Which of the following types of number is \(\sqrt[3]{8}\)?
Answer and explanation
Correct answer: Rational number
\(\sqrt[3]{8}=2\). Since 8 is a perfect cube, its cube root is an integer (2), and every integer is rational (for example \(2=\frac{2}{1}\)). Thus option A is correct. Option B is incorrect because irrational numbers are non‑terminating, non‑repeating decimals, which does not apply to 2. Option C is wrong because 2 is a real number (not a non‑real/complex‑only number). Option D is incorrect because 2 is a terminating decimal (2.0), not a non‑terminating decimal. Exam tip: first check if the radicand is a perfect power; a perfect cube gives an integer cube root which is rational.
Frequently asked questions
What is the correct answer to this question?
Rational number
Why is this the correct answer?
\(\sqrt[3]{8}=2\). Since 8 is a perfect cube, its cube root is an integer (2), and every integer is rational (for example \(2=\frac{2}{1}\)). Thus option A is correct. Option B is incorrect because irrational numbers are non‑terminating, non‑repeating decimals, which does not apply to 2. Option C is wrong because 2 is a real number (not a non‑real/complex‑only number). Option D is incorrect because 2 is a terminating decimal (2.0), not a non‑terminating decimal. Exam tip: first check if the radicand is a perfect power; a perfect cube gives an integer cube root which is rational.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Polynomials. Topic: Irrational numbers and real numbers.
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