यदि \(a_1=4\) और \(a_{n+1}=3a_n+n\) है तो \(a_4\) क्या होगा?
If \(a_1=4\) and \(a_{n+1}=3a_n+n\), what is \(a_4\)?
#recursive-rule
#triple-plus-index
#class-9
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A (118)
B (122)
C (126)
D (130)
Explanation opens after your attempt
Step 1
Concept
The terms are (4,13,41,126), so \(a_4=126\). Exam tip: find \(3a_n\) first and then add (n).
Step 2
Why this answer is correct
The correct answer is C. (126). The terms are (4,13,41,126), so \(a_4=126\). Exam tip: find \(3a_n\) first and then add (n).
Step 3
Exam Tip
पद (4,13,41,126) हैं इसलिए \(a_4=126\) है। हर चरण में पहले \(3a_n\) निकालें फिर (n) जोड़ें।
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किसी अनुक्रम में \(a_1=3\) और \(a_n=2a_{n-1}+1\) है। \(a_4\) का मान क्या होगा?
In a sequence, \(a_1=3\) and \(a_n=2a_{n-1}+1\). What will be the value of \(a_4\)?
#sequences
#progressions
#recursive-rule
#class-9
#expert
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A सत्ताईस / (27)
B उनतीस / (29)
C इकतीस / (31)
D तैंतीस / (33)
Explanation opens after your attempt
Correct Answer
C. इकतीस / (31)
Step 1
Concept
First \(a_2=7\), then \(a_3=15\), and finally \(a_4=31\). In exams, apply the recursive rule step by step.
Step 2
Why this answer is correct
The correct answer is C. इकतीस / (31). First \(a_2=7\), then \(a_3=15\), and finally \(a_4=31\). In exams, apply the recursive rule step by step.
Step 3
Exam Tip
पहले \(a_2=7\), फिर \(a_3=15\) और अंत में \(a_4=31\) मिलता है। परीक्षा में पुनरावर्ती नियम को क्रम से लागू करें।
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यदि \(a_1=150\) और (a_{n+1}=a_n-\(n^2+2n\)) है तो \(a_5\) क्या होगा?
If \(a_1=150\) and (a_{n+1}=a_n-\(n^2+2n\)), what is \(a_5\)?
#recursive-rule
#quadratic-decrement
#class-9
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A (96)
B (100)
C (104)
D (108)
Explanation opens after your attempt
Step 1
Concept
The subtracted values are (3,8,15,24), so \(a_5=100\). Exam tip: write all changing subtractions separately first.
Step 2
Why this answer is correct
The correct answer is B. (100). The subtracted values are (3,8,15,24), so \(a_5=100\). Exam tip: write all changing subtractions separately first.
Step 3
Exam Tip
घटने वाले मान (3,8,15,24) हैं इसलिए \(a_5=100\) है। पहले सभी बदलते घटावों को अलग लिखें।
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किसी अनुक्रम में \(t_1=2\), \(t_2=5\) और \(t_n=t_{n-1}+2t_{n-2}\) है। \(t_5\) का मान क्या होगा?
In a sequence, \(t_1=2\), \(t_2=5\), and \(t_n=t_{n-1}+2t_{n-2}\). What will be the value of \(t_5\)?
#sequences
#progressions
#recursive-rule
#class-9
#expert
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A इकतीस / (31)
B तैंतीस / (33)
C पैंतीस / (35)
D सैंतीस / (37)
Explanation opens after your attempt
Correct Answer
D. सैंतीस / (37)
Step 1
Concept
We get \(t_3=9\), \(t_4=19\), and \(t_5=37\). In exams, use the previous two terms carefully.
Step 2
Why this answer is correct
The correct answer is D. सैंतीस / (37). We get \(t_3=9\), \(t_4=19\), and \(t_5=37\). In exams, use the previous two terms carefully.
Step 3
Exam Tip
\(t_3=9\), \(t_4=19\) और \(t_5=37\) मिलता है। परीक्षा में पिछले दो पदों का सही उपयोग करें।
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यदि \(a_1=2\), \(a_2=5\) और \(a_n=2a_{n-1}+3a_{n-2}\) है तो \(a_5\) क्या होगा?
If \(a_1=2\), \(a_2=5\), and \(a_n=2a_{n-1}+3a_{n-2}\), what is \(a_5\)?
#recursive-rule
#two-term-recurrence
#class-9
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A (136)
B (142)
C (148)
D (154)
Explanation opens after your attempt
Step 1
Concept
The terms are (2,5,16,47,142), so \(a_5=142\). Exam tip: apply the correct coefficient to each previous term.
Step 2
Why this answer is correct
The correct answer is B. (142). The terms are (2,5,16,47,142), so \(a_5=142\). Exam tip: apply the correct coefficient to each previous term.
Step 3
Exam Tip
पद (2,5,16,47,142) हैं इसलिए \(a_5=142\) है। दोनों पिछले पदों पर सही गुणांक लगाएँ।
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यदि \(a_1=1\), \(a_2=3\) और \(a_n=3a_{n-1}-a_{n-2}+n\) है तो \(a_4\) क्या होगा?
If \(a_1=1\), \(a_2=3\), and \(a_n=3a_{n-1}-a_{n-2}+n\), what is \(a_4\)?
#recursive-rule
#second-order
#index
#class-9
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A (30)
B (34)
C (38)
D (42)
Explanation opens after your attempt
Step 1
Concept
\(a_3=11\) and \(a_4=34\). Exam tip: do not forget to add the current (n) in a two-term rule.
Step 2
Why this answer is correct
The correct answer is B. (34). \(a_3=11\) and \(a_4=34\). Exam tip: do not forget to add the current (n) in a two-term rule.
Step 3
Exam Tip
\(a_3=11\) और \(a_4=34\) है। दो-पद नियम में वर्तमान (n) भी जोड़ना न भूलें।
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यदि \(a_1=7\) और (a_{n+1}=2a_n+(-1)^n n) है तो \(a_5\) क्या होगा?
If \(a_1=7\) and (a_{n+1}=2a_n+(-1)^n n), what is \(a_5\)?
#recursive-rule
#alternating-index
#class-9
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A (104)
B (108)
C (110)
D (114)
Explanation opens after your attempt
Step 1
Concept
The terms are (7,13,28,53,110), so \(a_5=110\). Exam tip: the sign of ((-1)^n) changes with even and odd (n).
Step 2
Why this answer is correct
The correct answer is C. (110). The terms are (7,13,28,53,110), so \(a_5=110\). Exam tip: the sign of ((-1)^n) changes with even and odd (n).
Step 3
Exam Tip
पद (7,13,28,53,110) हैं इसलिए \(a_5=110\) है। ((-1)^n) का चिह्न सम-विषम (n) से बदलता है।
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यदि \(a_1=6\) और \(a_{n+1}=a_n+2^n+n^2\) है तो \(a_5\) क्या होगा?
If \(a_1=6\) and \(a_{n+1}=a_n+2^n+n^2\), what is \(a_5\)?
#recursive-rule
#power-plus-square
#class-9
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A (60)
B (63)
C (66)
D (69)
Explanation opens after your attempt
Step 1
Concept
The added values are (3,8,17,32), so \(a_5=66\). Exam tip: calculate the power and square separately.
Step 2
Why this answer is correct
The correct answer is C. (66). The added values are (3,8,17,32), so \(a_5=66\). Exam tip: calculate the power and square separately.
Step 3
Exam Tip
जुड़ने वाले मान (3,8,17,32) हैं इसलिए \(a_5=66\) है। घात और वर्ग अलग-अलग निकालें।
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यदि \(a_1=200\) और (a_{n+1}=a_n-\(3^n+n\)) है तो \(a_4\) क्या होगा?
If \(a_1=200\) and (a_{n+1}=a_n-\(3^n+n\)), what is \(a_4\)?
#recursive-rule
#power-plus-index
#class-9
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A (155)
B (158)
C (161)
D (164)
Explanation opens after your attempt
Step 1
Concept
The subtracted values are (4,11,30), so \(a_4=155\). Exam tip: first calculate the full value of \(3^n+n\).
Step 2
Why this answer is correct
The correct answer is A. (155). The subtracted values are (4,11,30), so \(a_4=155\). Exam tip: first calculate the full value of \(3^n+n\).
Step 3
Exam Tip
घटने वाले मान (4,11,30) हैं इसलिए \(a_4=155\) है। \(3^n+n\) को पहले पूरा निकालें।
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यदि \(a_1=5\) और \(a_{n+1}=a_n+n!+n\) है तो \(a_5\) क्या होगा?
If \(a_1=5\) and \(a_{n+1}=a_n+n!+n\), what is \(a_5\)?
#recursive-rule
#factorial-plus-index
#class-9
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A (48)
B (50)
C (52)
D (54)
Explanation opens after your attempt
Step 1
Concept
The added values are (2,4,9,28), so \(a_5=48\). Exam tip: add both the factorial and (n).
Step 2
Why this answer is correct
The correct answer is A. (48). The added values are (2,4,9,28), so \(a_5=48\). Exam tip: add both the factorial and (n).
Step 3
Exam Tip
जुड़ने वाले मान (2,4,9,28) हैं इसलिए \(a_5=48\) है। फैक्टोरियल और (n) दोनों जोड़ें।
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यदि \(a_1=90\) और (a_{n+1}=a_n-(n!+2n)) है तो \(a_5\) क्या होगा?
If \(a_1=90\) and (a_{n+1}=a_n-(n!+2n)), what is \(a_5\)?
#recursive-rule
#factorial-decrement
#class-9
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A (31)
B (34)
C (37)
D (40)
Explanation opens after your attempt
Step 1
Concept
The subtracted values are (3,6,12,32), so \(a_5=37\). Exam tip: write each subtraction in order.
Step 2
Why this answer is correct
The correct answer is C. (37). The subtracted values are (3,6,12,32), so \(a_5=37\). Exam tip: write each subtraction in order.
Step 3
Exam Tip
घटने वाले मान (3,6,12,32) हैं इसलिए \(a_5=37\) है। हर घटाव को क्रम से लिखें।
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यदि \(a_1=3\) और (a_{n+1}=4a_n-(n+1)) है तो \(a_3\) क्या होगा?
If \(a_1=3\) and (a_{n+1}=4a_n-(n+1)), what is \(a_3\)?
#recursive-rule
#quadruple-minus-index
#class-9
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A (35)
B (37)
C (39)
D (41)
Explanation opens after your attempt
Step 1
Concept
\(a_2=10\) and \(a_3=37\). Exam tip: multiply first and then subtract (n+1).
Step 2
Why this answer is correct
The correct answer is B. (37). \(a_2=10\) and \(a_3=37\). Exam tip: multiply first and then subtract (n+1).
Step 3
Exam Tip
\(a_2=10\) और \(a_3=37\) है। गुणा के बाद (n+1) घटाएँ।
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यदि \(a_1=2\), \(a_2=6\) और \(a_n=a_{n-1}+2a_{n-2}+n^2\) है तो \(a_4\) क्या होगा?
If \(a_1=2\), \(a_2=6\), and \(a_n=a_{n-1}+2a_{n-2}+n^2\), what is \(a_4\)?
#recursive-rule
#two-term-plus-square
#class-9
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A (41)
B (44)
C (47)
D (50)
Explanation opens after your attempt
Step 1
Concept
\(a_3=19\) and \(a_4=47\). Exam tip: also add \(n^2\) in the two-term rule.
Step 2
Why this answer is correct
The correct answer is C. (47). \(a_3=19\) and \(a_4=47\). Exam tip: also add \(n^2\) in the two-term rule.
Step 3
Exam Tip
\(a_3=19\) और \(a_4=47\) है। दो-पद नियम में \(n^2\) भी जोड़ें।
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यदि \(a_1=5\), \(a_2=11\) और \(a_n=3a_{n-1}-2a_{n-2}\) है तो \(a_5\) क्या होगा?
If \(a_1=5\), \(a_2=11\), and \(a_n=3a_{n-1}-2a_{n-2}\), what is \(a_5\)?
#recursive-rule
#second-order
#class-9
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A (89)
B (92)
C (95)
D (98)
Explanation opens after your attempt
Step 1
Concept
The terms are (5,11,23,47,95), so \(a_5=95\). Exam tip: keep the order of multiplication and subtraction correct.
Step 2
Why this answer is correct
The correct answer is C. (95). The terms are (5,11,23,47,95), so \(a_5=95\). Exam tip: keep the order of multiplication and subtraction correct.
Step 3
Exam Tip
पद (5,11,23,47,95) हैं इसलिए \(a_5=95\) है। गुणा और घटाव का क्रम सही रखें।
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यदि \(a_1=8\) और (a_{n+1}=a_n+n(n+2)+2^n) है तो \(a_4\) क्या होगा?
If \(a_1=8\) and (a_{n+1}=a_n+n(n+2)+2^n), what is \(a_4\)?
#recursive-rule
#product-plus-power
#class-9
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A (42)
B (45)
C (48)
D (51)
Explanation opens after your attempt
Step 1
Concept
The added values are (5,12,23), so \(a_4=48\). Exam tip: calculate both the product and the power.
Step 2
Why this answer is correct
The correct answer is C. (48). The added values are (5,12,23), so \(a_4=48\). Exam tip: calculate both the product and the power.
Step 3
Exam Tip
जुड़ने वाले मान (5,12,23) हैं इसलिए \(a_4=48\) है। गुणनफल और घात दोनों निकालें।
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यदि \(a_1=180\) और (a_{n+1}=a_n-(n(n+2)+2^n)) है तो \(a_4\) क्या होगा?
If \(a_1=180\) and (a_{n+1}=a_n-(n(n+2)+2^n)), what is \(a_4\)?
#recursive-rule
#product-power-decrement
#class-9
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A (134)
B (137)
C (140)
D (143)
Explanation opens after your attempt
Step 1
Concept
The subtracted values are (5,12,23), so \(a_4=140\). Exam tip: calculate the full value before subtracting.
Step 2
Why this answer is correct
The correct answer is C. (140). The subtracted values are (5,12,23), so \(a_4=140\). Exam tip: calculate the full value before subtracting.
Step 3
Exam Tip
घटने वाले मान (5,12,23) हैं इसलिए \(a_4=140\) है। घटाने से पहले पूरा मान निकालें।
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यदि \(a_1=9\) और \(a_{n+1}=2a_n+3n-2\) है तो \(a_3\) क्या होगा?
If \(a_1=9\) and \(a_{n+1}=2a_n+3n-2\), what is \(a_3\)?
#recursive-rule
#double-plus-linear
#class-9
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A (36)
B (39)
C (42)
D (45)
Explanation opens after your attempt
Step 1
Concept
The terms are (9,19,42), so \(a_3=42\). Exam tip: double the previous term first and then add (3n-2).
Step 2
Why this answer is correct
The correct answer is C. (42). The terms are (9,19,42), so \(a_3=42\). Exam tip: double the previous term first and then add (3n-2).
Step 3
Exam Tip
पद (9,19,42) हैं इसलिए \(a_3=42\) है। पहले पिछले पद को दोगुना करें फिर (3n-2) जोड़ें।
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यदि \(a_1=30\) और \(a_{n+1}=\frac{a_n}{3}+2n^2\) है तो \(a_3\) क्या होगा?
If \(a_1=30\) and \(a_{n+1}=\frac{a_n}{3}+2n^2\), what is \(a_3\)?
#recursive-rule
#third-plus-square
#class-9
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A (12)
B (14)
C (16)
D (18)
Explanation opens after your attempt
Step 1
Concept
\(a_2=12\) and \(a_3=12\). Exam tip: divide first and then add \(2n^2\).
Step 2
Why this answer is correct
The correct answer is A. (12). \(a_2=12\) and \(a_3=12\). Exam tip: divide first and then add \(2n^2\).
Step 3
Exam Tip
\(a_2=12\) और \(a_3=12\) है। भाग के बाद \(2n^2\) जोड़ें।
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यदि \(a_1=5\) और \(a_{n+1}=a_n+3a_1+n^2\) है तो \(a_3\) क्या होगा?
If \(a_1=5\) and \(a_{n+1}=a_n+3a_1+n^2\), what is \(a_3\)?
#recursive-rule
#first-term-and-square
#class-9
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A (36)
B (40)
C (44)
D (48)
Explanation opens after your attempt
Step 1
Concept
\(a_2=21\) and \(a_3=40\). Exam tip: \(a_1\) stays fixed while \(n^2\) changes.
Step 2
Why this answer is correct
The correct answer is B. (40). \(a_2=21\) and \(a_3=40\). Exam tip: \(a_1\) stays fixed while \(n^2\) changes.
Step 3
Exam Tip
\(a_2=21\) और \(a_3=40\) है। \(a_1\) स्थिर रहता है जबकि \(n^2\) बदलता है।
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यदि \(a_1=2\), \(a_2=4\) और \(a_n=a_{n-1}+a_{n-2}+3n\) है तो \(a_5\) क्या होगा?
If \(a_1=2\), \(a_2=4\), and \(a_n=a_{n-1}+a_{n-2}+3n\), what is \(a_5\)?
#recursive-rule
#two-term-plus-index
#class-9
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A (52)
B (55)
C (58)
D (61)
Explanation opens after your attempt
Step 1
Concept
The terms are (2,4,15,31,61), so \(a_5=61\). Exam tip: add current (3n) with the previous two terms.
Step 2
Why this answer is correct
The correct answer is D. (61). The terms are (2,4,15,31,61), so \(a_5=61\). Exam tip: add current (3n) with the previous two terms.
Step 3
Exam Tip
पद (2,4,15,31,61) हैं इसलिए \(a_5=61\) है। पिछले दो पदों के साथ वर्तमान (3n) जोड़ें।
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यदि \(a_1=2\), \(a_2=5\) और \(a_n=2a_{n-1}+a_{n-2}+n^2\) है तो \(a_4\) क्या होगा?
If \(a_1=2\), \(a_2=5\), and \(a_n=2a_{n-1}+a_{n-2}+n^2\), what is \(a_4\)?
#recursive-rule
#two-term-plus-square
#class-9
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A (63)
B (66)
C (69)
D (72)
Explanation opens after your attempt
Step 1
Concept
\(a_3=21\) and \(a_4=63\). Exam tip: after applying coefficients, also add \(n^2\).
Step 2
Why this answer is correct
The correct answer is A. (63). \(a_3=21\) and \(a_4=63\). Exam tip: after applying coefficients, also add \(n^2\).
Step 3
Exam Tip
\(a_3=21\) और \(a_4=63\) है। गुणांक लगाने के बाद \(n^2\) भी जोड़ें।
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यदि \(a_1=3\) और \(a_{n+1}=a_n^2-2a_n+4\) है तो \(a_3\) क्या होगा?
If \(a_1=3\) and \(a_{n+1}=a_n^2-2a_n+4\), what is \(a_3\)?
#recursive-rule
#nonlinear-recurrence
#class-9
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A (36)
B (39)
C (42)
D (45)
Explanation opens after your attempt
Step 1
Concept
\(a_2=7\) and \(a_3=39\). Exam tip: square, subtract \(2a_n\), and add (4).
Step 2
Why this answer is correct
The correct answer is B. (39). \(a_2=7\) and \(a_3=39\). Exam tip: square, subtract \(2a_n\), and add (4).
Step 3
Exam Tip
\(a_2=7\) और \(a_3=39\) है। वर्ग निकालकर \(2a_n\) घटाएँ और (4) जोड़ें।
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यदि \(a_1=4\) और \(a_{n+1}=a_n^2-a_n+2\) है तो \(a_2\) क्या होगा?
If \(a_1=4\) and \(a_{n+1}=a_n^2-a_n+2\), what is \(a_2\)?
#recursive-rule
#nonlinear-recurrence
#class-9
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A (8)
B (10)
C (12)
D (14)
Explanation opens after your attempt
Step 1
Concept
\(a_2=4^2-4+2=14\). Exam tip: square the term, subtract it, and add (2).
Step 2
Why this answer is correct
The correct answer is D. (14). \(a_2=4^2-4+2=14\). Exam tip: square the term, subtract it, and add (2).
Step 3
Exam Tip
\(a_2=4^2-4+2=14\) है। वर्ग लेकर वही पद घटाएँ और (2) जोड़ें।
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यदि \(a_1=13\) और \(a_{n+1}=a_n+6\) है तो कौन सा पद (79) है?
If \(a_1=13\) and \(a_{n+1}=a_n+6\), which term is (79)?
#recursive-rule
#term-position
#class-9
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A (12)वाँ / (12)th
B (13)वाँ / (13)th
C (14)वाँ / (14)th
D (15)वाँ / (15)th
Explanation opens after your attempt
Correct Answer
A. (12)वाँ / (12)th
Step 1
Concept
(79-13=66), and \(66\div6=11\) steps, so the term number is (12). Exam tip: add (1) to the number of steps.
Step 2
Why this answer is correct
The correct answer is A. (12)वाँ / (12)th. (79-13=66), and \(66\div6=11\) steps, so the term number is (12). Exam tip: add (1) to the number of steps.
Step 3
Exam Tip
(79-13=66) और \(66\div6=11\) चरण हैं इसलिए पद संख्या (12) है। चरणों में (1) जोड़कर पद संख्या मिलती है।
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यदि \(a_1=8\) और \(a_{n+1}=a_n+9\) है तो \(a_{12}\) क्या होगा?
If \(a_1=8\) and \(a_{n+1}=a_n+9\), what is \(a_{12}\)?
#recursive-rule
#constant-add
#class-9
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A (104)
B (107)
C (110)
D (113)
Explanation opens after your attempt
Step 1
Concept
For \(a_{12}\), (9) is added (11) times, so \(a_{12}=107\). Exam tip: the rule is applied one less time than the term number.
Step 2
Why this answer is correct
The correct answer is B. (107). For \(a_{12}\), (9) is added (11) times, so \(a_{12}=107\). Exam tip: the rule is applied one less time than the term number.
Step 3
Exam Tip
\(a_{12}\) के लिए (9) को (11) बार जोड़ा जाता है इसलिए \(a_{12}=107\) है। पद संख्या से एक कम बार नियम लगता है।
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यदि \(a_1=4\) और \(a_{n+1}=2a_n+9\) है तो \(a_4-a_2\) का मान क्या होगा?
If \(a_1=4\) and \(a_{n+1}=2a_n+9\), what is the value of \(a_4-a_2\)?
#recursive-rule
#difference-of-terms
#class-9
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A (69)
B (72)
C (75)
D (78)
Explanation opens after your attempt
Step 1
Concept
The terms are (4,17,43,95), so \(a_4-a_2=78\). Exam tip: find both terms first and then subtract.
Step 2
Why this answer is correct
The correct answer is D. (78). The terms are (4,17,43,95), so \(a_4-a_2=78\). Exam tip: find both terms first and then subtract.
Step 3
Exam Tip
पद (4,17,43,95) हैं इसलिए \(a_4-a_2=78\) है। पहले दोनों पद निकालें फिर घटाएँ।
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यदि \(a_1=3\), \(a_2=9\) और \(a_n=a_{n-1}+a_{n-2}+7\) है तो \(a_5\) क्या होगा?
If \(a_1=3\), \(a_2=9\), and \(a_n=a_{n-1}+a_{n-2}+7\), what is \(a_5\)?
#recursive-rule
#two-term-plus-constant
#class-9
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A (61)
B (64)
C (67)
D (70)
Explanation opens after your attempt
Step 1
Concept
The terms are (3,9,19,35,61), so \(a_5=61\). Exam tip: also add (7) with the previous two terms.
Step 2
Why this answer is correct
The correct answer is A. (61). The terms are (3,9,19,35,61), so \(a_5=61\). Exam tip: also add (7) with the previous two terms.
Step 3
Exam Tip
पद (3,9,19,35,61) हैं इसलिए \(a_5=61\) है। पिछले दो पदों के साथ (7) भी जोड़ें।
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यदि \(a_1=2\) और \(a_{n+1}=7a_n-4\) है तो \(a_3\) क्या होगा?
If \(a_1=2\) and \(a_{n+1}=7a_n-4\), what is \(a_3\)?
#recursive-rule
#multiply-minus
#class-9
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A (62)
B (66)
C (70)
D (74)
Explanation opens after your attempt
Step 1
Concept
\(a_2=10\) and \(a_3=66\). Exam tip: multiply by (7) first and then subtract (4).
Step 2
Why this answer is correct
The correct answer is B. (66). \(a_2=10\) and \(a_3=66\). Exam tip: multiply by (7) first and then subtract (4).
Step 3
Exam Tip
\(a_2=10\) और \(a_3=66\) है। पहले (7) से गुणा करें फिर (4) घटाएँ।
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यदि \(a_1=6\) और \(a_{n+1}=a_n+9n-4\) है तो \(a_4\) क्या होगा?
If \(a_1=6\) and \(a_{n+1}=a_n+9n-4\), what is \(a_4\)?
#recursive-rule
#linear-increment
#class-9
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A (39)
B (42)
C (45)
D (48)
Explanation opens after your attempt
Step 1
Concept
The added values are (5,14,23), so \(a_4=48\). Exam tip: (9n-4) changes at each step.
Step 2
Why this answer is correct
The correct answer is D. (48). The added values are (5,14,23), so \(a_4=48\). Exam tip: (9n-4) changes at each step.
Step 3
Exam Tip
जुड़ने वाले मान (5,14,23) हैं इसलिए \(a_4=48\) है। (9n-4) का मान हर चरण में बदलता है।
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यदि \(a_1=210\) और (a_{n+1}=a_n-(7n+6)) है तो \(a_4\) क्या होगा?
If \(a_1=210\) and (a_{n+1}=a_n-(7n+6)), what is \(a_4\)?
#recursive-rule
#linear-decrement
#class-9
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A (150)
B (153)
C (156)
D (159)
Explanation opens after your attempt
Step 1
Concept
The subtracted values are (13,20,27), so \(a_4=150\). Exam tip: calculate (7n+6) before subtracting.
Step 2
Why this answer is correct
The correct answer is A. (150). The subtracted values are (13,20,27), so \(a_4=150\). Exam tip: calculate (7n+6) before subtracting.
Step 3
Exam Tip
घटने वाले मान (13,20,27) हैं इसलिए \(a_4=150\) है। घटाने से पहले (7n+6) निकालें।
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यदि \(a_1=2\), \(a_2=3\) और \(a_n=5a_{n-1}-4a_{n-2}+3\) है तो \(a_4\) क्या होगा?
If \(a_1=2\), \(a_2=3\), and \(a_n=5a_{n-1}-4a_{n-2}+3\), what is \(a_4\)?
#recursive-rule
#second-order
#class-9
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A (35)
B (38)
C (41)
D (44)
Explanation opens after your attempt
Step 1
Concept
\(a_3=10\) and \(a_4=41\). Exam tip: apply the coefficients of both previous terms carefully.
Step 2
Why this answer is correct
The correct answer is C. (41). \(a_3=10\) and \(a_4=41\). Exam tip: apply the coefficients of both previous terms carefully.
Step 3
Exam Tip
\(a_3=10\) और \(a_4=41\) है। दोनों पिछले पदों के गुणांक सावधानी से लगाएँ।
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यदि \(a_1=7\) और \(a_{n+1}=a_n+\frac{7n}{2}\) है तो \(a_5\) क्या होगा?
If \(a_1=7\) and \(a_{n+1}=a_n+\frac{7n}{2}\), what is \(a_5\)?
#recursive-rule
#fractional-increment
#class-9
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A (39)
B (42)
C (45)
D (48)
Explanation opens after your attempt
Step 1
Concept
The total addition is (\frac{7(1+2+3+4)}{2}=35), so \(a_5=42\). Exam tip: find total fractional addition first.
Step 2
Why this answer is correct
The correct answer is B. (42). The total addition is (\frac{7(1+2+3+4)}{2}=35), so \(a_5=42\). Exam tip: find total fractional addition first.
Step 3
Exam Tip
कुल जोड़ (\frac{7(1+2+3+4)}{2}=35) है इसलिए \(a_5=42\) है। भिन्न जोड़ में कुल जोड़ पहले निकालें।
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यदि \(a_1=80\) और \(a_{n+1}=a_n-\frac{7n}{2}\) है तो \(a_5\) क्या होगा?
If \(a_1=80\) and \(a_{n+1}=a_n-\frac{7n}{2}\), what is \(a_5\)?
#recursive-rule
#fractional-decrement
#class-9
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A (45)
B (48)
C (51)
D (54)
Explanation opens after your attempt
Step 1
Concept
The total subtraction is (\frac{7(1+2+3+4)}{2}=35), so \(a_5=45\). Exam tip: add fractional subtractions first.
Step 2
Why this answer is correct
The correct answer is A. (45). The total subtraction is (\frac{7(1+2+3+4)}{2}=35), so \(a_5=45\). Exam tip: add fractional subtractions first.
Step 3
Exam Tip
कुल घटाव (\frac{7(1+2+3+4)}{2}=35) है इसलिए \(a_5=45\) है। भिन्न घटावों को पहले जोड़ें।
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यदि \(a_1=4\) और \(a_{n+1}=n a_n+5\) है तो \(a_4\) क्या होगा?
If \(a_1=4\) and \(a_{n+1}=n a_n+5\), what is \(a_4\)?
#recursive-rule
#index-multiplier
#class-9
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A (65)
B (68)
C (71)
D (74)
Explanation opens after your attempt
Step 1
Concept
\(a_2=9\), \(a_3=23\), and \(a_4=74\). Exam tip: the multiplier (n) changes at each step.
Step 2
Why this answer is correct
The correct answer is D. (74). \(a_2=9\), \(a_3=23\), and \(a_4=74\). Exam tip: the multiplier (n) changes at each step.
Step 3
Exam Tip
\(a_2=9\), \(a_3=23\) और \(a_4=74\) है। गुणक (n) हर चरण में बदलता है।
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यदि \(a_1=5\) और (a_{n+1}=(n+2)a_n-1) है तो \(a_4\) क्या होगा?
If \(a_1=5\) and (a_{n+1}=(n+2)a_n-1), what is \(a_4\)?
#recursive-rule
#index-multiplier
#class-9
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A (268)
B (274)
C (280)
D (286)
Explanation opens after your attempt
Step 1
Concept
\(a_2=14\), \(a_3=55\), and \(a_4=274\). Exam tip: the multiplier (n+2) changes.
Step 2
Why this answer is correct
The correct answer is B. (274). \(a_2=14\), \(a_3=55\), and \(a_4=274\). Exam tip: the multiplier (n+2) changes.
Step 3
Exam Tip
\(a_2=14\), \(a_3=55\) और \(a_4=274\) है। गुणक (n+2) बदलता है।
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अनुक्रम \(4,14,44,134,\ldots\) के लिए कौन सा पुनरावर्ती नियम सही है?
Which recursive rule is correct for the sequence \(4,14,44,134,\ldots\)?
#recursive-rule
#identify-rule
#class-9
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A \(a_1=4, a_{n+1}=2a_n+6\)
B \(a_1=14, a_{n+1}=3a_n+2\)
C \(a_1=4, a_{n+1}=3a_n+2\)
D \(a_1=4, a_{n+1}=3a_n-2\)
Explanation opens after your attempt
Correct Answer
C. \(a_1=4, a_{n+1}=3a_n+2\)
Step 1
Concept
\(3\times4+2=14\) and \(3\times14+2=44\). Exam tip: check the first term too when selecting a rule.
Step 2
Why this answer is correct
The correct answer is C. \(a_1=4, a_{n+1}=3a_n+2\). \(3\times4+2=14\) and \(3\times14+2=44\). Exam tip: check the first term too when selecting a rule.
Step 3
Exam Tip
\(3\times4+2=14\) और \(3\times14+2=44\) है। नियम चुनते समय पहला पद भी जाँचें।
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अनुक्रम \(6,11,19,30,\ldots\) के लिए कौन सा पुनरावर्ती नियम सही है?
Which recursive rule is correct for the sequence \(6,11,19,30,\ldots\)?
#recursive-rule
#identify-rule
#class-9
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A \(a_1=6, a_{n+1}=a_n+2n+3\)
B \(a_1=11, a_{n+1}=a_n+3n+2\)
C \(a_1=6, a_{n+1}=a_n+3n+1\)
D \(a_1=6, a_{n+1}=a_n+3n+2\)
Explanation opens after your attempt
Correct Answer
D. \(a_1=6, a_{n+1}=a_n+3n+2\)
Step 1
Concept
The additions are (5,8,11), so (3n+2) is added. Exam tip: match both the first term and changing additions.
Step 2
Why this answer is correct
The correct answer is D. \(a_1=6, a_{n+1}=a_n+3n+2\). The additions are (5,8,11), so (3n+2) is added. Exam tip: match both the first term and changing additions.
Step 3
Exam Tip
जोड़ (5,8,11) हैं इसलिए (3n+2) जुड़ता है। पहला पद और बदलते जोड़ दोनों मिलाएँ।
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यदि \(a_1=5\) और \(a_{n+1}=a_n+n^2\) है तो कौन सा पद (60) है?
If \(a_1=5\) and \(a_{n+1}=a_n+n^2\), which term is (60)?
#recursive-rule
#term-position
#square-increment
#class-9
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A (6)वाँ / (6)th
B (7)वाँ / (7)th
C (8)वाँ / (8)th
D (9)वाँ / (9)th
Explanation opens after your attempt
Correct Answer
A. (6)वाँ / (6)th
Step 1
Concept
The terms are (5,6,10,19,35,60), so (60) is the sixth term. Exam tip: write positions while adding squares.
Step 2
Why this answer is correct
The correct answer is A. (6)वाँ / (6)th. The terms are (5,6,10,19,35,60), so (60) is the sixth term. Exam tip: write positions while adding squares.
Step 3
Exam Tip
पद (5,6,10,19,35,60) हैं इसलिए (60) छठा पद है। वर्ग जोड़ते समय क्रमांक साथ लिखें।
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यदि \(a_1=5\) और \(a_{n+1}=a_n+n!+2^n\) है तो \(a_5\) क्या होगा?
If \(a_1=5\) and \(a_{n+1}=a_n+n!+2^n\), what is \(a_5\)?
#recursive-rule
#factorial-power
#class-9
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A (65)
B (68)
C (71)
D (74)
Explanation opens after your attempt
Step 1
Concept
The added values are (3,6,14,40), so \(a_5=68\). Exam tip: calculate both the factorial and the power.
Step 2
Why this answer is correct
The correct answer is B. (68). The added values are (3,6,14,40), so \(a_5=68\). Exam tip: calculate both the factorial and the power.
Step 3
Exam Tip
जुड़ने वाले मान (3,6,14,40) हैं इसलिए \(a_5=68\) है। फैक्टोरियल और घात दोनों निकालें।
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यदि \(a_1=120\) और (a_{n+1}=a_n-\(n!+2^n\)) है तो \(a_5\) क्या होगा?
If \(a_1=120\) and (a_{n+1}=a_n-\(n!+2^n\)), what is \(a_5\)?
#recursive-rule
#factorial-power-decrement
#class-9
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A (48)
B (51)
C (54)
D (57)
Explanation opens after your attempt
Step 1
Concept
The subtracted values are (3,6,14,40), so \(a_5=57\). Exam tip: find the sum of all subtractions first.
Step 2
Why this answer is correct
The correct answer is D. (57). The subtracted values are (3,6,14,40), so \(a_5=57\). Exam tip: find the sum of all subtractions first.
Step 3
Exam Tip
घटने वाले मान (3,6,14,40) हैं इसलिए \(a_5=57\) है। पूरे घटावों का योग पहले निकालें।
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यदि \(a_1=4\) और (a_{n+1}=2a_n+(-1)^n(2n+1)) है तो \(a_4\) क्या होगा?
If \(a_1=4\) and (a_{n+1}=2a_n+(-1)^n(2n+1)), what is \(a_4\)?
#recursive-rule
#alternating-sign
#class-9
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A (23)
B (25)
C (27)
D (29)
Explanation opens after your attempt
Step 1
Concept
The terms are (4,5,15,23), so \(a_4=23\). Exam tip: double first and then add the signed part.
Step 2
Why this answer is correct
The correct answer is A. (23). The terms are (4,5,15,23), so \(a_4=23\). Exam tip: double first and then add the signed part.
Step 3
Exam Tip
पद (4,5,15,23) हैं इसलिए \(a_4=23\) है। दोगुना करने के बाद चिह्न वाला भाग जोड़ें।
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यदि \(a_1=50\) और (a_{n+1}=a_n-(-1)^n\(n^2+1\)) है तो \(a_4\) क्या होगा?
If \(a_1=50\) and (a_{n+1}=a_n-(-1)^n\(n^2+1\)), what is \(a_4\)?
#recursive-rule
#alternating-square
#class-9
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A (54)
B (57)
C (60)
D (63)
Explanation opens after your attempt
Step 1
Concept
The terms are (50,52,47,57), so \(a_4=57\). Exam tip: track the outside minus sign with ((-1)^n).
Step 2
Why this answer is correct
The correct answer is B. (57). The terms are (50,52,47,57), so \(a_4=57\). Exam tip: track the outside minus sign with ((-1)^n).
Step 3
Exam Tip
पद (50,52,47,57) हैं इसलिए \(a_4=57\) है। बाहरी ऋण और ((-1)^n) को साथ में देखें।
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यदि \(a_1=2\), \(a_2=5\) और \(a_n=2a_{n-1}+a_{n-2}+2n\) है तो \(a_5\) क्या होगा?
If \(a_1=2\), \(a_2=5\), and \(a_n=2a_{n-1}+a_{n-2}+2n\), what is \(a_5\)?
#recursive-rule
#two-term-plus-index
#class-9
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A (114)
B (118)
C (122)
D (126)
Explanation opens after your attempt
Step 1
Concept
The terms are (2,5,18,49,126), so \(a_5=126\). Exam tip: add the current (2n) at each step.
Step 2
Why this answer is correct
The correct answer is D. (126). The terms are (2,5,18,49,126), so \(a_5=126\). Exam tip: add the current (2n) at each step.
Step 3
Exam Tip
पद (2,5,18,49,126) हैं इसलिए \(a_5=126\) है। वर्तमान (2n) को हर चरण में जोड़ें।
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यदि \(a_1=6\) और (a_{n+1}=a_n+a_1+n(n+1)) है तो \(a_4\) क्या होगा?
If \(a_1=6\) and (a_{n+1}=a_n+a_1+n(n+1)), what is \(a_4\)?
#recursive-rule
#first-term-and-product
#class-9
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A (44)
B (47)
C (50)
D (53)
Explanation opens after your attempt
Step 1
Concept
The terms are (6,14,26,44), so \(a_4=44\). Exam tip: \(a_1\) is fixed while (n(n+1)) changes.
Step 2
Why this answer is correct
The correct answer is A. (44). The terms are (6,14,26,44), so \(a_4=44\). Exam tip: \(a_1\) is fixed while (n(n+1)) changes.
Step 3
Exam Tip
पद (6,14,26,44) हैं इसलिए \(a_4=44\) है। \(a_1\) स्थिर है और (n(n+1)) बदलता है।
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यदि \(a_1=3\) और (a_{n+1}=a_n+(2n+1)2 ) है तो \(a_4\) क्या होगा?
If \(a_1=3\) and (a_{n+1}=a_n+(2n+1)2 ), what is \(a_4\)?
#recursive-rule
#odd-square-increment
#class-9
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A (83)
B (86)
C (89)
D (92)
Explanation opens after your attempt
Step 1
Concept
The added values are (9,25,49), so \(a_4=86\). Exam tip: add the odd squares in order.
Step 2
Why this answer is correct
The correct answer is B. (86). The added values are (9,25,49), so \(a_4=86\). Exam tip: add the odd squares in order.
Step 3
Exam Tip
जुड़ने वाले मान (9,25,49) हैं इसलिए \(a_4=86\) है। विषम वर्गों को क्रम से जोड़ें।
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यदि \(a_1=180\) और (a_{n+1}=a_n-(2n+1)2 ) है तो \(a_4\) क्या होगा?
If \(a_1=180\) and (a_{n+1}=a_n-(2n+1)2 ), what is \(a_4\)?
#recursive-rule
#odd-square-decrement
#class-9
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A (88)
B (91)
C (94)
D (97)
Explanation opens after your attempt
Step 1
Concept
The subtracted squares are (9,25,49), so \(a_4=97\). Exam tip: finding the sum of squares first is easier.
Step 2
Why this answer is correct
The correct answer is D. (97). The subtracted squares are (9,25,49), so \(a_4=97\). Exam tip: finding the sum of squares first is easier.
Step 3
Exam Tip
घटने वाले वर्ग (9,25,49) हैं इसलिए \(a_4=97\) है। पहले वर्गों का योग निकालना आसान है।
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यदि \(a_1=3\) और \(a_{n+1}=a_n+n^3\) है तो \(a_5\) क्या होगा?
If \(a_1=3\) and \(a_{n+1}=a_n+n^3\), what is \(a_5\)?
#recursive-rule
#cube-increment
#class-9
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A (103)
B (106)
C (109)
D (112)
Explanation opens after your attempt
Step 1
Concept
The cube additions are (1,8,27,64), so \(a_5=103\). Exam tip: add the new value of \(n^3\) at each step.
Step 2
Why this answer is correct
The correct answer is A. (103). The cube additions are (1,8,27,64), so \(a_5=103\). Exam tip: add the new value of \(n^3\) at each step.
Step 3
Exam Tip
घन जोड़ (1,8,27,64) हैं इसलिए \(a_5=103\) है। हर चरण में \(n^3\) का नया मान जोड़ें।
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यदि \(a_1=150\) और \(a_{n+1}=a_n-n^3\) है तो \(a_5\) क्या होगा?
If \(a_1=150\) and \(a_{n+1}=a_n-n^3\), what is \(a_5\)?
#recursive-rule
#cube-decrement
#class-9
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A (47)
B (50)
C (53)
D (56)
Explanation opens after your attempt
Step 1
Concept
The subtracted cubes are (1,8,27,64), so \(a_5=50\). Exam tip: find the sum of cubes first.
Step 2
Why this answer is correct
The correct answer is B. (50). The subtracted cubes are (1,8,27,64), so \(a_5=50\). Exam tip: find the sum of cubes first.
Step 3
Exam Tip
घटने वाले घन (1,8,27,64) हैं इसलिए \(a_5=50\) है। घनों का योग पहले निकालें।
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अनुक्रम \(3,8,19,46,\ldots\) के लिए कौन सा पुनरावर्ती नियम सही है?
Which recursive rule is correct for the sequence \(3,8,19,46,\ldots\)?
#recursive-rule
#identify-rule
#class-9
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A \(a_1=3, a_2=8, a_n=a_{n-1}+2a_{n-2}\)
B \(a_1=8, a_2=19, a_n=2a_{n-1}+a_{n-2}\)
C \(a_1=3, a_2=8, a_n=a_{n-1}+a_{n-2}+8\)
D \(a_1=3, a_2=8, a_n=2a_{n-1}+a_{n-2}\)
Explanation opens after your attempt
Correct Answer
D. \(a_1=3, a_2=8, a_n=2a_{n-1}+a_{n-2}\)
Step 1
Concept
\(2\times8+3=19\) and \(2\times19+8=46\). Exam tip: both starting terms must be correct in a two-term rule.
Step 2
Why this answer is correct
The correct answer is D. \(a_1=3, a_2=8, a_n=2a_{n-1}+a_{n-2}\). \(2\times8+3=19\) and \(2\times19+8=46\). Exam tip: both starting terms must be correct in a two-term rule.
Step 3
Exam Tip
\(2\times8+3=19\) और \(2\times19+8=46\) है। दो-पद नियम में दोनों शुरुआती पद सही होने चाहिए।
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यदि \(a_1=4\), \(a_2=6\) और \(a_n=a_{n-1}+3a_{n-2}+n\) है तो \(a_4\) क्या होगा?
If \(a_1=4\), \(a_2=6\), and \(a_n=a_{n-1}+3a_{n-2}+n\), what is \(a_4\)?
#recursive-rule
#two-term-plus-index
#class-9
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A (43)
B (46)
C (49)
D (52)
Explanation opens after your attempt
Step 1
Concept
\(a_3=21\) and \(a_4=43\). Exam tip: multiply \(a_{n-2}\) by (3) and add current (n).
Step 2
Why this answer is correct
The correct answer is A. (43). \(a_3=21\) and \(a_4=43\). Exam tip: multiply \(a_{n-2}\) by (3) and add current (n).
Step 3
Exam Tip
\(a_3=21\) और \(a_4=43\) है। \(a_{n-2}\) को (3) से गुणा करके वर्तमान (n) जोड़ें।
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