समीकरणों (2x+3y=8) और (5x+ky=19) का अद्वितीय हल होने के लिए कौन-सी शर्त सही है?

Which condition is correct for the equations (2x+3y=8) and (5x+ky=19) to have a unique solution?

Explanation opens after your attempt
Correct Answer

D. (k \ne 152)

Step 1

Concept

For a unique solution, \(2/5 \ne 3/k\) must hold. Therefore, \(k \ne 15/2\) is the correct condition.

Step 2

Why this answer is correct

The correct answer is D. \(k \ne 15 / 2\). For a unique solution, \(2/5 \ne 3/k\) must hold. Therefore, \(k \ne 15/2\) is the correct condition.

Step 3

Exam Tip

अद्वितीय हल के लिए \(2/5 \ne 3/k\) होना चाहिए। इसलिए \(k \ne 15/2\) सही शर्त है।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

समीकरणों (2x+3y=8) और (5x+ky=19) का अद्वितीय हल होने के लिए कौन-सी शर्त सही है? / Which condition is correct for the equations (2x+3y=8) and (5x+ky=19) to have a unique solution?

Correct Answer: D. \(k \ne 15 / 2\). Explanation: अद्वितीय हल के लिए \(2/5 \ne 3/k\) होना चाहिए। इसलिए \(k \ne 15/2\) सही शर्त है। / For a unique solution, \(2/5 \ne 3/k\) must hold. Therefore, \(k \ne 15/2\) is the correct condition.

Which concept should I revise for this Mathematics MCQ?

For a unique solution, \(2/5 \ne 3/k\) must hold. Therefore, \(k \ne 15/2\) is the correct condition.

What exam hint can help solve this Mathematics question?

अद्वितीय हल के लिए \(2/5 \ne 3/k\) होना चाहिए। इसलिए \(k \ne 15/2\) सही शर्त है।