Concept-wise Practice

cube root MCQ Questions for Class 10

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Practice Questions

21 questions tagged with cube root.

\(\sqrt[3]{343a^{15}b^{12}}\) का सरल रूप क्या है?

What is the simplified form of \(\sqrt[3]{343a^{15}b^{12}}\)?

Explanation opens after your attempt
Correct Answer

A. \(7a^{5}b^{4}\)

Step 1

Concept

We have \(\sqrt[3]{343}=7\), \(\sqrt[3]{a^{15}}=a^{5}\), and \(\sqrt[3]{b^{12}}=b^{4}\). In exams, divide exponents by (3) under a cube root.

Step 2

Why this answer is correct

The correct answer is A. \(7a^{5}b^{4}\). We have \(\sqrt[3]{343}=7\), \(\sqrt[3]{a^{15}}=a^{5}\), and \(\sqrt[3]{b^{12}}=b^{4}\). In exams, divide exponents by (3) under a cube root.

Step 3

Exam Tip

\(\sqrt[3]{343}=7\), \(\sqrt[3]{a^{15}}=a^{5}\), और \(\sqrt[3]{b^{12}}=b^{4}\)। परीक्षा में घनमूल में घातों को (3) से भाग दें।

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\(\sqrt[3]{216a^{12}b^{9}}\) का सरल रूप क्या है?

What is the simplified form of \(\sqrt[3]{216a^{12}b^{9}}\)?

Explanation opens after your attempt
Correct Answer

A. \(6a^{4}b^{3}\)

Step 1

Concept

We have \(\sqrt[3]{216}=6\), \(\sqrt[3]{a^{12}}=a^{4}\), and \(\sqrt[3]{b^{9}}=b^{3}\). In exams, divide exponents by (3) under a cube root.

Step 2

Why this answer is correct

The correct answer is A. \(6a^{4}b^{3}\). We have \(\sqrt[3]{216}=6\), \(\sqrt[3]{a^{12}}=a^{4}\), and \(\sqrt[3]{b^{9}}=b^{3}\). In exams, divide exponents by (3) under a cube root.

Step 3

Exam Tip

\(\sqrt[3]{216}=6\), \(\sqrt[3]{a^{12}}=a^{4}\), और \(\sqrt[3]{b^{9}}=b^{3}\)। परीक्षा में घनमूल में घातों को (3) से भाग दें।

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\(\sqrt[3]{125a^{9}b^{6}}\) का सरल रूप क्या है?

What is the simplified form of \(\sqrt[3]{125a^{9}b^{6}}\)?

Explanation opens after your attempt
Correct Answer

A. \(5a^{3}b^{2}\)

Step 1

Concept

We have \(\sqrt[3]{125}=5\), \(\sqrt[3]{a^{9}}=a^{3}\), and \(\sqrt[3]{b^{6}}=b^{2}\). In exams, divide exponents by (3) under a cube root.

Step 2

Why this answer is correct

The correct answer is A. \(5a^{3}b^{2}\). We have \(\sqrt[3]{125}=5\), \(\sqrt[3]{a^{9}}=a^{3}\), and \(\sqrt[3]{b^{6}}=b^{2}\). In exams, divide exponents by (3) under a cube root.

Step 3

Exam Tip

\(\sqrt[3]{125}=5\), \(\sqrt[3]{a^{9}}=a^{3}\), और \(\sqrt[3]{b^{6}}=b^{2}\)। परीक्षा में घनमूल में घातों को (3) से भाग दें।

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\(\sqrt[3]{64x^{6}}\) का सरल रूप क्या है, जहाँ (x) वास्तविक है?

What is the simplified form of \(\sqrt[3]{64x^{6}}\), where (x) is real?

Explanation opens after your attempt
Correct Answer

A. \(4x^{2}\)

Step 1

Concept

Since \(\sqrt[3]{64}=4\) and \(\sqrt[3]{x^{6}}=x^{2}\), the answer is \(4x^{2}\). In exams, divide the exponent by (3) for cube roots.

Step 2

Why this answer is correct

The correct answer is A. \(4x^{2}\). Since \(\sqrt[3]{64}=4\) and \(\sqrt[3]{x^{6}}=x^{2}\), the answer is \(4x^{2}\). In exams, divide the exponent by (3) for cube roots.

Step 3

Exam Tip

\(\sqrt[3]{64}=4\) और \(\sqrt[3]{x^{6}}=x^{2}\), इसलिए उत्तर \(4x^{2}\) है। परीक्षा में घनमूल में घात को (3) से भाग दें।

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यदि \(z=\sqrt[3]{9}\) है तो \(z^3\) किस प्रकार की संख्या है?

If \(z=\sqrt[3]{9}\), what type of number is \(z^3\)?

Explanation opens after your attempt
Correct Answer

A. परिमेय संख्याRational number

Step 1

Concept

Cubing gives \(z^3=9\). Even if (z) is irrational, its cube here is rational.

Step 2

Why this answer is correct

The correct answer is A. परिमेय संख्या / Rational number. Cubing gives \(z^3=9\). Even if (z) is irrational, its cube here is rational.

Step 3

Exam Tip

घन करने पर \(z^3=9\) मिलता है। भले (z) अपरिमेय हो, उसका घन यहाँ परिमेय है।

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कौन सा विकल्प \(\sqrt[3]{216}+\sqrt[3]{125}\) का मान है?

Which option is the value of \(\sqrt[3]{216}+\sqrt[3]{125}\)?

Explanation opens after your attempt
Correct Answer

A. (11)

Step 1

Concept

\(\sqrt[3]{216}=6\) and \(\sqrt[3]{125}=5\). So the sum is (11).

Step 2

Why this answer is correct

The correct answer is A. (11). \(\sqrt[3]{216}=6\) and \(\sqrt[3]{125}=5\). So the sum is (11).

Step 3

Exam Tip

\(\sqrt[3]{216}=6\) और \(\sqrt[3]{125}=5\) है। इसलिए योग (11) है।

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कौन सा विकल्प \(\sqrt[3]{20}\) के बारे में सही है?

Which option is correct about \(\sqrt[3]{20}\)?

Explanation opens after your attempt
Correct Answer

A. यह अपरिमेय हैIt is irrational

Step 1

Concept

(20) is not a perfect cube so \(\sqrt[3]{20}\) is irrational. Identify perfect cubes in cube roots.

Step 2

Why this answer is correct

The correct answer is A. यह अपरिमेय है / It is irrational. (20) is not a perfect cube so \(\sqrt[3]{20}\) is irrational. Identify perfect cubes in cube roots.

Step 3

Exam Tip

(20) पूर्ण घन नहीं है इसलिए \(\sqrt[3]{20}\) अपरिमेय है। घनमूल में पूर्ण घन पहचानें।

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कौन सा विकल्प \(\sqrt[3]{343}\) की प्रकृति सही बताता है?

Which option correctly describes the nature of \(\sqrt[3]{343}\)?

Explanation opens after your attempt
Correct Answer

A. परिमेय संख्याRational number

Step 1

Concept

\(\sqrt[3]{343}=7\), which is rational. The cube root of a perfect cube is rational.

Step 2

Why this answer is correct

The correct answer is A. परिमेय संख्या / Rational number. \(\sqrt[3]{343}=7\), which is rational. The cube root of a perfect cube is rational.

Step 3

Exam Tip

\(\sqrt[3]{343}=7\) है जो परिमेय है। पूर्ण घन की घनमूल परिमेय होती है।

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कौन सा विकल्प \(\sqrt[3]{216}\) की प्रकृति सही बताता है?

Which option correctly describes the nature of \(\sqrt[3]{216}\)?

Explanation opens after your attempt
Correct Answer

A. परिमेय संख्याRational number

Step 1

Concept

\(\sqrt[3]{216}=6\), which is rational. The cube root of a perfect cube is rational.

Step 2

Why this answer is correct

The correct answer is A. परिमेय संख्या / Rational number. \(\sqrt[3]{216}=6\), which is rational. The cube root of a perfect cube is rational.

Step 3

Exam Tip

\(\sqrt[3]{216}=6\) है जो परिमेय है। पूर्ण घन की घनमूल परिमेय होती है।

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कौन सा विकल्प \(\sqrt[3]{12}\) के लिए सही है?

Which option is correct for \(\sqrt[3]{12}\)?

Explanation opens after your attempt
Correct Answer

A. यह अपरिमेय हैIt is irrational

Step 1

Concept

(12) is not a perfect cube so \(\sqrt[3]{12}\) is irrational. Check perfect cubes in cube roots.

Step 2

Why this answer is correct

The correct answer is A. यह अपरिमेय है / It is irrational. (12) is not a perfect cube so \(\sqrt[3]{12}\) is irrational. Check perfect cubes in cube roots.

Step 3

Exam Tip

(12) पूर्ण घन नहीं है इसलिए \(\sqrt[3]{12}\) अपरिमेय है। घनमूल में पूर्ण घन देखें।

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कौन सा विकल्प \(\sqrt[3]{125}\) की प्रकृति सही बताता है?

Which option correctly describes the nature of \(\sqrt[3]{125}\)?

Explanation opens after your attempt
Correct Answer

A. परिमेय संख्याRational number

Step 1

Concept

\(\sqrt[3]{125}=5\), which is rational. The cube root of a perfect cube is rational.

Step 2

Why this answer is correct

The correct answer is A. परिमेय संख्या / Rational number. \(\sqrt[3]{125}=5\), which is rational. The cube root of a perfect cube is rational.

Step 3

Exam Tip

\(\sqrt[3]{125}=5\) है जो परिमेय है। पूर्ण घन की घनमूल परिमेय होती है।

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कौन सा विकल्प \(\sqrt[3]{16}\) के लिए सही है?

Which option is correct for \(\sqrt[3]{16}\)?

Explanation opens after your attempt
Correct Answer

A. यह अपरिमेय हैIt is irrational

Step 1

Concept

(16) is not a perfect cube so its cube root is irrational. Identify perfect cubes in cube roots.

Step 2

Why this answer is correct

The correct answer is A. यह अपरिमेय है / It is irrational. (16) is not a perfect cube so its cube root is irrational. Identify perfect cubes in cube roots.

Step 3

Exam Tip

(16) पूर्ण घन नहीं है इसलिए इसकी घनमूल अपरिमेय है। घनमूल में पूर्ण घन पहचानें।

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कौन सा विकल्प \(\sqrt[3]{64}\) की प्रकृति सही बताता है?

Which option correctly describes the nature of \(\sqrt[3]{64}\)?

Explanation opens after your attempt
Correct Answer

A. परिमेय संख्याRational number

Step 1

Concept

\(\sqrt[3]{64}=4\), which is rational. The cube root of a perfect cube is rational.

Step 2

Why this answer is correct

The correct answer is A. परिमेय संख्या / Rational number. \(\sqrt[3]{64}=4\), which is rational. The cube root of a perfect cube is rational.

Step 3

Exam Tip

\(\sqrt[3]{64}=4\) है जो परिमेय है। पूर्ण घन की घनमूल परिमेय होती है।

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\(\sqrt[3]{9}\) के बारे में सही कथन कौन सा है?

Which statement is correct about \(\sqrt[3]{9}\)?

Explanation opens after your attempt
Correct Answer

A. यह अपरिमेय हैIt is irrational

Step 1

Concept

(9) is not a perfect cube so \(\sqrt[3]{9}\) is irrational. Identifying perfect cubes is important in cube roots.

Step 2

Why this answer is correct

The correct answer is A. यह अपरिमेय है / It is irrational. (9) is not a perfect cube so \(\sqrt[3]{9}\) is irrational. Identifying perfect cubes is important in cube roots.

Step 3

Exam Tip

(9) पूर्ण घन नहीं है इसलिए \(\sqrt[3]{9}\) अपरिमेय है। घनमूल में पूर्ण घन पहचानना जरूरी है।

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\(\sqrt[3]{27}\) किस प्रकार की संख्या है?

What type of number is \(\sqrt[3]{27}\)?

Explanation opens after your attempt
Correct Answer

A. परिमेय संख्याRational number

Step 1

Concept

\(\sqrt[3]{27}=3\). The cube root of a perfect cube is rational.

Step 2

Why this answer is correct

The correct answer is A. परिमेय संख्या / Rational number. \(\sqrt[3]{27}=3\). The cube root of a perfect cube is rational.

Step 3

Exam Tip

\(\sqrt[3]{27}=3\) है। पूर्ण घन की घनमूल परिमेय होती है।

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\(\sqrt[3]{4}\) के बारे में कौन सा कथन सही है?

Which statement is correct about \(\sqrt[3]{4}\)?

Explanation opens after your attempt
Correct Answer

A. यह अपरिमेय हैIt is irrational

Step 1

Concept

(4) is not a perfect cube so \(\sqrt[3]{4}\) is irrational. Identify perfect cubes in cube roots.

Step 2

Why this answer is correct

The correct answer is A. यह अपरिमेय है / It is irrational. (4) is not a perfect cube so \(\sqrt[3]{4}\) is irrational. Identify perfect cubes in cube roots.

Step 3

Exam Tip

(4) पूर्ण घन नहीं है इसलिए \(\sqrt[3]{4}\) अपरिमेय है। घनमूल में पूर्ण घन पहचानें।

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\(\sqrt[3]{8}\) किस प्रकार की संख्या है?

What type of number is \(\sqrt[3]{8}\)?

Explanation opens after your attempt
Correct Answer

A. परिमेय संख्याRational number

Step 1

Concept

\(\sqrt[3]{8}=2\), which is rational. The cube root of a perfect cube is rational.

Step 2

Why this answer is correct

The correct answer is A. परिमेय संख्या / Rational number. \(\sqrt[3]{8}=2\), which is rational. The cube root of a perfect cube is rational.

Step 3

Exam Tip

\(\sqrt[3]{8}=2\) है जो परिमेय है। पूर्ण घन की घनमूल परिमेय होती है।

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\(2^9 \times 3^3\) का घनमूल क्या होगा?

What is the cube root of \(2^9 \times 3^3\)?

Explanation opens after your attempt
Correct Answer

B. \(2^3 \times 3\)

Step 1

Concept

In a cube root, divide prime exponents by (3).

Step 2

Why this answer is correct

\(2^9\) becomes \(2^3\), and \(3^3\) becomes (3).

Step 3

Exam Tip

In cube roots, bases stay the same and only exponents change. चरण 1: घनमूल में अभाज्य घातों को (3) से भाग देते हैं। चरण 2: \(2^9\) से \(2^3\) और \(3^3\) से (3) मिलेगा। चरण 3: घनमूल में आधार वही रहता है, केवल घात बदलती है।

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\(2^6 \times 3^3\) का घनमूल क्या होगा?

What is the cube root of \(2^6 \times 3^3\)?

Explanation opens after your attempt
Correct Answer

A. \(2^2 \times 3\)

Step 1

Concept

In a cube root, divide prime exponents by (3).

Step 2

Why this answer is correct

\(2^6\) becomes \(2^2\) and \(3^3\) becomes (3).

Step 3

Exam Tip

In cube roots, bases remain the same and only exponents change. चरण 1: घनमूल में अभाज्य घातों को (3) से भाग देते हैं। चरण 2: \(2^6\) से \(2^2\) और \(3^3\) से (3) मिलेगा। चरण 3: घनमूल में आधार वही रहता है, केवल घात बदलती है।

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यदि \(N=2^6 \times 5^3\) है, तो (N) का घनमूल किसके बराबर होगा?

If \(N=2^6 \times 5^3\), what is \(\sqrt[3]{N}\) equal to?

Explanation opens after your attempt
Correct Answer

A. \(2^2 \times 5\)

Step 1

Concept

In a cube root, divide each prime exponent by (3).

Step 2

Why this answer is correct

\(2^6\) becomes \(2^2\) and \(5^3\) becomes (5).

Step 3

Exam Tip

The cube root is an integer only when all exponents are multiples of (3). चरण 1: घनमूल में हर अभाज्य घात को (3) से भाग देते हैं। चरण 2: \(2^6\) से \(2^2\) और \(5^3\) से (5) मिलेगा। चरण 3: घनमूल तभी पूर्ण संख्या होगा जब सभी घातें (3) की गुणज हों।

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यदि किसी संख्या का अभाज्य गुणनखंड रूप \(2^9\times3^6\times7^3\) है, तो उसका घनमूल क्या होगा?

If a number has prime factorisation \(2^9\times3^6\times7^3\), what is its cube root?

Explanation opens after your attempt
Correct Answer

A. \(2^3\times3^2\times7\)

Step 1

Concept

For cube root, divide each prime exponent by (3).

Step 2

Why this answer is correct

\(9\div3=3\), \(6\div3=2\), and \(3\div3=1\), so the cube root is \(2^3\times3^2\times7\).

Step 3

Exam Tip

In a perfect cube, all exponents are multiples of (3). चरण 1: घनमूल लेते समय हर अभाज्य घात को (3) से भाग देते हैं। चरण 2: \(9\div3=3\), \(6\div3=2\), और \(3\div3=1\), इसलिए घनमूल \(2^3\times3^2\times7\) है। चरण 3: पूर्ण घन में सभी घातें (3) की गुणज होती हैं।

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