Class 11 Mathematics Medium Quiz

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यदि \(A=\{1,2,3,4\}\) और \(B=\{a,b,c\}\) हों, तो संबंध \(R=\{(1,a),(2,b),(3,c),(4,a)\}\) के बारे में सही कथन क्या है?

If \(A=\{1,2,3,4\}\) and \(B=\{a,b,c\}\), what is the correct statement about the relation \(R=\{(1,a),(2,b),(3,c),(4,a)\}\)?

Explanation opens after your attempt
Correct Answer

A. यह (A) से (B) में फलन हैIt is a function from (A) to (B)

Step 1

Concept

Each element of domain (A) has exactly one image. In exams, repetition of the same image does not make a function invalid.

Step 2

Why this answer is correct

The correct answer is A. यह (A) से (B) में फलन है / It is a function from (A) to (B). Each element of domain (A) has exactly one image. In exams, repetition of the same image does not make a function invalid.

Step 3

Exam Tip

प्रांत (A) के प्रत्येक तत्व की ठीक एक छवि है। परीक्षा में समान छवि दोहरना फलन को गलत नहीं करता।

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यदि \(A=\{1,2,3,4\}\), \(B=\{p,q\}\) और \(R=\{(1,p),(2,q),(4,p)\}\) हो, तो (R) फलन क्यों नहीं है?

If \(A=\{1,2,3,4\}\), \(B=\{p,q\}\), and \(R=\{(1,p),(2,q),(4,p)\}\), why is (R) not a function?

Explanation opens after your attempt
Correct Answer

A. क्योंकि (3) की कोई छवि नहीं हैBecause (3) has no image

Step 1

Concept

In a function every domain element must have exactly one image but (3) is missing. In exams, compare first components with the whole domain.

Step 2

Why this answer is correct

The correct answer is A. क्योंकि (3) की कोई छवि नहीं है / Because (3) has no image. In a function every domain element must have exactly one image but (3) is missing. In exams, compare first components with the whole domain.

Step 3

Exam Tip

फलन में प्रांत के हर तत्व की ठीक एक छवि होनी चाहिए पर (3) छूट गया है। परीक्षा में पहले घटकों को पूरे प्रांत से मिलाएं।

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यदि \(A=\{1,2,3\}\), \(B=\{5,6,7\}\) और \(R=\{(1,5),(2,6),(2,7),(3,5)\}\) हो, तो फलन की शर्त कौन तोड़ता है?

If \(A=\{1,2,3\}\), \(B=\{5,6,7\}\), and \(R=\{(1,5),(2,6),(2,7),(3,5)\}\), which element breaks the function condition?

Explanation opens after your attempt
Correct Answer

B. (2)

Step 1

Concept

(2) has two different images (6) and (7). In exams, immediately check different images of the same first component.

Step 2

Why this answer is correct

The correct answer is B. (2). (2) has two different images (6) and (7). In exams, immediately check different images of the same first component.

Step 3

Exam Tip

(2) की दो अलग छवियां (6) और (7) हैं। परीक्षा में एक ही पहले घटक की अलग छवियां तुरंत जांचें।

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यदि \(A=\{r,s,t\}\) और \(B=\{0,1,2,3\}\) हों, तो (A) से (B) में कुल फलनों की संख्या क्या है?

If \(A=\{r,s,t\}\) and \(B=\{0,1,2,3\}\), what is the total number of functions from (A) to (B)?

Explanation opens after your attempt
Correct Answer

B. \(4^3=64\)

Step 1

Concept

Each domain element has (4) choices in (B), so total functions are \(4^3=64\). In exams, use (n(B)^{n(A)}).

Step 2

Why this answer is correct

The correct answer is B. \(4^3=64\). Each domain element has (4) choices in (B), so total functions are \(4^3=64\). In exams, use (n(B)^{n(A)}).

Step 3

Exam Tip

हर प्रांत तत्व के लिए (B) की (4) पसंद हैं इसलिए कुल \(4^3=64\) फलन हैं। परीक्षा में सूत्र (n(B)^{n(A)}) लगाएं।

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यदि \(A=\{1,2,3,4\}\) और \(B=\{x,y,z\}\) हों, तो (A) से (B) में स्थिर फलनों की संख्या कितनी होगी?

If \(A=\{1,2,3,4\}\) and \(B=\{x,y,z\}\), how many constant functions are there from (A) to (B)?

Explanation opens after your attempt
Correct Answer

A. (3)

Step 1

Concept

In a constant function all domain elements map to one chosen element of (B). Therefore the number of constant functions is (3).

Step 2

Why this answer is correct

The correct answer is A. (3). In a constant function all domain elements map to one chosen element of (B). Therefore the number of constant functions is (3).

Step 3

Exam Tip

स्थिर फलन में सभी प्रांत तत्व (B) के एक ही चुने हुए तत्व पर जाते हैं। इसलिए स्थिर फलनों की संख्या (3) है।

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यदि \(A=\{1,2,3\}\) और \(B=\{a,b,c,d\}\) हों, तो (A) से (B) में कुल संबंधों की संख्या कितनी है?

If \(A=\{1,2,3\}\) and \(B=\{a,b,c,d\}\), how many relations are there from (A) to (B)?

Explanation opens after your attempt
Correct Answer

A. \(2^{12}=4096\)

Step 1

Concept

\(A\times B\) has \(3\times 4=12\) pairs, so relations are \(2^{12}=4096\). In exams, relations are counted as subsets.

Step 2

Why this answer is correct

The correct answer is A. \(2^{12}=4096\). \(A\times B\) has \(3\times 4=12\) pairs, so relations are \(2^{12}=4096\). In exams, relations are counted as subsets.

Step 3

Exam Tip

\(A\times B\) में \(3\times 4=12\) युग्म हैं इसलिए संबंध \(2^{12}=4096\) होंगे। परीक्षा में संबंध उपसमुच्चयों से गिने जाते हैं।

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यदि \(f:{0,1,2,3}\to{3,4,5,6}\) को (f(x)=x+3) से परिभाषित किया गया है, तो (f) का परिसर क्या है?

If \(f:{0,1,2,3}\to{3,4,5,6}\) is defined by (f(x)=x+3), what is the range of (f)?

Explanation opens after your attempt
Correct Answer

B. ({3,4,5,6})

Step 1

Concept

Putting (x=0,1,2,3) gives images (3,4,5,6). In exams, substitute all domain values to find the range.

Step 2

Why this answer is correct

The correct answer is B. ({3,4,5,6}). Putting (x=0,1,2,3) gives images (3,4,5,6). In exams, substitute all domain values to find the range.

Step 3

Exam Tip

(x=0,1,2,3) रखने पर छवियां (3,4,5,6) मिलती हैं। परीक्षा में परिसर निकालने के लिए सभी प्रांत मान रखें।

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यदि \(f=\{(2,1),(4,2),(6,3),(8,4)\}\) हो, तो (f) का प्रांत क्या है?

If \(f=\{(2,1),(4,2),(6,3),(8,4)\}\), what is the domain of (f)?

Explanation opens after your attempt
Correct Answer

B. ({2,4,6,8})

Step 1

Concept

The domain is the set of first components of ordered pairs. Therefore the domain is ({2,4,6,8}).

Step 2

Why this answer is correct

The correct answer is B. ({2,4,6,8}). The domain is the set of first components of ordered pairs. Therefore the domain is ({2,4,6,8}).

Step 3

Exam Tip

प्रांत क्रमित युग्मों के पहले घटकों का समुच्चय है। इसलिए प्रांत ({2,4,6,8}) है।

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यदि \(f=\{(1,4),(2,4),(3,5),(4,6)\}\) हो, तो (f) का परिसर क्या है?

If \(f=\{(1,4),(2,4),(3,5),(4,6)\}\), what is the range of (f)?

Explanation opens after your attempt
Correct Answer

C. ({4,5,6})

Step 1

Concept

The range is the set of distinct obtained second components. So writing (4) once gives ({4,5,6}).

Step 2

Why this answer is correct

The correct answer is C. ({4,5,6}). The range is the set of distinct obtained second components. So writing (4) once gives ({4,5,6}).

Step 3

Exam Tip

परिसर अलग-अलग प्राप्त दूसरे घटकों का समुच्चय है। इसलिए (4) को एक बार लिखकर ({4,5,6}) मिलेगा।

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यदि \(A=\{1,2,3,4\}\), \(B=\{0,1\}\) और \(R=\{(1,0),(2,1),(4,0)\}\) हो, तो (R) को फलन बनाने के लिए कौन-सा युग्म जोड़ा जा सकता है?

If \(A=\{1,2,3,4\}\), \(B=\{0,1\}\), and \(R=\{(1,0),(2,1),(4,0)\}\), which pair can be added to make (R) a function?

Explanation opens after your attempt
Correct Answer

A. ((3,1))

Step 1

Concept

Only the image of (3) is missing, so adding ((3,1)) is correct. In exams, first identify the missing domain element.

Step 2

Why this answer is correct

The correct answer is A. ((3,1)). Only the image of (3) is missing, so adding ((3,1)) is correct. In exams, first identify the missing domain element.

Step 3

Exam Tip

केवल (3) की छवि गायब है इसलिए ((3,1)) जोड़ना सही है। परीक्षा में छूटे प्रांत तत्व को पहले पहचानें।

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यदि \(R=\{(1,a),(2,b),(2,c),(3,a)\}\) है, तो इसे फलन बनाने के लिए कौन-सा युग्म हटाना पर्याप्त होगा?

If \(R=\{(1,a),(2,b),(2,c),(3,a)\}\), which pair is sufficient to remove to make it a function?

Explanation opens after your attempt
Correct Answer

A. ((2,c))

Step 1

Concept

(2) has two images and after removing ((2,c)) every first component has exactly one image. In exams, remove one pair from the repeated first component.

Step 2

Why this answer is correct

The correct answer is A. ((2,c)). (2) has two images and after removing ((2,c)) every first component has exactly one image. In exams, remove one pair from the repeated first component.

Step 3

Exam Tip

(2) की दो छवियां हैं और ((2,c)) हटाने पर हर पहले घटक की ठीक एक छवि रह जाएगी। परीक्षा में दोहराए पहले घटक से एक युग्म हटाएं।

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यदि \(f=\{(1,3),(2,5),(3,7)\}\) हो, तो उल्टा संबंध ({(3,1),(5,2),(7,3)}) किस कारण फलन है?

If \(f=\{(1,3),(2,5),(3,7)\}\), why is the reversed relation ({(3,1),(5,2),(7,3)}) a function?

Explanation opens after your attempt
Correct Answer

A. हर पहले घटक की ठीक एक छवि हैEvery first component has exactly one image

Step 1

Concept

In the reversed relation, each of (3,5,7) has exactly one image. In exams, test the reversed relation separately by the function condition.

Step 2

Why this answer is correct

The correct answer is A. हर पहले घटक की ठीक एक छवि है / Every first component has exactly one image. In the reversed relation, each of (3,5,7) has exactly one image. In exams, test the reversed relation separately by the function condition.

Step 3

Exam Tip

उल्टे संबंध में (3,5,7) में से प्रत्येक की ठीक एक छवि है। परीक्षा में उल्टा संबंध भी फलन शर्त से अलग जांचें।

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यदि \(f=\{(1,p),(2,p),(3,q)\}\) हो, तो उल्टा संबंध ({(p,1),(p,2),(q,3)}) फलन क्यों नहीं है?

If \(f=\{(1,p),(2,p),(3,q)\}\), why is the reversed relation ({(p,1),(p,2),(q,3)}) not a function?

Explanation opens after your attempt
Correct Answer

A. क्योंकि (p) की दो छवियां (1) और (2) हैंBecause (p) has two images (1) and (2)

Step 1

Concept

In the reversed relation, (p) as a first component is linked to two different images. In exams, watch repeated second components while reversing.

Step 2

Why this answer is correct

The correct answer is A. क्योंकि (p) की दो छवियां (1) और (2) हैं / Because (p) has two images (1) and (2). In the reversed relation, (p) as a first component is linked to two different images. In exams, watch repeated second components while reversing.

Step 3

Exam Tip

उल्टे संबंध में (p) पहले घटक के रूप में दो अलग छवियों से जुड़ा है। परीक्षा में उल्टा करते समय दोहराए दूसरे घटक पर ध्यान दें।

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यदि \(f:\mathbb{R}\to\mathbb{R}\) को (f(x)=\sqrt{x-1}) से परिभाषित करने की कोशिश की जाए, तो यह पूरे \(\mathbb{R}\) पर फलन क्यों नहीं है?

If one tries to define \(f:\mathbb{R}\to\mathbb{R}\) by (f(x)=\sqrt{x-1}), why is it not a function on all of \(\mathbb{R}\)?

Explanation opens after your attempt
Correct Answer

A. क्योंकि (x<1) पर \(\sqrt{x-1}\) वास्तविक नहीं हैBecause \(\sqrt{x-1}\) is not real for (x<1)

Step 1

Concept

The domain is \(\mathbb{R}\), but no real image is obtained for (x<1). In exams, check that the expression inside a square root is not negative.

Step 2

Why this answer is correct

The correct answer is A. क्योंकि (x<1) पर \(\sqrt{x-1}\) वास्तविक नहीं है / Because \(\sqrt{x-1}\) is not real for (x<1). The domain is \(\mathbb{R}\), but no real image is obtained for (x<1). In exams, check that the expression inside a square root is not negative.

Step 3

Exam Tip

प्रांत \(\mathbb{R}\) है पर (x<1) के लिए वास्तविक छवि नहीं मिलती। परीक्षा में वर्गमूल के अंदर का मान ऋणात्मक न हो यह जांचें।

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यदि \(f:\mathbb{R}\to\mathbb{R}\) को (f(x)=\frac{1}{x+3}) से परिभाषित किया जाए, तो यह पूरे \(\mathbb{R}\) पर फलन क्यों नहीं है?

If \(f:\mathbb{R}\to\mathbb{R}\) is defined by (f(x)=\frac{1}{x+3}), why is it not a function on all of \(\mathbb{R}\)?

Explanation opens after your attempt
Correct Answer

A. क्योंकि (x=-3) पर हर (0) हो जाता हैBecause the denominator becomes (0) at (x=-3)

Step 1

Concept

(x=-3) is in the domain but (f(-3)) is not defined. In exams, find values that make the denominator (0).

Step 2

Why this answer is correct

The correct answer is A. क्योंकि (x=-3) पर हर (0) हो जाता है / Because the denominator becomes (0) at (x=-3). (x=-3) is in the domain but (f(-3)) is not defined. In exams, find values that make the denominator (0).

Step 3

Exam Tip

(x=-3) प्रांत में है पर (f(-3)) परिभाषित नहीं है। परीक्षा में भिन्न में हर को (0) बनाने वाले मान खोजें।

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यदि \(f:\mathbb{R}\setminus{-3}\to\mathbb{R}\) और (f(x)=\frac{1}{x+3}) हो, तो यह फलन क्यों है?

If \(f:\mathbb{R}\setminus{-3}\to\mathbb{R}\) and (f(x)=\frac{1}{x+3}), why is it a function?

Explanation opens after your attempt
Correct Answer

A. क्योंकि (x=-3) को प्रांत से हटा दिया गया हैBecause (x=-3) is removed from the domain

Step 1

Concept

Now \(\frac{1}{x+3}\) is defined for every domain element and gives one value. In exams, changing the domain can make a rule valid.

Step 2

Why this answer is correct

The correct answer is A. क्योंकि (x=-3) को प्रांत से हटा दिया गया है / Because (x=-3) is removed from the domain. Now \(\frac{1}{x+3}\) is defined for every domain element and gives one value. In exams, changing the domain can make a rule valid.

Step 3

Exam Tip

अब हर प्रांत तत्व के लिए \(\frac{1}{x+3}\) परिभाषित है और एक ही मान देता है। परीक्षा में प्रांत बदलने से नियम वैध हो सकता है।

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यदि \(h:{1,2,3,4,5}\to{0,1}\) को (h(x)=0) जब (x<3) और (h(x)=1) जब \(x\ge 3\) से परिभाषित किया गया है, तो (h(3)) क्या है?

If \(h:{1,2,3,4,5}\to{0,1}\) is defined by (h(x)=0) when (x<3) and (h(x)=1) when \(x\ge 3\), what is (h(3))?

Explanation opens after your attempt
Correct Answer

B. (1)

Step 1

Concept

Because \(3\ge 3\), (h(3)=1). In exams, check which condition contains the boundary value.

Step 2

Why this answer is correct

The correct answer is B. (1). Because \(3\ge 3\), (h(3)=1). In exams, check which condition contains the boundary value.

Step 3

Exam Tip

क्योंकि \(3\ge 3\), इसलिए (h(3)=1) होगा। परीक्षा में सीमा मान किस शर्त में आता है यह देखें।

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यदि \(A=\{2,3,4,5\}\), \(B=\{0,1,2\}\) और (f(x)) को (x) को (3) से भाग देने पर शेषफल माना जाए, तो (f) का परिसर क्या है?

If \(A=\{2,3,4,5\}\), \(B=\{0,1,2\}\), and (f(x)) is the remainder when (x) is divided by (3), what is the range of (f)?

Explanation opens after your attempt
Correct Answer

C. ({0,1,2})

Step 1

Concept

The remainders of (2,3,4,5) are (2,0,1,2), so the range is ({0,1,2}). In exams, write only distinct images.

Step 2

Why this answer is correct

The correct answer is C. ({0,1,2}). The remainders of (2,3,4,5) are (2,0,1,2), so the range is ({0,1,2}). In exams, write only distinct images.

Step 3

Exam Tip

(2,3,4,5) के शेषफल क्रमशः (2,0,1,2) हैं इसलिए परिसर ({0,1,2}) है। परीक्षा में केवल अलग-अलग छवियां लिखें।

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यदि \(R=\{(x,y):y=2x+1,\ x\in{0,1,2}\}\) हो, तो (R) के क्रमित युग्म कौन-से हैं?

If \(R=\{(x,y):y=2x+1,\ x\in{0,1,2}\}\), which are the ordered pairs of (R)?

Explanation opens after your attempt
Correct Answer

A. ({(0,1),(1,3),(2,5)})

Step 1

Concept

Putting (x=0,1,2) gives (y=1,3,5). In exams, convert set-builder form into ordered pairs.

Step 2

Why this answer is correct

The correct answer is A. ({(0,1),(1,3),(2,5)}). Putting (x=0,1,2) gives (y=1,3,5). In exams, convert set-builder form into ordered pairs.

Step 3

Exam Tip

(x=0,1,2) रखने पर (y=1,3,5) मिलता है। परीक्षा में सेट-बिल्डर रूप को युग्मों में बदलें।

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यदि \(f:{1,2,3}\to{1,2,3}\) को (f(x)=x+1) से परिभाषित किया जाए, तो यह (A) से (B) में फलन क्यों नहीं है?

If \(f:{1,2,3}\to{1,2,3}\) is defined by (f(x)=x+1), why is it not a function from (A) to (B)?

Explanation opens after your attempt
Correct Answer

A. क्योंकि (f(3)=4) और \(4\notin{1,2,3}\)Because (f(3)=4) and \(4\notin{1,2,3}\)

Step 1

Concept

The image of (3) is (4), which is not in the codomain. In exams, check whether every output lies in the codomain.

Step 2

Why this answer is correct

The correct answer is A. क्योंकि (f(3)=4) और \(4\notin{1,2,3}\) / Because (f(3)=4) and \(4\notin{1,2,3}\). The image of (3) is (4), which is not in the codomain. In exams, check whether every output lies in the codomain.

Step 3

Exam Tip

(3) की छवि (4) आती है जो सहप्रांत में नहीं है। परीक्षा में हर आउटपुट सहप्रांत में है या नहीं जांचें।

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यदि \(A=\{1,2,3\}\) और नियम (f(x)=x-2+1) है, तो (f) को (A) से किस सहप्रांत में फलन माना जा सकता है?

If \(A=\{1,2,3\}\) and the rule is (f(x)=x-2+1), to which codomain can (f) be considered a function from (A)?

Explanation opens after your attempt
Correct Answer

A. ({2,5,10})

Step 1

Concept

(f(1)=2), (f(2)=5), and (f(3)=10). In exams, the codomain must contain all possible images.

Step 2

Why this answer is correct

The correct answer is A. ({2,5,10}). (f(1)=2), (f(2)=5), and (f(3)=10). In exams, the codomain must contain all possible images.

Step 3

Exam Tip

(f(1)=2), (f(2)=5) और (f(3)=10) हैं। परीक्षा में सहप्रांत में सभी संभावित छवियां शामिल होनी चाहिए।

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यदि \(f:\mathbb{Z}\to\mathbb{Z}\) को (f(x)=x-2) से परिभाषित किया गया है, तो कौन-सा कथन सही है?

If \(f:\mathbb{Z}\to\mathbb{Z}\) is defined by (f(x)=x-2), which statement is correct?

Explanation opens after your attempt
Correct Answer

A. यह फलन है क्योंकि हर \(x\in\mathbb{Z}\) की एक निश्चित छवि हैIt is a function because every \(x\in\mathbb{Z}\) has one definite image

Step 1

Concept

For every integer (x), \(x^2\) gives one definite integer. Having the same image does not break the function condition.

Step 2

Why this answer is correct

The correct answer is A. यह फलन है क्योंकि हर \(x\in\mathbb{Z}\) की एक निश्चित छवि है / It is a function because every \(x\in\mathbb{Z}\) has one definite image. For every integer (x), \(x^2\) gives one definite integer. Having the same image does not break the function condition.

Step 3

Exam Tip

हर पूर्णांक (x) के लिए \(x^2\) एक निश्चित पूर्णांक देता है। समान छवि आना फलन की शर्त नहीं तोड़ता।

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यदि \(f=\{(1,a),(2,a),(3,b),(4,b)\}\) हो, तो (f) किस प्रकार का सरल उदाहरण है?

If \(f=\{(1,a),(2,a),(3,b),(4,b)\}\), what simple type of example is (f)?

Explanation opens after your attempt
Correct Answer

A. अनेक-एक फलनMany-one function

Step 1

Concept

Two different elements have the same image, so it is a many-one type function. In exams, the same image is allowed.

Step 2

Why this answer is correct

The correct answer is A. अनेक-एक फलन / Many-one function. Two different elements have the same image, so it is a many-one type function. In exams, the same image is allowed.

Step 3

Exam Tip

दो अलग तत्वों की एक ही छवि आ रही है इसलिए यह अनेक-एक प्रकार का फलन है। परीक्षा में समान छवि स्वीकार्य होती है।

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यदि \(A=\{1,2,3\}\) और \(B=\{p,q,r\}\) हों, तो कौन-सा संबंध एक-एक फलन है?

If \(A=\{1,2,3\}\) and \(B=\{p,q,r\}\), which relation is a one-one function?

Explanation opens after your attempt
Correct Answer

A. ({(1,p),(2,q),(3,r)})

Step 1

Concept

In option (A), different domain elements have different images. In exams, images should not repeat for a one-one function.

Step 2

Why this answer is correct

The correct answer is A. ({(1,p),(2,q),(3,r)}). In option (A), different domain elements have different images. In exams, images should not repeat for a one-one function.

Step 3

Exam Tip

विकल्प (A) में अलग-अलग प्रांत तत्वों की छवियां भी अलग-अलग हैं। परीक्षा में एक-एक फलन के लिए छवियों की पुनरावृत्ति न हो।

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यदि \(f:{1,2,3}\to{7,8}\) को (f(x)=7) सभी (x) के लिए परिभाषित किया गया है, तो (f) का परिसर क्या है?

If \(f:{1,2,3}\to{7,8}\) is defined by (f(x)=7) for all (x), what is the range of (f)?

Explanation opens after your attempt
Correct Answer

A. ({7})

Step 1

Concept

Every domain element has image (7), so the range is ({7}). In exams, do not write an unattained codomain element in the range.

Step 2

Why this answer is correct

The correct answer is A. ({7}). Every domain element has image (7), so the range is ({7}). In exams, do not write an unattained codomain element in the range.

Step 3

Exam Tip

हर प्रांत तत्व की छवि (7) है इसलिए परिसर ({7}) है। परीक्षा में अप्राप्त सहप्रांत तत्व को परिसर में न लिखें।

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यदि (f(a)=b) है, तो (a) को (b) का क्या कहा जाता है?

If (f(a)=b), what is (a) called for (b)?

Explanation opens after your attempt
Correct Answer

A. पूर्वछविPreimage

Step 1

Concept

In (f(a)=b), (a) is the preimage and (b) is the image. In exams, do not reverse these two terms.

Step 2

Why this answer is correct

The correct answer is A. पूर्वछवि / Preimage. In (f(a)=b), (a) is the preimage and (b) is the image. In exams, do not reverse these two terms.

Step 3

Exam Tip

(f(a)=b) में (a) पूर्वछवि और (b) छवि है। परीक्षा में इन दोनों शब्दों को उल्टा न करें।

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यदि (f(5)=12) है, तो (12) को (5) का क्या कहा जाएगा?

If (f(5)=12), what will (12) be called for (5)?

Explanation opens after your attempt
Correct Answer

A. छविImage

Step 1

Concept

(f(5)=12) means (12) is the image of (5). In exams, (f(x)) represents the output.

Step 2

Why this answer is correct

The correct answer is A. छवि / Image. (f(5)=12) means (12) is the image of (5). In exams, (f(x)) represents the output.

Step 3

Exam Tip

(f(5)=12) का अर्थ है कि (12), (5) की छवि है। परीक्षा में (f(x)) आउटपुट को दर्शाता है।

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यदि \(A=\{1,2,3\}\), \(B=\{2,4,6,8\}\) और (f(x)=2x) हो, तो (8) के बारे में क्या सही है?

If \(A=\{1,2,3\}\), \(B=\{2,4,6,8\}\), and (f(x)=2x), what is true about (8)?

Explanation opens after your attempt
Correct Answer

A. (8) सहप्रांत में है पर परिसर में नहीं(8) is in the codomain but not in the range

Step 1

Concept

The images are (2,4,6), so (8) is not obtained. In exams, keep the difference between codomain and range clear.

Step 2

Why this answer is correct

The correct answer is A. (8) सहप्रांत में है पर परिसर में नहीं / (8) is in the codomain but not in the range. The images are (2,4,6), so (8) is not obtained. In exams, keep the difference between codomain and range clear.

Step 3

Exam Tip

छवियां (2,4,6) हैं इसलिए (8) प्राप्त नहीं होता। परीक्षा में सहप्रांत और परिसर का अंतर स्पष्ट रखें।

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यदि \(A=\{1,2,3,4\}\) और \(B=\{1,2\}\) हों, तो (A) से (B) में कोई फलन बनाते समय प्रत्येक प्रांत तत्व के लिए कितनी पसंद होती है?

If \(A=\{1,2,3,4\}\) and \(B=\{1,2\}\), how many choices are there for each domain element while forming a function from (A) to (B)?

Explanation opens after your attempt
Correct Answer

A. (2)

Step 1

Concept

Each domain element can map to one of the (2) elements of (B). In exams, multiply these choices to count total functions.

Step 2

Why this answer is correct

The correct answer is A. (2). Each domain element can map to one of the (2) elements of (B). In exams, multiply these choices to count total functions.

Step 3

Exam Tip

प्रत्येक प्रांत तत्व (B) के (2) तत्वों में से किसी एक पर जा सकता है। परीक्षा में कुल फलनों के लिए इन पसंदों को गुणा करें।

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यदि \(f:{1,2,3,4}\to{1,3,5,7}\) को (f(x)=2x-1) से परिभाषित किया गया है, तो (f(4)) क्या है?

If \(f:{1,2,3,4}\to{1,3,5,7}\) is defined by (f(x)=2x-1), what is (f(4))?

Explanation opens after your attempt
Correct Answer

C. (7)

Step 1

Concept

\(f(4)=2\times 4-1=7\). In exams, multiply first and then subtract.

Step 2

Why this answer is correct

The correct answer is C. (7). \(f(4)=2\times 4-1=7\). In exams, multiply first and then subtract.

Step 3

Exam Tip

\(f(4)=2\times 4-1=7\) है। परीक्षा में पहले गुणा करें और फिर घटाएं।

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यदि \(f:{0,1,2,3}\to{0,1,4,9}\) और (f(x)=x-2) है, तो कौन-सा क्रमित युग्म (f) में नहीं है?

If \(f:{0,1,2,3}\to{0,1,4,9}\) and (f(x)=x-2), which ordered pair is not in (f)?

Explanation opens after your attempt
Correct Answer

D. ((3,6))

Step 1

Concept

(f(3)=32=9), so ((3,6)) is an incorrect pair. In exams, check the pair by the given rule.

Step 2

Why this answer is correct

The correct answer is D. ((3,6)). (f(3)=32=9), so ((3,6)) is an incorrect pair. In exams, check the pair by the given rule.

Step 3

Exam Tip

(f(3)=32=9), इसलिए ((3,6)) गलत युग्म है। परीक्षा में युग्म को दिए गए नियम से जांचें।

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यदि \(f:{1,2,3}\to{1,8,27}\) को (f(x)=x-3) से परिभाषित किया गया है, तो (f) के क्रमित युग्म कौन-से हैं?

If \(f:{1,2,3}\to{1,8,27}\) is defined by (f(x)=x-3), which are the ordered pairs of (f)?

Explanation opens after your attempt
Correct Answer

A. ({(1,1),(2,8),(3,27)})

Step 1

Concept

\(1^3=1\), \(2^3=8\), and \(3^3=27\). In exams, the first component is the input and the second is the output.

Step 2

Why this answer is correct

The correct answer is A. ({(1,1),(2,8),(3,27)}). \(1^3=1\), \(2^3=8\), and \(3^3=27\). In exams, the first component is the input and the second is the output.

Step 3

Exam Tip

\(1^3=1\), \(2^3=8\) और \(3^3=27\) हैं। परीक्षा में पहला घटक इनपुट और दूसरा घटक आउटपुट होता है।

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यदि \(A=\{1,2,3\}\), \(B=\{2,3,4,5\}\) और (f(x)=x+1) हो, तो (5) के बारे में कौन-सा कथन सही है?

If \(A=\{1,2,3\}\), \(B=\{2,3,4,5\}\), and (f(x)=x+1), which statement about (5) is correct?

Explanation opens after your attempt
Correct Answer

A. (5) सहप्रांत में है पर परिसर में नहीं(5) is in the codomain but not in the range

Step 1

Concept

The range is ({2,3,4}), so (5) is not obtained. In exams, every element of the codomain need not be in the range.

Step 2

Why this answer is correct

The correct answer is A. (5) सहप्रांत में है पर परिसर में नहीं / (5) is in the codomain but not in the range. The range is ({2,3,4}), so (5) is not obtained. In exams, every element of the codomain need not be in the range.

Step 3

Exam Tip

परिसर ({2,3,4}) है इसलिए (5) प्राप्त नहीं होता। परीक्षा में सहप्रांत का हर तत्व परिसर में हो यह जरूरी नहीं है।

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यदि \(A=\{1,2,3,4\}\) और \(B=\{a,b,c,d\}\) हों, तो कौन-सा विकल्प फलन नहीं है क्योंकि (1) की दो छवियां हैं?

If \(A=\{1,2,3,4\}\) and \(B=\{a,b,c,d\}\), which option is not a function because (1) has two images?

Explanation opens after your attempt
Correct Answer

A. ({(1,a),(1,b),(2,c),(3,d),(4,a)})

Step 1

Concept

In option (A), (1) is associated with both (a) and (b). In exams, look for the same first component with two different second components.

Step 2

Why this answer is correct

The correct answer is A. ({(1,a),(1,b),(2,c),(3,d),(4,a)}). In option (A), (1) is associated with both (a) and (b). In exams, look for the same first component with two different second components.

Step 3

Exam Tip

विकल्प (A) में (1) को (a) और (b) दोनों से जोड़ा गया है। परीक्षा में समान पहले घटक के दो अलग दूसरे घटक खोजें।

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यदि \(A=\{1,2,3,4\}\) और \(B=\{a,b,c\}\) हों, तो कौन-सा विकल्प फलन नहीं है क्योंकि (4) की छवि नहीं है?

If \(A=\{1,2,3,4\}\) and \(B=\{a,b,c\}\), which option is not a function because (4) has no image?

Explanation opens after your attempt
Correct Answer

A. ({(1,a),(2,b),(3,c)})

Step 1

Concept

In option (A), there is no pair for (4). In exams, every domain element must be included for a function.

Step 2

Why this answer is correct

The correct answer is A. ({(1,a),(2,b),(3,c)}). In option (A), there is no pair for (4). In exams, every domain element must be included for a function.

Step 3

Exam Tip

विकल्प (A) में (4) के लिए कोई युग्म नहीं है। परीक्षा में फलन के लिए हर प्रांत तत्व शामिल होना चाहिए।

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यदि \(f:{1,2,3,4}\to{0,1}\) को (f(x)=1) जब (x) अभाज्य हो और (f(x)=0) जब (x) अभाज्य न हो से परिभाषित किया गया है, तो (f(4)) क्या है?

If \(f:{1,2,3,4}\to{0,1}\) is defined by (f(x)=1) when (x) is prime and (f(x)=0) when (x) is not prime, what is (f(4))?

Explanation opens after your attempt
Correct Answer

A. (0)

Step 1

Concept

(4) is not prime, so (f(4)=0). In exams, identify the condition in the rule first.

Step 2

Why this answer is correct

The correct answer is A. (0). (4) is not prime, so (f(4)=0). In exams, identify the condition in the rule first.

Step 3

Exam Tip

(4) अभाज्य नहीं है इसलिए (f(4)=0) है। परीक्षा में नियम की शर्त को पहले पहचानें।

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यदि \(f:{1,2,3,4}\to{0,1}\) को (f(x)=1) जब (x) अभाज्य हो और (f(x)=0) जब (x) अभाज्य न हो से परिभाषित किया गया है, तो (f) का परिसर क्या है?

If \(f:{1,2,3,4}\to{0,1}\) is defined by (f(x)=1) when (x) is prime and (f(x)=0) when (x) is not prime, what is the range of (f)?

Explanation opens after your attempt
Correct Answer

C. ({0,1})

Step 1

Concept

(2) and (3) give (1), while (1) and (4) give (0). In exams, write distinct obtained values in the range.

Step 2

Why this answer is correct

The correct answer is C. ({0,1}). (2) and (3) give (1), while (1) and (4) give (0). In exams, write distinct obtained values in the range.

Step 3

Exam Tip

(2) और (3) से (1) मिलता है तथा (1) और (4) से (0) मिलता है। परीक्षा में परिसर में प्राप्त अलग-अलग मान लिखें।

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फलन को संबंध का विशेष प्रकार क्यों माना जाता है?

Why is a function considered a special type of relation?

Explanation opens after your attempt
Correct Answer

A. क्योंकि प्रांत के हर तत्व की ठीक एक छवि होती हैBecause every domain element has exactly one image

Step 1

Concept

A function is a relation in which every domain element is associated with exactly one image. In exams, remember that every relation is not a function.

Step 2

Why this answer is correct

The correct answer is A. क्योंकि प्रांत के हर तत्व की ठीक एक छवि होती है / Because every domain element has exactly one image. A function is a relation in which every domain element is associated with exactly one image. In exams, remember that every relation is not a function.

Step 3

Exam Tip

फलन संबंध है पर इसमें प्रत्येक प्रांत तत्व ठीक एक छवि से जुड़ता है। परीक्षा में याद रखें कि हर संबंध फलन नहीं होता।

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यदि \(A=\{1,2\}\) और \(B=\{3,4,5\}\) हों, तो \(A\times B\) के किस उपसमुच्चय को (A) से (B) में फलन कहा जा सकता है?

If \(A=\{1,2\}\) and \(B=\{3,4,5\}\), which subset of \(A\times B\) can be called a function from (A) to (B)?

Explanation opens after your attempt
Correct Answer

A. ({(1,3),(2,5)})

Step 1

Concept

In option (A), both (1) and (2) have exactly one image. In exams, check the whole domain before calling a subset a function.

Step 2

Why this answer is correct

The correct answer is A. ({(1,3),(2,5)}). In option (A), both (1) and (2) have exactly one image. In exams, check the whole domain before calling a subset a function.

Step 3

Exam Tip

विकल्प (A) में (1) और (2) दोनों की ठीक एक छवि है। परीक्षा में उपसमुच्चय को फलन कहने से पहले पूरा प्रांत जांचें।

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यदि \(f:{1,2,3}\to{2,4,6,8}\) और (f(x)=2x) है, तो (f^{-1}(4)) के रूप में किस प्रांत तत्व को समझा जाएगा?

If \(f:{1,2,3}\to{2,4,6,8}\) and (f(x)=2x), which domain element is understood as (f^{-1}(4))?

Explanation opens after your attempt
Correct Answer

B. (2)

Step 1

Concept

(f(2)=4), so the preimage of (4) is (2). In exams, identify the input from the output to find a preimage.

Step 2

Why this answer is correct

The correct answer is B. (2). (f(2)=4), so the preimage of (4) is (2). In exams, identify the input from the output to find a preimage.

Step 3

Exam Tip

(f(2)=4) है इसलिए (4) की पूर्वछवि (2) है। परीक्षा में पूर्वछवि खोजने के लिए आउटपुट से इनपुट पहचानें।

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यदि \(f:{1,2,3,4}\to{1,4,9,16}\) और (f(x)=x-2) है, तो (9) की पूर्वछवि क्या है?

If \(f:{1,2,3,4}\to{1,4,9,16}\) and (f(x)=x-2), what is the preimage of (9)?

Explanation opens after your attempt
Correct Answer

C. (3)

Step 1

Concept

\(3^2=9\), so the preimage of (9) is (3). In exams, find the domain element associated with the image.

Step 2

Why this answer is correct

The correct answer is C. (3). \(3^2=9\), so the preimage of (9) is (3). In exams, find the domain element associated with the image.

Step 3

Exam Tip

\(3^2=9\) इसलिए (9) की पूर्वछवि (3) है। परीक्षा में छवि से संबंधित प्रांत तत्व खोजें।

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यदि \(f:{1,2,3}\to{1,4,9,16}\) और (f(x)=x-2) है, तो (16) की पूर्वछवि के बारे में क्या सही है?

If \(f:{1,2,3}\to{1,4,9,16}\) and (f(x)=x-2), what is true about the preimage of (16)?

Explanation opens after your attempt
Correct Answer

A. इसकी कोई पूर्वछवि नहीं हैIt has no preimage

Step 1

Concept

(4) is not in the domain, so (16) is not obtained. In exams, a preimage must come from the domain only.

Step 2

Why this answer is correct

The correct answer is A. इसकी कोई पूर्वछवि नहीं है / It has no preimage. (4) is not in the domain, so (16) is not obtained. In exams, a preimage must come from the domain only.

Step 3

Exam Tip

प्रांत में (4) नहीं है इसलिए (16) प्राप्त नहीं होता। परीक्षा में पूर्वछवि केवल प्रांत से ही ली जाती है।

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यदि \(f:{1,2,3}\to{2,4,6}\) और (f(x)=2x) है, तो निम्न में कौन-सा कथन सही है?

If \(f:{1,2,3}\to{2,4,6}\) and (f(x)=2x), which statement is correct?

Explanation opens after your attempt
Correct Answer

A. (f) फलन है और परिसर ({2,4,6}) है(f) is a function and the range is ({2,4,6})

Step 1

Concept

Every domain element has exactly one image and the images are (2,4,6). In exams, check both function validity and range using the rule.

Step 2

Why this answer is correct

The correct answer is A. (f) फलन है और परिसर ({2,4,6}) है / (f) is a function and the range is ({2,4,6}). Every domain element has exactly one image and the images are (2,4,6). In exams, check both function validity and range using the rule.

Step 3

Exam Tip

हर प्रांत तत्व की ठीक एक छवि है और छवियां (2,4,6) हैं। परीक्षा में फलन और परिसर दोनों को नियम से जांचें।

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यदि \(f:{1,2,3,4}\to{1,2,3,4}\) और (f(x)=5-x) है, तो (f(2)) क्या है?

If \(f:{1,2,3,4}\to{1,2,3,4}\) and (f(x)=5-x), what is (f(2))?

Explanation opens after your attempt
Correct Answer

C. (3)

Step 1

Concept

(f(2)=5-2=3). In exams, substitute the input directly into the given rule.

Step 2

Why this answer is correct

The correct answer is C. (3). (f(2)=5-2=3). In exams, substitute the input directly into the given rule.

Step 3

Exam Tip

(f(2)=5-2=3) है। परीक्षा में दिए गए नियम में इनपुट सीधे रखें।

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यदि \(f:{1,2,3,4}\to{1,2,3,4}\) और (f(x)=5-x) है, तो (f) का परिसर क्या है?

If \(f:{1,2,3,4}\to{1,2,3,4}\) and (f(x)=5-x), what is the range of (f)?

Explanation opens after your attempt
Correct Answer

A. ({1,2,3,4})

Step 1

Concept

For (x=1,2,3,4), the images are (4,3,2,1). Therefore the range is ({1,2,3,4}).

Step 2

Why this answer is correct

The correct answer is A. ({1,2,3,4}). For (x=1,2,3,4), the images are (4,3,2,1). Therefore the range is ({1,2,3,4}).

Step 3

Exam Tip

(x=1,2,3,4) पर छवियां (4,3,2,1) मिलती हैं। इसलिए परिसर ({1,2,3,4}) है।

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यदि \(A=\{1,2,3\}\) और \(B=\{a,b\}\) हों, तो कौन-सा संबंध फलन है पर एक-एक नहीं है?

If \(A=\{1,2,3\}\) and \(B=\{a,b\}\), which relation is a function but not one-one?

Explanation opens after your attempt
Correct Answer

A. ({(1,a),(2,a),(3,b)})

Step 1

Concept

In option (A), every domain element has one image, but (1) and (2) both have image (a). In exams, test function and one-one separately.

Step 2

Why this answer is correct

The correct answer is A. ({(1,a),(2,a),(3,b)}). In option (A), every domain element has one image, but (1) and (2) both have image (a). In exams, test function and one-one separately.

Step 3

Exam Tip

विकल्प (A) में हर प्रांत तत्व की एक छवि है पर (1) और (2) दोनों की छवि (a) है। परीक्षा में फलन और एक-एक की जांच अलग करें।

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यदि \(A=\{1,2,3\}\) और \(B=\{2,4,6\}\) हों, तो \(R=\{(1,2),(2,4),(3,6),(3,6)\}\) के बारे में सही कथन क्या है?

If \(A=\{1,2,3\}\) and \(B=\{2,4,6\}\), what is the correct statement about \(R=\{(1,2),(2,4),(3,6),(3,6)\}\)?

Explanation opens after your attempt
Correct Answer

A. यह फलन है क्योंकि दोहराया युग्म अलग छवि नहीं देताIt is a function because the repeated pair does not give a different image

Step 1

Concept

Repeating the same pair does not create a new different image. In exams, distinguish between a repeated pair and a different image.

Step 2

Why this answer is correct

The correct answer is A. यह फलन है क्योंकि दोहराया युग्म अलग छवि नहीं देता / It is a function because the repeated pair does not give a different image. Repeating the same pair does not create a new different image. In exams, distinguish between a repeated pair and a different image.

Step 3

Exam Tip

समान युग्म दोहराने से कोई नई अलग छवि नहीं बनती। परीक्षा में दोहराए युग्म और अलग छवि में अंतर करें।

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यदि \(A=\{1,2,3,4,5\}\), \(B=\{0,1\}\) और (f(x)=1) जब (x) सम हो तथा (f(x)=0) जब (x) विषम हो, तो (f) का परिसर क्या है?

If \(A=\{1,2,3,4,5\}\), \(B=\{0,1\}\), and (f(x)=1) when (x) is even and (f(x)=0) when (x) is odd, what is the range of (f)?

Explanation opens after your attempt
Correct Answer

C. ({0,1})

Step 1

Concept

(A) contains both even and odd elements, so both images (0) and (1) are obtained. In exams, check all types of inputs.

Step 2

Why this answer is correct

The correct answer is C. ({0,1}). (A) contains both even and odd elements, so both images (0) and (1) are obtained. In exams, check all types of inputs.

Step 3

Exam Tip

(A) में सम और विषम दोनों तत्व हैं इसलिए दोनों छवियां (0) और (1) प्राप्त होती हैं। परीक्षा में सभी प्रकार के इनपुट जांचें।

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यदि \(A=\{1,2,3\}\) और \(B=\{a,b,c,d\}\) हों, तो (A) से (B) में फलन होने पर क्रमित युग्मों की संख्या कितनी होगी?

If \(A=\{1,2,3\}\) and \(B=\{a,b,c,d\}\), how many ordered pairs will a function from (A) to (B) have?

Explanation opens after your attempt
Correct Answer

A. (3)

Step 1

Concept

A function has exactly one pair for every domain element, so the number of pairs will be (3). In exams, pairs in a function equal the number of domain elements.

Step 2

Why this answer is correct

The correct answer is A. (3). A function has exactly one pair for every domain element, so the number of pairs will be (3). In exams, pairs in a function equal the number of domain elements.

Step 3

Exam Tip

फलन में प्रांत के हर तत्व के लिए ठीक एक युग्म होता है इसलिए युग्मों की संख्या (3) होगी। परीक्षा में फलन के युग्म प्रांत के तत्वों के बराबर होते हैं।

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यदि \(A=\{-2,-1,0,1,2\}\), \(B=\{0,1,2\}\) और (f(x)=|x|) हो, तो (f) का परिसर क्या है?

If \(A=\{-2,-1,0,1,2\}\), \(B=\{0,1,2\}\), and (f(x)=|x|), what is the range of (f)?

Explanation opens after your attempt
Correct Answer

A. ({0,1,2})

Step 1

Concept

The values are (|-2|=2), (|-1|=1), (|0|=0), (|1|=1), and (|2|=2), so the range is ({0,1,2}). In exams, write only distinct obtained images in the range.

Step 2

Why this answer is correct

The correct answer is A. ({0,1,2}). The values are (|-2|=2), (|-1|=1), (|0|=0), (|1|=1), and (|2|=2), so the range is ({0,1,2}). In exams, write only distinct obtained images in the range.

Step 3

Exam Tip

(|-2|=2), (|-1|=1), (|0|=0), (|1|=1) और (|2|=2), इसलिए परिसर ({0,1,2}) है। परीक्षा में परिसर में केवल अलग-अलग प्राप्त छवियां लिखें।

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Class 11 Mathematics Quiz FAQs

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