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quadratic equations MCQ Questions for Class 10

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1750 questions tagged with quadratic equations.

Question 61/1750 Medium Mathematics Quadratic Equations Word Problems and Applications Class 10 Level 42

एक बस (180,किमी) की दूरी तय करती है। गति (15,किमी/घंटा) कम करने पर समय (1,घंटा) बढ़ जाता है। मूल गति क्या थी?

A bus covers (180,km). If its speed is reduced by (15,km/h), the time increases by (1,hour). What was the original speed?

Explanation opens after your attempt
Correct Answer

D. \((60,\text{किमी\)घंटा}) / (60,km / h)

Step 1

Concept

If the speed is (x), then \(\frac{180}{x-15}-\frac{180}{x}=1\). Solving gives (x=60).

Step 2

Why this answer is correct

The correct answer is D. (60,किमी / घंटा) / (60,km / h\(). If the speed is (x), then (\frac{180}{x-15}-\frac{180}{x}=1). Solving gives (x=60).\)

Step 3

Exam Tip

यदि गति (x) है तो \(\frac{180}{x-15}-\frac{180}{x}=1\)। हल से (x=60) है।

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Question 62/1750 Medium Mathematics Quadratic Equations Word Problems and Applications Class 10 Level 42

दो व्यक्तियों की आयुओं का योग (30) वर्ष और गुणनफल (216) है। उनकी आयु क्या है?

The sum of the ages of two people is (30) years and their product is (216). What are their ages?

Explanation opens after your attempt
Correct Answer

C. (12) वर्ष और (18) वर्ष(12) years and (18) years

Step 1

Concept

If one age is (x), the other is (30-x). From (x(30-x)=216), we get (12) and (18).

Step 2

Why this answer is correct

The correct answer is C. (12) वर्ष और (18) वर्ष / (12) years and (18) years. If one age is (x), the other is (30-x). From (x(30-x)=216), we get (12) and (18).

Step 3

Exam Tip

यदि एक आयु (x) है तो दूसरी (30-x) है। (x(30-x)=216) से (12) और (18) मिलते हैं।

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Question 63/1750 Medium Mathematics Quadratic Equations Word Problems and Applications Class 10 Level 42

एक धनात्मक संख्या और उसके व्युत्क्रम का अंतर \(\frac{3}{2}\) है। संख्या क्या है?

The difference between a positive number and its reciprocal is \(\frac{3}{2}\). What is the number?

Explanation opens after your attempt
Correct Answer

C. (2)

Step 1

Concept

The equation is \(x-\frac{1}{x}=\frac{3}{2}\). It gives \(2x^2-3x-2=0\) and (x=2).

Step 2

Why this answer is correct

The correct answer is C. (2). The equation is \(x-\frac{1}{x}=\frac{3}{2}\). It gives \(2x^2-3x-2=0\) and (x=2).

Step 3

Exam Tip

समीकरण \(x-\frac{1}{x}=\frac{3}{2}\) है। इससे \(2x^2-3x-2=0\) और (x=2) मिलता है।

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Question 64/1750 Medium Mathematics Quadratic Equations Word Problems and Applications Class 10 Level 42

एक समकोण त्रिभुज की भुजाएँ (x), (x+7) और कर्ण (x+8) हैं। छोटी भुजा क्या है?

The sides of a right triangle are (x), (x+7), and hypotenuse (x+8). What is the smallest side?

Explanation opens after your attempt
Correct Answer

B. (5)

Step 1

Concept

By Pythagoras, (x-2+(x+7)2=(x+8)2). Solving gives (x=5).

Step 2

Why this answer is correct

The correct answer is B. (5). By Pythagoras, (x-2+(x+7)2=(x+8)2). Solving gives (x=5).

Step 3

Exam Tip

पाइथागोरस से (x-2+(x+7)2=(x+8)2)। हल करने पर (x=5) है।

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Question 65/1750 Medium Mathematics Quadratic Equations Word Problems and Applications Class 10 Level 42

(3) के दो क्रमागत धनात्मक गुणजों का गुणनफल (270) है। वे गुणज कौन से हैं?

The product of two consecutive positive multiples of (3) is (270). Which multiples are they?

Explanation opens after your attempt
Correct Answer

C. (15) और (18)(15) and (18)

Step 1

Concept

Let the multiples be (x) and (x+3). From (x(x+3)=270), we get (x=15).

Step 2

Why this answer is correct

The correct answer is C. (15) और (18) / (15) and (18). Let the multiples be (x) and (x+3). From (x(x+3)=270), we get (x=15).

Step 3

Exam Tip

गुणज (x) और (x+3) मानें। (x(x+3)=270) से (x=15) मिलता है।

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Question 66/1750 Medium Mathematics Quadratic Equations Word Problems and Applications Class 10 Level 42

एक समकोण त्रिभुज का कर्ण (17,सेमी) है और एक भुजा दूसरी से (7,सेमी) अधिक है। छोटी भुजा क्या है?

The hypotenuse of a right triangle is (17,cm) and one side is (7,cm) more than the other. What is the smaller side?

Explanation opens after your attempt
Correct Answer

C. (8,सेमी)(8,cm)

Step 1

Concept

If the smaller side is (x), then (x-2+(x+7)2=172). This gives (x=8).

Step 2

Why this answer is correct

The correct answer is C. (8,सेमी) / (8,cm\(). If the smaller side is (x), then (x^2+(x+7)^2=17^2). This gives (x=8).\)

Step 3

Exam Tip

छोटी भुजा (x) हो तो (x-2+(x+7)2=172)। इससे (x=8) मिलता है।

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Question 67/1750 Medium Mathematics Quadratic Equations Word Problems and Applications Class 10 Level 42

(720) रुपये में कुछ कॉपियाँ खरीदी गईं। यदि प्रत्येक कॉपी (6) रुपये सस्ती हो जाए तो (4) कॉपियाँ अधिक मिलती हैं। मूल प्रति कॉपी मूल्य क्या था?

Some notebooks are bought for (720) rupees. If each notebook becomes (6) rupees cheaper, (4) more notebooks can be bought. What was the original price per notebook?

Explanation opens after your attempt
Correct Answer

C. (36) रुपये(36) rupees

Step 1

Concept

If the original price is (x), then \(\frac{720}{x-6}-\frac{720}{x}=4\). This gives (x=36).

Step 2

Why this answer is correct

The correct answer is C. (36) रुपये / (36) rupees. If the original price is (x), then \(\frac{720}{x-6}-\frac{720}{x}=4\). This gives (x=36).

Step 3

Exam Tip

मूल मूल्य (x) हो तो \(\frac{720}{x-6}-\frac{720}{x}=4\)। इससे (x=36) मिलता है।

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Question 68/1750 Medium Mathematics Quadratic Equations Word Problems and Applications Class 10 Level 42

एक आयत की लंबाई उसकी चौड़ाई के (2) गुने से (2,मी) अधिक है। क्षेत्रफल \(180,मी^2\) है। चौड़ाई क्या है?

The length of a rectangle is (2,m) more than twice its breadth. Its area is (180,m\(^2). What is the breadth\)?

Explanation opens after your attempt
Correct Answer

C. (9,मी)(9,m)

Step 1

Concept

If breadth is (x), then (x(2x+2)=180). This gives (x=9).

Step 2

Why this answer is correct

The correct answer is C. (9,मी) / (9,m\(). If breadth is (x), then (x(2x+2)=180). This gives (x=9).\)

Step 3

Exam Tip

यदि चौड़ाई (x) है तो (x(2x+2)=180)। इससे (x=9) मिलता है।

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Question 69/1750 Medium Mathematics Quadratic Equations Word Problems and Applications Class 10 Level 42

एक वाहन (150,किमी) की दूरी तय करता है। गति (5,किमी/घंटा) बढ़ाने पर समय (1,घंटा) कम हो जाता है। मूल गति क्या थी?

A vehicle covers (150,km). When its speed is increased by (5,km/h), the time decreases by (1,hour). What was the original speed?

Explanation opens after your attempt
Correct Answer

B. \((25,\text{किमी\)घंटा}) / (25,km / h)

Step 1

Concept

If the speed is (x), then \(\frac{150}{x}-\frac{150}{x+5}=1\). Solving gives (x=25).

Step 2

Why this answer is correct

The correct answer is B. (25,किमी / घंटा) / (25,km / h\(). If the speed is (x), then (\frac{150}{x}-\frac{150}{x+5}=1). Solving gives (x=25).\)

Step 3

Exam Tip

यदि गति (x) है तो \(\frac{150}{x}-\frac{150}{x+5}=1\)। हल करने पर (x=25) मिलता है।

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Question 70/1750 Medium Mathematics Quadratic Equations Word Problems and Applications Class 10 Level 42

दो पाइप अलग-अलग टंकी को (x) घंटे और (x+4) घंटे में भरते हैं। दोनों मिलकर टंकी को \(\frac{24}{5}\) घंटे में भरते हैं। तेज पाइप कितने घंटे में भरेगा?

Two pipes fill a tank separately in (x) hours and (x+4) hours. Together they fill the tank in \(\frac{24}{5}\) hours. In how many hours will the faster pipe fill it?

Explanation opens after your attempt
Correct Answer

B. (8) घंटे(8) hours

Step 1

Concept

The equation is \(\frac{1}{x}+\frac{1}{x+4}=\frac{5}{24}\). Solving gives (x=8).

Step 2

Why this answer is correct

The correct answer is B. (8) घंटे / (8) hours. The equation is \(\frac{1}{x}+\frac{1}{x+4}=\frac{5}{24}\). Solving gives (x=8).

Step 3

Exam Tip

समीकरण \(\frac{1}{x}+\frac{1}{x+4}=\frac{5}{24}\) है। हल से (x=8) है।

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Question 71/1750 Medium Mathematics Quadratic Equations Word Problems and Applications Class 10 Level 42

एक काम को (A) अकेला (x) दिनों में करता है और (B) अकेला (x+3) दिनों में करता है। दोनों मिलकर (2) दिनों में काम पूरा करते हैं। (A) अकेला कितने दिन लेगा?

Worker (A) alone completes a work in (x) days and worker (B) alone completes it in (x+3) days. Together they finish it in (2) days. How many days will (A) alone take?

Explanation opens after your attempt
Correct Answer

A. (3) दिन(3) days

Step 1

Concept

The equation is \(\frac{1}{x}+\frac{1}{x+3}=\frac{1}{2}\). This gives (x=3).

Step 2

Why this answer is correct

The correct answer is A. (3) दिन / (3) days. The equation is \(\frac{1}{x}+\frac{1}{x+3}=\frac{1}{2}\). This gives (x=3).

Step 3

Exam Tip

समीकरण \(\frac{1}{x}+\frac{1}{x+3}=\frac{1}{2}\) है। इससे (x=3) मिलता है।

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Question 72/1750 Medium Mathematics Quadratic Equations Word Problems and Applications Class 10 Level 42

एक बेटे की वर्तमान आयु (x) वर्ष है और पिता उससे (28) वर्ष बड़े हैं। (4) वर्ष बाद उनकी आयुओं का गुणनफल (960) होगा। बेटे की वर्तमान आयु क्या है?

A son's present age is (x) years and his father is (28) years older. After (4) years, the product of their ages will be (960). What is the son's present age?

Explanation opens after your attempt
Correct Answer

C. (16) वर्ष(16) years

Step 1

Concept

The equation is ((x+4)(x+32)=960). The positive solution is (x=16).

Step 2

Why this answer is correct

The correct answer is C. (16) वर्ष / (16) years. The equation is ((x+4)(x+32)=960). The positive solution is (x=16).

Step 3

Exam Tip

समीकरण ((x+4)(x+32)=960) है। धनात्मक हल (x=16) है।

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Question 73/1750 Medium Mathematics Quadratic Equations Word Problems and Applications Class 10 Level 42

दो धनात्मक संख्याओं में अंतर (9) है और उनके वर्गों का योग (585) है। छोटी संख्या क्या है?

Two positive numbers differ by (9) and the sum of their squares is (585). What is the smaller number?

Explanation opens after your attempt
Correct Answer

C. (12)

Step 1

Concept

If the smaller number is (x), then (x-2+(x+9)2=585). This gives (x=12).

Step 2

Why this answer is correct

The correct answer is C. (12). If the smaller number is (x), then (x-2+(x+9)2=585). This gives (x=12).

Step 3

Exam Tip

छोटी संख्या (x) हो तो (x-2+(x+9)2=585)। इससे (x=12) मिलता है।

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Question 74/1750 Medium Mathematics Quadratic Equations Word Problems and Applications Class 10 Level 42

एक संख्या और उससे (4) अधिक संख्या का गुणनफल (221) है। छोटी संख्या क्या है?

The product of a number and the number (4) more than it is (221). What is the smaller number?

Explanation opens after your attempt
Correct Answer

C. (13)

Step 1

Concept

The equation is (x(x+4)=221). The positive solution is (x=13).

Step 2

Why this answer is correct

The correct answer is C. (13). The equation is (x(x+4)=221). The positive solution is (x=13).

Step 3

Exam Tip

समीकरण (x(x+4)=221) है। धनात्मक हल (x=13) है।

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Question 75/1750 Medium Mathematics Quadratic Equations Word Problems and Applications Class 10 Level 42

दो धनात्मक संख्याओं का योग (19) और गुणनफल (84) है। वे संख्याएँ कौन सी हैं?

The sum of two positive numbers is (19) and their product is (84). Which numbers are they?

Explanation opens after your attempt
Correct Answer

B. (7) और (12)(7) and (12)

Step 1

Concept

If one number is (x), the other is (19-x). From (x(19-x)=84), we get (7) and (12).

Step 2

Why this answer is correct

The correct answer is B. (7) और (12) / (7) and (12). If one number is (x), the other is (19-x). From (x(19-x)=84), we get (7) and (12).

Step 3

Exam Tip

यदि एक संख्या (x) है तो दूसरी (19-x) है। (x(19-x)=84) से (7) और (12) मिलते हैं।

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Question 76/1750 Medium Mathematics Quadratic Equations Word Problems and Applications Class 10 Level 42

एक किसान (120,मी) बाड़ से आयताकार खेत बनाता है जिसका क्षेत्रफल \(875,मी^2\) है। खेत के आयाम क्या हैं?

A farmer uses (120,m) of fencing to make a rectangular field of area (875,m\(^2). What are the dimensions of the field\)?

Explanation opens after your attempt
Correct Answer

B. (25,मी) और (35,मी)(25,m) and (35,m)

Step 1

Concept

Here (l+b=60) and (lb=875). From (x(60-x)=875), we get (25) and (35).

Step 2

Why this answer is correct

The correct answer is B. (25,मी) और (35,मी) / (25,m) and (35,m\(). Here (l+b=60) and (lb=875). From (x(60-x)=875), we get (25) and (35).\)

Step 3

Exam Tip

यहाँ (l+b=60) और (lb=875) है। (x(60-x)=875) से (25) और (35) मिलते हैं।

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Question 77/1750 Medium Mathematics Quadratic Equations Word Problems and Applications Class 10 Level 42

एक धनात्मक संख्या के वर्ग और उसके (5) गुने का योग (84) है। संख्या क्या है?

The sum of the square of a positive number and (5) times the number is (84). What is the number?

Explanation opens after your attempt
Correct Answer

B. (7)

Step 1

Concept

The equation is \(x^2+5x=84\). It gives (x=7) or (x=-12), so the answer is (7).

Step 2

Why this answer is correct

The correct answer is B. (7). The equation is \(x^2+5x=84\). It gives (x=7) or (x=-12), so the answer is (7).

Step 3

Exam Tip

समीकरण \(x^2+5x=84\) है। इससे (x=7) या (x=-12) मिलता है और उत्तर (7) है।

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Question 78/1750 Medium Mathematics Quadratic Equations Word Problems and Applications Class 10 Level 42

एक (12,सेमी) लंबी और (8,सेमी) चौड़ी तस्वीर के चारों ओर समान चौड़ाई का फ्रेम है। अंदर की तस्वीर का क्षेत्रफल \(60,सेमी^2\) बचता है। फ्रेम की चौड़ाई क्या है?

A photograph frame has outside length (12,cm) and breadth (8,cm). A uniform border leaves an inside photo area of (60,cm\(^2). What is the width of the frame\)?

Explanation opens after your attempt
Correct Answer

A. (1,सेमी)(1,cm)

Step 1

Concept

If the width is (x), then ((12-2x)(8-2x)=60). The suitable solution is (x=1).

Step 2

Why this answer is correct

The correct answer is A. (1,सेमी) / (1,cm\(). If the width is (x), then ((12-2x)(8-2x)=60). The suitable solution is (x=1).\)

Step 3

Exam Tip

यदि चौड़ाई (x) है तो ((12-2x)(8-2x)=60)। उचित हल (x=1) है।

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Question 79/1750 Medium Mathematics Quadratic Equations Word Problems and Applications Class 10 Level 42

एक कक्षा में पंक्तियों की संख्या (x) है। प्रत्येक पंक्ति में विद्यार्थियों की संख्या पंक्तियों से (3) अधिक है और कुल विद्यार्थी (154) हैं। पंक्तियों की संख्या क्या है?

In a class, the number of rows is (x). Each row has (3) more students than the number of rows and the total number of students is (154). What is the number of rows?

Explanation opens after your attempt
Correct Answer

C. (11)

Step 1

Concept

The equation is (x(x+3)=154). The positive solution is (x=11).

Step 2

Why this answer is correct

The correct answer is C. (11). The equation is (x(x+3)=154). The positive solution is (x=11).

Step 3

Exam Tip

समीकरण (x(x+3)=154) है। धनात्मक हल (x=11) है।

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Question 80/1750 Medium Mathematics Quadratic Equations Word Problems and Applications Class 10 Level 42

एक आयत का विकर्ण (25,सेमी) है और लंबाई चौड़ाई से (5,सेमी) अधिक है। चौड़ाई क्या है?

The diagonal of a rectangle is (25,cm) and its length is (5,cm) more than its breadth. What is the breadth?

Explanation opens after your attempt
Correct Answer

C. (15,सेमी)(15,cm)

Step 1

Concept

If breadth is (x), then (x-2+(x+5)2=252). Solving gives (x=15).

Step 2

Why this answer is correct

The correct answer is C. (15,सेमी) / (15,cm\(). If breadth is (x), then (x^2+(x+5)^2=25^2). Solving gives (x=15).\)

Step 3

Exam Tip

यदि चौड़ाई (x) है तो (x-2+(x+5)2=252)। हल करने पर (x=15) मिलता है।

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Question 81/1750 Medium Mathematics Quadratic Equations Word Problems and Applications Class 10 Level 42

दो क्रमागत धनात्मक सम संख्याओं का गुणनफल (224) है। वे संख्याएँ कौन सी हैं?

The product of two consecutive positive even numbers is (224). Which numbers are they?

Explanation opens after your attempt
Correct Answer

C. (14) और (16)(14) and (16)

Step 1

Concept

Let the numbers be (x) and (x+2). From (x(x+2)=224), (x=14).

Step 2

Why this answer is correct

The correct answer is C. (14) और (16) / (14) and (16). Let the numbers be (x) and (x+2). From (x(x+2)=224), (x=14).

Step 3

Exam Tip

संख्याएँ (x) और (x+2) मानें। (x(x+2)=224) से (x=14) है।

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Question 82/1750 Medium Mathematics Quadratic Equations Word Problems and Applications Class 10 Level 42

दो क्रमागत प्राकृतिक संख्याओं के वर्गों का योग (365) है। वे संख्याएँ कौन सी हैं?

The sum of the squares of two consecutive natural numbers is (365). Which numbers are they?

Explanation opens after your attempt
Correct Answer

C. (13) और (14)(13) and (14)

Step 1

Concept

Take the numbers as (x) and (x+1). From (x-2+(x+1)2=365), we get (x=13).

Step 2

Why this answer is correct

The correct answer is C. (13) और (14) / (13) and (14). Take the numbers as (x) and (x+1). From (x-2+(x+1)2=365), we get (x=13).

Step 3

Exam Tip

संख्याएँ (x) और (x+1) लें। (x-2+(x+1)2=365) से (x=13) मिलता है।

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Question 83/1750 Medium Mathematics Quadratic Equations Word Problems and Applications Class 10 Level 42

दो धनात्मक संख्याओं में अंतर (6) है और उनका गुणनफल (216) है। छोटी संख्या क्या है?

Two positive numbers differ by (6) and their product is (216). What is the smaller number?

Explanation opens after your attempt
Correct Answer

C. (12)

Step 1

Concept

If the smaller number is (x), then (x(x+6)=216). The positive solution is (x=12).

Step 2

Why this answer is correct

The correct answer is C. (12). If the smaller number is (x), then (x(x+6)=216). The positive solution is (x=12).

Step 3

Exam Tip

छोटी संख्या (x) हो तो (x(x+6)=216)। धनात्मक हल (x=12) है।

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Question 84/1750 Medium Mathematics Quadratic Equations Word Problems and Applications Class 10 Level 42

एक नाव (48,किमी) धारा के विरुद्ध जाने में धारा के साथ जाने की तुलना में (3,घंटे) अधिक लेती है। धारा की चाल (4,किमी/घंटा) है। शांत जल में नाव की चाल क्या है?

A boat takes (3,hours) more to travel (48,km) upstream than downstream. The speed of the stream is (4,km/h). What is the speed of the boat in still water?

Explanation opens after your attempt
Correct Answer

B. \((12,\text{किमी\)घंटा}) / (12,km / h)

Step 1

Concept

If the still-water speed is (x), then \(\frac{48}{x-4}-\frac{48}{x+4}=3\). This gives (x=12).

Step 2

Why this answer is correct

The correct answer is B. (12,किमी / घंटा) / (12,km / h\(). If the still-water speed is (x), then (\frac{48}{x-4}-\frac{48}{x+4}=3). This gives (x=12).\)

Step 3

Exam Tip

यदि शांत जल की चाल (x) है तो \(\frac{48}{x-4}-\frac{48}{x+4}=3\)। इससे (x=12) मिलता है।

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Question 85/1750 Medium Mathematics Quadratic Equations Word Problems and Applications Class 10 Level 42

एक वस्तु पर (1200) रुपये खर्च होते हैं। यदि प्रति वस्तु मूल्य (10) रुपये कम हो जाए तो उसी धन से (4) वस्तुएँ अधिक मिलती हैं। मूल प्रति वस्तु मूल्य क्या था?

A total of (1200) rupees is spent on some items. If the price per item decreases by (10) rupees, (4) more items can be bought for the same money. What was the original price per item?

Explanation opens after your attempt
Correct Answer

B. (60) रुपये(60) rupees

Step 1

Concept

If original price is (x), then \(\frac{1200}{x-10}-\frac{1200}{x}=4\). Solving gives (x=60).

Step 2

Why this answer is correct

The correct answer is B. (60) रुपये / (60) rupees. If original price is (x), then \(\frac{1200}{x-10}-\frac{1200}{x}=4\). Solving gives (x=60).

Step 3

Exam Tip

मूल मूल्य (x) हो तो \(\frac{1200}{x-10}-\frac{1200}{x}=4\)। हल करने पर (x=60) मिलता है।

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Question 86/1750 Medium Mathematics Quadratic Equations Word Problems and Applications Class 10 Level 42

एक आयताकार पार्क का परिमाप (50,मी) और क्षेत्रफल \(150,मी^2\) है। उसके आयाम क्या हैं?

A rectangular park has perimeter (50,m) and area (150,m\(^2). What are its dimensions\)?

Explanation opens after your attempt
Correct Answer

C. (10,मी) और (15,मी)(10,m) and (15,m)

Step 1

Concept

Here (l+b=25) and (lb=150). From (x(25-x)=150), the dimensions are (10) and (15).

Step 2

Why this answer is correct

The correct answer is C. (10,मी) और (15,मी) / (10,m) and (15,m\(). Here (l+b=25) and (lb=150). From (x(25-x)=150), the dimensions are (10) and (15).\)

Step 3

Exam Tip

यहाँ (l+b=25) और (lb=150) है। (x(25-x)=150) से आयाम (10) और (15) हैं।

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Question 87/1750 Medium Mathematics Quadratic Equations Word Problems and Applications Class 10 Level 42

एक सीढ़ी दीवार से टिकाई गई है। उसका पाद दीवार से (x,मी) दूर है और दीवार पर ऊँचाई (x+7,मी) है। सीढ़ी की लंबाई (13,मी) है। पाद की दूरी क्या है?

A ladder is placed against a wall. Its foot is (x,m) from the wall and the height on the wall is (x+7,m). The ladder is (13,m) long. What is the foot distance?

Explanation opens after your attempt
Correct Answer

A. (5,मी)(5,m)

Step 1

Concept

In the right triangle, (x-2+(x+7)2=132). Solving gives (x=5).

Step 2

Why this answer is correct

The correct answer is A. (5,मी) / (5,m\(). In the right triangle, (x^2+(x+7)^2=13^2). Solving gives (x=5).\)

Step 3

Exam Tip

समकोण त्रिभुज में (x-2+(x+7)2=132)। हल से (x=5) मिलता है।

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Question 88/1750 Medium Mathematics Quadratic Equations Word Problems and Applications Class 10 Level 42

एक त्रिभुज का क्षेत्रफल \(60,सेमी^2\) है। उसका आधार ऊँचाई से (4,सेमी) अधिक है। ऊँचाई क्या है?

The area of a triangle is (60,cm\(^2). Its base is (4\),cm) more than its height. What is the height?

Explanation opens after your attempt
Correct Answer

B. (10,सेमी)(10,cm)

Step 1

Concept

If height is (x), then (\frac{1}{2}x(x+4)=60). Hence (x=10).

Step 2

Why this answer is correct

The correct answer is B. (10,सेमी) / (10,cm\(). If height is (x), then (\frac{1}{2}x(x+4)=60). Hence (x=10).\)

Step 3

Exam Tip

यदि ऊँचाई (x) है तो (\frac{1}{2}x(x+4)=60)। इसलिए (x=10) है।

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Question 89/1750 Medium Mathematics Quadratic Equations Word Problems and Applications Class 10 Level 42

एक धनात्मक संख्या का वर्ग उसके (3) गुने से (28) अधिक है। संख्या क्या है?

The square of a positive number is (28) more than (3) times the number. What is the number?

Explanation opens after your attempt
Correct Answer

C. (7)

Step 1

Concept

The equation is \(x^2=3x+28\). It gives (x=7) or (x=-4), so the positive answer is (7).

Step 2

Why this answer is correct

The correct answer is C. (7). The equation is \(x^2=3x+28\). It gives (x=7) or (x=-4), so the positive answer is (7).

Step 3

Exam Tip

समीकरण \(x^2=3x+28\) है। इससे (x=7) या (x=-4) मिलता है और धनात्मक उत्तर (7) है।

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Question 90/1750 Medium Mathematics Quadratic Equations Word Problems and Applications Class 10 Level 42

एक धनात्मक संख्या और उसके व्युत्क्रम का योग \(\frac{5}{2}\) है। वह संख्या क्या हो सकती है?

The sum of a positive number and its reciprocal is \(\frac{5}{2}\). What can the number be?

Explanation opens after your attempt
Correct Answer

C. (2) या \(\frac{1}{2}\)(2) or \(\frac{1}{2}\)

Step 1

Concept

The equation \(x+\frac{1}{x}=\frac{5}{2}\) gives \(2x^2-5x+2=0\). The solutions are (x=2) or \(x=\frac{1}{2}\).

Step 2

Why this answer is correct

The correct answer is C. (2) या \(\frac{1}{2}\) / (2) or \(\frac{1}{2}\). The equation \(x+\frac{1}{x}=\frac{5}{2}\) gives \(2x^2-5x+2=0\). The solutions are (x=2) or \(x=\frac{1}{2}\).

Step 3

Exam Tip

समीकरण \(x+\frac{1}{x}=\frac{5}{2}\) से \(2x^2-5x+2=0\) बनता है। हल (x=2) या \(x=\frac{1}{2}\) हैं।

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