(\tan\(2\pi-x\)) किसके बराबर है?
What is (\tan\(2\pi-x\)) equal to?
#allied-angles
#tangent
#quadrants
A \(\tan x\)
B -\(\tan x\)
C \(\cot x\)
D -\(\cot x\)
Explanation opens after your attempt
Correct Answer
B. -\(\tan x\)
Step 1
Concept
In the fourth quadrant, \(\tan x\) is negative. Therefore, (\tan\(2\pi-x\)=-\tan x).
Step 2
Why this answer is correct
The correct answer is B. -\(\tan x\). In the fourth quadrant, \(\tan x\) is negative. Therefore, (\tan\(2\pi-x\)=-\tan x).
Step 3
Exam Tip
चौथे चतुर्थांश में \(\tan x\) ऋणात्मक होता है। इसलिए (\tan\(2\pi-x\)=-\tan x)।
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(\cos\(2\pi-x\)) किसके बराबर है?
What is (\cos\(2\pi-x\)) equal to?
#allied-angles
#cosine
#quadrants
A \(-\cos x\)
B \(\sin x\)
C \(\cos x\)
D -\(\sin x\)
Explanation opens after your attempt
Correct Answer
C. \(\cos x\)
Step 1
Concept
\(2\pi-x\) lies in the fourth quadrant and \(\cos x\) remains positive. Hence (\cos\(2\pi-x\)=\cos x).
Step 2
Why this answer is correct
The correct answer is C. \(\cos x\). \(2\pi-x\) lies in the fourth quadrant and \(\cos x\) remains positive. Hence (\cos\(2\pi-x\)=\cos x).
Step 3
Exam Tip
\(2\pi-x\) चौथे चतुर्थांश में आता है और \(\cos x\) धनात्मक रहता है। इसलिए (\cos\(2\pi-x\)=\cos x)।
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(\sin\(2\pi-x\)) किसके बराबर है?
What is (\sin\(2\pi-x\)) equal to?
#allied-angles
#sine
#quadrants
A \(\sin x\)
B -\(\sin x\)
C \(\cos x\)
D -\(\cos x\)
Explanation opens after your attempt
Correct Answer
B. -\(\sin x\)
Step 1
Concept
\(2\pi-x\) is related to the fourth quadrant. There \(\sin x\) is negative, so (\sin\(2\pi-x\)=-\sin x).
Step 2
Why this answer is correct
The correct answer is B. -\(\sin x\). \(2\pi-x\) is related to the fourth quadrant. There \(\sin x\) is negative, so (\sin\(2\pi-x\)=-\sin x).
Step 3
Exam Tip
\(2\pi-x\) चौथे चतुर्थांश से संबंधित है। वहाँ \(\sin x\) ऋणात्मक होता है, इसलिए (\sin\(2\pi-x\)=-\sin x)।
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यदि (x) दूसरे चतुर्थांश में है और \(\sec x=-\frac{17}{8}\), तो \(\sin x\) का मान क्या है?
If (x) is in the second quadrant and \(\sec x=-\frac{17}{8}\), what is the value of \(\sin x\)?
#quadrants
#sine
#secant
A \(\frac{8}{17}\)
B -\(\frac{8}{17}\)
C \(\frac{15}{17}\)
D -\(\frac{15}{17}\)
Explanation opens after your attempt
Correct Answer
C. \(\frac{15}{17}\)
Step 1
Concept
\(\cos x=-\frac{8}{17}\). In the second quadrant, \(\sin x\) is positive, so \(\sin x=\frac{15}{17}\).
Step 2
Why this answer is correct
The correct answer is C. \(\frac{15}{17}\). \(\cos x=-\frac{8}{17}\). In the second quadrant, \(\sin x\) is positive, so \(\sin x=\frac{15}{17}\).
Step 3
Exam Tip
\(\cos x=-\frac{8}{17}\) होगा। दूसरे चतुर्थांश में \(\sin x\) धनात्मक है, इसलिए \(\sin x=\frac{15}{17}\) है।
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यदि (x) चौथे चतुर्थांश में है और \(\tan x=-\frac{24}{7}\), तो \(\cos x\) का मान क्या है?
If (x) is in the fourth quadrant and \(\tan x=-\frac{24}{7}\), what is the value of \(\cos x\)?
#quadrants
#cosine
#tangent
A \(\frac{7}{25}\)
B -\(\frac{7}{25}\)
C \(\frac{24}{25}\)
D -\(\frac{24}{25}\)
Explanation opens after your attempt
Correct Answer
A. \(\frac{7}{25}\)
Step 1
Concept
In the fourth quadrant, \(\cos x\) is positive and \(\sin x\) is negative. From the (7,24,25) triple, \(\cos x=\frac{7}{25}\).
Step 2
Why this answer is correct
The correct answer is A. \(\frac{7}{25}\). In the fourth quadrant, \(\cos x\) is positive and \(\sin x\) is negative. From the (7,24,25) triple, \(\cos x=\frac{7}{25}\).
Step 3
Exam Tip
चौथे चतुर्थांश में \(\cos x\) धनात्मक और \(\sin x\) ऋणात्मक होता है। (7,24,25) त्रिक से \(\cos x=\frac{7}{25}\) है।
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यदि (x) तीसरे चतुर्थांश में है और \(\sin x=-\frac{5}{13}\), तो \(\sec x\) का मान क्या है?
If (x) is in the third quadrant and \(\sin x=-\frac{5}{13}\), what is the value of \(\sec x\)?
#quadrants
#secant
#sine
A \(\frac{13}{12}\)
B -\(\frac{13}{12}\)
C -\(\frac{12}{13}\)
D \(\frac{12}{13}\)
Explanation opens after your attempt
Correct Answer
B. -\(\frac{13}{12}\)
Step 1
Concept
In the third quadrant, \(\cos x\) is negative. Since \(\cos x=-\frac{12}{13}\), \(\sec x=-\frac{13}{12}\).
Step 2
Why this answer is correct
The correct answer is B. -\(\frac{13}{12}\). In the third quadrant, \(\cos x\) is negative. Since \(\cos x=-\frac{12}{13}\), \(\sec x=-\frac{13}{12}\).
Step 3
Exam Tip
तीसरे चतुर्थांश में \(\cos x\) ऋणात्मक होता है। \(\cos x=-\frac{12}{13}\), इसलिए \(\sec x=-\frac{13}{12}\) है।
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यदि (x) दूसरे चतुर्थांश में है और \(\cos x=-\frac{3}{5}\), तो \(\tan x\) का मान क्या है?
If (x) is in the second quadrant and \(\cos x=-\frac{3}{5}\), what is the value of \(\tan x\)?
#quadrants
#tangent
#identity
A \(\frac{4}{3}\)
B -\(\frac{4}{3}\)
C \(\frac{3}{4}\)
D -\(\frac{3}{4}\)
Explanation opens after your attempt
Correct Answer
B. -\(\frac{4}{3}\)
Step 1
Concept
In the second quadrant, \(\sin x\) is positive and \(\cos x\) is negative. Since \(\sin x=\frac{4}{5}\), \(\tan x=-\frac{4}{3}\).
Step 2
Why this answer is correct
The correct answer is B. -\(\frac{4}{3}\). In the second quadrant, \(\sin x\) is positive and \(\cos x\) is negative. Since \(\sin x=\frac{4}{5}\), \(\tan x=-\frac{4}{3}\).
Step 3
Exam Tip
दूसरे चतुर्थांश में \(\sin x\) धनात्मक और \(\cos x\) ऋणात्मक होता है। \(\sin x=\frac{4}{5}\), इसलिए \(\tan x=-\frac{4}{3}\) है।
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यदि \(\cos^2 x=\frac{9}{16}\) और (x) चौथे चतुर्थांश में है, तो \(\sin x\) का मान क्या है?
If \(\cos^2 x=\frac{9}{16}\) and (x) is in the fourth quadrant, what is the value of \(\sin x\)?
#identity
#quadrants
#sine
A \(\frac{\sqrt{7}}{4}\)
B \(-\frac{\sqrt{7}}{4}\)
C \(\frac{3}{4}\)
D \(-\frac{3}{4}\)
Explanation opens after your attempt
Correct Answer
B. \(-\frac{\sqrt{7}}{4}\)
Step 1
Concept
\(\sin^2 x=1-\frac{9}{16}=\frac{7}{16}\). In the fourth quadrant, \(\sin x\) is negative.
Step 2
Why this answer is correct
The correct answer is B. \(-\frac{\sqrt{7}}{4}\). \(\sin^2 x=1-\frac{9}{16}=\frac{7}{16}\). In the fourth quadrant, \(\sin x\) is negative.
Step 3
Exam Tip
\(\sin^2 x=1-\frac{9}{16}=\frac{7}{16}\) होता है। चौथे चतुर्थांश में \(\sin x\) ऋणात्मक होता है।
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यदि (x) दूसरे चतुर्थांश में है और \(\cot x=-\frac{3}{4}\), तो \(\cosec x\) का मान क्या है?
If (x) is in the second quadrant and \(\cot x=-\frac{3}{4}\), what is the value of \(\cosec x\)?
#quadrants
#cosecant
#cotangent
A \(\frac{5}{4}\)
B \(-\frac{5}{4}\)
C \(\frac{4}{5}\)
D \(-\frac{4}{5}\)
Explanation opens after your attempt
Correct Answer
A. \(\frac{5}{4}\)
Step 1
Concept
From \(\cosec^2 x=1+\cot^2 x\), \(|\cosec x|=\frac{5}{4}\). In the second quadrant, \(\cosec x\) is positive.
Step 2
Why this answer is correct
The correct answer is A. \(\frac{5}{4}\). From \(\cosec^2 x=1+\cot^2 x\), \(|\cosec x|=\frac{5}{4}\). In the second quadrant, \(\cosec x\) is positive.
Step 3
Exam Tip
\(\cosec^2 x=1+\cot^2 x\) से \(|\cosec x|=\frac{5}{4}\) मिलता है। दूसरे चतुर्थांश में \(\cosec x\) धनात्मक होता है।
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यदि (x) चौथे चतुर्थांश में है और \(\cos x=\frac{15}{17}\), तो \(\sin x\) का मान क्या है?
If (x) is in the fourth quadrant and \(\cos x=\frac{15}{17}\), what is the value of \(\sin x\)?
#quadrants
#sine
#identity
A \(\frac{8}{17}\)
B \(-\frac{15}{17}\)
C \(-\frac{8}{17}\)
D \(\frac{15}{17}\)
Explanation opens after your attempt
Correct Answer
C. \(-\frac{8}{17}\)
Step 1
Concept
The identity gives \(|\sin x|=\frac{8}{17}\). In the fourth quadrant, \(\sin x\) is negative.
Step 2
Why this answer is correct
The correct answer is C. \(-\frac{8}{17}\). The identity gives \(|\sin x|=\frac{8}{17}\). In the fourth quadrant, \(\sin x\) is negative.
Step 3
Exam Tip
पहचान से \(|\sin x|=\frac{8}{17}\) मिलता है। चौथे चतुर्थांश में \(\sin x\) ऋणात्मक होता है।
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यदि (x) तीसरे चतुर्थांश में है और \(\tan x=\frac{9}{40}\), तो \(\sec x\) का मान क्या है?
If (x) is in the third quadrant and \(\tan x=\frac{9}{40}\), what is the value of \(\sec x\)?
#quadrants
#secant
#tangent
A \(\frac{41}{40}\)
B \(-\frac{41}{40}\)
C \(\frac{40}{41}\)
D \(-\frac{40}{41}\)
Explanation opens after your attempt
Correct Answer
B. \(-\frac{41}{40}\)
Step 1
Concept
From \(\sec^2 x=1+\tan^2 x\), \(|\sec x|=\frac{41}{40}\). In the third quadrant, \(\sec x\) is negative.
Step 2
Why this answer is correct
The correct answer is B. \(-\frac{41}{40}\). From \(\sec^2 x=1+\tan^2 x\), \(|\sec x|=\frac{41}{40}\). In the third quadrant, \(\sec x\) is negative.
Step 3
Exam Tip
\(\sec^2 x=1+\tan^2 x\) से \(|\sec x|=\frac{41}{40}\) मिलता है। तीसरे चतुर्थांश में \(\sec x\) ऋणात्मक होता है।
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यदि (x) दूसरे चतुर्थांश में है और \(\sin x=\frac{7}{25}\), तो \(\cos x\) का मान क्या है?
If (x) is in the second quadrant and \(\sin x=\frac{7}{25}\), what is the value of \(\cos x\)?
#quadrants
#cosine
#identity
A \(\frac{24}{25}\)
B \(-\frac{7}{25}\)
C \(-\frac{24}{25}\)
D \(\frac{7}{25}\)
Explanation opens after your attempt
Correct Answer
C. \(-\frac{24}{25}\)
Step 1
Concept
The identity gives \(|\cos x|=\frac{24}{25}\). In the second quadrant, \(\cos x\) is negative.
Step 2
Why this answer is correct
The correct answer is C. \(-\frac{24}{25}\). The identity gives \(|\cos x|=\frac{24}{25}\). In the second quadrant, \(\cos x\) is negative.
Step 3
Exam Tip
पहचान से \(|\cos x|=\frac{24}{25}\) मिलता है। दूसरे चतुर्थांश में \(\cos x\) ऋणात्मक होता है।
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(\cos\(\pi+x\)) किसके बराबर है?
What is (\cos\(\pi+x\)) equal to?
#allied-angles
#cosine
#quadrants
A \(\cos x\)
B \(-\cos x\)
C \(\sin x\)
D \(-\sin x\)
Explanation opens after your attempt
Correct Answer
B. \(-\cos x\)
Step 1
Concept
\(\pi+x\) is in the third quadrant and \(\cos x\) is negative there. Therefore, (\cos\(\pi+x\)=-\cos x).
Step 2
Why this answer is correct
The correct answer is B. \(-\cos x\). \(\pi+x\) is in the third quadrant and \(\cos x\) is negative there. Therefore, (\cos\(\pi+x\)=-\cos x).
Step 3
Exam Tip
\(\pi+x\) तीसरे चतुर्थांश में है और वहाँ \(\cos x\) ऋणात्मक होता है। इसलिए (\cos\(\pi+x\)=-\cos x)।
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(\sin\(\pi+x\)) किसके बराबर है?
What is (\sin\(\pi+x\)) equal to?
#allied-angles
#sine
#quadrants
A \(\sin x\)
B \(\cos x\)
C \(-\sin x\)
D \(-\cos x\)
Explanation opens after your attempt
Correct Answer
C. \(-\sin x\)
Step 1
Concept
\(\pi+x\) lies in the third quadrant and \(\sin x\) is negative there. Hence (\sin\(\pi+x\)=-\sin x).
Step 2
Why this answer is correct
The correct answer is C. \(-\sin x\). \(\pi+x\) lies in the third quadrant and \(\sin x\) is negative there. Hence (\sin\(\pi+x\)=-\sin x).
Step 3
Exam Tip
\(\pi+x\) तीसरे चतुर्थांश में आता है और वहाँ \(\sin x\) ऋणात्मक होता है। इसलिए (\sin\(\pi+x\)=-\sin x)।
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चौथे चतुर्थांश में \(\sin x\) का चिन्ह क्या होता है?
What is the sign of \(\sin x\) in the fourth quadrant?
#quadrants
#signs
#sine
A धनात्मक / Positive
B ऋणात्मक / Negative
C शून्य / Zero
D अपरिभाषित / Undefined
Explanation opens after your attempt
Correct Answer
B. ऋणात्मक / Negative
Step 1
Concept
In the fourth quadrant, \(\cos x\) and \(\sec x\) are positive. Hence \(\sin x\) is negative.
Step 2
Why this answer is correct
The correct answer is B. ऋणात्मक / Negative. In the fourth quadrant, \(\cos x\) and \(\sec x\) are positive. Hence \(\sin x\) is negative.
Step 3
Exam Tip
चौथे चतुर्थांश में \(\cos x\) और \(\sec x\) धनात्मक होते हैं। इसलिए \(\sin x\) ऋणात्मक होता है।
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तीसरे चतुर्थांश में \(\tan x\) का चिन्ह क्या होता है?
What is the sign of \(\tan x\) in the third quadrant?
#quadrants
#signs
#tangent
A ऋणात्मक / Negative
B शून्य / Zero
C धनात्मक / Positive
D अपरिभाषित / Undefined
Explanation opens after your attempt
Correct Answer
C. धनात्मक / Positive
Step 1
Concept
In the third quadrant, \(\tan x\) and \(\cot x\) are positive. The sign rule gives the answer directly.
Step 2
Why this answer is correct
The correct answer is C. धनात्मक / Positive. In the third quadrant, \(\tan x\) and \(\cot x\) are positive. The sign rule gives the answer directly.
Step 3
Exam Tip
तीसरे चतुर्थांश में \(\tan x\) और \(\cot x\) धनात्मक होते हैं। संकेत नियम से उत्तर सीधे मिलता है।
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दूसरे चतुर्थांश में \(\cos x\) का चिन्ह क्या होता है?
What is the sign of \(\cos x\) in the second quadrant?
#quadrants
#signs
#cosine
A धनात्मक / Positive
B ऋणात्मक / Negative
C शून्य / Zero
D अपरिभाषित / Undefined
Explanation opens after your attempt
Correct Answer
B. ऋणात्मक / Negative
Step 1
Concept
In the second quadrant, only \(\sin x\) and \(\cosec x\) are positive. Therefore, \(\cos x\) is negative.
Step 2
Why this answer is correct
The correct answer is B. ऋणात्मक / Negative. In the second quadrant, only \(\sin x\) and \(\cosec x\) are positive. Therefore, \(\cos x\) is negative.
Step 3
Exam Tip
दूसरे चतुर्थांश में केवल \(\sin x\) और \(\cosec x\) धनात्मक होते हैं। इसलिए \(\cos x\) ऋणात्मक होता है।
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पहले चतुर्थांश में \(\sin x\) का चिन्ह क्या होता है?
What is the sign of \(\sin x\) in the first quadrant?
#quadrants
#signs
#sine
A ऋणात्मक / Negative
B शून्य / Zero
C धनात्मक / Positive
D अपरिभाषित / Undefined
Explanation opens after your attempt
Correct Answer
C. धनात्मक / Positive
Step 1
Concept
In the first quadrant, all trigonometric functions are positive. Remember the quadrant sign table.
Step 2
Why this answer is correct
The correct answer is C. धनात्मक / Positive. In the first quadrant, all trigonometric functions are positive. Remember the quadrant sign table.
Step 3
Exam Tip
पहले चतुर्थांश में सभी त्रिकोणमितीय फलन धनात्मक होते हैं। चतुर्थांश संकेत तालिका याद रखें।
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\(200^\circ\) कोण किस चतुर्थांश में आता है?
In which quadrant does \(200^\circ\) lie?
#trigonometric-functions
#angles
#quadrants
A प्रथम चतुर्थांश / First quadrant
B द्वितीय चतुर्थांश / Second quadrant
C तृतीय चतुर्थांश / Third quadrant
D चतुर्थ चतुर्थांश / Fourth quadrant
Explanation opens after your attempt
Correct Answer
C. तृतीय चतुर्थांश / Third quadrant
Step 1
Concept
\(200^\circ\) lies between \(180^\circ\) and \(270^\circ\) so it is in the third quadrant. Remember the standard quadrant intervals.
Step 2
Why this answer is correct
The correct answer is C. तृतीय चतुर्थांश / Third quadrant. \(200^\circ\) lies between \(180^\circ\) and \(270^\circ\) so it is in the third quadrant. Remember the standard quadrant intervals.
Step 3
Exam Tip
\(200^\circ\) \(180^\circ\) और \(270^\circ\) के बीच है इसलिए तृतीय चतुर्थांश में है। चतुर्थांश के लिए मानक सीमाएं याद रखें।
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\(210^\circ\) किस चतुर्थांश में स्थित है?
In which quadrant does \(210^\circ\) lie?
#trigonometry
#angles
#quadrants
A पहला चतुर्थांश / First quadrant
B दूसरा चतुर्थांश / Second quadrant
C तीसरा चतुर्थांश / Third quadrant
D चौथा चतुर्थांश / Fourth quadrant
Explanation opens after your attempt
Correct Answer
C. तीसरा चतुर्थांश / Third quadrant
Step 1
Concept
\(210^\circ\) lies between \(180^\circ\) and \(270^\circ\), so it is in the third quadrant. Remember the boundary angles.
Step 2
Why this answer is correct
The correct answer is C. तीसरा चतुर्थांश / Third quadrant. \(210^\circ\) lies between \(180^\circ\) and \(270^\circ\), so it is in the third quadrant. Remember the boundary angles.
Step 3
Exam Tip
\(210^\circ\), \(180^\circ\) और \(270^\circ\) के बीच है इसलिए तीसरे चतुर्थांश में है। सीमा कोणों को याद रखें।
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किस फलन का ग्राफ दूसरे और चौथे चतुर्थांश में दो शाखाओं वाला होता है?
Which function has a graph with two branches in the second and fourth quadrants?
#graphs
#reciprocal
#quadrants
A \(y=-\frac{1}{x}\)
B \(y=\frac{1}{x}\)
C \(y=\frac{1}{x^2}\)
D \(y=x^2\)
Explanation opens after your attempt
Correct Answer
A. \(y=-\frac{1}{x}\)
Step 1
Concept
In \(y=-\frac{1}{x}\), (x) and (y) have opposite signs. In exams, connect the negative reciprocal graph with the second and fourth quadrants.
Step 2
Why this answer is correct
The correct answer is A. \(y=-\frac{1}{x}\). In \(y=-\frac{1}{x}\), (x) and (y) have opposite signs. In exams, connect the negative reciprocal graph with the second and fourth quadrants.
Step 3
Exam Tip
\(y=-\frac{1}{x}\) में (x) और (y) के चिह्न विपरीत होते हैं। परीक्षा में ऋणात्मक पारस्परिक ग्राफ को दूसरे और चौथे चतुर्थांश से जोड़ें।
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किस फलन का ग्राफ पहले और दूसरे चतुर्थांश में है लेकिन (x=0) पर परिभाषित नहीं है?
Which function has a graph in the first and second quadrants but is not defined at (x=0)?
#graphs
#reciprocal-square
#quadrants
A \(y=\frac{1}{x^2}\)
B \(y=x^2\)
C (y=|x|)
D \(y=\sqrt{x}\)
Explanation opens after your attempt
Correct Answer
A. \(y=\frac{1}{x^2}\)
Step 1
Concept
\(\frac{1}{x^2}>0\) for \(x\ne0\), so the graph stays above and is undefined at (x=0). In exams, remember positive branches on both sides when \(x^2\) is in the denominator.
Step 2
Why this answer is correct
The correct answer is A. \(y=\frac{1}{x^2}\). \(\frac{1}{x^2}>0\) for \(x\ne0\), so the graph stays above and is undefined at (x=0). In exams, remember positive branches on both sides when \(x^2\) is in the denominator.
Step 3
Exam Tip
\(\frac{1}{x^2}>0\) जब \(x\ne0\) इसलिए ग्राफ ऊपर रहता है और (x=0) पर परिभाषित नहीं। परीक्षा में हर में \(x^2\) होने पर दोनों ओर धनात्मक शाखाएं याद रखें।
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फलन (f(x)=\frac{2}{x}) का आलेख किन चतुर्थांशों में होता है?
In which quadrants does the graph of (f(x)=\frac{2}{x}) lie?
#standard-functions
#reciprocal-function
#quadrants
A प्रथम और तृतीय / First and third
B द्वितीय और चतुर्थ / Second and fourth
C केवल प्रथम / Only first
D केवल चतुर्थ / Only fourth
Explanation opens after your attempt
Correct Answer
A. प्रथम और तृतीय / First and third
Step 1
Concept
In \(\frac{2}{x}\), (x) and (y) have the same sign. So the graph lies in the first and third quadrants.
Step 2
Why this answer is correct
The correct answer is A. प्रथम और तृतीय / First and third. In \(\frac{2}{x}\), (x) and (y) have the same sign. So the graph lies in the first and third quadrants.
Step 3
Exam Tip
\(\frac{2}{x}\) में (x) और (y) के चिह्न समान होते हैं। इसलिए ग्राफ प्रथम और तृतीय चतुर्थांश में होता है।
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फलन (f(x)=x) का आलेख किस चतुर्थांश से होकर गुजरता है?
Through which quadrants does the graph of (f(x)=x) pass?
#standard-functions
#identity-function
#quadrants
A प्रथम और द्वितीय / First and second
B प्रथम और तृतीय / First and third
C द्वितीय और चतुर्थ / Second and fourth
D तृतीय और चतुर्थ / Third and fourth
Explanation opens after your attempt
Correct Answer
B. प्रथम और तृतीय / First and third
Step 1
Concept
In (y=x), (x) and (y) have the same sign. So the line passes through the first and third quadrants.
Step 2
Why this answer is correct
The correct answer is B. प्रथम और तृतीय / First and third. In (y=x), (x) and (y) have the same sign. So the line passes through the first and third quadrants.
Step 3
Exam Tip
(y=x) में (x) और (y) के चिह्न समान होते हैं। इसलिए रेखा प्रथम और तृतीय चतुर्थांश से गुजरती है।
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