Which of the following equations becomes \(x^2+2x-8=0\) after writing it in standard form (i.e., bringing all terms to the left)?
Answer and explanation
Correct answer: \(x^2+2x=8\)
Standard form for a quadratic is \(ax^2+bx+c=0\); to convert, bring the RHS term(s) to the left and change their signs. In option A, moving 8 to the left gives \(-8\), so \(x^2+2x=8\) becomes \(x^2+2x-8=0\) — correct. Option B is wrong because \(x^2+2x=-8\) would become \(x^2+2x+8=0\). Options C and D are incorrect because they have \(-2x\) (different sign for the linear term) not \(+2x\). Exam tip: always move all terms to one side to match \(ax^2+bx+c=0\) before comparing coefficients.
Frequently asked questions
What is the correct answer to this question?
\(x^2+2x=8\)
Why is this the correct answer?
Standard form for a quadratic is \(ax^2+bx+c=0\); to convert, bring the RHS term(s) to the left and change their signs. In option A, moving 8 to the left gives \(-8\), so \(x^2+2x=8\) becomes \(x^2+2x-8=0\) — correct. Option B is wrong because \(x^2+2x=-8\) would become \(x^2+2x+8=0\). Options C and D are incorrect because they have \(-2x\) (different sign for the linear term) not \(+2x\). Exam tip: always move all terms to one side to match \(ax^2+bx+c=0\) before comparing coefficients.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Introduction to Quadratic Equations.
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