यदि \(a_1=7\) और \(a_{n+1}=a_n+\frac{7n}{2}\) है तो \(a_5\) क्या होगा?

If \(a_1=7\) and \(a_{n+1}=a_n+\frac{7n}{2}\), what is \(a_5\)?

Author: Muft Shiksha Editorial Team Published: Updated:
Explanation opens after your attempt
Correct Answer

B. (42)

Step 1

Concept

The total addition is (\frac{7(1+2+3+4)}{2}=35), so \(a_5=42\). Exam tip: find total fractional addition first.

Step 2

Why this answer is correct

The correct answer is B. (42). The total addition is (\frac{7(1+2+3+4)}{2}=35), so \(a_5=42\). Exam tip: find total fractional addition first.

Step 3

Exam Tip

कुल जोड़ (\frac{7(1+2+3+4)}{2}=35) है इसलिए \(a_5=42\) है। भिन्न जोड़ में कुल जोड़ पहले निकालें।

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Mathematics Answer, Explanation and Revision Hints

यदि \(a_1=7\) और \(a_{n+1}=a_n+\frac{7n}{2}\) है तो \(a_5\) क्या होगा? / If \(a_1=7\) and \(a_{n+1}=a_n+\frac{7n}{2}\), what is \(a_5\)?

Correct Answer: B. (42). Explanation: कुल जोड़ (\frac{7(1+2+3+4)}{2}=35) है इसलिए \(a_5=42\) है। भिन्न जोड़ में कुल जोड़ पहले निकालें। / The total addition is (\frac{7(1+2+3+4)}{2}=35), so \(a_5=42\). Exam tip: find total fractional addition first.

Which concept should I revise for this Mathematics MCQ?

The total addition is (\frac{7(1+2+3+4)}{2}=35), so \(a_5=42\). Exam tip: find total fractional addition first.

What exam hint can help solve this Mathematics question?

कुल जोड़ (\frac{7(1+2+3+4)}{2}=35) है इसलिए \(a_5=42\) है। भिन्न जोड़ में कुल जोड़ पहले निकालें।