What is the standard form of \(x(x-5)=0\)?
Answer and explanation
Correct answer: \(x^2-5x=0\)
Expanding gives \(x(x-5)=x\cdot x - x\cdot 5 = x^2-5x\), so the standard form is \(x^2-5x=0\). Option A has the wrong sign (should be -5x, not +5x); option C has incorrect coefficients; option D incorrectly changes the linear term to a constant. Exam tip: apply distributive property term-by-term and pay attention to signs when removing brackets.
Frequently asked questions
What is the correct answer to this question?
\(x^2-5x=0\)
Why is this the correct answer?
Expanding gives \(x(x-5)=x\cdot x - x\cdot 5 = x^2-5x\), so the standard form is \(x^2-5x=0\). Option A has the wrong sign (should be -5x, not +5x); option C has incorrect coefficients; option D incorrectly changes the linear term to a constant. Exam tip: apply distributive property term-by-term and pay attention to signs when removing brackets.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Introduction to Quadratic Equations.
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