A. सीमाएं नागरिकता प्रवास विस्थापन और हिंसा के प्रश्न पैदा कर सकती थीं/Borders could create questions of citizenship migration displacement and violence
Step 1
Concept
Boundary making was not only mapping but linked with people's lives. For exams study citizenship and migration together.
Step 2
Why this answer is correct
The correct answer is A. सीमाएं नागरिकता प्रवास विस्थापन और हिंसा के प्रश्न पैदा कर सकती थीं / Borders could create questions of citizenship migration displacement and violence. Boundary making was not only mapping but linked with people's lives. For exams study citizenship and migration together.
Step 3
Exam Tip
सीमा निर्धारण केवल नक्शा नहीं बल्कि लोगों के जीवन से जुड़ा था। परीक्षा में नागरिकता और प्रवास साथ पढ़ें।
A. खनिज लाभ के साथ भूमि क्षति विस्थापन और श्रम शोषण जुड़ा था/Mineral profit was linked with land damage displacement and labour exploitation
Step 1
Concept
Mining is a major example of colonial resource extraction. For exams write both environment and society.
Step 2
Why this answer is correct
The correct answer is A. खनिज लाभ के साथ भूमि क्षति विस्थापन और श्रम शोषण जुड़ा था / Mineral profit was linked with land damage displacement and labour exploitation. Mining is a major example of colonial resource extraction. For exams write both environment and society.
Step 3
Exam Tip
खनन औपनिवेशिक संसाधन दोहन का प्रमुख उदाहरण है। परीक्षा में पर्यावरण और समाज दोनों लिखें।
\( \sqrt{18}\approx4.243 \) and \( \sqrt{17}\approx4.123 \), so the difference is about (0.12). The difference of nearby roots is small.
Step 2
Why this answer is correct
The correct answer is B. (0.12). \( \sqrt{18}\approx4.243 \) and \( \sqrt{17}\approx4.123 \), so the difference is about (0.12). The difference of nearby roots is small.
Step 3
Exam Tip
\( \sqrt{18}\approx4.243 \) और \( \sqrt{17}\approx4.123 \), इसलिए अंतर लगभग (0.12) है। पास-पास मूलों का अंतर छोटा होता है।
B. ( -6 ) और ( -5 ) के बीच/Between ( -6 ) and ( -5 )
Step 1
Concept
\( \sqrt{99}\approx9.95 \), so \(p\approx-5.95\). Hence it lies between (-6) and (-5).
Step 2
Why this answer is correct
The correct answer is B. ( -6 ) और ( -5 ) के बीच / Between ( -6 ) and ( -5 ). \( \sqrt{99}\approx9.95 \), so \(p\approx-5.95\). Hence it lies between (-6) and (-5).
Step 3
Exam Tip
\( \sqrt{99}\approx9.95 \), इसलिए \(p\approx-5.95\) है। अतः यह (-6) और (-5) के बीच होगा।
\( \sqrt{48}\approx6.928 \) and \( \sqrt{49}=7 \), so (6.95) lies between them. Use accurate estimation for close roots.
Step 2
Why this answer is correct
The correct answer is B. (6.95). \( \sqrt{48}\approx6.928 \) and \( \sqrt{49}=7 \), so (6.95) lies between them. Use accurate estimation for close roots.
Step 3
Exam Tip
\( \sqrt{48}\approx6.928 \) और \( \sqrt{49}=7 \), इसलिए (6.95) इनके बीच है। पास-पास मूलों में सटीक अनुमान करें।
\( \sqrt{126}\approx11.22 \) and \( \sqrt{80}\approx8.94 \), so the difference is about (2.28). Estimate both square roots first.
Step 2
Why this answer is correct
The correct answer is B. (2) और (3) / (2) and (3). \( \sqrt{126}\approx11.22 \) and \( \sqrt{80}\approx8.94 \), so the difference is about (2.28). Estimate both square roots first.
Step 3
Exam Tip
\( \sqrt{126}\approx11.22 \) और \( \sqrt{80}\approx8.94 \), इसलिए अंतर लगभग (2.28) है। पहले दोनों वर्गमूलों का अनुमान करें।
\( \sqrt{11}\approx3.317 \) and \( \sqrt{10}\approx3.162 \), so the difference is about (0.155). The difference of nearby roots is small.
Step 2
Why this answer is correct
The correct answer is B. (0.15). \( \sqrt{11}\approx3.317 \) and \( \sqrt{10}\approx3.162 \), so the difference is about (0.155). The difference of nearby roots is small.
Step 3
Exam Tip
\( \sqrt{11}\approx3.317 \) और \( \sqrt{10}\approx3.162 \), इसलिए अंतर लगभग (0.155) है। पास-पास मूलों का अंतर छोटा होता है।
A. ( -6 ) और ( -5 ) के बीच/Between ( -6 ) and ( -5 )
Step 1
Concept
\( \sqrt{68}\approx8.246 \), so \(p\approx-5.246\). Hence it lies between (-6) and (-5).
Step 2
Why this answer is correct
The correct answer is A. ( -6 ) और ( -5 ) के बीच / Between ( -6 ) and ( -5 ). \( \sqrt{68}\approx8.246 \), so \(p\approx-5.246\). Hence it lies between (-6) and (-5).
Step 3
Exam Tip
\( \sqrt{68}\approx8.246 \), इसलिए \(p\approx-5.246\) है। इसलिए यह (-6) और (-5) के बीच है।
\( \sqrt{33}\approx5.745 \) and \( \sqrt{34}\approx5.831 \), so (5.75) lies between them. Keep estimates accurate for close roots.
Step 2
Why this answer is correct
The correct answer is B. (5.75). \( \sqrt{33}\approx5.745 \) and \( \sqrt{34}\approx5.831 \), so (5.75) lies between them. Keep estimates accurate for close roots.
Step 3
Exam Tip
\( \sqrt{33}\approx5.745 \) और \( \sqrt{34}\approx5.831 \), इसलिए (5.75) इनके बीच है। निकट वर्गमूलों में अनुमान सटीक रखें।
\( \sqrt{91}\approx9.54 \) and \( \sqrt{55}\approx7.42 \), so the difference is about (2.12). Estimate both roots first.
Step 2
Why this answer is correct
The correct answer is B. (2) और (3) / (2) and (3). \( \sqrt{91}\approx9.54 \) and \( \sqrt{55}\approx7.42 \), so the difference is about (2.12). Estimate both roots first.
Step 3
Exam Tip
\( \sqrt{91}\approx9.54 \) और \( \sqrt{55}\approx7.42 \), इसलिए अंतर लगभग (2.12) है। पहले दोनों मूलों का अनुमान करें।
\( \sqrt{6}\approx2.449 \) and \( \frac{1}{3}\approx0.333 \), so the sum is about (2.782). For mixed values, estimate first.
Step 2
Why this answer is correct
The correct answer is B. (2) और (3) / (2) and (3). \( \sqrt{6}\approx2.449 \) and \( \frac{1}{3}\approx0.333 \), so the sum is about (2.782). For mixed values, estimate first.
Step 3
Exam Tip
\( \sqrt{6}\approx2.449 \) और \( \frac{1}{3}\approx0.333 \), इसलिए योग लगभग (2.782) है। मिश्रित मानों में पहले अनुमान लगाएँ।
\( \sqrt{21}\approx4.583 \) and \( \sqrt{22}\approx4.690 \), so (4.65) lies between them. Estimate accurately for close roots.
Step 2
Why this answer is correct
The correct answer is C. (4.65). \( \sqrt{21}\approx4.583 \) and \( \sqrt{22}\approx4.690 \), so (4.65) lies between them. Estimate accurately for close roots.
Step 3
Exam Tip
\( \sqrt{21}\approx4.583 \) और \( \sqrt{22}\approx4.690 \), इसलिए (4.65) इनके बीच है। पास-पास मूलों में सटीक अनुमान करें।
\( \sqrt{7}\approx2.646 \) and \( \sqrt{5}\approx2.236 \), so the difference is about (0.41). The difference of nearby roots is small.
Step 2
Why this answer is correct
The correct answer is A. (0.41). \( \sqrt{7}\approx2.646 \) and \( \sqrt{5}\approx2.236 \), so the difference is about (0.41). The difference of nearby roots is small.
Step 3
Exam Tip
\( \sqrt{7}\approx2.646 \) और \( \sqrt{5}\approx2.236 \), इसलिए अंतर लगभग (0.41) है। निकट मूलों का अंतर छोटा होता है।
A. ( -5 ) और ( -4 ) के बीच/Between ( -5 ) and ( -4 )
Step 1
Concept
\( \sqrt{45}\approx6.708 \), so \(p\approx-4.708\). Hence it lies between (-5) and (-4).
Step 2
Why this answer is correct
The correct answer is A. ( -5 ) और ( -4 ) के बीच / Between ( -5 ) and ( -4 ). \( \sqrt{45}\approx6.708 \), so \(p\approx-4.708\). Hence it lies between (-5) and (-4).
Step 3
Exam Tip
\( \sqrt{45}\approx6.708 \), इसलिए \(p\approx-4.708\) है। इसलिए यह (-5) और (-4) के बीच है।
\( \sqrt{31}\approx5.57 \) and \( \sqrt{12}\approx3.46 \) so the difference is about (2.11). Estimate both roots first.
Step 2
Why this answer is correct
The correct answer is B. (1) और (2) / (1) and (2). \( \sqrt{31}\approx5.57 \) and \( \sqrt{12}\approx3.46 \) so the difference is about (2.11). Estimate both roots first.
Step 3
Exam Tip
\( \sqrt{31}\approx5.57 \) और \( \sqrt{12}\approx3.46 \) इसलिए अंतर लगभग (2.11) है। पहले दोनों मूलों का अनुमान करें।
Since \( \sqrt{5}\approx2.236\), \( \sqrt{5}+\frac{1}{2}\approx2.736\). Use estimation to identify the interval quickly.
Step 2
Why this answer is correct
The correct answer is A. (2) और (3) / (2) and (3). Since \( \sqrt{5}\approx2.236\), \( \sqrt{5}+\frac{1}{2}\approx2.736\). Use estimation to identify the interval quickly.
Step 3
Exam Tip
क्योंकि \( \sqrt{5}\approx2.236\), इसलिए \( \sqrt{5}+\frac{1}{2}\approx2.736\)। अनुमान लगाकर अंतराल जल्दी पहचानें।
\( \sqrt{6}\approx2.449\) and \( \sqrt{7}\approx2.646\), so (2.5) lies between them. Estimate carefully for close square roots.
Step 2
Why this answer is correct
The correct answer is A. (2.5). \( \sqrt{6}\approx2.449\) and \( \sqrt{7}\approx2.646\), so (2.5) lies between them. Estimate carefully for close square roots.
Step 3
Exam Tip
\( \sqrt{6}\approx2.449\) और \( \sqrt{7}\approx2.646\), इसलिए (2.5) बीच में है। नजदीकी मूलों में सावधानी से अनुमान लगाएँ।
\(3.8^2=14.44\) and \(3.9^2=15.21\), so \( \sqrt{15}\) lies between them. Check squares for decimal bounds.
Step 2
Why this answer is correct
The correct answer is A. (3.8) और (3.9) के बीच / Between (3.8) and (3.9). \(3.8^2=14.44\) and \(3.9^2=15.21\), so \( \sqrt{15}\) lies between them. Check squares for decimal bounds.
Step 3
Exam Tip
\(3.8^2=14.44\) और \(3.9^2=15.21\), इसलिए \( \sqrt{15}\) इनके बीच है। दशमलव सीमा के लिए वर्ग जाँचें।
\( \sqrt{20}\approx4.47\) and \( \sqrt{27}\approx5.19\), so (5) lies between them. Use perfect squares to identify bounds.
Step 2
Why this answer is correct
The correct answer is A. (5). \( \sqrt{20}\approx4.47\) and \( \sqrt{27}\approx5.19\), so (5) lies between them. Use perfect squares to identify bounds.
Step 3
Exam Tip
\( \sqrt{20}\approx4.47\) और \( \sqrt{27}\approx5.19\), इसलिए (5) बीच में है। पूर्ण वर्गों से सीमा पहचानें।
A. यह (3) और (4) के बीच है/It lies between (3) and (4)
Step 1
Concept
\( \sqrt{2}\approx1.414\) and \( \sqrt{3}\approx1.732\), so the sum is about (3.146). Estimation is a safe method for such sums.
Step 2
Why this answer is correct
The correct answer is A. यह (3) और (4) के बीच है / It lies between (3) and (4). \( \sqrt{2}\approx1.414\) and \( \sqrt{3}\approx1.732\), so the sum is about (3.146). Estimation is a safe method for such sums.
Step 3
Exam Tip
\( \sqrt{2}\approx1.414\) और \( \sqrt{3}\approx1.732\), योग लगभग (3.146) है। कठिन योगों में अनुमान लगाना सुरक्षित तरीका है।
\(3\sqrt{2}\) is about (4.24), so it lies between (4) and (5). In exams, you may estimate \(\sqrt{2}\) as about (1.414).
Step 2
Why this answer is correct
The correct answer is B. (4) और (5) / (4) and (5). \(3\sqrt{2}\) is about (4.24), so it lies between (4) and (5). In exams, you may estimate \(\sqrt{2}\) as about (1.414).
Step 3
Exam Tip
\(3\sqrt{2}\) लगभग (4.24) है, इसलिए यह (4) और (5) के बीच है। परीक्षा में \(\sqrt{2}\) को लगभग (1.414) मानकर अनुमान लगा सकते हैं।
Since \(3^2=9\) and \(4^2=16\), \(\sqrt{13}\) lies between (3) and (4). Use nearby perfect squares to locate square roots.
Step 2
Why this answer is correct
The correct answer is A. (3) और (4) / (3) and (4). Since \(3^2=9\) and \(4^2=16\), \(\sqrt{13}\) lies between (3) and (4). Use nearby perfect squares to locate square roots.
Step 3
Exam Tip
क्योंकि \(3^2=9\) और \(4^2=16\), इसलिए \(\sqrt{13}\) (3) और (4) के बीच है। वर्गमूल की स्थिति के लिए निकट पूर्ण वर्ग देखें।
Since \(2^2=4\) and \(3^2=9\), \(\sqrt{7}\) lies between (2) and (3). Bound the number using nearby squares.
Step 2
Why this answer is correct
The correct answer is A. (2) और (3) / (2) and (3). Since \(2^2=4\) and \(3^2=9\), \(\sqrt{7}\) lies between (2) and (3). Bound the number using nearby squares.
Step 3
Exam Tip
क्योंकि \(2^2=4\) और \(3^2=9\), इसलिए \(\sqrt{7}\) (2) और (3) के बीच है। संख्या को निकट वर्गों से घेरें।
Since \(3^2=9\) and \(4^2=16\), \(\sqrt{10}\) lies between (3) and (4). Use perfect squares to locate square roots.
Step 2
Why this answer is correct
The correct answer is A. (3) और (4) / (3) and (4). Since \(3^2=9\) and \(4^2=16\), \(\sqrt{10}\) lies between (3) and (4). Use perfect squares to locate square roots.
Step 3
Exam Tip
क्योंकि \(3^2=9\) और \(4^2=16\), इसलिए \(\sqrt{10}\) (3) और (4) के बीच है। वर्गमूल की स्थिति पूर्ण वर्गों से पहचानें।
A. स्वतंत्रता के साथ विभाजन और विस्थापन/Partition and displacement along with independence
Step 1
Concept
The Mountbatten Plan opened the way to independence but also brought partition. Exam tip is to link 1947 with both freedom and tragedy.
Step 2
Why this answer is correct
The correct answer is A. स्वतंत्रता के साथ विभाजन और विस्थापन / Partition and displacement along with independence. The Mountbatten Plan opened the way to independence but also brought partition. Exam tip is to link 1947 with both freedom and tragedy.
Step 3
Exam Tip
माउंटबेटन योजना ने स्वतंत्रता का मार्ग खोला पर विभाजन भी हुआ। परीक्षा में 1947 को स्वतंत्रता और त्रासदी दोनों से जोड़ें।
A. संधि स्वीकार करने वाले भारतीय शासक पर/The Indian ruler accepting the alliance
Step 1
Concept
The state had to pay for British troops which increased its financial dependence. Exam tip: connect it with both economic and political control.
Step 2
Why this answer is correct
The correct answer is A. संधि स्वीकार करने वाले भारतीय शासक पर / The Indian ruler accepting the alliance. The state had to pay for British troops which increased its financial dependence. Exam tip: connect it with both economic and political control.
Step 3
Exam Tip
रियासत को अंग्रेजी सेना का खर्च उठाना पड़ता था जिससे उसकी आर्थिक निर्भरता बढ़ती थी। परीक्षा में इसे आर्थिक और राजनीतिक नियंत्रण दोनों से जोड़ें।
The costs form the decreasing AP \(1000,955,910,\ldots\) and \(S_{12}=9030\). Exam tip: take (d) negative for decreasing costs.
Step 2
Why this answer is correct
The correct answer is D. (9030). The costs form the decreasing AP \(1000,955,910,\ldots\) and \(S_{12}=9030\). Exam tip: take (d) negative for decreasing costs.
Step 3
Exam Tip
खर्च \(1000,955,910,\ldots\) घटती समान्तर श्रेणी है और \(S_{12}=9030\)। परीक्षा में घटते खर्च के लिए (d) ऋणात्मक लें।
Let the original number be (n). Then \(\frac{1200}{n}-\frac{1200}{n+4}=10\). This gives \(10n^2+40n-4800=0\), so (n=20).
Step 2
Why this answer is correct
The correct answer is B. (20). Let the original number be (n). Then \(\frac{1200}{n}-\frac{1200}{n+4}=10\). This gives \(10n^2+40n-4800=0\), so (n=20).
Step 3
Exam Tip
मूल संख्या (n) हो तो \(\frac{1200}{n}-\frac{1200}{n+4}=10\)। इससे \(10n^2+40n-4800=0\) और (n=20) है।
The cost price is (1200-200=1000), and profit percentage is \(\frac{200}{1000}\times100=20\). This does not match \(\frac{1000}{20}=50\), so the statement is inconsistent.
Step 2
Why this answer is correct
The correct answer is C. (₹1000). The cost price is (1200-200=1000), and profit percentage is \(\frac{200}{1000}\times100=20\). This does not match \(\frac{1000}{20}=50\), so the statement is inconsistent.
Step 3
Exam Tip
क्रय मूल्य (1200-200=1000) है और लाभ प्रतिशत \(\frac{200}{1000}\times100=20\) है। यह दी गई शर्त \(\frac{1000}{20}=50\) से मेल नहीं खाती, इसलिए कथन असंगत है।
A. क्योंकि आवश्यक वस्तु पर कर उनके दैनिक खर्च को बढ़ा देता था/Because tax on an essential item increased their daily expenses
Step 1
Concept
Poor families also needed salt daily.
Step 2
Why this answer is correct
Because of tax even an essential item felt costly.
Step 3
Exam Tip
Connect salt tax with the cost of living of the poor. चरण 1: गरीब परिवारों को भी रोज नमक चाहिए था। चरण 2: कर से जरूरी वस्तु भी महंगी लगती थी। चरण 3: नमक कर को गरीबों की जीवन लागत से जोड़ें।
A. क्योंकि आवश्यक वस्तु पर कर उनके दैनिक खर्च को बढ़ा देता था/Because tax on an essential item increased their daily expenses
Step 1
Concept
Poor families also needed salt daily.
Step 2
Why this answer is correct
Because of tax even an essential item felt costly.
Step 3
Exam Tip
Connect salt tax with the cost of living of the poor. चरण 1: गरीब परिवारों को भी रोज नमक चाहिए था। चरण 2: कर से जरूरी वस्तु भी महंगी लगती थी। चरण 3: नमक कर को गरीबों की जीवन लागत से जोड़ें।
A. क्योंकि आवश्यक वस्तु पर कर उनके दैनिक खर्च को बढ़ा देता था/Because tax on an essential item increased their daily expenses
Step 1
Concept
Poor families also needed salt daily.
Step 2
Why this answer is correct
Because of tax even an essential item felt costly.
Step 3
Exam Tip
Connect salt tax with the cost of living of the poor. चरण 1: गरीब परिवारों को भी रोज नमक चाहिए था। चरण 2: कर से जरूरी वस्तु भी महंगी लगती थी। चरण 3: नमक कर को गरीबों की जीवन लागत से जोड़ें।
A. क्योंकि यह विविधता बढ़ाकर अनुकूलन में सहायता कर सकता है/Because it can increase variation and help adaptation
Step 1
Concept
In sexual reproduction, gametes from two parents fuse.
Step 2
Why this answer is correct
This produces new genetic combinations.
Step 3
Exam Tip
Variation can be useful in changing environments. चरण 1: लैंगिक प्रजनन में दो जनकों के युग्मक मिलते हैं। चरण 2: इससे नए आनुवंशिक संयोजन बनते हैं। चरण 3: विविधता बदलते वातावरण में उपयोगी हो सकती है।
A. यह विविधता देकर बदलते वातावरण में लाभ दे सकता है/It can provide variation and advantage in changing environments
Step 1
Concept
Sexual reproduction needs a partner and formation of gametes.
Step 2
Why this answer is correct
Still, it increases genetic variation.
Step 3
Exam Tip
Variation can help survival in changing environments. चरण 1: लैंगिक प्रजनन में साथी और युग्मक निर्माण की आवश्यकता होती है। चरण 2: फिर भी इससे आनुवंशिक विविधता बढ़ती है। चरण 3: विविधता बदलते वातावरण में जीवित रहने में सहायक हो सकती है।
