What is the standard form of \((x+1)^2 = 0\)?
Answer and explanation
Correct answer: \(x^2 + 2x + 1 = 0\)
Expanding \((x+1)^2\) gives \(x^2 + 2x + 1\). The standard quadratic form places all terms on one side equal to zero, so the correct form is \(x^2 + 2x + 1 = 0\). Option B is incorrect because \(x^2 - 2x + 1\) is the expansion of \((x-1)^2\); options A and D omit or alter the linear term. Exam tip: use the identity \((a+b)^2 = a^2 + 2ab + b^2\) to expand quickly and then set the expression equal to zero.
Frequently asked questions
What is the correct answer to this question?
\(x^2 + 2x + 1 = 0\)
Why is this the correct answer?
Expanding \((x+1)^2\) gives \(x^2 + 2x + 1\). The standard quadratic form places all terms on one side equal to zero, so the correct form is \(x^2 + 2x + 1 = 0\). Option B is incorrect because \(x^2 - 2x + 1\) is the expansion of \((x-1)^2\); options A and D omit or alter the linear term. Exam tip: use the identity \((a+b)^2 = a^2 + 2ab + b^2\) to expand quickly and then set the expression equal to zero.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Introduction to Quadratic Equations.
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