What is the standard quadratic form of \((4x-1)(x+3)=0\)?
Answer and explanation
Correct answer: \(4x^2+11x-3=0\)
Expanding \((4x-1)(x+3)\) gives \(4x^2+12x-x-3\). Combining like terms yields \(4x^2+11x-3\), so the standard form is \(4x^2+11x-3=0\). Option B has the wrong sign for the middle term (should be +11x). Options C and D result from incorrect multiplication or sign errors. Exam tip: multiply each term carefully and then combine like terms to avoid sign mistakes.
Frequently asked questions
What is the correct answer to this question?
\(4x^2+11x-3=0\)
Why is this the correct answer?
Expanding \((4x-1)(x+3)\) gives \(4x^2+12x-x-3\). Combining like terms yields \(4x^2+11x-3\), so the standard form is \(4x^2+11x-3=0\). Option B has the wrong sign for the middle term (should be +11x). Options C and D result from incorrect multiplication or sign errors. Exam tip: multiply each term carefully and then combine like terms to avoid sign mistakes.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Introduction to Quadratic Equations.
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