समीकरण \(4=3x-x^2\) का मानक रूप क्या है?
What is the standard form of \(4=3x-x^2\)?
#quadratic-equations
#standard-form
#transposition
A \(x^2-3x+4=0\)
B \(x^2+3x+4=0\)
C \(x^2-3x-4=0\)
D \(x^2+3x-4=0\)
Explanation opens after your attempt
Correct Answer
A. \(x^2-3x+4=0\)
Step 1
Concept
Bringing all terms to one side gives \(x^2-3x+4=0\). In standard form, keep the right side as (0).
Step 2
Why this answer is correct
The correct answer is A. \(x^2-3x+4=0\). Bringing all terms to one side gives \(x^2-3x+4=0\). In standard form, keep the right side as (0).
Step 3
Exam Tip
सभी पद एक तरफ लाने पर \(x^2-3x+4=0\) मिलता है। मानक रूप में दायां पक्ष (0) रखें।
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समीकरण \(x^2-5x+6=0\) में (a,b,c) के मान क्या हैं?
What are the values of (a,b,c) in \(x^2-5x+6=0\)?
#quadratic-equations
#coefficients
#standard-form
A (a=1,\ b=-5,\ c=6)
B (a=1,\ b=5,\ c=6)
C (a=-1,\ b=-5,\ c=6)
D (a=6,\ b=-5,\ c=1)
Explanation opens after your attempt
Correct Answer
A. (a=1,\ b=-5,\ c=6)
Step 1
Concept
Comparing with standard form gives (a=1,\ b=-5,\ c=6). Pay special attention to signs.
Step 2
Why this answer is correct
The correct answer is A. (a=1,\ b=-5,\ c=6). Comparing with standard form gives (a=1,\ b=-5,\ c=6). Pay special attention to signs.
Step 3
Exam Tip
मानक रूप से मिलाने पर (a=1,\ b=-5,\ c=6) मिलता है। चिन्हों पर विशेष ध्यान रखें।
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द्विघात समीकरण का सामान्य रूप कौन-सा है?
What is the general form of a quadratic equation?
#quadratic-equations
#introduction
#standard-form
#easy
A \(ax^2+bx+c=0,\ a\neq 0\)
B (ax+b=0)
C \(ax^3+bx+c=0\)
D \(\frac{a}{x}+b=0\)
Explanation opens after your attempt
Correct Answer
A. \(ax^2+bx+c=0,\ a\neq 0\)
Step 1
Concept
A quadratic equation has highest power (2) of (x) and \(a\neq 0\). In exams identify the standard form first.
Step 2
Why this answer is correct
The correct answer is A. \(ax^2+bx+c=0,\ a\neq 0\). A quadratic equation has highest power (2) of (x) and \(a\neq 0\). In exams identify the standard form first.
Step 3
Exam Tip
द्विघात समीकरण में (x) की सबसे बड़ी घात (2) होती है और \(a\neq 0\) होता है। परीक्षा में पहले मानक रूप पहचानें।
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((x+3)2 =25) को मानक रूप में लिखने पर कौन सा समीकरण मिलेगा?
Which equation is obtained when ((x+3)2 =25) is written in standard form?
#quadratic equations
#standard form
#perfect square
A \(x^2+6x-16=0\)
B \(x^2+6x+16=0\)
C \(x^2+3x-25=0\)
D \(x^2+9x-25=0\)
Explanation opens after your attempt
Correct Answer
A. \(x^2+6x-16=0\)
Step 1
Concept
Here ((x+3)2 =x-2 +6x+9), and moving (25) left gives (-25). So \(x^2+6x-16=0\) is correct.
Step 2
Why this answer is correct
The correct answer is A. \(x^2+6x-16=0\). Here ((x+3)2 =x-2 +6x+9), and moving (25) left gives (-25). So \(x^2+6x-16=0\) is correct.
Step 3
Exam Tip
((x+3)2 =x-2 +6x+9) है और (25) को बाईं ओर लाने पर (-25) बनता है। इसलिए \(x^2+6x-16=0\) सही है।
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किस विकल्प में गलती है जब \(x^2=6x+7\) को मानक रूप में बदला जाता है?
Which option shows the mistake while converting \(x^2=6x+7\) to standard form?
#quadratic equations
#common mistake
#standard form
A \(x^2-6x-7=0\)
B \(x^2+6x+7=0\)
C \(x^2-6x=7\)
D \(x^2=6x+7\)
Explanation opens after your attempt
Correct Answer
B. \(x^2+6x+7=0\)
Step 1
Concept
The correct standard form is \(x^2-6x-7=0\). In option (B), the signs of the right-side terms were not changed.
Step 2
Why this answer is correct
The correct answer is B. \(x^2+6x+7=0\). The correct standard form is \(x^2-6x-7=0\). In option (B), the signs of the right-side terms were not changed.
Step 3
Exam Tip
सही मानक रूप \(x^2-6x-7=0\) है। विकल्प (B) में दाईं ओर के पदों के चिन्ह नहीं बदले गए।
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कौन सा समीकरण मानक रूप में लाने पर \(x^2+2x-8=0\) बनता है?
Which equation becomes \(x^2+2x-8=0\) after writing in standard form?
#quadratic equations
#standard form
#reverse form
A \(x^2+2x=8\)
B \(x^2+2x=-8\)
C \(x^2-2x=8\)
D \(x^2-2x=-8\)
Explanation opens after your attempt
Correct Answer
A. \(x^2+2x=8\)
Step 1
Concept
Moving (8) to the left makes it (-8). So we get \(x^2+2x-8=0\).
Step 2
Why this answer is correct
The correct answer is A. \(x^2+2x=8\). Moving (8) to the left makes it (-8). So we get \(x^2+2x-8=0\).
Step 3
Exam Tip
(8) को बाईं ओर लाने पर (-8) बनता है। इसलिए \(x^2+2x-8=0\) मिलता है।
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यदि (a=2), (b=0), (c=-18) हैं तो समीकरण क्या होगा?
If (a=2), (b=0), (c=-18), what is the equation?
#quadratic equations
#forming equation
#standard form
A \(2x^2-18=0\)
B \(2x^2+18=0\)
C \(2x^2+18x=0\)
D \(18x^2-2=0\)
Explanation opens after your attempt
Correct Answer
A. \(2x^2-18=0\)
Step 1
Concept
Substituting in standard form gives \(2x^2+0x-18=0\). This is written as \(2x^2-18=0\).
Step 2
Why this answer is correct
The correct answer is A. \(2x^2-18=0\). Substituting in standard form gives \(2x^2+0x-18=0\). This is written as \(2x^2-18=0\).
Step 3
Exam Tip
मानक रूप में रखने पर \(2x^2+0x-18=0\) मिलता है। इसे \(2x^2-18=0\) लिखते हैं।
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(4x(x-3)=0) का मानक रूप क्या है?
What is the standard form of (4x(x-3)=0)?
#quadratic equations
#expansion
#standard form
A \(4x^2-12x=0\)
B \(4x^2+12x=0\)
C \(x^2-12x=0\)
D (4x-12=0)
Explanation opens after your attempt
Correct Answer
A. \(4x^2-12x=0\)
Step 1
Concept
Multiplying (4x) by both terms gives \(4x^2-12x=0\). Pay attention to the negative sign.
Step 2
Why this answer is correct
The correct answer is A. \(4x^2-12x=0\). Multiplying (4x) by both terms gives \(4x^2-12x=0\). Pay attention to the negative sign.
Step 3
Exam Tip
(4x) को दोनों पदों से गुणा करने पर \(4x^2-12x=0\) मिलता है। ऋण चिन्ह पर ध्यान दें।
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((x-6)(x+2)=0) का मानक रूप कौन सा है?
Which is the standard form of ((x-6)(x+2)=0)?
#quadratic equations
#expansion
#standard form
A \(x^2-4x-12=0\)
B \(x^2+4x-12=0\)
C \(x^2-8x+12=0\)
D \(x^2+8x+12=0\)
Explanation opens after your attempt
Correct Answer
A. \(x^2-4x-12=0\)
Step 1
Concept
Expansion gives \(x^2+2x-6x-12=0\). So \(x^2-4x-12=0\) is correct.
Step 2
Why this answer is correct
The correct answer is A. \(x^2-4x-12=0\). Expansion gives \(x^2+2x-6x-12=0\). So \(x^2-4x-12=0\) is correct.
Step 3
Exam Tip
विस्तार से \(x^2+2x-6x-12=0\) मिलता है। इसलिए \(x^2-4x-12=0\) सही है।
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((x+4)(x+5)=0) का विस्तृत रूप क्या है?
What is the expanded form of ((x+4)(x+5)=0)?
#quadratic equations
#binomial expansion
#standard form
A \(x^2+9x+20=0\)
B \(x^2+20x+9=0\)
C \(x^2-9x+20=0\)
D \(x^2+9x-20=0\)
Explanation opens after your attempt
Correct Answer
A. \(x^2+9x+20=0\)
Step 1
Concept
Expanding gives \(x^2+5x+4x+20=0\). Combining like terms gives \(x^2+9x+20=0\).
Step 2
Why this answer is correct
The correct answer is A. \(x^2+9x+20=0\). Expanding gives \(x^2+5x+4x+20=0\). Combining like terms gives \(x^2+9x+20=0\).
Step 3
Exam Tip
विस्तार करने पर \(x^2+5x+4x+20=0\) मिलता है। समान पद जोड़कर \(x^2+9x+20=0\) बनता है।
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(2x(x+7)=0) को मानक रूप में लिखिए।
Write (2x(x+7)=0) in standard form.
#quadratic equations
#expansion
#standard form
A \(2x^2+14x=0\)
B \(2x^2-14x=0\)
C \(14x^2+2x=0\)
D (2x+7=0)
Explanation opens after your attempt
Correct Answer
A. \(2x^2+14x=0\)
Step 1
Concept
Multiply (2x) by both terms inside the bracket. This gives \(2x^2+14x=0\).
Step 2
Why this answer is correct
The correct answer is A. \(2x^2+14x=0\). Multiply (2x) by both terms inside the bracket. This gives \(2x^2+14x=0\).
Step 3
Exam Tip
(2x) को कोष्ठक के दोनों पदों से गुणा करें। इससे \(2x^2+14x=0\) मिलता है।
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समीकरण \(2x^2=5x+3\) का मानक रूप कौन सा है?
Which is the standard form of \(2x^2=5x+3\)?
#quadratic equations
#standard form
#sign change
A \(2x^2-5x-3=0\)
B \(2x^2+5x+3=0\)
C \(2x^2-5x+3=0\)
D \(2x^2+5x-3=0\)
Explanation opens after your attempt
Correct Answer
A. \(2x^2-5x-3=0\)
Step 1
Concept
Bringing all terms to one side gives \(2x^2-5x-3=0\). Changing signs is important.
Step 2
Why this answer is correct
The correct answer is A. \(2x^2-5x-3=0\). Bringing all terms to one side gives \(2x^2-5x-3=0\). Changing signs is important.
Step 3
Exam Tip
सभी पद एक तरफ लाने पर \(2x^2-5x-3=0\) मिलता है। चिन्ह बदलना जरूरी है।
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समीकरण \(4x^2+7x=9\) का मानक रूप क्या है?
What is the standard form of \(4x^2+7x=9\)?
#quadratic equations
#standard form
#transposition
A \(4x^2+7x+9=0\)
B \(4x^2+7x-9=0\)
C \(4x^2-7x-9=0\)
D \(4x^2-7x+9=0\)
Explanation opens after your attempt
Correct Answer
B. \(4x^2+7x-9=0\)
Step 1
Concept
Moving (9) to the left makes it (-9). So the standard form is \(4x^2+7x-9=0\).
Step 2
Why this answer is correct
The correct answer is B. \(4x^2+7x-9=0\). Moving (9) to the left makes it (-9). So the standard form is \(4x^2+7x-9=0\).
Step 3
Exam Tip
दाईं ओर के (9) को बाईं ओर लाने पर (-9) बनता है। इसलिए मानक रूप \(4x^2+7x-9=0\) है।
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समीकरण \(11x^2-6x=0\) में (c) का मान क्या होगा?
What will be the value of (c) in \(11x^2-6x=0\)?
#quadratic equations
#missing constant
#standard form
A (11)
B (-6)
C (0)
D (6)
Explanation opens after your attempt
Step 1
Concept
It can be written as \(11x^2-6x+0=0\). So (c=0).
Step 2
Why this answer is correct
The correct answer is C. (0). It can be written as \(11x^2-6x+0=0\). So (c=0).
Step 3
Exam Tip
इसे \(11x^2-6x+0=0\) लिखा जा सकता है। इसलिए (c=0) है।
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यदि \(x^2+kx+12=0\) एक द्विघात समीकरण है तो (k) किस पद का गुणांक है?
If \(x^2+kx+12=0\) is a quadratic equation, then (k) is the coefficient of which term?
#quadratic equations
#coefficient
#standard form
A \(x^2\) पद / \(x^2\) term
B (x) पद / (x) term
C स्थिर पद (12) / Constant term (12)
D शून्य पद (0) / Zero term (0)
Explanation opens after your attempt
Correct Answer
B. (x) पद / (x) term
Step 1
Concept
In \(ax^2+bx+c=0\), (b) is the coefficient of (x). Here in (kx), (k) is the coefficient of (x).
Step 2
Why this answer is correct
The correct answer is B. (x) पद / (x) term. In \(ax^2+bx+c=0\), (b) is the coefficient of (x). Here in (kx), (k) is the coefficient of (x).
Step 3
Exam Tip
मानक रूप \(ax^2+bx+c=0\) में (x) का गुणांक (b) होता है। यहां (kx) में (k) (x) का गुणांक है।
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किस विकल्प में सामान्य गलती है जब \(x^2=5x-6\) को मानक रूप में बदला जाता है?
Which option shows the common mistake while converting \(x^2=5x-6\) to standard form?
#quadratic equations
#common mistake
#standard form
A \(x^2-5x+6=0\)
B \(x^2-5x-6=0\)
C \(x^2+0x=5x-6\)
D \(x^2=5x-6\)
Explanation opens after your attempt
Correct Answer
B. \(x^2-5x-6=0\)
Step 1
Concept
The correct form is \(x^2-5x+6=0\). In option (B), the sign of (-6) was not changed.
Step 2
Why this answer is correct
The correct answer is B. \(x^2-5x-6=0\). The correct form is \(x^2-5x+6=0\). In option (B), the sign of (-6) was not changed.
Step 3
Exam Tip
सही रूप \(x^2-5x+6=0\) है। विकल्प (B) में (-6) का चिन्ह नहीं बदला गया।
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कौन सा समीकरण मानक रूप में लाने पर \(x^2-7x+10=0\) बनता है?
Which equation becomes \(x^2-7x+10=0\) after writing in standard form?
#quadratic equations
#standard form
#reverse thinking
A \(x^2-7x=-10\)
B \(x^2-7x=10\)
C \(x^2+7x=-10\)
D \(x^2+7x=10\)
Explanation opens after your attempt
Correct Answer
A. \(x^2-7x=-10\)
Step 1
Concept
In \(x^2-7x=-10\), moving (-10) to the left gives (+10). So the standard form is \(x^2-7x+10=0\).
Step 2
Why this answer is correct
The correct answer is A. \(x^2-7x=-10\). In \(x^2-7x=-10\), moving (-10) to the left gives (+10). So the standard form is \(x^2-7x+10=0\).
Step 3
Exam Tip
\(x^2-7x=-10\) में (-10) को बाईं ओर लाने पर (+10) बनता है। इसलिए मानक रूप \(x^2-7x+10=0\) है।
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यदि (a=1), (b=0), (c=-25) हैं तो समीकरण क्या होगा?
If (a=1), (b=0), (c=-25), what is the equation?
#quadratic equations
#forming equation
#standard form
A \(x^2-25=0\)
B \(x^2+25=0\)
C \(x^2+25x=0\)
D \(25x^2-1=0\)
Explanation opens after your attempt
Correct Answer
A. \(x^2-25=0\)
Step 1
Concept
Substituting in \(ax^2+bx+c=0\) gives \(x^2+0x-25=0\). This is written as \(x^2-25=0\).
Step 2
Why this answer is correct
The correct answer is A. \(x^2-25=0\). Substituting in \(ax^2+bx+c=0\) gives \(x^2+0x-25=0\). This is written as \(x^2-25=0\).
Step 3
Exam Tip
\(ax^2+bx+c=0\) में रखने पर \(x^2+0x-25=0\) मिलता है। इसे \(x^2-25=0\) लिखते हैं।
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(3x(x-2)=0) का मानक रूप क्या है?
What is the standard form of (3x(x-2)=0)?
#quadratic equations
#expansion
#standard form
A \(3x^2-6x=0\)
B \(3x^2+6x=0\)
C \(x^2-6x=0\)
D (3x-6=0)
Explanation opens after your attempt
Correct Answer
A. \(3x^2-6x=0\)
Step 1
Concept
Multiplying (3x) by both terms gives \(3x^2-6x=0\). Watch the sign.
Step 2
Why this answer is correct
The correct answer is A. \(3x^2-6x=0\). Multiplying (3x) by both terms gives \(3x^2-6x=0\). Watch the sign.
Step 3
Exam Tip
(3x) को दोनों पदों से गुणा करने पर \(3x^2-6x=0\) मिलता है। चिन्ह पर ध्यान दें।
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((x-4)(x+1)=0) का मानक रूप कौन सा है?
Which is the standard form of ((x-4)(x+1)=0)?
#quadratic equations
#expansion
#standard form
A \(x^2-3x-4=0\)
B \(x^2+3x-4=0\)
C \(x^2-5x+4=0\)
D \(x^2+5x+4=0\)
Explanation opens after your attempt
Correct Answer
A. \(x^2-3x-4=0\)
Step 1
Concept
Expanding gives \(x^2+x-4x-4=0\). So \(x^2-3x-4=0\) is correct.
Step 2
Why this answer is correct
The correct answer is A. \(x^2-3x-4=0\). Expanding gives \(x^2+x-4x-4=0\). So \(x^2-3x-4=0\) is correct.
Step 3
Exam Tip
विस्तार करने पर \(x^2+x-4x-4=0\) मिलता है। इसलिए \(x^2-3x-4=0\) सही है।
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(x(x+5)=0) को मानक रूप में लिखिए।
Write (x(x+5)=0) in standard form.
#quadratic equations
#expansion
#standard form
A \(x^2+5x=0\)
B \(x^2-5x=0\)
C \(5x^2+x=0\)
D (x+5=0)
Explanation opens after your attempt
Correct Answer
A. \(x^2+5x=0\)
Step 1
Concept
Multiplying gives \(x^2+5x=0\). While opening brackets, multiply each term.
Step 2
Why this answer is correct
The correct answer is A. \(x^2+5x=0\). Multiplying gives \(x^2+5x=0\). While opening brackets, multiply each term.
Step 3
Exam Tip
गुणा करने पर \(x^2+5x=0\) मिलता है। कोष्ठक खोलते समय हर पद से गुणा करें।
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कौन सा समीकरण \(ax^2+bx+c=0\) के मानक रूप में है?
Which equation is in the standard form \(ax^2+bx+c=0\)?
#quadratic equations
#standard form
#recognition
A \(x^2+2x+1=0\)
B \(x^2+2x=1\)
C \(x^2=2x+1\)
D (2x+1=0)
Explanation opens after your attempt
Correct Answer
A. \(x^2+2x+1=0\)
Step 1
Concept
In standard form the right side is (0). Option (A) matches this form.
Step 2
Why this answer is correct
The correct answer is A. \(x^2+2x+1=0\). In standard form the right side is (0). Option (A) matches this form.
Step 3
Exam Tip
मानक रूप में दाईं ओर (0) होता है। विकल्प (A) इसी रूप में है।
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समीकरण \(x^2=4x+12\) का मानक रूप कौन सा है?
Which is the standard form of \(x^2=4x+12\)?
#quadratic equations
#standard form
#signs
A \(x^2-4x-12=0\)
B \(x^2+4x+12=0\)
C \(x^2-4x+12=0\)
D \(x^2+4x-12=0\)
Explanation opens after your attempt
Correct Answer
A. \(x^2-4x-12=0\)
Step 1
Concept
When terms from the right side move left, their signs change. Thus \(x^2-4x-12=0\) is correct.
Step 2
Why this answer is correct
The correct answer is A. \(x^2-4x-12=0\). When terms from the right side move left, their signs change. Thus \(x^2-4x-12=0\) is correct.
Step 3
Exam Tip
दाईं ओर के पदों को बाईं ओर लाने पर चिन्ह बदलते हैं। इसलिए \(x^2-4x-12=0\) सही है।
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समीकरण \(2x^2+5x=3\) का मानक रूप क्या है?
What is the standard form of \(2x^2+5x=3\)?
#quadratic equations
#standard form
#transposition
A \(2x^2+5x+3=0\)
B \(2x^2+5x-3=0\)
C \(2x^2-5x-3=0\)
D \(2x^2-5x+3=0\)
Explanation opens after your attempt
Correct Answer
B. \(2x^2+5x-3=0\)
Step 1
Concept
Bringing all terms to one side gives \(2x^2+5x-3=0\). Do not forget the sign change.
Step 2
Why this answer is correct
The correct answer is B. \(2x^2+5x-3=0\). Bringing all terms to one side gives \(2x^2+5x-3=0\). Do not forget the sign change.
Step 3
Exam Tip
सभी पद एक तरफ लाने पर \(2x^2+5x-3=0\) मिलता है। चिन्ह बदलना न भूलें।
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किस शर्त पर \(ax^2+bx+c=0\) द्विघात समीकरण कहलाता है?
Under which condition is \(ax^2+bx+c=0\) called a quadratic equation?
#quadratic equations
#condition
#standard form
A (a=0)
B \(a\neq0\)
C (b=0)
D (c=0)
Explanation opens after your attempt
Correct Answer
B. \(a\neq0\)
Step 1
Concept
The quadratic term must remain, so \(a\neq0\). If (a=0), it may become linear.
Step 2
Why this answer is correct
The correct answer is B. \(a\neq0\). The quadratic term must remain, so \(a\neq0\). If (a=0), it may become linear.
Step 3
Exam Tip
द्विघात पद बना रहे इसलिए \(a\neq0\) होना चाहिए। परीक्षा में (a=0) होने पर यह रैखिक बन सकता है।
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समीकरण \(4x^2-8x+1=0\) में (c) का मान क्या है?
What is the value of (c) in \(4x^2-8x+1=0\)?
#quadratic equations
#constant term
#standard form
A (4)
B \(-8\)
C (1)
D \(-1\)
Explanation opens after your attempt
Step 1
Concept
In standard form, (c) is the constant term. Here the constant term is (1).
Step 2
Why this answer is correct
The correct answer is C. (1). In standard form, (c) is the constant term. Here the constant term is (1).
Step 3
Exam Tip
मानक रूप में (c) स्थिर पद होता है। यहां स्थिर पद (1) है।
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समीकरण \(5x^2-2x+9=0\) में (a) का मान क्या है?
What is the value of (a) in the equation \(5x^2-2x+9=0\)?
#quadratic equations
#coefficients
#standard form
A (5)
B \(-2\)
C (9)
D (0)
Explanation opens after your attempt
Step 1
Concept
In \(ax^2+bx+c=0\), (a) is the coefficient of \(x^2\). Here (a=5).
Step 2
Why this answer is correct
The correct answer is A. (5). In \(ax^2+bx+c=0\), (a) is the coefficient of \(x^2\). Here (a=5).
Step 3
Exam Tip
मानक रूप \(ax^2+bx+c=0\) में (a) \(x^2\) का गुणांक होता है। यहां (a=5) है।
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यदि (a=17q+16) है, तो (a) को 17 से भाग देने पर संभावित शेषफल क्या होगा?
If (a=17q+16), what is the possible remainder when (a) is divided by 17?
#euclids-division-lemma
#standard-form
#remainder
A 17
B 16
C 15
D 1
Explanation opens after your attempt
Step 1
Concept
Compare with the standard form (a=bq+r).
Step 2
Why this answer is correct
Here the divisor is 17 and the remainder is 16, which is less than 17.
Step 3
Exam Tip
Always compare the remainder with the divisor to check validity. चरण 1: मानक रूप (a=bq+r) से तुलना करें। चरण 2: यहाँ भाजक 17 है और शेषफल 16 है, जो 17 से छोटा है। चरण 3: शेषफल की वैधता देखने के लिए उसे भाजक से जरूर मिलाएं।
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कौन-सा रूप (a=31q+r) के लिए सही शेषफल की शर्त पूरी करता है?
Which form satisfies the correct remainder condition for (a=31q+r)?
#real-numbers
#valid-remainder
#standard-form
A (a=31q+31)
B (a=31q+37)
C (a=31q+30)
D (a=31q-1)
Explanation opens after your attempt
Correct Answer
C. (a=31q+30)
Step 1
Concept
On division by (31), the remainder must be from (0) to (30).
Step 2
Why this answer is correct
In (31q+30), the remainder is (30), which is less than (31).
Step 3
Exam Tip
A remainder (31), (37), or negative is not in standard form. चरण 1: (31) से भाग देने पर शेषफल (0) से (30) तक होना चाहिए। चरण 2: (31q+30) में शेषफल (30) है, जो (31) से छोटा है। चरण 3: शेषफल (31), (37) या ऋणात्मक हो तो वह मानक रूप नहीं होगा।
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(305) को (24) से भाग देने का सही यूक्लिडीय रूप कौन-सा है?
Which is the correct Euclidean form when (305) is divided by (24)?
#real-numbers
#euclidean-form
#standard-form
A \(305=24 \times 12+17\)
B \(305=24 \times 13-7\)
C \(305=24 \times 11+41\)
D \(305=24 \times 10+65\)
Explanation opens after your attempt
Correct Answer
A. \(305=24 \times 12+17\)
Step 1
Concept
\(24 \times 12=288\) and \(24 \times 13=312\).
Step 2
Why this answer is correct
Since (312) is greater, \(305=24 \times 12+17\) is correct.
Step 3
Exam Tip
A form with a negative remainder is not the standard Euclidean form. चरण 1: \(24 \times 12=288\) और \(24 \times 13=312\) है। चरण 2: (312) बड़ा है, इसलिए \(305=24 \times 12+17\) सही है। चरण 3: ऋणात्मक शेषफल वाला रूप मानक यूक्लिडीय रूप नहीं होता।
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