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If the two lines have a unique point of intersection (r, s) that satisfies 3r + s = 19 and r − s = 1, what is the value of r + s?यदि दो रेखाओं का एकमात्र प्रतिच्छेद-बिंदु (r, s) है और वह 3r + s = 19 तथा r − s = 1 को संतुष्ट करता है, तो r + s का मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: 99
From r − s = 1, we get s = r − 1. Substituting this into 3r + s = 19 gives 3r + r − 1 = 19, so r = 5 and s = 4. Therefore, r + s = 5 + 4 = 9, so option B is correct.r − s = 1 से s = r − 1 मिलता है। इसे 3r + s = 19 में रखने पर 3r + r − 1 = 19 मिलता है, इसलिए r = 5 और s = 4। अतः r + s = 5 + 4 = 9 है, इसलिए विकल्प B सही है।
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