0 reads0 ratings0 helpful
A trader bought some pens for (1200) rupees. If each pen cost (10) rupees less, he would get (4) more pens. What was the original number of pens?एक व्यापारी ने (1200) रुपये में कुछ पेन खरीदे। यदि प्रति पेन कीमत (10) रुपये कम होती तो (4) पेन अधिक मिलते। मूल पेन संख्या क्या थी?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (20)(20)
Let the original number be (n). Then (\frac{1200}{n}-\frac{1200}{n+4}=10). This gives (10n^2+40n-4800=0), so (n=20).मूल संख्या (n) हो तो (\frac{1200}{n}-\frac{1200}{n+4}=10)। इससे (10n^2+40n-4800=0) और (n=20) है।
Student feedback
Was this question useful?
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Difficulty
Easy0%
Medium0%
Hard0%
Was the explanation clear?
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.
