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What is the value of (p) for (px-10y=30) and (3x-5y=15) to have infinitely many solutions?

Answer and explanation

Correct answer: p=6

For two linear equations to have infinitely many solutions, the condition is \(\frac{a_1}{a_2}=\frac{b_1}{b_2}=\frac{c_1}{c_2}\). Here, \(\frac{-10}{-5}=\frac{30}{15}=2\), so \(\frac{p}{3}=2\), giving \(p=6\). Therefore, option C is correct. Exam tip: For infinitely many solutions, all three corresponding coefficient and constant ratios must be equal; matching only two ratios is not sufficient.

Related tags

Linear EquationsInfinite SolutionsSubstitution MethodElimination MethodParameterClass 10Conditions For SolvabilityPair Of Linear Equations In Two Variables

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