(p(x)=x-2 -1) के लिए (p(-1)) क्या है?
For (p(x)=x-2 -1), what is (p(-1))?
#polynomials
#value
#zero
#easy
A (0)
B (-2)
C (1)
D (2)
Explanation opens after your attempt
Step 1
Concept
(p(-1)=(-1)2 -1=1-1=0). Use brackets when substituting a negative value.
Step 2
Why this answer is correct
The correct answer is A. (0). (p(-1)=(-1)2 -1=1-1=0). Use brackets when substituting a negative value.
Step 3
Exam Tip
(p(-1)=(-1)2 -1=1-1=0) है। कोष्ठक लगाकर ऋणात्मक मान रखें।
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(p(x)=4x-8) में (x=2) रखने पर क्या निष्कर्ष निकलेगा?
What conclusion follows when (x=2) is substituted in (p(x)=4x-8)?
#polynomials
#zero
#reasoning
#easy
A (2) शून्यक है / (2) is a zero
B (2) घात है / (2) is the degree
C (2) गुणांक है / (2) is the coefficient
D (2) नियत पद है / (2) is the constant term
Explanation opens after your attempt
Correct Answer
A. (2) शून्यक है / (2) is a zero
Step 1
Concept
(p(2)=4\cdot2-8=0), so (2) is a zero. To test a zero, the value must be (0).
Step 2
Why this answer is correct
The correct answer is A. (2) शून्यक है / (2) is a zero. (p(2)=4\cdot2-8=0), so (2) is a zero. To test a zero, the value must be (0).
Step 3
Exam Tip
(p(2)=4\cdot2-8=0), इसलिए (2) शून्यक है। शून्यक जांचने के लिए मान (0) आना चाहिए।
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बहुपद \(x^3-1\) में (x=1) रखने पर मान क्या है?
What is the value of \(x^3-1\) when (x=1)?
#polynomials
#value
#zero
#easy
A (0)
B (1)
C (2)
D (3)
Explanation opens after your attempt
Step 1
Concept
\(1^3-1=0\). So (1) is also a zero of this polynomial.
Step 2
Why this answer is correct
The correct answer is A. (0). \(1^3-1=0\). So (1) is also a zero of this polynomial.
Step 3
Exam Tip
\(1^3-1=0\) है। इसलिए (1) इस बहुपद का शून्यक भी है।
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बहुपद \(x^2-9\) का कौन सा मान शून्यक है?
Which value is a zero of the polynomial \(x^2-9\)?
#polynomials
#zero
#quadratic
#easy
A (2)
B (3)
C (4)
D (9)
Explanation opens after your attempt
Step 1
Concept
\(3^2-9=0\), so (3) is a zero. Substituting options is an easy method.
Step 2
Why this answer is correct
The correct answer is B. (3). \(3^2-9=0\), so (3) is a zero. Substituting options is an easy method.
Step 3
Exam Tip
\(3^2-9=0\), इसलिए (3) शून्यक है। विकल्पों को रखकर जांचना आसान तरीका है।
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(p(x)=5x+10) का शून्यक कौन सा है?
Which is the zero of (p(x)=5x+10)?
#polynomials
#zero
#linear
#easy
A (2)
B (-2)
C (5)
D (-5)
Explanation opens after your attempt
Step 1
Concept
From (5x+10=0), we get (x=-2). Do not forget the sign change.
Step 2
Why this answer is correct
The correct answer is B. (-2). From (5x+10=0), we get (x=-2). Do not forget the sign change.
Step 3
Exam Tip
(5x+10=0) से (x=-2) मिलता है। चिह्न बदलना न भूलें।
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यदि (p(x)=3x-12) है, तो इसका शून्यक क्या है?
If (p(x)=3x-12), what is its zero?
#polynomials
#zero
#linear
#easy
A (3)
B (4)
C (-4)
D (12)
Explanation opens after your attempt
Step 1
Concept
From (3x-12=0), we get (x=4). For a linear polynomial, form a simple equation.
Step 2
Why this answer is correct
The correct answer is B. (4). From (3x-12=0), we get (x=4). For a linear polynomial, form a simple equation.
Step 3
Exam Tip
(3x-12=0) से (x=4) मिलता है। रैखिक बहुपद में सीधे समीकरण बनाएं।
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कौन सा मान (p(x)=x+4) का शून्यक है?
Which value is a zero of (p(x)=x+4)?
#polynomials
#zero
#linear
#easy
A (4)
B (-4)
C (0)
D (1)
Explanation opens after your attempt
Step 1
Concept
(p(-4)=-4+4=0), so (-4) is the zero. For (x+a), the zero is (-a).
Step 2
Why this answer is correct
The correct answer is B. (-4). (p(-4)=-4+4=0), so (-4) is the zero. For (x+a), the zero is (-a).
Step 3
Exam Tip
(p(-4)=-4+4=0), इसलिए (-4) शून्यक है। रैखिक बहुपद (x+a) का शून्यक (-a) होता है।
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यदि (p(x)=x-6) है तो (p(6)) क्या होगा?
If (p(x)=x-6), what is (p(6))?
#polynomials
#zero
#value
#easy
A (0)
B (1)
C (6)
D (12)
Explanation opens after your attempt
Step 1
Concept
(p(6)=6-6=0), so (6) is a zero of the polynomial. At a zero, the polynomial value is (0).
Step 2
Why this answer is correct
The correct answer is A. (0). (p(6)=6-6=0), so (6) is a zero of the polynomial. At a zero, the polynomial value is (0).
Step 3
Exam Tip
(p(6)=6-6=0), इसलिए (6) इस बहुपद का शून्यक है। शून्यक पर बहुपद का मान (0) आता है।
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यदि (p(x)=x-2 -4) है तो (p(2)) कितना है?
If (p(x)=x-2 -4), what is (p(2))?
#quadratic equations
#polynomial value
#zero
A (0)
B (2)
C (4)
D (-4)
Explanation opens after your attempt
Step 1
Concept
(p(2)=22 -4=0). So (2) is a zero of this polynomial.
Step 2
Why this answer is correct
The correct answer is A. (0). (p(2)=22 -4=0). So (2) is a zero of this polynomial.
Step 3
Exam Tip
(p(2)=22 -4=0) है। इसलिए (2) इस बहुपद का शून्यक है।
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यदि (p(x)=x-2 -1) है तो (p(1)) कितना है?
If (p(x)=x-2 -1), what is (p(1))?
#quadratic equations
#polynomial value
#zero
A (0)
B (1)
C \(-1\)
D (2)
Explanation opens after your attempt
Step 1
Concept
(p(1)=12 -1=0). When (p(a)=0), (a) is called a zero.
Step 2
Why this answer is correct
The correct answer is A. (0). (p(1)=12 -1=0). When (p(a)=0), (a) is called a zero.
Step 3
Exam Tip
(p(1)=12 -1=0) है। जब (p(a)=0) हो तो (a) शून्यक कहलाता है।
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यदि (p(x)=x-3 -2x), तो (p\(\sqrt{2}\)) क्या है?
If (p(x)=x-3 -2x), what is (p\(\sqrt{2}\))?
#cubic polynomial
#irrational value
#zero
A (0)
B \(\sqrt{2}\)
C \(2\sqrt{2}\)
D (4)
Explanation opens after your attempt
Step 1
Concept
(\(\sqrt{2}\)3 =2\sqrt{2}), so \(2\sqrt{2}-2\sqrt{2}=0\). Remember (\(\sqrt{a}\)3 =a\sqrt{a}).
Step 2
Why this answer is correct
The correct answer is A. (0). (\(\sqrt{2}\)3 =2\sqrt{2}), so \(2\sqrt{2}-2\sqrt{2}=0\). Remember (\(\sqrt{a}\)3 =a\sqrt{a}).
Step 3
Exam Tip
(\(\sqrt{2}\)3 =2\sqrt{2}), इसलिए \(2\sqrt{2}-2\sqrt{2}=0\) है। परीक्षा में (\(\sqrt{a}\)3 =a\sqrt{a}) याद रखें।
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यदि \(x=2+\sqrt{5}\), तो \(x^2-4x-1\) का मान क्या होगा?
If \(x=2+\sqrt{5}\), what is the value of \(x^2-4x-1\)?
#irrational equation
#polynomial value
#zero
A (0)
B (1)
C \(\sqrt{5}\)
D \(4\sqrt{5}\)
Explanation opens after your attempt
Step 1
Concept
Since \(x-2=\sqrt{5}\), squaring gives ((x-2)2 =5), so \(x^2-4x-1=0\). In exams square to remove the radical.
Step 2
Why this answer is correct
The correct answer is A. (0). Since \(x-2=\sqrt{5}\), squaring gives ((x-2)2 =5), so \(x^2-4x-1=0\). In exams square to remove the radical.
Step 3
Exam Tip
\(x-2=\sqrt{5}\), इसलिए ((x-2)2 =5) से \(x^2-4x-1=0\) मिलता है। परीक्षा में वर्ग करके अपरिमेय हटाएं।
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यदि (p(x)=x-2 -2x-2) है, तो (p\(1+\sqrt{3}\)) क्या है?
If (p(x)=x-2 -2x-2), what is (p\(1+\sqrt{3}\))?
#polynomial-evaluation
#irrational-input
#zero
A (0)
B \(2\sqrt{3}\)
C (-2)
D (3)
Explanation opens after your attempt
Step 1
Concept
(\(1+\sqrt{3}\)2 -2\(1+\sqrt{3}\)-2=1+2\sqrt{3}+3-2-2\sqrt{3}-2=0). Do not forget the middle term while expanding the square.
Step 2
Why this answer is correct
The correct answer is A. (0). (\(1+\sqrt{3}\)2 -2\(1+\sqrt{3}\)-2=1+2\sqrt{3}+3-2-2\sqrt{3}-2=0). Do not forget the middle term while expanding the square.
Step 3
Exam Tip
(\(1+\sqrt{3}\)2 -2\(1+\sqrt{3}\)-2=1+2\sqrt{3}+3-2-2\sqrt{3}-2=0)। वर्ग खोलते समय बीच का पद न भूलें।
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कौन सा विकल्प संख्या (0) के बारे में सही है?
Which option is correct about the number (0)?
#zero
#rational-number
#real-number
A यह परिमेय और वास्तविक है / It is rational and real
B यह अपरिमेय है / It is irrational
C यह वास्तविक नहीं है / It is not real
D यह प्राकृतिक संख्या अवश्य है / It must be natural
Explanation opens after your attempt
Correct Answer
A. यह परिमेय और वास्तविक है / It is rational and real
Step 1
Concept
(0) can be written as \(\frac{0}{1}\) so it is rational. It also lies on the number line.
Step 2
Why this answer is correct
The correct answer is A. यह परिमेय और वास्तविक है / It is rational and real. (0) can be written as \(\frac{0}{1}\) so it is rational. It also lies on the number line.
Step 3
Exam Tip
\(0=\frac{0}{1}\) लिखा जा सकता है इसलिए यह परिमेय है। यह संख्या रेखा पर भी आता है।
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यदि (b) एक अपरिमेय संख्या है तो (b+0) किस प्रकार की संख्या होगी?
If (b) is an irrational number then what type of number is (b+0)?
#irrational-numbers
#zero
#properties
A अपरिमेय संख्या / Irrational number
B परिमेय संख्या / Rational number
C पूर्णांक / Integer
D हमेशा शून्य / Always zero
Explanation opens after your attempt
Correct Answer
A. अपरिमेय संख्या / Irrational number
Step 1
Concept
Adding (0) leaves the irrational number unchanged. Hence (b+0=b) is irrational.
Step 2
Why this answer is correct
The correct answer is A. अपरिमेय संख्या / Irrational number. Adding (0) leaves the irrational number unchanged. Hence (b+0=b) is irrational.
Step 3
Exam Tip
(0) जोड़ने से अपरिमेय संख्या वही रहती है। इसलिए (b+0=b) अपरिमेय है।
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यदि (a) एक परिमेय संख्या है तो (a+0) किस प्रकार की संख्या होगी?
If (a) is a rational number then what type of number is (a+0)?
#rational-numbers
#zero
#properties
A परिमेय संख्या / Rational number
B अपरिमेय संख्या / Irrational number
C अवास्तविक संख्या / Non real number
D हमेशा प्राकृतिक संख्या / Always natural number
Explanation opens after your attempt
Correct Answer
A. परिमेय संख्या / Rational number
Step 1
Concept
Adding (0) does not change the number. So (a+0=a) remains rational.
Step 2
Why this answer is correct
The correct answer is A. परिमेय संख्या / Rational number. Adding (0) does not change the number. So (a+0=a) remains rational.
Step 3
Exam Tip
(0) जोड़ने से संख्या नहीं बदलती। इसलिए (a+0=a) परिमेय रहेगा।
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कौन सा विकल्प अपरिमेय संख्या को शून्य से गुणा करने का परिणाम दिखाता है?
Which option shows the result of multiplying an irrational number by zero?
#zero
#multiplication
#rational-result
A (0) जो परिमेय है / (0) which is rational
B हमेशा अपरिमेय / Always irrational
C हमेशा ऋणात्मक / Always negative
D हमेशा अवास्तविक / Always non real
Explanation opens after your attempt
Correct Answer
A. (0) जो परिमेय है / (0) which is rational
Step 1
Concept
Multiplying any real number by (0) gives (0). (0) is a rational number.
Step 2
Why this answer is correct
The correct answer is A. (0) जो परिमेय है / (0) which is rational. Multiplying any real number by (0) gives (0). (0) is a rational number.
Step 3
Exam Tip
किसी भी वास्तविक संख्या को (0) से गुणा करने पर (0) मिलता है। (0) परिमेय संख्या है।
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संख्या (0) किस प्रकार की संख्या है?
What type of number is (0)?
#zero
#rational-numbers
#real-numbers
A परिमेय और वास्तविक / Rational and real
B अपरिमेय / Irrational
C अवास्तविक / Non real
D केवल ऋणात्मक / Negative only
Explanation opens after your attempt
Correct Answer
A. परिमेय और वास्तविक / Rational and real
Step 1
Concept
(0) can be written as \(\frac{0}{1}\) so it is rational. It is also a real number.
Step 2
Why this answer is correct
The correct answer is A. परिमेय और वास्तविक / Rational and real. (0) can be written as \(\frac{0}{1}\) so it is rational. It is also a real number.
Step 3
Exam Tip
\(0=\frac{0}{1}\) लिखा जा सकता है इसलिए यह परिमेय है। यह वास्तविक संख्या भी है।
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यदि किसी ग्राफ का एक भाग (x)-अक्ष के ऊपर और दूसरा भाग नीचे है तथा बीच में ((9,0)) है तो ((9,0)) क्या दर्शाता है?
If one part of a graph is above the (x)-axis and another part is below it with ((9,0)) between them, what does ((9,0)) represent?
#sign-change
#crossing
#zero
A (x=9) शून्यक है / (x=9) is a zero
B (y=9) शून्यक है / (y=9) is a zero
C बहुपद स्थिर है / The polynomial is constant
D शून्यक नहीं है / It is not a zero
Explanation opens after your attempt
Correct Answer
A. (x=9) शून्यक है / (x=9) is a zero
Step 1
Concept
((9,0)) lies on the (x)-axis so (p(9)=0). Moving from above to below also shows crossing.
Step 2
Why this answer is correct
The correct answer is A. (x=9) शून्यक है / (x=9) is a zero. ((9,0)) lies on the (x)-axis so (p(9)=0). Moving from above to below also shows crossing.
Step 3
Exam Tip
((9,0)) (x)-अक्ष पर है इसलिए (p(9)=0) है। ऊपर से नीचे जाना कटान को भी दिखाता है।
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किस स्थिति में (x=3) बहुपद (p(x)) का शून्यक कहलाएगा?
In which situation will (x=3) be called a zero of polynomial (p(x))?
#definition
#zero
#function-value
A जब (p(3)=0) / When (p(3)=0)
B जब (p(0)=3) / When (p(0)=3)
C जब ग्राफ ((0,3)) से गुजरे / When the graph passes through ((0,3))
D जब (p(3)=3) / When (p(3)=3)
Explanation opens after your attempt
Correct Answer
A. जब (p(3)=0) / When (p(3)=0)
Step 1
Concept
A zero is the (x)-value at which the polynomial value is zero. In exams check (p(a)=0).
Step 2
Why this answer is correct
The correct answer is A. जब (p(3)=0) / When (p(3)=0). A zero is the (x)-value at which the polynomial value is zero. In exams check (p(a)=0).
Step 3
Exam Tip
शून्यक वही (x)-मान है जिस पर बहुपद का मान शून्य हो। परीक्षा में (p(a)=0) जांचें।
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किसी बहुपद का ग्राफ (x)-अक्ष से ((7,0)) पर मिलता है। उस बिंदु पर (p(x)) का मान क्या होगा?
A polynomial graph meets the (x)-axis at ((7,0)). What is the value of (p(x)) at that point?
#x-axis
#function-value
#zero
A (0)
B (7)
C (-7)
D (1)
Explanation opens after your attempt
Step 1
Concept
Every point on the (x)-axis has (y=0). Therefore (p(7)=0).
Step 2
Why this answer is correct
The correct answer is A. (0). Every point on the (x)-axis has (y=0). Therefore (p(7)=0).
Step 3
Exam Tip
(x)-अक्ष पर हर बिंदु का (y)-मान (0) होता है। इसलिए (p(7)=0) होगा।
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यदि ग्राफ (x)-अक्ष को ((0,0)) पर काटता है तो कौन सा निष्कर्ष निश्चित है?
If a graph cuts the (x)-axis at ((0,0)), which conclusion is certain?
#origin
#zero
#graphical-meaning
A (0) बहुपद का शून्यक है / (0) is a zero of the polynomial
B बहुपद की डिग्री (0) है / The degree of the polynomial is (0)
C सभी शून्यक (0) हैं / All zeroes are (0)
D ग्राफ (y)-अक्ष के समानांतर है / The graph is parallel to the (y)-axis
Explanation opens after your attempt
Correct Answer
A. (0) बहुपद का शून्यक है / (0) is a zero of the polynomial
Step 1
Concept
Meeting at the origin shows (p(0)=0). It only confirms that (0) is a zero.
Step 2
Why this answer is correct
The correct answer is A. (0) बहुपद का शून्यक है / (0) is a zero of the polynomial. Meeting at the origin shows (p(0)=0). It only confirms that (0) is a zero.
Step 3
Exam Tip
मूल बिंदु पर मिलना (p(0)=0) बताता है। इससे केवल (0) का शून्यक होना निश्चित है।
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बहुपद (p(x)=3x+6) के ग्राफ का (x)-अक्ष से प्रतिच्छेद कौन सा है?
What is the (x)-intercept of the graph of (p(x)=3x+6)?
#linear-polynomial
#x-intercept
#zero
A ((-2,0))
B ((2,0))
C ((0,6))
D ((0,-2))
Explanation opens after your attempt
Correct Answer
A. ((-2,0))
Step 1
Concept
Solving (3x+6=0) gives (x=-2). The (y)-coordinate of an (x)-intercept is always (0).
Step 2
Why this answer is correct
The correct answer is A. ((-2,0)). Solving (3x+6=0) gives (x=-2). The (y)-coordinate of an (x)-intercept is always (0).
Step 3
Exam Tip
(3x+6=0) से (x=-2) मिलता है। (x)-प्रतिच्छेद का (y)-निर्देशांक हमेशा (0) होता है।
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ग्राफ में (p(2)=0) दिख रहा है। इसका ज्यामितीय अर्थ क्या है?
The graph shows (p(2)=0). What is its geometrical meaning?
#graphical-meaning
#function-value
#zero
A ग्राफ (x)-अक्ष को ((2,0)) पर मिलता है / The graph meets the (x)-axis at ((2,0))
B ग्राफ (y)-अक्ष को ((2,0)) पर मिलता है / The graph meets the (y)-axis at ((2,0))
C ग्राफ का शीर्ष ((0,2)) है / The vertex is ((0,2))
D ग्राफ (x=2) के समानांतर है / The graph is parallel to (x=2)
Explanation opens after your attempt
Correct Answer
A. ग्राफ (x)-अक्ष को ((2,0)) पर मिलता है / The graph meets the (x)-axis at ((2,0))
Step 1
Concept
(p(2)=0) means (y=0) at (x=2). So the point lies on the (x)-axis.
Step 2
Why this answer is correct
The correct answer is A. ग्राफ (x)-अक्ष को ((2,0)) पर मिलता है / The graph meets the (x)-axis at ((2,0)). (p(2)=0) means (y=0) at (x=2). So the point lies on the (x)-axis.
Step 3
Exam Tip
(p(2)=0) का अर्थ (x=2) पर (y=0) है। इसलिए बिंदु (x)-अक्ष पर होगा।
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यदि (p(x)=x(x+6)4 (x-3)5 ) है, तो (x=3) पर ग्राफ का व्यवहार क्या होगा?
If (p(x)=x(x+6)4 (x-3)5 ), what will be the graph behavior at (x=3)?
#multiplicity
#crossing
#zero
A ग्राफ (x)-अक्ष को काटेगा / The graph will cross the (x)-axis
B ग्राफ (x)-अक्ष को स्पर्श करेगा / The graph will touch the (x)-axis
C ग्राफ (x)-अक्ष से नहीं मिलेगा / The graph will not meet the (x)-axis
D (x=3) शून्यक नहीं है / (x=3) is not a zero
Explanation opens after your attempt
Correct Answer
A. ग्राफ (x)-अक्ष को काटेगा / The graph will cross the (x)-axis
Step 1
Concept
((x-3)5 ) is an odd-power factor, so the graph crosses at (x=3). Tip: at an odd power the graph usually crosses the axis.
Step 2
Why this answer is correct
The correct answer is A. ग्राफ (x)-अक्ष को काटेगा / The graph will cross the (x)-axis. ((x-3)5 ) is an odd-power factor, so the graph crosses at (x=3). Tip: at an odd power the graph usually crosses the axis.
Step 3
Exam Tip
((x-3)5 ) विषम घात का कारक है, इसलिए (x=3) पर कटान होगा। टिप: विषम घात में ग्राफ सामान्यतः अक्ष पार करता है।
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यदि (p(x)=x-2 -2(b-4)x+(b-4)2 ) है, तो ग्राफ (x)-अक्ष को किस (x)-मान पर स्पर्श करेगा?
If (p(x)=x-2 -2(b-4)x+(b-4)2 ), at which (x)-value will the graph touch the (x)-axis?
#symbolic perfect square
#tangent
#zero
A (x=b-4)
B (x=b+4)
C (x=2b-8)
D (x=4-b)
Explanation opens after your attempt
Correct Answer
A. (x=b-4)
Step 1
Concept
It is ((x-(b-4))2 ), so the repeated zero is (b-4). Tip: a perfect square form shows the zero quickly.
Step 2
Why this answer is correct
The correct answer is A. (x=b-4). It is ((x-(b-4))2 ), so the repeated zero is (b-4). Tip: a perfect square form shows the zero quickly.
Step 3
Exam Tip
यह ((x-(b-4))2 ) है इसलिए दोहराया शून्यक (b-4) है। टिप: पूर्ण वर्ग रूप में शून्यक तुरंत दिखता है।
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यदि (p(x)=x(x-7)4 (x+2)3 ) है, तो (x=7) पर ग्राफ का व्यवहार क्या होगा?
If (p(x)=x(x-7)4 (x+2)3 ), what will be the graph behavior at (x=7)?
#multiplicity
#touching
#zero
A ग्राफ (x)-अक्ष को काटेगा / The graph will cross the (x)-axis
B ग्राफ (x)-अक्ष को स्पर्श करेगा / The graph will touch the (x)-axis
C ग्राफ (x)-अक्ष से नहीं मिलेगा / The graph will not meet the (x)-axis
D (x=7) शून्यक नहीं है / (x=7) is not a zero
Explanation opens after your attempt
Correct Answer
B. ग्राफ (x)-अक्ष को स्पर्श करेगा / The graph will touch the (x)-axis
Step 1
Concept
((x-7)4 ) is an even-power factor, so the graph touches at (x=7). Tip: at an even power the graph usually turns back.
Step 2
Why this answer is correct
The correct answer is B. ग्राफ (x)-अक्ष को स्पर्श करेगा / The graph will touch the (x)-axis. ((x-7)4 ) is an even-power factor, so the graph touches at (x=7). Tip: at an even power the graph usually turns back.
Step 3
Exam Tip
((x-7)4 ) सम घात का कारक है, इसलिए (x=7) पर स्पर्श होगा। टिप: सम घात में ग्राफ आमतौर पर लौटता है।
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यदि (p(x)=x-2 -2(a+3)x+(a+3)2 ) है, तो ग्राफ (x)-अक्ष को किस (x)-मान पर स्पर्श करेगा?
If (p(x)=x-2 -2(a+3)x+(a+3)2 ), at which (x)-value will the graph touch the (x)-axis?
#symbolic perfect square
#tangent
#zero
A (x=a-3)
B (x=a+3)
C (x=2a+6)
D (x=3-a)
Explanation opens after your attempt
Correct Answer
B. (x=a+3)
Step 1
Concept
It is ((x-(a+3))2 ), so the repeated zero is (a+3). Tip: a perfect square form shows the zero quickly.
Step 2
Why this answer is correct
The correct answer is B. (x=a+3). It is ((x-(a+3))2 ), so the repeated zero is (a+3). Tip: a perfect square form shows the zero quickly.
Step 3
Exam Tip
यह ((x-(a+3))2 ) है, इसलिए दोहराया शून्यक (a+3) है। टिप: पूर्ण वर्ग रूप में शून्यक तुरंत दिखता है।
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यदि (p(x)=x(x+4)2 (x-6)) है तो (x=-4) पर ग्राफ का व्यवहार क्या होगा?
If (p(x)=x(x+4)2 (x-6)), what will be the graph behavior at (x=-4)?
#multiplicity
#touching
#zero
A ग्राफ (x)-अक्ष को काटेगा / The graph will cross the (x)-axis
B ग्राफ (x)-अक्ष को स्पर्श करेगा / The graph will touch the (x)-axis
C ग्राफ (x)-अक्ष से नहीं मिलेगा / The graph will not meet the (x)-axis
D (x=-4) शून्यक नहीं है / (x=-4) is not a zero
Explanation opens after your attempt
Correct Answer
B. ग्राफ (x)-अक्ष को स्पर्श करेगा / The graph will touch the (x)-axis
Step 1
Concept
((x+4)2 ) is an even-power factor, so the graph touches at (x=-4). Tip: power (2) shows a repeated zero.
Step 2
Why this answer is correct
The correct answer is B. ग्राफ (x)-अक्ष को स्पर्श करेगा / The graph will touch the (x)-axis. ((x+4)2 ) is an even-power factor, so the graph touches at (x=-4). Tip: power (2) shows a repeated zero.
Step 3
Exam Tip
((x+4)2 ) सम घात का कारक है इसलिए (x=-4) पर स्पर्श होगा। टिप: घात (2) दोहराया शून्यक दिखाती है।
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यदि ग्राफ (y)-अक्ष को ((0,0)) पर छूता है तो शून्यकों के बारे में कौन सा निष्कर्ष सही है?
If a graph touches the (y)-axis at ((0,0)), which conclusion about zeroes is correct?
#origin
#y intercept
#zero
A (0) शून्यक है क्योंकि बिंदु (x)-अक्ष पर भी है / (0) is a zero because the point is also on the (x)-axis
B कोई शून्यक नहीं हो सकता / There can be no zero
C केवल (y)-अक्ष कटान मिला इसलिए शून्यक नहीं / It is only a (y)-intercept, so not a zero
D हर (x) शून्यक है / Every (x) is a zero
Explanation opens after your attempt
Correct Answer
A. (0) शून्यक है क्योंकि बिंदु (x)-अक्ष पर भी है / (0) is a zero because the point is also on the (x)-axis
Step 1
Concept
The origin lies on both axes, so (p(0)=0). Tip: treat ((0,0)) as a special point.
Step 2
Why this answer is correct
The correct answer is A. (0) शून्यक है क्योंकि बिंदु (x)-अक्ष पर भी है / (0) is a zero because the point is also on the (x)-axis. The origin lies on both axes, so (p(0)=0). Tip: treat ((0,0)) as a special point.
Step 3
Exam Tip
मूल बिंदु दोनों अक्षों पर होता है इसलिए (p(0)=0) है। टिप: ((0,0)) को विशेष बिंदु मानें।
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