समीकरणों (10x+3y=44) और (20x+ay=88) के अनंत हल होने के लिए (a) का मान क्या होगा?

What is the value of (a) for the equations (10x+3y=44) and (20x+ay=88) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

D. (6)

Step 1

Concept

For infinitely many solutions, (10/20=3/a=44/88) must hold. Therefore, (a=6) is correct.

Step 2

Why this answer is correct

The correct answer is D. (6). For infinitely many solutions, (10/20=3/a=44/88) must hold. Therefore, (a=6) is correct.

Step 3

Exam Tip

अनंत हल के लिए (10/20=3/a=44/88) होना चाहिए। इसलिए (a=6) सही है।

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समीकरणों (10x+3y=44) और (20x+ay=88) के अनंत हल होने के लिए (a) का मान क्या होगा? / What is the value of (a) for the equations (10x+3y=44) and (20x+ay=88) to have infinitely many solutions?

Correct Answer: D. (6). Explanation: अनंत हल के लिए (10/20=3/a=44/88) होना चाहिए। इसलिए (a=6) सही है। / For infinitely many solutions, (10/20=3/a=44/88) must hold. Therefore, (a=6) is correct.

Which concept should I revise for this Mathematics MCQ?

For infinitely many solutions, (10/20=3/a=44/88) must hold. Therefore, (a=6) is correct.

What exam hint can help solve this Mathematics question?

अनंत हल के लिए (10/20=3/a=44/88) होना चाहिए। इसलिए (a=6) सही है।