100 results found for "hue and value" in Class 10.
रंगत्व और मान में सही अंतर कौन सा है?
Which is the correct difference between hue and value?
#hue
#value
#difference
A रंगत्व रंग का नाम है और मान हल्का गहरा है / Hue is colour name and value is lightness darkness
B रंगत्व स्पर्श है और मान कागज है / Hue is touch and value is paper
C दोनों केवल बनावट हैं / Both are only textures
D दोनों का चित्र से संबंध नहीं है / Both have no relation with picture
Explanation opens after your attempt
Correct Answer
A. रंगत्व रंग का नाम है और मान हल्का गहरा है / Hue is colour name and value is lightness darkness
Step 1
Concept
Hue tells identity and value tells lightness darkness. Exam tip: keep hue and value separate.
Step 2
Why this answer is correct
The correct answer is A. रंगत्व रंग का नाम है और मान हल्का गहरा है / Hue is colour name and value is lightness darkness. Hue tells identity and value tells lightness darkness. Exam tip: keep hue and value separate.
Step 3
Exam Tip
रंगत्व पहचान बताता है और मान रोशनी अंधेरा बताता है। परीक्षा में hue और value अलग रखें।
Login to save your score, XP, coins and progress. Login
यदि चित्र में गहराई चाहिए तो केवल रंगत्व बदलना क्यों पर्याप्त नहीं है?
Why is changing only hue not enough if depth is needed in a picture?
#depth cues
#hue
#value space
A गहराई के लिए मान आकार ओवरलैपिंग और स्थान भी जरूरी हैं / Value size overlapping and space are also needed for depth
B रंगत्व गहराई से असंबंधित है हमेशा / Hue is always unrelated to depth
C मान का कोई काम नहीं / Value has no role
D आकार कभी प्रभाव नहीं देता / Shape never affects
Explanation opens after your attempt
Correct Answer
A. गहराई के लिए मान आकार ओवरलैपिंग और स्थान भी जरूरी हैं / Value size overlapping and space are also needed for depth
Step 1
Concept
Depth is created by many cues. Exam tip: write depth cues together.
Step 2
Why this answer is correct
The correct answer is A. गहराई के लिए मान आकार ओवरलैपिंग और स्थान भी जरूरी हैं / Value size overlapping and space are also needed for depth. Depth is created by many cues. Exam tip: write depth cues together.
Step 3
Exam Tip
गहराई कई संकेतों से बनती है। परीक्षा में depth cues को संयुक्त रूप से लिखें।
Login to save your score, XP, coins and progress. Login
किस रंग योजना में एक ही रंगत्व के टिंट टोन और शेड हो सकते हैं?
Which colour scheme can have tints tones and shades of one hue?
#monochromatic
#tint tone shade
#hue
A पूरक योजना / Complementary scheme
B एकरंगी योजना / Monochromatic scheme
C समानांतर योजना / Analogous scheme
D गर्म योजना / Warm scheme
Explanation opens after your attempt
Correct Answer
B. एकरंगी योजना / Monochromatic scheme
Step 1
Concept
A monochromatic scheme is based on different forms of one hue. Exam tip: connect one hue with monochromatic.
Step 2
Why this answer is correct
The correct answer is B. एकरंगी योजना / Monochromatic scheme. A monochromatic scheme is based on different forms of one hue. Exam tip: connect one hue with monochromatic.
Step 3
Exam Tip
एकरंगी योजना एक ही रंगत्व के अलग रूपों पर आधारित होती है। परीक्षा में one hue को monochromatic से जोड़ें।
Login to save your score, XP, coins and progress. Login
रंगत्व का सही अर्थ क्या है?
What is the correct meaning of hue?
#hue
#colour name
#identity
A रंग का नाम / Name of colour
B सतह का स्पर्श / Touch of surface
C वस्तु की गहराई / Depth of object
D रेखा की दिशा / Direction of line
Explanation opens after your attempt
Correct Answer
A. रंग का नाम / Name of colour
Step 1
Concept
Hue tells the colour name such as red blue or yellow. Exam tip: understand hue as colour identity.
Step 2
Why this answer is correct
The correct answer is A. रंग का नाम / Name of colour. Hue tells the colour name such as red blue or yellow. Exam tip: understand hue as colour identity.
Step 3
Exam Tip
रंगत्व लाल नीला पीला जैसे रंग नाम को बताता है। परीक्षा में hue को colour identity समझें।
Login to save your score, XP, coins and progress. Login
रंग का रंगत्व किस बात को बताता है?
What does hue of a colour tell?
#hue
#colour name
#colour
A सतह की कठोरता / Hardness of surface
B रंग का नाम / Name of the colour
C कागज का आकार / Size of paper
D रेखा की मोटाई / Thickness of line
Explanation opens after your attempt
Correct Answer
B. रंग का नाम / Name of the colour
Step 1
Concept
Hue tells the name of a colour such as red blue or green. Exam tip: remember hue as colour name.
Step 2
Why this answer is correct
The correct answer is B. रंग का नाम / Name of the colour. Hue tells the name of a colour such as red blue or green. Exam tip: remember hue as colour name.
Step 3
Exam Tip
रंगत्व से लाल नीला हरा जैसे रंग का नाम पता चलता है। परीक्षा में hue को colour name के रूप में याद रखें।
Login to save your score, XP, coins and progress. Login
हुए स्मारक समूह को किस वियतनामी राजकीय परंपरा से जोड़ा जाता है?
Complex of Hue Monuments is linked with which Vietnamese royal tradition?
#hue
#vietnam
#nguyen
A न्यूयेन राजवंश की शाही राजधानी / Imperial capital of the Nguyen dynasty
B माया खगोलीय केंद्र / Maya astronomical center
C रोमन जलसेतु नगर / Roman aqueduct city
D मुगल खानाबदोश छावनी / Mughal nomadic camp
Explanation opens after your attempt
Correct Answer
A. न्यूयेन राजवंश की शाही राजधानी / Imperial capital of the Nguyen dynasty
Step 1
Concept
Hue was the center of Nguyen imperial power and palace tradition in Vietnam. For exams remember imperial capital.
Step 2
Why this answer is correct
The correct answer is A. न्यूयेन राजवंश की शाही राजधानी / Imperial capital of the Nguyen dynasty. Hue was the center of Nguyen imperial power and palace tradition in Vietnam. For exams remember imperial capital.
Step 3
Exam Tip
हुए वियतनाम की न्यूयेन शाही सत्ता और राजमहल परंपरा का केंद्र था। परीक्षा में शाही राजधानी याद रखें।
Login to save your score, XP, coins and progress. Login
लाल रंग का नाम बताने वाला गुण क्या है?
What quality tells the name red as a colour?
#hue
#red
#colour
A रंगत्व / Hue
B बनावट / Texture
C स्थान / Space
D रूप / Form
Explanation opens after your attempt
Correct Answer
A. रंगत्व / Hue
Step 1
Concept
Hue tells the identity of a colour. Exam tip: connect hue with colour name.
Step 2
Why this answer is correct
The correct answer is A. रंगत्व / Hue. Hue tells the identity of a colour. Exam tip: connect hue with colour name.
Step 3
Exam Tip
रंगत्व रंग की पहचान बताता है। परीक्षा में रंगत्व को रंग नाम से जोड़ें।
Login to save your score, XP, coins and progress. Login
रंग का नाम जैसे लाल या नीला किस गुण से जाना जाता है?
The name of a colour such as red or blue is known by which quality?
#hue
#colour name
#identity
A रंगत्व / Hue
B छाया / Shade
C बनावट / Texture
D आकार / Shape
Explanation opens after your attempt
Correct Answer
A. रंगत्व / Hue
Step 1
Concept
Hue tells the identity or name of a colour. Exam tip: remember hue as the colour name.
Step 2
Why this answer is correct
The correct answer is A. रंगत्व / Hue. Hue tells the identity or name of a colour. Exam tip: remember hue as the colour name.
Step 3
Exam Tip
रंगत्व रंग की पहचान या नाम बताता है। परीक्षा में hue का अर्थ रंग का नाम याद रखें।
Login to save your score, XP, coins and progress. Login
रंग का नाम बताने वाला गुण कौन सा है?
Which quality tells the name of a colour?
#hue
#colour name
#identity
A बनावट / Texture
B रंगत्व / Hue
C स्थान / Space
D गहराई / Depth
Explanation opens after your attempt
Correct Answer
B. रंगत्व / Hue
Step 1
Concept
Hue tells the colour name such as red or blue. Exam tip: understand hue as colour identity.
Step 2
Why this answer is correct
The correct answer is B. रंगत्व / Hue. Hue tells the colour name such as red or blue. Exam tip: understand hue as colour identity.
Step 3
Exam Tip
रंगत्व रंग का नाम बताता है जैसे लाल या नीला। परीक्षा में hue को colour identity समझें।
Login to save your score, XP, coins and progress. Login
मान के अध्ययन में मध्यम मान की भूमिका क्या है?
What is the role of middle value in value study?
#middle value
#transition
#shading
A प्रकाश और छाया के बीच संक्रमण बनाना / Creating transition between light and shadow
B रंग का नाम बदलना / Changing colour name
C आकार मिटाना / Erasing shape
D कागज काटना / Cutting paper
Explanation opens after your attempt
Correct Answer
A. प्रकाश और छाया के बीच संक्रमण बनाना / Creating transition between light and shadow
Step 1
Concept
Middle value connects light and dark parts. Exam tip: connect mid value with transition.
Step 2
Why this answer is correct
The correct answer is A. प्रकाश और छाया के बीच संक्रमण बनाना / Creating transition between light and shadow. Middle value connects light and dark parts. Exam tip: connect mid value with transition.
Step 3
Exam Tip
मध्यम मान उजले और गहरे भागों को जोड़ता है। परीक्षा में mid value को transition से जोड़ें।
Login to save your score, XP, coins and progress. Login
यदि मान पट्टी में मध्य मान नहीं है तो छायांकन पर क्या असर होगा?
If a value scale has no middle values what effect will it have on shading?
#value scale
#middle value
#shading
A प्रकाश से छाया का संक्रमण कठोर लगेगा / Transition from light to shadow will look harsh
B छाया अधिक कोमल होगी / Shadow will become softer
C रंगत्व बढ़ेगा / Hue will increase
D बनावट वास्तविक होगी / Texture will become actual
Explanation opens after your attempt
Correct Answer
A. प्रकाश से छाया का संक्रमण कठोर लगेगा / Transition from light to shadow will look harsh
Step 1
Concept
Middle values create smooth transition. Exam tip: keep full range in value scale.
Step 2
Why this answer is correct
The correct answer is A. प्रकाश से छाया का संक्रमण कठोर लगेगा / Transition from light to shadow will look harsh. Middle values create smooth transition. Exam tip: keep full range in value scale.
Step 3
Exam Tip
मध्य मान smooth transition बनाते हैं। परीक्षा में value scale में full range रखें।
Login to save your score, XP, coins and progress. Login
छाया को अधिक गहरा दिखाने के लिए किस मान का उपयोग होगा?
Which value will be used to make shadow look darker?
#dark value
#shadow
#value
A हल्का मान / Light value
B गहरा मान / Dark value
C रंगत्व / Hue
D सकारात्मक स्थान / Positive space
Explanation opens after your attempt
Correct Answer
B. गहरा मान / Dark value
Step 1
Concept
Dark value increases the effect of shadow. Exam tip: connect shadow with dark value.
Step 2
Why this answer is correct
The correct answer is B. गहरा मान / Dark value. Dark value increases the effect of shadow. Exam tip: connect shadow with dark value.
Step 3
Exam Tip
गहरा मान छाया का प्रभाव बढ़ाता है। परीक्षा में shadow को dark value से जोड़ें।
Login to save your score, XP, coins and progress. Login
प्रकाश पड़ने वाले भाग को दिखाने के लिए कौन सा मान चाहिए?
Which value is needed to show the lighted part?
#light value
#highlight
#value
A गहरा मान / Dark value
B मध्यम अंधेरा / Medium dark
C हल्का मान / Light value
D काली रेखा / Black line
Explanation opens after your attempt
Correct Answer
C. हल्का मान / Light value
Step 1
Concept
Light value shows the lit part. Exam tip: connect highlight with light value.
Step 2
Why this answer is correct
The correct answer is C. हल्का मान / Light value. Light value shows the lit part. Exam tip: connect highlight with light value.
Step 3
Exam Tip
हल्का मान प्रकाश वाले भाग को दिखाता है। परीक्षा में प्रकाशित भाग को हल्का मान से जोड़ें।
Login to save your score, XP, coins and progress. Login
किस स्थिति में बाहरी रेखा को हटाकर केवल रंग और मान से आकृति बनाना अधिक परिपक्व तरीका माना जा सकता है?
In which situation can removing outline and forming figure only with colour and value be considered a more mature method?
#shape
#value contrast
#naturalism
A जब आकृति को प्राकृतिक और प्रकाश आधारित दिखाना हो / When figure needs to look natural and light-based
B जब केवल बाल रेखाएं दिखानी हों / When only hair lines are needed
C जब कागज काटना हो / When paper needs cutting
D जब पाठ लिखना हो / When text must be written
Explanation opens after your attempt
Correct Answer
A. जब आकृति को प्राकृतिक और प्रकाश आधारित दिखाना हो / When figure needs to look natural and light-based
Step 1
Concept
Boundary made by colour and value can look more natural. Exam tip: understand shape formation without outline.
Step 2
Why this answer is correct
The correct answer is A. जब आकृति को प्राकृतिक और प्रकाश आधारित दिखाना हो / When figure needs to look natural and light-based. Boundary made by colour and value can look more natural. Exam tip: understand shape formation without outline.
Step 3
Exam Tip
रंग और मान से बनी सीमा अधिक प्राकृतिक दिख सकती है। परीक्षा में outline के बिना shape formation समझें।
Login to save your score, XP, coins and progress. Login
यदि (4x+5y=7) और (8x-5y=29), तो (3x-y) का मान क्या है?
If (4x+5y=7) and (8x-5y=29), what is the value of (3x-y)?
#pair-linear-equations-negative-value
A (8)
B (9)
C (10)
D (11)
Explanation opens after your attempt
Step 1
Concept
Adding gives (12x=36), so (x=3) and (y=-1). Therefore (3x-y=10).
Step 2
Why this answer is correct
The correct answer is C. (10). Adding gives (12x=36), so (x=3) and (y=-1). Therefore (3x-y=10).
Step 3
Exam Tip
जोड़ने पर (12x=36), इसलिए (x=3) और (y=-1)। अतः (3x-y=10)।
Login to save your score, XP, coins and progress. Login
समीकरणों (2x+7y=31) और (5x-7y=4) के हल में (x+y) का मान क्या है?
For (2x+7y=31) and (5x-7y=4), what is the value of (x+y) in the solution?
#pair-linear-equations
#elimination
#value-expression
A (9)
B (8)
C (7)
D (6)
Explanation opens after your attempt
Step 1
Concept
Adding gives (7x=35), so (x=5) and (y=3). Therefore (x+y=8); substitute back before choosing the option.
Step 2
Why this answer is correct
The correct answer is A. (9). Adding gives (7x=35), so (x=5) and (y=3). Therefore (x+y=8); substitute back before choosing the option.
Step 3
Exam Tip
जोड़ने पर (7x=35), इसलिए (x=5) और (y=3)। अतः (x+y=8) नहीं बल्कि ध्यान से रखने पर (5+3=8) मिलता है।
Login to save your score, XP, coins and progress. Login
समीकरण (7x+4y=2) और (3x-4y=18) के हल में (x-y) का मान क्या होगा?
For (7x+4y=2) and (3x-4y=18), what is the value of (x-y) in the solution?
#pair-linear-equations
#value-expression
#expert
A (4)
B (5)
C (6)
D (3)
Explanation opens after your attempt
Step 1
Concept
Adding the equations gives (10x=20), so (x=2) and (y=-3). Therefore (x-y=5).
Step 2
Why this answer is correct
The correct answer is B. (5). Adding the equations gives (10x=20), so (x=2) and (y=-3). Therefore (x-y=5).
Step 3
Exam Tip
समीकरण जोड़ने पर (10x=20), इसलिए (x=2) और (y=-3)। अतः (x-y=5)।
Login to save your score, XP, coins and progress. Login
यदि (x=5y-8) और (4x+3y=61), तो (y) का मान क्या है?
If (x=5y-8) and (4x+3y=61), what is the value of (y)?
#linear equations
#substitution
#fraction value
#expert
#class 10
A \(y=\frac{83}{23}\)
B \(y=\frac{88}{23}\)
C \(y=\frac{93}{23}\)
D \(y=\frac{98}{23}\)
Explanation opens after your attempt
Correct Answer
C. \(y=\frac{93}{23}\)
Step 1
Concept
Substitute (x=5y-8) in the second equation. (20y-32+3y=61), so \(y=\frac{93}{23}\).
Step 2
Why this answer is correct
The correct answer is C. \(y=\frac{93}{23}\). Substitute (x=5y-8) in the second equation. (20y-32+3y=61), so \(y=\frac{93}{23}\).
Step 3
Exam Tip
(x=5y-8) को दूसरे समीकरण में रखें। (20y-32+3y=61), इसलिए \(y=\frac{93}{23}\)।
Login to save your score, XP, coins and progress. Login
समीकरणों (9x-5y=42) और (3x+5y=30) से (x+2y) का मान क्या है?
What is the value of (x+2y) from (9x-5y=42) and (3x+5y=30)?
#linear equations
#elimination
#expression value
#expert
#class 10
A \(x+2y=\frac{44}{5}\)
B \(x+2y=\frac{49}{5}\)
C \(x+2y=\frac{54}{5}\)
D \(x+2y=\frac{59}{5}\)
Explanation opens after your attempt
Correct Answer
C. \(x+2y=\frac{54}{5}\)
Step 1
Concept
Adding both equations gives (12x=72), so (x=6). Then \(y=\frac{12}{5}\), hence \(x+2y=\frac{54}{5}\).
Step 2
Why this answer is correct
The correct answer is C. \(x+2y=\frac{54}{5}\). Adding both equations gives (12x=72), so (x=6). Then \(y=\frac{12}{5}\), hence \(x+2y=\frac{54}{5}\).
Step 3
Exam Tip
दोनों समीकरण जोड़ने पर (12x=72), इसलिए (x=6)। फिर \(y=\frac{12}{5}\), अतः \(x+2y=\frac{54}{5}\)।
Login to save your score, XP, coins and progress. Login
समीकरणों (6x+9y=117) और (8x-3y=37) से (y) का मान क्या है?
What is the value of (y) from (6x+9y=117) and (8x-3y=37)?
#linear equations
#elimination
#fraction value
#expert
#class 10
A \(y=\frac{109}{15}\)
B \(y=\frac{114}{15}\)
C \(y=\frac{119}{15}\)
D \(y=\frac{124}{15}\)
Explanation opens after your attempt
Correct Answer
C. \(y=\frac{119}{15}\)
Step 1
Concept
Multiply the second equation by (3) and add it to the first. Solving gives \(y=\frac{119}{15}\).
Step 2
Why this answer is correct
The correct answer is C. \(y=\frac{119}{15}\). Multiply the second equation by (3) and add it to the first. Solving gives \(y=\frac{119}{15}\).
Step 3
Exam Tip
दूसरे समीकरण को (3) से गुणा कर पहले में जोड़ें। हल करने पर \(y=\frac{119}{15}\) मिलता है।
Login to save your score, XP, coins and progress. Login
समीकरणों \(\frac{x+4y}{5}=10\) और \(\frac{3x-y}{4}=7\) से (x-y) का मान क्या है?
What is the value of (x-y) from \(\frac{x+4y}{5}=10\) and \(\frac{3x-y}{4}=7\)?
#linear equations
#transformed equations
#expression value
#expert
#class 10
A \(x-y=\frac{34}{13}\)
B \(x-y=\frac{40}{13}\)
C \(x-y=\frac{46}{13}\)
D \(x-y=\frac{52}{13}\)
Explanation opens after your attempt
Correct Answer
B. \(x-y=\frac{40}{13}\)
Step 1
Concept
The equations become (x+4y=50) and (3x-y=28). Solving gives \(x-y=\frac{40}{13}\).
Step 2
Why this answer is correct
The correct answer is B. \(x-y=\frac{40}{13}\). The equations become (x+4y=50) and (3x-y=28). Solving gives \(x-y=\frac{40}{13}\).
Step 3
Exam Tip
दिए समीकरण (x+4y=50) और (3x-y=28) बनते हैं। हल से \(x-y=\frac{40}{13}\)।
Login to save your score, XP, coins and progress. Login
यदि (x+y=31) और (4x-3y=19), तो (2x-y) का मान क्या है?
If (x+y=31) and (4x-3y=19), what is the value of (2x-y)?
#linear equations
#substitution
#expression value
#expert
#class 10
A (15)
B (16)
C (17)
D (18)
Explanation opens after your attempt
Step 1
Concept
Using (x=31-y) gives (124-7y=19), so (y=15) and (x=16). Hence (2x-y=17).
Step 2
Why this answer is correct
The correct answer is C. (17). Using (x=31-y) gives (124-7y=19), so (y=15) and (x=16). Hence (2x-y=17).
Step 3
Exam Tip
(x=31-y) रखने पर (124-7y=19), इसलिए (y=15) और (x=16)। अतः (2x-y=17)।
Login to save your score, XP, coins and progress. Login
समीकरणों (9x+2y=10) और (3x-2y=14) से (y) का मान क्या है?
What is the value of (y) from (9x+2y=10) and (3x-2y=14)?
#linear equations
#elimination
#negative value
#expert
#class 10
A (y=-5)
B (y=-4)
C (y=-3)
D (y=-2)
Explanation opens after your attempt
Step 1
Concept
Adding both equations gives (12x=24), so (x=2). The first equation gives (y=-4).
Step 2
Why this answer is correct
The correct answer is B. (y=-4). Adding both equations gives (12x=24), so (x=2). The first equation gives (y=-4).
Step 3
Exam Tip
दोनों समीकरण जोड़ने पर (12x=24), इसलिए (x=2)। पहले समीकरण से (y=-4)।
Login to save your score, XP, coins and progress. Login
समीकरणों (0.5x+0.4y=6.1) और (0.3x-0.2y=1.7) से (x+y) का मान क्या है?
What is the value of (x+y) from (0.5x+0.4y=6.1) and (0.3x-0.2y=1.7)?
#linear equations
#decimal equations
#expression value
#expert
#class 10
A \(x+y=\frac{134}{11}\)
B \(x+y=\frac{139}{11}\)
C \(x+y=\frac{144}{11}\)
D \(x+y=\frac{149}{11}\)
Explanation opens after your attempt
Correct Answer
C. \(x+y=\frac{144}{11}\)
Step 1
Concept
Removing decimals gives (5x+4y=61) and (3x-2y=17). Solving gives \(x+y=\frac{144}{11}\).
Step 2
Why this answer is correct
The correct answer is C. \(x+y=\frac{144}{11}\). Removing decimals gives (5x+4y=61) and (3x-2y=17). Solving gives \(x+y=\frac{144}{11}\).
Step 3
Exam Tip
दशमलव हटाने पर (5x+4y=61) और (3x-2y=17) मिलते हैं। हल से \(x+y=\frac{144}{11}\) मिलता है।
Login to save your score, XP, coins and progress. Login
यदि (7x+6y=70) और (7x-4y=20), तो (x-y) का मान क्या है?
If (7x+6y=70) and (7x-4y=20), what is the value of (x-y)?
#linear equations
#elimination
#expression value
#expert
#class 10
A \(x-y=\frac{3}{7}\)
B \(x-y=\frac{4}{7}\)
C \(x-y=\frac{5}{7}\)
D \(x-y=\frac{6}{7}\)
Explanation opens after your attempt
Correct Answer
C. \(x-y=\frac{5}{7}\)
Step 1
Concept
Subtracting the second equation from the first gives (10y=50), so (y=5). Then \(x=\frac{40}{7}\), hence \(x-y=\frac{5}{7}\).
Step 2
Why this answer is correct
The correct answer is C. \(x-y=\frac{5}{7}\). Subtracting the second equation from the first gives (10y=50), so (y=5). Then \(x=\frac{40}{7}\), hence \(x-y=\frac{5}{7}\).
Step 3
Exam Tip
पहले समीकरण से दूसरा घटाने पर (10y=50), इसलिए (y=5)। फिर \(x=\frac{40}{7}\), अतः \(x-y=\frac{5}{7}\)।
Login to save your score, XP, coins and progress. Login
समीकरणों (11x+4y=91) और (5x-4y=21) से (y) का मान क्या है?
What is the value of (y) from (11x+4y=91) and (5x-4y=21)?
#linear equations
#elimination
#fraction value
#expert
#class 10
A \(y=\frac{5}{2}\)
B (y=3)
C \(y=\frac{7}{2}\)
D (y=4)
Explanation opens after your attempt
Correct Answer
C. \(y=\frac{7}{2}\)
Step 1
Concept
Adding both equations gives (16x=112), so (x=7). The first equation gives \(y=\frac{7}{2}\).
Step 2
Why this answer is correct
The correct answer is C. \(y=\frac{7}{2}\). Adding both equations gives (16x=112), so (x=7). The first equation gives \(y=\frac{7}{2}\).
Step 3
Exam Tip
दोनों समीकरण जोड़ने पर (16x=112), इसलिए (x=7)। पहले समीकरण से \(y=\frac{7}{2}\)।
Login to save your score, XP, coins and progress. Login
समीकरणों (4x-7y=9) और (6x+7y=71) से (x+y) का मान क्या है?
What is the value of (x+y) from (4x-7y=9) and (6x+7y=71)?
#linear equations
#elimination
#expression value
#expert
#class 10
A \(x+y=\frac{73}{7}\)
B \(x+y=\frac{75}{7}\)
C \(x+y=\frac{77}{7}\)
D \(x+y=\frac{79}{7}\)
Explanation opens after your attempt
Correct Answer
D. \(x+y=\frac{79}{7}\)
Step 1
Concept
Adding both equations gives (10x=80), so (x=8). Then \(y=\frac{23}{7}\), hence \(x+y=\frac{79}{7}\).
Step 2
Why this answer is correct
The correct answer is D. \(x+y=\frac{79}{7}\). Adding both equations gives (10x=80), so (x=8). Then \(y=\frac{23}{7}\), hence \(x+y=\frac{79}{7}\).
Step 3
Exam Tip
दोनों समीकरण जोड़ने पर (10x=80), इसलिए (x=8)। फिर \(y=\frac{23}{7}\), अतः \(x+y=\frac{79}{7}\)।
Login to save your score, XP, coins and progress. Login
यदि (5x+6y=142) और (6x+5y=144), तो (x-y) का मान क्या है?
If (5x+6y=142) and (6x+5y=144), what is the value of (x-y)?
#linear equations
#elimination
#expression value
#expert
#class 10
A (1)
B (2)
C (3)
D (4)
Explanation opens after your attempt
Step 1
Concept
Subtracting the first equation from the second directly gives (x-y=2). In such questions, subtraction saves time.
Step 2
Why this answer is correct
The correct answer is B. (2). Subtracting the first equation from the second directly gives (x-y=2). In such questions, subtraction saves time.
Step 3
Exam Tip
दूसरे समीकरण से पहला घटाने पर (x-y=2) सीधे मिलता है। ऐसे प्रश्नों में घटाना समय बचाता है।
Login to save your score, XP, coins and progress. Login
समीकरणों (7x+4y=58) और (3x-4y=22) को हल करने पर (y) का मान क्या है?
On solving (7x+4y=58) and (3x-4y=22), what is the value of (y)?
#linear equations
#elimination
#fraction value
#expert
#class 10
A \(y=\frac{1}{2}\)
B (y=1)
C \(y=\frac{3}{2}\)
D (y=2)
Explanation opens after your attempt
Correct Answer
A. \(y=\frac{1}{2}\)
Step 1
Concept
Adding both equations gives (10x=80), so (x=8). The first equation gives \(y=\frac{1}{2}\).
Step 2
Why this answer is correct
The correct answer is A. \(y=\frac{1}{2}\). Adding both equations gives (10x=80), so (x=8). The first equation gives \(y=\frac{1}{2}\).
Step 3
Exam Tip
दोनों समीकरण जोड़ने पर (10x=80), इसलिए (x=8)। पहले समीकरण से \(y=\frac{1}{2}\)।
Login to save your score, XP, coins and progress. Login
यदि (2x+3y=41) और (5x-2y=14), तो (2x+y) का मान क्या है?
If (2x+3y=41) and (5x-2y=14), what is the value of (2x+y)?
#linear equations
#elimination
#expression value
#expert
#class 10
A \(2x+y=\frac{405}{19}\)
B \(2x+y=\frac{415}{19}\)
C \(2x+y=\frac{425}{19}\)
D \(2x+y=\frac{435}{19}\)
Explanation opens after your attempt
Correct Answer
C. \(2x+y=\frac{425}{19}\)
Step 1
Concept
Elimination gives \(x=\frac{124}{19}\) and \(y=\frac{177}{19}\). Therefore \(2x+y=\frac{425}{19}\).
Step 2
Why this answer is correct
The correct answer is C. \(2x+y=\frac{425}{19}\). Elimination gives \(x=\frac{124}{19}\) and \(y=\frac{177}{19}\). Therefore \(2x+y=\frac{425}{19}\).
Step 3
Exam Tip
विलोपन से \(x=\frac{124}{19}\) और \(y=\frac{177}{19}\) मिलता है। इसलिए \(2x+y=\frac{425}{19}\)।
Login to save your score, XP, coins and progress. Login
यदि (5x-3y=19) और (2x+3y=26), तो (x-y) का मान क्या है?
If (5x-3y=19) and (2x+3y=26), what is the value of (x-y)?
#linear equations
#elimination
#expression value
#expert
#class 10
A \(x-y=\frac{43}{21}\)
B \(x-y=\frac{47}{21}\)
C \(x-y=\frac{51}{21}\)
D \(x-y=\frac{55}{21}\)
Explanation opens after your attempt
Correct Answer
A. \(x-y=\frac{43}{21}\)
Step 1
Concept
Adding both equations gives (7x=45). Then \(y=\frac{92}{21}\), so \(x-y=\frac{43}{21}\).
Step 2
Why this answer is correct
The correct answer is A. \(x-y=\frac{43}{21}\). Adding both equations gives (7x=45). Then \(y=\frac{92}{21}\), so \(x-y=\frac{43}{21}\).
Step 3
Exam Tip
दोनों समीकरण जोड़ने पर (7x=45) मिलता है। फिर \(y=\frac{92}{21}\), इसलिए \(x-y=\frac{43}{21}\)।
Login to save your score, XP, coins and progress. Login
यदि (4x-5y=-7) और (6x+5y=57), तो (3x+y) का मान क्या है?
If (4x-5y=-7) and (6x+5y=57), what is the value of (3x+y)?
#linear equations
#elimination
#expression value
#hard
#class 10
A (22)
B (24)
C (26)
D (28)
Explanation opens after your attempt
Step 1
Concept
Adding both equations gives (10x=50), so (x=5). Then \(y=\frac{27}{5}\), hence \(3x+y=\frac{102}{5}\), so none of the options is correct.
Step 2
Why this answer is correct
The correct answer is D. (28). Adding both equations gives (10x=50), so (x=5). Then \(y=\frac{27}{5}\), hence \(3x+y=\frac{102}{5}\), so none of the options is correct.
Step 3
Exam Tip
दोनों समीकरण जोड़ने पर (10x=50), इसलिए (x=5)। फिर \(y=\frac{27}{5}\), अतः \(3x+y=\frac{102}{5}\), इसलिए विकल्पों में कोई सही नहीं है।
Login to save your score, XP, coins and progress. Login
यदि (x=4y-7) और (3x+2y=59), तो (y) का मान क्या है?
If (x=4y-7) and (3x+2y=59), what is the value of (y)?
#linear equations
#substitution
#fraction value
#hard
#class 10
A \(y=\frac{36}{14}\)
B \(y=\frac{40}{14}\)
C \(y=\frac{80}{14}\)
D \(y=\frac{84}{14}\)
Explanation opens after your attempt
Correct Answer
C. \(y=\frac{80}{14}\)
Step 1
Concept
Substitute (x=4y-7) in the second equation. (12y-21+2y=59), so \(y=\frac{40}{7}\).
Step 2
Why this answer is correct
The correct answer is C. \(y=\frac{80}{14}\). Substitute (x=4y-7) in the second equation. (12y-21+2y=59), so \(y=\frac{40}{7}\).
Step 3
Exam Tip
(x=4y-7) को दूसरे समीकरण में रखिए। (12y-21+2y=59), इसलिए \(y=\frac{40}{7}\)।
Login to save your score, XP, coins and progress. Login
समीकरणों (8x-3y=54) और (2x+3y=21) से (x+2y) का मान क्या है?
What is the value of (x+2y) from (8x-3y=54) and (2x+3y=21)?
#linear equations
#elimination
#expression value
#hard
#class 10
A (12)
B (14)
C (16)
D (18)
Explanation opens after your attempt
Step 1
Concept
Adding both equations gives (10x=75), so \(x=\frac{15}{2}\). Then (y=2), hence \(x+2y=\frac{23}{2}\), so none of the options is correct.
Step 2
Why this answer is correct
The correct answer is D. (18). Adding both equations gives (10x=75), so \(x=\frac{15}{2}\). Then (y=2), hence \(x+2y=\frac{23}{2}\), so none of the options is correct.
Step 3
Exam Tip
दोनों समीकरण जोड़ने पर (10x=75), इसलिए \(x=\frac{15}{2}\)। फिर (y=2), अतः \(x+2y=\frac{23}{2}\), इसलिए विकल्पों में कोई सही नहीं है।
Login to save your score, XP, coins and progress. Login
समीकरणों (5x+8y=86) और (7x-4y=38) से (y) का मान क्या है?
What is the value of (y) from (5x+8y=86) and (7x-4y=38)?
#linear equations
#elimination
#fraction value
#hard
#class 10
A \(y=\frac{93}{17}\)
B \(y=\frac{96}{17}\)
C \(y=\frac{99}{17}\)
D \(y=\frac{102}{17}\)
Explanation opens after your attempt
Correct Answer
D. \(y=\frac{102}{17}\)
Step 1
Concept
Multiply the second equation by (2) and add it to the first. This gives \(x=\frac{162}{19}\) and \(y=\frac{103}{19}\), so none of the given options is correct.
Step 2
Why this answer is correct
The correct answer is D. \(y=\frac{102}{17}\). Multiply the second equation by (2) and add it to the first. This gives \(x=\frac{162}{19}\) and \(y=\frac{103}{19}\), so none of the given options is correct.
Step 3
Exam Tip
दूसरे समीकरण को (2) से गुणा कर पहले में जोड़ें। \(x=\frac{162}{19}\) और \(y=\frac{103}{19}\) मिलता है, इसलिए दिए विकल्पों में कोई सही नहीं है।
Login to save your score, XP, coins and progress. Login
समीकरणों \(\frac{x+3y}{4}=9\) और \(\frac{2x-y}{3}=5\) से (x-y) का मान क्या है?
What is the value of (x-y) from \(\frac{x+3y}{4}=9\) and \(\frac{2x-y}{3}=5\)?
#linear equations
#transformed equations
#expression value
#hard
#class 10
A (0)
B (1)
C (2)
D (3)
Explanation opens after your attempt
Step 1
Concept
The equations become (x+3y=36) and (2x-y=15). The solution is \(x=\frac{81}{7},\ y=\frac{57}{7}\), so \(x-y=\frac{24}{7}\), hence no option is correct.
Step 2
Why this answer is correct
The correct answer is D. (3). The equations become (x+3y=36) and (2x-y=15). The solution is \(x=\frac{81}{7},\ y=\frac{57}{7}\), so \(x-y=\frac{24}{7}\), hence no option is correct.
Step 3
Exam Tip
दिए समीकरण (x+3y=36) और (2x-y=15) बनते हैं। हल \(x=\frac{81}{7},\ y=\frac{57}{7}\), इसलिए \(x-y=\frac{24}{7}\), अतः विकल्पों में कोई सही नहीं है।
Login to save your score, XP, coins and progress. Login
यदि (x+y=24) और (3x-2y=37), तो (2x+y) का मान क्या है?
If (x+y=24) and (3x-2y=37), what is the value of (2x+y)?
#linear equations
#substitution
#expression value
#hard
#class 10
A (35)
B (37)
C (39)
D (41)
Explanation opens after your attempt
Step 1
Concept
Using (x=24-y) gives (72-5y=37), so (y=7) and (x=17). Hence (2x+y=41), so the correct option is (D).
Step 2
Why this answer is correct
The correct answer is B. (37). Using (x=24-y) gives (72-5y=37), so (y=7) and (x=17). Hence (2x+y=41), so the correct option is (D).
Step 3
Exam Tip
(x=24-y) रखने पर (72-5y=37), इसलिए (y=7) और (x=17)। अतः (2x+y=41), इसलिए सही विकल्प (D) है।
Login to save your score, XP, coins and progress. Login
समीकरणों (0.4x+0.7y=5.3) और (0.8x-0.2y=3.8) से (x+y) का मान क्या है?
What is the value of (x+y) from (0.4x+0.7y=5.3) and (0.8x-0.2y=3.8)?
#linear equations
#decimal equations
#expression value
#hard
#class 10
A \(x+y=\frac{102}{13}\)
B \(x+y=\frac{106}{13}\)
C \(x+y=\frac{110}{13}\)
D \(x+y=\frac{114}{13}\)
Explanation opens after your attempt
Correct Answer
B. \(x+y=\frac{106}{13}\)
Step 1
Concept
Removing decimals gives (4x+7y=53) and (8x-2y=38). Solving gives \(x+y=\frac{106}{13}\).
Step 2
Why this answer is correct
The correct answer is B. \(x+y=\frac{106}{13}\). Removing decimals gives (4x+7y=53) and (8x-2y=38). Solving gives \(x+y=\frac{106}{13}\).
Step 3
Exam Tip
दशमलव हटाने पर (4x+7y=53) और (8x-2y=38) मिलते हैं। हल से \(x+y=\frac{106}{13}\) मिलता है।
Login to save your score, XP, coins and progress. Login
यदि (6x+5y=64) और (6x-2y=29), तो (x-y) का मान क्या है?
If (6x+5y=64) and (6x-2y=29), what is the value of (x-y)?
#linear equations
#elimination
#expression value
#hard
#class 10
A \(x-y=\frac{1}{2}\)
B \(x-y=\frac{3}{2}\)
C \(x-y=\frac{5}{2}\)
D \(x-y=\frac{7}{2}\)
Explanation opens after your attempt
Correct Answer
C. \(x-y=\frac{5}{2}\)
Step 1
Concept
Subtracting the second equation from the first gives (7y=35), so (y=5). Then \(x=\frac{15}{2}\), hence \(x-y=\frac{5}{2}\).
Step 2
Why this answer is correct
The correct answer is C. \(x-y=\frac{5}{2}\). Subtracting the second equation from the first gives (7y=35), so (y=5). Then \(x=\frac{15}{2}\), hence \(x-y=\frac{5}{2}\).
Step 3
Exam Tip
पहले समीकरण से दूसरा घटाने पर (7y=35), इसलिए (y=5)। फिर \(x=\frac{15}{2}\), अतः \(x-y=\frac{5}{2}\)।
Login to save your score, XP, coins and progress. Login
समीकरणों (9x+5y=97) और (4x-5y=-12) से (y) का मान क्या है?
What is the value of (y) from (9x+5y=97) and (4x-5y=-12)?
#linear equations
#elimination
#fraction value
#hard
#class 10
A \(y=\frac{91}{13}\)
B \(y=\frac{92}{13}\)
C \(y=\frac{93}{13}\)
D \(y=\frac{94}{13}\)
Explanation opens after your attempt
Correct Answer
C. \(y=\frac{93}{13}\)
Step 1
Concept
Adding both equations gives (13x=85). Substituting \(x=\frac{85}{13}\) gives \(y=\frac{93}{13}\).
Step 2
Why this answer is correct
The correct answer is C. \(y=\frac{93}{13}\). Adding both equations gives (13x=85). Substituting \(x=\frac{85}{13}\) gives \(y=\frac{93}{13}\).
Step 3
Exam Tip
दोनों समीकरण जोड़ने पर (13x=85) मिलता है। \(x=\frac{85}{13}\) रखकर \(y=\frac{93}{13}\) मिलता है।
Login to save your score, XP, coins and progress. Login
समीकरणों (5x-4y=17) और (6x+8y=92) से (x+y) का मान क्या है?
What is the value of (x+y) from (5x-4y=17) and (6x+8y=92)?
#linear equations
#elimination
#expression value
#hard
#class 10
A \(x+y=\frac{315}{22}\)
B \(x+y=\frac{325}{22}\)
C \(x+y=\frac{335}{22}\)
D \(x+y=\frac{345}{22}\)
Explanation opens after your attempt
Correct Answer
B. \(x+y=\frac{325}{22}\)
Step 1
Concept
Multiply the first equation by (2) and add it to the second. \(x=\frac{126}{11}\) and \(y=\frac{73}{22}\), so \(x+y=\frac{325}{22}\).
Step 2
Why this answer is correct
The correct answer is B. \(x+y=\frac{325}{22}\). Multiply the first equation by (2) and add it to the second. \(x=\frac{126}{11}\) and \(y=\frac{73}{22}\), so \(x+y=\frac{325}{22}\).
Step 3
Exam Tip
पहले समीकरण को (2) से गुणा कर दूसरे में जोड़ें। \(x=\frac{126}{11}\) और \(y=\frac{73}{22}\), इसलिए \(x+y=\frac{325}{22}\)।
Login to save your score, XP, coins and progress. Login
यदि (3x+4y=141) और (4x+3y=145), तो (x-y) का मान क्या है?
If (3x+4y=141) and (4x+3y=145), what is the value of (x-y)?
#linear equations
#elimination
#expression value
#hard
#class 10
A (2)
B (3)
C (4)
D (5)
Explanation opens after your attempt
Step 1
Concept
Subtracting the first equation from the second directly gives (x-y=4). In such questions, the difference of equations gives the answer quickly.
Step 2
Why this answer is correct
The correct answer is C. (4). Subtracting the first equation from the second directly gives (x-y=4). In such questions, the difference of equations gives the answer quickly.
Step 3
Exam Tip
दूसरे समीकरण से पहला घटाने पर (x-y=4) सीधे मिलता है। ऐसे प्रश्नों में समीकरणों का अंतर जल्दी उत्तर देता है।
Login to save your score, XP, coins and progress. Login
यदि \(\frac{x+y}{3}=7\) और \(\frac{x-y}{4}=2\), तो (x-y) का मान क्या है?
If \(\frac{x+y}{3}=7\) and \(\frac{x-y}{4}=2\), what is the value of (x-y)?
#linear equations
#transformed equations
#direct value
#hard
#class 10
A (6)
B (7)
C (8)
D (9)
Explanation opens after your attempt
Step 1
Concept
The second equation directly gives (x-y=8). In exams, the asked expression is sometimes obtained directly.
Step 2
Why this answer is correct
The correct answer is C. (8). The second equation directly gives (x-y=8). In exams, the asked expression is sometimes obtained directly.
Step 3
Exam Tip
दूसरा समीकरण सीधे (x-y=8) देता है। परीक्षा में कभी-कभी पूछे गए व्यंजक का मान सीधे मिल जाता है।
Login to save your score, XP, coins and progress. Login
समीकरणों (5x+4y=73) और (3x-2y=19) को हल करने पर (y) का मान क्या है?
On solving (5x+4y=73) and (3x-2y=19), what is the value of (y)?
#linear equations
#elimination
#fraction value
#hard
#class 10
A \(y=\frac{17}{11}\)
B \(y=\frac{19}{11}\)
C \(y=\frac{23}{11}\)
D \(y=\frac{31}{11}\)
Explanation opens after your attempt
Correct Answer
C. \(y=\frac{23}{11}\)
Step 1
Concept
Multiply the second equation by (2) and add it to the first. This gives \(x=\frac{111}{11}\) and then \(y=\frac{23}{11}\).
Step 2
Why this answer is correct
The correct answer is C. \(y=\frac{23}{11}\). Multiply the second equation by (2) and add it to the first. This gives \(x=\frac{111}{11}\) and then \(y=\frac{23}{11}\).
Step 3
Exam Tip
दूसरे समीकरण को (2) से गुणा कर पहले में जोड़ें। \(x=\frac{111}{11}\) और फिर \(y=\frac{23}{11}\) मिलता है।
Login to save your score, XP, coins and progress. Login
समीकरणों (9x-4y=41) और (3x+4y=19) से (x) का मान क्या है?
What is the value of (x) from (9x-4y=41) and (3x+4y=19)?
#linear equations
#elimination
#value of x
#hard
#class 10
A (x=4)
B (x=5)
C (x=6)
D (x=7)
Explanation opens after your attempt
Step 1
Concept
Adding both equations gives (12x=60). Therefore (x=5).
Step 2
Why this answer is correct
The correct answer is B. (x=5). Adding both equations gives (12x=60). Therefore (x=5).
Step 3
Exam Tip
दोनों समीकरण जोड़ने पर (12x=60) मिलता है। इसलिए (x=5)।
Login to save your score, XP, coins and progress. Login
यदि (4x+7y=71) और (6x-7y=29), तो (x+2y) का मान क्या है?
If (4x+7y=71) and (6x-7y=29), what is the value of (x+2y)?
#linear equations
#elimination
#expression value
#hard
#class 10
A (18)
B (20)
C (22)
D (24)
Explanation opens after your attempt
Step 1
Concept
Adding both equations gives (10x=100), so (x=10). Then \(y=\frac{31}{7}\), hence \(x+2y=\frac{132}{7}\), so no integer option is correct.
Step 2
Why this answer is correct
The correct answer is D. (24). Adding both equations gives (10x=100), so (x=10). Then \(y=\frac{31}{7}\), hence \(x+2y=\frac{132}{7}\), so no integer option is correct.
Step 3
Exam Tip
दोनों समीकरण जोड़ने पर (10x=100), इसलिए (x=10)। फिर \(y=\frac{31}{7}\), अतः \(x+2y=\frac{132}{7}\), इसलिए विकल्पों में कोई पूर्णांक सही नहीं होता।
Login to save your score, XP, coins and progress. Login
यदि (11x-5y=13) और (7x+10y=74), तो (x+2y) का मान क्या है?
If (11x-5y=13) and (7x+10y=74), what is the value of (x+2y)?
#linear equations
#elimination
#fraction value
#class 10
A (11)
B (12)
C (13)
D (14)
Explanation opens after your attempt
Step 1
Concept
Multiply the first equation by (2) and add it to the second to get (x=4), \(y=\frac{9}{2}\). In exams, substitute fractional values carefully in the expression.
Step 2
Why this answer is correct
The correct answer is C. (13). Multiply the first equation by (2) and add it to the second to get (x=4), \(y=\frac{9}{2}\). In exams, substitute fractional values carefully in the expression.
Step 3
Exam Tip
पहले समीकरण को (2) से गुणा करके दूसरे में जोड़ें और (x=4), \(y=\frac{9}{2}\) पाएँ। परीक्षा में भिन्न मानों को व्यंजक में सावधानी से रखें।
Login to save your score, XP, coins and progress. Login
यदि (2x+3y=18) और (5x-4y=1), तो (x-2y) का मान ज्ञात कीजिए।
If (2x+3y=18) and (5x-4y=1), find the value of (x-2y).
#linear equations
#elimination
#negative value
#class 10
A (-5)
B (-4)
C (-3)
D (-2)
Explanation opens after your attempt
Step 1
Concept
Solving gives (x=3) and (y=3). In exams, recheck signs when the answer is negative.
Step 2
Why this answer is correct
The correct answer is C. (-3). Solving gives (x=3) and (y=3). In exams, recheck signs when the answer is negative.
Step 3
Exam Tip
हल करने पर (x=3) और (y=3) मिलता है। परीक्षा में ऋणात्मक उत्तर आने पर संकेत दोबारा जाँचें।
Login to save your score, XP, coins and progress. Login
समीकरणों (9x+8y=73) और (3x-2y=7) में (y) का मान ज्ञात कीजिए।
Find the value of (y) in the equations (9x+8y=73) and (3x-2y=7).
#linear equations
#elimination
#y value
#class 10
A (3)
B (4)
C (5)
D (6)
Explanation opens after your attempt
Step 1
Concept
Multiply the second equation by (3) to eliminate (x). In exams, making equal coefficients makes subtraction easier.
Step 2
Why this answer is correct
The correct answer is C. (5). Multiply the second equation by (3) to eliminate (x). In exams, making equal coefficients makes subtraction easier.
Step 3
Exam Tip
दूसरे समीकरण को (3) से गुणा करके (x) हटाएँ। परीक्षा में समान गुणांक बनाकर घटाना आसान रहता है।
Login to save your score, XP, coins and progress. Login
यदि (8x+5y=13) और (3x-2y=12), तो (x) का मान क्या है?
If (8x+5y=13) and (3x-2y=12), what is the value of (x)?
#linear equations
#elimination
#x value
#class 10
A (2)
B (3)
C (4)
D (5)
Explanation opens after your attempt
Step 1
Concept
Multiply the first equation by (2) and the second by (5) to eliminate (y). In exams, making equal coefficients is an easy method.
Step 2
Why this answer is correct
The correct answer is B. (3). Multiply the first equation by (2) and the second by (5) to eliminate (y). In exams, making equal coefficients is an easy method.
Step 3
Exam Tip
पहले समीकरण को (2) और दूसरे को (5) से गुणा करके (y) हटाएँ। परीक्षा में दोनों समीकरणों में बराबर गुणांक बनाना आसान तरीका है।
Login to save your score, XP, coins and progress. Login
समीकरणों (6x+7y=39) और (2x-y=1) में (y) का मान क्या है?
In the equations (6x+7y=39) and (2x-y=1), what is the value of (y)?
#linear equations
#substitution
#y value
#class 10
A (1)
B (2)
C (3)
D (4)
Explanation opens after your attempt
Step 1
Concept
From (2x-y=1), put (y=2x-1) in the first equation. In exams, isolate one variable clearly first.
Step 2
Why this answer is correct
The correct answer is C. (3). From (2x-y=1), put (y=2x-1) in the first equation. In exams, isolate one variable clearly first.
Step 3
Exam Tip
(2x-y=1) से (y=2x-1) रखकर पहला समीकरण हल करें। परीक्षा में पहले एक चर को स्पष्ट रूप से अलग करें।
Login to save your score, XP, coins and progress. Login
यदि (7x-4y=2) और (3x+2y=20) हैं, तो (2x+y) का मान ज्ञात कीजिए।
If (7x-4y=2) and (3x+2y=20), find the value of (2x+y).
#linear equations
#elimination
#value expression
#class 10
A (9)
B (10)
C (11)
D (12)
Explanation opens after your attempt
Step 1
Concept
Multiply the second equation by (2) to eliminate (y), then find (x). In exams, eliminate one variable first and then calculate the required expression.
Step 2
Why this answer is correct
The correct answer is C. (11). Multiply the second equation by (2) to eliminate (y), then find (x). In exams, eliminate one variable first and then calculate the required expression.
Step 3
Exam Tip
दूसरे समीकरण को (2) से गुणा करके (y) हटाएँ और फिर (x) निकालें। परीक्षा में पहले चर हटाकर फिर मांगा गया व्यंजक निकालें।
Login to save your score, XP, coins and progress. Login
यदि (3x-4y=-2) और (5x+4y=34), तो (2x+y) का मान क्या है?
If (3x-4y=-2) and (5x+4y=34), what is the value of (2x+y)?
#linear equations
#elimination
#expression value
#hard
#class 10
A \(\frac{23}{2}\)
B \(\frac{21}{2}\)
C \(\frac{25}{2}\)
D \(\frac{27}{2}\)
Explanation opens after your attempt
Correct Answer
A. \(\frac{23}{2}\)
Step 1
Concept
Adding both equations gives (8x=32), so (x=4). Then \(y=\frac{7}{2}\), hence \(2x+y=\frac{23}{2}\).
Step 2
Why this answer is correct
The correct answer is A. \(\frac{23}{2}\). Adding both equations gives (8x=32), so (x=4). Then \(y=\frac{7}{2}\), hence \(2x+y=\frac{23}{2}\).
Step 3
Exam Tip
दोनों समीकरण जोड़ने पर (8x=32), इसलिए (x=4)। फिर \(y=\frac{7}{2}\), अतः \(2x+y=\frac{23}{2}\)।
Login to save your score, XP, coins and progress. Login
यदि (x=3y-4) और (2x+5y=37), तो (y) का मान क्या है?
If (x=3y-4) and (2x+5y=37), what is the value of (y)?
#linear equations
#substitution
#fraction value
#hard
#class 10
A \(y=\frac{39}{11}\)
B \(y=\frac{42}{11}\)
C \(y=\frac{45}{11}\)
D \(y=\frac{48}{11}\)
Explanation opens after your attempt
Correct Answer
C. \(y=\frac{45}{11}\)
Step 1
Concept
Substitute (x=3y-4) in the second equation. (6y-8+5y=37), so \(y=\frac{45}{11}\).
Step 2
Why this answer is correct
The correct answer is C. \(y=\frac{45}{11}\). Substitute (x=3y-4) in the second equation. (6y-8+5y=37), so \(y=\frac{45}{11}\).
Step 3
Exam Tip
(x=3y-4) को दूसरे समीकरण में रखें। (6y-8+5y=37), इसलिए \(y=\frac{45}{11}\)।
Login to save your score, XP, coins and progress. Login
समीकरणों (7x-2y=39) और (3x+2y=21) से (x+2y) का मान क्या है?
What is the value of (x+2y) from (7x-2y=39) and (3x+2y=21)?
#linear equations
#elimination
#expression value
#hard
#class 10
A (9)
B (8)
C (10)
D (11)
Explanation opens after your attempt
Step 1
Concept
Adding both equations gives (10x=60), so (x=6). Then \(y=\frac{3}{2}\), hence (x+2y=9).
Step 2
Why this answer is correct
The correct answer is A. (9). Adding both equations gives (10x=60), so (x=6). Then \(y=\frac{3}{2}\), hence (x+2y=9).
Step 3
Exam Tip
दोनों समीकरण जोड़ने पर (10x=60), इसलिए (x=6)। फिर \(y=\frac{3}{2}\), अतः (x+2y=9)।
Login to save your score, XP, coins and progress. Login
समीकरणों (4x+9y=71) और (5x-3y=8) से (y) का मान क्या है?
What is the value of (y) from (4x+9y=71) and (5x-3y=8)?
#linear equations
#elimination
#fraction value
#hard
#class 10
A \(y=\frac{14}{3}\)
B \(y=\frac{17}{3}\)
C \(y=\frac{19}{3}\)
D \(y=\frac{20}{3}\)
Explanation opens after your attempt
Correct Answer
B. \(y=\frac{17}{3}\)
Step 1
Concept
Multiply the second equation by (3) and add the first. (x=5), then (4(5)+9y=71) gives \(y=\frac{17}{3}\).
Step 2
Why this answer is correct
The correct answer is B. \(y=\frac{17}{3}\). Multiply the second equation by (3) and add the first. (x=5), then (4(5)+9y=71) gives \(y=\frac{17}{3}\).
Step 3
Exam Tip
दूसरे समीकरण को (3) से गुणा कर पहले से जोड़ें। (x=5), फिर (4(5)+9y=71) से \(y=\frac{17}{3}\)।
Login to save your score, XP, coins and progress. Login
समीकरणों \(\frac{x+2y}{3}=8\) और \(\frac{2x-y}{5}=3\) से (x-y) का मान क्या है?
What is the value of (x-y) from \(\frac{x+2y}{3}=8\) and \(\frac{2x-y}{5}=3\)?
#linear equations
#transformed equations
#expression value
#hard
#class 10
A \(\frac{18}{5}\)
B \(\frac{19}{5}\)
C \(\frac{20}{5}\)
D \(\frac{21}{5}\)
Explanation opens after your attempt
Correct Answer
D. \(\frac{21}{5}\)
Step 1
Concept
The equations become (x+2y=24) and (2x-y=15). The solution is \(x=\frac{54}{5},\ y=\frac{33}{5}\), so \(x-y=\frac{21}{5}\).
Step 2
Why this answer is correct
The correct answer is D. \(\frac{21}{5}\). The equations become (x+2y=24) and (2x-y=15). The solution is \(x=\frac{54}{5},\ y=\frac{33}{5}\), so \(x-y=\frac{21}{5}\).
Step 3
Exam Tip
दिए समीकरण (x+2y=24) और (2x-y=15) बनते हैं। हल \(x=\frac{54}{5},\ y=\frac{33}{5}\), इसलिए \(x-y=\frac{21}{5}\)।
Login to save your score, XP, coins and progress. Login
यदि (x+y=15) और (2x-3y=10), तो (3x+y) का मान क्या है?
If (x+y=15) and (2x-3y=10), what is the value of (3x+y)?
#linear equations
#substitution
#expression value
#hard
#class 10
A (35)
B (37)
C (39)
D (41)
Explanation opens after your attempt
Step 1
Concept
Using (x=15-y) gives (30-5y=10), so (y=4) and (x=11). Hence (3x+y=37).
Step 2
Why this answer is correct
The correct answer is B. (37). Using (x=15-y) gives (30-5y=10), so (y=4) and (x=11). Hence (3x+y=37).
Step 3
Exam Tip
(x=15-y) रखने पर (30-5y=10), इसलिए (y=4) और (x=11)। अतः (3x+y=37)।
Login to save your score, XP, coins and progress. Login
समीकरणों (0.2x+0.5y=3.1) और (0.4x-0.1y=1.3) से (x+y) का मान क्या है?
What is the value of (x+y) from (0.2x+0.5y=3.1) and (0.4x-0.1y=1.3)?
#linear equations
#decimal equations
#expression value
#hard
#class 10
A \(x+y=\frac{97}{11}\)
B \(x+y=\frac{89}{11}\)
C \(x+y=\frac{101}{11}\)
D \(x+y=\frac{105}{11}\)
Explanation opens after your attempt
Correct Answer
A. \(x+y=\frac{97}{11}\)
Step 1
Concept
Removing decimals gives (2x+5y=31) and (4x-y=13). The solution is \(x=\frac{48}{11},\ y=\frac{49}{11}\), so \(x+y=\frac{97}{11}\).
Step 2
Why this answer is correct
The correct answer is A. \(x+y=\frac{97}{11}\). Removing decimals gives (2x+5y=31) and (4x-y=13). The solution is \(x=\frac{48}{11},\ y=\frac{49}{11}\), so \(x+y=\frac{97}{11}\).
Step 3
Exam Tip
दशमलव हटाने पर (2x+5y=31) और (4x-y=13) मिलते हैं। हल \(x=\frac{48}{11},\ y=\frac{49}{11}\), इसलिए \(x+y=\frac{97}{11}\)।
Login to save your score, XP, coins and progress. Login
यदि (4x+7y=53) और (4x-3y=13), तो (x-y) का मान क्या है?
If (4x+7y=53) and (4x-3y=13), what is the value of (x-y)?
#linear equations
#elimination
#expression value
#hard
#class 10
A \(x-y=\frac{9}{4}\)
B \(x-y=\frac{7}{4}\)
C \(x-y=\frac{11}{4}\)
D \(x-y=\frac{13}{4}\)
Explanation opens after your attempt
Correct Answer
A. \(x-y=\frac{9}{4}\)
Step 1
Concept
Subtracting the equations gives (10y=40), so (y=4). Then \(x=\frac{25}{4}\), hence \(x-y=\frac{9}{4}\).
Step 2
Why this answer is correct
The correct answer is A. \(x-y=\frac{9}{4}\). Subtracting the equations gives (10y=40), so (y=4). Then \(x=\frac{25}{4}\), hence \(x-y=\frac{9}{4}\).
Step 3
Exam Tip
दोनों समीकरण घटाने पर (10y=40), इसलिए (y=4)। फिर \(x=\frac{25}{4}\), अतः \(x-y=\frac{9}{4}\)।
Login to save your score, XP, coins and progress. Login
समीकरणों (7x+2y=32) और (3x-4y=-6) से (y) का मान क्या है?
What is the value of (y) from (7x+2y=32) and (3x-4y=-6)?
#linear equations
#elimination
#fraction value
#hard
#class 10
A \(y=\frac{69}{17}\)
B \(y=\frac{65}{17}\)
C \(y=\frac{72}{17}\)
D \(y=\frac{76}{17}\)
Explanation opens after your attempt
Correct Answer
A. \(y=\frac{69}{17}\)
Step 1
Concept
Multiply the first equation by (2) and add the second. \(x=\frac{58}{17}\) and \(y=\frac{69}{17}\).
Step 2
Why this answer is correct
The correct answer is A. \(y=\frac{69}{17}\). Multiply the first equation by (2) and add the second. \(x=\frac{58}{17}\) and \(y=\frac{69}{17}\).
Step 3
Exam Tip
पहले समीकरण को (2) से गुणा कर दूसरे से जोड़ें। \(x=\frac{58}{17}\) और \(y=\frac{69}{17}\)।
Login to save your score, XP, coins and progress. Login
समीकरणों (4x-3y=7) और (5x+6y=44) से (x+y) का मान क्या है?
What is the value of (x+y) from (4x-3y=7) and (5x+6y=44)?
#linear equations
#elimination
#expression value
#hard
#class 10
A \(x+y=\frac{105}{13}\)
B \(x+y=\frac{99}{13}\)
C \(x+y=\frac{111}{13}\)
D \(x+y=\frac{117}{13}\)
Explanation opens after your attempt
Correct Answer
A. \(x+y=\frac{105}{13}\)
Step 1
Concept
Multiply the first equation by (2) and add the second. \(x=\frac{58}{13}\) and \(y=\frac{47}{13}\), so \(x+y=\frac{105}{13}\).
Step 2
Why this answer is correct
The correct answer is A. \(x+y=\frac{105}{13}\). Multiply the first equation by (2) and add the second. \(x=\frac{58}{13}\) and \(y=\frac{47}{13}\), so \(x+y=\frac{105}{13}\).
Step 3
Exam Tip
पहले समीकरण को (2) से गुणा कर दूसरे से जोड़ें। \(x=\frac{58}{13}\) और \(y=\frac{47}{13}\), अतः \(x+y=\frac{105}{13}\)।
Login to save your score, XP, coins and progress. Login
समीकरणों (4x+3y=50) और (2x-5y=-6) को हल करने पर (y) का मान क्या है?
On solving (4x+3y=50) and (2x-5y=-6), what is the value of (y)?
#linear equations
#substitution
#fraction value
#hard
#class 10
A \(y=\frac{52}{13}\)
B \(y=\frac{56}{13}\)
C \(y=\frac{58}{13}\)
D \(y=\frac{62}{13}\)
Explanation opens after your attempt
Correct Answer
D. \(y=\frac{62}{13}\)
Step 1
Concept
Use \(x=\frac{5y-6}{2}\) from the second equation. Substitution gives (13y=62), so \(y=\frac{62}{13}\).
Step 2
Why this answer is correct
The correct answer is D. \(y=\frac{62}{13}\). Use \(x=\frac{5y-6}{2}\) from the second equation. Substitution gives (13y=62), so \(y=\frac{62}{13}\).
Step 3
Exam Tip
दूसरे समीकरण से \(x=\frac{5y-6}{2}\) रखें। पहले में रखने पर (13y=62), इसलिए \(y=\frac{62}{13}\)।
Login to save your score, XP, coins and progress. Login
समीकरणों (7x-5y=4) और (2x+5y=41) से (x) का मान क्या है?
What is the value of (x) from (7x-5y=4) and (2x+5y=41)?
#linear equations
#elimination
#value of x
#hard
#class 10
A (x=4)
B (x=5)
C (x=6)
D (x=7)
Explanation opens after your attempt
Step 1
Concept
Adding both equations gives (9x=45). Therefore (x=5).
Step 2
Why this answer is correct
The correct answer is B. (x=5). Adding both equations gives (9x=45). Therefore (x=5).
Step 3
Exam Tip
दोनों समीकरण जोड़ने पर (9x=45) मिलता है। इसलिए (x=5)।
Login to save your score, XP, coins and progress. Login
यदि (3x+2y=28) और (5x-4y=8), तो (x-y) का मान क्या है?
If (3x+2y=28) and (5x-4y=8), what is the value of (x-y)?
#linear equations
#elimination
#expression value
#hard
#class 10
A \(\frac{6}{11}\)
B \(\frac{8}{11}\)
C \(\frac{10}{11}\)
D \(\frac{12}{11}\)
Explanation opens after your attempt
Correct Answer
A. \(\frac{6}{11}\)
Step 1
Concept
Multiply the first equation by (2) and eliminate (y). \(x=\frac{64}{11}\) and \(y=\frac{58}{11}\), so \(x-y=\frac{6}{11}\).
Step 2
Why this answer is correct
The correct answer is A. \(\frac{6}{11}\). Multiply the first equation by (2) and eliminate (y). \(x=\frac{64}{11}\) and \(y=\frac{58}{11}\), so \(x-y=\frac{6}{11}\).
Step 3
Exam Tip
पहले समीकरण को (2) से गुणा कर (y) हटाएं। \(x=\frac{64}{11}\) और \(y=\frac{58}{11}\), इसलिए \(x-y=\frac{6}{11}\)।
Login to save your score, XP, coins and progress. Login
समीकरणों (x+3y=21) और (3x-y=11) को हल करने पर (2x+y) का मान क्या है?
On solving (x+3y=21) and (3x-y=11), what is the value of (2x+y)?
#linear-equations
#substitution
#expression-value
#medium
#class-10
A (14)
B (13)
C (12)
D (11)
Explanation opens after your attempt
Step 1
Concept
Use (y=3x-11) from the second equation. Substitution gives \(x=\frac{27}{5},\ y=\frac{16}{5}\), so (2x+y=14).
Step 2
Why this answer is correct
The correct answer is A. (14). Use (y=3x-11) from the second equation. Substitution gives \(x=\frac{27}{5},\ y=\frac{16}{5}\), so (2x+y=14).
Step 3
Exam Tip
दूसरे समीकरण से (y=3x-11) रखें। पहले में रखने पर \(x=\frac{27}{5},\ y=\frac{16}{5}\), इसलिए (2x+y=14)।
Login to save your score, XP, coins and progress. Login
यदि (3x-5y=-1) और (2x+5y=21), तो (x) का मान क्या होगा?
If (3x-5y=-1) and (2x+5y=21), what will be the value of (x)?
#linear-equations
#elimination
#value-of-x
#medium
#class-10
A (x=3)
B (x=4)
C (x=5)
D (x=6)
Explanation opens after your attempt
Step 1
Concept
Adding both equations gives (5x=20). Therefore (x=4).
Step 2
Why this answer is correct
The correct answer is B. (x=4). Adding both equations gives (5x=20). Therefore (x=4).
Step 3
Exam Tip
दोनों समीकरण जोड़ने पर (5x=20) मिलता है। इसलिए (x=4)।
Login to save your score, XP, coins and progress. Login
समीकरणों (6x+5y=47) और (2x-y=5) से (y) का मान क्या है?
What is the value of (y) from (6x+5y=47) and (2x-y=5)?
#linear-equations
#substitution
#value-of-y
#medium
#class-10
A (y=2)
B (y=3)
C (y=5)
D (y=4)
Explanation opens after your attempt
Step 1
Concept
Use (y=2x-5) from the second equation. Substitution gives (16x=72), so \(x=\frac{9}{2}\) and (y=4).
Step 2
Why this answer is correct
The correct answer is D. (y=4). Use (y=2x-5) from the second equation. Substitution gives (16x=72), so \(x=\frac{9}{2}\) and (y=4).
Step 3
Exam Tip
दूसरे समीकरण से (y=2x-5) रखें। पहले में रखने पर (16x=72), इसलिए \(x=\frac{9}{2}\) और (y=4)।
Login to save your score, XP, coins and progress. Login
यदि (2x+y=14) और (x+2y=16), तो (xy) का मान क्या है?
If (2x+y=14) and (x+2y=16), what is the value of (xy)?
#linear-equations
#elimination
#product-value
#medium
#class-10
A (20)
B (22)
C (24)
D (26)
Explanation opens after your attempt
Step 1
Concept
Solving gives (x=4) and (y=6). Therefore (xy=24).
Step 2
Why this answer is correct
The correct answer is C. (24). Solving gives (x=4) and (y=6). Therefore (xy=24).
Step 3
Exam Tip
हल करने पर (x=4) और (y=6) मिलते हैं। इसलिए (xy=24)।
Login to save your score, XP, coins and progress. Login
समीकरणों (5x+4y=44) और (5x-y=14) से (y) का मान क्या है?
What is the value of (y) from (5x+4y=44) and (5x-y=14)?
#linear-equations
#elimination
#value-of-y
#medium
#class-10
A (y=4)
B (y=6)
C (y=8)
D (y=10)
Explanation opens after your attempt
Step 1
Concept
Subtracting the second equation from the first gives (5y=30). Therefore (y=6).
Step 2
Why this answer is correct
The correct answer is B. (y=6). Subtracting the second equation from the first gives (5y=30). Therefore (y=6).
Step 3
Exam Tip
पहले समीकरण से दूसरा घटाने पर (5y=30) मिलता है। इसलिए (y=6)।
Login to save your score, XP, coins and progress. Login
यदि (3x+y=22) और (x+2y=19), तो (x-y) का मान क्या है?
If (3x+y=22) and (x+2y=19), what is the value of (x-y)?
#linear-equations
#substitution
#expression-value
#medium
#class-10
A (2)
B (0)
C (-1)
D (-2)
Explanation opens after your attempt
Step 1
Concept
Use (y=22-3x) from the first equation. Substitution gives (x=5,\ y=7), so (x-y=-2).
Step 2
Why this answer is correct
The correct answer is D. (-2). Use (y=22-3x) from the first equation. Substitution gives (x=5,\ y=7), so (x-y=-2).
Step 3
Exam Tip
पहले समीकरण से (y=22-3x) रखें। दूसरे में रखने पर (x=5,\ y=7), इसलिए (x-y=-2)।
Login to save your score, XP, coins and progress. Login
समीकरणों (4x-7y=-19) और (2x+y=13) से (x) का मान ज्ञात कीजिए।
Find the value of (x) from (4x-7y=-19) and (2x+y=13).
#linear-equations
#substitution
#value-of-x
#medium
#class-10
A (x=3)
B (x=4)
C (x=5)
D (x=6)
Explanation opens after your attempt
Step 1
Concept
Use (y=13-2x) from the second equation. Substitution gives (18x=72), so (x=4).
Step 2
Why this answer is correct
The correct answer is B. (x=4). Use (y=13-2x) from the second equation. Substitution gives (18x=72), so (x=4).
Step 3
Exam Tip
दूसरे समीकरण से (y=13-2x) रखें। पहले में रखने पर (18x=72), इसलिए (x=4)।
Login to save your score, XP, coins and progress. Login
यदि \(\frac{x}{3}+\frac{y}{2}=7\) और (x-y=3), तो (y) का मान क्या है?
If \(\frac{x}{3}+\frac{y}{2}=7\) and (x-y=3), what is the value of (y)?
#linear-equations
#fraction-equation
#value-of-y
#medium
#class-10
A \(y=\frac{31}{5}\)
B (y=7)
C \(y=\frac{36}{5}\)
D \(y=\frac{41}{5}\)
Explanation opens after your attempt
Correct Answer
C. \(y=\frac{36}{5}\)
Step 1
Concept
Multiplying the first equation by (6) gives (2x+3y=42). Using (x=y+3) gives (5y=36), so \(y=\frac{36}{5}\).
Step 2
Why this answer is correct
The correct answer is C. \(y=\frac{36}{5}\). Multiplying the first equation by (6) gives (2x+3y=42). Using (x=y+3) gives (5y=36), so \(y=\frac{36}{5}\).
Step 3
Exam Tip
पहले समीकरण को (6) से गुणा करने पर (2x+3y=42) मिलता है। (x=y+3) रखने पर (5y=36), इसलिए \(y=\frac{36}{5}\)।
Login to save your score, XP, coins and progress. Login
समीकरणों (8x-5y=29) और (3x+5y=26) से (y) का मान क्या है?
What is the value of (y) from (8x-5y=29) and (3x+5y=26)?
#linear-equations
#elimination
#fraction-value
#medium
#class-10
A (y=2)
B \(y=\frac{9}{5}\)
C \(y=\frac{12}{5}\)
D \(y=\frac{11}{5}\)
Explanation opens after your attempt
Correct Answer
D. \(y=\frac{11}{5}\)
Step 1
Concept
Adding both equations gives (11x=55), so (x=5). From the second equation (15+5y=26), hence \(y=\frac{11}{5}\).
Step 2
Why this answer is correct
The correct answer is D. \(y=\frac{11}{5}\). Adding both equations gives (11x=55), so (x=5). From the second equation (15+5y=26), hence \(y=\frac{11}{5}\).
Step 3
Exam Tip
दोनों समीकरण जोड़ने पर (11x=55), इसलिए (x=5)। दूसरे समीकरण से (15+5y=26), अतः \(y=\frac{11}{5}\)।
Login to save your score, XP, coins and progress. Login
यदि (2x+y=23) और (x+3y=19), तो (x-2y) का मान क्या है?
If (2x+y=23) and (x+3y=19), what is the value of (x-2y)?
#linear-equations
#substitution
#expression-value
#medium
#class-10
A (2)
B (3)
C (5)
D (4)
Explanation opens after your attempt
Step 1
Concept
Use (y=23-2x) from the first equation. Substitution gives (x=10,\ y=3), so (x-2y=4).
Step 2
Why this answer is correct
The correct answer is D. (4). Use (y=23-2x) from the first equation. Substitution gives (x=10,\ y=3), so (x-2y=4).
Step 3
Exam Tip
पहले समीकरण से (y=23-2x) रखें। दूसरे में रखने पर (x=10,\ y=3), इसलिए (x-2y=4)।
Login to save your score, XP, coins and progress. Login
यदि (5x-3y=2) और (2x+3y=19), तो (x) का मान क्या है?
If (5x-3y=2) and (2x+3y=19), what is the value of (x)?
#linear-equations
#elimination
#value-of-x
#medium
#class-10
A (x=2)
B (x=3)
C (x=4)
D (x=5)
Explanation opens after your attempt
Step 1
Concept
Adding both equations gives (7x=21). Therefore (x=3).
Step 2
Why this answer is correct
The correct answer is B. (x=3). Adding both equations gives (7x=21). Therefore (x=3).
Step 3
Exam Tip
दोनों समीकरण जोड़ने पर (7x=21) मिलता है। इसलिए (x=3)।
Login to save your score, XP, coins and progress. Login
यदि (3x+2y=130) और (2x+3y=120), तो (y) का मान क्या होगा?
If (3x+2y=130) and (2x+3y=120), what will be the value of (y)?
#linear-equations
#elimination
#value-of-y
#medium
#class-10
A (10)
B (15)
C (20)
D (25)
Explanation opens after your attempt
Step 1
Concept
Multiply the first equation by (3) and the second by (2), then subtract. This gives (5x=150), then (y=20).
Step 2
Why this answer is correct
The correct answer is C. (20). Multiply the first equation by (3) and the second by (2), then subtract. This gives (5x=150), then (y=20).
Step 3
Exam Tip
पहले समीकरण को (3) और दूसरे को (2) से गुणा कर घटाएं। इससे (5x=150), फिर (y=20)।
Login to save your score, XP, coins and progress. Login
समीकरणों (7x+4y=45) और (7x-y=15) से (y) का मान ज्ञात कीजिए।
Find the value of (y) from (7x+4y=45) and (7x-y=15).
#linear-equations
#elimination
#value-of-y
#medium
#class-10
A (y=4)
B (y=6)
C (y=7)
D (y=8)
Explanation opens after your attempt
Step 1
Concept
Subtracting the second equation from the first gives (5y=30). Therefore (y=6).
Step 2
Why this answer is correct
The correct answer is B. (y=6). Subtracting the second equation from the first gives (5y=30). Therefore (y=6).
Step 3
Exam Tip
पहले समीकरण से दूसरा घटाने पर (5y=30) मिलता है। इसलिए (y=6)।
Login to save your score, XP, coins and progress. Login
यदि (3x+2y=25) और (x-y=1), तो (x+y) का मान क्या है?
If (3x+2y=25) and (x-y=1), what is the value of (x+y)?
#linear-equations
#substitution
#expression-value
#medium
#class-10
A (8)
B (9)
C \(\frac{49}{5}\)
D \(\frac{51}{5}\)
Explanation opens after your attempt
Correct Answer
C. \(\frac{49}{5}\)
Step 1
Concept
Using (x=y+1) gives (5y+3=25), so \(y=\frac{22}{5}\) and \(x=\frac{27}{5}\). Hence \(x+y=\frac{49}{5}\).
Step 2
Why this answer is correct
The correct answer is C. \(\frac{49}{5}\). Using (x=y+1) gives (5y+3=25), so \(y=\frac{22}{5}\) and \(x=\frac{27}{5}\). Hence \(x+y=\frac{49}{5}\).
Step 3
Exam Tip
(x=y+1) रखने पर (5y+3=25), इसलिए \(y=\frac{22}{5}\) और \(x=\frac{27}{5}\)। अतः \(x+y=\frac{49}{5}\)।
Login to save your score, XP, coins and progress. Login
समीकरणों (3x+5y=31) और (x+y=9) को हल करने पर (x) का मान क्या है?
On solving (3x+5y=31) and (x+y=9), what is the value of (x)?
#linear-equations
#substitution
#value-of-x
#medium
#class-10
A (x=7)
B (x=6)
C (x=5)
D (x=4)
Explanation opens after your attempt
Step 1
Concept
Using (x=9-y) gives (27-3y+5y=31). Thus (y=2) and (x=7).
Step 2
Why this answer is correct
The correct answer is A. (x=7). Using (x=9-y) gives (27-3y+5y=31). Thus (y=2) and (x=7).
Step 3
Exam Tip
(x=9-y) रखने पर (27-3y+5y=31) मिलता है। इसलिए (y=2) और (x=7)।
Login to save your score, XP, coins and progress. Login
यदि (5x+2y=28) और (3x-2y=4), तो (x+y) का मान क्या होगा?
If (5x+2y=28) and (3x-2y=4), what will be the value of (x+y)?
#linear-equations
#elimination
#expression-value
#medium
#class-10
A (6)
B (7)
C (9)
D (8)
Explanation opens after your attempt
Step 1
Concept
Adding both equations gives (8x=32), so (x=4). Then (y=4), so (x+y=8).
Step 2
Why this answer is correct
The correct answer is D. (8). Adding both equations gives (8x=32), so (x=4). Then (y=4), so (x+y=8).
Step 3
Exam Tip
दोनों समीकरण जोड़ने पर (8x=32), इसलिए (x=4)। फिर (y=4), इसलिए (x+y=8)।
Login to save your score, XP, coins and progress. Login
यदि (x+3y=19) और (2x-y=3), तो (x+2y) का मान क्या है?
If (x+3y=19) and (2x-y=3), what is the value of (x+2y)?
#linear equations
#substitution
#expression value
#medium
#class 10
A (11)
B (12)
C (13)
D (14)
Explanation opens after your attempt
Step 1
Concept
Use (y=2x-3) from the second equation. Substitution gives (7x=28), so (x=4,\ y=5) and (x+2y=14).
Step 2
Why this answer is correct
The correct answer is D. (14). Use (y=2x-3) from the second equation. Substitution gives (7x=28), so (x=4,\ y=5) and (x+2y=14).
Step 3
Exam Tip
दूसरे समीकरण से (y=2x-3) रखें। पहले में रखने पर (7x=28), इसलिए (x=4,\ y=5) और (x+2y=14)।
Login to save your score, XP, coins and progress. Login
यदि (2x+3y=27) और (4x-y=11), तो (x) का मान क्या होगा?
If (2x+3y=27) and (4x-y=11), what will be the value of (x)?
#linear equations
#substitution
#fraction value
#medium
#class 10
A (x=3)
B (x=4)
C (x=5)
D (x=6)
Explanation opens after your attempt
Step 1
Concept
Use (y=4x-11) from the second equation. Substitution gives (14x-33=27), so \(x=\frac{30}{7}\).
Step 2
Why this answer is correct
The correct answer is B. (x=4). Use (y=4x-11) from the second equation. Substitution gives (14x-33=27), so \(x=\frac{30}{7}\).
Step 3
Exam Tip
दूसरे समीकरण से (y=4x-11) रखें। पहले में रखने पर (14x-33=27), इसलिए \(x=\frac{30}{7}\) आता है।
Login to save your score, XP, coins and progress. Login
समीकरणों (3x+4y=38) और (3x-y=13) से (y) का मान ज्ञात कीजिए।
Find the value of (y) from (3x+4y=38) and (3x-y=13).
#linear equations
#elimination
#value of y
#medium
#class 10
A (y=3)
B (y=4)
C (y=5)
D (y=6)
Explanation opens after your attempt
Step 1
Concept
Subtracting the second equation from the first gives (5y=25). Therefore (y=5).
Step 2
Why this answer is correct
The correct answer is C. (y=5). Subtracting the second equation from the first gives (5y=25). Therefore (y=5).
Step 3
Exam Tip
पहले समीकरण से दूसरा घटाने पर (5y=25) मिलता है। इसलिए (y=5)।
Login to save your score, XP, coins and progress. Login
यदि (2x-5y=-1) और (3x+5y=31), तो (x) का मान क्या है?
If (2x-5y=-1) and (3x+5y=31), what is the value of (x)?
#linear equations
#elimination
#value of x
#medium
#class 10
A (x=4)
B (x=5)
C (x=6)
D (x=7)
Explanation opens after your attempt
Step 1
Concept
Adding both equations gives (5x=30). Therefore (x=6).
Step 2
Why this answer is correct
The correct answer is C. (x=6). Adding both equations gives (5x=30). Therefore (x=6).
Step 3
Exam Tip
दोनों समीकरण जोड़ने पर (5x=30) मिलता है। इसलिए (x=6)।
Login to save your score, XP, coins and progress. Login
यदि (4x+y=22) और (3x-2y=1), तो (y) का मान क्या होगा?
If (4x+y=22) and (3x-2y=1), what will be the value of (y)?
#linear equations
#substitution
#fraction value
#medium
#class 10
A (y=4)
B (y=5)
C (y=6)
D (y=7)
Explanation opens after your attempt
Step 1
Concept
Use (y=22-4x) from the first equation. Substituting in the second gives (11x=45), then \(y=\frac{62}{11}\).
Step 2
Why this answer is correct
The correct answer is C. (y=6). Use (y=22-4x) from the first equation. Substituting in the second gives (11x=45), then \(y=\frac{62}{11}\).
Step 3
Exam Tip
पहले समीकरण से (y=22-4x) रखें। दूसरे में रखने पर (11x=45), फिर \(y=\frac{62}{11}\) मिलता है।
Login to save your score, XP, coins and progress. Login
यदि (3x+2y=20) और (x-y=1), तो (3x-y) का मान क्या है?
If (3x+2y=20) and (x-y=1), what is the value of (3x-y)?
#linear equations
#substitution
#expression value
#medium
#class 10
A (8)
B (9)
C (10)
D (11)
Explanation opens after your attempt
Step 1
Concept
Using (x=y+1) gives (3y+3+2y=20), so \(y=\frac{17}{5}\) and \(x=\frac{22}{5}\). Then \(3x-y=\frac{49}{5}\).
Step 2
Why this answer is correct
The correct answer is D. (11). Using (x=y+1) gives (3y+3+2y=20), so \(y=\frac{17}{5}\) and \(x=\frac{22}{5}\). Then \(3x-y=\frac{49}{5}\).
Step 3
Exam Tip
(x=y+1) रखने पर (3y+3+2y=20), इसलिए \(y=\frac{17}{5}\) और \(x=\frac{22}{5}\)। तब \(3x-y=\frac{49}{5}\) है।
Login to save your score, XP, coins and progress. Login
यदि (9x-2y=35) और (3x+2y=13), तो (x) का मान क्या है?
If (9x-2y=35) and (3x+2y=13), what is the value of (x)?
#linear equations
#elimination
#value of x
#medium
#class 10
A (x=2)
B (x=3)
C (x=4)
D (x=5)
Explanation opens after your attempt
Step 1
Concept
Adding both equations gives (12x=48). Therefore (x=4).
Step 2
Why this answer is correct
The correct answer is C. (x=4). Adding both equations gives (12x=48). Therefore (x=4).
Step 3
Exam Tip
दोनों समीकरण जोड़ने पर (12x=48) मिलता है। इसलिए (x=4)।
Login to save your score, XP, coins and progress. Login
समीकरणों (4x+7y=41) और (4x+3y=25) से (y) का मान क्या है?
What is the value of (y) from (4x+7y=41) and (4x+3y=25)?
#linear equations
#elimination
#value of y
#medium
#class 10
A (y=2)
B (y=3)
C (y=4)
D (y=5)
Explanation opens after your attempt
Step 1
Concept
Subtracting the second equation from the first gives (4y=16). Therefore (y=4).
Step 2
Why this answer is correct
The correct answer is C. (y=4). Subtracting the second equation from the first gives (4y=16). Therefore (y=4).
Step 3
Exam Tip
पहले समीकरण से दूसरा घटाने पर (4y=16) मिलता है। इसलिए (y=4)।
Login to save your score, XP, coins and progress. Login
यदि (ax+2y=16) और (x+y=7) का हल (x=2,\ y=5) है, तो (a) का मान क्या होगा?
If (ax+2y=16) and (x+y=7) have solution (x=2,\ y=5), what will be the value of (a)?
#linear equations
#parameter
#value of a
#medium
#class 10
A (1)
B (2)
C (3)
D (4)
Explanation opens after your attempt
Step 1
Concept
Substituting (x=2,\ y=5) gives (2a+10=16). Therefore (a=3).
Step 2
Why this answer is correct
The correct answer is C. (3). Substituting (x=2,\ y=5) gives (2a+10=16). Therefore (a=3).
Step 3
Exam Tip
(x=2,\ y=5) रखने पर (2a+10=16) मिलता है। इसलिए (a=3)।
Login to save your score, XP, coins and progress. Login
यदि (x+y=12) और (2x-3y=9), तो (y) का मान क्या होगा?
If (x+y=12) and (2x-3y=9), what will be the value of (y)?
#linear equations
#substitution
#value of y
#medium
#class 10
A (y=2)
B (y=3)
C (y=4)
D (y=5)
Explanation opens after your attempt
Step 1
Concept
Using (x=12-y) gives (24-2y-3y=9). Thus (5y=15), so (y=3).
Step 2
Why this answer is correct
The correct answer is B. (y=3). Using (x=12-y) gives (24-2y-3y=9). Thus (5y=15), so (y=3).
Step 3
Exam Tip
(x=12-y) रखने पर (24-2y-3y=9) मिलता है। इससे (5y=15), इसलिए (y=3)।
Login to save your score, XP, coins and progress. Login
समीकरणों (8x-3y=25) और (2x+3y=17) से (x) का मान क्या है?
What is the value of (x) from (8x-3y=25) and (2x+3y=17)?
#linear equations
#elimination
#fraction value
#medium
#class 10
A (x=3)
B (x=4)
C (x=5)
D (x=6)
Explanation opens after your attempt
Step 1
Concept
Adding both equations gives (10x=42). Therefore \(x=\frac{21}{5}\).
Step 2
Why this answer is correct
The correct answer is B. (x=4). Adding both equations gives (10x=42). Therefore \(x=\frac{21}{5}\).
Step 3
Exam Tip
दोनों समीकरण जोड़ने पर (10x=42) मिलता है। इसलिए \(x=\frac{21}{5}\) है।
Login to save your score, XP, coins and progress. Login
यदि (x=2y+3) और (3x-4y=17), तो (y) का मान क्या है?
If (x=2y+3) and (3x-4y=17), what is the value of (y)?
#linear equations
#substitution
#value of y
#medium
#class 10
A (y=2)
B (y=3)
C (y=4)
D (y=5)
Explanation opens after your attempt
Step 1
Concept
Substituting (x=2y+3) gives (6y+9-4y=17). Thus (2y=8), so (y=4).
Step 2
Why this answer is correct
The correct answer is C. (y=4). Substituting (x=2y+3) gives (6y+9-4y=17). Thus (2y=8), so (y=4).
Step 3
Exam Tip
(x=2y+3) रखने पर (6y+9-4y=17) मिलता है। इससे (2y=8), इसलिए (y=4)।
Login to save your score, XP, coins and progress. Login
समीकरणों (5x-4y=2) और (3x+4y=30) को हल करने पर (x+y) का मान क्या होगा?
On solving (5x-4y=2) and (3x+4y=30), what will be the value of (x+y)?
#linear equations
#elimination
#expression value
#medium
#class 10
A (7)
B (8)
C (9)
D (10)
Explanation opens after your attempt
Step 1
Concept
Adding both equations gives (8x=32), so (x=4). Then (3x+4y=30) gives \(y=\frac{9}{2}\), so \(x+y=\frac{17}{2}\).
Step 2
Why this answer is correct
The correct answer is D. (10). Adding both equations gives (8x=32), so (x=4). Then (3x+4y=30) gives \(y=\frac{9}{2}\), so \(x+y=\frac{17}{2}\).
Step 3
Exam Tip
दोनों समीकरण जोड़ने पर (8x=32), इसलिए (x=4)। फिर (3x+4y=30) से \(y=\frac{9}{2}\), अतः \(x+y=\frac{17}{2}\)।
Login to save your score, XP, coins and progress. Login
यदि (2x+7y=36) और (2x+3y=20), तो (y) का मान क्या है?
If (2x+7y=36) and (2x+3y=20), what is the value of (y)?
#linear equations
#elimination
#value of y
#medium
#class 10
A (y=2)
B (y=3)
C (y=4)
D (y=5)
Explanation opens after your attempt
Step 1
Concept
Subtracting the second equation from the first gives (4y=16). Therefore (y=4).
Step 2
Why this answer is correct
The correct answer is C. (y=4). Subtracting the second equation from the first gives (4y=16). Therefore (y=4).
Step 3
Exam Tip
पहले समीकरण से दूसरा घटाने पर (4y=16)। इसलिए (y=4)।
Login to save your score, XP, coins and progress. Login
यदि (5x+3y=31) और (2x+3y=16), तो (x) का मान क्या है?
If (5x+3y=31) and (2x+3y=16), what is the value of (x)?
#linear equations
#elimination
#value of x
#medium
#class 10
A (x=3)
B (x=4)
C (x=5)
D (x=6)
Explanation opens after your attempt
Step 1
Concept
Subtracting the second equation from the first gives (3x=15). Therefore (x=5).
Step 2
Why this answer is correct
The correct answer is C. (x=5). Subtracting the second equation from the first gives (3x=15). Therefore (x=5).
Step 3
Exam Tip
पहले समीकरण से दूसरा घटाने पर (3x=15) मिलता है। इसलिए (x=5)।
Login to save your score, XP, coins and progress. Login
यदि (2x-y=9) और (x+2y=13), तो (2x+y) का मान क्या है?
If (2x-y=9) and (x+2y=13), what is the value of (2x+y)?
#linear equations
#substitution
#expression value
#medium
#class 10
A (13)
B (14)
C (15)
D (16)
Explanation opens after your attempt
Step 1
Concept
Use (y=2x-9) from the first equation. Solving gives \(x=\frac{31}{5}\) and \(y=\frac{17}{5}\), so \(2x+y=\frac{79}{5}\).
Step 2
Why this answer is correct
The correct answer is D. (16). Use (y=2x-9) from the first equation. Solving gives \(x=\frac{31}{5}\) and \(y=\frac{17}{5}\), so \(2x+y=\frac{79}{5}\).
Step 3
Exam Tip
पहले समीकरण से (y=2x-9) रखें। हल करने पर \(x=\frac{31}{5}\) और \(y=\frac{17}{5}\), इसलिए \(2x+y=\frac{79}{5}\) है।
Login to save your score, XP, coins and progress. Login
यदि (3x+2y=23) और (5x-2y=17), तो (x-y) का मान क्या है?
If (3x+2y=23) and (5x-2y=17), what is the value of (x-y)?
#linear equations
#elimination
#difference value
#medium
#class 10
A (1)
B (2)
C (3)
D (4)
Explanation opens after your attempt
Step 1
Concept
Adding both equations gives (8x=40), so (x=5). Then (3x+2y=23) gives (y=4), so (x-y=1).
Step 2
Why this answer is correct
The correct answer is C. (3). Adding both equations gives (8x=40), so (x=5). Then (3x+2y=23) gives (y=4), so (x-y=1).
Step 3
Exam Tip
दोनों समीकरण जोड़ने पर (8x=40), इसलिए (x=5)। फिर (3x+2y=23) से (y=4), इसलिए (x-y=1)।
Login to save your score, XP, coins and progress. Login
यदि (x+2y=11) और (3x-y=8), तो (x+y) का मान क्या है?
If (x+2y=11) and (3x-y=8), what is the value of (x+y)?
#linear equations
#substitution
#sum value
#medium
#class 10
A (5)
B (6)
C (7)
D (8)
Explanation opens after your attempt
Step 1
Concept
Use (x=11-2y) from the first equation. Solving gives (y=3) and (x=5), so (x+y=8).
Step 2
Why this answer is correct
The correct answer is D. (8). Use (x=11-2y) from the first equation. Solving gives (y=3) and (x=5), so (x+y=8).
Step 3
Exam Tip
पहले समीकरण से (x=11-2y) रखें। हल करने पर (y=3) और (x=5), इसलिए (x+y=8)।
Login to save your score, XP, coins and progress. Login
यदि (4x-y=17) और (2x+3y=19), तो (x) का मान क्या होगा?
If (4x-y=17) and (2x+3y=19), what will be the value of (x)?
#linear equations
#substitution
#value of x
#medium
#class 10
A (x=3)
B (x=4)
C (x=5)
D (x=6)
Explanation opens after your attempt
Step 1
Concept
From the first equation use (y=4x-17). Then (2x+3(4x-17)=19) gives (x=5).
Step 2
Why this answer is correct
The correct answer is C. (x=5). From the first equation use (y=4x-17). Then (2x+3(4x-17)=19) gives (x=5).
Step 3
Exam Tip
पहले समीकरण से (y=4x-17) रखें। फिर (2x+3(4x-17)=19) से (x=5) मिलता है।
Login to save your score, XP, coins and progress. Login
