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standard form MCQ Questions for Class 10

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123 questions tagged with standard form.

Question 61/123 Hard Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 29

समीकरण \(\frac{x^2-3}{2}+\frac{x-1}{3}=4\) को पूर्णांक गुणांकों वाले मानक रूप में लिखिए।

Write \(\frac{x^2-3}{2}+\frac{x-1}{3}=4\) in standard form with integer coefficients.

Explanation opens after your attempt
Correct Answer

A. \(3x^2+2x-29=0\)

Step 1

Concept

Multiplying the whole equation by (6) gives \(3x^2-9+2x-2=24\). Thus the standard form is \(3x^2+2x-35=0\).

Step 2

Why this answer is correct

The correct answer is A. \(3x^2+2x-29=0\). Multiplying the whole equation by (6) gives \(3x^2-9+2x-2=24\). Thus the standard form is \(3x^2+2x-35=0\).

Step 3

Exam Tip

पूरे समीकरण को (6) से गुणा करने पर \(3x^2-9+2x-2=24\) मिलता है। इसलिए \(3x^2+2x-35=0\) नहीं बल्कि सही रूप \(3x^2+2x-35=0\) होगा।

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Question 62/123 Hard Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 29

समीकरण ((5x-2)(2x+3)=7x) का मानक द्विघात रूप कौन-सा है?

What is the standard quadratic form of ((5x-2)(2x+3)=7x)?

Explanation opens after your attempt
Correct Answer

A. \(10x^2+4x-6=0\)

Step 1

Concept

Here ((5x-2)(2x+3)=10x-2+11x-6) and subtracting (7x) gives \(10x^2+4x-6=0\). First expand and then bring all terms to one side.

Step 2

Why this answer is correct

The correct answer is A. \(10x^2+4x-6=0\). Here ((5x-2)(2x+3)=10x-2+11x-6) and subtracting (7x) gives \(10x^2+4x-6=0\). First expand and then bring all terms to one side.

Step 3

Exam Tip

((5x-2)(2x+3)=10x-2+11x-6) है और (7x) घटाने पर \(10x^2+4x-6=0\) मिलता है। पहले विस्तार करें फिर सभी पद एक ओर लाएं।

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Question 63/123 Medium Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 30

समीकरण ((3x+4)2=7x+16) का मानक रूप कौन-सा है?

What is the standard form of ((3x+4)2=7x+16)?

Explanation opens after your attempt
Correct Answer

A. \(9x^2+17x=0\)

Step 1

Concept

((3x+4)2=9x-2+24x+16). Subtracting (7x+16) gives \(9x^2+17x=0\).

Step 2

Why this answer is correct

The correct answer is A. \(9x^2+17x=0\). ((3x+4)2=9x-2+24x+16). Subtracting (7x+16) gives \(9x^2+17x=0\).

Step 3

Exam Tip

((3x+4)2=9x-2+24x+16) है। (7x+16) घटाने पर \(9x^2+17x=0\) मिलता है।

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Question 64/123 Medium Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 30

समीकरण ((x-4)(x+9)=5x) का मानक रूप क्या है?

What is the standard form of ((x-4)(x+9)=5x)?

Explanation opens after your attempt
Correct Answer

A. \(x^2-36=0\)

Step 1

Concept

The left side gives \(x^2+5x-36\). Subtracting (5x) gives \(x^2-36=0\).

Step 2

Why this answer is correct

The correct answer is A. \(x^2-36=0\). The left side gives \(x^2+5x-36\). Subtracting (5x) gives \(x^2-36=0\).

Step 3

Exam Tip

बाईं ओर \(x^2+5x-36\) मिलता है। (5x) घटाने पर \(x^2-36=0\) बनता है।

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Question 65/123 Medium Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 30

समीकरण \(\frac{x^2}{5}+2x-7=0\) को बिना भिन्न के किस रूप में लिखा जाएगा?

How will \(\frac{x^2}{5}+2x-7=0\) be written without fractions?

Explanation opens after your attempt
Correct Answer

A. \(x^2+10x-35=0\)

Step 1

Concept

Multiplying the whole equation by (5) gives \(x^2+10x-35=0\). To remove fractions, multiply the whole equation.

Step 2

Why this answer is correct

The correct answer is A. \(x^2+10x-35=0\). Multiplying the whole equation by (5) gives \(x^2+10x-35=0\). To remove fractions, multiply the whole equation.

Step 3

Exam Tip

पूरे समीकरण को (5) से गुणा करने पर \(x^2+10x-35=0\) मिलता है। भिन्न हटाने के लिए पूरे समीकरण पर गुणा करें।

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Question 66/123 Medium Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 30

समीकरण ((x-6)2=4x+5) का मानक रूप कौन-सा है?

What is the standard form of ((x-6)2=4x+5)?

Explanation opens after your attempt
Correct Answer

A. \(x^2-16x+31=0\)

Step 1

Concept

((x-6)2=x-2-12x+36). Subtracting (4x+5) gives \(x^2-16x+31=0\).

Step 2

Why this answer is correct

The correct answer is A. \(x^2-16x+31=0\). ((x-6)2=x-2-12x+36). Subtracting (4x+5) gives \(x^2-16x+31=0\).

Step 3

Exam Tip

((x-6)2=x-2-12x+36) है। (4x+5) को घटाने पर \(x^2-16x+31=0\) मिलता है।

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Question 67/123 Medium Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 30

समीकरण \(12-7x+x^2=0\) को \(ax^2+bx+c=0\) के रूप में लिखने पर (b) का मान क्या होगा?

When \(12-7x+x^2=0\) is written as \(ax^2+bx+c=0\), what is the value of (b)?

Explanation opens after your attempt
Correct Answer

B. (-7)

Step 1

Concept

In proper order, the equation is \(x^2-7x+12=0\). So the coefficient of (x) is (b=-7).

Step 2

Why this answer is correct

The correct answer is B. (-7). In proper order, the equation is \(x^2-7x+12=0\). So the coefficient of (x) is (b=-7).

Step 3

Exam Tip

सही क्रम में समीकरण \(x^2-7x+12=0\) है। इसलिए (x) का गुणांक (b=-7) है।

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Question 68/123 Medium Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 30

समीकरण ((4x-1)(x+3)=0) का मानक द्विघात रूप कौन-सा है?

What is the standard quadratic form of ((4x-1)(x+3)=0)?

Explanation opens after your attempt
Correct Answer

A. \(4x^2+11x-3=0\)

Step 1

Concept

Expanding ((4x-1)(x+3)) gives \(4x^2+12x-x-3\). So the standard form is \(4x^2+11x-3=0\).

Step 2

Why this answer is correct

The correct answer is A. \(4x^2+11x-3=0\). Expanding ((4x-1)(x+3)) gives \(4x^2+12x-x-3\). So the standard form is \(4x^2+11x-3=0\).

Step 3

Exam Tip

((4x-1)(x+3)) को फैलाने पर \(4x^2+12x-x-3\) मिलता है। इसलिए मानक रूप \(4x^2+11x-3=0\) है।

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Question 69/123 Medium Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 29

समीकरण ((2x-1)2=3x+5) का मानक रूप कौन-सा है?

What is the standard form of ((2x-1)2=3x+5)?

Explanation opens after your attempt
Correct Answer

A. \(4x^2-7x-4=0\)

Step 1

Concept

Here ((2x-1)2=4x-2-4x+1), and bringing all terms to one side gives \(4x^2-7x-4=0\). Apply the square identity and signs carefully.

Step 2

Why this answer is correct

The correct answer is A. \(4x^2-7x-4=0\). Here ((2x-1)2=4x-2-4x+1), and bringing all terms to one side gives \(4x^2-7x-4=0\). Apply the square identity and signs carefully.

Step 3

Exam Tip

((2x-1)2=4x-2-4x+1) है और सभी पद एक ओर लाने पर \(4x^2-7x-4=0\) मिलता है। वर्ग सूत्र और चिन्ह दोनों ध्यान से लगाएं।

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Question 70/123 Medium Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 29

समीकरण ((x+2)(x-7)=3x) का मानक रूप क्या है?

What is the standard form of ((x+2)(x-7)=3x)?

Explanation opens after your attempt
Correct Answer

A. \(x^2-8x-14=0\)

Step 1

Concept

The left side gives \(x^2-5x-14\). Subtracting (3x) gives \(x^2-8x-14=0\).

Step 2

Why this answer is correct

The correct answer is A. \(x^2-8x-14=0\). The left side gives \(x^2-5x-14\). Subtracting (3x) gives \(x^2-8x-14=0\).

Step 3

Exam Tip

बाईं ओर \(x^2-5x-14\) मिलता है। (3x) को घटाने पर \(x^2-8x-14=0\) बनता है।

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Question 71/123 Medium Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 29

समीकरण \(\frac{x^2}{4}-x+3=0\) को बिना भिन्न के किस रूप में लिखा जाएगा?

How will \(\frac{x^2}{4}-x+3=0\) be written without fractions?

Explanation opens after your attempt
Correct Answer

A. \(x^2-4x+12=0\)

Step 1

Concept

Multiplying the whole equation by (4) gives \(x^2-4x+12=0\). To remove fractions, multiply the whole equation.

Step 2

Why this answer is correct

The correct answer is A. \(x^2-4x+12=0\). Multiplying the whole equation by (4) gives \(x^2-4x+12=0\). To remove fractions, multiply the whole equation.

Step 3

Exam Tip

पूरे समीकरण को (4) से गुणा करने पर \(x^2-4x+12=0\) मिलता है। भिन्न हटाने के लिए पूरे समीकरण पर गुणा करें।

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Question 72/123 Medium Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 29

समीकरण ((x+4)2=5x+10) का मानक रूप कौन-सा है?

What is the standard form of ((x+4)2=5x+10)?

Explanation opens after your attempt
Correct Answer

A. \(x^2+3x+6=0\)

Step 1

Concept

((x+4)2=x-2+8x+16), and subtracting (5x+10) gives \(x^2+3x+6=0\). Keep the middle term correct in square identities.

Step 2

Why this answer is correct

The correct answer is A. \(x^2+3x+6=0\). ((x+4)2=x-2+8x+16), and subtracting (5x+10) gives \(x^2+3x+6=0\). Keep the middle term correct in square identities.

Step 3

Exam Tip

((x+4)2=x-2+8x+16) है और (5x+10) हटाने पर \(x^2+3x+6=0\) मिलता है। वर्ग सूत्र में मध्य पद सही रखें।

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Question 73/123 Medium Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 29

कौन-सा समीकरण द्विघात है लेकिन अभी मानक रूप में नहीं है?

Which equation is quadratic but not yet in standard form?

Explanation opens after your attempt
Correct Answer

B. \(4x^2+1=3x\)

Step 1

Concept

\(4x^2+1=3x\) can be written as \(4x^2-3x+1=0\). In standard form, all terms are on one side and (0) is on the other.

Step 2

Why this answer is correct

The correct answer is B. \(4x^2+1=3x\). \(4x^2+1=3x\) can be written as \(4x^2-3x+1=0\). In standard form, all terms are on one side and (0) is on the other.

Step 3

Exam Tip

\(4x^2+1=3x\) को \(4x^2-3x+1=0\) लिखा जा सकता है। मानक रूप में सभी पद एक ओर और दूसरी ओर (0) होता है।

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Question 74/123 Medium Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 29

समीकरण \(8x-x^2=15\) का मानक रूप कौन-सा है जिसमें \(x^2\) का गुणांक धनात्मक हो?

What is the standard form of \(8x-x^2=15\) with positive coefficient of \(x^2\)?

Explanation opens after your attempt
Correct Answer

A. \(x^2-8x+15=0\)

Step 1

Concept

Bringing all terms to one side gives \(-x^2+8x-15=0\). Multiplying by (-1) gives \(x^2-8x+15=0\).

Step 2

Why this answer is correct

The correct answer is A. \(x^2-8x+15=0\). Bringing all terms to one side gives \(-x^2+8x-15=0\). Multiplying by (-1) gives \(x^2-8x+15=0\).

Step 3

Exam Tip

सभी पद एक ओर लाने पर \(-x^2+8x-15=0\) मिलता है। (-1) से गुणा करने पर \(x^2-8x+15=0\) मिलता है।

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Question 75/123 Medium Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 29

समीकरण ((3x+2)(x-5)=0) का मानक द्विघात रूप कौन-सा है?

What is the standard quadratic form of ((3x+2)(x-5)=0)?

Explanation opens after your attempt
Correct Answer

A. \(3x^2-13x-10=0\)

Step 1

Concept

Expanding ((3x+2)(x-5)) gives \(3x^2-15x+2x-10\). So the standard form is \(3x^2-13x-10=0\).

Step 2

Why this answer is correct

The correct answer is A. \(3x^2-13x-10=0\). Expanding ((3x+2)(x-5)) gives \(3x^2-15x+2x-10\). So the standard form is \(3x^2-13x-10=0\).

Step 3

Exam Tip

((3x+2)(x-5)) को फैलाने पर \(3x^2-15x+2x-10\) मिलता है। इसलिए मानक रूप \(3x^2-13x-10=0\) है।

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Question 76/123 Medium Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 28

समीकरण ((x+3)2=2x+15) का मानक रूप कौन-सा है?

What is the standard form of ((x+3)2=2x+15)?

Explanation opens after your attempt
Correct Answer

A. \(x^2+4x-6=0\)

Step 1

Concept

Here ((x+3)2=x-2+6x+9), and bringing all terms to one side gives \(x^2+4x-6=0\). Use the square identity and transposition carefully.

Step 2

Why this answer is correct

The correct answer is A. \(x^2+4x-6=0\). Here ((x+3)2=x-2+6x+9), and bringing all terms to one side gives \(x^2+4x-6=0\). Use the square identity and transposition carefully.

Step 3

Exam Tip

((x+3)2=x-2+6x+9) है और सभी पद एक ओर लाने पर \(x^2+4x-6=0\) मिलता है। वर्ग सूत्र और स्थानांतरण दोनों सावधानी से करें।

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Question 77/123 Medium Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 28

समीकरण ((x-1)(x+6)=2x) का मानक रूप क्या है?

What is the standard form of ((x-1)(x+6)=2x)?

Explanation opens after your attempt
Correct Answer

A. \(x^2+3x-6=0\)

Step 1

Concept

The left side gives \(x^2+5x-6\), and subtracting (2x) gives \(x^2+3x-6=0\). First expand and then bring all terms to one side.

Step 2

Why this answer is correct

The correct answer is A. \(x^2+3x-6=0\). The left side gives \(x^2+5x-6\), and subtracting (2x) gives \(x^2+3x-6=0\). First expand and then bring all terms to one side.

Step 3

Exam Tip

बाईं ओर \(x^2+5x-6\) मिलता है, फिर (2x) घटाने पर \(x^2+3x-6=0\) बनता है। पहले फैलाएं फिर सभी पद एक ओर लाएं।

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Question 78/123 Medium Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 28

समीकरण \(\frac{x^2}{2}+3x-5=0\) को बिना भिन्न के मानक रूप में कौन-सा लिखा जाएगा?

How will \(\frac{x^2}{2}+3x-5=0\) be written in standard form without fractions?

Explanation opens after your attempt
Correct Answer

A. \(x^2+6x-10=0\)

Step 1

Concept

Multiplying the whole equation by (2) gives \(x^2+6x-10=0\). To remove fractions, multiply by the denominator.

Step 2

Why this answer is correct

The correct answer is A. \(x^2+6x-10=0\). Multiplying the whole equation by (2) gives \(x^2+6x-10=0\). To remove fractions, multiply by the denominator.

Step 3

Exam Tip

पूरे समीकरण को (2) से गुणा करने पर \(x^2+6x-10=0\) मिलता है। भिन्न हटाने के लिए हर से गुणा करें।

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Question 79/123 Medium Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 28

समीकरण ((x-5)2=16) का मानक रूप कौन-सा है?

What is the standard form of ((x-5)2=16)?

Explanation opens after your attempt
Correct Answer

A. \(x^2-10x+9=0\)

Step 1

Concept

((x-5)2=x-2-10x+25), so \(x^2-10x+25-16=0\). Do not forget the middle term while using square identities.

Step 2

Why this answer is correct

The correct answer is A. \(x^2-10x+9=0\). ((x-5)2=x-2-10x+25), so \(x^2-10x+25-16=0\). Do not forget the middle term while using square identities.

Step 3

Exam Tip

((x-5)2=x-2-10x+25), इसलिए \(x^2-10x+25-16=0\) मिलता है। वर्ग सूत्र लगाते समय मध्य पद न भूलें।

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Question 80/123 Medium Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 28

कौन-सा समीकरण द्विघात है लेकिन मानक रूप में नहीं लिखा गया है?

Which equation is quadratic but not written in standard form?

Explanation opens after your attempt
Correct Answer

B. \(x^2=5x-4\)

Step 1

Concept

\(x^2=5x-4\) can be written as \(x^2-5x+4=0\), so it is quadratic. In standard form, the right side must be (0).

Step 2

Why this answer is correct

The correct answer is B. \(x^2=5x-4\). \(x^2=5x-4\) can be written as \(x^2-5x+4=0\), so it is quadratic. In standard form, the right side must be (0).

Step 3

Exam Tip

\(x^2=5x-4\) को \(x^2-5x+4=0\) बनाया जा सकता है, इसलिए यह द्विघात है। मानक रूप में दायां पक्ष (0) होना चाहिए।

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Question 81/123 Medium Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 28

समीकरण \(5x-2x^2=9\) का मानक रूप कौन-सा है जिसमें \(x^2\) का गुणांक धनात्मक हो?

What is the standard form of \(5x-2x^2=9\) with positive coefficient of \(x^2\)?

Explanation opens after your attempt
Correct Answer

A. \(2x^2-5x+9=0\)

Step 1

Concept

Bringing all terms to one side gives \(-2x^2+5x-9=0\), and multiplying by (-1) gives \(2x^2-5x+9=0\). Change signs carefully in standard form.

Step 2

Why this answer is correct

The correct answer is A. \(2x^2-5x+9=0\). Bringing all terms to one side gives \(-2x^2+5x-9=0\), and multiplying by (-1) gives \(2x^2-5x+9=0\). Change signs carefully in standard form.

Step 3

Exam Tip

सभी पद एक ओर लाकर \(-2x^2+5x-9=0\) मिलता है और (-1) से गुणा करने पर \(2x^2-5x+9=0\) मिलता है। मानक रूप में चिन्ह सावधानी से बदलें।

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Question 82/123 Medium Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 28

समीकरण \(3x^2-2x+7=0\) के लिए (a+b+c) का मान क्या है?

For the equation \(3x^2-2x+7=0\), what is the value of (a+b+c)?

Explanation opens after your attempt
Correct Answer

A. (8)

Step 1

Concept

Here (a=3), (b=-2), (c=7), so (a+b+c=8). Always include the signs of coefficients.

Step 2

Why this answer is correct

The correct answer is A. (8). Here (a=3), (b=-2), (c=7), so (a+b+c=8). Always include the signs of coefficients.

Step 3

Exam Tip

यहाँ (a=3), (b=-2), (c=7), इसलिए (a+b+c=8) है। गुणांकों के चिन्ह हमेशा साथ लिखें।

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Question 83/123 Medium Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 28

समीकरण ((2x-3)(x+4)=0) का मानक द्विघात रूप कौन-सा है?

What is the standard quadratic form of ((2x-3)(x+4)=0)?

Explanation opens after your attempt
Correct Answer

A. \(2x^2+5x-12=0\)

Step 1

Concept

Multiplying gives \(2x^2+8x-3x-12=0\), so \(2x^2+5x-12=0\). Adding middle terms correctly is important in exams.

Step 2

Why this answer is correct

The correct answer is A. \(2x^2+5x-12=0\). Multiplying gives \(2x^2+8x-3x-12=0\), so \(2x^2+5x-12=0\). Adding middle terms correctly is important in exams.

Step 3

Exam Tip

गुणा करने पर \(2x^2+8x-3x-12=0\), इसलिए \(2x^2+5x-12=0\) मिलता है। मध्य पदों को सही जोड़ना परीक्षा में जरूरी है।

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Question 84/123 Easy Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 30

मानक द्विघात समीकरण \(ax^2+bx+c=0\) में अधिकतम कितने अलग-अलग पद हो सकते हैं?

In the standard quadratic equation \(ax^2+bx+c=0\), what is the maximum number of different terms?

Explanation opens after your attempt
Correct Answer

C. (3)

Step 1

Concept

The standard form may contain the \(x^2\) term, the (x) term, and the constant term. So the maximum number of terms is (3).

Step 2

Why this answer is correct

The correct answer is C. (3). The standard form may contain the \(x^2\) term, the (x) term, and the constant term. So the maximum number of terms is (3).

Step 3

Exam Tip

मानक रूप में \(x^2\) पद, (x) पद और स्थिर पद हो सकते हैं। इसलिए अधिकतम (3) पद होते हैं।

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Question 85/123 Easy Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 30

मानक रूप \(ax^2+bx+c=0\) में \(x^2\) का गुणांक किससे दर्शाया जाता है?

In the standard form \(ax^2+bx+c=0\), which symbol denotes the coefficient of \(x^2\)?

Explanation opens after your attempt
Correct Answer

B. (a)

Step 1

Concept

In standard form, the coefficient of \(x^2\) is (a). This coefficient must not be (0).

Step 2

Why this answer is correct

The correct answer is B. (a). In standard form, the coefficient of \(x^2\) is (a). This coefficient must not be (0).

Step 3

Exam Tip

मानक रूप में \(x^2\) का गुणांक (a) होता है। यही गुणांक (0) नहीं होना चाहिए।

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Question 86/123 Easy Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 30

((x+1)2=0) का मानक रूप क्या है?

What is the standard form of ((x+1)2=0)?

Explanation opens after your attempt
Correct Answer

C. \(x^2+2x+1=0\)

Step 1

Concept

((x+1)2=x-2+2x+1). Remember the formula ((a+b)2=a-2+2ab+b-2).

Step 2

Why this answer is correct

The correct answer is C. \(x^2+2x+1=0\). ((x+1)2=x-2+2x+1). Remember the formula ((a+b)2=a-2+2ab+b-2).

Step 3

Exam Tip

((x+1)2=x-2+2x+1) होता है। सूत्र ((a+b)2=a-2+2ab+b-2) याद रखें।

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Question 87/123 Easy Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 30

समीकरण \(x^2=6x\) का मानक रूप कौन-सा है?

What is the standard form of \(x^2=6x\)?

Explanation opens after your attempt
Correct Answer

B. \(x^2-6x=0\)

Step 1

Concept

Bringing (6x) to the left gives \(x^2-6x=0\). The sign changes during transposition.

Step 2

Why this answer is correct

The correct answer is B. \(x^2-6x=0\). Bringing (6x) to the left gives \(x^2-6x=0\). The sign changes during transposition.

Step 3

Exam Tip

(6x) को बाईं ओर लाने पर \(x^2-6x=0\) मिलता है। स्थानांतरण करते समय चिन्ह बदलता है।

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Question 88/123 Easy Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 30

समीकरण (x(x-5)=0) का मानक रूप कौन-सा है?

What is the standard form of (x(x-5)=0)?

Explanation opens after your attempt
Correct Answer

B. \(x^2-5x=0\)

Step 1

Concept

Expanding (x(x-5)) gives \(x^2-5x\). Keep signs correct while removing brackets.

Step 2

Why this answer is correct

The correct answer is B. \(x^2-5x=0\). Expanding (x(x-5)) gives \(x^2-5x\). Keep signs correct while removing brackets.

Step 3

Exam Tip

(x(x-5)) को फैलाने पर \(x^2-5x\) मिलता है। कोष्ठक हटाते समय चिन्ह सही रखें।

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Question 89/123 Easy Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 30

समीकरण \(x^2=7\) का मानक रूप कौन-सा है?

What is the standard form of \(x^2=7\)?

Explanation opens after your attempt
Correct Answer

D. \(x^2-7=0\)

Step 1

Concept

Bringing (7) to the left gives \(x^2-7=0\). In standard form, all terms are on one side.

Step 2

Why this answer is correct

The correct answer is D. \(x^2-7=0\). Bringing (7) to the left gives \(x^2-7=0\). In standard form, all terms are on one side.

Step 3

Exam Tip

(7) को बाईं ओर लाने पर \(x^2-7=0\) मिलता है। मानक रूप में सभी पद एक तरफ होते हैं।

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Question 90/123 Easy Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 30

((x+1)(x+2)=0) को फैलाने पर कौन-सा समीकरण मिलेगा?

Which equation is obtained by expanding ((x+1)(x+2)=0)?

Explanation opens after your attempt
Correct Answer

A. \(x^2+3x+2=0\)

Step 1

Concept

((x+1)(x+2)=x-2+3x+2). Do not forget to add the middle terms while multiplying.

Step 2

Why this answer is correct

The correct answer is A. \(x^2+3x+2=0\). ((x+1)(x+2)=x-2+3x+2). Do not forget to add the middle terms while multiplying.

Step 3

Exam Tip

((x+1)(x+2)=x-2+3x+2) होता है। गुणा करते समय मध्य पदों को जोड़ना न भूलें।

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