यदि (p(x)=36x-2-49) है, तो ग्राफ के (x)-अक्ष कटान कौन से हैं?
If (p(x)=36x-2-49), what are the (x)-axis intersections of the graph?
Explanation opens after your attempt
A. (\left\(\frac{7}{6},0\right\)) और (\left\(-\frac{7}{6},0\right\))(\left\(\frac{7}{6},0\right\)) and (\left\(-\frac{7}{6},0\right\))
Concept
From \(36x^2-49=0\), \(x=\pm\frac{7}{6}\). Tip: treat \(36x^2\) as ((6x)2).
Why this answer is correct
The correct answer is A. (\left\(\frac{7}{6},0\right\)) और (\left\(-\frac{7}{6},0\right\)) / (\left\(\frac{7}{6},0\right\)) and (\left\(-\frac{7}{6},0\right\)). From \(36x^2-49=0\), \(x=\pm\frac{7}{6}\). Tip: treat \(36x^2\) as ((6x)2).
Exam Tip
\(36x^2-49=0\) से \(x=\pm\frac{7}{6}\) मिलता है। टिप: \(36x^2\) को ((6x)2) समझें।
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