What is the standard form of the equation \((x-6)(x+2)=0\)?
Answer and explanation
Correct answer: \(x^2-4x-12=0\)
Multiply the factors: \((x-6)(x+2)=x^2+2x-6x-12=x^2-4x-12\). Thus the standard form is \((x^2-4x-12=0)\). Option B has the wrong sign on the x-term (+4x instead of -4x); option C shows -8x which results from incorrect addition of like terms. Exam tip: Use FOIL or multiply term-by-term and then combine like terms carefully.
Frequently asked questions
What is the correct answer to this question?
\(x^2-4x-12=0\)
Why is this the correct answer?
Multiply the factors: \((x-6)(x+2)=x^2+2x-6x-12=x^2-4x-12\). Thus the standard form is \((x^2-4x-12=0)\). Option B has the wrong sign on the x-term (+4x instead of -4x); option C shows -8x which results from incorrect addition of like terms. Exam tip: Use FOIL or multiply term-by-term and then combine like terms carefully.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Introduction to Quadratic Equations.
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