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common mistake MCQ Questions for Class 10

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91 questions tagged with common mistake.

Question 31/91 Easy Mathematics Polynomials Operations on real numbers and the laws of exponents Class 10 Level 43

कौन सा ((a+b)2) के बराबर नहीं है?

Which is not equal to ((a+b)2)?

Explanation opens after your attempt
Correct Answer

B. \(a^2+b^2\)

Step 1

Concept

The expansion of ((a+b)2) has the middle term (2ab). Therefore \(a^2+b^2\) is incomplete.

Step 2

Why this answer is correct

The correct answer is B. \(a^2+b^2\). The expansion of ((a+b)2) has the middle term (2ab). Therefore \(a^2+b^2\) is incomplete.

Step 3

Exam Tip

((a+b)2) में मध्य पद (2ab) आता है। इसलिए \(a^2+b^2\) अधूरा रूप है।

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Question 32/91 Easy Mathematics Quadratic Equations Word Problems and Applications Class 10 Level 42

किस स्थिति में द्विघात समीकरण बनेगा?

Which situation will form a quadratic equation?

Explanation opens after your attempt
Correct Answer

B. संख्या और उसके (3) अधिक मान का गुणनफल (88) हैA number and (3) more than it have product (88)

Step 1

Concept

Option (B) forms (x(x+3)=88), which is quadratic. When a variable is multiplied by a variable expression, an \(x^2\) term appears.

Step 2

Why this answer is correct

The correct answer is B. संख्या और उसके (3) अधिक मान का गुणनफल (88) है / A number and (3) more than it have product (88). Option (B) forms (x(x+3)=88), which is quadratic. When a variable is multiplied by a variable expression, an \(x^2\) term appears.

Step 3

Exam Tip

विकल्प (B) में (x(x+3)=88) बनता है, जो द्विघात है। गुणनफल में चर के साथ चर हो तो \(x^2\) पद आता है।

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Question 33/91 Easy Mathematics Quadratic Equations Word Problems and Applications Class 10 Level 42

एक संख्या और उसके (15) अधिक मान का योग (53) है। छोटी संख्या क्या है?

A number and (15) more than it have sum (53). What is the smaller number?

Explanation opens after your attempt
Correct Answer

B. (19)

Step 1

Concept

(x+(x+15)=53) gives (x=19). This is a simple linear case, so every word problem is not quadratic.

Step 2

Why this answer is correct

The correct answer is B. (19). (x+(x+15)=53) gives (x=19). This is a simple linear case, so every word problem is not quadratic.

Step 3

Exam Tip

(x+(x+15)=53) से (x=19) है। यह सरल रैखिक स्थिति है, इसलिए हर शब्द समस्या द्विघात नहीं होती।

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Question 34/91 Expert Mathematics Quadratic Equations Nature of Roots Class 10 Level 39

एक छात्र (x-2-2(k-3)x+k-2=0) के लिए (D=36) लिखता है। सही (D) क्या है?

A student writes (D=36) for (x-2-2(k-3)x+k-2=0). What is the correct (D)?

Explanation opens after your attempt
Correct Answer

A. (36-24k)

Step 1

Concept

The correct (D=4(k-3)2-4k-2=36-24k). While expanding the square, keep the (k)-term carefully.

Step 2

Why this answer is correct

The correct answer is A. (36-24k). The correct (D=4(k-3)2-4k-2=36-24k). While expanding the square, keep the (k)-term carefully.

Step 3

Exam Tip

सही (D=4(k-3)2-4k-2=36-24k) है। वर्ग खोलते समय (k)-पद को जरूर रखें।

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Question 35/91 Expert Mathematics Quadratic Equations Nature of Roots Class 10 Level 38

एक छात्र (x-2-2(k-2)x+k-2=0) के लिए (D=16) लिखता है। सही (D) क्या है?

A student writes (D=16) for (x-2-2(k-2)x+k-2=0). What is the correct (D)?

Explanation opens after your attempt
Correct Answer

A. (16(1-k))

Step 1

Concept

The correct (D=4(k-2)2-4k-2=16(1-k)). In such questions, do not miss signs while expanding squares.

Step 2

Why this answer is correct

The correct answer is A. (16(1-k)). The correct (D=4(k-2)2-4k-2=16(1-k)). In such questions, do not miss signs while expanding squares.

Step 3

Exam Tip

सही (D=4(k-2)2-4k-2=16(1-k)) है। ऐसे प्रश्नों में वर्ग खोलते समय चिन्ह न भूलें।

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Question 36/91 Expert Mathematics Quadratic Equations Nature of Roots Class 10 Level 37

एक छात्र (x-2-2(k+1)x+k-2=0) में (D=4) लिखता है। सही (D) क्या है?

A student writes (D=4) for (x-2-2(k+1)x+k-2=0). What is the correct (D)?

Explanation opens after your attempt
Correct Answer

A. (4(2k+1))

Step 1

Concept

The correct (D=4(k+1)2-4k-2=4(2k+1)). In parameter questions, expand fully.

Step 2

Why this answer is correct

The correct answer is A. (4(2k+1)). The correct (D=4(k+1)2-4k-2=4(2k+1)). In parameter questions, expand fully.

Step 3

Exam Tip

सही (D=4(k+1)2-4k-2=4(2k+1)) है। पैरामीटर वाले प्रश्नों में पूर्ण विस्तार करें।

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Question 37/91 Hard Mathematics Quadratic Equations Nature of Roots Class 10 Level 39

कथन: (D>0) होने पर द्विघात समीकरण के मूल हमेशा बराबर होते हैं। यह कथन कैसा है?

Statement: When (D>0), the roots of a quadratic equation are always equal. How is this statement?

Explanation opens after your attempt
Correct Answer

B. असत्यFalse

Step 1

Concept

When (D>0), roots are not equal; they are distinct real roots. In exams, equal roots occur only when (D=0).

Step 2

Why this answer is correct

The correct answer is B. असत्य / False. When (D>0), roots are not equal; they are distinct real roots. In exams, equal roots occur only when (D=0).

Step 3

Exam Tip

(D>0) होने पर मूल बराबर नहीं, बल्कि भिन्न वास्तविक होते हैं। परीक्षा में बराबर मूल केवल (D=0) पर आते हैं।

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Question 38/91 Medium Mathematics Quadratic Equations Nature of Roots Class 10 Level 39

एक छात्र \(2x^2-3x+5=0\) में (D=49) लिखता है। सही (D) क्या है?

A student writes (D=49) for \(2x^2-3x+5=0\). What is the correct (D)?

Explanation opens after your attempt
Correct Answer

A. (-31)

Step 1

Concept

The correct formula is \(D=b^2-4ac\). Here (D=(-3)2-4(2)(5)=-31).

Step 2

Why this answer is correct

The correct answer is A. (-31). The correct formula is \(D=b^2-4ac\). Here (D=(-3)2-4(2)(5)=-31).

Step 3

Exam Tip

सही सूत्र \(D=b^2-4ac\) है। यहाँ (D=(-3)2-4(2)(5)=-31) होगा।

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Question 39/91 Hard Mathematics Quadratic Equations Nature of Roots Class 10 Level 38

एक विद्यार्थी (D=-4) पर दो वास्तविक मूल मानता है। सही निष्कर्ष क्या है?

A student assumes two real roots when (D=-4). What is the correct conclusion?

Explanation opens after your attempt
Correct Answer

A. कोई वास्तविक मूल नहीं होगाThere will be no real root

Step 1

Concept

Because (D=-4<0), real roots are not obtained. Identify a negative discriminant quickly.

Step 2

Why this answer is correct

The correct answer is A. कोई वास्तविक मूल नहीं होगा / There will be no real root. Because (D=-4<0), real roots are not obtained. Identify a negative discriminant quickly.

Step 3

Exam Tip

क्योंकि (D=-4<0) है, वास्तविक मूल नहीं मिलते। ऋणात्मक विविक्तकर को तुरंत पहचानें।

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Question 40/91 Hard Mathematics Quadratic Equations Nature of Roots Class 10 Level 38

एक विद्यार्थी ने (D=18) देखकर परिमेय मूल लिख दिए। सही सुधार क्या है?

A student sees (D=18) and writes rational roots. What is the correct correction?

Explanation opens after your attempt
Correct Answer

A. मूल वास्तविक, अपरिमेय और भिन्न होंगेThe roots will be real, irrational and distinct

Step 1

Concept

(18>0) but (18) is not a perfect square. Hence the roots are real, irrational and distinct.

Step 2

Why this answer is correct

The correct answer is A. मूल वास्तविक, अपरिमेय और भिन्न होंगे / The roots will be real, irrational and distinct. (18>0) but (18) is not a perfect square. Hence the roots are real, irrational and distinct.

Step 3

Exam Tip

(18>0) है पर (18) पूर्ण वर्ग नहीं है। इसलिए मूल वास्तविक, अपरिमेय और भिन्न होंगे।

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Question 41/91 Medium Mathematics Quadratic Equations Nature of Roots Class 10 Level 38

एक छात्र \(x^2-4x+6=0\) में (D=40) लिखता है। सही (D) क्या है?

A student writes (D=40) for \(x^2-4x+6=0\). What is the correct (D)?

Explanation opens after your attempt
Correct Answer

A. (-8)

Step 1

Concept

The correct formula is \(D=b^2-4ac\). Here (D=(-4)2-4(1)(6)=-8).

Step 2

Why this answer is correct

The correct answer is A. (-8). The correct formula is \(D=b^2-4ac\). Here (D=(-4)2-4(1)(6)=-8).

Step 3

Exam Tip

सही सूत्र \(D=b^2-4ac\) है। यहाँ (D=(-4)2-4(1)(6)=-8) होगा।

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Question 42/91 Hard Mathematics Quadratic Equations Nature of Roots Class 10 Level 37

एक विद्यार्थी (D=0) को (D>0) समझकर दो भिन्न मूल लिखता है। सही सुधार क्या है?

A student treats (D=0) as (D>0) and writes two distinct roots. What is the correct correction?

Explanation opens after your attempt
Correct Answer

A. (D=0) पर मूल समान होते हैंAt (D=0), roots are equal

Step 1

Concept

(D=0) means two equal real roots. For distinct roots, (D>0) is required.

Step 2

Why this answer is correct

The correct answer is A. (D=0) पर मूल समान होते हैं / At (D=0), roots are equal. (D=0) means two equal real roots. For distinct roots, (D>0) is required.

Step 3

Exam Tip

(D=0) का अर्थ दो समान वास्तविक मूल है। भिन्न मूलों के लिए (D>0) चाहिए।

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Question 43/91 Medium Mathematics Quadratic Equations Nature of Roots Class 10 Level 37

एक छात्र \(D=b^2+4ac\) लगाता है। \(x^2+2x+3=0\) के लिए सही (D) क्या है?

A student uses \(D=b^2+4ac\). What is the correct (D) for \(x^2+2x+3=0\)?

Explanation opens after your attempt
Correct Answer

A. (-8)

Step 1

Concept

The correct formula is \(D=b^2-4ac\). Here (D=22-4(1)(3)=-8).

Step 2

Why this answer is correct

The correct answer is A. (-8). The correct formula is \(D=b^2-4ac\). Here (D=22-4(1)(3)=-8).

Step 3

Exam Tip

सही सूत्र \(D=b^2-4ac\) है। यहाँ (D=22-4(1)(3)=-8)।

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Question 44/91 Easy Mathematics Quadratic Equations Nature of Roots Class 10 Level 39

कथन: (D>0) होने पर मूल हमेशा समान होते हैं। सही विकल्प चुनिए।

Statement: When (D>0), roots are always equal. Choose the correct option.

Explanation opens after your attempt
Correct Answer

A. कथन गलत हैThe statement is wrong

Step 1

Concept

When (D>0), roots are real and distinct. Equal roots occur only when (D=0).

Step 2

Why this answer is correct

The correct answer is A. कथन गलत है / The statement is wrong. When (D>0), roots are real and distinct. Equal roots occur only when (D=0).

Step 3

Exam Tip

(D>0) पर मूल वास्तविक और भिन्न होते हैं। समान मूल केवल (D=0) पर होते हैं।

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Question 45/91 Medium Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 36

यदि किसी छात्र ने \(x^2=81\) से केवल (x=9) लिखा, तो सही सुधार क्या है?

If a student wrote only (x=9) from \(x^2=81\), what is the correct correction?

Explanation opens after your attempt
Correct Answer

A. \(x=\pm9\) लिखना चाहिएOne should write \(x=\pm9\)

Step 1

Concept

From \(x^2=81\), \(x=\pm\sqrt{81}=\pm9\). In exams, both signs are necessary in the square root method.

Step 2

Why this answer is correct

The correct answer is A. \(x=\pm9\) लिखना चाहिए / One should write \(x=\pm9\). From \(x^2=81\), \(x=\pm\sqrt{81}=\pm9\). In exams, both signs are necessary in the square root method.

Step 3

Exam Tip

\(x^2=81\) से \(x=\pm\sqrt{81}=\pm9\) मिलता है। परीक्षा में वर्गमूल विधि में दोनों चिन्ह अनिवार्य हैं।

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Question 46/91 Medium Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 36

\(8x^2-32x=0\) को हल करते समय कौनसी गलती नहीं करनी चाहिए?

Which mistake should be avoided while solving \(8x^2-32x=0\)?

Explanation opens after your attempt
Correct Answer

A. (x=0) को छोड़नाMissing (x=0)

Step 1

Concept

(8x-2-32x=8x(x-4)), so (x=0) and (x=4) are both roots. In exams, dividing by the variable can miss (x=0).

Step 2

Why this answer is correct

The correct answer is A. (x=0) को छोड़ना / Missing (x=0). (8x-2-32x=8x(x-4)), so (x=0) and (x=4) are both roots. In exams, dividing by the variable can miss (x=0).

Step 3

Exam Tip

(8x-2-32x=8x(x-4)), इसलिए (x=0) और (x=4) दोनों मूल हैं। परीक्षा में चर से भाग देने पर (x=0) छूट सकता है।

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Question 47/91 Medium Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 35

यदि किसी छात्र ने \(x^2=49\) से केवल (x=7) लिखा, तो सही सुधार क्या है?

If a student wrote only (x=7) from \(x^2=49\), what is the correct correction?

Explanation opens after your attempt
Correct Answer

A. \(x=\pm7\) लिखना चाहिएOne should write \(x=\pm7\)

Step 1

Concept

From \(x^2=49\), \(x=\pm\sqrt{49}=\pm7\). In exams, both signs are necessary in the square root method.

Step 2

Why this answer is correct

The correct answer is A. \(x=\pm7\) लिखना चाहिए / One should write \(x=\pm7\). From \(x^2=49\), \(x=\pm\sqrt{49}=\pm7\). In exams, both signs are necessary in the square root method.

Step 3

Exam Tip

\(x^2=49\) से \(x=\pm\sqrt{49}=\pm7\) मिलता है। परीक्षा में वर्गमूल विधि में दोनों चिन्ह अनिवार्य हैं।

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Question 48/91 Medium Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 35

\(6x^2-18x=0\) को हल करते समय कौनसी गलती नहीं करनी चाहिए?

Which mistake should be avoided while solving \(6x^2-18x=0\)?

Explanation opens after your attempt
Correct Answer

A. (x=0) को छोड़नाMissing (x=0)

Step 1

Concept

(6x-2-18x=6x(x-3)), so (x=0) and (x=3) are both roots. In exams, dividing by the variable can miss (x=0).

Step 2

Why this answer is correct

The correct answer is A. (x=0) को छोड़ना / Missing (x=0). (6x-2-18x=6x(x-3)), so (x=0) and (x=3) are both roots. In exams, dividing by the variable can miss (x=0).

Step 3

Exam Tip

(6x-2-18x=6x(x-3)), इसलिए (x=0) और (x=3) दोनों मूल हैं। परीक्षा में चर से भाग देने पर (x=0) छूट सकता है।

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Question 49/91 Medium Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 34

यदि किसी छात्र ने \(x^2=25\) से केवल (x=5) लिखा, तो सुधार क्या है?

If a student wrote only (x=5) from \(x^2=25\), what is the correction?

Explanation opens after your attempt
Correct Answer

A. \(x=\pm5\) लिखना चाहिएOne should write \(x=\pm5\)

Step 1

Concept

From \(x^2=25\), \(x=\pm\sqrt{25}=\pm5\). In exams, both signs are necessary in the square root method.

Step 2

Why this answer is correct

The correct answer is A. \(x=\pm5\) लिखना चाहिए / One should write \(x=\pm5\). From \(x^2=25\), \(x=\pm\sqrt{25}=\pm5\). In exams, both signs are necessary in the square root method.

Step 3

Exam Tip

\(x^2=25\) से \(x=\pm\sqrt{25}=\pm5\) मिलता है। परीक्षा में वर्गमूल विधि में दोनों चिन्ह अनिवार्य हैं।

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Question 50/91 Medium Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 34

किस समीकरण को पहले (x) से भाग करना सुरक्षित नहीं है?

For which equation is it not safe to divide by (x) first?

Explanation opens after your attempt
Correct Answer

A. \(x^2-8x=0\)

Step 1

Concept

In \(x^2-8x=0\), (x) is a common factor and (x=0) can be a root. In exams, write (x(x-8)=0) in such cases.

Step 2

Why this answer is correct

The correct answer is A. \(x^2-8x=0\). In \(x^2-8x=0\), (x) is a common factor and (x=0) can be a root. In exams, write (x(x-8)=0) in such cases.

Step 3

Exam Tip

\(x^2-8x=0\) में (x) सामान्य गुणनखंड है और (x=0) मूल हो सकता है। परीक्षा में ऐसे मामलों में (x(x-8)=0) लिखें।

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Question 51/91 Medium Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 34

\(5x^2-20x=0\) को हल करते समय कौनसी सामान्य गलती हो सकती है?

What common mistake can occur while solving \(5x^2-20x=0\)?

Explanation opens after your attempt
Correct Answer

A. (x=0) को छोड़ देनाMissing (x=0)

Step 1

Concept

The correct form is (5x(x-4)=0), giving (x=0) and (x=4). In exams, dividing directly by the variable can miss (x=0).

Step 2

Why this answer is correct

The correct answer is A. (x=0) को छोड़ देना / Missing (x=0). The correct form is (5x(x-4)=0), giving (x=0) and (x=4). In exams, dividing directly by the variable can miss (x=0).

Step 3

Exam Tip

सही रूप (5x(x-4)=0) है, जिससे (x=0) और (x=4) मिलते हैं। परीक्षा में चर से सीधे भाग देने से (x=0) छूट सकता है।

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Question 52/91 Easy Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 36

यदि \(x^2-11x=0\) को (x) से भाग देकर केवल (x-11=0) लिखा जाए, तो कौनसा मूल छूटेगा?

If \(x^2-11x=0\) is divided by (x) and only (x-11=0) is written, which root is missed?

Explanation opens after your attempt
Correct Answer

A. (x=0)

Step 1

Concept

Dividing by (x) misses the root (x=0). In exams, writing the factor form first is safer.

Step 2

Why this answer is correct

The correct answer is A. (x=0). Dividing by (x) misses the root (x=0). In exams, writing the factor form first is safer.

Step 3

Exam Tip

(x) से भाग देने पर (x=0) वाला मूल छूट जाता है। परीक्षा में पहले गुणनखंड रूप लिखना सुरक्षित है।

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Question 53/91 Easy Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 36

\(x^2-11x=0\) में (x=0) मूल क्यों है?

Why is (x=0) a root of \(x^2-11x=0\)?

Explanation opens after your attempt
Correct Answer

A. क्योंकि (x(x-11)=0)Because (x(x-11)=0)

Step 1

Concept

(x-2-11x=x(x-11)), so zero product rule gives (x=0). In exams, do not lose this root by dividing by the variable.

Step 2

Why this answer is correct

The correct answer is A. क्योंकि (x(x-11)=0) / Because (x(x-11)=0). (x-2-11x=x(x-11)), so zero product rule gives (x=0). In exams, do not lose this root by dividing by the variable.

Step 3

Exam Tip

(x-2-11x=x(x-11)), इसलिए शून्य गुणनफल नियम से (x=0) मिलता है। परीक्षा में चर से भाग देकर यह मूल न खोएं।

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Question 54/91 Easy Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 36

\(x^2=169\) को वर्गमूल विधि से हल करने पर क्या मिलेगा?

Solving \(x^2=169\) by square root method gives what?

Explanation opens after your attempt
Correct Answer

A. \(x=\pm13\)

Step 1

Concept

\(x=\pm\sqrt{169}=\pm13\). In exams, writing only (13) is an incomplete answer.

Step 2

Why this answer is correct

The correct answer is A. \(x=\pm13\). \(x=\pm\sqrt{169}=\pm13\). In exams, writing only (13) is an incomplete answer.

Step 3

Exam Tip

\(x=\pm\sqrt{169}=\pm13\) होता है। परीक्षा में केवल (13) लिखना अधूरा उत्तर है।

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Question 55/91 Easy Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 35

यदि \(x^2-5x=0\) को (x) से भाग देकर केवल (x-5=0) लिखा जाए, तो कौनसा मूल छूटेगा?

If \(x^2-5x=0\) is divided by (x) and only (x-5=0) is written, which root is missed?

Explanation opens after your attempt
Correct Answer

A. (x=0)

Step 1

Concept

Dividing by (x) misses the root (x=0). In exams, writing the factor form first is safer.

Step 2

Why this answer is correct

The correct answer is A. (x=0). Dividing by (x) misses the root (x=0). In exams, writing the factor form first is safer.

Step 3

Exam Tip

(x) से भाग देने पर (x=0) वाला मूल छूट जाता है। परीक्षा में पहले गुणनखंड रूप लिखना सुरक्षित है।

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Question 56/91 Easy Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 35

\(x^2-5x=0\) में (x=0) मूल क्यों है?

Why is (x=0) a root of \(x^2-5x=0\)?

Explanation opens after your attempt
Correct Answer

A. क्योंकि (x(x-5)=0)Because (x(x-5)=0)

Step 1

Concept

(x-2-5x=x(x-5)), so zero product rule gives (x=0). In exams, do not lose this root by dividing by the variable.

Step 2

Why this answer is correct

The correct answer is A. क्योंकि (x(x-5)=0) / Because (x(x-5)=0). (x-2-5x=x(x-5)), so zero product rule gives (x=0). In exams, do not lose this root by dividing by the variable.

Step 3

Exam Tip

(x-2-5x=x(x-5)), इसलिए शून्य गुणनफल नियम से (x=0) मिलता है। परीक्षा में चर से भाग देकर यह मूल न खोएं।

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Question 57/91 Easy Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 35

\(x^2=121\) को वर्गमूल विधि से हल करने पर क्या मिलेगा?

Solving \(x^2=121\) by square root method gives what?

Explanation opens after your attempt
Correct Answer

A. \(x=\pm11\)

Step 1

Concept

\(x=\pm\sqrt{121}=\pm11\). In exams, writing only (11) is an incomplete answer.

Step 2

Why this answer is correct

The correct answer is A. \(x=\pm11\). \(x=\pm\sqrt{121}=\pm11\). In exams, writing only (11) is an incomplete answer.

Step 3

Exam Tip

\(x=\pm\sqrt{121}=\pm11\) होता है। परीक्षा में केवल (11) लिखना अधूरा उत्तर है।

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Question 58/91 Easy Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 34

यदि \(x^2-3x=0\) को (x) से भाग देकर (x-3=0) लिखा जाए, तो कौनसा मूल छूट जाएगा?

If \(x^2-3x=0\) is divided by (x) to write (x-3=0), which root is missed?

Explanation opens after your attempt
Correct Answer

A. (x=0)

Step 1

Concept

Dividing by (x) misses the root (x=0). In exams, it is safer to write (x(x-3)=0) first.

Step 2

Why this answer is correct

The correct answer is A. (x=0). Dividing by (x) misses the root (x=0). In exams, it is safer to write (x(x-3)=0) first.

Step 3

Exam Tip

(x) से भाग देने पर (x=0) वाला मूल छूट जाता है। परीक्षा में पहले (x(x-3)=0) लिखना सुरक्षित है।

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Question 59/91 Easy Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 34

\(x^2-3x=0\) में (x=0) क्यों एक मूल है?

Why is (x=0) a root of \(x^2-3x=0\)?

Explanation opens after your attempt
Correct Answer

A. क्योंकि (x(x-3)=0)Because (x(x-3)=0)

Step 1

Concept

(x-2-3x=x(x-3)), so zero product rule gives (x=0). In exams, do not lose (x=0) by dividing by (x).

Step 2

Why this answer is correct

The correct answer is A. क्योंकि (x(x-3)=0) / Because (x(x-3)=0). (x-2-3x=x(x-3)), so zero product rule gives (x=0). In exams, do not lose (x=0) by dividing by (x).

Step 3

Exam Tip

(x-2-3x=x(x-3)), इसलिए शून्य गुणनफल नियम से (x=0) मिलता है। परीक्षा में (x) से भाग देकर (x=0) न खोएं।

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Question 60/91 Easy Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 34

\(x^2=49\) को वर्गमूल विधि से हल करने पर क्या मिलेगा?

Solving \(x^2=49\) by square root method gives what?

Explanation opens after your attempt
Correct Answer

A. \(x=\pm7\)

Step 1

Concept

\(x=\pm\sqrt{49}=\pm7\). In exams, writing only the positive root is a common mistake.

Step 2

Why this answer is correct

The correct answer is A. \(x=\pm7\). \(x=\pm\sqrt{49}=\pm7\). In exams, writing only the positive root is a common mistake.

Step 3

Exam Tip

\(x=\pm\sqrt{49}=\pm7\) होता है। परीक्षा में केवल धनात्मक मूल लिखना सामान्य गलती है।

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