यदि \(a_1=90\) और (a_{n+1}=a_n-(n!+2n)) है तो \(a_5\) क्या होगा?

If \(a_1=90\) and (a_{n+1}=a_n-(n!+2n)), what is \(a_5\)?

Author: Muft Shiksha Editorial Team Published: Updated:
Explanation opens after your attempt
Correct Answer

C. (37)

Step 1

Concept

The subtracted values are (3,6,12,32), so \(a_5=37\). Exam tip: write each subtraction in order.

Step 2

Why this answer is correct

The correct answer is C. (37). The subtracted values are (3,6,12,32), so \(a_5=37\). Exam tip: write each subtraction in order.

Step 3

Exam Tip

घटने वाले मान (3,6,12,32) हैं इसलिए \(a_5=37\) है। हर घटाव को क्रम से लिखें।

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Mathematics Answer, Explanation and Revision Hints

यदि \(a_1=90\) और (a_{n+1}=a_n-(n!+2n)) है तो \(a_5\) क्या होगा? / If \(a_1=90\) and (a_{n+1}=a_n-(n!+2n)), what is \(a_5\)?

Correct Answer: C. (37). Explanation: घटने वाले मान (3,6,12,32) हैं इसलिए \(a_5=37\) है। हर घटाव को क्रम से लिखें। / The subtracted values are (3,6,12,32), so \(a_5=37\). Exam tip: write each subtraction in order.

Which concept should I revise for this Mathematics MCQ?

The subtracted values are (3,6,12,32), so \(a_5=37\). Exam tip: write each subtraction in order.

What exam hint can help solve this Mathematics question?

घटने वाले मान (3,6,12,32) हैं इसलिए \(a_5=37\) है। हर घटाव को क्रम से लिखें।