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100 results found for "solutions" in Class 10.

यदि (3x+ky=21) और (12x+20y=84) अनंत समाधान देते हैं, तो (k) का मान क्या है?

If (3x+ky=21) and (12x+20y=84) give infinitely many solutions, what is the value of (k)?

Explanation opens after your attempt
Correct Answer

C. (5)

Step 1

Concept

The second equation is (4) times the first, so (4k=20) and (k=5). For infinite solutions, the lines must be coincident.

Step 2

Why this answer is correct

The correct answer is C. (5). The second equation is (4) times the first, so (4k=20) and (k=5). For infinite solutions, the lines must be coincident.

Step 3

Exam Tip

दूसरा समीकरण पहले का (4) गुना है, इसलिए (4k=20) और (k=5)। अनंत समाधान के लिए रेखाएं संपाती होनी चाहिए।

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यदि (5x+4y=p) और (15x+12y=96) की रेखाएं अनंत समाधान देती हैं, तो (p) क्या है?

If (5x+4y=p) and (15x+12y=96) give infinitely many solutions, what is (p)?

Explanation opens after your attempt
Correct Answer

C. (32)

Step 1

Concept

For infinitely many solutions, the second equation must be (3) times the first. Therefore (3p=96) and (p=32).

Step 2

Why this answer is correct

The correct answer is C. (32). For infinitely many solutions, the second equation must be (3) times the first. Therefore (3p=96) and (p=32).

Step 3

Exam Tip

अनंत समाधान के लिए दूसरा समीकरण पहले का (3) गुना होना चाहिए। इसलिए (3p=96) और (p=32)।

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यदि (2x+ky=18) और (6x+12y=54) अनंत समाधान देते हैं, तो (k) का मान क्या है?

If (2x+ky=18) and (6x+12y=54) give infinitely many solutions, what is the value of (k)?

Explanation opens after your attempt
Correct Answer

C. (4)

Step 1

Concept

The second equation is (3) times the first, so (3k=12) and (k=4). For infinite solutions, the lines must be coincident.

Step 2

Why this answer is correct

The correct answer is C. (4). The second equation is (3) times the first, so (3k=12) and (k=4). For infinite solutions, the lines must be coincident.

Step 3

Exam Tip

दूसरा समीकरण पहले का (3) गुना है, इसलिए (3k=12) और (k=4)। अनंत समाधान के लिए रेखाएं संपाती होनी चाहिए।

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यदि (4x+3y=p) और (8x+6y=42) की रेखाएं अनंत समाधान देती हैं, तो (p) क्या है?

If (4x+3y=p) and (8x+6y=42) give infinitely many solutions, what is (p)?

Explanation opens after your attempt
Correct Answer

C. (21)

Step 1

Concept

For infinitely many solutions, the second equation must be (2) times the first. Therefore (2p=42) and (p=21).

Step 2

Why this answer is correct

The correct answer is C. (21). For infinitely many solutions, the second equation must be (2) times the first. Therefore (2p=42) and (p=21).

Step 3

Exam Tip

अनंत समाधान के लिए दूसरा समीकरण पहले का (2) गुना होना चाहिए। इसलिए (2p=42) और (p=21)।

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यदि (x+ky=8) और (2x+6y=16) अनंत समाधान देते हैं, तो (k) का मान क्या है?

If (x+ky=8) and (2x+6y=16) give infinitely many solutions, what is the value of (k)?

Explanation opens after your attempt
Correct Answer

B. (3)

Step 1

Concept

The second equation is (2) times the first, so (2k=6) and (k=3). For infinite solutions, the lines must be coincident.

Step 2

Why this answer is correct

The correct answer is B. (3). The second equation is (2) times the first, so (2k=6) and (k=3). For infinite solutions, the lines must be coincident.

Step 3

Exam Tip

दूसरा समीकरण पहले का (2) गुना है, इसलिए (2k=6) और (k=3)। अनंत समाधान के लिए रेखाएं संपाती होनी चाहिए।

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यदि (3x+2y=p) और (6x+4y=20) की रेखाएं अनंत समाधान देती हैं, तो (p) क्या है?

If (3x+2y=p) and (6x+4y=20) give infinitely many solutions, what is (p)?

Explanation opens after your attempt
Correct Answer

B. (10)

Step 1

Concept

For infinitely many solutions, the second equation must be (2) times the first. Therefore (2p=20) and (p=10).

Step 2

Why this answer is correct

The correct answer is B. (10). For infinitely many solutions, the second equation must be (2) times the first. Therefore (2p=20) and (p=10).

Step 3

Exam Tip

अनंत समाधान के लिए दूसरा समीकरण पहले का (2) गुना होना चाहिए। इसलिए (2p=20) और (p=10)।

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किस स्थिति में दो रेखाओं का ग्राफ अनंत समाधान दिखाता है?

In which condition does the graph of two lines show infinitely many solutions?

Explanation opens after your attempt
Correct Answer

C. \(\frac{a_1}{a_2}=\frac{b_1}{b_2}=\frac{c_1}{c_2}\)

Step 1

Concept

Infinite solutions occur when both lines are the same line. For this, all three ratios are equal.

Step 2

Why this answer is correct

The correct answer is C. \(\frac{a_1}{a_2}=\frac{b_1}{b_2}=\frac{c_1}{c_2}\). Infinite solutions occur when both lines are the same line. For this, all three ratios are equal.

Step 3

Exam Tip

अनंत समाधान तब होते हैं जब दोनों रेखाएं एक ही रेखा हों। इसके लिए तीनों अनुपात बराबर होते हैं।

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रेखाएं (2x-y=1) और (4x-2y=2) के ग्राफ से कितने समाधान मिलेंगे?

How many solutions will be obtained from the graphs of (2x-y=1) and (4x-2y=2)?

Explanation opens after your attempt
Correct Answer

D. अनंतInfinite

Step 1

Concept

The second equation is (2) times the first, so the lines are coincident. In coincident lines, every point is a solution.

Step 2

Why this answer is correct

The correct answer is D. अनंत / Infinite. The second equation is (2) times the first, so the lines are coincident. In coincident lines, every point is a solution.

Step 3

Exam Tip

दूसरा समीकरण पहले का (2) गुना है, इसलिए रेखाएं संपाती हैं। संपाती रेखाओं में हर बिंदु समाधान होता है।

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रेखाएँ (2x+5y=20) और (4x+10y=40) के लिए हलों की संख्या कितनी है?

How many solutions are there for (2x+5y=20) and (4x+10y=40)?

Explanation opens after your attempt
Correct Answer

C. अनंत हलInfinitely many solutions

Step 1

Concept

The second equation is (2) times the first. Therefore the lines are coincident and have infinitely many common points.

Step 2

Why this answer is correct

The correct answer is C. अनंत हल / Infinitely many solutions. The second equation is (2) times the first. Therefore the lines are coincident and have infinitely many common points.

Step 3

Exam Tip

दूसरा समीकरण पहले का (2) गुना है। इसलिए रेखाएँ संपाती हैं और उनके अनंत सामान्य बिंदु हैं।

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समीकरण (x+3y=9) और (2x+6y=18) के लिए हलों की संख्या कितनी है?

How many solutions are there for (x+3y=9) and (2x+6y=18)?

Explanation opens after your attempt
Correct Answer

C. अनंतInfinitely many

Step 1

Concept

The second equation is (2) times the first. Hence the lines are coincident and have infinitely many common points.

Step 2

Why this answer is correct

The correct answer is C. अनंत / Infinitely many. The second equation is (2) times the first. Hence the lines are coincident and have infinitely many common points.

Step 3

Exam Tip

दूसरा समीकरण पहले का (2) गुना है। इसलिए दोनों रेखाएँ संपाती हैं और अनंत सामान्य बिंदु हैं।

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ग्राफीय विधि में अनंत हल कब मिलते हैं?

When does graphical method give infinitely many solutions?

Explanation opens after your attempt
Correct Answer

B. जब रेखाएँ एक ही रेखा होंWhen lines are the same line

Step 1

Concept

All points on the same line satisfy both equations. Therefore, there are infinitely many solutions.

Step 2

Why this answer is correct

The correct answer is B. जब रेखाएँ एक ही रेखा हों / When lines are the same line. All points on the same line satisfy both equations. Therefore, there are infinitely many solutions.

Step 3

Exam Tip

एक ही रेखा के सभी बिंदु दोनों समीकरणों को संतुष्ट करते हैं। इसलिए अनंत हल मिलते हैं।

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यदि ग्राफ पर दोनों रेखाएँ बिल्कुल एक ही रेखा बनती हैं, तो हलों की संख्या क्या होगी?

If both lines on a graph form exactly the same line, how many solutions will there be?

Explanation opens after your attempt
Correct Answer

B. अनंत हलInfinitely many solutions

Step 1

Concept

All points on the same line satisfy both equations. Therefore, there are infinitely many solutions.

Step 2

Why this answer is correct

The correct answer is B. अनंत हल / Infinitely many solutions. All points on the same line satisfy both equations. Therefore, there are infinitely many solutions.

Step 3

Exam Tip

एक ही रेखा के सभी बिंदु दोनों समीकरणों को संतुष्ट करते हैं। इसलिए अनंत हल मिलते हैं।

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किस स्थिति में ग्राफीय विधि से अनंत हल मिलते हैं?

In which situation does graphical method give infinitely many solutions?

Explanation opens after your attempt
Correct Answer

B. जब रेखाएँ एक ही रेखा होंWhen lines are the same line

Step 1

Concept

All points on the same line satisfy both equations. Therefore, there are infinitely many solutions.

Step 2

Why this answer is correct

The correct answer is B. जब रेखाएँ एक ही रेखा हों / When lines are the same line. All points on the same line satisfy both equations. Therefore, there are infinitely many solutions.

Step 3

Exam Tip

एक ही रेखा के सभी बिंदु दोनों समीकरणों को संतुष्ट करते हैं। इसलिए अनंत हल मिलते हैं।

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यदि ग्राफ पर दोनों रेखाएँ पूरी तरह एक ही जगह आती हैं, तो हलों की संख्या क्या होगी?

If both lines appear exactly at the same place on the graph, how many solutions will there be?

Explanation opens after your attempt
Correct Answer

B. अनंत हलInfinitely many solutions

Step 1

Concept

Coincident lines have infinitely many common points. Therefore, such a pair of equations has infinitely many solutions.

Step 2

Why this answer is correct

The correct answer is B. अनंत हल / Infinitely many solutions. Coincident lines have infinitely many common points. Therefore, such a pair of equations has infinitely many solutions.

Step 3

Exam Tip

संपाती रेखाओं के अनंत सामान्य बिंदु होते हैं। इसलिए ऐसे समीकरण युग्म के अनंत हल होते हैं।

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यदि दो रेखाएँ ग्राफ पर एक-दूसरे पर ही स्थित हों, तो हलों की संख्या क्या होगी?

If two lines coincide on the graph, how many solutions will the pair have?

Explanation opens after your attempt
Correct Answer

A. अनंत हलInfinitely many solutions

Step 1

Concept

Every point on coincident lines satisfies both equations. In exams, call this a consistent and dependent case.

Step 2

Why this answer is correct

The correct answer is A. अनंत हल / Infinitely many solutions. Every point on coincident lines satisfies both equations. In exams, call this a consistent and dependent case.

Step 3

Exam Tip

संपाती रेखाओं के सभी बिंदु दोनों समीकरणों को संतुष्ट करते हैं। परीक्षा में इसे संगत और आश्रित स्थिति कहें।

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यदि \(\frac{a_1}{a_2}\ne\frac{b_1}{b_2}\), तो ग्राफीय विधि में हलों की संख्या कितनी होगी?

If \(\frac{a_1}{a_2}\ne\frac{b_1}{b_2}\), how many solutions will there be in graphical method?

Explanation opens after your attempt
Correct Answer

B. ठीक (1) हलExactly (1) solution

Step 1

Concept

Unequal coefficient ratios make the lines intersect at one point. Therefore the pair is consistent and independent.

Step 2

Why this answer is correct

The correct answer is B. ठीक (1) हल / Exactly (1) solution. Unequal coefficient ratios make the lines intersect at one point. Therefore the pair is consistent and independent.

Step 3

Exam Tip

असमान गुणांक अनुपात से रेखाएँ एक बिंदु पर कटती हैं। इसलिए युग्म संगत और स्वतंत्र होता है।

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रेखाएँ (y=3) और (y=11) के लिए हलों की संख्या क्या होगी?

For the lines (y=3) and (y=11), how many solutions will there be?

Explanation opens after your attempt
Correct Answer

B. कोई हल नहींNo solution

Step 1

Concept

Both horizontal lines are at different levels. They are parallel, so there is no common point.

Step 2

Why this answer is correct

The correct answer is B. कोई हल नहीं / No solution. Both horizontal lines are at different levels. They are parallel, so there is no common point.

Step 3

Exam Tip

दोनों क्षैतिज रेखाएँ अलग-अलग स्तरों पर हैं। वे समांतर हैं, इसलिए कोई सामान्य बिंदु नहीं है।

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यदि दो रेखाएँ अलग-अलग समांतर हैं, तो हलों की संख्या क्या होगी?

If two lines are distinct and parallel, how many solutions will there be?

Explanation opens after your attempt
Correct Answer

A. कोई हल नहींNo solution

Step 1

Concept

Distinct parallel lines have no common point. Therefore, such a pair has no solution.

Step 2

Why this answer is correct

The correct answer is A. कोई हल नहीं / No solution. Distinct parallel lines have no common point. Therefore, such a pair has no solution.

Step 3

Exam Tip

अलग-अलग समांतर रेखाओं का कोई सामान्य बिंदु नहीं होता। इसलिए ऐसे युग्म का कोई हल नहीं होता।

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रेखाएँ (y=2) और (y=9) के लिए हलों की संख्या क्या होगी?

For the lines (y=2) and (y=9), how many solutions will there be?

Explanation opens after your attempt
Correct Answer

B. कोई हल नहींNo solution

Step 1

Concept

Both horizontal lines are at different levels. They are parallel, so there is no common point.

Step 2

Why this answer is correct

The correct answer is B. कोई हल नहीं / No solution. Both horizontal lines are at different levels. They are parallel, so there is no common point.

Step 3

Exam Tip

दोनों क्षैतिज रेखाएँ अलग-अलग स्तरों पर हैं। वे समांतर हैं इसलिए कोई सामान्य बिंदु नहीं है।

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यदि ग्राफ पर दो रेखाएँ एक-दूसरे को नहीं काटतीं और अलग-अलग रहती हैं, तो हलों की संख्या क्या होगी?

If two lines on a graph do not cut each other and remain distinct, how many solutions will there be?

Explanation opens after your attempt
Correct Answer

A. कोई हल नहींNo solution

Step 1

Concept

Distinct parallel lines have no common point. Therefore, such a pair has no solution.

Step 2

Why this answer is correct

The correct answer is A. कोई हल नहीं / No solution. Distinct parallel lines have no common point. Therefore, such a pair has no solution.

Step 3

Exam Tip

अलग-अलग समांतर रेखाओं का कोई सामान्य बिंदु नहीं होता। इसलिए ऐसे युग्म का कोई हल नहीं होता।

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यदि दो रेखाएँ ग्राफ पर केवल एक बिंदु पर मिलती हैं, तो हलों की संख्या क्या होगी?

If two lines meet at exactly one point on the graph, how many solutions are there?

Explanation opens after your attempt
Correct Answer

A. (1) अद्वितीय हल(1) unique solution

Step 1

Concept

One intersection point means the equations have exactly one solution. Remember, intersecting lines are consistent and independent.

Step 2

Why this answer is correct

The correct answer is A. (1) अद्वितीय हल / (1) unique solution. One intersection point means the equations have exactly one solution. Remember, intersecting lines are consistent and independent.

Step 3

Exam Tip

एक प्रतिच्छेद बिंदु होने पर समीकरणों का एक ही हल होता है। याद रखें, कटती हुई रेखाएँ संगत और स्वतंत्र होती हैं।

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एक दुकान में दो वस्तुओं के लिए (6x+11y=420) और (18x+33y=1260) समीकरण बनते हैं। हलों की संख्या क्या होगी?

In a shop, the equations for two items are (6x+11y=420) and (18x+33y=1260). How many solutions will there be?

Explanation opens after your attempt
Correct Answer

C. अनंत हलInfinitely many solutions

Step 1

Concept

The second equation is (3) times the first. Therefore, both conditions give the same information and have infinitely many solutions.

Step 2

Why this answer is correct

The correct answer is C. अनंत हल / Infinitely many solutions. The second equation is (3) times the first. Therefore, both conditions give the same information and have infinitely many solutions.

Step 3

Exam Tip

दूसरा समीकरण पहले का (3) गुना है। इसलिए दोनों शर्तें एक ही जानकारी देती हैं और अनंत हल होते हैं।

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यदि (11x+7y=59) और (33x+21y=n) के अनंत हल हैं, तो (n) कितना होगा?

If (11x+7y=59) and (33x+21y=n) have infinitely many solutions, what is (n)?

Explanation opens after your attempt
Correct Answer

C. (177)

Step 1

Concept

The second equation must be (3) times the first. Therefore, (n=177).

Step 2

Why this answer is correct

The correct answer is C. (177). The second equation must be (3) times the first. Therefore, (n=177).

Step 3

Exam Tip

दूसरा समीकरण पहले का (3) गुना होना चाहिए। इसलिए (n=177) होगा।

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समीकरणों (10x+ky=110) और (2x+9y=22) के अनंत हल होने के लिए (k) क्या होगा?

What will (k) be for the equations (10x+ky=110) and (2x+9y=22) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

C. (45)

Step 1

Concept

The first equation must be (5) times the second. Therefore, (k=45).

Step 2

Why this answer is correct

The correct answer is C. (45). The first equation must be (5) times the second. Therefore, (k=45).

Step 3

Exam Tip

पहला समीकरण दूसरे का (5) गुना होना चाहिए। इसलिए (k=45) है।

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एक दुकान में दो वस्तुओं के लिए (5x+9y=300) और (15x+27y=900) समीकरण बनते हैं। हलों की संख्या क्या होगी?

In a shop, the equations for two items are (5x+9y=300) and (15x+27y=900). How many solutions will there be?

Explanation opens after your attempt
Correct Answer

C. अनंत हलInfinitely many solutions

Step 1

Concept

The second equation is (3) times the first. Therefore, both conditions give the same information and have infinitely many solutions.

Step 2

Why this answer is correct

The correct answer is C. अनंत हल / Infinitely many solutions. The second equation is (3) times the first. Therefore, both conditions give the same information and have infinitely many solutions.

Step 3

Exam Tip

दूसरा समीकरण पहले का (3) गुना है। इसलिए दोनों शर्तें एक ही जानकारी देती हैं और अनंत हल होते हैं।

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यदि (9x+5y=47) और (27x+15y=n) के अनंत हल हैं, तो (n) कितना होगा?

If (9x+5y=47) and (27x+15y=n) have infinitely many solutions, what is (n)?

Explanation opens after your attempt
Correct Answer

C. (141)

Step 1

Concept

The second equation must be (3) times the first. Therefore, (n=141).

Step 2

Why this answer is correct

The correct answer is C. (141). The second equation must be (3) times the first. Therefore, (n=141).

Step 3

Exam Tip

दूसरा समीकरण पहले का (3) गुना होना चाहिए। इसलिए (n=141) होगा।

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समीकरणों (9x+ky=81) और (3x+8y=27) के अनंत हल होने के लिए (k) क्या होगा?

What will (k) be for the equations (9x+ky=81) and (3x+8y=27) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

C. (24)

Step 1

Concept

The first equation must be (3) times the second. Therefore, (k=24).

Step 2

Why this answer is correct

The correct answer is C. (24). The first equation must be (3) times the second. Therefore, (k=24).

Step 3

Exam Tip

पहला समीकरण दूसरे का (3) गुना होना चाहिए। इसलिए (k=24) है।

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एक दुकान में दो वस्तुओं के लिए (4x+7y=210) और (12x+21y=630) समीकरण बनते हैं। हलों की संख्या क्या होगी?

In a shop, the equations for two items are (4x+7y=210) and (12x+21y=630). How many solutions will there be?

Explanation opens after your attempt
Correct Answer

C. अनंत हलInfinitely many solutions

Step 1

Concept

The second equation is (3) times the first. Therefore, both conditions give the same information and have infinitely many solutions.

Step 2

Why this answer is correct

The correct answer is C. अनंत हल / Infinitely many solutions. The second equation is (3) times the first. Therefore, both conditions give the same information and have infinitely many solutions.

Step 3

Exam Tip

दूसरा समीकरण पहले का (3) गुना है। इसलिए दोनों शर्तें एक ही जानकारी देती हैं और अनंत हल होते हैं।

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यदि (8x+5y=43) और (24x+15y=n) के अनंत हल हैं, तो (n) कितना होगा?

If (8x+5y=43) and (24x+15y=n) have infinitely many solutions, what is (n)?

Explanation opens after your attempt
Correct Answer

C. (129)

Step 1

Concept

The second equation must be (3) times the first. Therefore, (n=129).

Step 2

Why this answer is correct

The correct answer is C. (129). The second equation must be (3) times the first. Therefore, (n=129).

Step 3

Exam Tip

दूसरा समीकरण पहले का (3) गुना होना चाहिए। इसलिए (n=129) होगा।

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यदि दो रेखाओं की ढाल समान और (y)-अवरोध भी समान हो, तो युग्म के हल कैसे होंगे?

If two lines have the same slope and the same (y)-intercept, what will be the solutions of the pair?

Explanation opens after your attempt
Correct Answer

C. अनंत हलInfinitely many solutions

Step 1

Concept

Same slope and same intercept mean both lines are identical. Therefore, the pair has infinitely many solutions.

Step 2

Why this answer is correct

The correct answer is C. अनंत हल / Infinitely many solutions. Same slope and same intercept mean both lines are identical. Therefore, the pair has infinitely many solutions.

Step 3

Exam Tip

समान ढाल और समान अवरोध का अर्थ है कि दोनों रेखाएं एक ही हैं। इसलिए युग्म के अनंत हल होते हैं।

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समीकरणों (8x+ky=72) और (2x+7y=18) के अनंत हल होने के लिए (k) क्या होगा?

What will (k) be for the equations (8x+ky=72) and (2x+7y=18) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

C. (28)

Step 1

Concept

The first equation must be (4) times the second. Therefore, (k=28).

Step 2

Why this answer is correct

The correct answer is C. (28). The first equation must be (4) times the second. Therefore, (k=28).

Step 3

Exam Tip

पहला समीकरण दूसरे का (4) गुना होना चाहिए। इसलिए (k=28) है।

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समीकरणों (px+6y=18) और (10x+15y=45) के अनंत हल होने के लिए (p) क्या होगा?

What will (p) be for the equations (px+6y=18) and (10x+15y=45) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

B. (3)

Step 1

Concept

For infinitely many solutions, (p/10=6/15=18/45) must hold. Since the common ratio is (2/5), (p=4) would be required.

Step 2

Why this answer is correct

The correct answer is B. (3). For infinitely many solutions, (p/10=6/15=18/45) must hold. Since the common ratio is (2/5), (p=4) would be required.

Step 3

Exam Tip

अनंत हल के लिए (p/10=6/15=18/45) होना चाहिए। इसलिए (p=4) नहीं, (p=4) नहीं बल्कि (p=4) अनुपात बिगाड़ता है और सही (p=4) नहीं है।

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समीकरण (4x+ay=36) और (12x+21y=108) के अनंत हल होने के लिए (a) का मान क्या होगा?

What will be the value of (a) for (4x+ay=36) and (12x+21y=108) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

C. (7)

Step 1

Concept

For infinitely many solutions (4/12=a/21=36/108) must hold. Therefore (a=7).

Step 2

Why this answer is correct

The correct answer is C. (7). For infinitely many solutions (4/12=a/21=36/108) must hold. Therefore (a=7).

Step 3

Exam Tip

अनंत हल के लिए (4/12=a/21=36/108) होना चाहिए। इसलिए (a=7) मिलता है।

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समीकरण (8x+ky=72) और (2x+7y=18) के अनंत हल होने के लिए (k) क्या होगा?

What will (k) be for (8x+ky=72) and (2x+7y=18) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

C. (28)

Step 1

Concept

The first equation must be (4) times the second. Therefore (k=28).

Step 2

Why this answer is correct

The correct answer is C. (28). The first equation must be (4) times the second. Therefore (k=28).

Step 3

Exam Tip

पहला समीकरण दूसरे का (4) गुना होना चाहिए। इसलिए (k=28) है।

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एक दुकान में दो वस्तुओं के लिए (3x+4y=150) और (9x+12y=450) समीकरण बनते हैं। हलों की संख्या क्या होगी?

In a shop the equations for two items are (3x+4y=150) and (9x+12y=450). How many solutions will there be?

Explanation opens after your attempt
Correct Answer

C. अनंत हलInfinitely many solutions

Step 1

Concept

The second equation is (3) times the first. Therefore both conditions give the same information and have infinitely many solutions.

Step 2

Why this answer is correct

The correct answer is C. अनंत हल / Infinitely many solutions. The second equation is (3) times the first. Therefore both conditions give the same information and have infinitely many solutions.

Step 3

Exam Tip

दूसरा समीकरण पहले का (3) गुना है। इसलिए दोनों शर्तें एक ही जानकारी देती हैं और अनंत हल होते हैं।

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यदि (7x+4y=37) और (21x+12y=n) के अनंत हल हैं तो (n) कितना होगा?

If (7x+4y=37) and (21x+12y=n) have infinitely many solutions then what is (n)?

Explanation opens after your attempt
Correct Answer

C. (111)

Step 1

Concept

The second equation must be (3) times the first. Therefore (n=111).

Step 2

Why this answer is correct

The correct answer is C. (111). The second equation must be (3) times the first. Therefore (n=111).

Step 3

Exam Tip

दूसरा समीकरण पहले का (3) गुना होना चाहिए। इसलिए (n=111) होगा।

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समीकरण (px+6y=18) और (10x+15y=45) के अनंत हल होने के लिए (p) का मान क्या होगा?

What is the value of (p) for (px+6y=18) and (10x+15y=45) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

B. (3)

Step 1

Concept

For infinitely many solutions (p/10=6/15=18/45) must hold. Therefore (p=3).

Step 2

Why this answer is correct

The correct answer is B. (3). For infinitely many solutions (p/10=6/15=18/45) must hold. Therefore (p=3).

Step 3

Exam Tip

अनंत हल के लिए (p/10=6/15=18/45) होना चाहिए। इसलिए (p=3)।

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समीकरण (2x+5y=16) और (6x+15y=k) के अनंत हल होने के लिए (k) का मान क्या होगा?

What is the value of (k) for (2x+5y=16) and (6x+15y=k) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

B. (48)

Step 1

Concept

The second equation must be (3) times the first so (k=48). For infinitely many solutions all ratios must be equal.

Step 2

Why this answer is correct

The correct answer is B. (48). The second equation must be (3) times the first so (k=48). For infinitely many solutions all ratios must be equal.

Step 3

Exam Tip

दूसरा समीकरण पहले का (3) गुना होना चाहिए इसलिए (k=48)। अनंत हल के लिए सभी अनुपात बराबर होने चाहिए।

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समीकरण (3x+my=24) और (12x+28y=96) के अनंत हल होने के लिए (m) का मान क्या होगा?

What will be the value of (m) for (3x+my=24) and (12x+28y=96) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

C. (7)

Step 1

Concept

For infinitely many solutions, (3/12=m/28=24/96) must hold. Therefore, (m=7) is correct.

Step 2

Why this answer is correct

The correct answer is C. (7). For infinitely many solutions, (3/12=m/28=24/96) must hold. Therefore, (m=7) is correct.

Step 3

Exam Tip

अनंत हल के लिए (3/12=m/28=24/96) होना चाहिए। इसलिए (m=7) सही है।

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समीकरण (6x+ky=42) और (2x+5y=14) के अनंत हल होने के लिए (k) क्या होगा?

What will (k) be for (6x+ky=42) and (2x+5y=14) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

B. (15)

Step 1

Concept

The first equation must be (3) times the second. Therefore, (k=15).

Step 2

Why this answer is correct

The correct answer is B. (15). The first equation must be (3) times the second. Therefore, (k=15).

Step 3

Exam Tip

पहला समीकरण दूसरे का (3) गुना होना चाहिए। इसलिए (k=15) है।

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एक दुकान में दो वस्तुओं के लिए (2x+3y=90) और (4x+6y=180) समीकरण बनते हैं। हलों की संख्या क्या होगी?

In a shop, the equations for two items are (2x+3y=90) and (4x+6y=180). How many solutions will there be?

Explanation opens after your attempt
Correct Answer

C. अनंत हलInfinitely many solutions

Step 1

Concept

The second equation is (2) times the first. Therefore, both conditions give the same information and have infinitely many solutions.

Step 2

Why this answer is correct

The correct answer is C. अनंत हल / Infinitely many solutions. The second equation is (2) times the first. Therefore, both conditions give the same information and have infinitely many solutions.

Step 3

Exam Tip

दूसरा समीकरण पहले का (2) गुना है। इसलिए दोनों शर्तें एक ही जानकारी देती हैं और अनंत हल होते हैं।

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यदि (6x+5y=31) और (12x+10y=n) के अनंत हल हैं, तो (n) कितना होगा?

If (6x+5y=31) and (12x+10y=n) have infinitely many solutions, what is (n)?

Explanation opens after your attempt
Correct Answer

C. (62)

Step 1

Concept

The second equation must be (2) times the first. Therefore, (n=62).

Step 2

Why this answer is correct

The correct answer is C. (62). The second equation must be (2) times the first. Therefore, (n=62).

Step 3

Exam Tip

दूसरा समीकरण पहले का (2) गुना होना चाहिए। इसलिए (n=62) होगा।

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समीकरण (px+3y=15) और (12x+6y=30) के अनंत हल होने के लिए (p) क्या होगा?

What will (p) be for (px+3y=15) and (12x+6y=30) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

C. (6)

Step 1

Concept

For infinitely many solutions, (p/12=3/6=15/30) must hold. Therefore, (p=6).

Step 2

Why this answer is correct

The correct answer is C. (6). For infinitely many solutions, (p/12=3/6=15/30) must hold. Therefore, (p=6).

Step 3

Exam Tip

अनंत हल के लिए (p/12=3/6=15/30) होना चाहिए। इसलिए (p=6) है।

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समीकरण (5x+4y=18) और (10x+8y=k) के अनंत हल होने के लिए (k) का मान क्या होगा?

What is the value of (k) for (5x+4y=18) and (10x+8y=k) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

B. (36)

Step 1

Concept

The second equation must be (2) times the first, so (k=36). For infinitely many solutions, keep all three ratios equal.

Step 2

Why this answer is correct

The correct answer is B. (36). The second equation must be (2) times the first, so (k=36). For infinitely many solutions, keep all three ratios equal.

Step 3

Exam Tip

दूसरा समीकरण पहले का (2) गुना होना चाहिए, इसलिए (k=36)। अनंत हल के लिए तीनों अनुपात बराबर रखें।

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समीकरण (2x+my=14) और (8x+20y=56) के अनंत हल होने के लिए (m) का मान क्या होगा?

What will be the value of (m) for (2x+my=14) and (8x+20y=56) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

A. (5)

Step 1

Concept

For infinitely many solutions, (2/8=m/20=14/56) must hold. Therefore, (m=5).

Step 2

Why this answer is correct

The correct answer is A. (5). For infinitely many solutions, (2/8=m/20=14/56) must hold. Therefore, (m=5).

Step 3

Exam Tip

अनंत हल के लिए (2/8=m/20=14/56) होना चाहिए। इसलिए (m=5) है।

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समीकरण (5x+ky=25) और (x+3y=5) के अनंत हल होने के लिए (k) क्या होगा?

What will (k) be for (5x+ky=25) and (x+3y=5) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

B. (15)

Step 1

Concept

The first equation must be (5) times the second. Therefore, (k=15).

Step 2

Why this answer is correct

The correct answer is B. (15). The first equation must be (5) times the second. Therefore, (k=15).

Step 3

Exam Tip

पहला समीकरण दूसरे का (5) गुना होना चाहिए। इसलिए (k=15)।

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एक दुकान पर दो वस्तुओं के लिए समीकरण (x+2y=50) और (2x+4y=100) बनते हैं। हलों की संख्या क्या होगी?

For two items in a shop, the equations are (x+2y=50) and (2x+4y=100). How many solutions will there be?

Explanation opens after your attempt
Correct Answer

C. अनंत हलInfinitely many solutions

Step 1

Concept

The second equation is (2) times the first. Therefore, both conditions give the same information and have infinitely many solutions.

Step 2

Why this answer is correct

The correct answer is C. अनंत हल / Infinitely many solutions. The second equation is (2) times the first. Therefore, both conditions give the same information and have infinitely many solutions.

Step 3

Exam Tip

दूसरा समीकरण पहले का (2) गुना है। इसलिए दोनों शर्तें एक ही जानकारी देती हैं और अनंत हल होते हैं।

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यदि (5x+2y=16) और (10x+4y=n) के अनंत हल हैं, तो (n) कितना होगा?

If (5x+2y=16) and (10x+4y=n) have infinitely many solutions, what is (n)?

Explanation opens after your attempt
Correct Answer

D. (32)

Step 1

Concept

The second equation must be (2) times the first. Therefore, (n=32).

Step 2

Why this answer is correct

The correct answer is D. (32). The second equation must be (2) times the first. Therefore, (n=32).

Step 3

Exam Tip

दूसरा समीकरण पहले का (2) गुना होना चाहिए। इसलिए (n=32) होगा।

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समीकरण (px+2y=6) और (9x+6y=18) के अनंत हल होने के लिए (p) का मान क्या है?

What is the value of (p) for (px+2y=6) and (9x+6y=18) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

C. (3)

Step 1

Concept

For infinitely many solutions, (p/9=2/6=6/18), so (p=3). All three ratios must be equal.

Step 2

Why this answer is correct

The correct answer is C. (3). For infinitely many solutions, (p/9=2/6=6/18), so (p=3). All three ratios must be equal.

Step 3

Exam Tip

अनंत हल के लिए (p/9=2/6=6/18), इसलिए (p=3)। तीनों अनुपात बराबर होने चाहिए।

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समीकरण (3x+ay=12) और (6x+8y=24) के अनंत हल होने के लिए (a) का मान क्या है?

What is the value of (a) for (3x+ay=12) and (6x+8y=24) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

B. (4)

Step 1

Concept

For infinitely many solutions, (3/6=a/8=12/24), so (a=4). Match the ratios of coefficients and constants first.

Step 2

Why this answer is correct

The correct answer is B. (4). For infinitely many solutions, (3/6=a/8=12/24), so (a=4). Match the ratios of coefficients and constants first.

Step 3

Exam Tip

अनंत हल के लिए (3/6=a/8=12/24), इसलिए (a=4)। पहले गुणांकों और स्थिर पदों के अनुपात मिलाएं।

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समीकरण (7x+my=28) और (x+2y=4) के अनंत हल के लिए (m) क्या होगा?

What will (m) be for infinitely many solutions of (7x+my=28) and (x+2y=4)?

Explanation opens after your attempt
Correct Answer

C. (14)

Step 1

Concept

The first equation must be (7) times the second. Therefore (m=14).

Step 2

Why this answer is correct

The correct answer is C. (14). The first equation must be (7) times the second. Therefore (m=14).

Step 3

Exam Tip

पहला समीकरण दूसरे का (7) गुना होना चाहिए। इसलिए (m=14) होगा।

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समीकरण (2x+ay=5) और (6x+9y=15) के अनंत हल होने के लिए (a) का मान क्या है?

What is the value of (a) for (2x+ay=5) and (6x+9y=15) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

B. (3)

Step 1

Concept

For infinitely many solutions (2/6=a/9=5/15) must hold. Therefore (a=3).

Step 2

Why this answer is correct

The correct answer is B. (3). For infinitely many solutions (2/6=a/9=5/15) must hold. Therefore (a=3).

Step 3

Exam Tip

अनंत हल के लिए (2/6=a/9=5/15) होना चाहिए। इसलिए (a=3) है।

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ग्राफ में यदि दोनों समीकरण एक ही रेखा दें तो युग्म में कितने हल होंगे?

If both equations give the same line in a graph then how many solutions will the pair have?

Explanation opens after your attempt
Correct Answer

D. अनंत हलInfinitely many solutions

Step 1

Concept

Every point on the same line satisfies both equations. Therefore such a pair has infinitely many solutions.

Step 2

Why this answer is correct

The correct answer is D. अनंत हल / Infinitely many solutions. Every point on the same line satisfies both equations. Therefore such a pair has infinitely many solutions.

Step 3

Exam Tip

एक ही रेखा के हर बिंदु से दोनों समीकरण संतुष्ट होते हैं। इसलिए ऐसे युग्म में अनंत हल होते हैं।

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समीकरण (3x+2y=7) और (6x+4y=14) के लिए हलों की संख्या क्या है?

What is the number of solutions for (3x+2y=7) and (6x+4y=14)?

Explanation opens after your attempt
Correct Answer

C. अनंत हलInfinitely many solutions

Step 1

Concept

The second equation is (2) times the first so the lines are coincident. Coincident lines have infinitely many solutions.

Step 2

Why this answer is correct

The correct answer is C. अनंत हल / Infinitely many solutions. The second equation is (2) times the first so the lines are coincident. Coincident lines have infinitely many solutions.

Step 3

Exam Tip

दूसरा समीकरण पहले का (2) गुना है इसलिए रेखाएं संपाती हैं। संपाती रेखाओं में अनंत हल होते हैं।

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संगत और आश्रित युग्म में हलों की संख्या क्या होती है?

How many solutions are there in a consistent and dependent pair?

Explanation opens after your attempt
Correct Answer

D. अनंत हलInfinitely many solutions

Step 1

Concept

In a consistent and dependent pair both equations represent the same line. Therefore every common point is a solution.

Step 2

Why this answer is correct

The correct answer is D. अनंत हल / Infinitely many solutions. In a consistent and dependent pair both equations represent the same line. Therefore every common point is a solution.

Step 3

Exam Tip

संगत और आश्रित युग्म में दोनों समीकरण एक ही रेखा दर्शाते हैं। इसलिए हर सामान्य बिंदु हल होता है।

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नीचे में से कौन-सा युग्म अनंत हल देता है?

Which of the following pairs gives infinitely many solutions?

Explanation opens after your attempt
Correct Answer

A. (x+y=5) और (2x+2y=10)(x+y=5) and (2x+2y=10)

Step 1

Concept

In the first option the second equation is (2) times the first. Therefore the lines are coincident and have infinitely many solutions.

Step 2

Why this answer is correct

The correct answer is A. (x+y=5) और (2x+2y=10) / (x+y=5) and (2x+2y=10). In the first option the second equation is (2) times the first. Therefore the lines are coincident and have infinitely many solutions.

Step 3

Exam Tip

पहले विकल्प में दूसरा समीकरण पहले का (2) गुना है। इसलिए दोनों रेखाएं संपाती हैं और अनंत हल हैं।

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समीकरण (7x+ay=21) और (x+2y=3) के अनंत हल के लिए (a) क्या होगा?

What will (a) be for infinitely many solutions of (7x+ay=21) and (x+2y=3)?

Explanation opens after your attempt
Correct Answer

C. (14)

Step 1

Concept

The first equation must be (7) times the second so (a=14). Then both equations represent the same line.

Step 2

Why this answer is correct

The correct answer is C. (14). The first equation must be (7) times the second so (a=14). Then both equations represent the same line.

Step 3

Exam Tip

पहला समीकरण दूसरे का (7) गुना होना चाहिए इसलिए (a=14)। इससे दोनों समीकरण एक ही रेखा दर्शाते हैं।

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समीकरण (3x+ky=12) और (6x+8y=24) के अनंत हल के लिए (k) क्या होगा?

What will (k) be for infinitely many solutions of (3x+ky=12) and (6x+8y=24)?

Explanation opens after your attempt
Correct Answer

B. (4)

Step 1

Concept

For infinitely many solutions (3/6=k/8=12/24) must hold. Therefore (k=4).

Step 2

Why this answer is correct

The correct answer is B. (4). For infinitely many solutions (3/6=k/8=12/24) must hold. Therefore (k=4).

Step 3

Exam Tip

अनंत हल के लिए (3/6=k/8=12/24) होना चाहिए। इसलिए (k=4) है।

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समीकरण (2x+ay=7) और (4x+10y=14) के अनंत हल होने के लिए (a) का मान क्या है?

What is the value of (a) for (2x+ay=7) and (4x+10y=14) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

C. (5)

Step 1

Concept

For infinitely many solutions (2/4=a/10=7/14) must hold so (a=5). Making all three ratios equal is necessary.

Step 2

Why this answer is correct

The correct answer is C. (5). For infinitely many solutions (2/4=a/10=7/14) must hold so (a=5). Making all three ratios equal is necessary.

Step 3

Exam Tip

अनंत हल के लिए (2/4=a/10=7/14) होना चाहिए इसलिए (a=5)। तीनों अनुपात बराबर करना जरूरी है।

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यदि दो समीकरणों के अनंत सामान्य हल हैं तो उनका ग्राफ कैसा होगा?

If two equations have infinitely many common solutions then how will their graph be?

Explanation opens after your attempt
Correct Answer

B. एक ही रेखाSame line

Step 1

Concept

Infinitely many common solutions occur only when both equations represent the same line. In exams this can be written as coincident lines.

Step 2

Why this answer is correct

The correct answer is B. एक ही रेखा / Same line. Infinitely many common solutions occur only when both equations represent the same line. In exams this can be written as coincident lines.

Step 3

Exam Tip

अनंत सामान्य हल तभी मिलते हैं जब दोनों समीकरण एक ही रेखा दर्शाते हैं। परीक्षा में इसे coincident lines लिख सकते हैं।

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समीकरण (2x+5y=9) और (4x+10y=18) के लिए हलों की संख्या क्या होगी?

What will be the number of solutions for (2x+5y=9) and (4x+10y=18)?

Explanation opens after your attempt
Correct Answer

C. अनंत हलInfinitely many solutions

Step 1

Concept

The second equation is (2) times the first so both lines are coincident. Coincident lines have infinitely many solutions.

Step 2

Why this answer is correct

The correct answer is C. अनंत हल / Infinitely many solutions. The second equation is (2) times the first so both lines are coincident. Coincident lines have infinitely many solutions.

Step 3

Exam Tip

दूसरा समीकरण पहले का (2) गुना है इसलिए दोनों रेखाएं संपाती हैं। संपाती रेखाओं में अनंत हल होते हैं।

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समीकरण (6x-2y=4) और (3x-y=2) के हलों की संख्या बताइए।

State the number of solutions of (6x-2y=4) and (3x-y=2).

Explanation opens after your attempt
Correct Answer

C. अनंत हलInfinitely many solutions

Step 1

Concept

The first equation is (2) times the second, so both lines are coincident. Coincident lines have infinitely many solutions.

Step 2

Why this answer is correct

The correct answer is C. अनंत हल / Infinitely many solutions. The first equation is (2) times the second, so both lines are coincident. Coincident lines have infinitely many solutions.

Step 3

Exam Tip

पहला समीकरण दूसरे का (2) गुना है, इसलिए दोनों रेखाएं संपाती हैं। संपाती रेखाओं के अनंत हल होते हैं।

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समीकरण (5x+ay=15) और (10x+6y=30) के अनंत हल होने के लिए (a) का मान क्या होगा?

What value of (a) gives infinitely many solutions for (5x+ay=15) and (10x+6y=30)?

Explanation opens after your attempt
Correct Answer

B. (3)

Step 1

Concept

For infinitely many solutions, (5/10=a/6=15/30), so (a=3). All three ratios must be equal.

Step 2

Why this answer is correct

The correct answer is B. (3). For infinitely many solutions, (5/10=a/6=15/30), so (a=3). All three ratios must be equal.

Step 3

Exam Tip

अनंत हल के लिए (5/10=a/6=15/30), इसलिए (a=3)। तीनों अनुपात बराबर होने जरूरी हैं।

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समीकरण (x+ky=2) और (2x+6y=4) के अनंत हल होने के लिए (k) का मान क्या है?

What is the value of (k) for (x+ky=2) and (2x+6y=4) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

B. (3)

Step 1

Concept

For infinitely many solutions, (1/2=k/6=2/4), so (k=3). Keeping ratios equal makes the equations dependent.

Step 2

Why this answer is correct

The correct answer is B. (3). For infinitely many solutions, (1/2=k/6=2/4), so (k=3). Keeping ratios equal makes the equations dependent.

Step 3

Exam Tip

अनंत हल के लिए (1/2=k/6=2/4), इसलिए (k=3)। अनुपात बराबर रखने से equations dependent बनती हैं।

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नीचे में से कौन-सी स्थिति अनंत हल देती है?

Which of the following conditions gives infinitely many solutions?

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Correct Answer

C. (a_1a_2=b_1 / b_2=c_1 / c_2)

Step 1

Concept

For infinitely many solutions, all three ratios must be equal. Then both equations form the same line.

Step 2

Why this answer is correct

The correct answer is C. \(a_1 / a_2=b_1 / b_2=c_1 / c_2\). For infinitely many solutions, all three ratios must be equal. Then both equations form the same line.

Step 3

Exam Tip

अनंत हल के लिए तीनों अनुपात बराबर होने चाहिए। इससे दोनों समीकरण एक ही रेखा बनाते हैं।

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समीकरण (2x+ky=4) और (6x+9y=12) के अनंत हल होने के लिए (k) का मान क्या होगा?

What value of (k) gives infinitely many solutions for (2x+ky=4) and (6x+9y=12)?

Explanation opens after your attempt
Correct Answer

C. (3)

Step 1

Concept

For infinitely many solutions, (2/6=k/9=4/12), so (k=3). Making all three ratios equal is the key method.

Step 2

Why this answer is correct

The correct answer is C. (3). For infinitely many solutions, (2/6=k/9=4/12), so (k=3). Making all three ratios equal is the key method.

Step 3

Exam Tip

अनंत हल के लिए (2/6=k/9=4/12), इसलिए (k=3)। तीनों अनुपात बराबर करना मुख्य तरीका है।

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ग्राफ में यदि दोनों रेखाएं एक ही रेखा बन जाएं, तो हलों की संख्या क्या होगी?

If both lines become the same line in a graph, how many solutions will there be?

Explanation opens after your attempt
Correct Answer

C. अनंत हलInfinitely many solutions

Step 1

Concept

Every point on the same line satisfies both equations. Therefore, such a pair has infinitely many solutions.

Step 2

Why this answer is correct

The correct answer is C. अनंत हल / Infinitely many solutions. Every point on the same line satisfies both equations. Therefore, such a pair has infinitely many solutions.

Step 3

Exam Tip

एक ही रेखा के हर बिंदु से दोनों समीकरण संतुष्ट होते हैं। इसलिए ऐसे युग्म के अनंत हल होते हैं।

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यदि \(a_1/a_2=b_1/b_2=c_1/c_2\) हो, तो समीकरणों के कितने हल होंगे?

If \(a_1/a_2=b_1/b_2=c_1/c_2\), how many solutions will the equations have?

Explanation opens after your attempt
Correct Answer

C. अनंत हलInfinitely many solutions

Step 1

Concept

If all three ratios are equal, the two lines are coincident. Such a pair has infinitely many solutions.

Step 2

Why this answer is correct

The correct answer is C. अनंत हल / Infinitely many solutions. If all three ratios are equal, the two lines are coincident. Such a pair has infinitely many solutions.

Step 3

Exam Tip

तीनों अनुपात बराबर हों तो दोनों रेखाएं संपाती होती हैं। ऐसी स्थिति में अनंत हल होते हैं।

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समीकरणों (4x+7y=31) और (8x+14y=62) के हलों की संख्या क्या है?

What is the number of solutions of (4x+7y=31) and (8x+14y=62)?

Explanation opens after your attempt
Correct Answer

D. अनंत हलInfinitely many solutions

Step 1

Concept

The second equation is (2) times the first. Therefore both are the same line and have infinitely many solutions.

Step 2

Why this answer is correct

The correct answer is D. अनंत हल / Infinitely many solutions. The second equation is (2) times the first. Therefore both are the same line and have infinitely many solutions.

Step 3

Exam Tip

दूसरा समीकरण पहले का (2) गुना है। इसलिए दोनों एक ही रेखा हैं और अनंत हल हैं।

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समीकरणों (ax+9y=27) और (2x+3y=9) के अनंत हल होने के लिए (a) का मान क्या है?

What is the value of (a) for (ax+9y=27) and (2x+3y=9) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

C. (a=6)

Step 1

Concept

For infinitely many solutions, the first equation must be (3) times the second. Therefore (a=6).

Step 2

Why this answer is correct

The correct answer is C. (a=6). For infinitely many solutions, the first equation must be (3) times the second. Therefore (a=6).

Step 3

Exam Tip

अनंत हल के लिए पहला समीकरण दूसरे का (3) गुना होना चाहिए। इसलिए (a=6)।

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समीकरणों (px-10y=30) और (3x-5y=15) के अनंत हल होने के लिए (p) का मान क्या है?

What is the value of (p) for (px-10y=30) and (3x-5y=15) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

C. (p=6)

Step 1

Concept

For infinitely many solutions, the first equation must be (2) times the second. Hence (p=6).

Step 2

Why this answer is correct

The correct answer is C. (p=6). For infinitely many solutions, the first equation must be (2) times the second. Hence (p=6).

Step 3

Exam Tip

अनंत हल के लिए पहला समीकरण दूसरे का (2) गुना होना चाहिए। इसलिए (p=6)।

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समीकरणों (3x+5y=20) और (6x+10y=40) के हलों की संख्या क्या है?

What is the number of solutions of (3x+5y=20) and (6x+10y=40)?

Explanation opens after your attempt
Correct Answer

A. अनंत हलInfinitely many solutions

Step 1

Concept

The second equation is (2) times the first. Therefore both represent the same line and have infinitely many solutions.

Step 2

Why this answer is correct

The correct answer is A. अनंत हल / Infinitely many solutions. The second equation is (2) times the first. Therefore both represent the same line and have infinitely many solutions.

Step 3

Exam Tip

दूसरा समीकरण पहले का (2) गुना है। इसलिए दोनों एक ही रेखा दर्शाते हैं और अनंत हल हैं।

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समीकरणों (ax+6y=14) और (2x+3y=7) के अनंत हल होने के लिए (a) का मान क्या है?

What is the value of (a) for (ax+6y=14) and (2x+3y=7) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

C. (a=4)

Step 1

Concept

For infinitely many solutions, the first equation must be (2) times the second. Therefore (a=4).

Step 2

Why this answer is correct

The correct answer is C. (a=4). For infinitely many solutions, the first equation must be (2) times the second. Therefore (a=4).

Step 3

Exam Tip

अनंत हल के लिए पहला समीकरण दूसरे का (2) गुना होना चाहिए। इसलिए (a=4)।

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समीकरणों (px-8y=24) और (3x-4y=12) के अनंत हल होने के लिए (p) का मान क्या है?

What is the value of (p) for (px-8y=24) and (3x-4y=12) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

C. (p=6)

Step 1

Concept

For infinitely many solutions, the first equation must be (2) times the second. Therefore (p=6).

Step 2

Why this answer is correct

The correct answer is C. (p=6). For infinitely many solutions, the first equation must be (2) times the second. Therefore (p=6).

Step 3

Exam Tip

अनंत हल के लिए पहला समीकरण दूसरे का (2) गुना होना चाहिए। इसलिए (p=6)।

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समीकरणों (4x+6y=30) और (6x+9y=45) के हलों के बारे में सही कथन चुनिए।

Choose the correct statement about the solutions of (4x+6y=30) and (6x+9y=45).

Explanation opens after your attempt
Correct Answer

C. अनंत अनेक हलInfinitely many solutions

Step 1

Concept

The second equation is \(\frac{3}{2}\) times the first, so both represent the same line. In exams, if all ratios are equal, there are infinitely many solutions.

Step 2

Why this answer is correct

The correct answer is C. अनंत अनेक हल / Infinitely many solutions. The second equation is \(\frac{3}{2}\) times the first, so both represent the same line. In exams, if all ratios are equal, there are infinitely many solutions.

Step 3

Exam Tip

दूसरा समीकरण पहले का \(\frac{3}{2}\) गुना है, इसलिए दोनों समान रेखा दर्शाते हैं। परीक्षा में सभी अनुपात बराबर हों तो अनंत हल होते हैं।

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समीकरणों (2x+3y=11) और (4x+6y=22) के हलों की संख्या क्या है?

What is the number of solutions of (2x+3y=11) and (4x+6y=22)?

Explanation opens after your attempt
Correct Answer

A. अनंत हलInfinitely many solutions

Step 1

Concept

The second equation is (2) times the first. Therefore both represent the same line and have infinitely many solutions.

Step 2

Why this answer is correct

The correct answer is A. अनंत हल / Infinitely many solutions. The second equation is (2) times the first. Therefore both represent the same line and have infinitely many solutions.

Step 3

Exam Tip

दूसरा समीकरण पहले का (2) गुना है। इसलिए दोनों एक ही रेखा दर्शाते हैं और अनंत हल हैं।

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समीकरणों (ax+4y=10) और (3x+6y=15) के अनंत हल होने के लिए (a) का मान क्या है?

What is the value of (a) for (ax+4y=10) and (3x+6y=15) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

B. (a=2)

Step 1

Concept

For infinitely many solutions, coefficients and constants must be in the same ratio. Since (4:6=10:15=2:3), (a=2).

Step 2

Why this answer is correct

The correct answer is B. (a=2). For infinitely many solutions, coefficients and constants must be in the same ratio. Since (4:6=10:15=2:3), (a=2).

Step 3

Exam Tip

अनंत हल के लिए गुणांक और स्थिरांक समान अनुपात में होने चाहिए। (4:6=10:15=2:3), इसलिए (a=2)।

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समीकरणों (px-6y=18) और (2x-3y=9) के अनंत हल होने के लिए (p) का मान क्या है?

What is the value of (p) for (px-6y=18) and (2x-3y=9) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

B. (p=4)

Step 1

Concept

For infinitely many solutions, the first equation must be (2) times the second. Hence (p=4).

Step 2

Why this answer is correct

The correct answer is B. (p=4). For infinitely many solutions, the first equation must be (2) times the second. Hence (p=4).

Step 3

Exam Tip

अनंत हल के लिए पहला समीकरण दूसरे का (2) गुना होना चाहिए। इसलिए (p=4)।

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(2x+py=10) और (4x+6y=20) के अनंत हल होने के लिए (p) का मान क्या है?

What is the value of (p) for (2x+py=10) and (4x+6y=20) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

A. (p=3)

Step 1

Concept

Twice the first equation must become the second equation. Hence (2p=6), so (p=3).

Step 2

Why this answer is correct

The correct answer is A. (p=3). Twice the first equation must become the second equation. Hence (2p=6), so (p=3).

Step 3

Exam Tip

पहले समीकरण का (2) गुना दूसरा समीकरण बनना चाहिए। इसलिए (2p=6), अतः (p=3)।

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(ax+4y=12) और (3x+2y=6) के अनंत हल होने के लिए (a) का मान क्या है?

What is the value of (a) for (ax+4y=12) and (3x+2y=6) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

B. (a=6)

Step 1

Concept

For infinitely many solutions, both equations must be proportional. The ratio of (4) and (2) is (2), so (a=6).

Step 2

Why this answer is correct

The correct answer is B. (a=6). For infinitely many solutions, both equations must be proportional. The ratio of (4) and (2) is (2), so (a=6).

Step 3

Exam Tip

अनंत हल के लिए दोनों समीकरण समानुपाती होने चाहिए। (4) और (2) का अनुपात (2) है, इसलिए (a=6) होना चाहिए।

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यदि (7x+3y=42) और (21x+9y=k) की रेखाएं संपाती हों, तो (k) का मान क्या होगा?

If the lines (7x+3y=42) and (21x+9y=k) are coincident, what will be the value of (k)?

Explanation opens after your attempt
Correct Answer

C. (126)

Step 1

Concept

The second equation must be (3) times the first, so (k=126). In coincident lines, the constant term also changes in the same ratio.

Step 2

Why this answer is correct

The correct answer is C. (126). The second equation must be (3) times the first, so (k=126). In coincident lines, the constant term also changes in the same ratio.

Step 3

Exam Tip

दूसरा समीकरण पहले का (3) गुना होना चाहिए, इसलिए (k=126)। संपाती रेखाओं में स्थिर पद भी उसी अनुपात में बदलता है।

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रेखाएं (15x+20y=60) और (3x+4y=12) किस प्रकार की हैं?

What type of lines are (15x+20y=60) and (3x+4y=12)?

Explanation opens after your attempt
Correct Answer

C. संपातीCoincident

Step 1

Concept

The first equation is (5) times the second. Therefore the lines are coincident and give infinitely many solutions.

Step 2

Why this answer is correct

The correct answer is C. संपाती / Coincident. The first equation is (5) times the second. Therefore the lines are coincident and give infinitely many solutions.

Step 3

Exam Tip

पहला समीकरण दूसरे का (5) गुना है। इसलिए दोनों रेखाएं संपाती हैं और अनंत समाधान देती हैं।

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यदि (ax+12y=48) और (5x+3y=12) संपाती रेखाएं हैं, तो (a) का मान क्या है?

If (ax+12y=48) and (5x+3y=12) are coincident lines, what is the value of (a)?

Explanation opens after your attempt
Correct Answer

C. (20)

Step 1

Concept

The first equation must be (4) times the second, so (a=20). In coincident lines, all terms change by the same multiplier.

Step 2

Why this answer is correct

The correct answer is C. (20). The first equation must be (4) times the second, so (a=20). In coincident lines, all terms change by the same multiplier.

Step 3

Exam Tip

पहला समीकरण दूसरे का (4) गुना होना चाहिए, इसलिए (a=20)। संपाती रेखाओं में सभी पद समान गुणक से बदलते हैं।

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यदि \(\frac{a_1}{a_2}=\frac{b_1}{b_2}=\frac{c_1}{c_2}\), तो ग्राफ में रेखाओं की स्थिति क्या होगी?

If \(\frac{a_1}{a_2}=\frac{b_1}{b_2}=\frac{c_1}{c_2}\), what will be the position of the lines on a graph?

Explanation opens after your attempt
Correct Answer

C. संपातीCoincident

Step 1

Concept

If all three ratios are equal, both equations represent the same line. Hence the lines are coincident and give infinitely many solutions.

Step 2

Why this answer is correct

The correct answer is C. संपाती / Coincident. If all three ratios are equal, both equations represent the same line. Hence the lines are coincident and give infinitely many solutions.

Step 3

Exam Tip

तीनों अनुपात बराबर हों तो दोनों समीकरण एक ही रेखा बताते हैं। इसलिए रेखाएं संपाती होती हैं और अनंत समाधान देती हैं।

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रेखाएं (11x-6y=33) और (22x-12y=66) ग्राफ पर क्या दर्शाती हैं?

What do the lines (11x-6y=33) and (22x-12y=66) represent on a graph?

Explanation opens after your attempt
Correct Answer

C. अनंत समाधानInfinitely many solutions

Step 1

Concept

The second equation is (2) times the first, so both lines are the same. All points on the same line are solutions.

Step 2

Why this answer is correct

The correct answer is C. अनंत समाधान / Infinitely many solutions. The second equation is (2) times the first, so both lines are the same. All points on the same line are solutions.

Step 3

Exam Tip

दूसरा समीकरण पहले का (2) गुना है, इसलिए दोनों रेखाएं एक ही हैं। एक ही रेखा के सभी बिंदु समाधान होते हैं।

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यदि (6x+ky=30) और (18x+15y=90) संपाती रेखाएं हों, तो (k) का मान क्या है?

If (6x+ky=30) and (18x+15y=90) are coincident lines, what is the value of (k)?

Explanation opens after your attempt
Correct Answer

C. (5)

Step 1

Concept

The second equation is (3) times the first, so (3k=15) and (k=5). In coincident lines, all terms are in the same ratio.

Step 2

Why this answer is correct

The correct answer is C. (5). The second equation is (3) times the first, so (3k=15) and (k=5). In coincident lines, all terms are in the same ratio.

Step 3

Exam Tip

दूसरा समीकरण पहले का (3) गुना है, इसलिए (3k=15) और (k=5)। संपाती रेखाओं में सभी पद समान अनुपात में होते हैं।

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रेखाएं (12x+15y=30) और (4x+5y=10) किस प्रकार की हैं?

What type of lines are (12x+15y=30) and (4x+5y=10)?

Explanation opens after your attempt
Correct Answer

C. संपातीCoincident

Step 1

Concept

The first equation is (3) times the second. Therefore the lines are coincident and give infinitely many solutions.

Step 2

Why this answer is correct

The correct answer is C. संपाती / Coincident. The first equation is (3) times the second. Therefore the lines are coincident and give infinitely many solutions.

Step 3

Exam Tip

पहला समीकरण दूसरे का (3) गुना है। इसलिए दोनों रेखाएं संपाती हैं और अनंत समाधान देती हैं।

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यदि (ax+9y=27) और (4x+3y=9) संपाती रेखाएं हैं, तो (a) का मान क्या है?

If (ax+9y=27) and (4x+3y=9) are coincident lines, what is the value of (a)?

Explanation opens after your attempt
Correct Answer

C. (12)

Step 1

Concept

The first equation must be (3) times the second, so (a=12). In coincident lines, all terms change by the same multiplier.

Step 2

Why this answer is correct

The correct answer is C. (12). The first equation must be (3) times the second, so (a=12). In coincident lines, all terms change by the same multiplier.

Step 3

Exam Tip

पहला समीकरण दूसरे का (3) गुना होना चाहिए, इसलिए (a=12)। संपाती रेखाओं में सभी पद समान गुणक से बदलते हैं।

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रेखाएं (8x-5y=24) और (16x-10y=48) ग्राफ पर क्या दर्शाती हैं?

What do the lines (8x-5y=24) and (16x-10y=48) represent on a graph?

Explanation opens after your attempt
Correct Answer

C. अनंत समाधानInfinitely many solutions

Step 1

Concept

The second equation is (2) times the first, so both lines are the same. All points on the same line are solutions.

Step 2

Why this answer is correct

The correct answer is C. अनंत समाधान / Infinitely many solutions. The second equation is (2) times the first, so both lines are the same. All points on the same line are solutions.

Step 3

Exam Tip

दूसरा समीकरण पहले का (2) गुना है, इसलिए दोनों रेखाएं एक ही हैं। एक ही रेखा के सभी बिंदु समाधान होते हैं।

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यदि (5x+ky=20) और (15x+6y=60) संपाती रेखाएं हों, तो (k) का मान क्या है?

If (5x+ky=20) and (15x+6y=60) are coincident lines, what is the value of (k)?

Explanation opens after your attempt
Correct Answer

B. (2)

Step 1

Concept

The second equation is (3) times the first, so (3k=6) and (k=2). In coincident lines, all terms are in the same ratio.

Step 2

Why this answer is correct

The correct answer is B. (2). The second equation is (3) times the first, so (3k=6) and (k=2). In coincident lines, all terms are in the same ratio.

Step 3

Exam Tip

दूसरा समीकरण पहले का (3) गुना है, इसलिए (3k=6) और (k=2)। संपाती रेखाओं में सभी पद समान अनुपात में होते हैं।

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रेखाएं (9x-6y=21) और (3x-2y=7) किस प्रकार की हैं?

What type of lines are (9x-6y=21) and (3x-2y=7)?

Explanation opens after your attempt
Correct Answer

C. संपातीCoincident

Step 1

Concept

The first equation is (3) times the second. Therefore the lines are coincident and give infinitely many solutions.

Step 2

Why this answer is correct

The correct answer is C. संपाती / Coincident. The first equation is (3) times the second. Therefore the lines are coincident and give infinitely many solutions.

Step 3

Exam Tip

पहला समीकरण दूसरे का (3) गुना है। इसलिए दोनों रेखाएं संपाती हैं और अनंत समाधान देती हैं।

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यदि (ax+6y=18) और (2x+3y=9) संपाती रेखाएं हैं, तो (a) का मान क्या है?

If (ax+6y=18) and (2x+3y=9) are coincident lines, what is the value of (a)?

Explanation opens after your attempt
Correct Answer

C. (4)

Step 1

Concept

The first equation must be (2) times the second, so (a=4). In coincident lines, all terms change by the same multiplier.

Step 2

Why this answer is correct

The correct answer is C. (4). The first equation must be (2) times the second, so (a=4). In coincident lines, all terms change by the same multiplier.

Step 3

Exam Tip

पहला समीकरण दूसरे का (2) गुना होना चाहिए, इसलिए (a=4)। संपाती रेखाओं में सभी पद समान गुणक से बदलते हैं।

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किस युग्म का ग्राफ संगत और आश्रित युग्म दिखाता है?

Which pair shows a consistent and dependent pair on the graph?

Explanation opens after your attempt
Correct Answer

A. (2x-y=7), (4x-2y=14)

Step 1

Concept

The second equation is (2) times the first, so the lines are coincident. Coincident lines give a consistent and dependent pair.

Step 2

Why this answer is correct

The correct answer is A. (2x-y=7), (4x-2y=14). The second equation is (2) times the first, so the lines are coincident. Coincident lines give a consistent and dependent pair.

Step 3

Exam Tip

दूसरा समीकरण पहले का (2) गुना है, इसलिए रेखाएं संपाती हैं। संपाती रेखाएं संगत और आश्रित युग्म देती हैं।

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रेखाएं (7x+2y=18) और (14x+4y=36) ग्राफ पर क्या दर्शाती हैं?

What do the lines (7x+2y=18) and (14x+4y=36) represent on a graph?

Explanation opens after your attempt
Correct Answer

C. अनंत समाधानInfinitely many solutions

Step 1

Concept

The second equation is (2) times the first, so both lines are the same. All points on the same line are solutions.

Step 2

Why this answer is correct

The correct answer is C. अनंत समाधान / Infinitely many solutions. The second equation is (2) times the first, so both lines are the same. All points on the same line are solutions.

Step 3

Exam Tip

दूसरा समीकरण पहले का (2) गुना है, इसलिए दोनों रेखाएं एक ही हैं। एक ही रेखा के सभी बिंदु समाधान होते हैं।

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यदि (kx+4y=12) और (6x+8y=24) की रेखाएं संपाती हैं, तो (k) का मान क्या होगा?

If the lines (kx+4y=12) and (6x+8y=24) are coincident, what is the value of (k)?

Explanation opens after your attempt
Correct Answer

B. (3)

Step 1

Concept

For coincident lines, \(\frac{k}{6}=\frac{4}{8}=\frac{12}{24}\), so (k=3). In coincidence, the whole equation stays in the same ratio.

Step 2

Why this answer is correct

The correct answer is B. (3). For coincident lines, \(\frac{k}{6}=\frac{4}{8}=\frac{12}{24}\), so (k=3). In coincidence, the whole equation stays in the same ratio.

Step 3

Exam Tip

संपाती रेखाओं के लिए \(\frac{k}{6}=\frac{4}{8}=\frac{12}{24}\), इसलिए (k=3)। संपाती स्थिति में पूरा समीकरण समान अनुपात में होता है।

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रेखाएं (2x+3y=13) और (4x+6y=26) को ग्राफ करने पर क्या मिलेगा?

What will be obtained by graphing (2x+3y=13) and (4x+6y=26)?

Explanation opens after your attempt
Correct Answer

C. अनंत समाधानInfinitely many solutions

Step 1

Concept

The second line is (2) times the first, so both are the same line. A same line has infinitely many solution points.

Step 2

Why this answer is correct

The correct answer is C. अनंत समाधान / Infinitely many solutions. The second line is (2) times the first, so both are the same line. A same line has infinitely many solution points.

Step 3

Exam Tip

दूसरी रेखा पहली की (2) गुनी है, इसलिए दोनों एक ही रेखा हैं। एक ही रेखा के अनंत बिंदु समाधान होते हैं।

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रेखाएं (3x-2y=6) और (6x-4y=12) ग्राफ पर कैसी दिखेंगी?

How will the lines (3x-2y=6) and (6x-4y=12) appear on a graph?

Explanation opens after your attempt
Correct Answer

C. संपातीCoincident

Step 1

Concept

The second equation is (2) times the first, so both lines are the same. If one line overlaps the other, there are infinitely many solutions.

Step 2

Why this answer is correct

The correct answer is C. संपाती / Coincident. The second equation is (2) times the first, so both lines are the same. If one line overlaps the other, there are infinitely many solutions.

Step 3

Exam Tip

दूसरा समीकरण पहले का (2) गुना है, इसलिए दोनों रेखाएं एक ही हैं। ग्राफ में एक ही रेखा दिखे तो अनंत समाधान होते हैं।

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यदि \(a_1=7,\ b_1=14,\ c_1=21\) और \(a_2=1,\ b_2=2,\ c_2=3\), तो रेखाएँ कैसी होंगी?

If \(a_1=7,\ b_1=14,\ c_1=21\) and \(a_2=1,\ b_2=2,\ c_2=3\), how will the lines be?

Explanation opens after your attempt
Correct Answer

B. संपातीCoincident

Step 1

Concept

Here \(\frac{a_1}{a_2}=\frac{b_1}{b_2}=\frac{c_1}{c_2}=7\). Therefore both lines will be coincident.

Step 2

Why this answer is correct

The correct answer is B. संपाती / Coincident. Here \(\frac{a_1}{a_2}=\frac{b_1}{b_2}=\frac{c_1}{c_2}=7\). Therefore both lines will be coincident.

Step 3

Exam Tip

यहाँ \(\frac{a_1}{a_2}=\frac{b_1}{b_2}=\frac{c_1}{c_2}=7\)। इसलिए दोनों रेखाएँ संपाती होंगी।

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समीकरण (8x-12y=20) और (2x-3y=5) के ग्राफ कैसे होंगे?

How will the graphs of (8x-12y=20) and (2x-3y=5) be?

Explanation opens after your attempt
Correct Answer

C. संपातीCoincident

Step 1

Concept

Dividing the first equation by (4) gives (2x-3y=5). Therefore both are the same line and have infinitely many solutions.

Step 2

Why this answer is correct

The correct answer is C. संपाती / Coincident. Dividing the first equation by (4) gives (2x-3y=5). Therefore both are the same line and have infinitely many solutions.

Step 3

Exam Tip

पहला समीकरण (4) से भाग देने पर (2x-3y=5) बनता है। इसलिए दोनों एक ही रेखा हैं और अनंत हल हैं।

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यदि \(a_1=5,\ b_1=10,\ c_1=15\) और \(a_2=1,\ b_2=2,\ c_2=3\), तो रेखाएँ कैसी होंगी?

If \(a_1=5,\ b_1=10,\ c_1=15\) and \(a_2=1,\ b_2=2,\ c_2=3\), how will the lines be?

Explanation opens after your attempt
Correct Answer

B. संपातीCoincident

Step 1

Concept

Here \(\frac{a_1}{a_2}=\frac{b_1}{b_2}=\frac{c_1}{c_2}=5\). Therefore both lines will be coincident.

Step 2

Why this answer is correct

The correct answer is B. संपाती / Coincident. Here \(\frac{a_1}{a_2}=\frac{b_1}{b_2}=\frac{c_1}{c_2}=5\). Therefore both lines will be coincident.

Step 3

Exam Tip

यहाँ \(\frac{a_1}{a_2}=\frac{b_1}{b_2}=\frac{c_1}{c_2}=5\)। इसलिए दोनों रेखाएँ संपाती होंगी।

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