The axis of symmetry passes through the average \(x=\frac{1+7}{2}=4\). Tip: the middle of two zeroes is useful in a parabola.
Step 2
Why this answer is correct
The correct answer is B. (x=4). The axis of symmetry passes through the average \(x=\frac{1+7}{2}=4\). Tip: the middle of two zeroes is useful in a parabola.
Step 3
Exam Tip
सममिति अक्ष शून्यकों के औसत \(x=\frac{1+7}{2}=4\) से गुजरता है। टिप: परवलय में दो शून्यकों का मध्य उपयोगी है।
Each distinct intersection with the (x)-axis gives one real zero. With two intersections, there are two real zeroes.
Step 2
Why this answer is correct
The correct answer is A. दो / Two. Each distinct intersection with the (x)-axis gives one real zero. With two intersections, there are two real zeroes.
Step 3
Exam Tip
(x)-अक्ष से प्रत्येक अलग कटाव एक वास्तविक शून्यक देता है। दो कटाव होने पर दो वास्तविक शून्यक होंगे।
A. वास्तविक शून्यकों की संख्या/Number of real zeroes
Step 1
Concept
The number of distinct times the graph meets the (x)-axis gives the number of real zeroes. Check this first while reading a graph.
Step 2
Why this answer is correct
The correct answer is A. वास्तविक शून्यकों की संख्या / Number of real zeroes. The number of distinct times the graph meets the (x)-axis gives the number of real zeroes. Check this first while reading a graph.
Step 3
Exam Tip
ग्राफ जितनी बार (x)-अक्ष से अलग-अलग मिलता है, उतने वास्तविक शून्यक होते हैं। इसे ग्राफ पढ़ते समय सबसे पहले देखें।
The related equation has (D=4k-2-4\(k^2+9\)=-36). So the graph does not cut the (x)-axis.
Step 2
Why this answer is correct
The correct answer is A. कोई प्रतिच्छेद नहीं / No intersection. The related equation has (D=4k-2-4\(k^2+9\)=-36). So the graph does not cut the (x)-axis.
Step 3
Exam Tip
संबंधित समीकरण का (D=4k-2-4\(k^2+9\)=-36) है। इसलिए ग्राफ (x)-अक्ष को नहीं काटता।
The related equation has (D=4k-2-4\(k^2+4\)=-16). So the graph does not cut the (x)-axis.
Step 2
Why this answer is correct
The correct answer is A. कोई प्रतिच्छेद नहीं / No intersection. The related equation has (D=4k-2-4\(k^2+4\)=-16). So the graph does not cut the (x)-axis.
Step 3
Exam Tip
संबंधित समीकरण का (D=4k-2-4\(k^2+4\)=-16) है। इसलिए ग्राफ (x)-अक्ष को नहीं काटता।
The related equation has (D=4k-2-4\(k^2+1\)=-4). So the graph does not cut the (x)-axis.
Step 2
Why this answer is correct
The correct answer is A. कोई प्रतिच्छेद नहीं / No intersection. The related equation has (D=4k-2-4\(k^2+1\)=-4). So the graph does not cut the (x)-axis.
Step 3
Exam Tip
संबंधित समीकरण का (D=4k-2-4\(k^2+1\)=-4) है। इसलिए ग्राफ (x)-अक्ष को नहीं काटता।
(x-4-1296=\(x^2-36\)\(x^2+36\)), and the real zeroes are only \(\pm6\). Tip: \(x^2+36\) gives no real zero.
Step 2
Why this answer is correct
The correct answer is A. ((-6,0)) और ((6,0)) / ((-6,0)) and ((6,0)). (x-4-1296=\(x^2-36\)\(x^2+36\)), and the real zeroes are only \(\pm6\). Tip: \(x^2+36\) gives no real zero.
Step 3
Exam Tip
(x-4-1296=\(x^2-36\)\(x^2+36\)) है और वास्तविक शून्यक केवल \(\pm6\) हैं। टिप: \(x^2+36\) वास्तविक शून्यक नहीं देता।
A. (\left\(\frac{7}{6},0\right\)) और (\left\(-\frac{7}{6},0\right\))/(\left\(\frac{7}{6},0\right\)) and (\left\(-\frac{7}{6},0\right\))
Step 1
Concept
From \(36x^2-49=0\), \(x=\pm\frac{7}{6}\). Tip: treat \(36x^2\) as ((6x)2).
Step 2
Why this answer is correct
The correct answer is A. (\left\(\frac{7}{6},0\right\)) और (\left\(-\frac{7}{6},0\right\)) / (\left\(\frac{7}{6},0\right\)) and (\left\(-\frac{7}{6},0\right\)). From \(36x^2-49=0\), \(x=\pm\frac{7}{6}\). Tip: treat \(36x^2\) as ((6x)2).
Step 3
Exam Tip
\(36x^2-49=0\) से \(x=\pm\frac{7}{6}\) मिलता है। टिप: \(36x^2\) को ((6x)2) समझें।
A. दूसरा (7), कटान ((6,0)), ((7,0))/Other (7), intersections ((6,0)), ((7,0))
Step 1
Concept
In the quadratic, the sum of zeroes is (13), so the other zero is (7). Tip: convert a zero into ((x,0)).
Step 2
Why this answer is correct
The correct answer is A. दूसरा (7), कटान ((6,0)), ((7,0)) / Other (7), intersections ((6,0)), ((7,0)). In the quadratic, the sum of zeroes is (13), so the other zero is (7). Tip: convert a zero into ((x,0)).
Step 3
Exam Tip
द्विघात में शून्यकों का योग (13) है, इसलिए दूसरा शून्यक (7) है। टिप: शून्यक को ((x,0)) में बदलें।
(x-2-13x-68=(x-17)(x+4)), so the zeroes are (17) and (-4). Tip: write intersection points from factors.
Step 2
Why this answer is correct
The correct answer is A. ((17,0)) और ((-4,0)) / ((17,0)) and ((-4,0)). (x-2-13x-68=(x-17)(x+4)), so the zeroes are (17) and (-4). Tip: write intersection points from factors.
Step 3
Exam Tip
(x-2-13x-68=(x-17)(x+4)) है, इसलिए शून्यक (17) और (-4) हैं। टिप: गुणनखंडों से कटान बिंदु लिखें।
The polynomial is ((x-n)(x-(n+3))), so the zeroes are (n) and (n+3). Tip: write zeroes as ((x,0)).
Step 2
Why this answer is correct
The correct answer is A. ((n,0)) और ((n+3,0)) / ((n,0)) and ((n+3,0)). The polynomial is ((x-n)(x-(n+3))), so the zeroes are (n) and (n+3). Tip: write zeroes as ((x,0)).
Step 3
Exam Tip
बहुपद ((x-n)(x-(n+3))) है इसलिए शून्यक (n) और (n+3) हैं। टिप: शून्यकों को ((x,0)) में लिखें।
(x-4-625=\(x^2-25\)\(x^2+25\)), and the real zeroes are only \(\pm5\). Tip: \(x^2+25\) gives no real zero.
Step 2
Why this answer is correct
The correct answer is A. ((-5,0)) और ((5,0)) / ((-5,0)) and ((5,0)). (x-4-625=\(x^2-25\)\(x^2+25\)), and the real zeroes are only \(\pm5\). Tip: \(x^2+25\) gives no real zero.
Step 3
Exam Tip
(x-4-625=\(x^2-25\)\(x^2+25\)) है और वास्तविक शून्यक केवल \(\pm5\) हैं। टिप: \(x^2+25\) वास्तविक शून्यक नहीं देता।
A. (\left\(\frac{6}{5},0\right\)) और (\left\(-\frac{6}{5},0\right\))/(\left\(\frac{6}{5},0\right\)) and (\left\(-\frac{6}{5},0\right\))
Step 1
Concept
From \(25x^2-36=0\), \(x=\pm\frac{6}{5}\). Tip: treat \(25x^2\) as ((5x)2).
Step 2
Why this answer is correct
The correct answer is A. (\left\(\frac{6}{5},0\right\)) और (\left\(-\frac{6}{5},0\right\)) / (\left\(\frac{6}{5},0\right\)) and (\left\(-\frac{6}{5},0\right\)). From \(25x^2-36=0\), \(x=\pm\frac{6}{5}\). Tip: treat \(25x^2\) as ((5x)2).
Step 3
Exam Tip
\(25x^2-36=0\) से \(x=\pm\frac{6}{5}\) मिलता है। टिप: \(25x^2\) को ((5x)2) समझें।
A. दूसरा (7), कटान ((4,0)), ((7,0))/Other (7), intersections ((4,0)), ((7,0))
Step 1
Concept
In the quadratic, the sum of zeroes is (11), so the other zero is (7). Tip: convert a zero into ((x,0)).
Step 2
Why this answer is correct
The correct answer is A. दूसरा (7), कटान ((4,0)), ((7,0)) / Other (7), intersections ((4,0)), ((7,0)). In the quadratic, the sum of zeroes is (11), so the other zero is (7). Tip: convert a zero into ((x,0)).
Step 3
Exam Tip
द्विघात में शून्यकों का योग (11) है, इसलिए दूसरा शून्यक (7) है। टिप: शून्यक को ((x,0)) में बदलें।
(x-2-9x-52=(x-13)(x+4)), so the zeroes are (13) and (-4). Tip: write intersection points from factors.
Step 2
Why this answer is correct
The correct answer is A. ((13,0)) और ((-4,0)) / ((13,0)) and ((-4,0)). (x-2-9x-52=(x-13)(x+4)), so the zeroes are (13) and (-4). Tip: write intersection points from factors.
Step 3
Exam Tip
(x-2-9x-52=(x-13)(x+4)) है, इसलिए शून्यक (13) और (-4) हैं। टिप: गुणनखंडों से कटान बिंदु लिखें।
The polynomial is ((x-m)(x-(m-1))), so the zeroes are (m) and (m-1). Tip: write zeroes as ((x,0)).
Step 2
Why this answer is correct
The correct answer is A. ((m,0)) और ((m-1,0)) / ((m,0)) and ((m-1,0)). The polynomial is ((x-m)(x-(m-1))), so the zeroes are (m) and (m-1). Tip: write zeroes as ((x,0)).
Step 3
Exam Tip
बहुपद ((x-m)(x-(m-1))) है, इसलिए शून्यक (m) और (m-1) हैं। टिप: शून्यकों को ((x,0)) में लिखें।
(x-4-81=\(x^2-9\)\(x^2+9\)), and the real zeroes are only \(\pm3\). Tip: \(x^2+9\) gives no real zero.
Step 2
Why this answer is correct
The correct answer is A. ((-3,0)) और ((3,0)) / ((-3,0)) and ((3,0)). (x-4-81=\(x^2-9\)\(x^2+9\)), and the real zeroes are only \(\pm3\). Tip: \(x^2+9\) gives no real zero.
Step 3
Exam Tip
(x-4-81=\(x^2-9\)\(x^2+9\)) है और वास्तविक शून्यक केवल \(\pm3\) हैं। टिप: \(x^2+9\) वास्तविक शून्यक नहीं देता।
A. (\left\(\frac{3}{4},0\right\)) और (\left\(-\frac{3}{4},0\right\))/(\left\(\frac{3}{4},0\right\)) and (\left\(-\frac{3}{4},0\right\))
Step 1
Concept
From \(16x^2-9=0\), \(x=\pm\frac{3}{4}\). Tip: treat \(16x^2\) as ((4x)2).
Step 2
Why this answer is correct
The correct answer is A. (\left\(\frac{3}{4},0\right\)) और (\left\(-\frac{3}{4},0\right\)) / (\left\(\frac{3}{4},0\right\)) and (\left\(-\frac{3}{4},0\right\)). From \(16x^2-9=0\), \(x=\pm\frac{3}{4}\). Tip: treat \(16x^2\) as ((4x)2).
Step 3
Exam Tip
\(16x^2-9=0\) से \(x=\pm\frac{3}{4}\) मिलता है। टिप: \(16x^2\) को ((4x)2) समझें।
The zeroes are (m), (n), (r), so the mean is \(\frac{m+n+r}{3}\). Tip: take the first coordinate even in symbolic points.
Step 2
Why this answer is correct
The correct answer is B. \(\frac{m+n+r}{3}\). The zeroes are (m), (n), (r), so the mean is \(\frac{m+n+r}{3}\). Tip: take the first coordinate even in symbolic points.
Step 3
Exam Tip
शून्यक (m), (n), (r) हैं इसलिए माध्य \(\frac{m+n+r}{3}\) है। टिप: प्रतीकात्मक बिंदुओं में भी पहला निर्देशांक लें।
(x-2-8x-33=(x-11)(x+3)), so the zeroes are (11) and (-3). Tip: form ((x,0)) points from factors.
Step 2
Why this answer is correct
The correct answer is A. ((11,0)) और ((-3,0)) / ((11,0)) and ((-3,0)). (x-2-8x-33=(x-11)(x+3)), so the zeroes are (11) and (-3). Tip: form ((x,0)) points from factors.
Step 3
Exam Tip
(x-2-8x-33=(x-11)(x+3)) है इसलिए शून्यक (11) और (-3) हैं। टिप: गुणनखंडों से बिंदु ((x,0)) बनाएं।
It is ((x-u)(x-v)), so the zeroes are (u) and (v). Tip: write each zero as the point ((x,0)).
Step 2
Why this answer is correct
The correct answer is A. ((u,0)) और ((v,0)) / ((u,0)) and ((v,0)). It is ((x-u)(x-v)), so the zeroes are (u) and (v). Tip: write each zero as the point ((x,0)).
Step 3
Exam Tip
यह ((x-u)(x-v)) है इसलिए शून्यक (u) और (v) हैं। टिप: शून्यक को ((x,0)) बिंदु के रूप में लिखें।
(x-4-16=\(x^2-4\)\(x^2+4\)), and the real zeroes are only \(\pm2\). Tip: \(x^2+4\) gives no real zero.
Step 2
Why this answer is correct
The correct answer is A. ((-2,0)) और ((2,0)) / ((-2,0)) and ((2,0)). (x-4-16=\(x^2-4\)\(x^2+4\)), and the real zeroes are only \(\pm2\). Tip: \(x^2+4\) gives no real zero.
Step 3
Exam Tip
(x-4-16=\(x^2-4\)\(x^2+4\)) है और वास्तविक शून्यक केवल \(\pm2\) हैं। टिप: \(x^2+4\) वास्तविक शून्यक नहीं देता।
A. (\left\(\frac{4}{3},0\right\)) और (\left\(-\frac{4}{3},0\right\))/(\left\(\frac{4}{3},0\right\)) and (\left\(-\frac{4}{3},0\right\))
Step 1
Concept
From \(9x^2-16=0\), \(x=\pm\frac{4}{3}\). Tip: treat \(9x^2\) as ((3x)2).
Step 2
Why this answer is correct
The correct answer is A. (\left\(\frac{4}{3},0\right\)) और (\left\(-\frac{4}{3},0\right\)) / (\left\(\frac{4}{3},0\right\)) and (\left\(-\frac{4}{3},0\right\)). From \(9x^2-16=0\), \(x=\pm\frac{4}{3}\). Tip: treat \(9x^2\) as ((3x)2).
Step 3
Exam Tip
\(9x^2-16=0\) से \(x=\pm\frac{4}{3}\) मिलता है। टिप: \(9x^2\) को ((3x)2) समझें।
The zeroes are (a), (b), (c), so their product is (abc). Tip: even in symbolic points, the first coordinate is the zero.
Step 2
Why this answer is correct
The correct answer is B. (abc). The zeroes are (a), (b), (c), so their product is (abc). Tip: even in symbolic points, the first coordinate is the zero.
Step 3
Exam Tip
शून्यक (a), (b), (c) हैं, इसलिए गुणनफल (abc) है। टिप: प्रतीकात्मक बिंदु में भी पहला निर्देशांक शून्यक है।
(x-2-4x-21=(x-7)(x+3)), so the zeroes are (7) and (-3). Tip: form ((x,0)) points from factors.
Step 2
Why this answer is correct
The correct answer is A. ((7,0)) और ((-3,0)) / ((7,0)) and ((-3,0)). (x-2-4x-21=(x-7)(x+3)), so the zeroes are (7) and (-3). Tip: form ((x,0)) points from factors.
Step 3
Exam Tip
(x-2-4x-21=(x-7)(x+3)) है, इसलिए शून्यक (7) और (-3) हैं। टिप: गुणनखंडों से बिंदु ((x,0)) बनाएं।
(x-4-1=\(x^2-1\)\(x^2+1\)), and the real zeroes are only \(\pm1\). Tip: \(x^2+1\) gives no real zero.
Step 2
Why this answer is correct
The correct answer is A. ((-1,0)) और ((1,0)) / ((-1,0)) and ((1,0)). (x-4-1=\(x^2-1\)\(x^2+1\)), and the real zeroes are only \(\pm1\). Tip: \(x^2+1\) gives no real zero.
Step 3
Exam Tip
(x-4-1=\(x^2-1\)\(x^2+1\)) है और वास्तविक शून्यक केवल \(\pm1\) हैं। टिप: \(x^2+1\) वास्तविक शून्यक नहीं देता।
A. (\left\(\frac{5}{2},0\right\)) और (\left\(-\frac{5}{2},0\right\))/(\left\(\frac{5}{2},0\right\)) and (\left\(-\frac{5}{2},0\right\))
Step 1
Concept
From \(4x^2-25=0\), \(x=\pm\frac{5}{2}\). Tip: treat \(4x^2\) as ((2x)2).
Step 2
Why this answer is correct
The correct answer is A. (\left\(\frac{5}{2},0\right\)) और (\left\(-\frac{5}{2},0\right\)) / (\left\(\frac{5}{2},0\right\)) and (\left\(-\frac{5}{2},0\right\)). From \(4x^2-25=0\), \(x=\pm\frac{5}{2}\). Tip: treat \(4x^2\) as ((2x)2).
Step 3
Exam Tip
\(4x^2-25=0\) से \(x=\pm\frac{5}{2}\) मिलता है। टिप: \(4x^2\) को ((2x)2) समझें।
A. दूसरा (3), कटान ((2,0)), ((3,0))/Other (3), intersections ((2,0)), ((3,0))
Step 1
Concept
In the quadratic, the sum of zeroes is (5), so the other zero is (3). Tip: immediately convert a zero to ((x,0)).
Step 2
Why this answer is correct
The correct answer is A. दूसरा (3), कटान ((2,0)), ((3,0)) / Other (3), intersections ((2,0)), ((3,0)). In the quadratic, the sum of zeroes is (5), so the other zero is (3). Tip: immediately convert a zero to ((x,0)).
Step 3
Exam Tip
द्विघात में शून्यकों का योग (5) है, इसलिए दूसरा शून्यक (3) है। टिप: शून्यक को तुरंत ((x,0)) में बदलें।
(x-2+2x-15=(x+5)(x-3)), so the zeroes are (-5) and (3). Tip: form points ((x,0)) from factors.
Step 2
Why this answer is correct
The correct answer is A. ((3,0)) और ((-5,0)) / ((3,0)) and ((-5,0)). (x-2+2x-15=(x+5)(x-3)), so the zeroes are (-5) and (3). Tip: form points ((x,0)) from factors.
Step 3
Exam Tip
(x-2+2x-15=(x+5)(x-3)), इसलिए शून्यक (-5) और (3) हैं। टिप: गुणनखंडों से बिंदु ((x,0)) बनाएं।
The polynomial equals ((x-a)(x-b)), so the zeroes are (a) and (b). Tip: connect factor form with graph intersections.
Step 2
Why this answer is correct
The correct answer is A. ((a,0)) और ((b,0)) / ((a,0)) and ((b,0)). The polynomial equals ((x-a)(x-b)), so the zeroes are (a) and (b). Tip: connect factor form with graph intersections.
Step 3
Exam Tip
बहुपद ((x-a)(x-b)) के बराबर है, इसलिए शून्यक (a) और (b) हैं। टिप: गुणनखंड रूप को ग्राफ कटान से जोड़ें।
(x-2-3x-10=(x-5)(x+2)), so the zeroes are (5) and (-2). Tip: write intersection points from factors.
Step 2
Why this answer is correct
The correct answer is A. ((5,0)) और ((-2,0)) / ((5,0)) and ((-2,0)). (x-2-3x-10=(x-5)(x+2)), so the zeroes are (5) and (-2). Tip: write intersection points from factors.
Step 3
Exam Tip
(x-2-3x-10=(x-5)(x+2)) इसलिए शून्यक (5) और (-2) हैं। टिप: गुणनखंडों से कटान बिंदु लिखें।
B. कटान नहीं बदलते/The intersections do not change
Step 1
Concept
A non-zero constant multiplier does not change zeroes. Tip: zeroes come from factors that make the value zero.
Step 2
Why this answer is correct
The correct answer is B. कटान नहीं बदलते / The intersections do not change. A non-zero constant multiplier does not change zeroes. Tip: zeroes come from factors that make the value zero.
Step 3
Exam Tip
अशून्य स्थिर गुणक शून्यकों को नहीं बदलता। टिप: शून्यक केवल शून्य बनाने वाले कारकों से मिलते हैं।
An (x)-axis intersection occurs where (p(x)=0). Tip: (p(2)=5) does not give a zero.
Step 2
Why this answer is correct
The correct answer is A. ((-3,0)) और ((8,0)) / ((-3,0)) and ((8,0)). An (x)-axis intersection occurs where (p(x)=0). Tip: (p(2)=5) does not give a zero.
Step 3
Exam Tip
जहाँ (p(x)=0) है वहीं (x)-अक्ष कटान होता है। टिप: (p(2)=5) शून्यक नहीं देता।
(x-2-7x+12=(x-3)(x-4)), so the zeroes are (3) and (4). Tip: factor and then write intersection points.
Step 2
Why this answer is correct
The correct answer is A. ((3,0)) और ((4,0)) / ((3,0)) and ((4,0)). (x-2-7x+12=(x-3)(x-4)), so the zeroes are (3) and (4). Tip: factor and then write intersection points.
Step 3
Exam Tip
(x-2-7x+12=(x-3)(x-4)) इसलिए शून्यक (3) और (4) हैं। टिप: गुणनखंड बनाकर कटान बिंदु लिखें।
The first coordinates of intersection points are the zeroes. Tip: choose points whose second coordinate is (0).
Step 2
Why this answer is correct
The correct answer is B. (-8) और (3) / (-8) and (3). The first coordinates of intersection points are the zeroes. Tip: choose points whose second coordinate is (0).
Step 3
Exam Tip
कटान बिंदुओं के पहले निर्देशांक शून्यक होते हैं। टिप: दूसरे निर्देशांक को (0) देखकर बिंदु चुनें।
The first coordinate of each intersection point is a zero. Tip: read the zero (a) from ((a,0)).
Step 2
Why this answer is correct
The correct answer is B. शून्यक (a,b,c) हैं / The zeroes are (a,b,c). The first coordinate of each intersection point is a zero. Tip: read the zero (a) from ((a,0)).
Step 3
Exam Tip
हर कटान बिंदु का पहला निर्देशांक शून्यक है। टिप: ((a,0)) से शून्यक (a) पढ़ें।
The zeroes are (r) and (s), so the average is \(\frac{r+s}{2}\). Tip: divide the sum by the number of values.
Step 2
Why this answer is correct
The correct answer is C. \(\frac{r+s}{2}\). The zeroes are (r) and (s), so the average is \(\frac{r+s}{2}\). Tip: divide the sum by the number of values.
Step 3
Exam Tip
शून्यक (r) और (s) हैं, इसलिए औसत \(\frac{r+s}{2}\) है। टिप: औसत में योग को संख्या से भाग दें।
Setting the factors to zero gives (x=4) and (x=-2). Tip: convert each zero into the point ((x,0)).
Step 2
Why this answer is correct
The correct answer is A. ((4,0)) और ((-2,0)) / ((4,0)) and ((-2,0)). Setting the factors to zero gives (x=4) and (x=-2). Tip: convert each zero into the point ((x,0)).
Step 3
Exam Tip
कारकों को शून्य करने पर (x=4) और (x=-2) मिलते हैं। टिप: शून्यक को ((x,0)) बिंदु में बदलें।
A. वास्तविक शून्यकों की संख्या जानना/To know the number of real zeroes
Step 1
Concept
The (x)-axis intersections tell the number of real zeroes. Tip: first count intersections from the graph.
Step 2
Why this answer is correct
The correct answer is A. वास्तविक शून्यकों की संख्या जानना / To know the number of real zeroes. The (x)-axis intersections tell the number of real zeroes. Tip: first count intersections from the graph.
Step 3
Exam Tip
(x)-अक्ष कटान वास्तविक शून्यकों की संख्या बताते हैं। टिप: ग्राफ से पहले कटान गिनें।
The axis of symmetry passes through the midpoint of zeroes, \(\frac{-2+6}{2}=2\). Tip: the average of two zeroes is useful for a parabola.
Step 2
Why this answer is correct
The correct answer is B. (x=2). The axis of symmetry passes through the midpoint of zeroes, \(\frac{-2+6}{2}=2\). Tip: the average of two zeroes is useful for a parabola.
Step 3
Exam Tip
सममिति अक्ष शून्यकों के मध्य से गुजरता है, \(\frac{-2+6}{2}=2\)। टिप: परवलय में दो शून्यकों का औसत उपयोगी होता है।
A. (x)-अक्ष पर (p(x)=0) होता है/On the (x)-axis (p(x)=0)
Step 1
Concept
A zero is obtained only when the graph lies on the (x)-axis. Tip: always identify (y=0).
Step 2
Why this answer is correct
The correct answer is A. (x)-अक्ष पर (p(x)=0) होता है / On the (x)-axis (p(x)=0). A zero is obtained only when the graph lies on the (x)-axis. Tip: always identify (y=0).
Step 3
Exam Tip
शून्यक तभी मिलता है जब आलेख (x)-अक्ष पर हो। टिप: (y=0) को हमेशा पहचानें।
The Rome Berlin Axis strengthened the alliance of aggressive powers before World War II. For exams connect it with the Axis powers.
Step 2
Why this answer is correct
The correct answer is B. द्वितीय विश्व युद्ध / Second World War. The Rome Berlin Axis strengthened the alliance of aggressive powers before World War II. For exams connect it with the Axis powers.
Step 3
Exam Tip
रोम बर्लिन धुरी ने द्वितीय विश्व युद्ध से पहले आक्रामक शक्तियों के गठबंधन को मजबूत किया। परीक्षा में इसे धुरी शक्तियों से जोड़ें।
A. इटली और जर्मनी के बीच बढ़ता राजनीतिक सहयोग/Growing political cooperation between Italy and Germany
Step 1
Concept
The Rome-Berlin Axis showed closeness between fascist powers. For exams remember the process of Axis formation.
Step 2
Why this answer is correct
The correct answer is A. इटली और जर्मनी के बीच बढ़ता राजनीतिक सहयोग / Growing political cooperation between Italy and Germany. The Rome-Berlin Axis showed closeness between fascist powers. For exams remember the process of Axis formation.
Step 3
Exam Tip
रोम बर्लिन धुरी ने फासीवादी शक्तियों की नजदीकी दिखाई। परीक्षा में धुरी शक्तियों के बनने की प्रक्रिया याद रखें।
Both axes meet at ( (0,0) ). While reading a graph, it is easy to count coordinates from the origin.
Step 2
Why this answer is correct
The correct answer is A. मूलबिंदु ( (0,0) ) / Origin ( (0,0) ). Both axes meet at ( (0,0) ). While reading a graph, it is easy to count coordinates from the origin.
Step 3
Exam Tip
दोनों अक्ष ( (0,0) ) पर मिलते हैं। ग्राफ पढ़ते समय मूलबिंदु से निर्देशांक गिनना आसान होता है।
A. (22) को (10) करना होगा/(22) must be changed to (10)
Step 1
Concept
For equal distance from the (y)-axis, zeroes should be opposites, so (10) is needed with (-10). Tip: symmetric zeroes are (a) and (-a).
Step 2
Why this answer is correct
The correct answer is A. (22) को (10) करना होगा / (22) must be changed to (10). For equal distance from the (y)-axis, zeroes should be opposites, so (10) is needed with (-10). Tip: symmetric zeroes are (a) and (-a).
Step 3
Exam Tip
(y)-अक्ष से समान दूरी के लिए शून्यक विपरीत होने चाहिए, इसलिए (-10) के साथ (10) चाहिए। टिप: सममित शून्यक (a) और (-a) होते हैं।
Real zeroes are counted from (x)-axis intersections, not from the (y)-axis intercept. Tip: ((0,25)) does not show a zero.
Step 2
Why this answer is correct
The correct answer is B. दो / Two. Real zeroes are counted from (x)-axis intersections, not from the (y)-axis intercept. Tip: ((0,25)) does not show a zero.
Step 3
Exam Tip
वास्तविक शून्यक (x)-अक्ष कटानों से गिने जाते हैं, (y)-अक्ष कटान से नहीं। टिप: ((0,25)) शून्यक नहीं बताता।
The origin is also on the (x)-axis, and (x=-9) is another (x)-axis intersection. Tip: count ((0,0)) as zero (0).
Step 2
Why this answer is correct
The correct answer is A. (0) और (-9) / (0) and (-9). The origin is also on the (x)-axis, and (x=-9) is another (x)-axis intersection. Tip: count ((0,0)) as zero (0).
Step 3
Exam Tip
मूल बिंदु (x)-अक्ष पर भी है और (x=-9) भी (x)-अक्ष कटान है। टिप: ((0,0)) को शून्यक (0) के रूप में गिनें।
A. (18) को (8) करना होगा/(18) must be changed to (8)
Step 1
Concept
For equal distance from the (y)-axis, zeroes should be opposites, so (8) is needed with (-8). Tip: symmetric zeroes are (a) and (-a).
Step 2
Why this answer is correct
The correct answer is A. (18) को (8) करना होगा / (18) must be changed to (8). For equal distance from the (y)-axis, zeroes should be opposites, so (8) is needed with (-8). Tip: symmetric zeroes are (a) and (-a).
Step 3
Exam Tip
(y)-अक्ष से समान दूरी के लिए शून्यक विपरीत होने चाहिए, इसलिए (-8) के साथ (8) चाहिए। टिप: सममित शून्यक (a) और (-a) होते हैं।
Real zeroes are counted from (x)-axis intersections, not from the (y)-axis intercept. Tip: ((0,-20)) does not show a zero.
Step 2
Why this answer is correct
The correct answer is B. दो / Two. Real zeroes are counted from (x)-axis intersections, not from the (y)-axis intercept. Tip: ((0,-20)) does not show a zero.
Step 3
Exam Tip
वास्तविक शून्यक (x)-अक्ष कटानों से गिने जाते हैं, (y)-अक्ष कटान से नहीं। टिप: ((0,-20)) शून्यक नहीं बताता।
The origin is also on the (x)-axis, and (x=6) is another (x)-axis intersection. Tip: count ((0,0)) as zero (0).
Step 2
Why this answer is correct
The correct answer is A. (0) और (6) / (0) and (6). The origin is also on the (x)-axis, and (x=6) is another (x)-axis intersection. Tip: count ((0,0)) as zero (0).
Step 3
Exam Tip
मूल बिंदु (x)-अक्ष पर भी है और (x=6) भी (x)-अक्ष कटान है। टिप: ((0,0)) को शून्यक (0) के रूप में गिनें।
A. (14) को (6) करना होगा/(14) must be changed to (6)
Step 1
Concept
For equal distance from the (y)-axis, zeroes should be opposites, so (6) is needed with (-6). Tip: symmetric zeroes are (a) and (-a).
Step 2
Why this answer is correct
The correct answer is A. (14) को (6) करना होगा / (14) must be changed to (6). For equal distance from the (y)-axis, zeroes should be opposites, so (6) is needed with (-6). Tip: symmetric zeroes are (a) and (-a).
Step 3
Exam Tip
(y)-अक्ष से समान दूरी के लिए शून्यक विपरीत होने चाहिए, इसलिए (-6) के साथ (6) चाहिए। टिप: सममित शून्यक (a) और (-a) होते हैं।
Real zeroes are counted from (x)-axis intersections, not from the (y)-axis intercept. Tip: ((0,18)) does not show a zero.
Step 2
Why this answer is correct
The correct answer is B. दो / Two. Real zeroes are counted from (x)-axis intersections, not from the (y)-axis intercept. Tip: ((0,18)) does not show a zero.
Step 3
Exam Tip
वास्तविक शून्यक (x)-अक्ष कटानों से गिने जाते हैं (y)-अक्ष कटान से नहीं। टिप: ((0,18)) शून्यक नहीं बताता।
A. (10) को (4) करना होगा/(10) must be changed to (4)
Step 1
Concept
For equal distance from the (y)-axis, zeroes should be opposites, so (4) is needed with (-4). Tip: symmetric zeroes are (a) and (-a).
Step 2
Why this answer is correct
The correct answer is A. (10) को (4) करना होगा / (10) must be changed to (4). For equal distance from the (y)-axis, zeroes should be opposites, so (4) is needed with (-4). Tip: symmetric zeroes are (a) and (-a).
Step 3
Exam Tip
(y)-अक्ष से समान दूरी के लिए शून्यक विपरीत होने चाहिए, इसलिए (-4) के साथ (4) चाहिए। टिप: सममित शून्यक (a) और (-a) होते हैं।
Real zeroes are counted from (x)-axis intersections, not from the (y)-axis intercept. Tip: ((0,-15)) does not show a zero.
Step 2
Why this answer is correct
The correct answer is B. दो / Two. Real zeroes are counted from (x)-axis intersections, not from the (y)-axis intercept. Tip: ((0,-15)) does not show a zero.
Step 3
Exam Tip
वास्तविक शून्यक (x)-अक्ष कटानों से गिने जाते हैं, (y)-अक्ष कटान से नहीं। टिप: ((0,-15)) शून्यक नहीं बताता।
A. (9) को (3) करना होगा/(9) must be changed to (3)
Step 1
Concept
For equal distance from the (y)-axis, zeroes should be opposites, so (3) is needed with (-3). Tip: symmetric zeroes are (a) and (-a).
Step 2
Why this answer is correct
The correct answer is A. (9) को (3) करना होगा / (9) must be changed to (3). For equal distance from the (y)-axis, zeroes should be opposites, so (3) is needed with (-3). Tip: symmetric zeroes are (a) and (-a).
Step 3
Exam Tip
(y)-अक्ष से समान दूरी के लिए शून्यक विपरीत होने चाहिए, इसलिए (-3) के साथ (3) चाहिए। टिप: सममित शून्यक (a) और (-a) होते हैं।
B. शून्यक (y)-अक्ष से समान दूरी पर हैं/The zeroes are equally distant from the (y)-axis
Step 1
Concept
(-5) and (5) are equally distant from the (y)-axis. Tip: opposite zeroes show symmetric positions.
Step 2
Why this answer is correct
The correct answer is B. शून्यक (y)-अक्ष से समान दूरी पर हैं / The zeroes are equally distant from the (y)-axis. (-5) and (5) are equally distant from the (y)-axis. Tip: opposite zeroes show symmetric positions.
Step 3
Exam Tip
(-5) और (5) (y)-अक्ष से बराबर दूरी पर हैं। टिप: विपरीत शून्यक सममित स्थिति दिखाते हैं।
The graph does not meet the (x)-axis, so there is no real zero. Tip: the vertex position can help judge intersections.
Step 2
Why this answer is correct
The correct answer is C. शून्य / Zero. The graph does not meet the (x)-axis, so there is no real zero. Tip: the vertex position can help judge intersections.
Step 3
Exam Tip
आलेख (x)-अक्ष से नहीं मिलता इसलिए कोई वास्तविक शून्यक नहीं है। टिप: शीर्ष की स्थिति से भी कटान का अंदाजा लग सकता है।
A (y)-axis intercept does not give a zero because (p(x)\neq0). Tip: meeting the (x)-axis is necessary for a zero.
Step 2
Why this answer is correct
The correct answer is A. शून्य / Zero. A (y)-axis intercept does not give a zero because (p(x)\neq0). Tip: meeting the (x)-axis is necessary for a zero.
Step 3
Exam Tip
(y)-अक्ष कटान शून्यक नहीं देता, क्योंकि (p(x)=0) नहीं है। टिप: शून्यक के लिए (x)-अक्ष से मिलना जरूरी है।
Zeroes are found from intersections with the (x)-axis, not the (y)-axis. So if there is no (x)-axis intersection, there are (0) real zeroes.
Step 2
Why this answer is correct
The correct answer is A. (0). Zeroes are found from intersections with the (x)-axis, not the (y)-axis. So if there is no (x)-axis intersection, there are (0) real zeroes.
Step 3
Exam Tip
शून्यक (x)-अक्ष से मिलने पर मिलते हैं, (y)-अक्ष से नहीं। इसलिए (x)-अक्ष से कटाव न होने पर वास्तविक शून्यक (0) होंगे।
Only one (x)-axis intersection is visible so there is one real zero. Tip: the count comes from the number of points.
Step 2
Why this answer is correct
The correct answer is A. एक / One. Only one (x)-axis intersection is visible so there is one real zero. Tip: the count comes from the number of points.
Step 3
Exam Tip
केवल एक (x)-अक्ष कटान दिख रहा है इसलिए एक वास्तविक शून्यक है। टिप: संख्या बिंदुओं की गिनती से आती है।
A. रेगिस्तानी दूरी और भूमध्यसागरीय अवरोधों ने ईंधन और सामग्री पहुंचाना कठिन किया/Desert distance and Mediterranean disruption made fuel and material supply difficult
Step 1
Concept
Even fast war in North Africa was limited by logistics. For exams treat the desert as a strategic obstacle.
Step 2
Why this answer is correct
The correct answer is A. रेगिस्तानी दूरी और भूमध्यसागरीय अवरोधों ने ईंधन और सामग्री पहुंचाना कठिन किया / Desert distance and Mediterranean disruption made fuel and material supply difficult. Even fast war in North Africa was limited by logistics. For exams treat the desert as a strategic obstacle.
Step 3
Exam Tip
उत्तर अफ्रीका में तेज युद्ध भी रसद सीमा से बंधा था। परीक्षा में रेगिस्तान को रणनीतिक बाधा मानें।
A. साम्यवाद विरोधी भाषा ने जर्मनी जापान और बाद में इटली को रणनीतिक निकटता दी/Anti-communist language gave Germany Japan and later Italy strategic closeness
Step 1
Concept
The Anti-Comintern Pact was ideological but had strategic meaning in Axis politics. For exams view ideology and power interests together.
Step 2
Why this answer is correct
The correct answer is A. साम्यवाद विरोधी भाषा ने जर्मनी जापान और बाद में इटली को रणनीतिक निकटता दी / Anti-communist language gave Germany Japan and later Italy strategic closeness. The Anti-Comintern Pact was ideological but had strategic meaning in Axis politics. For exams view ideology and power interests together.
Step 3
Exam Tip
एंटी कॉमिन्टर्न वैचारिक था लेकिन धुरी राजनीति में रणनीतिक अर्थ रखता था। परीक्षा में विचारधारा और शक्ति हित साथ देखें।
A. जर्मनी इटली और जापान को राजनीतिक सैन्य समझ में जोड़ा/It linked Germany Italy and Japan in a political military understanding
Step 1
Concept
The Tripartite Pact linked aggressive European and Asian powers into an Axis. For exams remember the sequence of Axis formation.
Step 2
Why this answer is correct
The correct answer is A. जर्मनी इटली और जापान को राजनीतिक सैन्य समझ में जोड़ा / It linked Germany Italy and Japan in a political military understanding. The Tripartite Pact linked aggressive European and Asian powers into an Axis. For exams remember the sequence of Axis formation.
Step 3
Exam Tip
ट्रिपार्टाइट पैक्ट ने यूरोपीय और एशियाई आक्रामक शक्तियों को एक धुरी में जोड़ा। परीक्षा में धुरी गठन का क्रम याद रखें।
B. वे पीछे हटने लगीं और दबाव में आ गईं/They began retreating and came under pressure
Step 1
Concept
El Alamein strengthened Allied initiative in North Africa. For exams understand it as a turning point of the African front.
Step 2
Why this answer is correct
The correct answer is B. वे पीछे हटने लगीं और दबाव में आ गईं / They began retreating and came under pressure. El Alamein strengthened Allied initiative in North Africa. For exams understand it as a turning point of the African front.
Step 3
Exam Tip
एल अलामेन ने उत्तरी अफ्रीका में मित्र राष्ट्रों की पहल मजबूत की। परीक्षा में इसे अफ्रीकी मोर्चे का मोड़ समझें।
