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4 results found for "cube-sum" in Class 10.

Question Expert Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 33

यदि \(4x^2-12x+5=0\) की जड़ें \(\alpha,\beta\) हैं, तो \(\alpha^3+\beta^3\) का सही मान क्या है?

If \(\alpha,\beta\) are the roots of \(4x^2-12x+5=0\), what is the correct value of \(\alpha^3+\beta^3\)?

Explanation opens after your attempt
Correct Answer

A. \(\frac{63}{4}\)

Step 1

Concept

Here \(\alpha+\beta=3\) and \(\alpha\beta=\frac{5}{4}\). Thus \(\alpha^3+\beta^3=27-\frac{45}{4}=\frac{63}{4}\).

Step 2

Why this answer is correct

The correct answer is A. \(\frac{63}{4}\). Here \(\alpha+\beta=3\) and \(\alpha\beta=\frac{5}{4}\). Thus \(\alpha^3+\beta^3=27-\frac{45}{4}=\frac{63}{4}\).

Step 3

Exam Tip

यहाँ \(\alpha+\beta=3\) और \(\alpha\beta=\frac{5}{4}\) है। \(\alpha^3+\beta^3=27-\frac{45}{4}=\frac{63}{4}\)।

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Question Expert Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 33

यदि \(4x^2-12x+5=0\) की जड़ें \(\alpha,\beta\) हैं, तो \(\alpha^3+\beta^3\) का मान क्या है?

If \(\alpha,\beta\) are the roots of \(4x^2-12x+5=0\), what is \(\alpha^3+\beta^3\)?

Explanation opens after your attempt
Correct Answer

A. \(\frac{81}{8}\)

Step 1

Concept

Here \(\alpha+\beta=3\) and \(\alpha\beta=\frac{5}{4}\). Using (\alpha-3+\beta-3=\(\alpha+\beta\)3-3\alpha\beta\(\alpha+\beta\)), we get \(\frac{63}{4}\), so none of the options is correct.

Step 2

Why this answer is correct

The correct answer is A. \(\frac{81}{8}\). Here \(\alpha+\beta=3\) and \(\alpha\beta=\frac{5}{4}\). Using (\alpha-3+\beta-3=\(\alpha+\beta\)3-3\alpha\beta\(\alpha+\beta\)), we get \(\frac{63}{4}\), so none of the options is correct.

Step 3

Exam Tip

यहाँ \(\alpha+\beta=3\) और \(\alpha\beta=\frac{5}{4}\) है। (\alpha-3+\beta-3=\(\alpha+\beta\)3-3\alpha\beta\(\alpha+\beta\)=\frac{63}{4}), इसलिए विकल्पों में कोई सही नहीं है।

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Question Expert Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 32

यदि \(3x^2-8x+4=0\) की जड़ें \(\alpha,\beta\) हैं, तो \(\alpha^3+\beta^3\) का मान क्या है?

If \(\alpha,\beta\) are the roots of \(3x^2-8x+4=0\), what is \(\alpha^3+\beta^3\)?

Explanation opens after your attempt
Correct Answer

B. \(\frac{224}{27}\)

Step 1

Concept

Here \(\alpha+\beta=\frac{8}{3}\) and \(\alpha\beta=\frac{4}{3}\). Using (\alpha-3+\beta-3=\(\alpha+\beta\)3-3\alpha\beta\(\alpha+\beta\)), we get \(\frac{224}{27}\).

Step 2

Why this answer is correct

The correct answer is B. \(\frac{224}{27}\). Here \(\alpha+\beta=\frac{8}{3}\) and \(\alpha\beta=\frac{4}{3}\). Using (\alpha-3+\beta-3=\(\alpha+\beta\)3-3\alpha\beta\(\alpha+\beta\)), we get \(\frac{224}{27}\).

Step 3

Exam Tip

यहाँ \(\alpha+\beta=\frac{8}{3}\) और \(\alpha\beta=\frac{4}{3}\) है। (\alpha-3+\beta-3=\(\alpha+\beta\)3-3\alpha\beta\(\alpha+\beta\)) से \(\frac{224}{27}\) मिलता है।

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Question Expert Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 31

यदि \(2x^2-5x+3=0\) की जड़ें \(\alpha,\beta\) हैं, तो \(\alpha^3+\beta^3\) का मान क्या है?

If \(\alpha,\beta\) are the roots of \(2x^2-5x+3=0\), what is \(\alpha^3+\beta^3\)?

Explanation opens after your attempt
Correct Answer

A. \(\frac{35}{8}\)

Step 1

Concept

Here \(\alpha+\beta=\frac{5}{2}\) and \(\alpha\beta=\frac{3}{2}\). Using (\alpha-3+\beta-3=\(\alpha+\beta\)3-3\alpha\beta\(\alpha+\beta\)), we get \(\frac{35}{8}\).

Step 2

Why this answer is correct

The correct answer is A. \(\frac{35}{8}\). Here \(\alpha+\beta=\frac{5}{2}\) and \(\alpha\beta=\frac{3}{2}\). Using (\alpha-3+\beta-3=\(\alpha+\beta\)3-3\alpha\beta\(\alpha+\beta\)), we get \(\frac{35}{8}\).

Step 3

Exam Tip

यहाँ \(\alpha+\beta=\frac{5}{2}\) और \(\alpha\beta=\frac{3}{2}\) है। (\alpha-3+\beta-3=\(\alpha+\beta\)3-3\alpha\beta\(\alpha+\beta\)) से \(\frac{35}{8}\) मिलता है।

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