समीकरणों (kx+10y=30) और (12x+15y=45) के अनंत हल होने के लिए (k) क्या होगा?

What will (k) be for the equations (kx+10y=30) and (12x+15y=45) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

B. (8)

Step 1

Concept

For infinitely many solutions, (k/12=10/15=30/45) must hold. Therefore, (k=8) is correct.

Step 2

Why this answer is correct

The correct answer is B. (8). For infinitely many solutions, (k/12=10/15=30/45) must hold. Therefore, (k=8) is correct.

Step 3

Exam Tip

अनंत हल के लिए (k/12=10/15=30/45) होना चाहिए। इसलिए (k=8) सही है।

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समीकरणों (kx+10y=30) और (12x+15y=45) के अनंत हल होने के लिए (k) क्या होगा? / What will (k) be for the equations (kx+10y=30) and (12x+15y=45) to have infinitely many solutions?

Correct Answer: B. (8). Explanation: अनंत हल के लिए (k/12=10/15=30/45) होना चाहिए। इसलिए (k=8) सही है। / For infinitely many solutions, (k/12=10/15=30/45) must hold. Therefore, (k=8) is correct.

Which concept should I revise for this Mathematics MCQ?

For infinitely many solutions, (k/12=10/15=30/45) must hold. Therefore, (k=8) is correct.

What exam hint can help solve this Mathematics question?

अनंत हल के लिए (k/12=10/15=30/45) होना चाहिए। इसलिए (k=8) सही है।