Concept-wise Practice

standard form MCQ Questions for Class 10

standard form se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.

Practice Questions

123 questions tagged with standard form.

समीकरण \(4=3x-x^2\) का मानक रूप क्या है?

What is the standard form of \(4=3x-x^2\)?

Explanation opens after your attempt
Correct Answer

A. \(x^2-3x+4=0\)

Step 1

Concept

Bringing all terms to one side gives \(x^2-3x+4=0\). In standard form, keep the right side as (0).

Step 2

Why this answer is correct

The correct answer is A. \(x^2-3x+4=0\). Bringing all terms to one side gives \(x^2-3x+4=0\). In standard form, keep the right side as (0).

Step 3

Exam Tip

सभी पद एक तरफ लाने पर \(x^2-3x+4=0\) मिलता है। मानक रूप में दायां पक्ष (0) रखें।

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समीकरण \(x^2-5x+6=0\) में (a,b,c) के मान क्या हैं?

What are the values of (a,b,c) in \(x^2-5x+6=0\)?

Explanation opens after your attempt
Correct Answer

A. (a=1,\ b=-5,\ c=6)

Step 1

Concept

Comparing with standard form gives (a=1,\ b=-5,\ c=6). Pay special attention to signs.

Step 2

Why this answer is correct

The correct answer is A. (a=1,\ b=-5,\ c=6). Comparing with standard form gives (a=1,\ b=-5,\ c=6). Pay special attention to signs.

Step 3

Exam Tip

मानक रूप से मिलाने पर (a=1,\ b=-5,\ c=6) मिलता है। चिन्हों पर विशेष ध्यान रखें।

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द्विघात समीकरण का सामान्य रूप कौन-सा है?

What is the general form of a quadratic equation?

Explanation opens after your attempt
Correct Answer

A. \(ax^2+bx+c=0,\ a\neq 0\)

Step 1

Concept

A quadratic equation has highest power (2) of (x) and \(a\neq 0\). In exams identify the standard form first.

Step 2

Why this answer is correct

The correct answer is A. \(ax^2+bx+c=0,\ a\neq 0\). A quadratic equation has highest power (2) of (x) and \(a\neq 0\). In exams identify the standard form first.

Step 3

Exam Tip

द्विघात समीकरण में (x) की सबसे बड़ी घात (2) होती है और \(a\neq 0\) होता है। परीक्षा में पहले मानक रूप पहचानें।

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((x+3)2=25) को मानक रूप में लिखने पर कौन सा समीकरण मिलेगा?

Which equation is obtained when ((x+3)2=25) is written in standard form?

Explanation opens after your attempt
Correct Answer

A. \(x^2+6x-16=0\)

Step 1

Concept

Here ((x+3)2=x-2+6x+9), and moving (25) left gives (-25). So \(x^2+6x-16=0\) is correct.

Step 2

Why this answer is correct

The correct answer is A. \(x^2+6x-16=0\). Here ((x+3)2=x-2+6x+9), and moving (25) left gives (-25). So \(x^2+6x-16=0\) is correct.

Step 3

Exam Tip

((x+3)2=x-2+6x+9) है और (25) को बाईं ओर लाने पर (-25) बनता है। इसलिए \(x^2+6x-16=0\) सही है।

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किस विकल्प में गलती है जब \(x^2=6x+7\) को मानक रूप में बदला जाता है?

Which option shows the mistake while converting \(x^2=6x+7\) to standard form?

Explanation opens after your attempt
Correct Answer

B. \(x^2+6x+7=0\)

Step 1

Concept

The correct standard form is \(x^2-6x-7=0\). In option (B), the signs of the right-side terms were not changed.

Step 2

Why this answer is correct

The correct answer is B. \(x^2+6x+7=0\). The correct standard form is \(x^2-6x-7=0\). In option (B), the signs of the right-side terms were not changed.

Step 3

Exam Tip

सही मानक रूप \(x^2-6x-7=0\) है। विकल्प (B) में दाईं ओर के पदों के चिन्ह नहीं बदले गए।

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कौन सा समीकरण मानक रूप में लाने पर \(x^2+2x-8=0\) बनता है?

Which equation becomes \(x^2+2x-8=0\) after writing in standard form?

Explanation opens after your attempt
Correct Answer

A. \(x^2+2x=8\)

Step 1

Concept

Moving (8) to the left makes it (-8). So we get \(x^2+2x-8=0\).

Step 2

Why this answer is correct

The correct answer is A. \(x^2+2x=8\). Moving (8) to the left makes it (-8). So we get \(x^2+2x-8=0\).

Step 3

Exam Tip

(8) को बाईं ओर लाने पर (-8) बनता है। इसलिए \(x^2+2x-8=0\) मिलता है।

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यदि (a=2), (b=0), (c=-18) हैं तो समीकरण क्या होगा?

If (a=2), (b=0), (c=-18), what is the equation?

Explanation opens after your attempt
Correct Answer

A. \(2x^2-18=0\)

Step 1

Concept

Substituting in standard form gives \(2x^2+0x-18=0\). This is written as \(2x^2-18=0\).

Step 2

Why this answer is correct

The correct answer is A. \(2x^2-18=0\). Substituting in standard form gives \(2x^2+0x-18=0\). This is written as \(2x^2-18=0\).

Step 3

Exam Tip

मानक रूप में रखने पर \(2x^2+0x-18=0\) मिलता है। इसे \(2x^2-18=0\) लिखते हैं।

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(4x(x-3)=0) का मानक रूप क्या है?

What is the standard form of (4x(x-3)=0)?

Explanation opens after your attempt
Correct Answer

A. \(4x^2-12x=0\)

Step 1

Concept

Multiplying (4x) by both terms gives \(4x^2-12x=0\). Pay attention to the negative sign.

Step 2

Why this answer is correct

The correct answer is A. \(4x^2-12x=0\). Multiplying (4x) by both terms gives \(4x^2-12x=0\). Pay attention to the negative sign.

Step 3

Exam Tip

(4x) को दोनों पदों से गुणा करने पर \(4x^2-12x=0\) मिलता है। ऋण चिन्ह पर ध्यान दें।

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((x-6)(x+2)=0) का मानक रूप कौन सा है?

Which is the standard form of ((x-6)(x+2)=0)?

Explanation opens after your attempt
Correct Answer

A. \(x^2-4x-12=0\)

Step 1

Concept

Expansion gives \(x^2+2x-6x-12=0\). So \(x^2-4x-12=0\) is correct.

Step 2

Why this answer is correct

The correct answer is A. \(x^2-4x-12=0\). Expansion gives \(x^2+2x-6x-12=0\). So \(x^2-4x-12=0\) is correct.

Step 3

Exam Tip

विस्तार से \(x^2+2x-6x-12=0\) मिलता है। इसलिए \(x^2-4x-12=0\) सही है।

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((x+4)(x+5)=0) का विस्तृत रूप क्या है?

What is the expanded form of ((x+4)(x+5)=0)?

Explanation opens after your attempt
Correct Answer

A. \(x^2+9x+20=0\)

Step 1

Concept

Expanding gives \(x^2+5x+4x+20=0\). Combining like terms gives \(x^2+9x+20=0\).

Step 2

Why this answer is correct

The correct answer is A. \(x^2+9x+20=0\). Expanding gives \(x^2+5x+4x+20=0\). Combining like terms gives \(x^2+9x+20=0\).

Step 3

Exam Tip

विस्तार करने पर \(x^2+5x+4x+20=0\) मिलता है। समान पद जोड़कर \(x^2+9x+20=0\) बनता है।

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(2x(x+7)=0) को मानक रूप में लिखिए।

Write (2x(x+7)=0) in standard form.

Explanation opens after your attempt
Correct Answer

A. \(2x^2+14x=0\)

Step 1

Concept

Multiply (2x) by both terms inside the bracket. This gives \(2x^2+14x=0\).

Step 2

Why this answer is correct

The correct answer is A. \(2x^2+14x=0\). Multiply (2x) by both terms inside the bracket. This gives \(2x^2+14x=0\).

Step 3

Exam Tip

(2x) को कोष्ठक के दोनों पदों से गुणा करें। इससे \(2x^2+14x=0\) मिलता है।

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समीकरण \(2x^2=5x+3\) का मानक रूप कौन सा है?

Which is the standard form of \(2x^2=5x+3\)?

Explanation opens after your attempt
Correct Answer

A. \(2x^2-5x-3=0\)

Step 1

Concept

Bringing all terms to one side gives \(2x^2-5x-3=0\). Changing signs is important.

Step 2

Why this answer is correct

The correct answer is A. \(2x^2-5x-3=0\). Bringing all terms to one side gives \(2x^2-5x-3=0\). Changing signs is important.

Step 3

Exam Tip

सभी पद एक तरफ लाने पर \(2x^2-5x-3=0\) मिलता है। चिन्ह बदलना जरूरी है।

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समीकरण \(4x^2+7x=9\) का मानक रूप क्या है?

What is the standard form of \(4x^2+7x=9\)?

Explanation opens after your attempt
Correct Answer

B. \(4x^2+7x-9=0\)

Step 1

Concept

Moving (9) to the left makes it (-9). So the standard form is \(4x^2+7x-9=0\).

Step 2

Why this answer is correct

The correct answer is B. \(4x^2+7x-9=0\). Moving (9) to the left makes it (-9). So the standard form is \(4x^2+7x-9=0\).

Step 3

Exam Tip

दाईं ओर के (9) को बाईं ओर लाने पर (-9) बनता है। इसलिए मानक रूप \(4x^2+7x-9=0\) है।

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समीकरण \(11x^2-6x=0\) में (c) का मान क्या होगा?

What will be the value of (c) in \(11x^2-6x=0\)?

Explanation opens after your attempt
Correct Answer

C. (0)

Step 1

Concept

It can be written as \(11x^2-6x+0=0\). So (c=0).

Step 2

Why this answer is correct

The correct answer is C. (0). It can be written as \(11x^2-6x+0=0\). So (c=0).

Step 3

Exam Tip

इसे \(11x^2-6x+0=0\) लिखा जा सकता है। इसलिए (c=0) है।

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यदि \(x^2+kx+12=0\) एक द्विघात समीकरण है तो (k) किस पद का गुणांक है?

If \(x^2+kx+12=0\) is a quadratic equation, then (k) is the coefficient of which term?

Explanation opens after your attempt
Correct Answer

B. (x) पद(x) term

Step 1

Concept

In \(ax^2+bx+c=0\), (b) is the coefficient of (x). Here in (kx), (k) is the coefficient of (x).

Step 2

Why this answer is correct

The correct answer is B. (x) पद / (x) term. In \(ax^2+bx+c=0\), (b) is the coefficient of (x). Here in (kx), (k) is the coefficient of (x).

Step 3

Exam Tip

मानक रूप \(ax^2+bx+c=0\) में (x) का गुणांक (b) होता है। यहां (kx) में (k) (x) का गुणांक है।

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किस विकल्प में सामान्य गलती है जब \(x^2=5x-6\) को मानक रूप में बदला जाता है?

Which option shows the common mistake while converting \(x^2=5x-6\) to standard form?

Explanation opens after your attempt
Correct Answer

B. \(x^2-5x-6=0\)

Step 1

Concept

The correct form is \(x^2-5x+6=0\). In option (B), the sign of (-6) was not changed.

Step 2

Why this answer is correct

The correct answer is B. \(x^2-5x-6=0\). The correct form is \(x^2-5x+6=0\). In option (B), the sign of (-6) was not changed.

Step 3

Exam Tip

सही रूप \(x^2-5x+6=0\) है। विकल्प (B) में (-6) का चिन्ह नहीं बदला गया।

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कौन सा समीकरण मानक रूप में लाने पर \(x^2-7x+10=0\) बनता है?

Which equation becomes \(x^2-7x+10=0\) after writing in standard form?

Explanation opens after your attempt
Correct Answer

A. \(x^2-7x=-10\)

Step 1

Concept

In \(x^2-7x=-10\), moving (-10) to the left gives (+10). So the standard form is \(x^2-7x+10=0\).

Step 2

Why this answer is correct

The correct answer is A. \(x^2-7x=-10\). In \(x^2-7x=-10\), moving (-10) to the left gives (+10). So the standard form is \(x^2-7x+10=0\).

Step 3

Exam Tip

\(x^2-7x=-10\) में (-10) को बाईं ओर लाने पर (+10) बनता है। इसलिए मानक रूप \(x^2-7x+10=0\) है।

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यदि (a=1), (b=0), (c=-25) हैं तो समीकरण क्या होगा?

If (a=1), (b=0), (c=-25), what is the equation?

Explanation opens after your attempt
Correct Answer

A. \(x^2-25=0\)

Step 1

Concept

Substituting in \(ax^2+bx+c=0\) gives \(x^2+0x-25=0\). This is written as \(x^2-25=0\).

Step 2

Why this answer is correct

The correct answer is A. \(x^2-25=0\). Substituting in \(ax^2+bx+c=0\) gives \(x^2+0x-25=0\). This is written as \(x^2-25=0\).

Step 3

Exam Tip

\(ax^2+bx+c=0\) में रखने पर \(x^2+0x-25=0\) मिलता है। इसे \(x^2-25=0\) लिखते हैं।

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(3x(x-2)=0) का मानक रूप क्या है?

What is the standard form of (3x(x-2)=0)?

Explanation opens after your attempt
Correct Answer

A. \(3x^2-6x=0\)

Step 1

Concept

Multiplying (3x) by both terms gives \(3x^2-6x=0\). Watch the sign.

Step 2

Why this answer is correct

The correct answer is A. \(3x^2-6x=0\). Multiplying (3x) by both terms gives \(3x^2-6x=0\). Watch the sign.

Step 3

Exam Tip

(3x) को दोनों पदों से गुणा करने पर \(3x^2-6x=0\) मिलता है। चिन्ह पर ध्यान दें।

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((x-4)(x+1)=0) का मानक रूप कौन सा है?

Which is the standard form of ((x-4)(x+1)=0)?

Explanation opens after your attempt
Correct Answer

A. \(x^2-3x-4=0\)

Step 1

Concept

Expanding gives \(x^2+x-4x-4=0\). So \(x^2-3x-4=0\) is correct.

Step 2

Why this answer is correct

The correct answer is A. \(x^2-3x-4=0\). Expanding gives \(x^2+x-4x-4=0\). So \(x^2-3x-4=0\) is correct.

Step 3

Exam Tip

विस्तार करने पर \(x^2+x-4x-4=0\) मिलता है। इसलिए \(x^2-3x-4=0\) सही है।

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(x(x+5)=0) को मानक रूप में लिखिए।

Write (x(x+5)=0) in standard form.

Explanation opens after your attempt
Correct Answer

A. \(x^2+5x=0\)

Step 1

Concept

Multiplying gives \(x^2+5x=0\). While opening brackets, multiply each term.

Step 2

Why this answer is correct

The correct answer is A. \(x^2+5x=0\). Multiplying gives \(x^2+5x=0\). While opening brackets, multiply each term.

Step 3

Exam Tip

गुणा करने पर \(x^2+5x=0\) मिलता है। कोष्ठक खोलते समय हर पद से गुणा करें।

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कौन सा समीकरण \(ax^2+bx+c=0\) के मानक रूप में है?

Which equation is in the standard form \(ax^2+bx+c=0\)?

Explanation opens after your attempt
Correct Answer

A. \(x^2+2x+1=0\)

Step 1

Concept

In standard form the right side is (0). Option (A) matches this form.

Step 2

Why this answer is correct

The correct answer is A. \(x^2+2x+1=0\). In standard form the right side is (0). Option (A) matches this form.

Step 3

Exam Tip

मानक रूप में दाईं ओर (0) होता है। विकल्प (A) इसी रूप में है।

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समीकरण \(x^2=4x+12\) का मानक रूप कौन सा है?

Which is the standard form of \(x^2=4x+12\)?

Explanation opens after your attempt
Correct Answer

A. \(x^2-4x-12=0\)

Step 1

Concept

When terms from the right side move left, their signs change. Thus \(x^2-4x-12=0\) is correct.

Step 2

Why this answer is correct

The correct answer is A. \(x^2-4x-12=0\). When terms from the right side move left, their signs change. Thus \(x^2-4x-12=0\) is correct.

Step 3

Exam Tip

दाईं ओर के पदों को बाईं ओर लाने पर चिन्ह बदलते हैं। इसलिए \(x^2-4x-12=0\) सही है।

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समीकरण \(2x^2+5x=3\) का मानक रूप क्या है?

What is the standard form of \(2x^2+5x=3\)?

Explanation opens after your attempt
Correct Answer

B. \(2x^2+5x-3=0\)

Step 1

Concept

Bringing all terms to one side gives \(2x^2+5x-3=0\). Do not forget the sign change.

Step 2

Why this answer is correct

The correct answer is B. \(2x^2+5x-3=0\). Bringing all terms to one side gives \(2x^2+5x-3=0\). Do not forget the sign change.

Step 3

Exam Tip

सभी पद एक तरफ लाने पर \(2x^2+5x-3=0\) मिलता है। चिन्ह बदलना न भूलें।

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किस शर्त पर \(ax^2+bx+c=0\) द्विघात समीकरण कहलाता है?

Under which condition is \(ax^2+bx+c=0\) called a quadratic equation?

Explanation opens after your attempt
Correct Answer

B. \(a\neq0\)

Step 1

Concept

The quadratic term must remain, so \(a\neq0\). If (a=0), it may become linear.

Step 2

Why this answer is correct

The correct answer is B. \(a\neq0\). The quadratic term must remain, so \(a\neq0\). If (a=0), it may become linear.

Step 3

Exam Tip

द्विघात पद बना रहे इसलिए \(a\neq0\) होना चाहिए। परीक्षा में (a=0) होने पर यह रैखिक बन सकता है।

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समीकरण \(4x^2-8x+1=0\) में (c) का मान क्या है?

What is the value of (c) in \(4x^2-8x+1=0\)?

Explanation opens after your attempt
Correct Answer

C. (1)

Step 1

Concept

In standard form, (c) is the constant term. Here the constant term is (1).

Step 2

Why this answer is correct

The correct answer is C. (1). In standard form, (c) is the constant term. Here the constant term is (1).

Step 3

Exam Tip

मानक रूप में (c) स्थिर पद होता है। यहां स्थिर पद (1) है।

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समीकरण \(5x^2-2x+9=0\) में (a) का मान क्या है?

What is the value of (a) in the equation \(5x^2-2x+9=0\)?

Explanation opens after your attempt
Correct Answer

A. (5)

Step 1

Concept

In \(ax^2+bx+c=0\), (a) is the coefficient of \(x^2\). Here (a=5).

Step 2

Why this answer is correct

The correct answer is A. (5). In \(ax^2+bx+c=0\), (a) is the coefficient of \(x^2\). Here (a=5).

Step 3

Exam Tip

मानक रूप \(ax^2+bx+c=0\) में (a) \(x^2\) का गुणांक होता है। यहां (a=5) है।

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यदि (a=17q+16) है, तो (a) को 17 से भाग देने पर संभावित शेषफल क्या होगा?

If (a=17q+16), what is the possible remainder when (a) is divided by 17?

Explanation opens after your attempt
Correct Answer

B. 16

Step 1

Concept

Compare with the standard form (a=bq+r).

Step 2

Why this answer is correct

Here the divisor is 17 and the remainder is 16, which is less than 17.

Step 3

Exam Tip

Always compare the remainder with the divisor to check validity. चरण 1: मानक रूप (a=bq+r) से तुलना करें। चरण 2: यहाँ भाजक 17 है और शेषफल 16 है, जो 17 से छोटा है। चरण 3: शेषफल की वैधता देखने के लिए उसे भाजक से जरूर मिलाएं।

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कौन-सा रूप (a=31q+r) के लिए सही शेषफल की शर्त पूरी करता है?

Which form satisfies the correct remainder condition for (a=31q+r)?

Explanation opens after your attempt
Correct Answer

C. (a=31q+30)

Step 1

Concept

On division by (31), the remainder must be from (0) to (30).

Step 2

Why this answer is correct

In (31q+30), the remainder is (30), which is less than (31).

Step 3

Exam Tip

A remainder (31), (37), or negative is not in standard form. चरण 1: (31) से भाग देने पर शेषफल (0) से (30) तक होना चाहिए। चरण 2: (31q+30) में शेषफल (30) है, जो (31) से छोटा है। चरण 3: शेषफल (31), (37) या ऋणात्मक हो तो वह मानक रूप नहीं होगा।

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(305) को (24) से भाग देने का सही यूक्लिडीय रूप कौन-सा है?

Which is the correct Euclidean form when (305) is divided by (24)?

Explanation opens after your attempt
Correct Answer

A. \(305=24 \times 12+17\)

Step 1

Concept

\(24 \times 12=288\) and \(24 \times 13=312\).

Step 2

Why this answer is correct

Since (312) is greater, \(305=24 \times 12+17\) is correct.

Step 3

Exam Tip

A form with a negative remainder is not the standard Euclidean form. चरण 1: \(24 \times 12=288\) और \(24 \times 13=312\) है। चरण 2: (312) बड़ा है, इसलिए \(305=24 \times 12+17\) सही है। चरण 3: ऋणात्मक शेषफल वाला रूप मानक यूक्लिडीय रूप नहीं होता।

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