समीकरणों (4x+ay=32) और (12x+21y=96) के अनंत हल होने के लिए (a) का मान क्या होगा?

What is the value of (a) for the equations (4x+ay=32) and (12x+21y=96) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

C. (7)

Step 1

Concept

For infinitely many solutions, (4/12=a/21=32/96) must hold. Therefore, (a=7) is correct.

Step 2

Why this answer is correct

The correct answer is C. (7). For infinitely many solutions, (4/12=a/21=32/96) must hold. Therefore, (a=7) is correct.

Step 3

Exam Tip

अनंत हल के लिए (4/12=a/21=32/96) होना चाहिए। इसलिए (a=7) सही है।

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समीकरणों (4x+ay=32) और (12x+21y=96) के अनंत हल होने के लिए (a) का मान क्या होगा? / What is the value of (a) for the equations (4x+ay=32) and (12x+21y=96) to have infinitely many solutions?

Correct Answer: C. (7). Explanation: अनंत हल के लिए (4/12=a/21=32/96) होना चाहिए। इसलिए (a=7) सही है। / For infinitely many solutions, (4/12=a/21=32/96) must hold. Therefore, (a=7) is correct.

Which concept should I revise for this Mathematics MCQ?

For infinitely many solutions, (4/12=a/21=32/96) must hold. Therefore, (a=7) is correct.

What exam hint can help solve this Mathematics question?

अनंत हल के लिए (4/12=a/21=32/96) होना चाहिए। इसलिए (a=7) सही है।