समीकरणों (8x+py=40) और (2x+3y=11) का अद्वितीय हल होने के लिए कौन-सी शर्त सही है?
Which condition is correct for the equations (8x+py=40) and (2x+3y=11) to have a unique solution?
Explanation opens after your attempt
B. \(p \ne 12\)
Concept
For a unique solution, \(8/2 \ne p/3\) must hold. Therefore, \(p \ne 12\) is the correct condition.
Why this answer is correct
The correct answer is B. \(p \ne 12\). For a unique solution, \(8/2 \ne p/3\) must hold. Therefore, \(p \ne 12\) is the correct condition.
Exam Tip
अद्वितीय हल के लिए \(8/2 \ne p/3\) होना चाहिए। इसलिए \(p \ne 12\) सही शर्त है।
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