यदि (p(x)=x-2-7x+12) है तो ग्राफ के (x)-अक्ष कटान कौन से हैं?
If (p(x)=x-2-7x+12), what are the (x)-axis intersections of the graph?
Explanation opens after your attempt
Correct Answer
A. ((3,0)) और ((4,0))((3,0)) and ((4,0))
Concept
(x-2-7x+12=(x-3)(x-4)), so the zeroes are (3) and (4). Tip: factor and then write intersection points.
Why this answer is correct
The correct answer is A. ((3,0)) और ((4,0)) / ((3,0)) and ((4,0)). (x-2-7x+12=(x-3)(x-4)), so the zeroes are (3) and (4). Tip: factor and then write intersection points.
Exam Tip
(x-2-7x+12=(x-3)(x-4)) इसलिए शून्यक (3) और (4) हैं। टिप: गुणनखंड बनाकर कटान बिंदु लिखें।
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