80 results found for "evaluate-factorisation" in Class 10.
Question
Expert Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8
यदि \(2^3\times3^3\times5^2\times7\times11\) किसी संख्या का अभाज्य गुणनखंडन है, तो संख्या क्या है?
If \(2^3\times3^3\times5^2\times7\times11\) is the prime factorisation of a number, what is the number?
#evaluate-factorisation
#number-415800
#expert
A 415800
B 207900
C 831600
D 277200
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^3=8\), \(3^3=27\), and \(5^2=25\).
Step 2
Why this answer is correct
\(8\times27\times25\times7\times11=415800\).
Step 3
Exam Tip
When there are many factors, multiply in small groups. चरण 1: \(2^3=8\), \(3^3=27\) और \(5^2=25\) निकालें। चरण 2: \(8\times27\times25\times7\times11=415800\)। चरण 3: कई गुणनखंड हों तो छोटे समूह बनाकर गुणा करें।
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Question
Expert Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8
यदि \(2^4\times3^5\times5^2\times7\) किसी संख्या का अभाज्य गुणनखंडन है, तो संख्या क्या है?
If \(2^4\times3^5\times5^2\times7\) is the prime factorisation of a number, what is the number?
#evaluate-factorisation
#expert
#mcq
A 680400
B 340200
C 1360800
D 453600
Explanation opens after your attempt
Step 1
Concept
Take \(2^4=16\), \(3^5=243\), \(5^2=25\), and (7).
Step 2
Why this answer is correct
\(16\times243\times25\times7=680400\).
Step 3
Exam Tip
Solving powers first helps find the correct option quickly. चरण 1: \(2^4=16\), \(3^5=243\), \(5^2=25\) और (7) लें। चरण 2: \(16\times243\times25\times7=680400\)। चरण 3: घातों को पहले हल करने से सही विकल्प जल्दी मिलता है।
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Question
Expert Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8
किस विकल्प में \(2^4\times3^3\times5^2\times7^2\) का सही मान है?
Which option gives the correct value of \(2^4\times3^3\times5^2\times7^2\)?
#evaluate-factorisation
#number-529200
#expert
A 529200
B 264600
C 1058400
D 415800
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^4=16\), \(3^3=27\), \(5^2=25\), and \(7^2=49\).
Step 2
Why this answer is correct
\(16\times27\times25\times49=529200\).
Step 3
Exam Tip
Do the multiplication step by step. चरण 1: \(2^4=16\), \(3^3=27\), \(5^2=25\) और \(7^2=49\) निकालें। चरण 2: \(16\times27\times25\times49=529200\)। चरण 3: गुणा को चरणों में करें।
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Question
Expert Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8
किस विकल्प में \(2^6\times3^4\times11^2\) का सही मान है?
Which option gives the correct value of \(2^6\times3^4\times11^2\)?
#evaluate-factorisation
#number-627264
#expert
A 627264
B 313632
C 1254528
D 139392
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^6=64\), \(3^4=81\), and \(11^2=121\).
Step 2
Why this answer is correct
\(64\times81\times121=627264\).
Step 3
Exam Tip
Solve all three powers separately first. चरण 1: \(2^6=64\), \(3^4=81\) और \(11^2=121\) निकालें। चरण 2: \(64\times81\times121=627264\)। चरण 3: तीनों घातों को पहले अलग-अलग हल करें।
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Question
Expert Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8
किस संख्या का अभाज्य गुणनखंडन \(2^3\times3^6\times5\times13\) है?
Which number has prime factorisation \(2^3\times3^6\times5\times13\)?
#evaluate-factorisation
#number-379080
#expert
A 379080
B 189540
C 758160
D 117000
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^3=8\) and \(3^6=729\).
Step 2
Why this answer is correct
\(8\times729\times5\times13=379080\).
Step 3
Exam Tip
Simplify the higher-power part first. चरण 1: \(2^3=8\) और \(3^6=729\) निकालें। चरण 2: \(8\times729\times5\times13=379080\)। चरण 3: बड़े घात वाले भाग को पहले सरल करें।
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Question
Expert Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8
किस संख्या का अभाज्य गुणनखंडन \(3^4\times5^2\times7^2\) है?
Which number has prime factorisation \(3^4\times5^2\times7^2\)?
#evaluate-factorisation
#number-99225
#expert
A 99225
B 49612
C 198450
D 11025
Explanation opens after your attempt
Step 1
Concept
Calculate \(3^4=81\), \(5^2=25\), and \(7^2=49\).
Step 2
Why this answer is correct
\(81\times25\times49=99225\).
Step 3
Exam Tip
Do not skip square powers in a hurry. चरण 1: \(3^4=81\), \(5^2=25\) और \(7^2=49\) निकालें। चरण 2: \(81\times25\times49=99225\)। चरण 3: वर्ग घातों को जल्दबाजी में न छोड़ें।
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Question
Expert Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8
किस संख्या का अभाज्य गुणनखंडन \(2^7\times3^2\times11^2\) है?
Which number has prime factorisation \(2^7\times3^2\times11^2\)?
#evaluate-factorisation
#number-139392
#expert
A 139392
B 69696
C 278784
D 177408
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^7=128\), \(3^2=9\), and \(11^2=121\).
Step 2
Why this answer is correct
\(128\times9\times121=139392\).
Step 3
Exam Tip
Find the values of powers first, then multiply. चरण 1: \(2^7=128\), \(3^2=9\) और \(11^2=121\) निकालें। चरण 2: \(128\times9\times121=139392\)। चरण 3: पहले घातों का मान निकालें, फिर गुणा करें।
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Question
Expert Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8
किस संख्या का अभाज्य गुणनखंडन \(2^4\times3^5\times7^2\) है?
Which number has prime factorisation \(2^4\times3^5\times7^2\)?
#evaluate-factorisation
#number-190512
#expert
A 190512
B 95256
C 381024
D 127008
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^4=16\), \(3^5=243\), and \(7^2=49\).
Step 2
Why this answer is correct
\(16\times243\times49=190512\).
Step 3
Exam Tip
Finding all three powers separately is safer. चरण 1: \(2^4=16\), \(3^5=243\) और \(7^2=49\) निकालें। चरण 2: \(16\times243\times49=190512\)। चरण 3: तीनों घातों का मान अलग-अलग निकालना सुरक्षित रहता है।
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Question
Expert Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8
किस संख्या का अभाज्य गुणनखंडन \(2^6\times3^5\times7^2\) है?
Which number has prime factorisation \(2^6\times3^5\times7^2\)?
#evaluate-factorisation
#number-762048
#expert
A 762048
B 381024
C 1524096
D 190512
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^6=64\), \(3^5=243\), and \(7^2=49\).
Step 2
Why this answer is correct
\(64\times243\times49=762048\).
Step 3
Exam Tip
In such calculations, solve powers first. चरण 1: \(2^6=64\), \(3^5=243\) और \(7^2=49\) निकालें। चरण 2: \(64\times243\times49=762048\)। चरण 3: ऐसी गणना में घातों को पहले हल करें।
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Question
Hard Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 9
यदि \(2^2\times3^2\times5^2\times11^2\) किसी संख्या का अभाज्य गुणनखंडन है, तो संख्या क्या है?
If \(2^2\times3^2\times5^2\times11^2\) is the prime factorisation of a number, what is the number?
#evaluate-factorisation
#square-number
#hard
A 108900
B 54450
C 217800
D 27225
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^2=4\), \(3^2=9\), \(5^2=25\), and \(11^2=121\).
Step 2
Why this answer is correct
\(4\times9\times25\times121=108900\).
Step 3
Exam Tip
This is a square form, so observe the powers carefully. चरण 1: \(2^2=4\), \(3^2=9\), \(5^2=25\) और \(11^2=121\) निकालें। चरण 2: \(4\times9\times25\times121=108900\)। चरण 3: यह वर्ग रूप है, इसलिए घातों को ध्यान से देखें।
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Question
Hard Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 9
यदि \(2^6\times3^3\times5^2\) किसी संख्या का अभाज्य गुणनखंडन है, तो संख्या क्या है?
If \(2^6\times3^3\times5^2\) is the prime factorisation of a number, what is the number?
#evaluate-factorisation
#hard
#mcq
A 43200
B 21600
C 86400
D 32400
Explanation opens after your attempt
Step 1
Concept
\(2^6=64\), \(3^3=27\), and \(5^2=25\).
Step 2
Why this answer is correct
\(64\times27\times25=43200\).
Step 3
Exam Tip
Solving powers first helps find the correct option quickly. चरण 1: \(2^6=64\), \(3^3=27\) और \(5^2=25\) हैं। चरण 2: \(64\times27\times25=43200\)। चरण 3: घातों को पहले हल करने से सही विकल्प जल्दी मिलता है।
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Question
Hard Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 9
किस विकल्प में \(2^3\times3^5\times7^2\) का सही मान है?
Which option gives the correct value of \(2^3\times3^5\times7^2\)?
#evaluate-factorisation
#number-95256
#hard
A 95256
B 47628
C 190512
D 68040
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^3=8\), \(3^5=243\), and \(7^2=49\).
Step 2
Why this answer is correct
\(8\times243\times49=95256\).
Step 3
Exam Tip
Simplify higher powers first. चरण 1: \(2^3=8\), \(3^5=243\) और \(7^2=49\) निकालें। चरण 2: \(8\times243\times49=95256\)। चरण 3: बड़ी घातों को पहले सरल करें।
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Question
Hard Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 9
किस विकल्प में \(2^5\times3^4\times7^2\) का सही मान है?
Which option gives the correct value of \(2^5\times3^4\times7^2\)?
#evaluate-factorisation
#number-127008
#hard
A 127008
B 63504
C 254016
D 95256
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^5=32\), \(3^4=81\), and \(7^2=49\).
Step 2
Why this answer is correct
\(32\times81\times49=127008\).
Step 3
Exam Tip
Solve all three powers separately first. चरण 1: \(2^5=32\), \(3^4=81\) और \(7^2=49\) निकालें। चरण 2: \(32\times81\times49=127008\)। चरण 3: तीनों घातों को पहले अलग-अलग हल करें।
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Question
Hard Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 9
किस संख्या का अभाज्य गुणनखंडन \(2^5\times3^4\times7^2\) है?
Which number has prime factorisation \(2^5\times3^4\times7^2\)?
#evaluate-factorisation
#number-127008
#hard
A 127008
B 63504
C 254016
D 95256
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^5=32\), \(3^4=81\), and \(7^2=49\).
Step 2
Why this answer is correct
\(32\times81\times49=127008\).
Step 3
Exam Tip
Solving powers first keeps multiplication clear. चरण 1: \(2^5=32\), \(3^4=81\) और \(7^2=49\) निकालें। चरण 2: \(32\times81\times49=127008\)। चरण 3: घातों को पहले हल करने से गुणा साफ रहता है।
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Question
Hard Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 9
किस संख्या का अभाज्य गुणनखंडन \(2^6\times3^3\times5^2\) है?
Which number has prime factorisation \(2^6\times3^3\times5^2\)?
#evaluate-factorisation
#number-43200
#hard
A 43200
B 21600
C 86400
D 32400
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^6=64\), \(3^3=27\), and \(5^2=25\).
Step 2
Why this answer is correct
\(64\times27\times25=43200\).
Step 3
Exam Tip
Simplify all three powers separately. चरण 1: \(2^6=64\), \(3^3=27\) और \(5^2=25\) निकालें। चरण 2: \(64\times27\times25=43200\)। चरण 3: तीनों घातों को अलग-अलग सरल करें।
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Question
Hard Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 9
किस संख्या का अभाज्य गुणनखंडन \(2\times3\times5\times7\times11^2\) है?
Which number has prime factorisation \(2\times3\times5\times7\times11^2\)?
#evaluate-factorisation
#number-25410
#hard
A 25410
B 12705
C 50820
D 27720
Explanation opens after your attempt
Step 1
Concept
Calculate \(11^2=121\).
Step 2
Why this answer is correct
\(2\times3\times5\times7\times121=25410\).
Step 3
Exam Tip
First take the product of smaller factors as 210, then multiply by 121. चरण 1: \(11^2=121\) निकालें। चरण 2: \(2\times3\times5\times7\times121=25410\)। चरण 3: पहले छोटे गुणनखंडों का गुणनफल 210 लें, फिर 121 से गुणा करें।
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Question
Hard Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 9
किस संख्या का अभाज्य गुणनखंडन \(2^5\times3^4\times7\) है?
Which number has prime factorisation \(2^5\times3^4\times7\)?
#evaluate-factorisation
#number-18144
#hard
A 18144
B 9072
C 36288
D 12096
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^5=32\) and \(3^4=81\).
Step 2
Why this answer is correct
\(32\times81\times7=18144\).
Step 3
Exam Tip
It is better to find higher powers first. चरण 1: \(2^5=32\) और \(3^4=81\) निकालें। चरण 2: \(32\times81\times7=18144\)। चरण 3: बड़ी घातों का मान पहले निकालना ठीक रहता है।
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Question
Hard Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 9
किस संख्या का अभाज्य गुणनखंडन \(2^4\times3^4\times11\) है?
Which number has prime factorisation \(2^4\times3^4\times11\)?
#evaluate-factorisation
#number-14256
#hard
A 14256
B 7128
C 28512
D 18144
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^4=16\) and \(3^4=81\).
Step 2
Why this answer is correct
\(16\times81\times11=14256\).
Step 3
Exam Tip
Solve powers first, then multiply by 11. चरण 1: \(2^4=16\) और \(3^4=81\) निकालें। चरण 2: \(16\times81\times11=14256\)। चरण 3: घातों को पहले हल करें, फिर 11 से गुणा करें।
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Question
Hard Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 7
यदि \(2^3\times5^2\times7^2\) किसी संख्या का अभाज्य गुणनखंडन है, तो संख्या क्या है?
If \(2^3\times5^2\times7^2\) is the prime factorisation of a number, what is the number?
#evaluate-factorisation
#square-base
#hard
A 9800
B 4900
C 19600
D 1225
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^3=8\), \(5^2=25\), and \(7^2=49\).
Step 2
Why this answer is correct
\(8\times25\times49=9800\).
Step 3
Exam Tip
Find all three powers separately. चरण 1: \(2^3=8\), \(5^2=25\) और \(7^2=49\) निकालें। चरण 2: \(8\times25\times49=9800\)। चरण 3: तीनों घातों का मान अलग-अलग निकालें।
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Question
Hard Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 7
यदि \(2^4\times3^2\times5\times7\) किसी संख्या का अभाज्य गुणनखंडन है, तो संख्या क्या है?
If \(2^4\times3^2\times5\times7\) is the prime factorisation of a number, what is the number?
#evaluate-factorisation
#hard
#mcq
A 5040
B 2520
C 10080
D 7560
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^4=16\) and \(3^2=9\).
Step 2
Why this answer is correct
\(16\times9\times5\times7=5040\).
Step 3
Exam Tip
Solving powers first helps find the correct option quickly. चरण 1: \(2^4=16\) और \(3^2=9\) निकालें। चरण 2: \(16\times9\times5\times7=5040\)। चरण 3: घातों को पहले हल करने से सही विकल्प जल्दी मिलता है।
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Question
Hard Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 7
किस विकल्प में \(2^8\times3^4\) का सही मान है?
Which option gives the correct value of \(2^8\times3^4\)?
#evaluate-factorisation
#number-20736
#hard
A 20736
B 10368
C 41472
D 7776
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^8=256\) and \(3^4=81\).
Step 2
Why this answer is correct
\(256\times81=20736\).
Step 3
Exam Tip
Simplify higher powers separately and multiply. चरण 1: \(2^8=256\) और \(3^4=81\) निकालें। चरण 2: \(256\times81=20736\)। चरण 3: बड़ी घातों को अलग-अलग सरल करके गुणा करें।
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Question
Hard Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 7
किस विकल्प में \(2^4\times3^2\times5\times7^2\) का सही मान है?
Which option gives the correct value of \(2^4\times3^2\times5\times7^2\)?
#evaluate-factorisation
#number-35280
#hard
A 35280
B 17640
C 70560
D 22050
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^4=16\), \(3^2=9\), and \(7^2=49\).
Step 2
Why this answer is correct
\(16\times9\times5\times49=35280\).
Step 3
Exam Tip
Solve powers separately first. चरण 1: \(2^4=16\), \(3^2=9\) और \(7^2=49\) निकालें। चरण 2: \(16\times9\times5\times49=35280\)। चरण 3: घातों को पहले अलग-अलग हल करें।
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Question
Hard Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 7
किस संख्या का अभाज्य गुणनखंडन \(2^7\times3^4\) है?
Which number has prime factorisation \(2^7\times3^4\)?
#evaluate-factorisation
#number-10368
#hard
A 10368
B 5184
C 20736
D 7776
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^7=128\) and \(3^4=81\).
Step 2
Why this answer is correct
\(128\times81=10368\).
Step 3
Exam Tip
Solving large powers first reduces mistakes. चरण 1: \(2^7=128\) और \(3^4=81\) निकालें। चरण 2: \(128\times81=10368\)। चरण 3: बड़ी घातों को पहले हल करने से गलती कम होती है।
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Question
Hard Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 7
किस संख्या का अभाज्य गुणनखंडन \(2^2\times3^3\times7^2\) है?
Which number has prime factorisation \(2^2\times3^3\times7^2\)?
#evaluate-factorisation
#number-5292
#hard
A 5292
B 2646
C 10584
D 4410
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^2=4\), \(3^3=27\), and \(7^2=49\).
Step 2
Why this answer is correct
\(4\times27\times49=5292\).
Step 3
Exam Tip
Simplify all three powers separately. चरण 1: \(2^2=4\), \(3^3=27\) और \(7^2=49\) निकालें। चरण 2: \(4\times27\times49=5292\)। चरण 3: तीनों घातों को अलग-अलग सरल करें।
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Question
Hard Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 7
किस संख्या का अभाज्य गुणनखंडन \(2^4\times3^2\times5\times7\) है?
Which number has prime factorisation \(2^4\times3^2\times5\times7\)?
#evaluate-factorisation
#number-5040
#hard
A 5040
B 2520
C 10080
D 7560
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^4=16\) and \(3^2=9\).
Step 2
Why this answer is correct
\(16\times9\times5\times7=5040\).
Step 3
Exam Tip
First do \(16\times9=144\), then multiply the rest. चरण 1: \(2^4=16\) और \(3^2=9\) निकालें। चरण 2: \(16\times9\times5\times7=5040\)। चरण 3: पहले \(16\times9=144\) करें, फिर बाकी गुणा करें।
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Question
Hard Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 7
किस संख्या का अभाज्य गुणनखंडन \(3^2\times5\times7\times11\) है?
Which number has prime factorisation \(3^2\times5\times7\times11\)?
#evaluate-factorisation
#number-3465
#hard
A 3465
B 1732
C 6930
D 1155
Explanation opens after your attempt
Step 1
Concept
Calculate \(3^2=9\).
Step 2
Why this answer is correct
\(9\times5\times7\times11=3465\).
Step 3
Exam Tip
When there are many factors, multiply in pairs. चरण 1: \(3^2=9\) निकालें। चरण 2: \(9\times5\times7\times11=3465\)। चरण 3: कई गुणनखंड हों तो जोड़े बनाकर गुणा करें।
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Question
Hard Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 7
किस संख्या का अभाज्य गुणनखंडन \(2^3\times3^3\times11\) है?
Which number has prime factorisation \(2^3\times3^3\times11\)?
#evaluate-factorisation
#number-2376
#hard
A 2376
B 1188
C 4752
D 3564
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^3=8\) and \(3^3=27\).
Step 2
Why this answer is correct
\(8\times27\times11=2376\).
Step 3
Exam Tip
Finding powers first is the correct method. चरण 1: \(2^3=8\) और \(3^3=27\) निकालें। चरण 2: \(8\times27\times11=2376\)। चरण 3: घातों का मान पहले निकालना सही तरीका है।
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Question
Hard Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8
यदि \(2^4\times5^2\times7^2\) किसी संख्या का अभाज्य गुणनखंडन है, तो संख्या क्या है?
If \(2^4\times5^2\times7^2\) is the prime factorisation of a number, what is the number?
#evaluate-factorisation
#square-number
#hard
A 19600
B 9800
C 39200
D 4900
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^4=16\), \(5^2=25\), and \(7^2=49\).
Step 2
Why this answer is correct
\(16\times25\times49=19600\).
Step 3
Exam Tip
Finding all three powers separately is safer. चरण 1: \(2^4=16\), \(5^2=25\) और \(7^2=49\) निकालें। चरण 2: \(16\times25\times49=19600\)। चरण 3: तीनों घातों का मान अलग-अलग निकालना सुरक्षित रहता है।
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Question
Hard Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8
यदि \(2^6\times3^2\times7^2\) किसी संख्या का अभाज्य गुणनखंडन है, तो संख्या क्या है?
If \(2^6\times3^2\times7^2\) is the prime factorisation of a number, what is the number?
#evaluate-factorisation
#hard
#mcq
A 28224
B 14112
C 56448
D 21168
Explanation opens after your attempt
Step 1
Concept
\(2^6=64\), \(3^2=9\), and \(7^2=49\).
Step 2
Why this answer is correct
\(64\times9\times49=28224\).
Step 3
Exam Tip
Solving powers first helps find the correct option quickly. चरण 1: \(2^6=64\), \(3^2=9\) और \(7^2=49\) हैं। चरण 2: \(64\times9\times49=28224\)। चरण 3: घातों को पहले हल करने से सही विकल्प जल्दी मिलता है।
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Question
Hard Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8
किस विकल्प में \(2^6\times3^2\times7^2\) का सही मान है?
Which option gives the correct value of \(2^6\times3^2\times7^2\)?
#evaluate-factorisation
#number-28224
#hard
A 28224
B 14112
C 56448
D 21168
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^6=64\), \(3^2=9\), and \(7^2=49\).
Step 2
Why this answer is correct
\(64\times9\times49=28224\).
Step 3
Exam Tip
Do multiplication step by step to avoid mistakes. चरण 1: \(2^6=64\), \(3^2=9\) और \(7^2=49\) निकालें। चरण 2: \(64\times9\times49=28224\)। चरण 3: गुणा को चरणों में करें ताकि गलती न हो।
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Question
Hard Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8
किस विकल्प में \(2^4\times3^3\times7^2\) का सही मान है?
Which option gives the correct value of \(2^4\times3^3\times7^2\)?
#evaluate-factorisation
#number-21168
#hard
A 21168
B 10584
C 28224
D 14112
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^4=16\), \(3^3=27\), and \(7^2=49\).
Step 2
Why this answer is correct
\(16\times27\times49=21168\).
Step 3
Exam Tip
Solve all three powers separately first. चरण 1: \(2^4=16\), \(3^3=27\) और \(7^2=49\) निकालें। चरण 2: \(16\times27\times49=21168\)। चरण 3: तीनों घातों को पहले अलग-अलग हल करें।
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Question
Hard Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8
किस संख्या का अभाज्य गुणनखंडन \(2^7\times3^5\) है?
Which number has prime factorisation \(2^7\times3^5\)?
#evaluate-factorisation
#number-31104
#hard
A 31104
B 15552
C 62208
D 20736
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^7=128\) and \(3^5=243\).
Step 2
Why this answer is correct
\(128\times243=31104\).
Step 3
Exam Tip
Simplifying both powers first is the correct method. चरण 1: \(2^7=128\) और \(3^5=243\) निकालें। चरण 2: \(128\times243=31104\)। चरण 3: दोनों घातों को पहले सरल करना सही तरीका है।
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Question
Hard Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8
किस संख्या का अभाज्य गुणनखंडन \(2^4\times3\times5\times7^2\) है?
Which number has prime factorisation \(2^4\times3\times5\times7^2\)?
#evaluate-factorisation
#number-11760
#hard
A 11760
B 5880
C 23520
D 17640
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^4=16\) and \(7^2=49\).
Step 2
Why this answer is correct
\(16\times3\times5\times49=11760\).
Step 3
Exam Tip
Calculating powers first makes the work easier. चरण 1: \(2^4=16\) और \(7^2=49\) निकालें। चरण 2: \(16\times3\times5\times49=11760\)। चरण 3: घातों का मान पहले निकालने से गणना आसान होती है।
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Question
Hard Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8
किस संख्या का अभाज्य गुणनखंडन \(3^2\times5^2\times7^2\) है?
Which number has prime factorisation \(3^2\times5^2\times7^2\)?
#evaluate-factorisation
#square-number
#hard
A 11025
B 3675
C 22050
D 1225
Explanation opens after your attempt
Step 1
Concept
Calculate \(3^2=9\), \(5^2=25\), and \(7^2=49\).
Step 2
Why this answer is correct
\(9\times25\times49=11025\).
Step 3
Exam Tip
In this square form, all exponents are 2, so multiply carefully. चरण 1: \(3^2=9\), \(5^2=25\) और \(7^2=49\) निकालें। चरण 2: \(9\times25\times49=11025\)। चरण 3: वर्ग रूप में सभी घातें 2 हैं, इसलिए गुणा ध्यान से करें।
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Question
Hard Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8
किस संख्या का अभाज्य गुणनखंडन \(2^5\times3^3\times7\) है?
Which number has prime factorisation \(2^5\times3^3\times7\)?
#evaluate-factorisation
#number-6048
#hard
A 6048
B 3024
C 12096
D 8064
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^5=32\) and \(3^3=27\).
Step 2
Why this answer is correct
\(32\times27\times7=6048\).
Step 3
Exam Tip
Find the values of higher powers separately. चरण 1: \(2^5=32\) और \(3^3=27\) निकालें। चरण 2: \(32\times27\times7=6048\)। चरण 3: बड़ी घातों का मान अलग से निकालें।
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Question
Hard Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8
किस संख्या का अभाज्य गुणनखंडन \(2^3\times3^2\times7\times11\) है?
Which number has prime factorisation \(2^3\times3^2\times7\times11\)?
#evaluate-factorisation
#number-5544
#hard
A 5544
B 2772
C 11088
D 8316
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^3=8\) and \(3^2=9\).
Step 2
Why this answer is correct
\(8\times9\times7\times11=5544\).
Step 3
Exam Tip
Simplify powers first and then multiply. चरण 1: \(2^3=8\) और \(3^2=9\) निकालें। चरण 2: \(8\times9\times7\times11=5544\)। चरण 3: घातों को पहले सरल करके गुणा करें।
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Question
Medium Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 9
किस संख्या का अभाज्य गुणनखंडन \(2\times3^2\times5^2\times13\) है?
Which number has prime factorisation \(2\times3^2\times5^2\times13\)?
#evaluate-factorisation
#number-5850
#medium
A 5850
B 2925
C 11700
D 3900
Explanation opens after your attempt
Step 1
Concept
Calculate \(3^2=9\) and \(5^2=25\).
Step 2
Why this answer is correct
\(2\times9\times25\times13=5850\).
Step 3
Exam Tip
First do \(9\times25=225\), then multiply the rest. चरण 1: \(3^2=9\) और \(5^2=25\) निकालें। चरण 2: \(2\times9\times25\times13=5850\)। चरण 3: पहले \(9\times25=225\) करें, फिर बाकी गुणा करें।
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Question
Medium Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 9
यदि \(2^4\times3\times5\times11\) किसी संख्या का अभाज्य गुणनखंडन है, तो संख्या क्या है?
If \(2^4\times3\times5\times11\) is the prime factorisation of a number, what is the number?
#evaluate-factorisation
#number-2640
#medium
A 2640
B 1320
C 5280
D 3960
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^4=16\).
Step 2
Why this answer is correct
\(16\times3\times5\times11=2640\).
Step 3
Exam Tip
Do multiplication in small steps to avoid mistakes. चरण 1: \(2^4=16\) निकालें। चरण 2: \(16\times3\times5\times11=2640\)। चरण 3: गुणन को छोटे चरणों में करें ताकि गलती न हो।
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Question
Medium Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 9
यदि किसी संख्या का अभाज्य गुणनखंडन \(2^2\times3^4\times7\) है, तो वह संख्या कौन सी है?
If the prime factorisation of a number is \(2^2\times3^4\times7\), which number is it?
#evaluate-factorisation
#number-2268
#medium
A 2268
B 1134
C 4536
D 3402
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^2=4\) and \(3^4=81\).
Step 2
Why this answer is correct
\(4\times81\times7=2268\).
Step 3
Exam Tip
Simplifying the higher power first is the right method. चरण 1: \(2^2=4\) और \(3^4=81\) निकालें। चरण 2: \(4\times81\times7=2268\)। चरण 3: बड़ी घात को पहले सरल करना सही तरीका है।
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Question
Medium Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 9
यदि किसी संख्या का अभाज्य गुणनखंडन \(3^2\times5\times7^2\) है, तो वह संख्या कौन सी है?
If the prime factorisation of a number is \(3^2\times5\times7^2\), which number is it?
#evaluate-factorisation
#number-2205
#medium
A 2205
B 735
C 4410
D 1470
Explanation opens after your attempt
Step 1
Concept
Calculate \(3^2=9\) and \(7^2=49\).
Step 2
Why this answer is correct
\(9\times5\times49=2205\).
Step 3
Exam Tip
Simplify the two powers first and multiply. चरण 1: \(3^2=9\) और \(7^2=49\) निकालें। चरण 2: \(9\times5\times49=2205\)। चरण 3: दो घातों को पहले सरल करके गुणा करें।
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Question
Medium Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 9
यदि \(2^5\times3^2\times7\) से संख्या बनाई जाए, तो वह कौन सी होगी?
If a number is formed from \(2^5\times3^2\times7\), which number will it be?
#evaluate-factorisation
#mcq-pattern
#medium
A 2016
B 1008
C 4032
D 1344
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^5=32\) and \(3^2=9\).
Step 2
Why this answer is correct
\(32\times9\times7=2016\).
Step 3
Exam Tip
Solving powers first gives the answer quickly. चरण 1: \(2^5=32\) और \(3^2=9\) निकालें। चरण 2: \(32\times9\times7=2016\)। चरण 3: घातों को पहले हल करने से उत्तर जल्दी मिलता है।
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Question
Medium Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 9
यदि \(m=3^4\times5\times7\), तो (m) का मान क्या है?
If \(m=3^4\times5\times7\), what is the value of (m)?
#evaluate-factorisation
#powers
#medium
A 2835
B 945
C 5670
D 2025
Explanation opens after your attempt
Step 1
Concept
\(3^4=81\).
Step 2
Why this answer is correct
\(81\times5\times7=2835\).
Step 3
Exam Tip
Simplifying the power first keeps the calculation clear. चरण 1: \(3^4=81\) है। चरण 2: \(81\times5\times7=2835\)। चरण 3: घात को पहले सरल करने से गणना साफ रहती है।
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Question
Medium Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 9
यदि \(n=2^4\times3\times5\times11\), तो (n) का मान क्या है?
If \(n=2^4\times3\times5\times11\), what is the value of (n)?
#evaluate-factorisation
#powers
#medium
A 2640
B 1320
C 5280
D 1980
Explanation opens after your attempt
Step 1
Concept
\(2^4=16\).
Step 2
Why this answer is correct
\(16\times3\times5\times11=2640\).
Step 3
Exam Tip
Multiply all factors to get the number from prime form. चरण 1: \(2^4=16\) है। चरण 2: \(16\times3\times5\times11=2640\)। चरण 3: अभाज्य रूप से संख्या पाने के लिए सभी गुणनखंडों को गुणा करें।
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Question
Medium Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 9
किस संख्या का अभाज्य गुणनखंडन \(2^4\times3\times5\times13\) है?
Which number has prime factorisation \(2^4\times3\times5\times13\)?
#evaluate-factorisation
#number-3120
#medium
A 3120
B 1560
C 6240
D 2340
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^4=16\).
Step 2
Why this answer is correct
\(16\times3\times5\times13=3120\).
Step 3
Exam Tip
It is easy to first treat \(3\times5\times13\) as 195 and multiply. चरण 1: \(2^4=16\) निकालें। चरण 2: \(16\times3\times5\times13=3120\)। चरण 3: पहले \(3\times5\times13\) को 195 समझकर गुणा करना आसान है।
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Question
Medium Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 9
किस संख्या का अभाज्य गुणनखंडन \(2^2\times3\times7\times11\) है?
Which number has prime factorisation \(2^2\times3\times7\times11\)?
#evaluate-factorisation
#number-924
#medium
A 924
B 462
C 1848
D 1386
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^2=4\).
Step 2
Why this answer is correct
\(4\times3\times7\times11=924\).
Step 3
Exam Tip
With many factors, multiply in pairs. चरण 1: \(2^2=4\) निकालें। चरण 2: \(4\times3\times7\times11=924\)। चरण 3: कई गुणनखंडों में जोड़े बनाकर गुणा करें।
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Question
Medium Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 9
किस संख्या का अभाज्य गुणनखंडन \(2^5\times3^3\) है?
Which number has prime factorisation \(2^5\times3^3\)?
#evaluate-factorisation
#number-864
#medium
A 864
B 432
C 1728
D 1296
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^5=32\) and \(3^3=27\).
Step 2
Why this answer is correct
\(32\times27=864\).
Step 3
Exam Tip
Simplify both powers separately. चरण 1: \(2^5=32\) और \(3^3=27\) निकालें। चरण 2: \(32\times27=864\)। चरण 3: दोनों घातों को अलग-अलग सरल करें।
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Question
Medium Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 9
किस संख्या का अभाज्य गुणनखंडन \(3\times5^2\times11\) है?
Which number has prime factorisation \(3\times5^2\times11\)?
#evaluate-factorisation
#number-825
#medium
A 825
B 550
C 1650
D 275
Explanation opens after your attempt
Step 1
Concept
Calculate \(5^2=25\).
Step 2
Why this answer is correct
\(3\times25\times11=825\).
Step 3
Exam Tip
It is useful to simplify the power part first. चरण 1: \(5^2=25\) निकालें। चरण 2: \(3\times25\times11=825\)। चरण 3: घात वाले भाग को पहले सरल करना उपयोगी है।
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Medium Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 9
किस संख्या का अभाज्य गुणनखंडन \(2^3\times3^2\times11\) है?
Which number has prime factorisation \(2^3\times3^2\times11\)?
#evaluate-factorisation
#number-792
#medium
A 792
B 396
C 1188
D 1584
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^3=8\) and \(3^2=9\).
Step 2
Why this answer is correct
\(8\times9\times11=792\).
Step 3
Exam Tip
First solve the powers, then multiply by 11. चरण 1: \(2^3=8\) और \(3^2=9\) निकालें। चरण 2: \(8\times9\times11=792\)। चरण 3: पहले घातों को हल करें, फिर 11 से गुणा करें।
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Question
Medium Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8
किस संख्या का अभाज्य गुणनखंडन \(2^2\times3\times5\times7\times11\) है?
Which number has prime factorisation \(2^2\times3\times5\times7\times11\)?
#evaluate-factorisation
#number-4620
#medium
A 4620
B 2310
C 9240
D 3850
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^2=4\).
Step 2
Why this answer is correct
\(4\times3\times5\times7\times11=4620\).
Step 3
Exam Tip
When there are many factors, multiply in pairs. चरण 1: \(2^2=4\) निकालें। चरण 2: \(4\times3\times5\times7\times11=4620\)। चरण 3: कई गुणनखंड हों तो जोड़े बनाकर गुणा करें।
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Question
Medium Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8
यदि \(2^2\times3^2\times7\times11\) किसी संख्या का अभाज्य गुणनखंडन है, तो संख्या क्या है?
If \(2^2\times3^2\times7\times11\) is the prime factorisation of a number, what is the number?
#evaluate-factorisation
#number-2772
#medium
A 2772
B 1386
C 5544
D 1980
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^2=4\) and \(3^2=9\).
Step 2
Why this answer is correct
\(4\times9\times7\times11=2772\).
Step 3
Exam Tip
Move step by step while multiplying. चरण 1: \(2^2=4\) और \(3^2=9\) निकालें। चरण 2: \(4\times9\times7\times11=2772\)। चरण 3: गुणा करते समय चरणों में आगे बढ़ें।
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Question
Medium Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8
यदि किसी संख्या का अभाज्य गुणनखंडन \(2\times3^3\times5^2\) है, तो वह संख्या कौन सी है?
If the prime factorisation of a number is \(2\times3^3\times5^2\), which number is it?
#evaluate-factorisation
#number-1350
#medium
A 1350
B 675
C 2700
D 1500
Explanation opens after your attempt
Step 1
Concept
Calculate \(3^3=27\) and \(5^2=25\).
Step 2
Why this answer is correct
\(2\times27\times25=1350\).
Step 3
Exam Tip
Simplifying the two powers first makes multiplication easy. चरण 1: \(3^3=27\) और \(5^2=25\) निकालें। चरण 2: \(2\times27\times25=1350\)। चरण 3: दो घातों को पहले सरल करने से गुणा आसान होता है।
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Question
Medium Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8
यदि किसी संख्या का अभाज्य गुणनखंडन \(2^2\times3^3\times11\) है, तो वह संख्या कौन सी है?
If the prime factorisation of a number is \(2^2\times3^3\times11\), which number is it?
#evaluate-factorisation
#number-1188
#medium
A 1188
B 594
C 2376
D 1320
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^2=4\) and \(3^3=27\).
Step 2
Why this answer is correct
\(4\times27\times11=1188\).
Step 3
Exam Tip
Finding the value of powers first is the right method. चरण 1: \(2^2=4\) और \(3^3=27\) निकालें। चरण 2: \(4\times27\times11=1188\)। चरण 3: पहले घातों का मान निकालना ठीक तरीका है।
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Question
Medium Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8
यदि \(2^4\times3^2\times11\) से संख्या बनाई जाए, तो वह कौन सी होगी?
If a number is formed from \(2^4\times3^2\times11\), which number will it be?
#evaluate-factorisation
#mcq-pattern
#medium
A 1584
B 792
C 3168
D 1188
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^4=16\) and \(3^2=9\).
Step 2
Why this answer is correct
\(16\times9\times11=1584\).
Step 3
Exam Tip
Solve powers first and then multiply. चरण 1: \(2^4=16\) और \(3^2=9\) निकालें। चरण 2: \(16\times9\times11=1584\)। चरण 3: घातों को पहले हल करके गुणा करें।
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Question
Medium Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8
यदि \(m=2^3\times3^2\times5\times7\), तो (m) का मान क्या है?
If \(m=2^3\times3^2\times5\times7\), what is the value of (m)?
#evaluate-factorisation
#powers
#medium
A 2520
B 1260
C 5040
D 1680
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^3=8\) and \(3^2=9\).
Step 2
Why this answer is correct
\(8\times9\times5\times7=2520\).
Step 3
Exam Tip
First solve powers, then multiply by the remaining factors. चरण 1: \(2^3=8\) और \(3^2=9\) निकालें। चरण 2: \(8\times9\times5\times7=2520\)। चरण 3: पहले घातों को हल करें, फिर बाकी गुणनखंडों से गुणा करें।
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Question
Medium Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8
यदि \(n=2^2\times3\times5^2\times7\), तो (n) का मान क्या है?
If \(n=2^2\times3\times5^2\times7\), what is the value of (n)?
#evaluate-factorisation
#powers
#medium
A 2100
B 1050
C 4200
D 700
Explanation opens after your attempt
Step 1
Concept
\(2^2=4\) and \(5^2=25\).
Step 2
Why this answer is correct
\(4\times3\times25\times7=2100\).
Step 3
Exam Tip
Solving the powers first makes multiplication easier. चरण 1: \(2^2=4\) और \(5^2=25\) हैं। चरण 2: \(4\times3\times25\times7=2100\)। चरण 3: दो घातों को पहले हल करने से गुणा आसान होता है।
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Question
Medium Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8
किस संख्या का अभाज्य गुणनखंडन \(2^4\times3^3\times7\) है?
Which number has prime factorisation \(2^4\times3^3\times7\)?
#evaluate-factorisation
#number-3024
#medium
A 3024
B 1512
C 6048
D 2016
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^4=16\) and \(3^3=27\).
Step 2
Why this answer is correct
\(16\times27\times7=3024\).
Step 3
Exam Tip
Simplify higher powers separately and multiply. चरण 1: \(2^4=16\) और \(3^3=27\) निकालें। चरण 2: \(16\times27\times7=3024\)। चरण 3: बड़ी घातों को अलग से सरल करके गुणा करें।
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Question
Medium Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8
किस संख्या का अभाज्य गुणनखंडन \(2^2\times3^2\times7\times11\) है?
Which number has prime factorisation \(2^2\times3^2\times7\times11\)?
#evaluate-factorisation
#number-2772
#medium
A 2772
B 1386
C 5544
D 1980
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^2=4\) and \(3^2=9\).
Step 2
Why this answer is correct
\(4\times9\times7\times11=2772\).
Step 3
Exam Tip
First multiply 4 and 9, then include the remaining factors. चरण 1: \(2^2=4\) और \(3^2=9\) निकालें। चरण 2: \(4\times9\times7\times11=2772\)। चरण 3: पहले 4 और 9 को गुणा करें, फिर बाकी गुणनखंड जोड़ें।
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Question
Medium Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8
किस संख्या का अभाज्य गुणनखंडन \(2\times3^3\times5\times7\) है?
Which number has prime factorisation \(2\times3^3\times5\times7\)?
#evaluate-factorisation
#number-1890
#medium
A 1890
B 945
C 3780
D 1350
Explanation opens after your attempt
Step 1
Concept
Calculate \(3^3=27\).
Step 2
Why this answer is correct
\(2\times27\times5\times7=1890\).
Step 3
Exam Tip
Finding the value of the power first makes calculation simple. चरण 1: \(3^3=27\) निकालें। चरण 2: \(2\times27\times5\times7=1890\)। चरण 3: घात का मान पहले निकालना गणना को सरल बनाता है।
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Question
Medium Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8
किस संख्या का अभाज्य गुणनखंडन \(2^4\times3\times5\times7\) है?
Which number has prime factorisation \(2^4\times3\times5\times7\)?
#evaluate-factorisation
#number-1680
#medium
A 1680
B 840
C 3360
D 1260
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^4=16\).
Step 2
Why this answer is correct
\(16\times3\times5\times7=1680\).
Step 3
Exam Tip
When there are four factors, multiply smaller products in order. चरण 1: \(2^4=16\) निकालें। चरण 2: \(16\times3\times5\times7=1680\)। चरण 3: चार गुणनखंड हों तो क्रम से छोटे गुणन करें।
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Question
Medium Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8
किस संख्या का अभाज्य गुणनखंडन \(2^3\times3^2\times11\) है?
Which number has prime factorisation \(2^3\times3^2\times11\)?
#evaluate-factorisation
#number-792
#medium
A 792
B 396
C 1584
D 1188
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^3=8\) and \(3^2=9\).
Step 2
Why this answer is correct
\(8\times9\times11=792\).
Step 3
Exam Tip
Solve prime powers first, then multiply. चरण 1: \(2^3=8\) और \(3^2=9\) निकालें। चरण 2: \(8\times9\times11=792\)। चरण 3: अभाज्य घातों को पहले हल करें, फिर गुणा करें।
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Question
Medium Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 7
किस संख्या का अभाज्य गुणनखंडन \(2^3\times5\times7\times11\) है?
Which number has prime factorisation \(2^3\times5\times7\times11\)?
#evaluate-factorisation
#number-3080
#medium
A 3080
B 1540
C 6160
D 3850
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^3=8\).
Step 2
Why this answer is correct
\(8\times5\times7\times11=3080\).
Step 3
Exam Tip
Whatever the order, the product remains the same. चरण 1: \(2^3=8\) निकालें। चरण 2: \(8\times5\times7\times11=3080\)। चरण 3: क्रम कोई भी हो, गुणनफल वही रहेगा।
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Question
Medium Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 7
यदि \(2^2\times5^4\) किसी संख्या का अभाज्य गुणनखंडन है, तो संख्या क्या है?
If \(2^2\times5^4\) is the prime factorisation of a number, what is the number?
#evaluate-factorisation
#number-2500
#medium
A 2500
B 1250
C 5000
D 625
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^2=4\) and \(5^4=625\).
Step 2
Why this answer is correct
\(4\times625=2500\).
Step 3
Exam Tip
Finding the higher power first makes the answer easier. चरण 1: \(2^2=4\) और \(5^4=625\) निकालें। चरण 2: \(4\times625=2500\)। चरण 3: बड़ी घात को पहले निकालने से उत्तर आसान बनता है।
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Question
Medium Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 7
यदि किसी संख्या का अभाज्य गुणनखंडन \(2^4\times3^4\) है, तो वह संख्या कौन सी है?
If the prime factorisation of a number is \(2^4\times3^4\), which number is it?
#evaluate-factorisation
#number-1296
#medium
A 1296
B 648
C 2592
D 1728
Explanation opens after your attempt
Step 1
Concept
\(2^4=16\) and \(3^4=81\).
Step 2
Why this answer is correct
\(16\times81=1296\).
Step 3
Exam Tip
In such calculations, simplifying powers first is safer. चरण 1: \(2^4=16\) और \(3^4=81\) हैं। चरण 2: \(16\times81=1296\)। चरण 3: ऐसी गणना में घातों को पहले सरल करना सुरक्षित रहता है।
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Question
Medium Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 7
यदि किसी संख्या का अभाज्य गुणनखंडन \(2^3\times3^2\times5^2\) है, तो वह संख्या कौन सी है?
If the prime factorisation of a number is \(2^3\times3^2\times5^2\), which number is it?
#evaluate-factorisation
#number-1800
#medium
A 1800
B 900
C 3600
D 1200
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^3=8\), \(3^2=9\), and \(5^2=25\).
Step 2
Why this answer is correct
\(8\times9\times25=1800\).
Step 3
Exam Tip
Find each power separately and then multiply. चरण 1: \(2^3=8\), \(3^2=9\) और \(5^2=25\) निकालें। चरण 2: \(8\times9\times25=1800\)। चरण 3: तीनों घातों का मान अलग-अलग निकालकर गुणा करें।
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Question
Medium Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 7
यदि \(2^4\times3^2\times5\) से संख्या बनाई जाए, तो वह कौन सी होगी?
If a number is formed from \(2^4\times3^2\times5\), which number will it be?
#evaluate-factorisation
#mcq-pattern
#medium
A 720
B 360
C 1440
D 1080
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^4=16\) and \(3^2=9\).
Step 2
Why this answer is correct
\(16\times9\times5=720\).
Step 3
Exam Tip
Solving powers first helps find the option quickly. चरण 1: \(2^4=16\) और \(3^2=9\) निकालें। चरण 2: \(16\times9\times5=720\)। चरण 3: घातों को पहले हल करने से विकल्प जल्दी मिल जाता है।
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Question
Medium Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 7
यदि \(m=3^3\times5\times7\), तो (m) का मान क्या है?
If \(m=3^3\times5\times7\), what is the value of (m)?
#evaluate-factorisation
#powers
#medium
A 945
B 315
C 1890
D 735
Explanation opens after your attempt
Step 1
Concept
\(3^3=27\).
Step 2
Why this answer is correct
\(27\times5\times7=945\).
Step 3
Exam Tip
It is better to simplify the power part first. चरण 1: \(3^3=27\) है। चरण 2: \(27\times5\times7=945\)। चरण 3: घात वाले भाग को पहले सरल करना ठीक रहता है।
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Question
Medium Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 7
यदि \(n=2^5\times3\times7\), तो (n) का मान क्या है?
If \(n=2^5\times3\times7\), what is the value of (n)?
#evaluate-factorisation
#powers
#medium
A 672
B 336
C 1008
D 504
Explanation opens after your attempt
Step 1
Concept
\(2^5=32\).
Step 2
Why this answer is correct
\(32\times3\times7=672\).
Step 3
Exam Tip
Multiply all factors to convert prime factorisation into the number. चरण 1: \(2^5=32\) है। चरण 2: \(32\times3\times7=672\)। चरण 3: अभाज्य गुणनखंडन को संख्या में बदलने के लिए सभी गुणनखंडों का गुणा करें।
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Question
Medium Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 7
किस संख्या का अभाज्य गुणनखंडन \(2^2\times3^2\times5\times11\) है?
Which number has prime factorisation \(2^2\times3^2\times5\times11\)?
#evaluate-factorisation
#number-1980
#medium
A 1980
B 990
C 3960
D 1080
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^2=4\) and \(3^2=9\).
Step 2
Why this answer is correct
\(4\times9\times5\times11=1980\).
Step 3
Exam Tip
Simplifying powers first gives the answer quickly. चरण 1: \(2^2=4\) और \(3^2=9\) निकालें। चरण 2: \(4\times9\times5\times11=1980\)। चरण 3: घातों को पहले सरल करने से उत्तर जल्दी मिलता है।
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Question
Medium Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 7
किस संख्या का अभाज्य गुणनखंडन \(2^6\times3^3\) है?
Which number has prime factorisation \(2^6\times3^3\)?
#evaluate-factorisation
#number-1728
#medium
A 1728
B 864
C 3456
D 1296
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^6=64\) and \(3^3=27\).
Step 2
Why this answer is correct
\(64\times27=1728\).
Step 3
Exam Tip
Simplify higher powers separately first. चरण 1: \(2^6=64\) और \(3^3=27\) निकालें। चरण 2: \(64\times27=1728\)। चरण 3: बड़ी घातों को पहले अलग से सरल करें।
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Question
Medium Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 7
किस संख्या का अभाज्य गुणनखंडन \(2^2\times5\times7^2\) है?
Which number has prime factorisation \(2^2\times5\times7^2\)?
#evaluate-factorisation
#number-980
#medium
A 980
B 490
C 1960
D 700
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^2=4\) and \(7^2=49\).
Step 2
Why this answer is correct
\(4\times5\times49=980\).
Step 3
Exam Tip
Finding powers first reduces mistakes. चरण 1: \(2^2=4\) और \(7^2=49\) निकालें। चरण 2: \(4\times5\times49=980\)। चरण 3: घातों का मान पहले निकालने से गलती कम होती है।
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Question
Medium Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 7
किस संख्या का अभाज्य गुणनखंडन \(2^4\times3\times11\) है?
Which number has prime factorisation \(2^4\times3\times11\)?
#evaluate-factorisation
#number-528
#medium
A 528
B 264
C 1056
D 396
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^4=16\).
Step 2
Why this answer is correct
\(16\times3\times11=528\).
Step 3
Exam Tip
While multiplying, complete smaller products first. चरण 1: \(2^4=16\) निकालें। चरण 2: \(16\times3\times11=528\)। चरण 3: गुणन करते समय पहले छोटे गुणन को पूरा करें।
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Question
Medium Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 7
किस संख्या का अभाज्य गुणनखंडन \(2^3\times3^2\times7\) है?
Which number has prime factorisation \(2^3\times3^2\times7\)?
#evaluate-factorisation
#number-504
#medium
A 504
B 252
C 1008
D 756
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^3=8\) and \(3^2=9\).
Step 2
Why this answer is correct
\(8\times9\times7=504\).
Step 3
Exam Tip
Evaluate prime powers first, then multiply. चरण 1: \(2^3=8\) और \(3^2=9\) निकालें। चरण 2: \(8\times9\times7=504\)। चरण 3: अभाज्य घातों का मान पहले निकालें, फिर गुणा करें।
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Question
Easy Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 9
यदि किसी संख्या का अभाज्य गुणनखंडन \(2^4\times3^4\) है, तो वह संख्या कौन सी है?
If the prime factorisation of a number is \(2^4\times3^4\), which number is it?
#evaluate-factorisation
#number-1296
#easy
A 1296
B 648
C 2592
D 1728
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^4=16\) and \(3^4=81\).
Step 2
Why this answer is correct
\(16\times81=1296\).
Step 3
Exam Tip
Evaluate prime powers and then multiply. चरण 1: \(2^4=16\) और \(3^4=81\) निकालें। चरण 2: \(16\times81=1296\)। चरण 3: अभाज्य घातों का मान निकालकर गुणा करें।
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Question
Easy Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 9
किस संख्या का अभाज्य गुणनखंडन \(2^3\times3^2\times5^2\) है?
Which number has prime factorisation \(2^3\times3^2\times5^2\)?
#evaluate-factorisation
#number-1800
#easy
A 1800
B 900
C 3600
D 1200
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^3=8\), \(3^2=9\), and \(5^2=25\).
Step 2
Why this answer is correct
\(8\times9\times25=1800\).
Step 3
Exam Tip
Simplify powers first, then multiply. चरण 1: \(2^3=8\), \(3^2=9\) और \(5^2=25\) निकालें। चरण 2: \(8\times9\times25=1800\)। चरण 3: घातों को पहले सरल करें, फिर गुणा करें।
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Question
Easy Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 9
किस संख्या का अभाज्य गुणनखंडन \(2\times3\times5\times7\times11\) है?
Which number has prime factorisation \(2\times3\times5\times7\times11\)?
#evaluate-factorisation
#number-2310
#easy
A 2310
B 1155
C 4620
D 3300
Explanation opens after your attempt
Step 1
Concept
Multiply all given prime factors.
Step 2
Why this answer is correct
\(2\times3\times5\times7\times11=2310\).
Step 3
Exam Tip
When no power is written, each prime is taken once. चरण 1: दिए गए सभी अभाज्य गुणनखंडों को गुणा करें। चरण 2: \(2\times3\times5\times7\times11=2310\)। चरण 3: जब घात न हो तो प्रत्येक अभाज्य एक बार लिया जाता है।
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Question
Easy Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 9
यदि किसी संख्या का अभाज्य गुणनखंडन \(5^2\times7^2\) है, तो वह संख्या कौन सी है?
If the prime factorisation of a number is \(5^2\times7^2\), which number is it?
#evaluate-factorisation
#number-1225
#easy
A 1225
B 875
C 2450
D 6125
Explanation opens after your attempt
Step 1
Concept
\(5^2=25\) and \(7^2=49\).
Step 2
Why this answer is correct
\(25\times49=1225\).
Step 3
Exam Tip
Both powers are 2 in this square form, so multiply carefully. चरण 1: \(5^2=25\) और \(7^2=49\) हैं। चरण 2: \(25\times49=1225\)। चरण 3: वर्ग रूप में दोनों घातें 2 हैं, इसलिए गुणा साफ करें।
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Question
Easy Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 9
यदि किसी संख्या का अभाज्य गुणनखंडन \(2^3\times3\times7^2\) है, तो वह संख्या कौन सी है?
If the prime factorisation of a number is \(2^3\times3\times7^2\), which number is it?
#evaluate-factorisation
#number-1176
#easy
A 1176
B 588
C 1470
D 2352
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^3=8\) and \(7^2=49\).
Step 2
Why this answer is correct
\(8\times3\times49=1176\).
Step 3
Exam Tip
Evaluating powers first makes calculation easier. चरण 1: \(2^3=8\) और \(7^2=49\) निकालें। चरण 2: \(8\times3\times49=1176\)। चरण 3: घातों का मान पहले निकालना गणना को आसान बनाता है।
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Question
Easy Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 9
यदि \(m=3^2\times5^2\), तो (m) का मान क्या है?
If \(m=3^2\times5^2\), what is the value of (m)?
#evaluate-factorisation
#powers
#easy
A 225
B 150
C 300
D 450
Explanation opens after your attempt
Step 1
Concept
\(3^2=9\) and \(5^2=25\).
Step 2
Why this answer is correct
\(9\times25=225\).
Step 3
Exam Tip
Simplify both powers first. चरण 1: \(3^2=9\) और \(5^2=25\) हैं। चरण 2: \(9\times25=225\)। चरण 3: दोनों घातों को पहले सरल करें।
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Question
Easy Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 9
यदि \(n=2^3\times3\times7\), तो (n) का मान क्या है?
If \(n=2^3\times3\times7\), what is the value of (n)?
#evaluate-factorisation
#powers
#easy
A 168
B 84
C 126
D 336
Explanation opens after your attempt
Step 1
Concept
\(2^3=8\).
Step 2
Why this answer is correct
\(8\times3\times7=168\).
Step 3
Exam Tip
Multiply to get the number from prime factorisation. चरण 1: \(2^3=8\) है। चरण 2: \(8\times3\times7=168\)। चरण 3: अभाज्य गुणनखंडन से संख्या पाने के लिए गुणा करें।
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Question
Easy Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 9
किस संख्या का अभाज्य गुणनखंडन \(2\times3^4\) है?
Which number has prime factorisation \(2\times3^4\)?
#evaluate-factorisation
#number-162
#easy
A 162
B 81
C 324
D 486
Explanation opens after your attempt
Step 1
Concept
Calculate \(3^4=81\).
Step 2
Why this answer is correct
\(2\times81=162\).
Step 3
Exam Tip
Simplify the factor with a power first. चरण 1: \(3^4=81\) निकालें। चरण 2: \(2\times81=162\)। चरण 3: घात वाले गुणनखंड को पहले सरल करें।
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