यदि (2x-y=9) और (x+2y=13), तो (2x+y) का मान क्या है?

If (2x-y=9) and (x+2y=13), what is the value of (2x+y)?

Explanation opens after your attempt
Correct Answer

D. (16)

Step 1

Concept

Use (y=2x-9) from the first equation. Solving gives \(x=\frac{31}{5}\) and \(y=\frac{17}{5}\), so \(2x+y=\frac{79}{5}\).

Step 2

Why this answer is correct

The correct answer is D. (16). Use (y=2x-9) from the first equation. Solving gives \(x=\frac{31}{5}\) and \(y=\frac{17}{5}\), so \(2x+y=\frac{79}{5}\).

Step 3

Exam Tip

पहले समीकरण से (y=2x-9) रखें। हल करने पर \(x=\frac{31}{5}\) और \(y=\frac{17}{5}\), इसलिए \(2x+y=\frac{79}{5}\) है।

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Mathematics Answer, Explanation and Revision Hints

यदि (2x-y=9) और (x+2y=13), तो (2x+y) का मान क्या है? / If (2x-y=9) and (x+2y=13), what is the value of (2x+y)?

Correct Answer: D. (16). Explanation: पहले समीकरण से (y=2x-9) रखें। हल करने पर \(x=\frac{31}{5}\) और \(y=\frac{17}{5}\), इसलिए \(2x+y=\frac{79}{5}\) है। / Use (y=2x-9) from the first equation. Solving gives \(x=\frac{31}{5}\) and \(y=\frac{17}{5}\), so \(2x+y=\frac{79}{5}\).

Which concept should I revise for this Mathematics MCQ?

Use (y=2x-9) from the first equation. Solving gives \(x=\frac{31}{5}\) and \(y=\frac{17}{5}\), so \(2x+y=\frac{79}{5}\).

What exam hint can help solve this Mathematics question?

पहले समीकरण से (y=2x-9) रखें। हल करने पर \(x=\frac{31}{5}\) और \(y=\frac{17}{5}\), इसलिए \(2x+y=\frac{79}{5}\) है।