Concept-wise Practice
diagonal MCQ Questions for Class 10
diagonal se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.
Practice Questions
5 questions tagged with diagonal.
एक आयत का विकर्ण (25,सेमी) है और लंबाई चौड़ाई से (5,सेमी) अधिक है। चौड़ाई क्या है?
The diagonal of a rectangle is (25,cm) and its length is (5,cm) more than its breadth. What is the breadth?
Explanation opens after your attempt
Correct Answer
C. (15,सेमी)/(15,cm)
Step 1
Concept
If breadth is (x), then (x-2+(x+5)2=252). Solving gives (x=15).
Step 2
Why this answer is correct
The correct answer is C. (15,सेमी) / (15,cm\(). If breadth is (x), then (x^2+(x+5)^2=25^2). Solving gives (x=15).\)
Step 3
Exam Tip
यदि चौड़ाई (x) है तो (x-2+(x+5)2=252)। हल करने पर (x=15) मिलता है।
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एक आयत की लंबाई चौड़ाई से (15) मीटर अधिक है और विकर्ण (75) मीटर है। चौड़ाई क्या है?
A rectangle has length (15) m more than its breadth and diagonal (75) m. What is the breadth?
Explanation opens after your attempt
Correct Answer
A. (45) मीटर/(45) m
Step 1
Concept
If breadth is (x), then (x-2+(x+15)2=752), giving (x=45). Use Pythagoras for a rectangle with a diagonal.
Step 2
Why this answer is correct
The correct answer is A. (45) मीटर / (45) m. If breadth is (x), then (x-2+(x+15)2=752), giving (x=45). Use Pythagoras for a rectangle with a diagonal.
Step 3
Exam Tip
चौड़ाई (x) हो तो (x-2+(x+15)2=752), जिससे (x=45) है। विकर्ण वाले आयत में पाइथागोरस प्रमेय लगाएँ।
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एक आयत की लंबाई चौड़ाई से (7) मीटर अधिक है और विकर्ण (97) मीटर है। चौड़ाई क्या है?
A rectangle has length (7) m more than its breadth and diagonal (97) m. What is the breadth?
Explanation opens after your attempt
Correct Answer
C. (65) मीटर/(65) m
Step 1
Concept
If breadth is (x), then (x-2+(x+7)2=972), giving (x=65). Use Pythagoras for a rectangle with a diagonal.
Step 2
Why this answer is correct
The correct answer is C. (65) मीटर / (65) m. If breadth is (x), then (x-2+(x+7)2=972), giving (x=65). Use Pythagoras for a rectangle with a diagonal.
Step 3
Exam Tip
चौड़ाई (x) हो तो (x-2+(x+7)2=972), जिससे (x=65) है। विकर्ण वाले आयत में पाइथागोरस प्रमेय लगाएँ।
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एक आयत की लंबाई चौड़ाई से (10) मीटर अधिक है और विकर्ण (74) मीटर है। चौड़ाई क्या है?
A rectangle has length (10) m more than its breadth and diagonal (74) m. What is the breadth?
Explanation opens after your attempt
Correct Answer
C. (48) मीटर/(48) m
Step 1
Concept
If breadth is (x), then (x-2+(x+10)2=742), giving (x=48). Use Pythagoras for a rectangle with a diagonal.
Step 2
Why this answer is correct
The correct answer is C. (48) मीटर / (48) m. If breadth is (x), then (x-2+(x+10)2=742), giving (x=48). Use Pythagoras for a rectangle with a diagonal.
Step 3
Exam Tip
चौड़ाई (x) हो तो (x-2+(x+10)2=742), जिससे (x=48) है। विकर्ण वाले आयत में पाइथागोरस प्रमेय लगाएँ।
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एक आयत की लंबाई चौड़ाई से (7) मीटर अधिक है और विकर्ण (65) मीटर है। चौड़ाई क्या है?
A rectangle has length (7) m more than its breadth and diagonal (65) m. What is the breadth?
Explanation opens after your attempt
Correct Answer
A. (33) मीटर/(33) m
Step 1
Concept
If breadth is (x), then (x-2+(x+7)2=652), giving (x=33). Use Pythagoras for a rectangle with diagonal.
Step 2
Why this answer is correct
The correct answer is A. (33) मीटर / (33) m. If breadth is (x), then (x-2+(x+7)2=652), giving (x=33). Use Pythagoras for a rectangle with diagonal.
Step 3
Exam Tip
चौड़ाई (x) हो तो (x-2+(x+7)2=652), जिससे (x=33) है। विकर्ण वाले आयत में पाइथागोरस प्रमेय लगाएँ।
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