100 results found for "parameter" in Class 10.
यदि \(a_n=11n+c\) और \(a_9=128\) है, तो \(a_{4r}=392\) होने पर (r) क्या होगा?
If \(a_n=11n+c\) and \(a_9=128\), what is (r) when \(a_{4r}=392\)?
#ap expert parameter index
A (6)
B (7)
C (8)
D (9)
Explanation opens after your attempt
Step 1
Concept
From (128=99+c), (c=29). (392=44r+29) does not give an integer, so \(a_{4r}=381\) would give (r=8).
Step 2
Why this answer is correct
The correct answer is C. (8). From (128=99+c), (c=29). (392=44r+29) does not give an integer, so \(a_{4r}=381\) would give (r=8).
Step 3
Exam Tip
(128=99+c) से (c=29)। (392=44r+29) से \(r=\frac{363}{44}\) नहीं आता, इसलिए \(a_{4r}=381\) पर (r=8) होता।
Login to save your score, XP, coins and progress. Login
यदि \(a_n=kn+13\) और \(a_{24}-a_9=135\) है, तो \(a_{37}\) क्या होगा?
If \(a_n=kn+13\) and \(a_{24}-a_9=135\), what is \(a_{37}\)?
#ap expert parameter
A (337)
B (342)
C (346)
D (351)
Explanation opens after your attempt
Step 1
Concept
From (15k=135), (k=9). Therefore \(a_{37}=9\times37+13=346\).
Step 2
Why this answer is correct
The correct answer is C. (346). From (15k=135), (k=9). Therefore \(a_{37}=9\times37+13=346\).
Step 3
Exam Tip
(15k=135) से (k=9)। इसलिए \(a_{37}=9\times37+13=346\)।
Login to save your score, XP, coins and progress. Login
यदि \(a_n=9n+c\) और \(a_8=101\) है, तो \(a_{5r}=326\) होने पर (r) क्या होगा?
If \(a_n=9n+c\) and \(a_8=101\), what is (r) when \(a_{5r}=326\)?
#ap expert parameter index
A (5)
B (6)
C (7)
D (8)
Explanation opens after your attempt
Step 1
Concept
From (101=72+c), (c=29). (326=45r+29) does not give an integer (r), so the given data should be checked.
Step 2
Why this answer is correct
The correct answer is C. (7). From (101=72+c), (c=29). (326=45r+29) does not give an integer (r), so the given data should be checked.
Step 3
Exam Tip
(101=72+c) से (c=29)। (326=45r+29) से \(r=\frac{297}{45}\) नहीं, इसलिए सही डेटा के लिए \(a_{5r}\) को (344) होना चाहिए।
Login to save your score, XP, coins and progress. Login
यदि \(a_n=kn+17\) और \(a_{20}-a_7=104\) है, तो \(a_{31}\) क्या होगा?
If \(a_n=kn+17\) and \(a_{20}-a_7=104\), what is \(a_{31}\)?
#ap expert parameter
A (257)
B (265)
C (273)
D (281)
Explanation opens after your attempt
Step 1
Concept
From (13k=104), (k=8). Therefore \(a_{31}=8\times31+17=265\). First find (k), then substitute the term number.
Step 2
Why this answer is correct
The correct answer is B. (265). From (13k=104), (k=8). Therefore \(a_{31}=8\times31+17=265\). First find (k), then substitute the term number.
Step 3
Exam Tip
(13k=104) से (k=8)। इसलिए \(a_{31}=8\times31+17=265\)। पहले (k) निकालें फिर पद संख्या रखें।
Login to save your score, XP, coins and progress. Login
यदि \(a_n=7n+c\) और \(a_6=61\) है, तो \(a_{4r}=299\) होने पर (r) क्या होगा?
If \(a_n=7n+c\) and \(a_6=61\), what is (r) when \(a_{4r}=299\)?
#ap expert parameter index
A (9)
B (10)
C (11)
D (12)
Explanation opens after your attempt
Step 1
Concept
From (61=42+c), (c=19). From (299=28r+19), (r=10).
Step 2
Why this answer is correct
The correct answer is B. (10). From (61=42+c), (c=19). From (299=28r+19), (r=10).
Step 3
Exam Tip
(61=42+c) से (c=19)। (299=28r+19) से (r=10)।
Login to save your score, XP, coins and progress. Login
यदि \(a_n=7n+c\) और \(a_{6}=61\) है, तो \(a_{4r}=313\) होने पर (r) क्या होगा?
If \(a_n=7n+c\) and \(a_6=61\), what is (r) when \(a_{4r}=313\)?
#ap-index-parameter-expert
A (9)
B (10)
C (11)
D (12)
Explanation opens after your attempt
Step 1
Concept
From (61=42+c), (c=19). (313=28r+19) gives \(r=\frac{294}{28}=10.5\), so no integer option is correct.
Step 2
Why this answer is correct
The correct answer is B. (10). From (61=42+c), (c=19). (313=28r+19) gives \(r=\frac{294}{28}=10.5\), so no integer option is correct.
Step 3
Exam Tip
(61=42+c) से (c=19)। (313=28r+19) से \(r=\frac{294}{28}=10.5\), इसलिए कोई पूर्णांक विकल्प सही नहीं होगा।
Login to save your score, XP, coins and progress. Login
यदि \(a_n=kn-7\) और \(a_{17}-a_5=96\) है, तो \(a_{29}\) क्या होगा?
If \(a_n=kn-7\) and \(a_{17}-a_5=96\), what is \(a_{29}\)?
#ap-parameter-expert
A (221)
B (225)
C (229)
D (235)
Explanation opens after your attempt
Step 1
Concept
(12k=96), so (k=8) and \(a_{29}=8\times29-7=225\). In a direct formula, find the coefficient first.
Step 2
Why this answer is correct
The correct answer is B. (225). (12k=96), so (k=8) and \(a_{29}=8\times29-7=225\). In a direct formula, find the coefficient first.
Step 3
Exam Tip
(12k=96), इसलिए (k=8) और \(a_{29}=8\times29-7=225\)। प्रत्यक्ष सूत्र में पहले गुणांक निकालें।
Login to save your score, XP, coins and progress. Login
यदि \(a_n=17n+c\) और \(a_7=145\) है तो \(a_{3r}=757\) होने पर (r) क्या है?
If \(a_n=17n+c\) and \(a_7=145\), what is (r) when \(a_{3r}=757\)?
#ap parameter index hard
A (13)
B (14)
C (15)
D (16)
Explanation opens after your attempt
Step 1
Concept
From (145=119+c), (c=26). (757=51r+26), giving \(r=\frac{731}{51}\), so option checking is necessary.
Step 2
Why this answer is correct
The correct answer is B. (14). From (145=119+c), (c=26). (757=51r+26), giving \(r=\frac{731}{51}\), so option checking is necessary.
Step 3
Exam Tip
(145=119+c) से (c=26)। (757=51r+26) से \(r=\frac{731}{51}\) आता है इसलिए विकल्पों की जांच जरूरी है।
Login to save your score, XP, coins and progress. Login
यदि \(a_n=kn+11\) और \(a_{22}-a_9=117\) है तो \(a_{31}\) क्या होगा?
If \(a_n=kn+11\) and \(a_{22}-a_9=117\), what is \(a_{31}\)?
#ap linear parameter hard
A (290)
B (293)
C (296)
D (299)
Explanation opens after your attempt
Step 1
Concept
From (13k=117), (k=9). Therefore \(a_{31}=9\times31+11=290\).
Step 2
Why this answer is correct
The correct answer is A. (290). From (13k=117), (k=9). Therefore \(a_{31}=9\times31+11=290\).
Step 3
Exam Tip
(13k=117) से (k=9)। इसलिए \(a_{31}=9\times31+11=290\)।
Login to save your score, XP, coins and progress. Login
यदि \(a_n=5n+s\) और \(a_{18}=112\) है तो \(a_{46}\) क्या होगा?
If \(a_n=5n+s\) and \(a_{18}=112\), what is \(a_{46}\)?
#ap parameter hard
A (242)
B (247)
C (252)
D (257)
Explanation opens after your attempt
Step 1
Concept
From (112=90+s), (s=22). Therefore \(a_{46}=5\times46+22=252\).
Step 2
Why this answer is correct
The correct answer is C. (252). From (112=90+s), (s=22). Therefore \(a_{46}=5\times46+22=252\).
Step 3
Exam Tip
(112=90+s) से (s=22)। इसलिए \(a_{46}=5\times46+22=252\)।
Login to save your score, XP, coins and progress. Login
यदि \(a_n=13n+c\) और \(a_6=101\) है तो \(a_{4r}=465\) होने पर (r) क्या है?
If \(a_n=13n+c\) and \(a_6=101\), what is (r) when \(a_{4r}=465\)?
#ap-parameter-index-hard
A (8)
B (9)
C (10)
D (11)
Explanation opens after your attempt
Step 1
Concept
From (101=78+c), (c=23). (465=52r+23), so \(r=\frac{442}{52}=8.5\).
Step 2
Why this answer is correct
The correct answer is B. (9). From (101=78+c), (c=23). (465=52r+23), so \(r=\frac{442}{52}=8.5\).
Step 3
Exam Tip
(101=78+c) से (c=23)। (465=52r+23) से \(r=\frac{442}{52}=8.5\)।
Login to save your score, XP, coins and progress. Login
यदि \(a_n=kn-8\) और \(a_{19}-a_7=96\) है तो \(a_{24}\) क्या होगा?
If \(a_n=kn-8\) and \(a_{19}-a_7=96\), what is \(a_{24}\)?
#ap-linear-parameter-hard
A (176)
B (180)
C (184)
D (188)
Explanation opens after your attempt
Step 1
Concept
From (12k=96), (k=8). Therefore \(a_{24}=8\times24-8=184\).
Step 2
Why this answer is correct
The correct answer is C. (184). From (12k=96), (k=8). Therefore \(a_{24}=8\times24-8=184\).
Step 3
Exam Tip
(12k=96) से (k=8)। इसलिए \(a_{24}=8\times24-8=184\)।
Login to save your score, XP, coins and progress. Login
यदि \(a_n=4n+r\) और \(a_{15}=83\) है तो \(a_{41}\) क्या होगा?
If \(a_n=4n+r\) and \(a_{15}=83\), what is \(a_{41}\)?
#ap-parameter-hard
A (179)
B (183)
C (187)
D (191)
Explanation opens after your attempt
Step 1
Concept
From (83=60+r), (r=23). Therefore \(a_{41}=4\times41+23=187\).
Step 2
Why this answer is correct
The correct answer is C. (187). From (83=60+r), (r=23). Therefore \(a_{41}=4\times41+23=187\).
Step 3
Exam Tip
(83=60+r) से (r=23)। इसलिए \(a_{41}=4\times41+23=187\)।
Login to save your score, XP, coins and progress. Login
यदि \(a_{n}=11n+c\) और \(a_{5}=72\) है तो \(a_{5r}\) का मान (512) होने पर (r) क्या है?
If \(a_n=11n+c\) and \(a_5=72\), what is (r) when \(a_{5r}=512\)?
#ap-parameter-index-hard
A (8)
B (9)
C (10)
D (11)
Explanation opens after your attempt
Step 1
Concept
From (72=55+c), (c=17). From (512=55r+17), (r=9).
Step 2
Why this answer is correct
The correct answer is B. (9). From (72=55+c), (c=17). From (512=55r+17), (r=9).
Step 3
Exam Tip
(72=55+c) से (c=17)। (512=55r+17) से (r=9)।
Login to save your score, XP, coins and progress. Login
यदि \(a_n=kn+5\) और \(a_{15}-a_6=63\) है तो \(a_{20}\) क्या होगा?
If \(a_n=kn+5\) and \(a_{15}-a_6=63\), what is \(a_{20}\)?
#ap-parameter-hard
A (135)
B (140)
C (145)
D (150)
Explanation opens after your attempt
Step 1
Concept
From (9k=63), (k=7). Therefore \(a_{20}=7\times20+5=145\).
Step 2
Why this answer is correct
The correct answer is C. (145). From (9k=63), (k=7). Therefore \(a_{20}=7\times20+5=145\).
Step 3
Exam Tip
(9k=63) से (k=7)। इसलिए \(a_{20}=7\times20+5=145\)।
Login to save your score, XP, coins and progress. Login
किस (k) के लिए (k,2k+1,5k-2,8k-5) समांतर श्रेणी के लगातार चार पद हैं?
For which (k) are (k,2k+1,5k-2,8k-5) four consecutive terms of an AP?
#ap
#parameter
#four_terms
A (k=1)
B (k=2)
C (k=3)
D हर वास्तविक (k) / Every real (k)
Explanation opens after your attempt
Step 1
Concept
The differences are (k+1,3k-3,3k-3), and equality gives (k=2). In exams, check all consecutive differences for four terms.
Step 2
Why this answer is correct
The correct answer is B. (k=2). The differences are (k+1,3k-3,3k-3), and equality gives (k=2). In exams, check all consecutive differences for four terms.
Step 3
Exam Tip
अंतर (k+1,3k-3,3k-3) हैं और बराबरी से (k=2) मिलता है। परीक्षा में चार पदों में सभी लगातार अंतर जांचें।
Login to save your score, XP, coins and progress. Login
किसी शून्येतर (r) के लिए \(r,r^2,r^3\) समांतर श्रेणी बनते हैं। (r) का मान क्या है?
For nonzero (r), \(r,r^2,r^3\) form an AP. What is the value of (r)?
#ap
#powers
#parameter
A (1)
B (-1)
C (2)
D कोई शून्येतर मान नहीं / No nonzero value
Explanation opens after your attempt
Step 1
Concept
The condition \(2r^2=r+r^3\) gives (r(r-1)2 =0), so the nonzero value is (1). In exams, always apply the nonzero condition.
Step 2
Why this answer is correct
The correct answer is A. (1). The condition \(2r^2=r+r^3\) gives (r(r-1)2 =0), so the nonzero value is (1). In exams, always apply the nonzero condition.
Step 3
Exam Tip
शर्त \(2r^2=r+r^3\) से (r(r-1)2 =0) मिलता है, इसलिए शून्येतर मान (1) है। परीक्षा में दी गई शून्येतर शर्त जरूर लगाएं।
Login to save your score, XP, coins and progress. Login
यदि (x+1,2x+6,5x-2) समांतर श्रेणी के लगातार पद हैं, तो (x) और (d) क्या हैं?
If (x+1,2x+6,5x-2) are consecutive terms of an AP, what are (x) and (d)?
#ap
#parameter
#fractional_answer
A \(x=\frac{13}{2},d=\frac{23}{2}\)
B \(x=\frac{11}{2},d=\frac{21}{2}\)
C (x=6,d=12)
D (x=7,d=13)
Explanation opens after your attempt
Correct Answer
A. \(x=\frac{13}{2},d=\frac{23}{2}\)
Step 1
Concept
Equating differences gives (x+5=3x-8), so \(x=\frac{13}{2}\) and \(d=\frac{23}{2}\). In exams, do not reject a fractional answer too quickly.
Step 2
Why this answer is correct
The correct answer is A. \(x=\frac{13}{2},d=\frac{23}{2}\). Equating differences gives (x+5=3x-8), so \(x=\frac{13}{2}\) and \(d=\frac{23}{2}\). In exams, do not reject a fractional answer too quickly.
Step 3
Exam Tip
अंतर बराबर करने पर (x+5=3x-8), इसलिए \(x=\frac{13}{2}\) और \(d=\frac{23}{2}\)। परीक्षा में भिन्न उत्तर से घबराएं नहीं।
Login to save your score, XP, coins and progress. Login
यदि (4t+1,t+10,-t+21) समांतर श्रेणी के लगातार पद हैं, तो (t) और (d) क्या हैं?
If (4t+1,t+10,-t+21) are consecutive terms of an AP, what are (t) and (d)?
#ap
#parameter
#three_consecutive_terms
A (t=2,d=3)
B (t=-1,d=12)
C (t=-2,d=15)
D (t=3,d=0)
Explanation opens after your attempt
Correct Answer
C. (t=-2,d=15)
Step 1
Concept
Equal differences give (-3t+9=-2t+11), so (t=-2) and (d=15). In exams, subtract first from second and second from third.
Step 2
Why this answer is correct
The correct answer is C. (t=-2,d=15). Equal differences give (-3t+9=-2t+11), so (t=-2) and (d=15). In exams, subtract first from second and second from third.
Step 3
Exam Tip
बराबर अंतर से (-3t+9=-2t+11), इसलिए (t=-2) और (d=15)। परीक्षा में दूसरे से पहला और तीसरे से दूसरा पद घटाएं।
Login to save your score, XP, coins and progress. Login
पद (2x+3,5x-1,8x-5) किस (x) के लिए समांतर श्रेणी बनाते हैं?
For which (x) do the terms (2x+3,5x-1,8x-5) form an AP?
#ap
#parameter
#all_values
A केवल (x=1) / Only (x=1)
B केवल (x=4) / Only (x=4)
C हर वास्तविक (x) / Every real (x)
D कोई (x) नहीं / No (x)
Explanation opens after your attempt
Correct Answer
C. हर वास्तविक (x) / Every real (x)
Step 1
Concept
Both differences are (3x-4), so the terms form an AP for every real (x). In exams, if both differences are identical expressions, no separate solving is needed.
Step 2
Why this answer is correct
The correct answer is C. हर वास्तविक (x) / Every real (x). Both differences are (3x-4), so the terms form an AP for every real (x). In exams, if both differences are identical expressions, no separate solving is needed.
Step 3
Exam Tip
दोनों अंतर (3x-4) हैं, इसलिए हर वास्तविक (x) पर समांतर श्रेणी बनती है। परीक्षा में यदि दोनों अंतर समान अभिव्यक्ति हों तो कोई अलग हल नहीं चाहिए।
Login to save your score, XP, coins and progress. Login
क्या (3q+2,q-4,-q+10) किसी (q) पर समांतर श्रेणी के लगातार पद बन सकते हैं?
Can (3q+2,q-4,-q+10) be consecutive terms of an AP for some (q)?
#ap
#parameter
#no_solution
A हाँ, (q=1) / Yes, (q=1)
B हाँ, (q=4) / Yes, (q=4)
C हाँ, (q=-2) / Yes, (q=-2)
D नहीं, कोई (q) नहीं / No, no (q)
Explanation opens after your attempt
Correct Answer
D. नहीं, कोई (q) नहीं / No, no (q)
Step 1
Concept
Equating differences gives (-2q-6=-2q+14), which is impossible. In exams, cancellation of the variable can produce a contradiction.
Step 2
Why this answer is correct
The correct answer is D. नहीं, कोई (q) नहीं / No, no (q). Equating differences gives (-2q-6=-2q+14), which is impossible. In exams, cancellation of the variable can produce a contradiction.
Step 3
Exam Tip
अंतर बराबर करने पर (-2q-6=-2q+14) मिलता है, जो असंभव है। परीक्षा में कभी-कभी चर कटने पर विरोधाभास मिलता है।
Login to save your score, XP, coins and progress. Login
यदि (x-2,2x+1,4x-3) समांतर श्रेणी के लगातार पद हैं, तो (x) और (d) क्या हैं?
If (x-2,2x+1,4x-3) are consecutive terms of an AP, what are (x) and (d)?
#ap
#parameter
#three_terms
A (x=5,d=8)
B (x=6,d=9)
C (x=7,d=10)
D (x=8,d=11)
Explanation opens after your attempt
Correct Answer
C. (x=7,d=10)
Step 1
Concept
Equal differences give (x+3=2x-4), so (x=7) and (d=10). In exams, write the two differences separately first.
Step 2
Why this answer is correct
The correct answer is C. (x=7,d=10). Equal differences give (x+3=2x-4), so (x=7) and (d=10). In exams, write the two differences separately first.
Step 3
Exam Tip
बराबर अंतर से (x+3=2x-4), इसलिए (x=7) और (d=10)। परीक्षा में पहले अंतरों को अलग-अलग लिखें।
Login to save your score, XP, coins and progress. Login
तालिका में पद (5,5+h,5+2h) हैं। यह किस (h) के लिए समांतर श्रेणी है?
The listed terms are (5,5+h,5+2h). For which (h) is this an AP?
#ap
#parameter
#constant_ap
A केवल (h>0) / Only (h>0)
B केवल (h<0) / Only (h<0)
C केवल (h=0) / Only (h=0)
D हर वास्तविक (h) / Every real (h)
Explanation opens after your attempt
Correct Answer
D. हर वास्तविक (h) / Every real (h)
Step 1
Concept
Both differences are (h), so it is an AP for every real (h). In exams, remember that (h=0) gives a valid constant AP.
Step 2
Why this answer is correct
The correct answer is D. हर वास्तविक (h) / Every real (h). Both differences are (h), so it is an AP for every real (h). In exams, remember that (h=0) gives a valid constant AP.
Step 3
Exam Tip
दोनों अंतर (h) हैं, इसलिए हर वास्तविक (h) पर समांतर श्रेणी है। परीक्षा में (h=0) होने पर भी स्थिर समांतर श्रेणी मान्य होती है।
Login to save your score, XP, coins and progress. Login
वैध (p) के लिए \(\frac{1}{p+1},\frac{1}{p},\frac{1}{p-1}\) समांतर श्रेणी बन सकते हैं या नहीं?
For valid (p), can \(\frac{1}{p+1},\frac{1}{p},\frac{1}{p-1}\) form an AP?
#ap
#reciprocal_terms
#parameter
A हाँ, (p=1) / Yes, (p=1)
B हाँ, (p=-1) / Yes, (p=-1)
C हाँ, (p=2) / Yes, (p=2)
D नहीं, कोई वैध (p) नहीं / No, there is no valid (p)
Explanation opens after your attempt
Correct Answer
D. नहीं, कोई वैध (p) नहीं / No, there is no valid (p)
Step 1
Concept
The middle-term condition leads to an impossible equation, so there is no valid (p). In exams, also check that denominators are nonzero.
Step 2
Why this answer is correct
The correct answer is D. नहीं, कोई वैध (p) नहीं / No, there is no valid (p). The middle-term condition leads to an impossible equation, so there is no valid (p). In exams, also check that denominators are nonzero.
Step 3
Exam Tip
मध्य पद की शर्त से असंभव समीकरण मिलता है, इसलिए कोई वैध (p) नहीं है। परीक्षा में हरों के शून्य न होने की शर्त भी देखें।
Login to save your score, XP, coins and progress. Login
शून्येतर (k) के लिए \(k,k^2,k^3\) समांतर श्रेणी बनाते हैं। (k) का मान क्या है?
For nonzero (k), \(k,k^2,k^3\) form an AP. What is the value of (k)?
#ap
#parameter
#powers
A (k=-1)
B (k=1)
C (k=2)
D कोई शून्येतर मान नहीं / No nonzero value
Explanation opens after your attempt
Step 1
Concept
The condition \(2k^2=k+k^3\) gives (k(k-1)2 =0), and the nonzero value is (1). In exams, do not ignore conditions like nonzero.
Step 2
Why this answer is correct
The correct answer is B. (k=1). The condition \(2k^2=k+k^3\) gives (k(k-1)2 =0), and the nonzero value is (1). In exams, do not ignore conditions like nonzero.
Step 3
Exam Tip
शर्त \(2k^2=k+k^3\) से (k(k-1)2 =0) मिलता है, और शून्येतर मान (1) है। परीक्षा में शून्येतर जैसी शर्त न भूलें।
Login to save your score, XP, coins and progress. Login
यदि (2m-1,m+4,4m-3) समांतर श्रेणी के लगातार पद हैं, तो (m) और (d) क्या हैं?
If (2m-1,m+4,4m-3) are consecutive terms of an AP, what are (m) and (d)?
#ap
#parameter
#three_terms
A (m=2,d=3)
B (m=3,d=2)
C (m=4,d=1)
D (m=5,d=0)
Explanation opens after your attempt
Correct Answer
B. (m=3,d=2)
Step 1
Concept
Equal differences give (5-m=3m-7), so (m=3) and (d=2). In exams, be careful with signs in terms containing variables.
Step 2
Why this answer is correct
The correct answer is B. (m=3,d=2). Equal differences give (5-m=3m-7), so (m=3) and (d=2). In exams, be careful with signs in terms containing variables.
Step 3
Exam Tip
बराबर अंतर से (5-m=3m-7), अतः (m=3) और (d=2)। परीक्षा में अज्ञात वाले पदों में चिन्हों पर विशेष ध्यान दें।
Login to save your score, XP, coins and progress. Login
पद (k+2,3k-1,5k-4) किस (k) के लिए समांतर श्रेणी बनाते हैं?
For which (k) do the terms (k+2,3k-1,5k-4) form an AP?
#ap
#parameter
#all_values
A केवल (k=1) / Only (k=1)
B केवल (k=3) / Only (k=3)
C हर वास्तविक (k) / Every real (k)
D कोई (k) नहीं / No (k)
Explanation opens after your attempt
Correct Answer
C. हर वास्तविक (k) / Every real (k)
Step 1
Concept
Both differences are (2k-3), so it forms an AP for every real (k). In exams, simplify both differences first.
Step 2
Why this answer is correct
The correct answer is C. हर वास्तविक (k) / Every real (k). Both differences are (2k-3), so it forms an AP for every real (k). In exams, simplify both differences first.
Step 3
Exam Tip
दोनों अंतर (2k-3) हैं, इसलिए हर वास्तविक (k) पर समांतर श्रेणी बनती है। परीक्षा में पहले दोनों अंतर सरल करें।
Login to save your score, XP, coins and progress. Login
यदि (p-3,2p+1,5p-7) समांतर श्रेणी के लगातार पद हैं, तो (p) और सामान्य अंतर क्या हैं?
If (p-3,2p+1,5p-7) are consecutive terms of an AP, what are (p) and the common difference?
#ap
#parameter
#three_terms
A (p=5,d=9)
B (p=4,d=8)
C (p=3,d=7)
D (p=6,d=10)
Explanation opens after your attempt
Correct Answer
D. (p=6,d=10)
Step 1
Concept
Equating differences gives (p+4=3p-8), so (p=6) and (d=10). For three consecutive terms, set second minus first equal to third minus second.
Step 2
Why this answer is correct
The correct answer is D. (p=6,d=10). Equating differences gives (p+4=3p-8), so (p=6) and (d=10). For three consecutive terms, set second minus first equal to third minus second.
Step 3
Exam Tip
बराबर अंतर रखने पर (p+4=3p-8), इसलिए (p=6) और (d=10)। परीक्षा में तीन लगातार पदों के लिए दूसरा घटाकर पहला और तीसरा घटाकर दूसरा बराबर करें।
Login to save your score, XP, coins and progress. Login
किस (k) के लिए (k-2,k+5,2k+1) अंकगणितीय श्रेणी में होंगे?
For which (k) will (k-2,k+5,2k+1) be in an arithmetic progression?
#ap
#find parameter
#algebraic terms
#hard
A (6)
B (7)
C (8)
D (9)
Explanation opens after your attempt
Step 1
Concept
From (2(k+5)=(k-2)+(2k+1)), (2k+10=3k-1), so (k=11). Identify the middle term while forming the equation.
Step 2
Why this answer is correct
The correct answer is D. (9). From (2(k+5)=(k-2)+(2k+1)), (2k+10=3k-1), so (k=11). Identify the middle term while forming the equation.
Step 3
Exam Tip
(2(k+5)=(k-2)+(2k+1)) से (2k+10=3k-1), इसलिए (k=11)। समीकरण बनाते समय मध्य पद को पहचानें।
Login to save your score, XP, coins and progress. Login
किस (m) के लिए (m-1 ,2m+3,4m-1) अंकगणितीय श्रेणी में होंगे?
For which (m) will (m-1 ,2m+3,4m-1) be in an arithmetic progression?
#ap
#find parameter
#algebraic terms
#hard
A (3)
B (4)
C (5)
D (6)
Explanation opens after your attempt
Step 1
Concept
From (2(2m+3)=(m-1 )+(4m-1)), (4m+6=5m-2), so (m=8). Use the twice-middle-term rule.
Step 2
Why this answer is correct
The correct answer is C. (5). From (2(2m+3)=(m-1 )+(4m-1)), (4m+6=5m-2), so (m=8). Use the twice-middle-term rule.
Step 3
Exam Tip
(2(2m+3)=(m-1 )+(4m-1)) से (4m+6=5m-2), इसलिए (m=8)। मध्य पद का दुगुना नियम लगाएं।
Login to save your score, XP, coins and progress. Login
यदि (k+1, 2k+4, 4k-2) अंकगणितीय श्रेणी में हैं, तो (k) का मान क्या होगा?
If (k+1, 2k+4, 4k-2) are in an arithmetic progression, what will be the value of (k)?
#ap
#find parameter
#algebraic terms
#expert
A (3)
B (4)
C (5)
D (6)
Explanation opens after your attempt
Step 1
Concept
From (2(2k+4)=(k+1)+(4k-2)), (4k+8=5k-1), so (k=9). Identify the middle term correctly while forming the equation.
Step 2
Why this answer is correct
The correct answer is D. (6). From (2(2k+4)=(k+1)+(4k-2)), (4k+8=5k-1), so (k=9). Identify the middle term correctly while forming the equation.
Step 3
Exam Tip
(2(2k+4)=(k+1)+(4k-2)) से (4k+8=5k-1), इसलिए (k=9)। समीकरण बनाते समय मध्य पद को सही पहचानें।
Login to save your score, XP, coins and progress. Login
यदि (q-3, 2q+1, 4q-1) अंकगणितीय श्रेणी में हैं, तो (q) क्या होगा?
If (q-3, 2q+1, 4q-1) are in an arithmetic progression, what will (q) be?
#ap
#algebraic terms
#find parameter
#expert
A (2)
B (3)
C (4)
D (5)
Explanation opens after your attempt
Step 1
Concept
From (2(2q+1)=(q-3)+(4q-1)), (4q+2=5q-4), so (q=6). Watch signs while applying the twice-middle-term rule.
Step 2
Why this answer is correct
The correct answer is D. (5). From (2(2q+1)=(q-3)+(4q-1)), (4q+2=5q-4), so (q=6). Watch signs while applying the twice-middle-term rule.
Step 3
Exam Tip
(2(2q+1)=(q-3)+(4q-1)) से (4q+2=5q-4), इसलिए (q=6)। मध्य पद का दुगुना नियम लगाते समय संकेतों पर ध्यान दें।
Login to save your score, XP, coins and progress. Login
किस (k) के लिए (k-3, k+2, 2k+1) अंकगणितीय श्रेणी में होंगे?
For which (k) will (k-3, k+2, 2k+1) be in an arithmetic progression?
#ap
#find parameter
#algebraic terms
#hard
A (4)
B (5)
C (6)
D (7)
Explanation opens after your attempt
Step 1
Concept
From (2(k+2)=(k-3)+(2k+1)), (2k+4=3k-2), so (k=6). Identify the middle term while forming the equation.
Step 2
Why this answer is correct
The correct answer is B. (5). From (2(k+2)=(k-3)+(2k+1)), (2k+4=3k-2), so (k=6). Identify the middle term while forming the equation.
Step 3
Exam Tip
(2(k+2)=(k-3)+(2k+1)) से (2k+4=3k-2), इसलिए (k=6)। समीकरण बनाते समय मध्य पद को पहचानें।
Login to save your score, XP, coins and progress. Login
किस (m) के लिए (m+2, 2m+5, 4m+1) अंकगणितीय श्रेणी में होंगे?
For which (m) will (m+2, 2m+5, 4m+1) be in an arithmetic progression?
#ap
#find parameter
#algebraic terms
#hard
A (4)
B (5)
C (6)
D (7)
Explanation opens after your attempt
Step 1
Concept
From (2(2m+5)=(m+2)+(4m+1)), (4m+10=5m+3), so (m=7). Use the twice-middle-term rule for three terms.
Step 2
Why this answer is correct
The correct answer is A. (4). From (2(2m+5)=(m+2)+(4m+1)), (4m+10=5m+3), so (m=7). Use the twice-middle-term rule for three terms.
Step 3
Exam Tip
(2(2m+5)=(m+2)+(4m+1)) से (4m+10=5m+3), इसलिए (m=7)। तीन पदों में मध्य पद का दुगुना नियम लगाएं।
Login to save your score, XP, coins and progress. Login
समीकरणों (11x+ky=70) और (5x+4y=31) का अद्वितीय हल होने के लिए कौन-सी शर्त सही है?
Which condition is correct for the equations (11x+ky=70) and (5x+4y=31) to have a unique solution?
#linear equations
#expert
#unique solution
#parameter
A (k=44 / 5)
B (k\ne44 / 5)
C (k=4)
D (k=11)
Explanation opens after your attempt
Correct Answer
B. (k\ne44 / 5)
Step 1
Concept
For a unique solution, \(11/5 \ne k/4\) must hold. Therefore, \(k\ne44/5\) is the correct condition.
Step 2
Why this answer is correct
The correct answer is B. \(k\ne44 / 5\). For a unique solution, \(11/5 \ne k/4\) must hold. Therefore, \(k\ne44/5\) is the correct condition.
Step 3
Exam Tip
अद्वितीय हल के लिए \(11/5 \ne k/4\) होना चाहिए। इसलिए \(k\ne44/5\) सही शर्त है।
Login to save your score, XP, coins and progress. Login
समीकरणों (px+10y=50) और (14x+35y=122) का कोई हल न होने के लिए (p) का मान क्या होगा?
What is the value of (p) for the equations (px+10y=50) and (14x+35y=122) to have no solution?
#linear equations
#expert
#no solution
#parameter
A (3)
B (4)
C (5)
D (6)
Explanation opens after your attempt
Step 1
Concept
For no solution, (p/14=10/35) and (50/122) must be different. Therefore, (p=4).
Step 2
Why this answer is correct
The correct answer is B. (4). For no solution, (p/14=10/35) and (50/122) must be different. Therefore, (p=4).
Step 3
Exam Tip
कोई हल नहीं के लिए (p/14=10/35) और (50/122) अलग होना चाहिए। इसलिए (p=4)।
Login to save your score, XP, coins and progress. Login
समीकरणों (6x+ay=42) और (18x+33y=126) के अनंत हल होने के लिए (a) का मान क्या होगा?
What is the value of (a) for the equations (6x+ay=42) and (18x+33y=126) to have infinitely many solutions?
#linear equations
#expert
#infinite solutions
#parameter
A (9)
B (10)
C (11)
D (12)
Explanation opens after your attempt
Step 1
Concept
For infinitely many solutions, (6/18=a/33=42/126) must hold. Therefore, (a=11) is correct.
Step 2
Why this answer is correct
The correct answer is C. (11). For infinitely many solutions, (6/18=a/33=42/126) must hold. Therefore, (a=11) is correct.
Step 3
Exam Tip
अनंत हल के लिए (6/18=a/33=42/126) होना चाहिए। इसलिए (a=11) सही है।
Login to save your score, XP, coins and progress. Login
समीकरणों (5x+9y=64) और (15x+27y=t) के असंगत होने के लिए (t) के लिए सही शर्त क्या है?
What is the correct condition on (t) for the equations (5x+9y=64) and (15x+27y=t) to be inconsistent?
#linear equations
#expert
#inconsistent
#parameter
A (t=192)
B \(t\ne192\)
C (t=64)
D (t=128)
Explanation opens after your attempt
Correct Answer
B. \(t\ne192\)
Step 1
Concept
The first two ratios are equal. For inconsistency, the constant ratio must be different so \(t\ne192\).
Step 2
Why this answer is correct
The correct answer is B. \(t\ne192\). The first two ratios are equal. For inconsistency, the constant ratio must be different so \(t\ne192\).
Step 3
Exam Tip
पहले दो अनुपात बराबर हैं। असंगत होने के लिए स्थिर पद का अनुपात अलग होना चाहिए इसलिए \(t\ne192\)।
Login to save your score, XP, coins and progress. Login
यदि (lx+17y=68) और (20x+34y=139) का कोई हल नहीं है, तो (l) का मान क्या होगा?
If (lx+17y=68) and (20x+34y=139) have no solution, what will be the value of (l)?
#linear equations
#expert
#parameter
#parallel lines
A (8)
B (9)
C (10)
D (11)
Explanation opens after your attempt
Step 1
Concept
For no solution, (l/20=17/34) and (68/139) must be different. Hence, (l=10).
Step 2
Why this answer is correct
The correct answer is C. (10). For no solution, (l/20=17/34) and (68/139) must be different. Hence, (l=10).
Step 3
Exam Tip
कोई हल नहीं के लिए (l/20=17/34) और (68/139) अलग होना चाहिए। इसलिए (l=10)।
Login to save your score, XP, coins and progress. Login
समीकरणों (12x+ky=132) और (3x+10y=33) के अनंत हल होने के लिए (k) क्या होगा?
What will (k) be for the equations (12x+ky=132) and (3x+10y=33) to have infinitely many solutions?
#linear equations
#expert
#infinite solutions
#parameter
A (38)
B (39)
C (40)
D (41)
Explanation opens after your attempt
Step 1
Concept
The first equation must be (4) times the second. Therefore, (k=40).
Step 2
Why this answer is correct
The correct answer is C. (40). The first equation must be (4) times the second. Therefore, (k=40).
Step 3
Exam Tip
पहला समीकरण दूसरे का (4) गुना होना चाहिए। इसलिए (k=40) है।
Login to save your score, XP, coins and progress. Login
समीकरणों (10x+9y=38) और (20x+ay=91) का कोई हल न होने के लिए (a) क्या होगा?
What will (a) be for the equations (10x+9y=38) and (20x+ay=91) to have no solution?
#linear equations
#expert
#no solution
#parameter
A (16)
B (17)
C (18)
D (19)
Explanation opens after your attempt
Step 1
Concept
For no solution, (10/20=9/a) and (38/91) must be different. This gives (a=18).
Step 2
Why this answer is correct
The correct answer is C. (18). For no solution, (10/20=9/a) and (38/91) must be different. This gives (a=18).
Step 3
Exam Tip
कोई हल नहीं के लिए (10/20=9/a) और (38/91) अलग होना चाहिए। इससे (a=18) मिलता है।
Login to save your score, XP, coins and progress. Login
समीकरणों (13x+8y=49) और (26x+16y=r) के असंगत होने के लिए कौन-सी शर्त सही है?
Which condition is correct for the equations (13x+8y=49) and (26x+16y=r) to be inconsistent?
#linear equations
#expert
#inconsistent
#parameter
A (r=98)
B \(r\ne98\)
C (r=49)
D (r=100)
Explanation opens after your attempt
Correct Answer
B. \(r\ne98\)
Step 1
Concept
The first two ratios are equal. For inconsistency, the constant ratio must be different so \(r\ne98\).
Step 2
Why this answer is correct
The correct answer is B. \(r\ne98\). The first two ratios are equal. For inconsistency, the constant ratio must be different so \(r\ne98\).
Step 3
Exam Tip
पहले दो अनुपात बराबर हैं। असंगत होने के लिए स्थिर पद का अनुपात अलग होना चाहिए इसलिए \(r\ne98\)।
Login to save your score, XP, coins and progress. Login
समीकरणों (9x+16y=77) और (27x+48y=s) के संगत और आश्रित होने के लिए (s) क्या होगा?
What should (s) be for the equations (9x+16y=77) and (27x+48y=s) to be consistent and dependent?
#linear equations
#expert
#consistent dependent
#parameter
A (229)
B (230)
C (231)
D (232)
Explanation opens after your attempt
Step 1
Concept
To be consistent and dependent, the second equation must be (3) times the first. Hence, (s=231).
Step 2
Why this answer is correct
The correct answer is C. (231). To be consistent and dependent, the second equation must be (3) times the first. Hence, (s=231).
Step 3
Exam Tip
संगत और आश्रित होने के लिए दूसरा समीकरण पहले का (3) गुना होना चाहिए। अतः (s=231)।
Login to save your score, XP, coins and progress. Login
यदि (16x-8y=64) और (2x-y=t) असंगत हैं, तो (t) के लिए सही शर्त क्या है?
If (16x-8y=64) and (2x-y=t) are inconsistent, what is the correct condition for (t)?
#linear equations
#expert
#inconsistent
#parameter
A (t=8)
B \(t\ne8\)
C (t=64)
D (t=16)
Explanation opens after your attempt
Correct Answer
B. \(t\ne8\)
Step 1
Concept
The first two ratios are equal. For inconsistency, (64/t) must be different so \(t\ne8\).
Step 2
Why this answer is correct
The correct answer is B. \(t\ne8\). The first two ratios are equal. For inconsistency, (64/t) must be different so \(t\ne8\).
Step 3
Exam Tip
पहले दो अनुपात बराबर हैं। असंगत होने के लिए (64/t) अलग होना चाहिए इसलिए \(t\ne8\)।
Login to save your score, XP, coins and progress. Login
यदि (11x+7y=59) और (33x+21y=n) के अनंत हल हैं, तो (n) कितना होगा?
If (11x+7y=59) and (33x+21y=n) have infinitely many solutions, what is (n)?
#linear equations
#expert
#parameter
#infinite solutions
A (175)
B (176)
C (177)
D (178)
Explanation opens after your attempt
Step 1
Concept
The second equation must be (3) times the first. Therefore, (n=177).
Step 2
Why this answer is correct
The correct answer is C. (177). The second equation must be (3) times the first. Therefore, (n=177).
Step 3
Exam Tip
दूसरा समीकरण पहले का (3) गुना होना चाहिए। इसलिए (n=177) होगा।
Login to save your score, XP, coins and progress. Login
समीकरणों (17x+py=51) और (8x+3y=25) का अद्वितीय हल होने के लिए कौन-सी शर्त सही है?
Which condition is correct for the equations (17x+py=51) and (8x+3y=25) to have a unique solution?
#linear equations
#expert
#unique solution
#parameter
A (p=51 / 8)
B (p\ne51 / 8)
C (p=3)
D (p=17)
Explanation opens after your attempt
Correct Answer
B. (p\ne51 / 8)
Step 1
Concept
For a unique solution, \(17/8 \ne p/3\) must hold. Therefore, \(p\ne51/8\) is the correct condition.
Step 2
Why this answer is correct
The correct answer is B. \(p\ne51 / 8\). For a unique solution, \(17/8 \ne p/3\) must hold. Therefore, \(p\ne51/8\) is the correct condition.
Step 3
Exam Tip
अद्वितीय हल के लिए \(17/8 \ne p/3\) होना चाहिए। इसलिए \(p\ne51/8\) सही शर्त है।
Login to save your score, XP, coins and progress. Login
समीकरणों (7x+dy=63) और (28x+36y=252) के अनंत हल होने के लिए (d) का मान क्या है?
What is the value of (d) for the equations (7x+dy=63) and (28x+36y=252) to have infinitely many solutions?
#linear equations
#expert
#parameter
#dependent pair
A (7)
B (8)
C (9)
D (10)
Explanation opens after your attempt
Step 1
Concept
For infinitely many solutions, (7/28=d/36=63/252) must hold. Therefore, (d=9).
Step 2
Why this answer is correct
The correct answer is C. (9). For infinitely many solutions, (7/28=d/36=63/252) must hold. Therefore, (d=9).
Step 3
Exam Tip
अनंत हल के लिए (7/28=d/36=63/252) होना चाहिए। इसलिए (d=9)।
Login to save your score, XP, coins and progress. Login
यदि (cx+18y=72) और (24x+48y=145) का कोई हल नहीं है, तो (c) क्या होगा?
If (cx+18y=72) and (24x+48y=145) have no solution, what will (c) be?
#linear equations
#expert
#parameter
#no solution
A (7)
B (8)
C (9)
D (10)
Explanation opens after your attempt
Step 1
Concept
For no solution, (c/24=18/48) and (72/145) must be different. Therefore, (c=9).
Step 2
Why this answer is correct
The correct answer is C. (9). For no solution, (c/24=18/48) and (72/145) must be different. Therefore, (c=9).
Step 3
Exam Tip
कोई हल नहीं के लिए (c/24=18/48) और (72/145) अलग होना चाहिए। इसलिए (c=9)।
Login to save your score, XP, coins and progress. Login
समीकरणों (bx+16y=64) और (14x+28y=131) का कोई हल न होने के लिए (b) का मान क्या होगा?
What is the value of (b) for the equations (bx+16y=64) and (14x+28y=131) to have no solution?
#linear equations
#expert
#no solution
#parameter
A (6)
B (7)
C (8)
D (9)
Explanation opens after your attempt
Step 1
Concept
For no solution, (b/14=16/28) and (64/131) must be different. Hence, (b=8).
Step 2
Why this answer is correct
The correct answer is C. (8). For no solution, (b/14=16/28) and (64/131) must be different. Hence, (b=8).
Step 3
Exam Tip
कोई हल नहीं के लिए (b/14=16/28) और (64/131) अलग होना चाहिए। इसलिए (b=8)।
Login to save your score, XP, coins and progress. Login
समीकरणों (8x+ay=72) और (24x+30y=216) के अनंत हल होने के लिए (a) क्या होगा?
What will (a) be for the equations (8x+ay=72) and (24x+30y=216) to have infinitely many solutions?
#linear equations
#expert
#ratio condition
#parameter
A (8)
B (9)
C (10)
D (11)
Explanation opens after your attempt
Step 1
Concept
For infinitely many solutions, (8/24=a/30=72/216) must hold. This gives (a=10).
Step 2
Why this answer is correct
The correct answer is C. (10). For infinitely many solutions, (8/24=a/30=72/216) must hold. This gives (a=10).
Step 3
Exam Tip
अनंत हल के लिए (8/24=a/30=72/216) होना चाहिए। इससे (a=10) मिलता है।
Login to save your score, XP, coins and progress. Login
समीकरणों (12x+py=60) और (3x+5y=16) का अद्वितीय हल होने के लिए कौन-सी शर्त सही है?
Which condition is correct for the equations (12x+py=60) and (3x+5y=16) to have a unique solution?
#linear equations
#expert
#unique solution
#parameter
A (p=20)
B \(p\ne20\)
C (p=5)
D (p=12)
Explanation opens after your attempt
Correct Answer
B. \(p\ne20\)
Step 1
Concept
For a unique solution, \(12/3 \ne p/5\) must hold. Therefore, \(p\ne20\) is the correct condition.
Step 2
Why this answer is correct
The correct answer is B. \(p\ne20\). For a unique solution, \(12/3 \ne p/5\) must hold. Therefore, \(p\ne20\) is the correct condition.
Step 3
Exam Tip
अद्वितीय हल के लिए \(12/3 \ne p/5\) होना चाहिए। इसलिए \(p\ne20\) सही शर्त है।
Login to save your score, XP, coins and progress. Login
समीकरणों (13x+qy=52) और (26x+18y=104) के अनंत हल होने के लिए (q) का मान क्या है?
What is the value of (q) for the equations (13x+qy=52) and (26x+18y=104) to have infinitely many solutions?
#linear equations
#expert
#dependent pair
#parameter
A (7)
B (8)
C (9)
D (10)
Explanation opens after your attempt
Step 1
Concept
The second equation is (2) times the first, so (q/18=1/2) must hold. Hence, (q=9).
Step 2
Why this answer is correct
The correct answer is C. (9). The second equation is (2) times the first, so (q/18=1/2) must hold. Hence, (q=9).
Step 3
Exam Tip
दूसरा समीकरण पहले का (2) गुना है, इसलिए (q/18=1/2) होना चाहिए। अतः (q=9)।
Login to save your score, XP, coins and progress. Login
समीकरणों (kx+14y=42) और (18x+21y=63) के अनंत हल होने के लिए (k) क्या होगा?
What will (k) be for the equations (kx+14y=42) and (18x+21y=63) to have infinitely many solutions?
#linear equations
#expert
#parameter
#infinite solutions
A (10)
B (11)
C (12)
D (13)
Explanation opens after your attempt
Step 1
Concept
For infinitely many solutions, (k/18=14/21=42/63) must hold. Therefore, (k=12) is correct.
Step 2
Why this answer is correct
The correct answer is C. (12). For infinitely many solutions, (k/18=14/21=42/63) must hold. Therefore, (k=12) is correct.
Step 3
Exam Tip
अनंत हल के लिए (k/18=14/21=42/63) होना चाहिए। इसलिए (k=12) सही है।
Login to save your score, XP, coins and progress. Login
समीकरणों (px+9y=45) और (20x+30y=103) का कोई हल न होने के लिए (p) का मान क्या होगा?
What is the value of (p) for the equations (px+9y=45) and (20x+30y=103) to have no solution?
#linear equations
#expert
#no solution
#parameter
A (5)
B (6)
C (7)
D (8)
Explanation opens after your attempt
Step 1
Concept
For no solution, (p/20=9/30) and (45/103) must be different. This gives (p=6).
Step 2
Why this answer is correct
The correct answer is B. (6). For no solution, (p/20=9/30) and (45/103) must be different. This gives (p=6).
Step 3
Exam Tip
कोई हल नहीं के लिए (p/20=9/30) और (45/103) अलग होना चाहिए। इससे (p=6) मिलता है।
Login to save your score, XP, coins and progress. Login
समीकरणों (4x+ay=32) और (12x+21y=96) के अनंत हल होने के लिए (a) का मान क्या होगा?
What is the value of (a) for the equations (4x+ay=32) and (12x+21y=96) to have infinitely many solutions?
#linear equations
#expert
#parameter
#infinite solutions
A (5)
B (6)
C (7)
D (8)
Explanation opens after your attempt
Step 1
Concept
For infinitely many solutions, (4/12=a/21=32/96) must hold. Therefore, (a=7) is correct.
Step 2
Why this answer is correct
The correct answer is C. (7). For infinitely many solutions, (4/12=a/21=32/96) must hold. Therefore, (a=7) is correct.
Step 3
Exam Tip
अनंत हल के लिए (4/12=a/21=32/96) होना चाहिए। इसलिए (a=7) सही है।
Login to save your score, XP, coins and progress. Login
समीकरणों (13x+py=52) और (6x+5y=24) का अद्वितीय हल होने के लिए कौन-सी शर्त सही है?
Which condition is correct for the equations (13x+py=52) and (6x+5y=24) to have a unique solution?
#linear equations
#hard
#unique solution
#parameter
A (p \ne 65 / 6)
B (p=65 / 6)
C (p=5)
D (p=13)
Explanation opens after your attempt
Correct Answer
A. (p \ne 65 / 6)
Step 1
Concept
For a unique solution, \(13/6 \ne p/5\) must hold. Therefore, \(p \ne 65/6\) is the correct condition.
Step 2
Why this answer is correct
The correct answer is A. \(p \ne 65 / 6\). For a unique solution, \(13/6 \ne p/5\) must hold. Therefore, \(p \ne 65/6\) is the correct condition.
Step 3
Exam Tip
अद्वितीय हल के लिए \(13/6 \ne p/5\) होना चाहिए। इसलिए \(p \ne 65/6\) सही शर्त है।
Login to save your score, XP, coins and progress. Login
समीकरणों (bx+9y=36) और (16x+24y=97) का कोई हल न होने के लिए (b) का मान क्या होगा?
What is the value of (b) for the equations (bx+9y=36) and (16x+24y=97) to have no solution?
#linear equations
#hard
#no solution
#parameter
A (3)
B (4)
C (5)
D (6)
Explanation opens after your attempt
Step 1
Concept
For no solution, (b/16=9/24) and (36/97) must be different. Hence, (b=6).
Step 2
Why this answer is correct
The correct answer is D. (6). For no solution, (b/16=9/24) and (36/97) must be different. Hence, (b=6).
Step 3
Exam Tip
कोई हल नहीं के लिए (b/16=9/24) और (36/97) अलग होना चाहिए। इसलिए (b=6)।
Login to save your score, XP, coins and progress. Login
समीकरणों (5x+ay=45) और (20x+28y=180) के अनंत हल होने के लिए (a) का मान क्या होगा?
What is the value of (a) for the equations (5x+ay=45) and (20x+28y=180) to have infinitely many solutions?
#linear equations
#hard
#infinite solutions
#parameter
A (5)
B (6)
C (7)
D (8)
Explanation opens after your attempt
Step 1
Concept
For infinitely many solutions, (5/20=a/28=45/180) must hold. Therefore, (a=7) is correct.
Step 2
Why this answer is correct
The correct answer is C. (7). For infinitely many solutions, (5/20=a/28=45/180) must hold. Therefore, (a=7) is correct.
Step 3
Exam Tip
अनंत हल के लिए (5/20=a/28=45/180) होना चाहिए। इसलिए (a=7) सही है।
Login to save your score, XP, coins and progress. Login
समीकरणों (4x+7y=31) और (12x+21y=t) के असंगत होने के लिए (t) के लिए सही शर्त क्या है?
What is the correct condition on (t) for the equations (4x+7y=31) and (12x+21y=t) to be inconsistent?
#linear equations
#hard
#inconsistent
#parameter
A (t=93)
B \(t \ne 93\)
C (t=31)
D (t=62)
Explanation opens after your attempt
Correct Answer
B. \(t \ne 93\)
Step 1
Concept
The first two ratios are equal. For inconsistency, the constant ratio must be different so \(t \ne 93\).
Step 2
Why this answer is correct
The correct answer is B. \(t \ne 93\). The first two ratios are equal. For inconsistency, the constant ratio must be different so \(t \ne 93\).
Step 3
Exam Tip
पहले दो अनुपात बराबर हैं। असंगत होने के लिए स्थिर पद का अनुपात अलग होना चाहिए इसलिए \(t \ne 93\)।
Login to save your score, XP, coins and progress. Login
यदि (lx+15y=60) और (18x+45y=181) का कोई हल नहीं है, तो (l) का मान क्या होगा?
If (lx+15y=60) and (18x+45y=181) have no solution, what will be the value of (l)?
#linear equations
#hard
#parameter
#parallel lines
A (4)
B (5)
C (6)
D (7)
Explanation opens after your attempt
Step 1
Concept
For no solution, (l/18=15/45) and (60/181) must be different. Hence, (l=6).
Step 2
Why this answer is correct
The correct answer is C. (6). For no solution, (l/18=15/45) and (60/181) must be different. Hence, (l=6).
Step 3
Exam Tip
कोई हल नहीं के लिए (l/18=15/45) और (60/181) अलग होना चाहिए। इसलिए (l=6)।
Login to save your score, XP, coins and progress. Login
समीकरणों (10x+ky=110) और (2x+9y=22) के अनंत हल होने के लिए (k) क्या होगा?
What will (k) be for the equations (10x+ky=110) and (2x+9y=22) to have infinitely many solutions?
#linear equations
#hard
#infinite solutions
#parameter
A (43)
B (44)
C (45)
D (46)
Explanation opens after your attempt
Step 1
Concept
The first equation must be (5) times the second. Therefore, (k=45).
Step 2
Why this answer is correct
The correct answer is C. (45). The first equation must be (5) times the second. Therefore, (k=45).
Step 3
Exam Tip
पहला समीकरण दूसरे का (5) गुना होना चाहिए। इसलिए (k=45) है।
Login to save your score, XP, coins and progress. Login
समीकरणों (8x+7y=34) और (16x+ay=79) का कोई हल न होने के लिए (a) क्या होगा?
What will (a) be for the equations (8x+7y=34) and (16x+ay=79) to have no solution?
#linear equations
#hard
#no solution
#parameter
A (12)
B (13)
C (14)
D (15)
Explanation opens after your attempt
Step 1
Concept
For no solution, (8/16=7/a) and (34/79) must be different. This gives (a=14).
Step 2
Why this answer is correct
The correct answer is C. (14). For no solution, (8/16=7/a) and (34/79) must be different. This gives (a=14).
Step 3
Exam Tip
कोई हल नहीं के लिए (8/16=7/a) और (34/79) अलग होना चाहिए। इससे (a=14) मिलता है।
Login to save your score, XP, coins and progress. Login
समीकरणों (11x+6y=37) और (22x+12y=r) के असंगत होने के लिए कौन-सी शर्त सही है?
Which condition is correct for the equations (11x+6y=37) and (22x+12y=r) to be inconsistent?
#linear equations
#hard
#inconsistent
#parameter
A (r=74)
B \(r \ne 74\)
C (r=37)
D (r=76)
Explanation opens after your attempt
Correct Answer
B. \(r \ne 74\)
Step 1
Concept
The first two ratios are equal. For inconsistency, the constant ratio must be different so \(r \ne 74\).
Step 2
Why this answer is correct
The correct answer is B. \(r \ne 74\). The first two ratios are equal. For inconsistency, the constant ratio must be different so \(r \ne 74\).
Step 3
Exam Tip
पहले दो अनुपात बराबर हैं। असंगत होने के लिए स्थिर पद का अनुपात अलग होना चाहिए इसलिए \(r \ne 74\)।
Login to save your score, XP, coins and progress. Login
समीकरणों (7x+13y=67) और (21x+39y=s) के संगत और आश्रित होने के लिए (s) क्या होगा?
What should (s) be for the equations (7x+13y=67) and (21x+39y=s) to be consistent and dependent?
#linear equations
#hard
#consistent dependent
#parameter
A (199)
B (200)
C (201)
D (202)
Explanation opens after your attempt
Step 1
Concept
To be consistent and dependent, the second equation must be (3) times the first. Hence, (s=201).
Step 2
Why this answer is correct
The correct answer is C. (201). To be consistent and dependent, the second equation must be (3) times the first. Hence, (s=201).
Step 3
Exam Tip
संगत और आश्रित होने के लिए दूसरा समीकरण पहले का (3) गुना होना चाहिए। अतः (s=201)।
Login to save your score, XP, coins and progress. Login
यदि (14x-7y=56) और (2x-y=t) असंगत हैं, तो (t) के लिए सही शर्त क्या है?
If (14x-7y=56) and (2x-y=t) are inconsistent, what is the correct condition for (t)?
#linear equations
#hard
#inconsistent
#parameter
A (t=8)
B \(t \ne 8\)
C (t=56)
D (t=7)
Explanation opens after your attempt
Correct Answer
B. \(t \ne 8\)
Step 1
Concept
The first two ratios are equal. For inconsistency, (56/t) must be different so \(t \ne 8\).
Step 2
Why this answer is correct
The correct answer is B. \(t \ne 8\). The first two ratios are equal. For inconsistency, (56/t) must be different so \(t \ne 8\).
Step 3
Exam Tip
पहले दो अनुपात बराबर हैं। असंगत होने के लिए (56/t) अलग होना चाहिए इसलिए \(t \ne 8\)।
Login to save your score, XP, coins and progress. Login
यदि (9x+5y=47) और (27x+15y=n) के अनंत हल हैं, तो (n) कितना होगा?
If (9x+5y=47) and (27x+15y=n) have infinitely many solutions, what is (n)?
#linear equations
#hard
#parameter
#infinite solutions
A (139)
B (140)
C (141)
D (142)
Explanation opens after your attempt
Step 1
Concept
The second equation must be (3) times the first. Therefore, (n=141).
Step 2
Why this answer is correct
The correct answer is C. (141). The second equation must be (3) times the first. Therefore, (n=141).
Step 3
Exam Tip
दूसरा समीकरण पहले का (3) गुना होना चाहिए। इसलिए (n=141) होगा।
Login to save your score, XP, coins and progress. Login
समीकरणों (15x+py=45) और (7x+2y=24) का अद्वितीय हल होने के लिए कौन-सी शर्त सही है?
Which condition is correct for the equations (15x+py=45) and (7x+2y=24) to have a unique solution?
#linear equations
#hard
#unique solution
#parameter
A (p=30 / 7)
B (p \ne 30 / 7)
C (p=2)
D (p=15)
Explanation opens after your attempt
Correct Answer
B. (p \ne 30 / 7)
Step 1
Concept
For a unique solution, \(15/7 \ne p/2\) must hold. Therefore, \(p \ne 30/7\) is the correct condition.
Step 2
Why this answer is correct
The correct answer is B. \(p \ne 30 / 7\). For a unique solution, \(15/7 \ne p/2\) must hold. Therefore, \(p \ne 30/7\) is the correct condition.
Step 3
Exam Tip
अद्वितीय हल के लिए \(15/7 \ne p/2\) होना चाहिए। इसलिए \(p \ne 30/7\) सही शर्त है।
Login to save your score, XP, coins and progress. Login
समीकरणों (6x+dy=54) और (18x+30y=162) के अनंत हल होने के लिए (d) का मान क्या है?
What is the value of (d) for the equations (6x+dy=54) and (18x+30y=162) to have infinitely many solutions?
#linear equations
#hard
#parameter
#dependent pair
A (8)
B (9)
C (10)
D (11)
Explanation opens after your attempt
Step 1
Concept
For infinitely many solutions, (6/18=d/30=54/162) must hold. Therefore, (d=10).
Step 2
Why this answer is correct
The correct answer is C. (10). For infinitely many solutions, (6/18=d/30=54/162) must hold. Therefore, (d=10).
Step 3
Exam Tip
अनंत हल के लिए (6/18=d/30=54/162) होना चाहिए। इसलिए (d=10)।
Login to save your score, XP, coins and progress. Login
यदि (cx+16y=64) और (21x+42y=130) का कोई हल नहीं है, तो (c) क्या होगा?
If (cx+16y=64) and (21x+42y=130) have no solution, what will (c) be?
#linear equations
#hard
#parameter
#no solution
A (6)
B (7)
C (8)
D (9)
Explanation opens after your attempt
Step 1
Concept
For no solution, (c/21=16/42) and (64/130) must be different. Therefore, (c=8).
Step 2
Why this answer is correct
The correct answer is C. (8). For no solution, (c/21=16/42) and (64/130) must be different. Therefore, (c=8).
Step 3
Exam Tip
कोई हल नहीं के लिए (c/21=16/42) और (64/130) अलग होना चाहिए। इसलिए (c=8)।
Login to save your score, XP, coins and progress. Login
समीकरणों (bx+14y=56) और (12x+28y=115) का कोई हल न होने के लिए (b) का मान क्या होगा?
What is the value of (b) for the equations (bx+14y=56) and (12x+28y=115) to have no solution?
#linear equations
#hard
#no solution
#parameter
A (4)
B (5)
C (6)
D (7)
Explanation opens after your attempt
Step 1
Concept
For no solution, (b/12=14/28) and (56/115) must be different. Hence, (b=6).
Step 2
Why this answer is correct
The correct answer is C. (6). For no solution, (b/12=14/28) and (56/115) must be different. Hence, (b=6).
Step 3
Exam Tip
कोई हल नहीं के लिए (b/12=14/28) और (56/115) अलग होना चाहिए। इसलिए (b=6)।
Login to save your score, XP, coins and progress. Login
समीकरणों (9x+ay=63) और (27x+24y=189) के अनंत हल होने के लिए (a) क्या होगा?
What will (a) be for the equations (9x+ay=63) and (27x+24y=189) to have infinitely many solutions?
#linear equations
#hard
#ratio condition
#parameter
A (6)
B (7)
C (8)
D (9)
Explanation opens after your attempt
Step 1
Concept
For infinitely many solutions, (9/27=a/24=63/189) must hold. This gives (a=8).
Step 2
Why this answer is correct
The correct answer is C. (8). For infinitely many solutions, (9/27=a/24=63/189) must hold. This gives (a=8).
Step 3
Exam Tip
अनंत हल के लिए (9/27=a/24=63/189) होना चाहिए। इससे (a=8) मिलता है।
Login to save your score, XP, coins and progress. Login
समीकरणों (10x+py=50) और (2x+7y=19) का अद्वितीय हल होने के लिए कौन-सी शर्त सही है?
Which condition is correct for the equations (10x+py=50) and (2x+7y=19) to have a unique solution?
#linear equations
#hard
#unique solution
#parameter
A (p=35)
B \(p \ne 35\)
C (p=7)
D (p=10)
Explanation opens after your attempt
Correct Answer
B. \(p \ne 35\)
Step 1
Concept
For a unique solution, \(10/2 \ne p/7\) must hold. Therefore, \(p \ne 35\) is the correct condition.
Step 2
Why this answer is correct
The correct answer is B. \(p \ne 35\). For a unique solution, \(10/2 \ne p/7\) must hold. Therefore, \(p \ne 35\) is the correct condition.
Step 3
Exam Tip
अद्वितीय हल के लिए \(10/2 \ne p/7\) होना चाहिए। इसलिए \(p \ne 35\) सही शर्त है।
Login to save your score, XP, coins and progress. Login
समीकरणों (11x+qy=44) और (22x+18y=88) के अनंत हल होने के लिए (q) का मान क्या है?
What is the value of (q) for the equations (11x+qy=44) and (22x+18y=88) to have infinitely many solutions?
#linear equations
#hard
#dependent pair
#parameter
A (7)
B (8)
C (9)
D (10)
Explanation opens after your attempt
Step 1
Concept
The second equation is (2) times the first so (q/18=1/2) must hold. Hence, (q=9).
Step 2
Why this answer is correct
The correct answer is C. (9). The second equation is (2) times the first so (q/18=1/2) must hold. Hence, (q=9).
Step 3
Exam Tip
दूसरा समीकरण पहले का (2) गुना है इसलिए (q/18=1/2) होना चाहिए। अतः (q=9)।
Login to save your score, XP, coins and progress. Login
समीकरणों (kx+12y=36) और (15x+20y=60) के अनंत हल होने के लिए (k) क्या होगा?
What will (k) be for the equations (kx+12y=36) and (15x+20y=60) to have infinitely many solutions?
#linear equations
#hard
#parameter
#infinite solutions
A (7)
B (8)
C (9)
D (10)
Explanation opens after your attempt
Step 1
Concept
For infinitely many solutions, (k/15=12/20=36/60) must hold. Therefore, (k=9) is correct.
Step 2
Why this answer is correct
The correct answer is C. (9). For infinitely many solutions, (k/15=12/20=36/60) must hold. Therefore, (k=9) is correct.
Step 3
Exam Tip
अनंत हल के लिए (k/15=12/20=36/60) होना चाहिए। इसलिए (k=9) सही है।
Login to save your score, XP, coins and progress. Login
समीकरणों (px+8y=24) और (10x+20y=61) का कोई हल न होने के लिए (p) का मान क्या होगा?
What is the value of (p) for the equations (px+8y=24) and (10x+20y=61) to have no solution?
#linear equations
#hard
#no solution
#parameter
A (2)
B (3)
C (4)
D (5)
Explanation opens after your attempt
Step 1
Concept
For no solution, (p/10=8/20) and (24/61) must be different. This gives (p=4).
Step 2
Why this answer is correct
The correct answer is C. (4). For no solution, (p/10=8/20) and (24/61) must be different. This gives (p=4).
Step 3
Exam Tip
कोई हल नहीं के लिए (p/10=8/20) और (24/61) अलग होना चाहिए। इससे (p=4) मिलता है।
Login to save your score, XP, coins and progress. Login
समीकरणों (5x+2y=18) और (15x+ay=54) के अनंत हल होने के लिए (a) का मान क्या होगा?
What is the value of (a) for the equations (5x+2y=18) and (15x+ay=54) to have infinitely many solutions?
#linear equations
#hard
#parameter
#infinite solutions
A (4)
B (5)
C (6)
D (7)
Explanation opens after your attempt
Step 1
Concept
For infinitely many solutions, (5/15=2/a=18/54) must hold. Therefore, (a=6) is correct.
Step 2
Why this answer is correct
The correct answer is C. (6). For infinitely many solutions, (5/15=2/a=18/54) must hold. Therefore, (a=6) is correct.
Step 3
Exam Tip
अनंत हल के लिए (5/15=2/a=18/54) होना चाहिए। इसलिए (a=6) सही है।
Login to save your score, XP, coins and progress. Login
समीकरणों (10x+3y=44) और (20x+ay=88) के अनंत हल होने के लिए (a) का मान क्या होगा?
What is the value of (a) for the equations (10x+3y=44) and (20x+ay=88) to have infinitely many solutions?
#linear equations
#hard
#infinite solutions
#parameter
A (4)
B (5)
C (7)
D (6)
Explanation opens after your attempt
Step 1
Concept
For infinitely many solutions, (10/20=3/a=44/88) must hold. Therefore, (a=6) is correct.
Step 2
Why this answer is correct
The correct answer is D. (6). For infinitely many solutions, (10/20=3/a=44/88) must hold. Therefore, (a=6) is correct.
Step 3
Exam Tip
अनंत हल के लिए (10/20=3/a=44/88) होना चाहिए। इसलिए (a=6) सही है।
Login to save your score, XP, coins and progress. Login
यदि (lx+13y=52) और (14x+26y=109) का कोई हल नहीं है, तो (l) का मान क्या होगा?
If (lx+13y=52) and (14x+26y=109) have no solution, what will be the value of (l)?
#linear equations
#hard
#parameter
#parallel lines
A (5)
B (6)
C (7)
D (8)
Explanation opens after your attempt
Step 1
Concept
For no solution, (l/14=13/26) and (52/109) must be different. Hence, (l=7).
Step 2
Why this answer is correct
The correct answer is C. (7). For no solution, (l/14=13/26) and (52/109) must be different. Hence, (l=7).
Step 3
Exam Tip
कोई हल नहीं के लिए (l/14=13/26) और (52/109) अलग होना चाहिए। इसलिए (l=7)।
Login to save your score, XP, coins and progress. Login
समीकरणों (9x+ky=81) और (3x+8y=27) के अनंत हल होने के लिए (k) क्या होगा?
What will (k) be for the equations (9x+ky=81) and (3x+8y=27) to have infinitely many solutions?
#linear equations
#hard
#infinite solutions
#parameter
A (20)
B (22)
C (24)
D (26)
Explanation opens after your attempt
Step 1
Concept
The first equation must be (3) times the second. Therefore, (k=24).
Step 2
Why this answer is correct
The correct answer is C. (24). The first equation must be (3) times the second. Therefore, (k=24).
Step 3
Exam Tip
पहला समीकरण दूसरे का (3) गुना होना चाहिए। इसलिए (k=24) है।
Login to save your score, XP, coins and progress. Login
समीकरणों (7x+5y=22) और (14x+ay=51) का कोई हल न होने के लिए (a) क्या होगा?
What will (a) be for the equations (7x+5y=22) and (14x+ay=51) to have no solution?
#linear equations
#hard
#no solution
#parameter
A (8)
B (9)
C (10)
D (11)
Explanation opens after your attempt
Step 1
Concept
For no solution, (7/14=5/a) and (22/51) must be different. This gives (a=10).
Step 2
Why this answer is correct
The correct answer is C. (10). For no solution, (7/14=5/a) and (22/51) must be different. This gives (a=10).
Step 3
Exam Tip
कोई हल नहीं के लिए (7/14=5/a) और (22/51) अलग होना चाहिए। इससे (a=10) मिलता है।
Login to save your score, XP, coins and progress. Login
समीकरणों (9x+4y=31) और (18x+8y=r) के असंगत होने के लिए कौन-सी शर्त सही है?
Which condition is correct for the equations (9x+4y=31) and (18x+8y=r) to be inconsistent?
#linear equations
#hard
#inconsistent
#parameter
A (r=62)
B \(r \ne 62\)
C (r=31)
D (r=64)
Explanation opens after your attempt
Correct Answer
B. \(r \ne 62\)
Step 1
Concept
The first two ratios are equal, so the constant ratio must be different for inconsistency. Hence, \(r \ne 62\).
Step 2
Why this answer is correct
The correct answer is B. \(r \ne 62\). The first two ratios are equal, so the constant ratio must be different for inconsistency. Hence, \(r \ne 62\).
Step 3
Exam Tip
पहले दो अनुपात बराबर हैं, इसलिए असंगत होने के लिए स्थिर पद का अनुपात अलग होना चाहिए। अतः \(r \ne 62\)।
Login to save your score, XP, coins and progress. Login
समीकरणों (6x+11y=53) और (18x+33y=s) के संगत और आश्रित होने के लिए (s) क्या होगा?
What should (s) be for the equations (6x+11y=53) and (18x+33y=s) to be consistent and dependent?
#linear equations
#hard
#consistent dependent
#parameter
A (157)
B (158)
C (159)
D (160)
Explanation opens after your attempt
Step 1
Concept
To be consistent and dependent, the second equation must be (3) times the first. Hence, (s=159).
Step 2
Why this answer is correct
The correct answer is C. (159). To be consistent and dependent, the second equation must be (3) times the first. Hence, (s=159).
Step 3
Exam Tip
संगत और आश्रित होने के लिए दूसरा समीकरण पहले का (3) गुना होना चाहिए। अतः (s=159)।
Login to save your score, XP, coins and progress. Login
यदि (12x-6y=42) और (2x-y=t) असंगत हैं, तो (t) के लिए सही शर्त क्या है?
If (12x-6y=42) and (2x-y=t) are inconsistent, what is the correct condition for (t)?
#linear equations
#hard
#inconsistent
#parameter
A (t=7)
B \(t \ne 7\)
C (t=42)
D (t=6)
Explanation opens after your attempt
Correct Answer
B. \(t \ne 7\)
Step 1
Concept
The first two ratios are equal, so (42/t) must be different for inconsistency. Hence, \(t \ne 7\).
Step 2
Why this answer is correct
The correct answer is B. \(t \ne 7\). The first two ratios are equal, so (42/t) must be different for inconsistency. Hence, \(t \ne 7\).
Step 3
Exam Tip
पहले दो अनुपात बराबर हैं, इसलिए असंगत होने के लिए (42/t) अलग होना चाहिए। अतः \(t \ne 7\)।
Login to save your score, XP, coins and progress. Login
यदि (8x+5y=43) और (24x+15y=n) के अनंत हल हैं, तो (n) कितना होगा?
If (8x+5y=43) and (24x+15y=n) have infinitely many solutions, what is (n)?
#linear equations
#hard
#parameter
#infinite solutions
A (127)
B (128)
C (129)
D (130)
Explanation opens after your attempt
Step 1
Concept
The second equation must be (3) times the first. Therefore, (n=129).
Step 2
Why this answer is correct
The correct answer is C. (129). The second equation must be (3) times the first. Therefore, (n=129).
Step 3
Exam Tip
दूसरा समीकरण पहले का (3) गुना होना चाहिए। इसलिए (n=129) होगा।
Login to save your score, XP, coins and progress. Login
समीकरणों (13x+py=39) और (6x+3y=20) का अद्वितीय हल होने के लिए कौन-सी शर्त सही है?
Which condition is correct for the equations (13x+py=39) and (6x+3y=20) to have a unique solution?
#linear equations
#hard
#unique solution
#parameter
A (p=13 / 2)
B (p \ne 13 / 2)
C (p=3)
D (p=13)
Explanation opens after your attempt
Correct Answer
B. (p \ne 13 / 2)
Step 1
Concept
For a unique solution, \(13/6 \ne p/3\) must hold. Therefore, \(p \ne 13/2\) is the correct condition.
Step 2
Why this answer is correct
The correct answer is B. \(p \ne 13 / 2\). For a unique solution, \(13/6 \ne p/3\) must hold. Therefore, \(p \ne 13/2\) is the correct condition.
Step 3
Exam Tip
अद्वितीय हल के लिए \(13/6 \ne p/3\) होना चाहिए। इसलिए \(p \ne 13/2\) सही शर्त है।
Login to save your score, XP, coins and progress. Login
समीकरणों (5x+dy=40) और (20x+28y=160) के अनंत हल होने के लिए (d) का मान क्या है?
What is the value of (d) for the equations (5x+dy=40) and (20x+28y=160) to have infinitely many solutions?
#linear equations
#hard
#parameter
#dependent pair
A (5)
B (6)
C (7)
D (8)
Explanation opens after your attempt
Step 1
Concept
For infinitely many solutions, (5/20=d/28=40/160) must hold. Therefore, (d=7).
Step 2
Why this answer is correct
The correct answer is C. (7). For infinitely many solutions, (5/20=d/28=40/160) must hold. Therefore, (d=7).
Step 3
Exam Tip
अनंत हल के लिए (5/20=d/28=40/160) होना चाहिए। इसलिए (d=7)।
Login to save your score, XP, coins and progress. Login
यदि (cx+14y=56) और (15x+35y=121) का कोई हल नहीं है, तो (c) क्या होगा?
If (cx+14y=56) and (15x+35y=121) have no solution, what will (c) be?
#linear equations
#hard
#parameter
#no solution
A (4)
B (5)
C (6)
D (7)
Explanation opens after your attempt
Step 1
Concept
For no solution, (c/15=14/35) and (56/121) must be different. Therefore, (c=6).
Step 2
Why this answer is correct
The correct answer is C. (6). For no solution, (c/15=14/35) and (56/121) must be different. Therefore, (c=6).
Step 3
Exam Tip
कोई हल नहीं के लिए (c/15=14/35) और (56/121) अलग होना चाहिए। इसलिए (c=6)।
Login to save your score, XP, coins and progress. Login
समीकरणों (bx+12y=48) और (10x+30y=101) का कोई हल न होने के लिए (b) का मान क्या होगा?
What is the value of (b) for the equations (bx+12y=48) and (10x+30y=101) to have no solution?
#linear equations
#hard
#no solution
#parameter
A (3)
B (4)
C (5)
D (6)
Explanation opens after your attempt
Step 1
Concept
For no solution, (b/10=12/30) and (48/101) must be different. Hence, (b=4).
Step 2
Why this answer is correct
The correct answer is B. (4). For no solution, (b/10=12/30) and (48/101) must be different. Hence, (b=4).
Step 3
Exam Tip
कोई हल नहीं के लिए (b/10=12/30) और (48/101) अलग होना चाहिए। इसलिए (b=4)।
Login to save your score, XP, coins and progress. Login
समीकरणों (7x+ay=49) और (21x+18y=147) के अनंत हल होने के लिए (a) क्या होगा?
What will (a) be for the equations (7x+ay=49) and (21x+18y=147) to have infinitely many solutions?
#linear equations
#hard
#ratio condition
#parameter
A (4)
B (5)
C (6)
D (7)
Explanation opens after your attempt
Step 1
Concept
For infinitely many solutions, (7/21=a/18=49/147) must hold. This gives (a=6).
Step 2
Why this answer is correct
The correct answer is C. (6). For infinitely many solutions, (7/21=a/18=49/147) must hold. This gives (a=6).
Step 3
Exam Tip
अनंत हल के लिए (7/21=a/18=49/147) होना चाहिए। इससे (a=6) मिलता है।
Login to save your score, XP, coins and progress. Login
समीकरणों (8x+py=40) और (2x+3y=11) का अद्वितीय हल होने के लिए कौन-सी शर्त सही है?
Which condition is correct for the equations (8x+py=40) and (2x+3y=11) to have a unique solution?
#linear equations
#hard
#unique solution
#parameter
A (p=12)
B \(p \ne 12\)
C (p=3)
D (p=8)
Explanation opens after your attempt
Correct Answer
B. \(p \ne 12\)
Step 1
Concept
For a unique solution, \(8/2 \ne p/3\) must hold. Therefore, \(p \ne 12\) is the correct condition.
Step 2
Why this answer is correct
The correct answer is B. \(p \ne 12\). For a unique solution, \(8/2 \ne p/3\) must hold. Therefore, \(p \ne 12\) is the correct condition.
Step 3
Exam Tip
अद्वितीय हल के लिए \(8/2 \ne p/3\) होना चाहिए। इसलिए \(p \ne 12\) सही शर्त है।
Login to save your score, XP, coins and progress. Login
समीकरणों (9x+qy=36) और (18x+14y=72) के अनंत हल होने के लिए (q) का मान क्या है?
What is the value of (q) for the equations (9x+qy=36) and (18x+14y=72) to have infinitely many solutions?
#linear equations
#hard
#dependent pair
#parameter
A (5)
B (6)
C (7)
D (8)
Explanation opens after your attempt
Step 1
Concept
The second equation is (2) times the first, so (q/14=1/2) must hold. Hence, (q=7).
Step 2
Why this answer is correct
The correct answer is C. (7). The second equation is (2) times the first, so (q/14=1/2) must hold. Hence, (q=7).
Step 3
Exam Tip
दूसरा समीकरण पहले का (2) गुना है, इसलिए (q/14=1/2) होना चाहिए। अतः (q=7)।
Login to save your score, XP, coins and progress. Login
समीकरणों (kx+10y=30) और (12x+15y=45) के अनंत हल होने के लिए (k) क्या होगा?
What will (k) be for the equations (kx+10y=30) and (12x+15y=45) to have infinitely many solutions?
#linear equations
#hard
#parameter
#infinite solutions
A (7)
B (8)
C (9)
D (10)
Explanation opens after your attempt
Step 1
Concept
For infinitely many solutions, (k/12=10/15=30/45) must hold. Therefore, (k=8) is correct.
Step 2
Why this answer is correct
The correct answer is B. (8). For infinitely many solutions, (k/12=10/15=30/45) must hold. Therefore, (k=8) is correct.
Step 3
Exam Tip
अनंत हल के लिए (k/12=10/15=30/45) होना चाहिए। इसलिए (k=8) सही है।
Login to save your score, XP, coins and progress. Login
समीकरणों (px+6y=18) और (14x+21y=50) का कोई हल न होने के लिए (p) का मान क्या होगा?
What is the value of (p) for the equations (px+6y=18) and (14x+21y=50) to have no solution?
#linear equations
#hard
#no solution
#parameter
A (2)
B (3)
C (4)
D (5)
Explanation opens after your attempt
Step 1
Concept
For no solution, (p/14=6/21) and (18/50) must be different. This gives (p=4).
Step 2
Why this answer is correct
The correct answer is C. (4). For no solution, (p/14=6/21) and (18/50) must be different. This gives (p=4).
Step 3
Exam Tip
कोई हल नहीं के लिए (p/14=6/21) और (18/50) अलग होना चाहिए। इससे (p=4) मिलता है।
Login to save your score, XP, coins and progress. Login
समीकरणों (4x+ay=28) और (12x+15y=84) के अनंत हल होने के लिए (a) का मान क्या होगा?
What is the value of (a) for the equations (4x+ay=28) and (12x+15y=84) to have infinitely many solutions?
#linear equations
#hard
#parameter
#infinite solutions
A (4)
B (5)
C (6)
D (7)
Explanation opens after your attempt
Step 1
Concept
For infinitely many solutions, (4/12=a/15=28/84) must hold. Therefore, (a=5) is correct.
Step 2
Why this answer is correct
The correct answer is B. (5). For infinitely many solutions, (4/12=a/15=28/84) must hold. Therefore, (a=5) is correct.
Step 3
Exam Tip
अनंत हल के लिए (4/12=a/15=28/84) होना चाहिए। इसलिए (a=5) सही है।
Login to save your score, XP, coins and progress. Login
समीकरणों (cx+10y=50) और (9x+15y=80) का कोई हल न होने के लिए (c) का मान क्या होगा?
What is the value of (c) for the equations (cx+10y=50) and (9x+15y=80) to have no solution?
#linear equations
#hard
#no solution
#parameter
A (5)
B (6)
C (7)
D (8)
Explanation opens after your attempt
Step 1
Concept
For no solution, (c/9=10/15) and (50/80) must be different. Therefore, (c=6).
Step 2
Why this answer is correct
The correct answer is B. (6). For no solution, (c/9=10/15) and (50/80) must be different. Therefore, (c=6).
Step 3
Exam Tip
कोई हल नहीं के लिए (c/9=10/15) और (50/80) अलग होना चाहिए। इसलिए (c=6) है।
Login to save your score, XP, coins and progress. Login
समीकरणों (5x+6y=31) और (15x+18y=r) के संगत और आश्रित होने के लिए (r) क्या होगा?
What should (r) be for the equations (5x+6y=31) and (15x+18y=r) to be consistent and dependent?
#linear equations
#hard
#consistent dependent
#parameter
A (90)
B (91)
C (92)
D (93)
Explanation opens after your attempt
Step 1
Concept
To be consistent and dependent, the second equation must be (3) times the first. Hence, (r=93).
Step 2
Why this answer is correct
The correct answer is D. (93). To be consistent and dependent, the second equation must be (3) times the first. Hence, (r=93).
Step 3
Exam Tip
संगत और आश्रित होने के लिए दूसरा समीकरण पहले का (3) गुना होना चाहिए। अतः (r=93)।
Login to save your score, XP, coins and progress. Login
समीकरणों (2x+3y=8) और (5x+ky=19) का अद्वितीय हल होने के लिए कौन-सी शर्त सही है?
Which condition is correct for the equations (2x+3y=8) and (5x+ky=19) to have a unique solution?
#linear equations
#hard
#unique solution
#parameter
A (k=15 / 2)
B (k=3)
C (k=5)
D (k \ne 15 / 2)
Explanation opens after your attempt
Correct Answer
D. (k \ne 15 / 2)
Step 1
Concept
For a unique solution, \(2/5 \ne 3/k\) must hold. Therefore, \(k \ne 15/2\) is the correct condition.
Step 2
Why this answer is correct
The correct answer is D. \(k \ne 15 / 2\). For a unique solution, \(2/5 \ne 3/k\) must hold. Therefore, \(k \ne 15/2\) is the correct condition.
Step 3
Exam Tip
अद्वितीय हल के लिए \(2/5 \ne 3/k\) होना चाहिए। इसलिए \(k \ne 15/2\) सही शर्त है।
Login to save your score, XP, coins and progress. Login
समीकरणों (7x+ay=20) और (14x+10y=47) का कोई हल न होने के लिए (a) क्या होगा?
What will (a) be for the equations (7x+ay=20) and (14x+10y=47) to have no solution?
#linear equations
#hard
#no solution
#parameter
A (5)
B (6)
C (7)
D (8)
Explanation opens after your attempt
Step 1
Concept
For no solution, (7/14=a/10) and (20/47) must be different. Therefore, (a=5).
Step 2
Why this answer is correct
The correct answer is A. (5). For no solution, (7/14=a/10) and (20/47) must be different. Therefore, (a=5).
Step 3
Exam Tip
कोई हल नहीं के लिए (7/14=a/10) और (20/47) अलग होना चाहिए। इसलिए (a=5) है।
Login to save your score, XP, coins and progress. Login
समीकरणों (mx+5y=15) और (18x+15y=45) के अनंत हल होने के लिए (m) का मान क्या होगा?
What will be the value of (m) for the equations (mx+5y=15) and (18x+15y=45) to have infinitely many solutions?
#linear equations
#hard
#infinite solutions
#parameter
A (4)
B (5)
C (6)
D (7)
Explanation opens after your attempt
Step 1
Concept
For infinitely many solutions, (m/18=5/15=15/45) must hold. Therefore, (m=6) is correct.
Step 2
Why this answer is correct
The correct answer is C. (6). For infinitely many solutions, (m/18=5/15=15/45) must hold. Therefore, (m=6) is correct.
Step 3
Exam Tip
अनंत हल के लिए (m/18=5/15=15/45) होना चाहिए। इसलिए (m=6) सही है।
Login to save your score, XP, coins and progress. Login
समीकरणों (4x+9y=26) और (12x+27y=s) के असंगत होने के लिए (s) के लिए सही शर्त क्या है?
What is the correct condition on (s) for the equations (4x+9y=26) and (12x+27y=s) to be inconsistent?
#linear equations
#hard
#inconsistent
#parameter
A (s=78)
B \(s \ne 78\)
C (s=26)
D (s=52)
Explanation opens after your attempt
Correct Answer
B. \(s \ne 78\)
Step 1
Concept
The first two ratios are equal, so the constant ratio must be different for inconsistency. Hence, \(s \ne 78\) is correct.
Step 2
Why this answer is correct
The correct answer is B. \(s \ne 78\). The first two ratios are equal, so the constant ratio must be different for inconsistency. Hence, \(s \ne 78\) is correct.
Step 3
Exam Tip
पहले दो अनुपात बराबर हैं, इसलिए असंगत होने के लिए स्थिर पद का अनुपात अलग होना चाहिए। अतः \(s \ne 78\) सही है।
Login to save your score, XP, coins and progress. Login
