समीकरणों (kx+10y=30) और (12x+15y=45) के अनंत हल होने के लिए (k) क्या होगा?
What will (k) be for the equations (kx+10y=30) and (12x+15y=45) to have infinitely many solutions?
Explanation opens after your attempt
B. (8)
Concept
For infinitely many solutions, (k/12=10/15=30/45) must hold. Therefore, (k=8) is correct.
Why this answer is correct
The correct answer is B. (8). For infinitely many solutions, (k/12=10/15=30/45) must hold. Therefore, (k=8) is correct.
Exam Tip
अनंत हल के लिए (k/12=10/15=30/45) होना चाहिए। इसलिए (k=8) सही है।
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