What is the standard form of \(4x^2+7x=9\)?
Answer and explanation
Correct answer: \(4x^2+7x-9=0\)
A quadratic is written in standard form as \(ax^2+bx+c=0\). Moving the RHS term \(9\) to the left changes its sign, giving \(4x^2+7x-9=0\), so option B is correct. Option A is wrong because it keeps \(+9\) instead of \(-9\). Options C and D are wrong because they change the sign of the linear term \(7x\). Exam tip: bring every term to one side and combine like terms to reach \(ax^2+bx+c=0\).
Frequently asked questions
What is the correct answer to this question?
\(4x^2+7x-9=0\)
Why is this the correct answer?
A quadratic is written in standard form as \(ax^2+bx+c=0\). Moving the RHS term \(9\) to the left changes its sign, giving \(4x^2+7x-9=0\), so option B is correct. Option A is wrong because it keeps \(+9\) instead of \(-9\). Options C and D are wrong because they change the sign of the linear term \(7x\). Exam tip: bring every term to one side and combine like terms to reach \(ax^2+bx+c=0\).
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Introduction to Quadratic Equations.
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