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What is the simplified form of (\sqrt[3]{64x^{6}}), where (x) is real?(\sqrt[3]{64x^{6}}) का सरल रूप क्या है, जहाँ (x) वास्तविक है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (4x^{2})(4x^{2})
Since (\sqrt[3]{64}=4) and (\sqrt[3]{x^{6}}=x^{2}), the answer is (4x^{2}). In exams, divide the exponent by (3) for cube roots.(\sqrt[3]{64}=4) और (\sqrt[3]{x^{6}}=x^{2}), इसलिए उत्तर (4x^{2}) है। परीक्षा में घनमूल में घात को (3) से भाग दें।
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