Class 11 Mathematics - Relations And Functions - Algebra of real functions Medium Quiz

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रेखा (y=x) के ग्राफ पर कौन-सा बिंदु स्थित है?

Which point lies on the graph of the line (y=x)?

Explanation opens after your attempt
Correct Answer

A. ( (2,2) )

Step 1

Concept

On (y=x), both coordinates are equal. In exams, first compare (x) and (y).

Step 2

Why this answer is correct

The correct answer is A. ( (2,2) ). On (y=x), both coordinates are equal. In exams, first compare (x) and (y).

Step 3

Exam Tip

(y=x) पर दोनों निर्देशांक बराबर होते हैं। परीक्षा में पहले (x) और (y) की तुलना करें।

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साइनम फलन (f(x)=\operatorname{sgn}(x)) में (x<0) के लिए ग्राफ का (y)-मान क्या होता है?

For the signum function (f(x)=\operatorname{sgn}(x)), what is the (y)-value of the graph for (x<0)?

Explanation opens after your attempt
Correct Answer

A. ( -1 )

Step 1

Concept

In the signum function, the value is (-1) for negative (x). In exams, keep the three cases (x<0), (x=0), and (x>0) separate.

Step 2

Why this answer is correct

The correct answer is A. ( -1 ). In the signum function, the value is (-1) for negative (x). In exams, keep the three cases (x<0), (x=0), and (x>0) separate.

Step 3

Exam Tip

साइनम फलन में ऋणात्मक (x) के लिए मान (-1) होता है। परीक्षा में (x<0), (x=0), (x>0) तीन स्थितियां अलग रखें।

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फलन (f(x)=x-2) का ग्राफ किस अक्ष के प्रति सममित होता है?

The graph of (f(x)=x-2) is symmetric about which axis?

Explanation opens after your attempt
Correct Answer

B. (y)-अक्ष(y)-axis

Step 1

Concept

Since (f(-x)=f(x)), the graph is symmetric about the (y)-axis. In exams, check (f(-x)) to identify an even function.

Step 2

Why this answer is correct

The correct answer is B. (y)-अक्ष / (y)-axis. Since (f(-x)=f(x)), the graph is symmetric about the (y)-axis. In exams, check (f(-x)) to identify an even function.

Step 3

Exam Tip

(f(-x)=f(x)) इसलिए ग्राफ (y)-अक्ष के प्रति सममित है। परीक्षा में सम फलन पहचानने के लिए (f(-x)) जांचें।

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महत्तम पूर्णांक फलन (f(x)=\lfloor x\rfloor) के ग्राफ पर (x=2.7) के लिए (y) क्या होगा?

For (x=2.7) on the graph of the greatest integer function (f(x)=\lfloor x\rfloor), what is (y)?

Explanation opens after your attempt
Correct Answer

A. ( 2 )

Step 1

Concept

\(\lfloor 2.7\rfloor=2\) because it is the greatest integer less than or equal to (2.7). In exams, do not round; move down to the greatest integer.

Step 2

Why this answer is correct

The correct answer is A. ( 2 ). \(\lfloor 2.7\rfloor=2\) because it is the greatest integer less than or equal to (2.7). In exams, do not round; move down to the greatest integer.

Step 3

Exam Tip

\(\lfloor 2.7\rfloor=2\) क्योंकि यह (2.7) से छोटा या बराबर सबसे बड़ा पूर्णांक है। परीक्षा में दशमलव को निकटतम पूर्णांक नहीं, नीचे वाले पूर्णांक में बदलें।

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फलन (f(x)=x-3) के ग्राफ की मूल बिंदु के प्रति सममिति किस कारण होती है?

Why is the graph of (f(x)=x-3) symmetric about the origin?

Explanation opens after your attempt
Correct Answer

B. क्योंकि (f(-x)=-f(x))because (f(-x)=-f(x))

Step 1

Concept

\(x^3\) is an odd function because (f(-x)=-f(x)). In exams, origin symmetry usually indicates an odd function.

Step 2

Why this answer is correct

The correct answer is B. क्योंकि (f(-x)=-f(x)) / because (f(-x)=-f(x)). \(x^3\) is an odd function because (f(-x)=-f(x)). In exams, origin symmetry usually indicates an odd function.

Step 3

Exam Tip

\(x^3\) विषम फलन है क्योंकि (f(-x)=-f(x))। परीक्षा में मूल बिंदु सममिति के लिए विषम फलन देखें।

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फलन (f(x)=\lfloor x\rfloor) के ग्राफ में अंतराल ( [1,2) ) पर (y) का मान क्या रहता है?

In the graph of (f(x)=\lfloor x\rfloor), what is the value of (y) on the interval ( [1,2) )?

Explanation opens after your attempt
Correct Answer

B. ( 1 )

Step 1

Concept

For every \(x\in[1,2\)), \(\lfloor x\rfloor=1\). In exams, remember this graph as a step graph.

Step 2

Why this answer is correct

The correct answer is B. ( 1 ). For every \(x\in[1,2\)), \(\lfloor x\rfloor=1\). In exams, remember this graph as a step graph.

Step 3

Exam Tip

हर \(x\in[1,2\)) के लिए \(\lfloor x\rfloor=1\) होता है। परीक्षा में इस ग्राफ को सीढ़ीनुमा ग्राफ के रूप में याद रखें।

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फलन (f(x)=|x|) का न्यूनतम मान क्या है?

What is the minimum value of (f(x)=|x|)?

Explanation opens after your attempt
Correct Answer

B. ( 0 )

Step 1

Concept

(|x|) is always (0) or greater and equals (0) at (x=0). In exams, remember the vertex of the modulus graph.

Step 2

Why this answer is correct

The correct answer is B. ( 0 ). (|x|) is always (0) or greater and equals (0) at (x=0). In exams, remember the vertex of the modulus graph.

Step 3

Exam Tip

(|x|) हमेशा (0) या उससे बड़ा होता है और (x=0) पर (0) मिलता है। परीक्षा में मापांक ग्राफ का शीर्ष याद रखें।

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फलन (f(x)=\sqrt{x}) के ग्राफ का प्रांत क्या है?

What is the domain of the graph of (f(x)=\sqrt{x})?

Explanation opens after your attempt
Correct Answer

B. \( [0,\infty\) )

Step 1

Concept

For real \(\sqrt{x}\), we need \(x\ge 0\). In exams, keep the expression inside a square root non-negative.

Step 2

Why this answer is correct

The correct answer is B. \( [0,\infty\) ). For real \(\sqrt{x}\), we need \(x\ge 0\). In exams, keep the expression inside a square root non-negative.

Step 3

Exam Tip

वास्तविक \(\sqrt{x}\) के लिए \(x\ge 0\) होना चाहिए। परीक्षा में वर्गमूल के अंदर की राशि को अनऋणात्मक रखें।

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फलन (f(x)=\frac{1}{x}) का ग्राफ किस रेखा को नहीं काटता?

Which line is not crossed by the graph of (f(x)=\frac{1}{x})?

Explanation opens after your attempt
Correct Answer

A. (x=0)

Step 1

Concept

\(\frac{1}{x}\) is undefined at (x=0). In exams, treat (x=0) as a vertical asymptote.

Step 2

Why this answer is correct

The correct answer is A. (x=0). \(\frac{1}{x}\) is undefined at (x=0). In exams, treat (x=0) as a vertical asymptote.

Step 3

Exam Tip

\(\frac{1}{x}\) में (x=0) पर मान परिभाषित नहीं है। परीक्षा में (x=0) को लंबवत आसमापी समझें।

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स्थिर फलन (f(x)=3) के ग्राफ की आकृति कैसी होती है?

What is the shape of the graph of the constant function (f(x)=3)?

Explanation opens after your attempt
Correct Answer

A. (x)-अक्ष के समानांतर रेखाline parallel to (x)-axis

Step 1

Concept

In (f(x)=3), (y=3) for every (x). In exams, treat a constant function as a horizontal line.

Step 2

Why this answer is correct

The correct answer is A. (x)-अक्ष के समानांतर रेखा / line parallel to (x)-axis. In (f(x)=3), (y=3) for every (x). In exams, treat a constant function as a horizontal line.

Step 3

Exam Tip

(f(x)=3) में हर (x) के लिए (y=3) रहता है। परीक्षा में स्थिर फलन को क्षैतिज रेखा मानें।

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ग्राफ (y=|x|) का शीर्ष कौन-सा है?

What is the vertex of the graph (y=|x|)?

Explanation opens after your attempt
Correct Answer

A. ( (0,0) )

Step 1

Concept

The least value of (y=|x|) is (0) at (x=0). In exams, remember its (V)-shaped graph.

Step 2

Why this answer is correct

The correct answer is A. ( (0,0) ). The least value of (y=|x|) is (0) at (x=0). In exams, remember its (V)-shaped graph.

Step 3

Exam Tip

(y=|x|) का सबसे छोटा मान (0) है जो (x=0) पर मिलता है। परीक्षा में इसका ग्राफ (V)-आकार का याद रखें।

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फलन (f(x)=x-2+2) के ग्राफ का शीर्ष कौन-सा है?

What is the vertex of the graph of (f(x)=x-2+2)?

Explanation opens after your attempt
Correct Answer

B. ( (0,2) )

Step 1

Concept

The graph of \(x^2\) shifts (2) units upward. In exams, read (+k) as an upward shift.

Step 2

Why this answer is correct

The correct answer is B. ( (0,2) ). The graph of \(x^2\) shifts (2) units upward. In exams, read (+k) as an upward shift.

Step 3

Exam Tip

\(x^2\) का ग्राफ (2) इकाई ऊपर खिसकता है। परीक्षा में (+k) को ऊपर की ओर विस्थापन मानें।

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फलन (f(x)=(x-3)2) का ग्राफ \(y=x^2\) से कैसे प्राप्त होता है?

How is the graph of (f(x)=(x-3)2) obtained from \(y=x^2\)?

Explanation opens after your attempt
Correct Answer

B. (3) इकाई दाईं ओर(3) units right

Step 1

Concept

((x-3)) means shifting the graph (3) units to the right. In exams, read (x-a) as a right shift.

Step 2

Why this answer is correct

The correct answer is B. (3) इकाई दाईं ओर / (3) units right. ((x-3)) means shifting the graph (3) units to the right. In exams, read (x-a) as a right shift.

Step 3

Exam Tip

((x-3)) का अर्थ ग्राफ को दाईं ओर (3) इकाई खिसकाना है। परीक्षा में (x-a) को दाईं ओर विस्थापन समझें।

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फलन (f(x)=|x+2|) का शीर्ष कौन-सा है?

What is the vertex of (f(x)=|x+2|)?

Explanation opens after your attempt
Correct Answer

A. ( (-2,0) )

Step 1

Concept

(|x+2|=0) when (x=-2). In exams, set the inside of the modulus equal to (0) to find the vertex.

Step 2

Why this answer is correct

The correct answer is A. ( (-2,0) ). (|x+2|=0) when (x=-2). In exams, set the inside of the modulus equal to (0) to find the vertex.

Step 3

Exam Tip

(|x+2|=0) तब होता है जब (x=-2)। परीक्षा में मापांक के अंदर को (0) रखकर शीर्ष निकालें।

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ग्राफ \(y=\sqrt{x-4}\) का प्रारंभिक बिंदु कौन-सा है?

What is the starting point of the graph \(y=\sqrt{x-4}\)?

Explanation opens after your attempt
Correct Answer

B. ( (4,0) )

Step 1

Concept

For \(\sqrt{x-4}\), the smallest (x) is (4) and then (y=0). In exams, start a square-root graph by making the inside expression (0).

Step 2

Why this answer is correct

The correct answer is B. ( (4,0) ). For \(\sqrt{x-4}\), the smallest (x) is (4) and then (y=0). In exams, start a square-root graph by making the inside expression (0).

Step 3

Exam Tip

\(\sqrt{x-4}\) में सबसे छोटा (x=4) है और तब (y=0) है। परीक्षा में वर्गमूल ग्राफ की शुरुआत अंदर की राशि (0) से करें।

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फलन (f(x)=\frac{1}{x-2}) का लंबवत आसमापी क्या है?

What is the vertical asymptote of (f(x)=\frac{1}{x-2})?

Explanation opens after your attempt
Correct Answer

B. (x=2)

Step 1

Concept

Setting the denominator (x-2) equal to (0) gives (x=2). In exams, set the denominator to (0) for a vertical asymptote.

Step 2

Why this answer is correct

The correct answer is B. (x=2). Setting the denominator (x-2) equal to (0) gives (x=2). In exams, set the denominator to (0) for a vertical asymptote.

Step 3

Exam Tip

हर (x-2) को (0) करने पर (x=2) मिलता है। परीक्षा में हर को (0) रखकर लंबवत आसमापी निकालें।

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फलन (f(x)=\frac{1}{x}+1) का क्षैतिज आसमापी क्या है?

What is the horizontal asymptote of (f(x)=\frac{1}{x}+1)?

Explanation opens after your attempt
Correct Answer

B. (y=1)

Step 1

Concept

The horizontal asymptote of \(\frac{1}{x}\) is (y=0), and (+1) shifts it to (y=1). In exams, apply vertical shifts to asymptotes too.

Step 2

Why this answer is correct

The correct answer is B. (y=1). The horizontal asymptote of \(\frac{1}{x}\) is (y=0), and (+1) shifts it to (y=1). In exams, apply vertical shifts to asymptotes too.

Step 3

Exam Tip

\(\frac{1}{x}\) का क्षैतिज आसमापी (y=0) है और (+1) से वह (y=1) हो जाता है। परीक्षा में ऊर्ध्व विस्थापन आसमापी पर भी लागू करें।

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किस फलन का ग्राफ पहले और तीसरे चतुर्थांश में दो शाखाओं वाला होता है?

Which function has a graph with two branches in the first and third quadrants?

Explanation opens after your attempt
Correct Answer

B. \(y=\frac{1}{x}\)

Step 1

Concept

In \(y=\frac{1}{x}\), (x) and (y) have the same sign. In exams, remember that the reciprocal graph lies in quadrants (1) and (3).

Step 2

Why this answer is correct

The correct answer is B. \(y=\frac{1}{x}\). In \(y=\frac{1}{x}\), (x) and (y) have the same sign. In exams, remember that the reciprocal graph lies in quadrants (1) and (3).

Step 3

Exam Tip

\(y=\frac{1}{x}\) में (x) और (y) का चिह्न समान होता है। परीक्षा में पारस्परिक फलन की शाखाएं चतुर्थांश (1) और (3) में याद रखें।

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किस फलन का ग्राफ पहले और दूसरे चतुर्थांश में (U)-आकार का होता है?

Which function has a (U)-shaped graph in the first and second quadrants?

Explanation opens after your attempt
Correct Answer

A. \(y=x^2\)

Step 1

Concept

For \(y=x^2\), \(y\ge 0\) and the graph lies on both sides of the (y)-axis. In exams, identify the parabola by its (U)-shape.

Step 2

Why this answer is correct

The correct answer is A. \(y=x^2\). For \(y=x^2\), \(y\ge 0\) and the graph lies on both sides of the (y)-axis. In exams, identify the parabola by its (U)-shape.

Step 3

Exam Tip

\(y=x^2\) में \(y\ge 0\) होता है और ग्राफ (y)-अक्ष के दोनों ओर होता है। परीक्षा में परवलय को (U)-आकार से पहचानें।

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फलन (f(x)=x-3) किस अंतराल पर बढ़ता है?

On which interval is (f(x)=x-3) increasing?

Explanation opens after your attempt
Correct Answer

C. पूरे ( \(-\infty,\infty\) ) परon all ( \(-\infty,\infty\) )

Step 1

Concept

The graph of \(x^3\) rises continuously from left to right. In exams, remember \(x^3\) is increasing on the whole real domain.

Step 2

Why this answer is correct

The correct answer is C. पूरे ( \(-\infty,\infty\) ) पर / on all ( \(-\infty,\infty\) ). The graph of \(x^3\) rises continuously from left to right. In exams, remember \(x^3\) is increasing on the whole real domain.

Step 3

Exam Tip

\(x^3\) का ग्राफ बाएं से दाएं लगातार ऊपर जाता है। परीक्षा में \(x^3\) को पूरे वास्तविक प्रांत में बढ़ता हुआ याद रखें।

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फलन (f(x)=|x|) किस अंतराल पर घटता है?

On which interval is (f(x)=|x|) decreasing?

Explanation opens after your attempt
Correct Answer

A. ( \(-\infty,0] \)

Step 1

Concept

The graph of (|x|) decreases up to (x=0) and then increases. In exams, see the left arm of the (V)-graph as decreasing.

Step 2

Why this answer is correct

The correct answer is A. ( \(-\infty,0] \). The graph of (|x|) decreases up to (x=0) and then increases. In exams, see the left arm of the (V)-graph as decreasing.

Step 3

Exam Tip

(|x|) का ग्राफ (x=0) तक नीचे आता है और फिर ऊपर जाता है। परीक्षा में (V)-ग्राफ का बायां भाग घटता हुआ देखें।

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ग्राफ \(y=x^2-4\) (x)-अक्ष को किन बिंदुओं पर काटता है?

Where does the graph \(y=x^2-4\) cut the (x)-axis?

Explanation opens after your attempt
Correct Answer

A. ( (-2,0) ) और ( (2,0) )( (-2,0) ) and ( (2,0) )

Step 1

Concept

On the (x)-axis, set (y=0), giving \(x^2-4=0\). In exams, set the related coordinate to (0) for intercepts.

Step 2

Why this answer is correct

The correct answer is A. ( (-2,0) ) और ( (2,0) ) / ( (-2,0) ) and ( (2,0) ). On the (x)-axis, set (y=0), giving \(x^2-4=0\). In exams, set the related coordinate to (0) for intercepts.

Step 3

Exam Tip

(x)-अक्ष पर (y=0) रखकर \(x^2-4=0\) मिलता है। परीक्षा में अवरोधों के लिए संबंधित निर्देशांक (0) रखें।

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ग्राफ \(y=x^2+1\) (x)-अक्ष को कितनी बार काटता है?

How many times does the graph \(y=x^2+1\) cut the (x)-axis?

Explanation opens after your attempt
Correct Answer

A. (0) बार(0) times

Step 1

Concept

\(x^2+1\) is always at least (1), so (y=0) is impossible. In exams, use the minimum value to check (x)-intercepts.

Step 2

Why this answer is correct

The correct answer is A. (0) बार / (0) times. \(x^2+1\) is always at least (1), so (y=0) is impossible. In exams, use the minimum value to check (x)-intercepts.

Step 3

Exam Tip

\(x^2+1\) हमेशा (1) या उससे बड़ा है इसलिए (y=0) नहीं हो सकता। परीक्षा में न्यूनतम मान से (x)-अवरोध जांचें।

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रेखा (y=-x) का ग्राफ किस बिंदु से अवश्य गुजरता है?

The graph of the line (y=-x) must pass through which point?

Explanation opens after your attempt
Correct Answer

B. ( (3,-3) )

Step 1

Concept

In (y=-x), when (x=3), (y=-3). In exams, substitute the point into the equation quickly.

Step 2

Why this answer is correct

The correct answer is B. ( (3,-3) ). In (y=-x), when (x=3), (y=-3). In exams, substitute the point into the equation quickly.

Step 3

Exam Tip

(y=-x) में (x=3) पर (y=-3) होता है। परीक्षा में दिए बिंदु को समीकरण में रखकर तुरंत जांचें।

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फलन (f(x)=2x) का ग्राफ (f(x)=x) की तुलना में कैसा होता है?

How is the graph of (f(x)=2x) compared with (f(x)=x)?

Explanation opens after your attempt
Correct Answer

B. अधिक ढाल वाली रेखाline with greater slope

Step 1

Concept

The slope of (2x) is (2), greater than the slope (1) of (x). In exams, treat the coefficient of (x) as the slope in a linear function.

Step 2

Why this answer is correct

The correct answer is B. अधिक ढाल वाली रेखा / line with greater slope. The slope of (2x) is (2), greater than the slope (1) of (x). In exams, treat the coefficient of (x) as the slope in a linear function.

Step 3

Exam Tip

(2x) की ढाल (2) है जो (x) की ढाल (1) से अधिक है। परीक्षा में रैखिक फलन में (x) के गुणांक को ढाल मानें।

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ग्राफ (y=-|x|) का अधिकतम मान क्या है?

What is the maximum value of the graph (y=-|x|)?

Explanation opens after your attempt
Correct Answer

A. (0)

Step 1

Concept

(-|x|) is always (0) or less and equals (0) at (x=0). In exams, the vertex of a downward (V)-graph is the maximum.

Step 2

Why this answer is correct

The correct answer is A. (0). (-|x|) is always (0) or less and equals (0) at (x=0). In exams, the vertex of a downward (V)-graph is the maximum.

Step 3

Exam Tip

(-|x|) हमेशा (0) या उससे कम होता है और (x=0) पर (0) मिलता है। परीक्षा में नीचे खुले (V)-ग्राफ का शीर्ष अधिकतम होता है।

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कौन-सा ग्राफ केवल पहले चतुर्थांश और मूल बिंदु में स्थित होता है?

Which graph lies only in the first quadrant and at the origin?

Explanation opens after your attempt
Correct Answer

A. \(y=\sqrt{x}\)

Step 1

Concept

For \(y=\sqrt{x}\), \(x\ge 0\) and \(y\ge 0\). In exams, associate the square-root graph with the first quadrant.

Step 2

Why this answer is correct

The correct answer is A. \(y=\sqrt{x}\). For \(y=\sqrt{x}\), \(x\ge 0\) and \(y\ge 0\). In exams, associate the square-root graph with the first quadrant.

Step 3

Exam Tip

\(y=\sqrt{x}\) में \(x\ge 0\) और \(y\ge 0\) होता है। परीक्षा में वर्गमूल ग्राफ को पहले चतुर्थांश से जोड़ें।

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फलन (f(x)=x-2) और (g(x)=\sqrt{x}) के ग्राफ किस बिंदु पर मिलते हैं?

At which point do the graphs of (f(x)=x-2) and (g(x)=\sqrt{x}) meet?

Explanation opens after your attempt
Correct Answer

C. ( (0,0) ) और ( (1,1) )( (0,0) ) and ( (1,1) )

Step 1

Concept

For \(x^2=\sqrt{x}\), (x=0) and (x=1) work. In exams, test simple possible points first.

Step 2

Why this answer is correct

The correct answer is C. ( (0,0) ) और ( (1,1) ) / ( (0,0) ) and ( (1,1) ). For \(x^2=\sqrt{x}\), (x=0) and (x=1) work. In exams, test simple possible points first.

Step 3

Exam Tip

समानता \(x^2=\sqrt{x}\) के लिए (x=0) और (x=1) सही हैं। परीक्षा में संभावित सरल बिंदुओं को पहले जांचें।

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कौन-सा फलन अपने ग्राफ में (y)-अक्ष को ( (0,5) ) पर काटता है?

Which function cuts the (y)-axis at ( (0,5) )?

Explanation opens after your attempt
Correct Answer

A. (f(x)=x+5)

Step 1

Concept

On the (y)-axis, (x=0), and only (x+5) gives (f(0)=5). In exams, set (x=0) for the (y)-intercept.

Step 2

Why this answer is correct

The correct answer is A. (f(x)=x+5). On the (y)-axis, (x=0), and only (x+5) gives (f(0)=5). In exams, set (x=0) for the (y)-intercept.

Step 3

Exam Tip

(y)-अक्ष पर (x=0) होता है और (f(0)=5) केवल (x+5) में है। परीक्षा में (y)-अवरोध के लिए (x=0) रखें।

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फलन (f(x)=|x-1|+2) का न्यूनतम मान क्या है?

What is the minimum value of (f(x)=|x-1|+2)?

Explanation opens after your attempt
Correct Answer

C. (2)

Step 1

Concept

The minimum of (|x-1|) is (0), so the total minimum is (2). In exams, take the minimum of a modulus part as (0).

Step 2

Why this answer is correct

The correct answer is C. (2). The minimum of (|x-1|) is (0), so the total minimum is (2). In exams, take the minimum of a modulus part as (0).

Step 3

Exam Tip

(|x-1|) का न्यूनतम (0) है इसलिए कुल न्यूनतम (2) है। परीक्षा में मापांक वाले भाग का न्यूनतम (0) मानें।

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ग्राफ (y=(x+1)2-3) का शीर्ष क्या है?

What is the vertex of the graph (y=(x+1)2-3)?

Explanation opens after your attempt
Correct Answer

B. ( (-1,-3) )

Step 1

Concept

((x+1)2) shifts the graph (1) unit left and (-3) downward. In exams, for (y=(x-h)2+k), use vertex ((h,k)).

Step 2

Why this answer is correct

The correct answer is B. ( (-1,-3) ). ((x+1)2) shifts the graph (1) unit left and (-3) downward. In exams, for (y=(x-h)2+k), use vertex ((h,k)).

Step 3

Exam Tip

((x+1)2) ग्राफ को (1) इकाई बाईं ओर और (-3) नीचे ले जाता है। परीक्षा में (y=(x-h)2+k) का शीर्ष ((h,k)) लें।

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कौन-सा फलन (y)-अक्ष के प्रति सममित ग्राफ देता है?

Which function gives a graph symmetric about the (y)-axis?

Explanation opens after your attempt
Correct Answer

B. (f(x)=x-2)

Step 1

Concept

\(x^2\) is an even function because (f(-x)=f(x)). In exams, identify even functions for (y)-axis symmetry.

Step 2

Why this answer is correct

The correct answer is B. (f(x)=x-2). \(x^2\) is an even function because (f(-x)=f(x)). In exams, identify even functions for (y)-axis symmetry.

Step 3

Exam Tip

\(x^2\) सम फलन है क्योंकि (f(-x)=f(x))। परीक्षा में (y)-अक्ष सममिति के लिए सम फलन पहचानें।

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कौन-सा फलन मूल बिंदु के प्रति सममित ग्राफ देता है?

Which function gives a graph symmetric about the origin?

Explanation opens after your attempt
Correct Answer

C. (f(x)=x-3)

Step 1

Concept

\(x^3\) is an odd function, so its graph is symmetric about the origin. In exams, check (f(-x)=-f(x)).

Step 2

Why this answer is correct

The correct answer is C. (f(x)=x-3). \(x^3\) is an odd function, so its graph is symmetric about the origin. In exams, check (f(-x)=-f(x)).

Step 3

Exam Tip

\(x^3\) विषम फलन है इसलिए इसका ग्राफ मूल बिंदु के प्रति सममित है। परीक्षा में (f(-x)=-f(x)) जांचें।

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ग्राफ \(y=\frac{1}{x^2}\) किस चतुर्थांश में स्थित होता है?

In which quadrants does the graph \(y=\frac{1}{x^2}\) lie?

Explanation opens after your attempt
Correct Answer

A. पहले और दूसरेfirst and second

Step 1

Concept

\(\frac{1}{x^2}\) is always positive and \(x\ne 0\). In exams, when \(x^2\) is in the denominator, remember (y) is positive.

Step 2

Why this answer is correct

The correct answer is A. पहले और दूसरे / first and second. \(\frac{1}{x^2}\) is always positive and \(x\ne 0\). In exams, when \(x^2\) is in the denominator, remember (y) is positive.

Step 3

Exam Tip

\(\frac{1}{x^2}\) हमेशा धनात्मक होता है और \(x\ne 0\) होता है। परीक्षा में \(x^2\) हर में हो तो (y) धनात्मक याद रखें।

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फलन (f(x)=x-2) के ग्राफ पर (x=-3) के लिए (y) का मान क्या होगा?

For (x=-3) on the graph of (f(x)=x-2), what is the value of (y)?

Explanation opens after your attempt
Correct Answer

D. ( 9 )

Step 1

Concept

(y=(-3)2=9), so ((-3,9)) lies on the graph. In exams, remember a square is always non-negative.

Step 2

Why this answer is correct

The correct answer is D. ( 9 ). (y=(-3)2=9), so ((-3,9)) lies on the graph. In exams, remember a square is always non-negative.

Step 3

Exam Tip

(y=(-3)2=9) इसलिए बिंदु ((-3,9)) ग्राफ पर है। परीक्षा में वर्ग का मान हमेशा अनऋणात्मक रखें।

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फलन (f(x)=\sqrt{x}) के ग्राफ पर (x=16) के लिए (y) क्या है?

For (x=16) on the graph of (f(x)=\sqrt{x}), what is (y)?

Explanation opens after your attempt
Correct Answer

B. (4)

Step 1

Concept

\(\sqrt{16}=4\), so ((16,4)) lies on the graph. In exams, remember square roots of perfect squares.

Step 2

Why this answer is correct

The correct answer is B. (4). \(\sqrt{16}=4\), so ((16,4)) lies on the graph. In exams, remember square roots of perfect squares.

Step 3

Exam Tip

\(\sqrt{16}=4\) इसलिए बिंदु ((16,4)) ग्राफ पर है। परीक्षा में पूर्ण वर्गों के वर्गमूल याद रखें।

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यदि (y=|x|) के ग्राफ पर (y=5) है तो (x) के संभावित मान क्या हैं?

If (y=5) on the graph (y=|x|), what are the possible values of (x)?

Explanation opens after your attempt
Correct Answer

C. (5) और (-5)(5) and (-5)

Step 1

Concept

(|x|=5) gives (x=5) or (x=-5). In exams, take both signs in a modulus equation.

Step 2

Why this answer is correct

The correct answer is C. (5) और (-5) / (5) and (-5). (|x|=5) gives (x=5) or (x=-5). In exams, take both signs in a modulus equation.

Step 3

Exam Tip

(|x|=5) से (x=5) या (x=-5) मिलता है। परीक्षा में मापांक समीकरण में दोनों चिह्न लें।

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ग्राफ \(y=x^2\) पर (y=25) होने पर (x) के मान क्या हैं?

On the graph \(y=x^2\), if (y=25), what are the values of (x)?

Explanation opens after your attempt
Correct Answer

A. (5) और (-5)(5) and (-5)

Step 1

Concept

\(x^2=25\) gives \(x=\pm 5\). In exams, do not forget both roots from a square equation.

Step 2

Why this answer is correct

The correct answer is A. (5) और (-5) / (5) and (-5). \(x^2=25\) gives \(x=\pm 5\). In exams, do not forget both roots from a square equation.

Step 3

Exam Tip

\(x^2=25\) से \(x=\pm 5\) होता है। परीक्षा में वर्ग समीकरण से दोनों मूल लेना न भूलें।

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फलन (f(x)=\frac{1}{x}) के ग्राफ पर (x=4) के लिए (y) क्या है?

For (x=4) on the graph of (f(x)=\frac{1}{x}), what is (y)?

Explanation opens after your attempt
Correct Answer

B. \(\frac{1}{4}\)

Step 1

Concept

\(y=\frac{1}{4}\) is obtained by substituting (x=4). In exams, put (x) in the denominator for a reciprocal function.

Step 2

Why this answer is correct

The correct answer is B. \(\frac{1}{4}\). \(y=\frac{1}{4}\) is obtained by substituting (x=4). In exams, put (x) in the denominator for a reciprocal function.

Step 3

Exam Tip

\(y=\frac{1}{4}\) सीधे (x=4) रखने से मिलता है। परीक्षा में पारस्परिक फलन में (x) को हर में रखें।

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किस फलन के ग्राफ का परिसर ( \(-\infty,\infty\) ) है?

Which function has range ( \(-\infty,\infty\) )?

Explanation opens after your attempt
Correct Answer

C. (f(x)=x-3)

Step 1

Concept

\(x^3\) can take every real (y)-value. In exams, take the range of the cubic function as all real numbers.

Step 2

Why this answer is correct

The correct answer is C. (f(x)=x-3). \(x^3\) can take every real (y)-value. In exams, take the range of the cubic function as all real numbers.

Step 3

Exam Tip

\(x^3\) हर वास्तविक (y)-मान ले सकता है। परीक्षा में घन फलन का परिसर पूरे वास्तविक संख्याओं का सेट मानें।

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ग्राफ (y=|x|-3) का शीर्ष क्या है?

What is the vertex of the graph (y=|x|-3)?

Explanation opens after your attempt
Correct Answer

C. ( (0,-3) )

Step 1

Concept

The vertex of (y=|x|) is ((0,0)), and (-3) shifts it downward. In exams, add vertical shifts directly to the (y)-coordinate.

Step 2

Why this answer is correct

The correct answer is C. ( (0,-3) ). The vertex of (y=|x|) is ((0,0)), and (-3) shifts it downward. In exams, add vertical shifts directly to the (y)-coordinate.

Step 3

Exam Tip

(y=|x|) का शीर्ष ((0,0)) है और (-3) से नीचे खिसकता है। परीक्षा में ऊर्ध्व विस्थापन सीधे (y)-निर्देशांक में जोड़ें।

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किस ग्राफ में (x=0) और (y=0) दोनों आसमापी होते हैं?

Which graph has both (x=0) and (y=0) as asymptotes?

Explanation opens after your attempt
Correct Answer

C. \(y=\frac{1}{x}\)

Step 1

Concept

The graph \(y=\frac{1}{x}\) approaches the axes as asymptotes. In exams, remember both asymptotes of the reciprocal graph.

Step 2

Why this answer is correct

The correct answer is C. \(y=\frac{1}{x}\). The graph \(y=\frac{1}{x}\) approaches the axes as asymptotes. In exams, remember both asymptotes of the reciprocal graph.

Step 3

Exam Tip

\(y=\frac{1}{x}\) अक्षों के पास जाता है लेकिन उन्हें आसमापी की तरह नहीं काटता। परीक्षा में पारस्परिक ग्राफ के दोनों आसमापी याद रखें।

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यदि (f(x)=x-2) का ग्राफ (2) गुना ऊर्ध्व खिंचता है तो नया फलन क्या होगा?

If the graph of (f(x)=x-2) is stretched vertically by a factor of (2), what is the new function?

Explanation opens after your attempt
Correct Answer

B. \(y=2x^2\)

Step 1

Concept

For vertical stretching, multiply the whole function by (2). In exams, treat an outside multiplier as vertical scaling.

Step 2

Why this answer is correct

The correct answer is B. \(y=2x^2\). For vertical stretching, multiply the whole function by (2). In exams, treat an outside multiplier as vertical scaling.

Step 3

Exam Tip

ऊर्ध्व खिंचाव में पूरे फलन को (2) से गुणा करते हैं। परीक्षा में बाहरी गुणक को ऊर्ध्व खिंचाव मानें।

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ग्राफ \(y=\sqrt{x}+3\) का परिसर क्या है?

What is the range of the graph \(y=\sqrt{x}+3\)?

Explanation opens after your attempt
Correct Answer

B. \( [3,\infty\) )

Step 1

Concept

Since \(\sqrt{x}\ge 0\), \(\sqrt{x}+3\ge 3\). In exams, change the range after a vertical shift.

Step 2

Why this answer is correct

The correct answer is B. \( [3,\infty\) ). Since \(\sqrt{x}\ge 0\), \(\sqrt{x}+3\ge 3\). In exams, change the range after a vertical shift.

Step 3

Exam Tip

\(\sqrt{x}\ge 0\) इसलिए \(\sqrt{x}+3\ge 3\)। परीक्षा में ऊर्ध्व विस्थापन से परिसर भी बदलें।

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फलन (f(x)=-(x-1)2+4) का अधिकतम मान क्या है?

What is the maximum value of (f(x)=-(x-1)2+4)?

Explanation opens after your attempt
Correct Answer

C. (4)

Step 1

Concept

Because the coefficient is negative, the parabola opens downward and the vertex (y)-value (4) is maximum. In exams, the vertex is maximum for a downward parabola.

Step 2

Why this answer is correct

The correct answer is C. (4). Because the coefficient is negative, the parabola opens downward and the vertex (y)-value (4) is maximum. In exams, the vertex is maximum for a downward parabola.

Step 3

Exam Tip

ऋणात्मक गुणांक के कारण परवलय नीचे खुलता है और शीर्ष का (y)-मान (4) अधिकतम है। परीक्षा में नीचे खुलने वाले परवलय में शीर्ष अधिकतम होता है।

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किस फलन का ग्राफ (x)-अक्ष के नीचे भी जाता है और (x)-अक्ष के ऊपर भी जाता है?

Which function has a graph both below and above the (x)-axis?

Explanation opens after your attempt
Correct Answer

C. \(y=x^3\)

Step 1

Concept

\(y=x^3\) is negative for negative (x) and positive for positive (x). In exams, remember the cubic graph crosses the (x)-axis.

Step 2

Why this answer is correct

The correct answer is C. \(y=x^3\). \(y=x^3\) is negative for negative (x) and positive for positive (x). In exams, remember the cubic graph crosses the (x)-axis.

Step 3

Exam Tip

\(y=x^3\) ऋणात्मक (x) पर ऋणात्मक और धनात्मक (x) पर धनात्मक होता है। परीक्षा में घन ग्राफ को (x)-अक्ष पार करते हुए याद रखें।

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ग्राफ (y=|x+1|-2) (x)-अक्ष को किन (x)-मानों पर काटता है?

At which (x)-values does the graph (y=|x+1|-2) cut the (x)-axis?

Explanation opens after your attempt
Correct Answer

B. (x=-3) और (x=1)(x=-3) and (x=1)

Step 1

Concept

For the (x)-axis, (|x+1|-2=0) gives (|x+1|=2). In exams, open the modulus into both cases.

Step 2

Why this answer is correct

The correct answer is B. (x=-3) और (x=1) / (x=-3) and (x=1). For the (x)-axis, (|x+1|-2=0) gives (|x+1|=2). In exams, open the modulus into both cases.

Step 3

Exam Tip

(x)-अक्ष के लिए (|x+1|-2=0) से (|x+1|=2) मिलता है। परीक्षा में मापांक को खोलकर दोनों स्थितियां हल करें।

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फलन (f(x)=\sqrt{x+5}) का प्रांत क्या है?

What is the domain of (f(x)=\sqrt{x+5})?

Explanation opens after your attempt
Correct Answer

A. \( [-5,\infty\) )

Step 1

Concept

For \(\sqrt{x+5}\), \(x+5\ge 0\), so \(x\ge -5\). In exams, keep the expression inside the square root at least (0).

Step 2

Why this answer is correct

The correct answer is A. \( [-5,\infty\) ). For \(\sqrt{x+5}\), \(x+5\ge 0\), so \(x\ge -5\). In exams, keep the expression inside the square root at least (0).

Step 3

Exam Tip

\(\sqrt{x+5}\) के लिए \(x+5\ge 0\) इसलिए \(x\ge -5\)। परीक्षा में वर्गमूल के अंदर की राशि को (0) या उससे बड़ा रखें।

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फलन (f(x)=2) के ग्राफ का परिसर क्या है?

What is the range of the graph of (f(x)=2)?

Explanation opens after your attempt
Correct Answer

A. ( {2} )

Step 1

Concept

In a constant function, (y) is always (2). In exams, the range of a constant line is the set containing only that (y)-value.

Step 2

Why this answer is correct

The correct answer is A. ( {2} ). In a constant function, (y) is always (2). In exams, the range of a constant line is the set containing only that (y)-value.

Step 3

Exam Tip

स्थिर फलन में (y) हमेशा (2) रहता है। परीक्षा में स्थिर रेखा का परिसर केवल उसी (y)-मान का सेट होता है।

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किस विकल्प में \(y=x^2\) के ग्राफ के बारे में सही कथन है?

Which option gives the correct statement about the graph of \(y=x^2\)?

Explanation opens after your attempt
Correct Answer

B. यह (y)-अक्ष के प्रति सममित हैit is symmetric about the (y)-axis

Step 1

Concept

The domain of \(y=x^2\) is all real numbers and its graph is symmetric about the (y)-axis. In exams, remember the domain and range of a parabola separately.

Step 2

Why this answer is correct

The correct answer is B. यह (y)-अक्ष के प्रति सममित है / it is symmetric about the (y)-axis. The domain of \(y=x^2\) is all real numbers and its graph is symmetric about the (y)-axis. In exams, remember the domain and range of a parabola separately.

Step 3

Exam Tip

\(y=x^2\) का प्रांत सभी वास्तविक संख्याएं है और ग्राफ (y)-अक्ष के प्रति सममित है। परीक्षा में परवलय के प्रांत और परिसर अलग-अलग याद रखें।

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FAQs

Class 11 Mathematics Quiz FAQs

How many questions are in this quiz?

This level is designed for 50 active questions. Currently 50 questions are available for the selected class and difficulty.

Is there a timer in this quiz?

Yes, the timer uses 35 seconds per question for Medium difficulty and shows the total remaining time on the page.

Can I open each question separately?

Yes, every question has its own SEO-friendly page with answer, explanation and related practice links.