Update

Muft Shiksha™ एक 100% Free Education Portal है 🇮🇳, जिसका उद्देश्य Class 9–12 के हर विद्यार्थी तक High-Quality Education को पूरी तरह मुफ्त पहुँचाना है। 🇮🇳 हम मानते हैं कि अच्छी शिक्षा किसी student की आर्थिक स्थिति पर निर्भर नहीं होनी चाहिए। 🇮🇳 हर विद्यार्थी को वही Quality Study Material, MCQs, Quizzes, Exam Preparation, Concept-Based Learning और Bilingual Support मिलना चाहिए, जो आमतौर पर महंगी Coaching या Premium Platforms में मिलता है। Muft Shiksha™ 🇮🇳 इसी सोच के साथ बनाया गया है

Subjects
0 reads0 ratings0 helpful

What is the most suitable conclusion by observing the equations (6x+7y=41) and (18x+21y=123)?

Advertisement

Answer and explanation

Correct answer: There are infinitely many solutions

Dividing every term of the second equation by 3 gives \(6x+7y=41\), which is exactly the first equation. Hence, both equations represent the same line and have infinitely many common solutions. Therefore, option C is correct. Option B would apply if the two lines were distinct parallel lines. For exams, remember: if \(\frac{a_1}{a_2}=\frac{b_1}{b_2}=\frac{c_1}{c_2}\), the pair has infinitely many solutions.

Related tags

Linear EquationsSolvability ConditionsCoincident LinesInfinite SolutionsClass 10 Mathematics

Frequently asked questions

What is the correct answer to this question?

There are infinitely many solutions

Why is this the correct answer?

Dividing every term of the second equation by 3 gives \(6x+7y=41\), which is exactly the first equation. Hence, both equations represent the same line and have infinitely many common solutions. Therefore, option C is correct. Option B would apply if the two lines were distinct parallel lines. For exams, remember: if \(\frac{a_1}{a_2}=\frac{b_1}{b_2}=\frac{c_1}{c_2}\), the pair has infinitely many solutions.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Pair of Linear Equations in Two Variables. Topic: Conditions for solvability.

Was this question useful?

No ratings yetWrite a review / Rate this question

Student Reviews

No published reviews yet.

Advertisement