समीकरणों (12x+ky=132) और (3x+10y=33) के अनंत हल होने के लिए (k) क्या होगा?

What will (k) be for the equations (12x+ky=132) and (3x+10y=33) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

C. (40)

Step 1

Concept

The first equation must be (4) times the second. Therefore, (k=40).

Step 2

Why this answer is correct

The correct answer is C. (40). The first equation must be (4) times the second. Therefore, (k=40).

Step 3

Exam Tip

पहला समीकरण दूसरे का (4) गुना होना चाहिए। इसलिए (k=40) है।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

समीकरणों (12x+ky=132) और (3x+10y=33) के अनंत हल होने के लिए (k) क्या होगा? / What will (k) be for the equations (12x+ky=132) and (3x+10y=33) to have infinitely many solutions?

Correct Answer: C. (40). Explanation: पहला समीकरण दूसरे का (4) गुना होना चाहिए। इसलिए (k=40) है। / The first equation must be (4) times the second. Therefore, (k=40).

Which concept should I revise for this Mathematics MCQ?

The first equation must be (4) times the second. Therefore, (k=40).

What exam hint can help solve this Mathematics question?

पहला समीकरण दूसरे का (4) गुना होना चाहिए। इसलिए (k=40) है।