In an arithmetic progression (S_{10}=310) and (S_{20}=1120). What is the sum from the (11)th term to the (20)th term?
Answer and explanation
Correct answer: (810)
The required sum is (S_{20}-S_{10}=1120-310=810). Exam tip: use the difference of cumulative sums for middle terms.
Frequently asked questions
What is the correct answer to this question?
(810)
Why is this the correct answer?
The required sum is (S_{20}-S_{10}=1120-310=810). Exam tip: use the difference of cumulative sums for middle terms.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Arithmetic Progressions (AP). Topic: Finding the sum of the first $n$ terms of an AP.
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