The remaining area is \(a^2-b^2\), and its rectangle form is ((a+b)(a-b)). In exams identify sides after rearranging the cut part.
Step 2
Why this answer is correct
The correct answer is C. (a+b) और (a-b) / sum and difference sides. The remaining area is \(a^2-b^2\), and its rectangle form is ((a+b)(a-b)). In exams identify sides after rearranging the cut part.
Step 3
Exam Tip
शेष क्षेत्रफल \(a^2-b^2\) होता है और उसका आयत रूप ((a+b)(a-b)) है। परीक्षा में कटे भाग को पुनर्व्यवस्थित करके भुजाएं पहचानें।
(4x-2=(2x)2), (9y-2=(3y)2), and the middle term is negative. In exams connect the sign with tile color or direction.
Step 2
Why this answer is correct
The correct answer is D. (2x-3y) / signed square side. (4x-2=(2x)2), (9y-2=(3y)2), and the middle term is negative. In exams connect the sign with tile color or direction.
Step 3
Exam Tip
(4x-2=(2x)2), (9y-2=(3y)2), और मध्य पद ऋणात्मक है। परीक्षा में चिन्ह को टाइल के रंग या दिशा से जोड़ें।
The middle term is ((4+9)x=13x), so (p=13). In exams the sum of strips in a rectangle model gives the middle coefficient.
Step 2
Why this answer is correct
The correct answer is C. (13) / sum of constants. The middle term is ((4+9)x=13x), so (p=13). In exams the sum of strips in a rectangle model gives the middle coefficient.
Step 3
Exam Tip
मध्य पद ((4+9)x=13x) है इसलिए (p=13) है। परीक्षा में आयत मॉडल में पट्टियों का योग मध्य गुणांक देता है।
The total area of the two rectangles is \(2\cdot3a\cdot2b=12ab\). In exams find the middle area of a perfect square using the (2ab) pattern.
Step 2
Why this answer is correct
The correct answer is D. (12ab) / combined middle area. The total area of the two rectangles is \(2\cdot3a\cdot2b=12ab\). In exams find the middle area of a perfect square using the (2ab) pattern.
Step 3
Exam Tip
दो आयतों का कुल क्षेत्रफल \(2\cdot3a\cdot2b=12ab\) है। परीक्षा में पूर्ण वर्ग में मध्य क्षेत्रफल (2ab) रूप से निकालें।
(9m-2=(3m)2) and (25n-2=(5n)2), so it forms a difference of squares. In exams first find the sides of both squares.
Step 2
Why this answer is correct
The correct answer is B. (3m+5n) और (3m-5n) / square-root sides. (9m-2=(3m)2) and (25n-2=(5n)2), so it forms a difference of squares. In exams first find the sides of both squares.
Step 3
Exam Tip
(9m-2=(3m)2) और (25n-2=(5n)2), इसलिए वर्गों का अंतर बनता है। परीक्षा में पहले दोनों वर्गों की भुजाएं निकालें।
Two (5x) strips are removed and the (5) by (5) overlap is added back. In exams the last term in a subtraction square is the square of the strip width.
Step 2
Why this answer is correct
The correct answer is C. (25) / overlap square. Two (5x) strips are removed and the (5) by (5) overlap is added back. In exams the last term in a subtraction square is the square of the strip width.
Step 3
Exam Tip
दो (5x) पट्टियां हटती हैं और (5) बाय (5) ओवरलैप वापस जुड़ता है। परीक्षा में घटाव वर्ग में अंतिम पद पट्टी की चौड़ाई का वर्ग होता है।
C. भुजाओं (2x+7) और (2x-7) वाला आयत/rectangle with sides (2x+7) and (2x-7)
Step 1
Concept
Factors with opposite signs form a rectangle with area \(4x^2-49\). In exams connect the sum-difference form with a rectangle.
Step 2
Why this answer is correct
The correct answer is C. भुजाओं (2x+7) और (2x-7) वाला आयत / rectangle with sides (2x+7) and (2x-7). Factors with opposite signs form a rectangle with area \(4x^2-49\). In exams connect the sum-difference form with a rectangle.
Step 3
Exam Tip
विपरीत चिन्ह वाले गुणनखंडों का मॉडल आयत होता है जिसका क्षेत्रफल \(4x^2-49\) है। परीक्षा में योग-अंतर रूप को आयत से जोड़ें।
Three squares and six rectangles make \(a^2+b^2+c^2+2ab+2bc+2ca\). In exams count each pair of rectangles.
Step 2
Why this answer is correct
The correct answer is B. \(a^2+b^2+c^2+2ab+2bc+2ca\) / complete partition. Three squares and six rectangles make \(a^2+b^2+c^2+2ab+2bc+2ca\). In exams count each pair of rectangles.
Step 3
Exam Tip
तीन वर्ग और छह आयत मिलकर \(a^2+b^2+c^2+2ab+2bc+2ca\) बनाते हैं। परीक्षा में हर आयत की जोड़ी गिनें।
((x+3)(x+5)=x-2+8x+15) and ((x+4)2=x-2+8x+16), so the difference is (-1). In exams compare nearby rectangles and squares by expansion.
Step 2
Why this answer is correct
The correct answer is B. (-1) / rectangle smaller by one. ((x+3)(x+5)=x-2+8x+15) and ((x+4)2=x-2+8x+16), so the difference is (-1). In exams compare nearby rectangles and squares by expansion.
Step 3
Exam Tip
((x+3)(x+5)=x-2+8x+15) और ((x+4)2=x-2+8x+16), इसलिए अंतर (-1) है। परीक्षा में पास-पास के आयत और वर्ग की तुलना विस्तार से करें।
\(49=7^2\) and \(-14x=-2\cdot x\cdot7\), so the side is (x-7). In exams use both the middle term and the last term to identify a perfect square.
Step 2
Why this answer is correct
The correct answer is C. (x-7) / reduced side. \(49=7^2\) and \(-14x=-2\cdot x\cdot7\), so the side is (x-7). In exams use both the middle term and the last term to identify a perfect square.
Step 3
Exam Tip
\(49=7^2\) और \(-14x=-2\cdot x\cdot7\), इसलिए भुजा (x-7) है। परीक्षा में पूर्ण वर्ग पहचानने के लिए मध्य पद और अंतिम पद दोनों देखें।
Since (5y+(-4y)=y) and (5y\cdot(-4y)=-20y-2), the sides are (x+5y) and (x-4y). In exams add tiles with signs.
Step 2
Why this answer is correct
The correct answer is C. (x+5y) और (x-4y) / signed side lengths. Since (5y+(-4y)=y) and (5y\cdot(-4y)=-20y-2), the sides are (x+5y) and (x-4y). In exams add tiles with signs.
Step 3
Exam Tip
(5y+(-4y)=y) और (5y\cdot(-4y)=-20y-2), इसलिए भुजाएं (x+5y) और (x-4y) हैं। परीक्षा में चिन्ह सहित टाइलों का योग करें।
The corner is ((2q)2=4q-2), and the middle area is (2\cdot5p\cdot(-2q)=-20pq). In exams the corner area can remain a positive square.
Step 2
Why this answer is correct
The correct answer is C. \(4q^2\) और (-20pq) / corner and middle. The corner is ((2q)2=4q-2), and the middle area is (2\cdot5p\cdot(-2q)=-20pq). In exams the corner area can remain a positive square.
Step 3
Exam Tip
कोना ((2q)2=4q-2) और मध्य क्षेत्रफल (2\cdot5p\cdot(-2q)=-20pq) है। परीक्षा में कोने का क्षेत्रफल हमेशा धनात्मक वर्ग हो सकता है।
The cells of ((2x+3)(4x+5)) are \(8x^2\), (10x), (12x), and (15). In exams multiply rows and columns in the grid.
Step 2
Why this answer is correct
The correct answer is C. (2x+3) और (4x+5) / grid. The cells of ((2x+3)(4x+5)) are \(8x^2\), (10x), (12x), and (15). In exams multiply rows and columns in the grid.
Step 3
Exam Tip
((2x+3)(4x+5)) के खाने \(8x^2\), (10x), (12x), और (15) हैं। परीक्षा में ग्रिड में पंक्ति और स्तंभ गुणा करें।
Subtracting the two expansions leaves (4ab). In exams the equal \(a^2\) and \(b^2\) terms cancel.
Step 2
Why this answer is correct
The correct answer is B. (4ab) / four rectangular parts. Subtracting the two expansions leaves (4ab). In exams the equal \(a^2\) and \(b^2\) terms cancel.
Step 3
Exam Tip
दोनों विस्तार घटाने पर (4ab) बचता है। परीक्षा में समान \(a^2\) और \(b^2\) पद कट जाते हैं।
First (x-2+2xy+y-2=(x+y)2), then \(z^2\) is subtracted. In exams first group the large part as a perfect square.
Step 2
Why this answer is correct
The correct answer is B. ((x+y)2-z-2) / square minus square. First (x-2+2xy+y-2=(x+y)2), then \(z^2\) is subtracted. In exams first group the large part as a perfect square.
Step 3
Exam Tip
पहले (x-2+2xy+y-2=(x+y)2) है, फिर \(z^2\) घटता है। परीक्षा में बड़े समूह को पहले पूर्ण वर्ग बनाएं।
The square model gives \(2\cdot2x\cdot z=4xz\) and \(2\cdot3y\cdot z=6yz\). In exams each pair appears twice in a three-part square.
Step 2
Why this answer is correct
The correct answer is B. (4xz+6yz) / both symmetric pairs. The square model gives \(2\cdot2x\cdot z=4xz\) and \(2\cdot3y\cdot z=6yz\). In exams each pair appears twice in a three-part square.
Step 3
Exam Tip
वर्ग मॉडल में \(2\cdot2x\cdot z=4xz\) और \(2\cdot3y\cdot z=6yz\) मिलता है। परीक्षा में तीन-भाग वर्ग में हर जोड़ी दो बार आती है।
(16x-2=(4x)2), (25y-2=(5y)2), and the middle term is \(-2\cdot4x\cdot5y\). In exams check all three parts of a perfect square.
Step 2
Why this answer is correct
The correct answer is B. (4x-5y) / reduced side. (16x-2=(4x)2), (25y-2=(5y)2), and the middle term is \(-2\cdot4x\cdot5y\). In exams check all three parts of a perfect square.
Step 3
Exam Tip
(16x-2=(4x)2), (25y-2=(5y)2), और मध्य पद \(-2\cdot4x\cdot5y\) है। परीक्षा में पूर्ण वर्ग के तीनों भाग जांचें।
(x-2-y-2=(x-y)(x+y)), so if the height is (x-y), the length is (x+y). In exams identify the other side of the rearranged rectangle.
Step 2
Why this answer is correct
The correct answer is B. (x+y) / sum side. (x-2-y-2=(x-y)(x+y)), so if the height is (x-y), the length is (x+y). In exams identify the other side of the rearranged rectangle.
Step 3
Exam Tip
(x-2-y-2=(x-y)(x+y)), इसलिए ऊंचाई (x-y) हो तो लंबाई (x+y) है। परीक्षा में पुनर्व्यवस्थित आयत की दूसरी भुजा पहचानें।
From the total area ((a+b)2), removing the shaded \(2ab+b^2\) leaves \(a^2\). In exams shaded and unshaded parts add to the whole square.
Step 2
Why this answer is correct
The correct answer is D. \(a^2\) / remaining main square. From the total area ((a+b)2), removing the shaded \(2ab+b^2\) leaves \(a^2\). In exams shaded and unshaded parts add to the whole square.
Step 3
Exam Tip
पूरे क्षेत्रफल ((a+b)2) में से रंगीन \(2ab+b^2\) हटाने पर \(a^2\) बचता है। परीक्षा में रंगीन और बिना रंग भागों का योग पूरा वर्ग होता है।
D. (x) बाय (x) वर्ग से (8) बाय (8) वर्ग हटाना/remove an (8) by (8) square from an (x) by (x) square
Step 1
Concept
The removed small square is (64), and the remaining part rearranges into ((x-8)(x+8)). In exams keep difference and square-difference models distinct.
Step 2
Why this answer is correct
The correct answer is D. (x) बाय (x) वर्ग से (8) बाय (8) वर्ग हटाना / remove an (8) by (8) square from an (x) by (x) square. The removed small square is (64), and the remaining part rearranges into ((x-8)(x+8)). In exams keep difference and square-difference models distinct.
Step 3
Exam Tip
हटा हुआ छोटा वर्ग (64) है और शेष भाग पुनर्व्यवस्थित होकर ((x-8)(x+8)) बनता है। परीक्षा में अंतर और वर्ग-अंतर के मॉडल अलग रखें।
((3x+5)(4x-1)=12x-2-3x+20x-5=12x-2+17x-5). In exams the sum of cross strips gives the middle term.
Step 2
Why this answer is correct
The correct answer is D. ((3x+5)(4x-1)) / signed factors. ((3x+5)(4x-1)=12x-2-3x+20x-5=12x-2+17x-5). In exams the sum of cross strips gives the middle term.
Step 3
Exam Tip
((3x+5)(4x-1)=12x-2-3x+20x-5=12x-2+17x-5) है। परीक्षा में क्रॉस पट्टियों का योग मध्य पद देता है।
The difference is ((p+q)2-(p-q)2=4pq). In exams subtract the inner square from the outer square.
Step 2
Why this answer is correct
The correct answer is B. (4pq) / complete border area. The difference is ((p+q)2-(p-q)2=4pq). In exams subtract the inner square from the outer square.
Step 3
Exam Tip
अंतर ((p+q)2-(p-q)2=4pq) है। परीक्षा में बाहरी और अंदरूनी वर्गों का अंतर निकालें।
Since \(6\cdot7=42\) and (6+7=13), the strips are (6x) and (7x). In exams match both the corner and the middle conditions.
Step 2
Why this answer is correct
The correct answer is D. (6) और (7) / pair. Since \(6\cdot7=42\) and (6+7=13), the strips are (6x) and (7x). In exams match both the corner and the middle conditions.
Step 3
Exam Tip
\(6\cdot7=42\) और (6+7=13), इसलिए पट्टियां (6x) और (7x) हैं। परीक्षा में कोने और मध्य दोनों शर्तें साथ मिलाएं।
It is ((2x)2-32=4x-2-9). In exams treat a rectangle with same center and opposite offset as a difference of squares.
Step 2
Why this answer is correct
The correct answer is B. \(4x^2-9\) / difference. It is ((2x)2-32=4x-2-9). In exams treat a rectangle with same center and opposite offset as a difference of squares.
Step 3
Exam Tip
यह ((2x)2-32=4x-2-9) है। परीक्षा में समान केंद्र और विपरीत दूरी वाले आयत को वर्गों का अंतर मानें।
D. दो (ab) आयत हमेशा बराबर होते हैं/the two (ab) rectangles are always equal
Step 1
Concept
Both rectangles have sides (a) and (b), so they have equal area (ab). In exams a rotated rectangle keeps the same area.
Step 2
Why this answer is correct
The correct answer is D. दो (ab) आयत हमेशा बराबर होते हैं / the two (ab) rectangles are always equal. Both rectangles have sides (a) and (b), so they have equal area (ab). In exams a rotated rectangle keeps the same area.
Step 3
Exam Tip
दोनों आयतों की भुजाएं (a) और (b) हैं इसलिए वे बराबर क्षेत्रफल (ab) रखते हैं। परीक्षा में घुमे हुए आयत का क्षेत्रफल नहीं बदलता।
Both have \(x^2+8x\) common, and the only difference is (16-15=1). In exams cancel common parts while comparing.
Step 2
Why this answer is correct
The correct answer is D. (1) / corner difference. Both have \(x^2+8x\) common, and the only difference is (16-15=1). In exams cancel common parts while comparing.
Step 3
Exam Tip
दोनों में \(x^2+8x\) समान है और केवल (16-15=1) का अंतर है। परीक्षा में समान भाग काटकर तुलना करें।
D. भुजा (7a-5b) वाला वर्ग/square with side (7a-5b)
Step 1
Concept
The middle term is \(-2\cdot7a\cdot5b=-70ab\), so the side is (7a-5b). In exams the sign of the middle term fixes the identity.
Step 2
Why this answer is correct
The correct answer is D. भुजा (7a-5b) वाला वर्ग / square with side (7a-5b). The middle term is \(-2\cdot7a\cdot5b=-70ab\), so the side is (7a-5b). In exams the sign of the middle term fixes the identity.
Step 3
Exam Tip
मध्य पद \(-2\cdot7a\cdot5b=-70ab\) है इसलिए भुजा (7a-5b) है। परीक्षा में मध्य पद का चिन्ह पहचान को तय करता है।
The middle rectangles in the grid are (7x) and (8x), whose sum is (15x). In exams write separate strips first and then add them.
Step 2
Why this answer is correct
The correct answer is D. (7x) और (8x) / strips. The middle rectangles in the grid are (7x) and (8x), whose sum is (15x). In exams write separate strips first and then add them.
Step 3
Exam Tip
ग्रिड में मध्य आयत (7x) और (8x) होते हैं जिनका योग (15x) है। परीक्षा में अलग पट्टियां पहले लिखें फिर जोड़ें।
The area difference is (12x), equal to four (3x) strips. In exams think of four equal strips in the difference of symmetric squares.
Step 2
Why this answer is correct
The correct answer is C. (4) / four strips. The area difference is (12x), equal to four (3x) strips. In exams think of four equal strips in the difference of symmetric squares.
Step 3
Exam Tip
क्षेत्रफल अंतर (12x) है जो चार (3x) पट्टियों के बराबर है। परीक्षा में सममित वर्गों के अंतर में चार समान पट्टियां सोचें।
((2x-5)(x+3)=2x-2+6x-5x-15=2x-2+x-15). In exams strips with opposite signs subtract to form the middle term.
Step 2
Why this answer is correct
The correct answer is A. ((2x-5)(x+3)) / model. ((2x-5)(x+3)=2x-2+6x-5x-15=2x-2+x-15). In exams strips with opposite signs subtract to form the middle term.
Step 3
Exam Tip
((2x-5)(x+3)=2x-2+6x-5x-15=2x-2+x-15) है। परीक्षा में विपरीत चिन्ह वाली पट्टियां घटकर मध्य पद बनाती हैं।
First (a-2+2ab+b-2=(a+b)2), then \(c^2\) is subtracted. In exams group first and then apply difference of squares.
Step 2
Why this answer is correct
The correct answer is A. ((a+b+c)(a+b-c)) / difference after grouping. First (a-2+2ab+b-2=(a+b)2), then \(c^2\) is subtracted. In exams group first and then apply difference of squares.
Step 3
Exam Tip
पहले (a-2+2ab+b-2=(a+b)2), फिर \(c^2\) घटता है। परीक्षा में समूह बनाकर वर्गों का अंतर लगाएं।
The cells are \(3x^2\), (6x), (-5x), and (-10), whose sum is \(3x^2+x-10\). In exams include the sign of every cell.
Step 2
Why this answer is correct
The correct answer is A. \(3x^2+x-10\) / signed sum. The cells are \(3x^2\), (6x), (-5x), and (-10), whose sum is \(3x^2+x-10\). In exams include the sign of every cell.
Step 3
Exam Tip
खाने \(3x^2\), (6x), (-5x), और (-10) हैं जिनका योग \(3x^2+x-10\) है। परीक्षा में हर खाने का चिन्ह शामिल करें।
The full model has two (xy) rectangles, so missing one gives \(x^2+xy+y^2\). In exams always check the two parts of the middle term.
Step 2
Why this answer is correct
The correct answer is A. \(x^2+xy+y^2\) / one rectangle partial. The full model has two (xy) rectangles, so missing one gives \(x^2+xy+y^2\). In exams always check the two parts of the middle term.
Step 3
Exam Tip
पूर्ण मॉडल में दो (xy) आयत होते हैं, एक छोड़ने पर \(x^2+xy+y^2\) मिलता है। परीक्षा में मध्य पद के दो भाग हमेशा जांचें।
Adding two (ab) strips and a \(b^2\) corner to the (a) square forms ((a+b)2). In exams distinguish addition and removal models.
Step 2
Why this answer is correct
The correct answer is A. ((a+b)2=a-2+2ab+b-2) / two strips and corner. Adding two (ab) strips and a \(b^2\) corner to the (a) square forms ((a+b)2). In exams distinguish addition and removal models.
Step 3
Exam Tip
(a) वर्ग में दो (ab) पट्टियां और \(b^2\) कोना जोड़कर ((a+b)2) बनता है। परीक्षा में जोड़ और हटाव मॉडल अलग पहचानें।
(25x-2=(5x)2) and \(1=1^2\), so the sides are (5x-1) and (5x+1). In exams take square roots and form sum-difference.
Step 2
Why this answer is correct
The correct answer is A. (5x-1) और (5x+1) / sides. (25x-2=(5x)2) and \(1=1^2\), so the sides are (5x-1) and (5x+1). In exams take square roots and form sum-difference.
Step 3
Exam Tip
(25x-2=(5x)2) और \(1=1^2\), इसलिए भुजाएं (5x-1) और (5x+1) हैं। परीक्षा में वर्गमूल लेकर योग-अंतर बनाएं।
The total middle area is (14xy), so each equal rectangle is (7xy). In exams the middle part of a perfect square splits into two equal rectangles.
Step 2
Why this answer is correct
The correct answer is A. (7xy) / each middle rectangle. The total middle area is (14xy), so each equal rectangle is (7xy). In exams the middle part of a perfect square splits into two equal rectangles.
Step 3
Exam Tip
कुल मध्य क्षेत्रफल (14xy) है इसलिए प्रत्येक समान आयत (7xy) है। परीक्षा में पूर्ण वर्ग का मध्य भाग दो बराबर आयतों में बंटता है।
First (x-2-4xy+4y-2=(x-2y)2), then \(z^2\) is subtracted. In exams identify the perfect-square trinomial first.
Step 2
Why this answer is correct
The correct answer is A. ((x-2y)2-z-2) / grouping. First (x-2-4xy+4y-2=(x-2y)2), then \(z^2\) is subtracted. In exams identify the perfect-square trinomial first.
Step 3
Exam Tip
पहले (x-2-4xy+4y-2=(x-2y)2) बनता है, फिर \(z^2\) घटता है। परीक्षा में पूर्ण वर्ग त्रिपद को पहले पहचानें।
Since (6+(-5)=1) and (6\cdot(-5)=-30), the sides are (x+6) and (x-5). In exams use constants with opposite signs for a negative corner.
Step 2
Why this answer is correct
The correct answer is A. (x+6) और (x-5) / signed sides. Since (6+(-5)=1) and (6\cdot(-5)=-30), the sides are (x+6) and (x-5). In exams use constants with opposite signs for a negative corner.
Step 3
Exam Tip
(6+(-5)=1) और (6\cdot(-5)=-30), इसलिए भुजाएं (x+6) और (x-5) हैं। परीक्षा में ऋण कोने के लिए विपरीत चिन्ह वाले स्थिर भाग लें।
A. ((101-99)(101+99))/difference of squares rectangle
Step 1
Concept
The difference of squares is ((101-99)(101+99)=2\cdot200=400). In exams turn larger square minus smaller square into a rectangle.
Step 2
Why this answer is correct
The correct answer is A. ((101-99)(101+99)) / difference of squares rectangle. The difference of squares is ((101-99)(101+99)=2\cdot200=400). In exams turn larger square minus smaller square into a rectangle.
Step 3
Exam Tip
वर्गों का अंतर ((101-99)(101+99)=2\cdot200=400) है। परीक्षा में बड़े वर्ग माइनस छोटे वर्ग को आयत में बदलें।
After removal, the parts involving (a) and (b) remain and make ((a+b)2). In exams add the remaining small regions to identify the new square.
Step 2
Why this answer is correct
The correct answer is A. \(a^2+b^2+2ab\) / square of (a+b). After removal, the parts involving (a) and (b) remain and make ((a+b)2). In exams add the remaining small regions to identify the new square.
Step 3
Exam Tip
हटाने के बाद (a) और (b) वाले भाग बचते हैं जो ((a+b)2) बनाते हैं। परीक्षा में बचे हुए छोटे क्षेत्रों को जोड़कर नया वर्ग पहचानें।
In ((3x+2)(5x-4)), the cells are \(15x^2\), (-12x), (10x), and (-8). In exams the sum of cross areas gives (-2x).
Step 2
Why this answer is correct
The correct answer is A. ((3x+2)(5x-4)) / grid. In ((3x+2)(5x-4)), the cells are \(15x^2\), (-12x), (10x), and (-8). In exams the sum of cross areas gives (-2x).
Step 3
Exam Tip
((3x+2)(5x-4)) में खाने \(15x^2\), (-12x), (10x), और (-8) हैं। परीक्षा में क्रॉस क्षेत्रों का योग (-2x) देता है।
This is ((u+c)2-(u-c)2=4uc) where (u=a+b), so the area is (4c(a+b)). In exams treat the whole group (a+b) as one side.
Step 2
Why this answer is correct
The correct answer is A. (4c(a+b)) / strip area. This is ((u+c)2-(u-c)2=4uc) where (u=a+b), so the area is (4c(a+b)). In exams treat the whole group (a+b) as one side.
Step 3
Exam Tip
यह ((u+c)2-(u-c)2=4uc) है जहां (u=a+b), इसलिए क्षेत्रफल (4c(a+b)) है। परीक्षा में पूरे समूह (a+b) को एक भुजा मानें।
