Update
Muft Shiksha™ एक 100% Free Education Portal है 🇮🇳, जिसका उद्देश्य Class 9–12 के हर विद्यार्थी तक High-Quality Education को पूरी तरह मुफ्त पहुँचाना है। 🇮🇳 हम मानते हैं कि अच्छी शिक्षा किसी student की आर्थिक स्थिति पर निर्भर नहीं होनी चाहिए। 🇮🇳 हर विद्यार्थी को वही Quality Study Material, MCQs, Quizzes, Exam Preparation, Concept-Based Learning और Bilingual Support मिलना चाहिए, जो आमतौर पर महंगी Coaching या Premium Platforms में मिलता है। Muft Shiksha™ 🇮🇳 इसी सोच के साथ बनाया गया है • Muft Shiksha™ एक 100% Free Education Portal है 🇮🇳, जिसका उद्देश्य Class 9–12 के हर विद्यार्थी तक High-Quality Education को पूरी तरह मुफ्त पहुँचाना है। 🇮🇳 हम मानते हैं कि अच्छी शिक्षा किसी student की आर्थिक स्थिति पर निर्भर नहीं होनी चाहिए। 🇮🇳 हर विद्यार्थी को वही Quality Study Material, MCQs, Quizzes, Exam Preparation, Concept-Based Learning और Bilingual Support मिलना चाहिए, जो आमतौर पर महंगी Coaching या Premium Platforms में मिलता है। Muft Shiksha™ 🇮🇳 इसी सोच के साथ बनाया गया है • Muft Shiksha™ एक 100% Free Education Portal है 🇮🇳, जिसका उद्देश्य Class 9–12 के हर विद्यार्थी तक High-Quality Education को पूरी तरह मुफ्त पहुँचाना है। 🇮🇳 हम मानते हैं कि अच्छी शिक्षा किसी student की आर्थिक स्थिति पर निर्भर नहीं होनी चाहिए। 🇮🇳 हर विद्यार्थी को वही Quality Study Material, MCQs, Quizzes, Exam Preparation, Concept-Based Learning और Bilingual Support मिलना चाहिए, जो आमतौर पर महंगी Coaching या Premium Platforms में मिलता है। Muft Shiksha™ 🇮🇳 इसी सोच के साथ बनाया गया है
Subjects

Search Class 10 Questions

100 results found for "infinite_interval" in Class 10.

Question Hard Mathematics Arithmetic Progressions (AP) Finding the sum of the first $n$ terms of an AP Class 10 Level 67

(50) से (250) तक (7) से विभाज्य सभी संख्याओं का योग ज्ञात कीजिए।

Find the sum of all numbers divisible by (7) from (50) to (250).

Explanation opens after your attempt
Correct Answer

C. (4214)

Explanation

Simple Explanation

श्रेढ़ी \(56,63,\ldots,245\) है जिसमें (28) पद हैं और योग (4214) है। सीमा के अंदर पहला और अंतिम गुणज सही चुनें। / The AP is \(56,63,\ldots,245\) with (28) terms, and the sum is (4214). Choose the first and last multiples within the limits correctly.

Open Question Page
Ask Friends
Question Medium Mathematics Arithmetic Progressions (AP) Finding the sum of the first $n$ terms of an AP Class 10 Level 69

एक सड़क पर खंभों की दूरी के क्रम \(6,12,18,\ldots\) मीटर हैं। पहले (25) अंतरालों की कुल दूरी कितनी होगी?

On a road, the distances of intervals are \(6,12,18,\ldots\) meters. What is the total distance of the first (25) intervals?

Explanation opens after your attempt
Correct Answer

C. (1950)

Explanation

Simple Explanation

यह (6) के पहले (25) गुणजों का योग है, इसलिए कुल दूरी (1950) मीटर है। गुणजों के योग में (a=d) होता है। / This is the sum of the first (25) multiples of (6), so the total distance is (1950) meters. In sums of multiples, (a=d).

Open Question Page
Ask Friends
Question Expert Mathematics Arithmetic Progressions (AP) Introduction to APs and common difference. Class 10 Level 63

एक वाहन समान समयांतरालों में (18,30,42,54) किलोमीटर चलता है। दूरी अनुक्रम का सामान्य अंतर क्या है?

A vehicle covers (18,30,42,54) kilometres in equal time intervals. What is the common difference of the distance sequence?

Explanation opens after your attempt
Correct Answer

B. (12) किलोमीटर(12) kilometres

Explanation

Simple Explanation

हर बार दूरी (12) किलोमीटर बढ़ती है। परीक्षा में वास्तविक जीवन प्रश्न में भी वही लगातार अंतर निकालें। / The distance increases by (12) kilometres each time. In word problems, still find the same consecutive difference.

Open Question Page
Ask Friends
Question Easy Mathematics Arithmetic Progressions (AP) Introduction to APs and common difference. Class 10 Level 62

एक बस हर स्टॉप पर (8) मिनट के अंतर से पहुंचती है। समय \(6,14,22,30,\ldots\) मिनट हैं तो यह किस प्रकार का अनुक्रम है?

A bus reaches each stop at intervals of (8) minutes. The times are \(6,14,22,30,\ldots\) minutes. What type of sequence is this?

Explanation opens after your attempt
Correct Answer

A. अंकगणितीय श्रेणीArithmetic progression

Explanation

Simple Explanation

हर क्रमागत समय में (8) का समान अंतर है इसलिए यह अंकगणितीय श्रेणी है। शब्द प्रश्न में समान अंतर को पहचानें। / Each consecutive time has the same difference of (8), so it is an arithmetic progression. In word problems identify the equal difference.

Open Question Page
Ask Friends
Question Expert Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 58

युग्म (tx+9y=6) और (20x+15y=10) के अनंत हलों के लिए (t) का मान क्या होगा?

What is the value of (t) for infinitely many solutions of (tx+9y=6) and (20x+15y=10)?

Explanation opens after your attempt
Correct Answer

C. (t=12)

Explanation

Simple Explanation

तीनों अनुपात \(\frac{3}{5}\) होने चाहिए। इसलिए \(\frac{t}{20}=\frac{3}{5}\) से (t=12)। / All three ratios must be \(\frac{3}{5}\). Therefore, \(\frac{t}{20}=\frac{3}{5}\) gives (t=12).

Open Question Page
Ask Friends
Question Expert Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 58

युग्म (qx+11y=22) और (18x+33y=66) के अनंत हलों के लिए (q) का मान क्या है?

What is the value of (q) for infinitely many solutions of (qx+11y=22) and (18x+33y=66)?

Explanation opens after your attempt
Correct Answer

C. (q=6)

Explanation

Simple Explanation

अनंत हलों में \(\frac{q}{18}=\frac{11}{33}=\frac{22}{66}\) होता है। इसलिए (q=6) सही मान है। / For infinitely many solutions, \(\frac{q}{18}=\frac{11}{33}=\frac{22}{66}\). Therefore, (q=6) is correct.

Open Question Page
Ask Friends
Question Expert Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 58

युग्म (3x+ny=18) और (5x+10y=30) के अनंत हलों के लिए (n) क्या होगा?

For infinitely many solutions of (3x+ny=18) and (5x+10y=30), what is (n)?

Explanation opens after your attempt
Correct Answer

C. (n=6)

Explanation

Simple Explanation

अनंत हलों के लिए \(\frac{3}{5}=\frac{n}{10}=\frac{18}{30}\) चाहिए। इससे (n=6) मिलता है। / For infinitely many solutions, \(\frac{3}{5}=\frac{n}{10}=\frac{18}{30}\) is needed. This gives (n=6).

Open Question Page
Ask Friends
Question Expert Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 58

युग्म (jx+5y=10) और (14x+7y=14) के अनंत हलों के लिए (j) क्या होगा?

For infinitely many solutions of (jx+5y=10) and (14x+7y=14), what is (j)?

Explanation opens after your attempt
Correct Answer

C. (j=10)

Explanation

Simple Explanation

तीनों अनुपात \(\frac{5}{7}\) होने चाहिए। इसलिए \(\frac{j}{14}=\frac{5}{7}\) से (j=10)। / All three ratios must be \(\frac{5}{7}\). Therefore, \(\frac{j}{14}=\frac{5}{7}\) gives (j=10).

Open Question Page
Ask Friends
Question Expert Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 58

युग्म ((g-1)x+10y=15) और (8x+20y=30) के अनंत हलों के लिए (g) क्या होगा?

For infinitely many solutions of ((g-1)x+10y=15) and (8x+20y=30), what is (g)?

Explanation opens after your attempt
Correct Answer

B. (g=5)

Explanation

Simple Explanation

अनंत हलों के लिए \(\frac{g-1}{8}=\frac{10}{20}=\frac{15}{30}\) होना चाहिए। इससे (g=5) मिलता है। / For infinitely many solutions, \(\frac{g-1}{8}=\frac{10}{20}=\frac{15}{30}\) must hold. This gives (g=5).

Open Question Page
Ask Friends
Question Expert Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 58

युग्म (4x+dy=7) और (12x+15y=21) के अनंत हलों के लिए (d) का मान क्या है?

What is the value of (d) for infinitely many solutions of (4x+dy=7) and (12x+15y=21)?

Explanation opens after your attempt
Correct Answer

C. (d=5)

Explanation

Simple Explanation

अनंत हलों में \(\frac{4}{12}=\frac{d}{15}=\frac{7}{21}\) होना चाहिए। इसलिए (d=5) सही है। / For infinitely many solutions, \(\frac{4}{12}=\frac{d}{15}=\frac{7}{21}\) must hold. So (d=5) is correct.

Open Question Page
Ask Friends
Question Expert Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 58

युग्म (2x+by=6) और (bx+8y=24) के अनंत हलों के लिए (b) का मान क्या होगा?

What is the value of (b) for infinitely many solutions of (2x+by=6) and (bx+8y=24)?

Explanation opens after your attempt
Correct Answer

C. (b=4)

Explanation

Simple Explanation

अनंत हलों के लिए \(\frac{2}{b}=\frac{b}{8}=\frac{6}{24}\) होना चाहिए। इससे (b=4) मिलता है। / For infinitely many solutions, \(\frac{2}{b}=\frac{b}{8}=\frac{6}{24}\) must hold. This gives (b=4).

Open Question Page
Ask Friends
Question Expert Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 58

युग्म (9x+\(\beta+4\)y=15) और (27x+18y=45) के अनंत हलों के लिए \(\beta\) क्या होगा?

For infinitely many solutions of (9x+\(\beta+4\)y=15) and (27x+18y=45), what is \(\beta\)?

Explanation opens after your attempt
Correct Answer

B. \(\beta=2\)

Explanation

Simple Explanation

अनंत हलों में \(\frac{9}{27}=\frac{\beta+4}{18}=\frac{15}{45}\) होना चाहिए। इससे \(\beta=2\) मिलता है। / For infinitely many solutions, \(\frac{9}{27}=\frac{\beta+4}{18}=\frac{15}{45}\) must hold. This gives \(\beta=2\).

Open Question Page
Ask Friends
Question Expert Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 58

युग्म \(3x+2y=\lambda\) और (18x+12y=48) के अनंत हलों के लिए \(\lambda\) क्या होगा?

For infinitely many solutions of \(3x+2y=\lambda\) and (18x+12y=48), what is \(\lambda\)?

Explanation opens after your attempt
Correct Answer

B. \(\lambda=8\)

Explanation

Simple Explanation

गुणांक अनुपात \(\frac{1}{6}\) है। अनंत हलों के लिए \(\frac{\lambda}{48}=\frac{1}{6}\) इसलिए \(\lambda=8\)। / The coefficient ratio is \(\frac{1}{6}\). For infinitely many solutions, \(\frac{\lambda}{48}=\frac{1}{6}\), so \(\lambda=8\).

Open Question Page
Ask Friends
Question Expert Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 58

युग्म ((u+3)x+8y=16) और (10x+20y=40) के अनंत हलों के लिए (u) क्या होगा?

For infinitely many solutions of ((u+3)x+8y=16) and (10x+20y=40), what is (u)?

Explanation opens after your attempt
Correct Answer

A. (u=1)

Explanation

Simple Explanation

अनंत हलों के लिए \(\frac{u+3}{10}=\frac{8}{20}=\frac{16}{40}\) चाहिए। इससे (u=1) मिलता है। / For infinitely many solutions, \(\frac{u+3}{10}=\frac{8}{20}=\frac{16}{40}\) is needed. This gives (u=1).

Open Question Page
Ask Friends
Question Expert Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 58

युग्म (6x-ty=18) और (14x-21y=42) के अनंत हलों के लिए (t) का मान क्या होगा?

What is the value of (t) for infinitely many solutions of (6x-ty=18) and (14x-21y=42)?

Explanation opens after your attempt
Correct Answer

C. (t=9)

Explanation

Simple Explanation

अनंत हलों के लिए \(\frac{6}{14}=\frac{-t}{-21}=\frac{18}{42}\) होना चाहिए। इससे (t=9) मिलता है। / For infinitely many solutions, \(\frac{6}{14}=\frac{-t}{-21}=\frac{18}{42}\) must hold. This gives (t=9).

Open Question Page
Ask Friends
Question Expert Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 58

युग्म (5x+(r+1)y=11) और (15x+18y=33) के अनंत हलों के लिए (r) क्या होगा?

For infinitely many solutions of (5x+(r+1)y=11) and (15x+18y=33), what is (r)?

Explanation opens after your attempt
Correct Answer

B. (r=5)

Explanation

Simple Explanation

अनंत हलों के लिए \(\frac{5}{15}=\frac{r+1}{18}=\frac{11}{33}\) चाहिए। इससे (r=5) मिलता है। / For infinitely many solutions, \(\frac{5}{15}=\frac{r+1}{18}=\frac{11}{33}\) is needed. This gives (r=5).

Open Question Page
Ask Friends
Question Expert Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 58

युग्म (8x+ay=12) और (20x+10y=30) के अनंत हलों के लिए (a) का मान बताइए।

Find the value of (a) for infinitely many solutions of (8x+ay=12) and (20x+10y=30).

Explanation opens after your attempt
Correct Answer

B. (a=4)

Explanation

Simple Explanation

यहाँ \(\frac{8}{20}=\frac{12}{30}\) है। अतः \(\frac{a}{10}=\frac{2}{5}\) से (a=4) होगा। / Here \(\frac{8}{20}=\frac{12}{30}\). Thus \(\frac{a}{10}=\frac{2}{5}\) gives (a=4).

Open Question Page
Ask Friends
Question Expert Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 58

युग्म ((p-2)x+7y=14) और (9x+21y=42) के अनंत हलों के लिए (p) क्या होगा?

For infinitely many solutions of ((p-2)x+7y=14) and (9x+21y=42), what is (p)?

Explanation opens after your attempt
Correct Answer

C. (p=5)

Explanation

Simple Explanation

अनंत हलों के लिए तीनों अनुपात समान होने चाहिए। \(\frac{p-2}{9}=\frac{7}{21}\) से (p=5) मिलता है। / For infinitely many solutions, all three ratios must be equal. From \(\frac{p-2}{9}=\frac{7}{21}\), (p=5).

Open Question Page
Ask Friends
Question Expert Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 60

समीकरणों (6x+ay=42) और (18x+33y=126) के अनंत हल होने के लिए (a) का मान क्या होगा?

What is the value of (a) for the equations (6x+ay=42) and (18x+33y=126) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

C. (11)

Explanation

Simple Explanation

अनंत हल के लिए (6/18=a/33=42/126) होना चाहिए। इसलिए (a=11) सही है। / For infinitely many solutions, (6/18=a/33=42/126) must hold. Therefore, (a=11) is correct.

Open Question Page
Ask Friends
Question Expert Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 59

युग्म \(5x-2y=\gamma\) और (20x-8y=36) के अनंत हलों के लिए \(\gamma\) का मान क्या है?

What is \(\gamma\) for infinitely many solutions of \(5x-2y=\gamma\) and (20x-8y=36)?

Explanation opens after your attempt
Correct Answer

C. \(\gamma=9\)

Explanation

Simple Explanation

गुणांक अनुपात \(\frac{1}{4}\) है। अनंत हलों के लिए \(\frac{\gamma}{36}=\frac{1}{4}\), इसलिए \(\gamma=9\)। / The coefficient ratio is \(\frac{1}{4}\). For infinitely many solutions, \(\frac{\gamma}{36}=\frac{1}{4}\), so \(\gamma=9\).

Open Question Page
Ask Friends
Question Expert Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 59

युग्म \(rx+\frac{3}{2}y=6\) और (8x+6y=24) के अनंत हलों के लिए (r) का मान क्या है?

What is (r) for infinitely many solutions of \(rx+\frac{3}{2}y=6\) and (8x+6y=24)?

Explanation opens after your attempt
Correct Answer

B. (r=2)

Explanation

Simple Explanation

तीनों अनुपात \(\frac{1}{4}\) होने चाहिए। इसलिए (r=2) सही मान है। / All three ratios must be \(\frac{1}{4}\). Therefore, (r=2) is the correct value.

Open Question Page
Ask Friends
Question Expert Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 59

युग्म (4x+(m-5)y=9) और (12x+6y=27) के अनंत हलों के लिए (m) कितना है?

What is (m) for infinitely many solutions of (4x+(m-5)y=9) and (12x+6y=27)?

Explanation opens after your attempt
Correct Answer

C. (m=7)

Explanation

Simple Explanation

अनंत हलों के लिए \(\frac{4}{12}=\frac{m-5}{6}=\frac{9}{27}\) चाहिए। इससे (m=7) मिलता है। / For infinitely many solutions, \(\frac{4}{12}=\frac{m-5}{6}=\frac{9}{27}\) is required. This gives (m=7).

Open Question Page
Ask Friends
Question Expert Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 59

युग्म (6x+(h+1)y=12) और (15x+20y=30) के अनंत हलों के लिए (h) क्या है?

For infinitely many solutions of (6x+(h+1)y=12) and (15x+20y=30), what is (h)?

Explanation opens after your attempt
Correct Answer

C. (h=7)

Explanation

Simple Explanation

अनंत हलों के लिए \(\frac{6}{15}=\frac{h+1}{20}=\frac{12}{30}\) होना चाहिए। इससे (h=7) मिलता है। / For infinitely many solutions, \(\frac{6}{15}=\frac{h+1}{20}=\frac{12}{30}\) must hold. This gives (h=7).

Open Question Page
Ask Friends
Question Expert Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 59

युग्म ((v+2)x-3y=6) और (10x-5y=10) के अनंत हलों के लिए (v) क्या होगा?

For infinitely many solutions of ((v+2)x-3y=6) and (10x-5y=10), what is (v)?

Explanation opens after your attempt
Correct Answer

C. (v=4)

Explanation

Simple Explanation

यहाँ \(\frac{v+2}{10}=\frac{-3}{-5}=\frac{6}{10}\) होना चाहिए। इससे (v=4) मिलता है। / Here \(\frac{v+2}{10}=\frac{-3}{-5}=\frac{6}{10}\) must hold. This gives (v=4).

Open Question Page
Ask Friends
Question Expert Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 59

युग्म (12x+sy=18) और (20x+10y=30) के अनंत हलों के लिए (s) क्या होगा?

What is (s) for infinitely many solutions of (12x+sy=18) and (20x+10y=30)?

Explanation opens after your attempt
Correct Answer

C. (s=6)

Explanation

Simple Explanation

अनंत हलों के लिए \(\frac{12}{20}=\frac{s}{10}=\frac{18}{30}\) चाहिए। इससे (s=6) आता है। / For infinitely many solutions, \(\frac{12}{20}=\frac{s}{10}=\frac{18}{30}\) is needed. This gives (s=6).

Open Question Page
Ask Friends
Question Expert Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 59

युग्म (3x+ay=6) और (9x+12y=b) के अनंत हलों के लिए ((a,b)) क्या होगा?

For infinitely many solutions of (3x+ay=6) and (9x+12y=b), what is ((a,b))?

Explanation opens after your attempt
Correct Answer

B. (a=4,\ b=18)

Explanation

Simple Explanation

तीनों अनुपात \(\frac{1}{3}\) होने चाहिए। इसलिए (a=4) और (b=18) है। / All three ratios must be \(\frac{1}{3}\). So (a=4) and (b=18).

Open Question Page
Ask Friends
Question Expert Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 59

युग्म (7x+(m-4)y=13) और (14x+6y=26) के अनंत हलों के लिए (m) का मान बताइए।

Find (m) for infinitely many solutions of (7x+(m-4)y=13) and (14x+6y=26).

Explanation opens after your attempt
Correct Answer

B. (m=7)

Explanation

Simple Explanation

अनंत हलों में \(\frac{7}{14}=\frac{m-4}{6}=\frac{13}{26}\) होना चाहिए। इससे (m=7) मिलता है। / For infinitely many solutions, \(\frac{7}{14}=\frac{m-4}{6}=\frac{13}{26}\) must hold. This gives (m=7).

Open Question Page
Ask Friends
Question Expert Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 59

युग्म (6x-8y=16) और (sx-12y=24) के अनंत हलों के लिए (s) का मान क्या होगा?

For infinitely many solutions of (6x-8y=16) and (sx-12y=24), what is (s)?

Explanation opens after your attempt
Correct Answer

C. (s=9)

Explanation

Simple Explanation

अनंत हलों के लिए सभी अनुपात बराबर होने चाहिए। \(\frac{6}{s}=\frac{-8}{-12}=\frac{16}{24}\) से (s=9) है। / For infinitely many solutions, all ratios must be equal. From \(\frac{6}{s}=\frac{-8}{-12}=\frac{16}{24}\), (s=9).

Open Question Page
Ask Friends
Question Expert Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 59

युग्म (4x+(r-2)y=14) और (10x+15y=35) के अनंत हलों के लिए (r) का मान क्या है?

What is the value of (r) for infinitely many solutions of (4x+(r-2)y=14) and (10x+15y=35)?

Explanation opens after your attempt
Correct Answer

B. (r=8)

Explanation

Simple Explanation

अनंत हलों में \(\frac{4}{10}=\frac{r-2}{15}=\frac{14}{35}\) होता है। इससे (r=8) प्राप्त होता है। / In infinitely many solutions, \(\frac{4}{10}=\frac{r-2}{15}=\frac{14}{35}\). This gives (r=8).

Open Question Page
Ask Friends
Question Expert Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 59

युग्म ((m-1)x+6y=10) और (3x+9y=15) के अनंत हलों के लिए (m) का मान क्या होगा?

For infinitely many solutions of ((m-1)x+6y=10) and (3x+9y=15), what is the value of (m)?

Explanation opens after your attempt
Correct Answer

C. (m=3)

Explanation

Simple Explanation

अनंत हलों के लिए तीनों अनुपात समान होते हैं। यहाँ \(\frac{m-1}{3}=\frac{6}{9}=\frac{10}{15}\) से (m=3) मिलता है। / For infinitely many solutions, all three ratios are equal. From \(\frac{m-1}{3}=\frac{6}{9}=\frac{10}{15}\), (m=3).

Open Question Page
Ask Friends
Question Expert Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 60

समीकरणों (12x+ky=132) और (3x+10y=33) के अनंत हल होने के लिए (k) क्या होगा?

What will (k) be for the equations (12x+ky=132) and (3x+10y=33) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

C. (40)

Explanation

Simple Explanation

पहला समीकरण दूसरे का (4) गुना होना चाहिए। इसलिए (k=40) है। / The first equation must be (4) times the second. Therefore, (k=40).

Open Question Page
Ask Friends
Question Expert Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 60

एक दुकान में दो वस्तुओं के लिए (6x+11y=420) और (18x+33y=1260) समीकरण बनते हैं। हलों की संख्या क्या होगी?

In a shop, the equations for two items are (6x+11y=420) and (18x+33y=1260). How many solutions will there be?

Explanation opens after your attempt
Correct Answer

C. अनंत हलInfinitely many solutions

Explanation

Simple Explanation

दूसरा समीकरण पहले का (3) गुना है। इसलिए दोनों शर्तें एक ही जानकारी देती हैं और अनंत हल होते हैं। / The second equation is (3) times the first. Therefore, both conditions give the same information and have infinitely many solutions.

Open Question Page
Ask Friends
Question Expert Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 60

समीकरणों (8x+15y=73) और (24x+45y=219) को देखकर सबसे उचित निष्कर्ष क्या है?

What is the most suitable conclusion by observing the equations (8x+15y=73) and (24x+45y=219)?

Explanation opens after your attempt
Correct Answer

C. अनंत हल हैंThere are infinitely many solutions

Explanation

Simple Explanation

दूसरा समीकरण पहले का (3) गुना है। इसलिए दोनों रेखाएं संपाती हैं। / The second equation is (3) times the first. Therefore, both lines are coincident.

Open Question Page
Ask Friends
Question Expert Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 60

यदि (11x+7y=59) और (33x+21y=n) के अनंत हल हैं, तो (n) कितना होगा?

If (11x+7y=59) and (33x+21y=n) have infinitely many solutions, what is (n)?

Explanation opens after your attempt
Correct Answer

C. (177)

Explanation

Simple Explanation

दूसरा समीकरण पहले का (3) गुना होना चाहिए। इसलिए (n=177) होगा। / The second equation must be (3) times the first. Therefore, (n=177).

Open Question Page
Ask Friends
Question Expert Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 60

समीकरणों (7x+dy=63) और (28x+36y=252) के अनंत हल होने के लिए (d) का मान क्या है?

What is the value of (d) for the equations (7x+dy=63) and (28x+36y=252) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

C. (9)

Explanation

Simple Explanation

अनंत हल के लिए (7/28=d/36=63/252) होना चाहिए। इसलिए (d=9)। / For infinitely many solutions, (7/28=d/36=63/252) must hold. Therefore, (d=9).

Open Question Page
Ask Friends
Question Expert Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 60

समीकरणों (10x+13y-71=0) और (30x+39y-213=0) के लिए सही अनुपात संबंध कौन-सा है?

Which ratio relation is correct for the equations (10x+13y-71=0) and (30x+39y-213=0)?

Explanation opens after your attempt
Correct Answer

C. (1030=13 / 39=(-71) / (-213))

Explanation

Simple Explanation

यहां तीनों अनुपात बराबर हैं। इसलिए दोनों रेखाएं संपाती हैं और अनंत हल हैं। / Here all three ratios are equal. Therefore, both lines are coincident and have infinitely many solutions.

Open Question Page
Ask Friends
Question Expert Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 60

समीकरणों (8x+ay=72) और (24x+30y=216) के अनंत हल होने के लिए (a) क्या होगा?

What will (a) be for the equations (8x+ay=72) and (24x+30y=216) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

C. (10)

Explanation

Simple Explanation

अनंत हल के लिए (8/24=a/30=72/216) होना चाहिए। इससे (a=10) मिलता है। / For infinitely many solutions, (8/24=a/30=72/216) must hold. This gives (a=10).

Open Question Page
Ask Friends
Question Expert Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 60

समीकरणों (13x+qy=52) और (26x+18y=104) के अनंत हल होने के लिए (q) का मान क्या है?

What is the value of (q) for the equations (13x+qy=52) and (26x+18y=104) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

C. (9)

Explanation

Simple Explanation

दूसरा समीकरण पहले का (2) गुना है, इसलिए (q/18=1/2) होना चाहिए। अतः (q=9)। / The second equation is (2) times the first, so (q/18=1/2) must hold. Hence, (q=9).

Open Question Page
Ask Friends
Question Expert Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 60

समीकरणों (kx+14y=42) और (18x+21y=63) के अनंत हल होने के लिए (k) क्या होगा?

What will (k) be for the equations (kx+14y=42) and (18x+21y=63) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

C. (12)

Explanation

Simple Explanation

अनंत हल के लिए (k/18=14/21=42/63) होना चाहिए। इसलिए (k=12) सही है। / For infinitely many solutions, (k/18=14/21=42/63) must hold. Therefore, (k=12) is correct.

Open Question Page
Ask Friends
Question Expert Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 60

समीकरणों (4x+ay=32) और (12x+21y=96) के अनंत हल होने के लिए (a) का मान क्या होगा?

What is the value of (a) for the equations (4x+ay=32) and (12x+21y=96) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

C. (7)

Explanation

Simple Explanation

अनंत हल के लिए (4/12=a/21=32/96) होना चाहिए। इसलिए (a=7) सही है। / For infinitely many solutions, (4/12=a/21=32/96) must hold. Therefore, (a=7) is correct.

Open Question Page
Ask Friends
Question Hard Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 60

समीकरणों (5x+ay=45) और (20x+28y=180) के अनंत हल होने के लिए (a) का मान क्या होगा?

What is the value of (a) for the equations (5x+ay=45) and (20x+28y=180) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

C. (7)

Explanation

Simple Explanation

अनंत हल के लिए (5/20=a/28=45/180) होना चाहिए। इसलिए (a=7) सही है। / For infinitely many solutions, (5/20=a/28=45/180) must hold. Therefore, (a=7) is correct.

Open Question Page
Ask Friends
Question Hard Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 60

समीकरणों (10x+ky=110) और (2x+9y=22) के अनंत हल होने के लिए (k) क्या होगा?

What will (k) be for the equations (10x+ky=110) and (2x+9y=22) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

C. (45)

Explanation

Simple Explanation

पहला समीकरण दूसरे का (5) गुना होना चाहिए। इसलिए (k=45) है। / The first equation must be (5) times the second. Therefore, (k=45).

Open Question Page
Ask Friends
Question Hard Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 60

एक दुकान में दो वस्तुओं के लिए (5x+9y=300) और (15x+27y=900) समीकरण बनते हैं। हलों की संख्या क्या होगी?

In a shop, the equations for two items are (5x+9y=300) and (15x+27y=900). How many solutions will there be?

Explanation opens after your attempt
Correct Answer

C. अनंत हलInfinitely many solutions

Explanation

Simple Explanation

दूसरा समीकरण पहले का (3) गुना है। इसलिए दोनों शर्तें एक ही जानकारी देती हैं और अनंत हल होते हैं। / The second equation is (3) times the first. Therefore, both conditions give the same information and have infinitely many solutions.

Open Question Page
Ask Friends
Question Hard Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 60

समीकरणों (9x+14y=71) और (27x+42y=213) को देखकर सबसे उचित निष्कर्ष क्या है?

What is the most suitable conclusion by observing the equations (9x+14y=71) and (27x+42y=213)?

Explanation opens after your attempt
Correct Answer

C. अनंत हल हैंThere are infinitely many solutions

Explanation

Simple Explanation

दूसरा समीकरण पहले का (3) गुना है। इसलिए दोनों रेखाएं संपाती हैं। / The second equation is (3) times the first. Therefore, both lines are coincident.

Open Question Page
Ask Friends
Question Hard Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 60

यदि (9x+5y=47) और (27x+15y=n) के अनंत हल हैं, तो (n) कितना होगा?

If (9x+5y=47) and (27x+15y=n) have infinitely many solutions, what is (n)?

Explanation opens after your attempt
Correct Answer

C. (141)

Explanation

Simple Explanation

दूसरा समीकरण पहले का (3) गुना होना चाहिए। इसलिए (n=141) होगा। / The second equation must be (3) times the first. Therefore, (n=141).

Open Question Page
Ask Friends
Question Hard Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 60

समीकरणों (6x+dy=54) और (18x+30y=162) के अनंत हल होने के लिए (d) का मान क्या है?

What is the value of (d) for the equations (6x+dy=54) and (18x+30y=162) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

C. (10)

Explanation

Simple Explanation

अनंत हल के लिए (6/18=d/30=54/162) होना चाहिए। इसलिए (d=10)। / For infinitely many solutions, (6/18=d/30=54/162) must hold. Therefore, (d=10).

Open Question Page
Ask Friends
Question Hard Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 60

समीकरणों (8x+13y-59=0) और (24x+39y-177=0) के लिए सही अनुपात संबंध कौन-सा है?

Which ratio relation is correct for the equations (8x+13y-59=0) and (24x+39y-177=0)?

Explanation opens after your attempt
Correct Answer

C. (824=13 / 39=(-59) / (-177))

Explanation

Simple Explanation

यहां तीनों अनुपात बराबर हैं। इसलिए दोनों रेखाएं संपाती हैं और अनंत हल हैं। / Here all three ratios are equal. Therefore, both lines are coincident and have infinitely many solutions.

Open Question Page
Ask Friends
Question Hard Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 60

समीकरणों (9x+ay=63) और (27x+24y=189) के अनंत हल होने के लिए (a) क्या होगा?

What will (a) be for the equations (9x+ay=63) and (27x+24y=189) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

C. (8)

Explanation

Simple Explanation

अनंत हल के लिए (9/27=a/24=63/189) होना चाहिए। इससे (a=8) मिलता है। / For infinitely many solutions, (9/27=a/24=63/189) must hold. This gives (a=8).

Open Question Page
Ask Friends
Question Hard Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 60

समीकरणों (11x+qy=44) और (22x+18y=88) के अनंत हल होने के लिए (q) का मान क्या है?

What is the value of (q) for the equations (11x+qy=44) and (22x+18y=88) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

C. (9)

Explanation

Simple Explanation

दूसरा समीकरण पहले का (2) गुना है इसलिए (q/18=1/2) होना चाहिए। अतः (q=9)। / The second equation is (2) times the first so (q/18=1/2) must hold. Hence, (q=9).

Open Question Page
Ask Friends
Question Hard Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 60

समीकरणों (kx+12y=36) और (15x+20y=60) के अनंत हल होने के लिए (k) क्या होगा?

What will (k) be for the equations (kx+12y=36) and (15x+20y=60) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

C. (9)

Explanation

Simple Explanation

अनंत हल के लिए (k/15=12/20=36/60) होना चाहिए। इसलिए (k=9) सही है। / For infinitely many solutions, (k/15=12/20=36/60) must hold. Therefore, (k=9) is correct.

Open Question Page
Ask Friends
Question Hard Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 60

समीकरणों (5x+2y=18) और (15x+ay=54) के अनंत हल होने के लिए (a) का मान क्या होगा?

What is the value of (a) for the equations (5x+2y=18) and (15x+ay=54) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

C. (6)

Explanation

Simple Explanation

अनंत हल के लिए (5/15=2/a=18/54) होना चाहिए। इसलिए (a=6) सही है। / For infinitely many solutions, (5/15=2/a=18/54) must hold. Therefore, (a=6) is correct.

Open Question Page
Ask Friends
Question Hard Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 59

समीकरणों (10x+3y=44) और (20x+ay=88) के अनंत हल होने के लिए (a) का मान क्या होगा?

What is the value of (a) for the equations (10x+3y=44) and (20x+ay=88) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

D. (6)

Explanation

Simple Explanation

अनंत हल के लिए (10/20=3/a=44/88) होना चाहिए। इसलिए (a=6) सही है। / For infinitely many solutions, (10/20=3/a=44/88) must hold. Therefore, (a=6) is correct.

Open Question Page
Ask Friends
Question Hard Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 59

समीकरणों (9x+ky=81) और (3x+8y=27) के अनंत हल होने के लिए (k) क्या होगा?

What will (k) be for the equations (9x+ky=81) and (3x+8y=27) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

C. (24)

Explanation

Simple Explanation

पहला समीकरण दूसरे का (3) गुना होना चाहिए। इसलिए (k=24) है। / The first equation must be (3) times the second. Therefore, (k=24).

Open Question Page
Ask Friends
Question Hard Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 59

एक दुकान में दो वस्तुओं के लिए (4x+7y=210) और (12x+21y=630) समीकरण बनते हैं। हलों की संख्या क्या होगी?

In a shop, the equations for two items are (4x+7y=210) and (12x+21y=630). How many solutions will there be?

Explanation opens after your attempt
Correct Answer

C. अनंत हलInfinitely many solutions

Explanation

Simple Explanation

दूसरा समीकरण पहले का (3) गुना है। इसलिए दोनों शर्तें एक ही जानकारी देती हैं और अनंत हल होते हैं। / The second equation is (3) times the first. Therefore, both conditions give the same information and have infinitely many solutions.

Open Question Page
Ask Friends
Question Hard Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 59

समीकरणों (7x+12y=53) और (21x+36y=159) को देखकर सबसे उचित निष्कर्ष क्या है?

What is the most suitable conclusion by observing the equations (7x+12y=53) and (21x+36y=159)?

Explanation opens after your attempt
Correct Answer

C. अनंत हल हैंThere are infinitely many solutions

Explanation

Simple Explanation

दूसरा समीकरण पहले का (3) गुना है। इसलिए दोनों रेखाएं संपाती हैं। / The second equation is (3) times the first. Therefore, both lines are coincident.

Open Question Page
Ask Friends
Question Hard Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 59

यदि (8x+5y=43) और (24x+15y=n) के अनंत हल हैं, तो (n) कितना होगा?

If (8x+5y=43) and (24x+15y=n) have infinitely many solutions, what is (n)?

Explanation opens after your attempt
Correct Answer

C. (129)

Explanation

Simple Explanation

दूसरा समीकरण पहले का (3) गुना होना चाहिए। इसलिए (n=129) होगा। / The second equation must be (3) times the first. Therefore, (n=129).

Open Question Page
Ask Friends
Question Hard Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 59

समीकरणों (5x+dy=40) और (20x+28y=160) के अनंत हल होने के लिए (d) का मान क्या है?

What is the value of (d) for the equations (5x+dy=40) and (20x+28y=160) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

C. (7)

Explanation

Simple Explanation

अनंत हल के लिए (5/20=d/28=40/160) होना चाहिए। इसलिए (d=7)। / For infinitely many solutions, (5/20=d/28=40/160) must hold. Therefore, (d=7).

Open Question Page
Ask Friends
Question Hard Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 59

समीकरणों (6x+11y-47=0) और (18x+33y-141=0) के लिए सही अनुपात संबंध कौन-सा है?

Which ratio relation is correct for the equations (6x+11y-47=0) and (18x+33y-141=0)?

Explanation opens after your attempt
Correct Answer

C. (618=11 / 33=(-47) / (-141))

Explanation

Simple Explanation

यहां तीनों अनुपात बराबर हैं। इसलिए दोनों रेखाएं संपाती हैं और अनंत हल हैं। / Here all three ratios are equal. Therefore, both lines are coincident and have infinitely many solutions.

Open Question Page
Ask Friends
Question Hard Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 59

यदि दो रेखाओं की ढाल समान और (y)-अवरोध भी समान हो, तो युग्म के हल कैसे होंगे?

If two lines have the same slope and the same (y)-intercept, what will be the solutions of the pair?

Explanation opens after your attempt
Correct Answer

C. अनंत हलInfinitely many solutions

Explanation

Simple Explanation

समान ढाल और समान अवरोध का अर्थ है कि दोनों रेखाएं एक ही हैं। इसलिए युग्म के अनंत हल होते हैं। / Same slope and same intercept mean both lines are identical. Therefore, the pair has infinitely many solutions.

Open Question Page
Ask Friends
Question Hard Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 59

समीकरणों (7x+ay=49) और (21x+18y=147) के अनंत हल होने के लिए (a) क्या होगा?

What will (a) be for the equations (7x+ay=49) and (21x+18y=147) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

C. (6)

Explanation

Simple Explanation

अनंत हल के लिए (7/21=a/18=49/147) होना चाहिए। इससे (a=6) मिलता है। / For infinitely many solutions, (7/21=a/18=49/147) must hold. This gives (a=6).

Open Question Page
Ask Friends
Question Hard Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 59

समीकरणों (9x+qy=36) और (18x+14y=72) के अनंत हल होने के लिए (q) का मान क्या है?

What is the value of (q) for the equations (9x+qy=36) and (18x+14y=72) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

C. (7)

Explanation

Simple Explanation

दूसरा समीकरण पहले का (2) गुना है, इसलिए (q/14=1/2) होना चाहिए। अतः (q=7)। / The second equation is (2) times the first, so (q/14=1/2) must hold. Hence, (q=7).

Open Question Page
Ask Friends
Question Hard Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 59

समीकरणों (kx+10y=30) और (12x+15y=45) के अनंत हल होने के लिए (k) क्या होगा?

What will (k) be for the equations (kx+10y=30) and (12x+15y=45) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

B. (8)

Explanation

Simple Explanation

अनंत हल के लिए (k/12=10/15=30/45) होना चाहिए। इसलिए (k=8) सही है। / For infinitely many solutions, (k/12=10/15=30/45) must hold. Therefore, (k=8) is correct.

Open Question Page
Ask Friends
Question Hard Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 59

समीकरणों (4x+ay=28) और (12x+15y=84) के अनंत हल होने के लिए (a) का मान क्या होगा?

What is the value of (a) for the equations (4x+ay=28) and (12x+15y=84) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

B. (5)

Explanation

Simple Explanation

अनंत हल के लिए (4/12=a/15=28/84) होना चाहिए। इसलिए (a=5) सही है। / For infinitely many solutions, (4/12=a/15=28/84) must hold. Therefore, (a=5) is correct.

Open Question Page
Ask Friends
Question Hard Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 58

समीकरणों (mx+5y=15) और (18x+15y=45) के अनंत हल होने के लिए (m) का मान क्या होगा?

What will be the value of (m) for the equations (mx+5y=15) and (18x+15y=45) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

C. (6)

Explanation

Simple Explanation

अनंत हल के लिए (m/18=5/15=15/45) होना चाहिए। इसलिए (m=6) सही है। / For infinitely many solutions, (m/18=5/15=15/45) must hold. Therefore, (m=6) is correct.

Open Question Page
Ask Friends
Question Hard Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 58

समीकरणों (8x+ky=72) और (2x+7y=18) के अनंत हल होने के लिए (k) क्या होगा?

What will (k) be for the equations (8x+ky=72) and (2x+7y=18) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

C. (28)

Explanation

Simple Explanation

पहला समीकरण दूसरे का (4) गुना होना चाहिए। इसलिए (k=28) है। / The first equation must be (4) times the second. Therefore, (k=28).

Open Question Page
Ask Friends
Question Hard Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 58

समीकरणों (6x+7y=41) और (18x+21y=123) को देखकर सबसे उचित निष्कर्ष क्या है?

What is the most suitable conclusion by observing the equations (6x+7y=41) and (18x+21y=123)?

Explanation opens after your attempt
Correct Answer

C. अनंत हल हैंThere are infinitely many solutions

Explanation

Simple Explanation

दूसरा समीकरण पहले का (3) गुना है। इसलिए दोनों रेखाएं संपाती हैं। / The second equation is (3) times the first. Therefore, both lines are coincident.

Open Question Page
Ask Friends
Question Hard Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 58

समीकरणों (3x+by=24) और (12x+20y=96) के अनंत हल होने के लिए (b) का मान क्या है?

What is the value of (b) for the equations (3x+by=24) and (12x+20y=96) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

C. (5)

Explanation

Simple Explanation

अनंत हल के लिए (3/12=b/20=24/96) होना चाहिए। इसलिए (b=5)। / For infinitely many solutions, (3/12=b/20=24/96) must hold. Therefore, (b=5).

Open Question Page
Ask Friends
Question Hard Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 58

समीकरणों (4x+9y-31=0) और (12x+27y-93=0) के लिए सही अनुपात संबंध कौन-सा है?

Which ratio relation is correct for the equations (4x+9y-31=0) and (12x+27y-93=0)?

Explanation opens after your attempt
Correct Answer

C. (412=9 / 27=(-31) / (-93))

Explanation

Simple Explanation

यहां तीनों अनुपात बराबर हैं। इसलिए दोनों रेखाएं संपाती हैं और अनंत हल हैं। / Here all three ratios are equal. Therefore, both lines are coincident and have infinitely many solutions.

Open Question Page
Ask Friends
Question Hard Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 58

समीकरणों (5x+ay=35) और (15x+18y=105) के अनंत हल होने के लिए (a) क्या होगा?

What will (a) be for the equations (5x+ay=35) and (15x+18y=105) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

C. (6)

Explanation

Simple Explanation

अनंत हल के लिए (5/15=a/18=35/105) होना चाहिए। इससे (a=6) मिलता है। / For infinitely many solutions, (5/15=a/18=35/105) must hold. This gives (a=6).

Open Question Page
Ask Friends
Question Hard Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 58

समीकरणों (7x+qy=29) और (14x+10y=58) के अनंत हल होने के लिए (q) का मान क्या है?

What is the value of (q) for the equations (7x+qy=29) and (14x+10y=58) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

C. (5)

Explanation

Simple Explanation

दूसरा समीकरण पहले का (2) गुना है, इसलिए (q/10=1/2) होना चाहिए। अतः (q=5)। / The second equation is (2) times the first, so (q/10=1/2) must hold. Hence, (q=5).

Open Question Page
Ask Friends
Question Hard Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 58

समीकरणों (px+6y=18) और (10x+15y=45) के अनंत हल होने के लिए (p) क्या होगा?

What will (p) be for the equations (px+6y=18) and (10x+15y=45) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

B. (3)

Explanation

Simple Explanation

अनंत हल के लिए (p/10=6/15=18/45) होना चाहिए। इसलिए (p=4) नहीं, (p=4) नहीं बल्कि (p=4) अनुपात बिगाड़ता है और सही (p=4) नहीं है। / For infinitely many solutions, (p/10=6/15=18/45) must hold. Since the common ratio is (2/5), (p=4) would be required.

Open Question Page
Ask Friends
Question Hard Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 58

समीकरणों (3x+ky=12) और (9x+15y=36) के अनंत हल होने के लिए (k) का मान क्या होगा?

What is the value of (k) for the equations (3x+ky=12) and (9x+15y=36) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

C. (5)

Explanation

Simple Explanation

अनंत हल के लिए (3/9=k/15=12/36) होना चाहिए। इसलिए (k=5) सही है। / For infinitely many solutions, (3/9=k/15=12/36) must hold. Therefore, (k=5) is correct.

Open Question Page
Ask Friends
Question Medium Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 60

समीकरण (4x+ay=36) और (12x+21y=108) के अनंत हल होने के लिए (a) का मान क्या होगा?

What will be the value of (a) for (4x+ay=36) and (12x+21y=108) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

C. (7)

Explanation

Simple Explanation

अनंत हल के लिए (4/12=a/21=36/108) होना चाहिए। इसलिए (a=7) मिलता है। / For infinitely many solutions (4/12=a/21=36/108) must hold. Therefore (a=7).

Open Question Page
Ask Friends
Question Medium Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 60

समीकरण (8x+ky=72) और (2x+7y=18) के अनंत हल होने के लिए (k) क्या होगा?

What will (k) be for (8x+ky=72) and (2x+7y=18) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

C. (28)

Explanation

Simple Explanation

पहला समीकरण दूसरे का (4) गुना होना चाहिए। इसलिए (k=28) है। / The first equation must be (4) times the second. Therefore (k=28).

Open Question Page
Ask Friends
Question Medium Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 60

एक दुकान में दो वस्तुओं के लिए (3x+4y=150) और (9x+12y=450) समीकरण बनते हैं। हलों की संख्या क्या होगी?

In a shop the equations for two items are (3x+4y=150) and (9x+12y=450). How many solutions will there be?

Explanation opens after your attempt
Correct Answer

C. अनंत हलInfinitely many solutions

Explanation

Simple Explanation

दूसरा समीकरण पहले का (3) गुना है। इसलिए दोनों शर्तें एक ही जानकारी देती हैं और अनंत हल होते हैं। / The second equation is (3) times the first. Therefore both conditions give the same information and have infinitely many solutions.

Open Question Page
Ask Friends
Question Medium Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 60

समीकरण (6x+7y=41) और (18x+21y=123) को देखकर सबसे उचित निष्कर्ष क्या है?

What is the most suitable conclusion by observing (6x+7y=41) and (18x+21y=123)?

Explanation opens after your attempt
Correct Answer

C. अनंत हल हैंThere are infinitely many solutions

Explanation

Simple Explanation

दूसरा समीकरण पहले का (3) गुना है। इसलिए दोनों रेखाएं संपाती हैं। / The second equation is (3) times the first. Therefore both lines are coincident.

Open Question Page
Ask Friends
Question Medium Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 60

यदि (7x+4y=37) और (21x+12y=n) के अनंत हल हैं तो (n) कितना होगा?

If (7x+4y=37) and (21x+12y=n) have infinitely many solutions then what is (n)?

Explanation opens after your attempt
Correct Answer

C. (111)

Explanation

Simple Explanation

दूसरा समीकरण पहले का (3) गुना होना चाहिए। इसलिए (n=111) होगा। / The second equation must be (3) times the first. Therefore (n=111).

Open Question Page
Ask Friends
Question Medium Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 60

समीकरण (3x+by=24) और (12x+20y=96) के अनंत हल होने के लिए (b) का मान क्या है?

What is the value of (b) for (3x+by=24) and (12x+20y=96) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

C. (5)

Explanation

Simple Explanation

अनंत हल के लिए (3/12=b/20=24/96) होना चाहिए। इसलिए (b=5)। / For infinitely many solutions (3/12=b/20=24/96) must hold. Therefore (b=5).

Open Question Page
Ask Friends
Question Medium Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 60

समीकरण (4x+9y-31=0) और (12x+27y-93=0) के लिए सही अनुपात संबंध कौन-सा है?

Which ratio relation is correct for (4x+9y-31=0) and (12x+27y-93=0)?

Explanation opens after your attempt
Correct Answer

C. (412=9 / 27=(-31) / (-93))

Explanation

Simple Explanation

यहां तीनों अनुपात बराबर हैं। इसलिए दोनों रेखाएं संपाती हैं और अनंत हल हैं। / Here all three ratios are equal. Therefore both lines are coincident and have infinitely many solutions.

Open Question Page
Ask Friends
Question Medium Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 60

समीकरण (5x+ay=35) और (15x+18y=105) के अनंत हल होने के लिए (a) क्या होगा?

What will (a) be for (5x+ay=35) and (15x+18y=105) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

C. (6)

Explanation

Simple Explanation

अनंत हल के लिए (5/15=a/18=35/105) होना चाहिए। इससे (a=6) मिलता है। / For infinitely many solutions (5/15=a/18=35/105) must hold. This gives (a=6).

Open Question Page
Ask Friends
Question Medium Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 60

समीकरण (7x+qy=29) और (14x+10y=58) के अनंत हल होने के लिए (q) क्या होगा?

What will (q) be for (7x+qy=29) and (14x+10y=58) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

C. (5)

Explanation

Simple Explanation

दूसरा समीकरण पहले का (2) गुना है इसलिए (q/10=1/2) होना चाहिए। अतः (q=5)। / The second equation is (2) times the first so (q/10=1/2) must hold. Hence (q=5).

Open Question Page
Ask Friends
Question Medium Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 60

समीकरण (px+6y=18) और (10x+15y=45) के अनंत हल होने के लिए (p) का मान क्या होगा?

What is the value of (p) for (px+6y=18) and (10x+15y=45) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

B. (3)

Explanation

Simple Explanation

अनंत हल के लिए (p/10=6/15=18/45) होना चाहिए। इसलिए (p=3)। / For infinitely many solutions (p/10=6/15=18/45) must hold. Therefore (p=3).

Open Question Page
Ask Friends
Question Medium Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 60

समीकरण (8x+3y=21) और (16x+6y=42) के लिए सही निष्कर्ष क्या है?

What is the correct conclusion for (8x+3y=21) and (16x+6y=42)?

Explanation opens after your attempt
Correct Answer

A. अनंत हलInfinitely many solutions

Explanation

Simple Explanation

दूसरा समीकरण पहले का (2) गुना है इसलिए दोनों रेखाएं संपाती हैं। संपाती रेखाओं के अनंत हल होते हैं। / The second equation is (2) times the first so both lines are coincident. Coincident lines have infinitely many solutions.

Open Question Page
Ask Friends
Question Medium Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 60

समीकरण (2x+5y=16) और (6x+15y=k) के अनंत हल होने के लिए (k) का मान क्या होगा?

What is the value of (k) for (2x+5y=16) and (6x+15y=k) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

B. (48)

Explanation

Simple Explanation

दूसरा समीकरण पहले का (3) गुना होना चाहिए इसलिए (k=48)। अनंत हल के लिए सभी अनुपात बराबर होने चाहिए। / The second equation must be (3) times the first so (k=48). For infinitely many solutions all ratios must be equal.

Open Question Page
Ask Friends
Question Medium Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 59

समीकरण (3x+my=24) और (12x+28y=96) के अनंत हल होने के लिए (m) का मान क्या होगा?

What will be the value of (m) for (3x+my=24) and (12x+28y=96) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

C. (7)

Explanation

Simple Explanation

अनंत हल के लिए (3/12=m/28=24/96) होना चाहिए। इसलिए (m=7) सही है। / For infinitely many solutions, (3/12=m/28=24/96) must hold. Therefore, (m=7) is correct.

Open Question Page
Ask Friends
Question Medium Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 59

समीकरण (6x+ky=42) और (2x+5y=14) के अनंत हल होने के लिए (k) क्या होगा?

What will (k) be for (6x+ky=42) and (2x+5y=14) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

B. (15)

Explanation

Simple Explanation

पहला समीकरण दूसरे का (3) गुना होना चाहिए। इसलिए (k=15) है। / The first equation must be (3) times the second. Therefore, (k=15).

Open Question Page
Ask Friends
Question Medium Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 59

एक दुकान में दो वस्तुओं के लिए (2x+3y=90) और (4x+6y=180) समीकरण बनते हैं। हलों की संख्या क्या होगी?

In a shop, the equations for two items are (2x+3y=90) and (4x+6y=180). How many solutions will there be?

Explanation opens after your attempt
Correct Answer

C. अनंत हलInfinitely many solutions

Explanation

Simple Explanation

दूसरा समीकरण पहले का (2) गुना है। इसलिए दोनों शर्तें एक ही जानकारी देती हैं और अनंत हल होते हैं। / The second equation is (2) times the first. Therefore, both conditions give the same information and have infinitely many solutions.

Open Question Page
Ask Friends
Question Medium Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 59

समीकरण (5x+3y=17) और (15x+9y=51) को देखकर सबसे उचित निष्कर्ष क्या है?

What is the most suitable conclusion by observing (5x+3y=17) and (15x+9y=51)?

Explanation opens after your attempt
Correct Answer

C. अनंत हल हैंThere are infinitely many solutions

Explanation

Simple Explanation

दूसरा समीकरण पहले का (3) गुना है। इसलिए दोनों रेखाएं संपाती हैं। / The second equation is (3) times the first. Therefore, both lines are coincident.

Open Question Page
Ask Friends
Question Medium Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 59

यदि (6x+5y=31) और (12x+10y=n) के अनंत हल हैं, तो (n) कितना होगा?

If (6x+5y=31) and (12x+10y=n) have infinitely many solutions, what is (n)?

Explanation opens after your attempt
Correct Answer

C. (62)

Explanation

Simple Explanation

दूसरा समीकरण पहले का (2) गुना होना चाहिए। इसलिए (n=62) होगा। / The second equation must be (2) times the first. Therefore, (n=62).

Open Question Page
Ask Friends
Question Medium Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 59

समीकरण (4x+by=28) और (12x+21y=84) के अनंत हल होने के लिए (b) का मान क्या है?

What is the value of (b) for (4x+by=28) and (12x+21y=84) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

C. (7)

Explanation

Simple Explanation

अनंत हल के लिए (4/12=b/21=28/84) होना चाहिए। इसलिए (b=7) होगा। / For infinitely many solutions, (4/12=b/21=28/84) must hold. Therefore, (b=7).

Open Question Page
Ask Friends
Question Medium Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 59

समीकरण (3x+5y-20=0) और (9x+15y-60=0) के लिए सही अनुपात संबंध कौन-सा है?

Which ratio relation is correct for (3x+5y-20=0) and (9x+15y-60=0)?

Explanation opens after your attempt
Correct Answer

C. (39=5 / 15=(-20) / (-60))

Explanation

Simple Explanation

यहां तीनों अनुपात बराबर हैं। इसलिए दोनों रेखाएं संपाती हैं और अनंत हल हैं। / Here all three ratios are equal. Therefore, both lines are coincident and have infinitely many solutions.

Open Question Page
Ask Friends
Question Medium Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 59

समीकरण (5x+ky=35) और (x+4y=7) के अनंत हल होने के लिए (k) का मान क्या होगा?

What is the value of (k) for (5x+ky=35) and (x+4y=7) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

C. (20)

Explanation

Simple Explanation

पहला समीकरण दूसरे का (5) गुना होना चाहिए, इसलिए (k=20)। समान गुणक से दोनों रेखाएं संपाती होती हैं। / The first equation must be (5) times the second, so (k=20). A common multiplier makes both lines coincident.

Open Question Page
Ask Friends
Question Medium Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 59

समीकरण (px+3y=15) और (12x+6y=30) के अनंत हल होने के लिए (p) क्या होगा?

What will (p) be for (px+3y=15) and (12x+6y=30) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

C. (6)

Explanation

Simple Explanation

अनंत हल के लिए (p/12=3/6=15/30) होना चाहिए। इसलिए (p=6) है। / For infinitely many solutions, (p/12=3/6=15/30) must hold. Therefore, (p=6).

Open Question Page
Ask Friends
Question Medium Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 59

समीकरण (7x+2y=19) और (14x+4y=38) के लिए सही निष्कर्ष क्या है?

What is the correct conclusion for (7x+2y=19) and (14x+4y=38)?

Explanation opens after your attempt
Correct Answer

C. अनंत हलInfinitely many solutions

Explanation

Simple Explanation

दूसरा समीकरण पहले का (2) गुना है, इसलिए दोनों रेखाएं संपाती हैं। संपाती रेखाओं के अनंत हल होते हैं। / The second equation is (2) times the first, so both lines are coincident. Coincident lines have infinitely many solutions.

Open Question Page
Ask Friends
Question Medium Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 59

समीकरण (3x+ay=21) और (9x+12y=63) के अनंत हल होने के लिए (a) क्या होगा?

What will (a) be for (3x+ay=21) and (9x+12y=63) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

C. (4)

Explanation

Simple Explanation

अनंत हल के लिए (3/9=a/12=21/63) होना चाहिए। इसलिए (a=4) है। / For infinitely many solutions, (3/9=a/12=21/63) must hold. Therefore, (a=4).

Open Question Page
Ask Friends
Question Medium Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 59

समीकरण (5x+4y=18) और (10x+8y=k) के अनंत हल होने के लिए (k) का मान क्या होगा?

What is the value of (k) for (5x+4y=18) and (10x+8y=k) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

B. (36)

Explanation

Simple Explanation

दूसरा समीकरण पहले का (2) गुना होना चाहिए, इसलिए (k=36)। अनंत हल के लिए तीनों अनुपात बराबर रखें। / The second equation must be (2) times the first, so (k=36). For infinitely many solutions, keep all three ratios equal.

Open Question Page
Ask Friends
Question Medium Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 58

समीकरण (2x+my=14) और (8x+20y=56) के अनंत हल होने के लिए (m) का मान क्या होगा?

What will be the value of (m) for (2x+my=14) and (8x+20y=56) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

A. (5)

Explanation

Simple Explanation

अनंत हल के लिए (2/8=m/20=14/56) होना चाहिए। इसलिए (m=5) है। / For infinitely many solutions, (2/8=m/20=14/56) must hold. Therefore, (m=5).

Open Question Page
Ask Friends
Question Medium Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 58

समीकरण (5x+ky=25) और (x+3y=5) के अनंत हल होने के लिए (k) क्या होगा?

What will (k) be for (5x+ky=25) and (x+3y=5) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

B. (15)

Explanation

Simple Explanation

पहला समीकरण दूसरे का (5) गुना होना चाहिए। इसलिए (k=15)। / The first equation must be (5) times the second. Therefore, (k=15).

Open Question Page
Ask Friends
Question Medium Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 58

एक दुकान पर दो वस्तुओं के लिए समीकरण (x+2y=50) और (2x+4y=100) बनते हैं। हलों की संख्या क्या होगी?

For two items in a shop, the equations are (x+2y=50) and (2x+4y=100). How many solutions will there be?

Explanation opens after your attempt
Correct Answer

C. अनंत हलInfinitely many solutions

Explanation

Simple Explanation

दूसरा समीकरण पहले का (2) गुना है। इसलिए दोनों शर्तें एक ही जानकारी देती हैं और अनंत हल होते हैं। / The second equation is (2) times the first. Therefore, both conditions give the same information and have infinitely many solutions.

Open Question Page
Ask Friends
Question Medium Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 58

समीकरण (3x+2y=8) और (9x+6y=24) को देखकर सबसे उचित निष्कर्ष क्या है?

What is the most suitable conclusion by observing (3x+2y=8) and (9x+6y=24)?

Explanation opens after your attempt
Correct Answer

C. अनंत हल हैंThere are infinitely many solutions

Explanation

Simple Explanation

दूसरा समीकरण पहले का (3) गुना है। इसलिए दोनों रेखाएं संपाती हैं। / The second equation is (3) times the first. Therefore, both lines are coincident.

Open Question Page
Ask Friends