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Three chairs and two tables cost ₹4900. Two chairs and three tables cost ₹5600. What is the price of one table?

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Answer and explanation

Correct answer: ₹1400

Let the price of one chair be c and the price of one table be t. The information gives the simultaneous equations 3c + 2t = 4900 and 2c + 3t = 5600. Multiply the first equation by 2 and the second by 3: 6c + 4t = 9800 and 6c + 9t = 16800. Subtracting the first new equation from the second gives 5t = 7000, so t = 1400. Therefore, one table costs ₹1400, making option C correct. The other options do not satisfy both original cost equations when the corresponding chair price is found.

Related tags

Simultaneous EquationsElimination MethodWord ProblemAlgebraic Methods: Substitution Method And Elimination Method.Algebraic Methods Substitution Method And Elimination MethodPair Of Linear Equations In Two VariablesMathematicsClass 10 Mcq

Frequently asked questions

What is the correct answer to this question?

₹1400

Why is this the correct answer?

Let the price of one chair be c and the price of one table be t. The information gives the simultaneous equations 3c + 2t = 4900 and 2c + 3t = 5600. Multiply the first equation by 2 and the second by 3: 6c + 4t = 9800 and 6c + 9t = 16800. Subtracting the first new equation from the second gives 5t = 7000, so t = 1400. Therefore, one table costs ₹1400, making option C correct. The other options do not satisfy both original cost equations when the corresponding chair price is found.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Pair of Linear Equations in Two Variables. Topic: Algebraic methods: Substitution method and Elimination method..

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