यदि \(a_1=4\), \(a_2=6\) और \(a_n=a_{n-1}+3a_{n-2}+n\) है तो \(a_4\) क्या होगा?

If \(a_1=4\), \(a_2=6\), and \(a_n=a_{n-1}+3a_{n-2}+n\), what is \(a_4\)?

Author: Muft Shiksha Editorial Team Published: Updated:
Explanation opens after your attempt
Correct Answer

A. (43)

Step 1

Concept

\(a_3=21\) and \(a_4=43\). Exam tip: multiply \(a_{n-2}\) by (3) and add current (n).

Step 2

Why this answer is correct

The correct answer is A. (43). \(a_3=21\) and \(a_4=43\). Exam tip: multiply \(a_{n-2}\) by (3) and add current (n).

Step 3

Exam Tip

\(a_3=21\) और \(a_4=43\) है। \(a_{n-2}\) को (3) से गुणा करके वर्तमान (n) जोड़ें।

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Mathematics Answer, Explanation and Revision Hints

यदि \(a_1=4\), \(a_2=6\) और \(a_n=a_{n-1}+3a_{n-2}+n\) है तो \(a_4\) क्या होगा? / If \(a_1=4\), \(a_2=6\), and \(a_n=a_{n-1}+3a_{n-2}+n\), what is \(a_4\)?

Correct Answer: A. (43). Explanation: \(a_3=21\) और \(a_4=43\) है। \(a_{n-2}\) को (3) से गुणा करके वर्तमान (n) जोड़ें। / \(a_3=21\) and \(a_4=43\). Exam tip: multiply \(a_{n-2}\) by (3) and add current (n).

Which concept should I revise for this Mathematics MCQ?

\(a_3=21\) and \(a_4=43\). Exam tip: multiply \(a_{n-2}\) by (3) and add current (n).

What exam hint can help solve this Mathematics question?

\(a_3=21\) और \(a_4=43\) है। \(a_{n-2}\) को (3) से गुणा करके वर्तमान (n) जोड़ें।