्तविक मूलों के लिए \(D\ge0\) चाहिए। यहाँ (D=4(p+2)(2p-9)), इसलिए \(p\le -2\) या \(p\ge \frac{9}{2}\)। / For real roots, \(D\ge0\) is required. Here (D=4(p+2)(2p-9)), so \(p\le -2\) or \(p\ge \frac{9}{2}\).
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If (2x-2+(k+1)x+3=0) has two distinct real roots, which condition on (k) is correct?
A. \(k<-1-2\sqrt{6}\) या \(k>-1+2\sqrt{6}\)\(k<-1-2\sqrt{6}\) or \(k>-1+2\sqrt{6}\)
यहाँ (D=(k+1)2-24) है। असमान वास्तविक मूलों के लिए (D>0), इसलिए ((k+1)2>24)। / Here (D=(k+1)2-24). For distinct real roots (D>0), so ((k+1)2>24).
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