Search: middle-term

Question Expert Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 36

\(30x^2-61x+30=0\) में मध्य पद का सही विभाजन कौनसा है?

What is the correct splitting of the middle term in \(30x^2-61x+30=0\)?

Explanation opens after your attempt

Correct Answer

A. \(30x^2-36x-25x+30=0\)

Step 1

Concept

Here (ac=900) and (-36+(-25)=-61), so the correct split is (-36x-25x). In exams, even for large (ac), match both sum and product.

Step 2

Why this answer is correct

The correct answer is A. \(30x^2-36x-25x+30=0\). Here (ac=900) and (-36+(-25)=-61), so the correct split is (-36x-25x). In exams, even for large (ac), match both sum and product.

Step 3

Exam Tip

यहां (ac=900) और (-36+(-25)=-61), इसलिए सही विभाजन (-36x-25x) है। परीक्षा में बड़ा (ac) हो तो भी योग और गुणनफल दोनों मिलाएं।

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Question Expert Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 35

\(24x^2-50x+25=0\) में मध्य पद का सही विभाजन कौनसा है?

What is the correct splitting of the middle term in \(24x^2-50x+25=0\)?

Explanation opens after your attempt

Correct Answer

A. \(24x^2-30x-20x+25=0\)

Step 1

Concept

Here (ac=600) and (-30+(-20)=-50), so the correct split is (-30x-20x). In exams, even for large (ac), match both sum and product.

Step 2

Why this answer is correct

The correct answer is A. \(24x^2-30x-20x+25=0\). Here (ac=600) and (-30+(-20)=-50), so the correct split is (-30x-20x). In exams, even for large (ac), match both sum and product.

Step 3

Exam Tip

यहां (ac=600) और (-30+(-20)=-50), इसलिए सही विभाजन (-30x-20x) है। परीक्षा में बड़ा (ac) हो तो भी योग और गुणनफल दोनों मिलाएं।

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Question Expert Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 34

\(20x^2-43x+21=0\) में मध्य पद का सही विभाजन कौनसा है?

What is the correct splitting of the middle term in \(20x^2-43x+21=0\)?

Explanation opens after your attempt

Correct Answer

A. \(20x^2-28x-15x+21=0\)

Step 1

Concept

Here (ac=420) and (-28+(-15)=-43), so the correct split is (-28x-15x). In exams, even when (ac) is large, match both sum and product.

Step 2

Why this answer is correct

The correct answer is A. \(20x^2-28x-15x+21=0\). Here (ac=420) and (-28+(-15)=-43), so the correct split is (-28x-15x). In exams, even when (ac) is large, match both sum and product.

Step 3

Exam Tip

यहां (ac=420) और (-28+(-15)=-43), इसलिए सही विभाजन (-28x-15x) है। परीक्षा में (ac) बड़ा हो तो भी योग और गुणनफल दोनों मिलाएं।

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Question Hard Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 36

\(18x^2-27x+10=0\) में मध्य पद का सही विभाजन कौनसा है?

What is the correct splitting of the middle term in \(18x^2-27x+10=0\)?

Explanation opens after your attempt

Correct Answer

A. \(18x^2-15x-12x+10=0\)

Step 1

Concept

Here (ac=180) and (-15+(-12)=-27), so the correct split is (-15x-12x). In exams, match both sum (b) and product (ac).

Step 2

Why this answer is correct

The correct answer is A. \(18x^2-15x-12x+10=0\). Here (ac=180) and (-15+(-12)=-27), so the correct split is (-15x-12x). In exams, match both sum (b) and product (ac).

Step 3

Exam Tip

यहां (ac=180) और (-15+(-12)=-27), इसलिए सही विभाजन (-15x-12x) है। परीक्षा में योग (b) और गुणनफल (ac) दोनों मिलाएं।

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Question Hard Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 35

\(15x^2+16x+4=0\) में मध्य पद का सही विभाजन कौनसा है?

What is the correct splitting of the middle term in \(15x^2+16x+4=0\)?

Explanation opens after your attempt

Correct Answer

A. \(15x^2+10x+6x+4=0\)

Step 1

Concept

Here (ac=60) and (10+6=16), so (16x) is split as (10x+6x). In exams, check both sum (b) and product (ac).

Step 2

Why this answer is correct

The correct answer is A. \(15x^2+10x+6x+4=0\). Here (ac=60) and (10+6=16), so (16x) is split as (10x+6x). In exams, check both sum (b) and product (ac).

Step 3

Exam Tip

यहां (ac=60) और (10+6=16), इसलिए (16x) को (10x+6x) में तोड़ते हैं। परीक्षा में योग (b) और गुणनफल (ac) दोनों जांचें।

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Question Hard Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 34

\(12x^2-17x+6=0\) में मध्य पद का सही विभाजन कौनसा है?

What is the correct splitting of the middle term in \(12x^2-17x+6=0\)?

Explanation opens after your attempt

Correct Answer

A. \(12x^2-9x-8x+6=0\)

Step 1

Concept

Here (ac=72) and (-9+(-8)=-17), so the correct split is (-9x-8x). In exams, check both sum (b) and product (ac).

Step 2

Why this answer is correct

The correct answer is A. \(12x^2-9x-8x+6=0\). Here (ac=72) and (-9+(-8)=-17), so the correct split is (-9x-8x). In exams, check both sum (b) and product (ac).

Step 3

Exam Tip

यहां (ac=72) और (-9+(-8)=-17), इसलिए सही विभाजन (-9x-8x) है। परीक्षा में योग (b) और गुणनफल (ac) दोनों जांचें।

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Question Medium Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 36

\(8x^2-2x-3=0\) में मध्य पद का सही विभाजन कौनसा है?

What is the correct splitting of the middle term in \(8x^2-2x-3=0\)?

Explanation opens after your attempt

Correct Answer

A. \(8x^2+4x-6x-3=0\)

Step 1

Concept

(ac=-24) and (4+(-6)=-2), so (-2x) is split as (4x-6x). In exams, check the sign of (ac) carefully.

Step 2

Why this answer is correct

The correct answer is A. \(8x^2+4x-6x-3=0\). (ac=-24) and (4+(-6)=-2), so (-2x) is split as (4x-6x). In exams, check the sign of (ac) carefully.

Step 3

Exam Tip

(ac=-24) और (4+(-6)=-2), इसलिए (-2x) को (4x-6x) में तोड़ते हैं। परीक्षा में (ac) का संकेत ध्यान से देखें।

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Question Medium Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 36

\(x^2-20x+96=0\) में कौनसी संख्या जोड़ी मध्य पद बनाने में मदद करेगी?

Which number pair helps in making the middle term in \(x^2-20x+96=0\)?

Explanation opens after your attempt

Correct Answer

A. (-8) और (-12)(-8) and (-12)

Step 1

Concept

(-8+(-12)=-20) and ((-8)(-12)=96), so this pair is correct. In exams, when (c) is positive and (b) is negative, both numbers are negative.

Step 2

Why this answer is correct

The correct answer is A. (-8) और (-12) / (-8) and (-12). (-8+(-12)=-20) and ((-8)(-12)=96), so this pair is correct. In exams, when (c) is positive and (b) is negative, both numbers are negative.

Step 3

Exam Tip

(-8+(-12)=-20) और ((-8)(-12)=96), इसलिए यह जोड़ी सही है। परीक्षा में (c) धनात्मक और (b) ऋणात्मक हो तो दोनों संख्याएं ऋणात्मक होती हैं।

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Question Medium Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 36

\(4x^2-19x-5=0\) में मध्य पद का सही विभाजन कौनसा है?

What is the correct splitting of the middle term in \(4x^2-19x-5=0\)?

Explanation opens after your attempt

Correct Answer

A. \(4x^2-20x+x-5=0\)

Step 1

Concept

Here (ac=-20) and (-20+1=-19), so the middle term is (-20x+x). In exams, check the sign of (ac) carefully.

Step 2

Why this answer is correct

The correct answer is A. \(4x^2-20x+x-5=0\). Here (ac=-20) and (-20+1=-19), so the middle term is (-20x+x). In exams, check the sign of (ac) carefully.

Step 3

Exam Tip

यहां (ac=-20) और (-20+1=-19), इसलिए मध्य पद (-20x+x) होगा। परीक्षा में (ac) का संकेत ध्यान से देखें।

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Question Medium Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 36

\(10x^2-17x+3=0\) में मध्य पद का सही विभाजन कौनसा है?

What is the correct splitting of the middle term in \(10x^2-17x+3=0\)?

Explanation opens after your attempt

Correct Answer

A. \(10x^2-15x-2x+3=0\)

Step 1

Concept

Here (ac=30) and (-15+(-2)=-17), so the middle term is (-15x-2x). In exams, check both sum and product.

Step 2

Why this answer is correct

The correct answer is A. \(10x^2-15x-2x+3=0\). Here (ac=30) and (-15+(-2)=-17), so the middle term is (-15x-2x). In exams, check both sum and product.

Step 3

Exam Tip

यहां (ac=30) और (-15+(-2)=-17), इसलिए मध्य पद (-15x-2x) होगा। परीक्षा में योग और गुणनफल दोनों जांचें।

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Question Medium Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 35

\(6x^2+x-2=0\) में मध्य पद का सही विभाजन कौनसा है?

What is the correct splitting of the middle term in \(6x^2+x-2=0\)?

Explanation opens after your attempt

Correct Answer

A. \(6x^2+4x-3x-2=0\)

Step 1

Concept

(ac=-12) and (4+(-3)=1), so (x) is split as (4x-3x). In exams, check the sign of (ac) carefully.

Step 2

Why this answer is correct

The correct answer is A. \(6x^2+4x-3x-2=0\). (ac=-12) and (4+(-3)=1), so (x) is split as (4x-3x). In exams, check the sign of (ac) carefully.

Step 3

Exam Tip

(ac=-12) और (4+(-3)=1), इसलिए (x) को (4x-3x) में तोड़ते हैं। परीक्षा में (ac) का संकेत ध्यान से देखें।

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Question Medium Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 35

\(x^2-18x+80=0\) में कौनसी संख्या जोड़ी मध्य पद बनाने में मदद करेगी?

Which number pair helps in making the middle term in \(x^2-18x+80=0\)?

Explanation opens after your attempt

Correct Answer

A. (-8) और (-10)(-8) and (-10)

Step 1

Concept

(-8+(-10)=-18) and ((-8)(-10)=80), so this pair is correct. In exams, when (c) is positive and (b) is negative, both numbers are negative.

Step 2

Why this answer is correct

The correct answer is A. (-8) और (-10) / (-8) and (-10). (-8+(-10)=-18) and ((-8)(-10)=80), so this pair is correct. In exams, when (c) is positive and (b) is negative, both numbers are negative.

Step 3

Exam Tip

(-8+(-10)=-18) और ((-8)(-10)=80), इसलिए यह जोड़ी सही है। परीक्षा में (c) धनात्मक और (b) ऋणात्मक हो तो दोनों संख्याएं ऋणात्मक होती हैं।

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Question Medium Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 35

\(5x^2-13x-6=0\) में मध्य पद का सही विभाजन कौनसा है?

What is the correct splitting of the middle term in \(5x^2-13x-6=0\)?

Explanation opens after your attempt

Correct Answer

A. \(5x^2-15x+2x-6=0\)

Step 1

Concept

Here (ac=-30) and (-15+2=-13), so the middle term is (-15x+2x). In exams, check the sign of (ac) carefully.

Step 2

Why this answer is correct

The correct answer is A. \(5x^2-15x+2x-6=0\). Here (ac=-30) and (-15+2=-13), so the middle term is (-15x+2x). In exams, check the sign of (ac) carefully.

Step 3

Exam Tip

यहां (ac=-30) और (-15+2=-13), इसलिए मध्य पद (-15x+2x) होगा। परीक्षा में (ac) का संकेत ध्यान से देखें।

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Question Medium Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 35

\(8x^2+14x+3=0\) में मध्य पद का सही विभाजन कौनसा है?

What is the correct splitting of the middle term in \(8x^2+14x+3=0\)?

Explanation opens after your attempt

Correct Answer

A. \(8x^2+12x+2x+3=0\)

Step 1

Concept

Here (ac=24) and (12+2=14), so (14x) is split as (12x+2x). In exams, find (ac) first.

Step 2

Why this answer is correct

The correct answer is A. \(8x^2+12x+2x+3=0\). Here (ac=24) and (12+2=14), so (14x) is split as (12x+2x). In exams, find (ac) first.

Step 3

Exam Tip

यहां (ac=24) और (12+2=14), इसलिए (14x) को (12x+2x) में तोड़ते हैं। परीक्षा में पहले (ac) निकालें।

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Question Medium Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 34

\(2x^2+x-6=0\) में मध्य पद का सही विभाजन कौनसा है?

What is the correct splitting of the middle term in \(2x^2+x-6=0\)?

Explanation opens after your attempt

Correct Answer

A. \(2x^2+4x-3x-6=0\)

Step 1

Concept

(ac=-12) and (4+(-3)=1), so (x) is split as (4x-3x). In exams, check the sign of (ac) carefully.

Step 2

Why this answer is correct

The correct answer is A. \(2x^2+4x-3x-6=0\). (ac=-12) and (4+(-3)=1), so (x) is split as (4x-3x). In exams, check the sign of (ac) carefully.

Step 3

Exam Tip

(ac=-12) और (4+(-3)=1), इसलिए (x) को (4x-3x) में तोड़ते हैं। परीक्षा में (ac) का संकेत ध्यान से देखें।

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Question Medium Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 34

\(x^2-14x+45=0\) में कौनसी संख्या जोड़ी मध्य पद बनाने में मदद करेगी?

Which number pair helps in making the middle term in \(x^2-14x+45=0\)?

Explanation opens after your attempt

Correct Answer

A. (-5) और (-9)(-5) and (-9)

Step 1

Concept

(-5+(-9)=-14) and ((-5)(-9)=45), so this pair is correct. In exams, if (c) is positive and (b) is negative, both numbers may be negative.

Step 2

Why this answer is correct

The correct answer is A. (-5) और (-9) / (-5) and (-9). (-5+(-9)=-14) and ((-5)(-9)=45), so this pair is correct. In exams, if (c) is positive and (b) is negative, both numbers may be negative.

Step 3

Exam Tip

(-5+(-9)=-14) और ((-5)(-9)=45), इसलिए यह जोड़ी सही है। परीक्षा में (c) धनात्मक और (b) ऋणात्मक हो तो दोनों संख्याएं ऋणात्मक हो सकती हैं।

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Question Medium Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 34

\(x^2-3x-10=0\) के लिए निम्न में से कौनसा कथन सही है?

Which statement is correct for \(x^2-3x-10=0\)?

Explanation opens after your attempt

Correct Answer

A. मूल (5) और (-2) हैंThe roots are (5) and (-2)

Step 1

Concept

(x^-2-3x-10=(x-5)(x+2)), so the roots are (5) and (-2). In exams, in mixed signs the larger value decides the middle-term sign.

Step 2

Why this answer is correct

The correct answer is A. मूल (5) और (-2) हैं / The roots are (5) and (-2). (x^-2-3x-10=(x-5)(x+2)), so the roots are (5) and (-2). In exams, in mixed signs the larger value decides the middle-term sign.

Step 3

Exam Tip

(x^-2-3x-10=(x-5)(x+2)), इसलिए मूल (5) और (-2) हैं। परीक्षा में मिश्रित चिन्हों में बड़ा मान मध्य पद का चिन्ह तय करता है।

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Question Medium Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 34

\(6x^2+11x+3=0\) में मध्य पद का सही विभाजन कौनसा है?

What is the correct splitting of the middle term in \(6x^2+11x+3=0\)?

Explanation opens after your attempt

Correct Answer

A. \(6x^2+9x+2x+3=0\)

Step 1

Concept

Here (ac=18) and (9+2=11), so (11x) is split as (9x+2x). In exams, check both sum (b) and product (ac).

Step 2

Why this answer is correct

The correct answer is A. \(6x^2+9x+2x+3=0\). Here (ac=18) and (9+2=11), so (11x) is split as (9x+2x). In exams, check both sum (b) and product (ac).

Step 3

Exam Tip

यहां (ac=18) और (9+2=11), इसलिए (11x) को (9x+2x) में तोड़ते हैं। परीक्षा में योग (b) और गुणनफल (ac) दोनों जांचें।

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Question Easy Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 36

\(3x^2-11x+6=0\) के गुणनखंड कौनसे हैं?

What are the factors of \(3x^2-11x+6=0\)?

Explanation opens after your attempt

Correct Answer

A. ((3x-2)(x-3))

Step 1

Concept

(3x^-2-11x+6=(3x-2)(x-3)). In exams, expand back to check (-11x).

Step 2

Why this answer is correct

The correct answer is A. ((3x-2)(x-3)). (3x^-2-11x+6=(3x-2)(x-3)). In exams, expand back to check (-11x).

Step 3

Exam Tip

(3x^-2-11x+6=(3x-2)(x-3)) है। परीक्षा में विस्तार करके (-11x) वापस जांचें।

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Question Easy Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 36

\(3x^2-11x+6=0\) में मध्य पद का सही विभाजन क्या है?

What is the correct splitting of the middle term in \(3x^2-11x+6=0\)?

Explanation opens after your attempt

Correct Answer

A. \(3x^2-9x-2x+6=0\)

Step 1

Concept

((-9)+(-2)=-11) and ((-9)(-2)=18=ac), so (-9x-2x) is correct. In exams, split the middle term by checking (ac).

Step 2

Why this answer is correct

The correct answer is A. \(3x^2-9x-2x+6=0\). ((-9)+(-2)=-11) and ((-9)(-2)=18=ac), so (-9x-2x) is correct. In exams, split the middle term by checking (ac).

Step 3

Exam Tip

((-9)+(-2)=-11) और ((-9)(-2)=18=ac), इसलिए (-9x-2x) सही है। परीक्षा में (ac) देखकर मध्य पद तोड़ें।

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Question Easy Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 36

\(x^2-19x+90=0\) के गुणनखंड कौनसे होंगे?

What will be the factors of \(x^2-19x+90=0\)?

Explanation opens after your attempt

Correct Answer

A. ((x-9)(x-10))

Step 1

Concept

(9+10=19) and \(9\times10=90\), so ((x-9)(x-10)) is correct. In exams, take both negative signs for a negative middle term.

Step 2

Why this answer is correct

The correct answer is A. ((x-9)(x-10)). (9+10=19) and \(9\times10=90\), so ((x-9)(x-10)) is correct. In exams, take both negative signs for a negative middle term.

Step 3

Exam Tip

(9+10=19) और \(9\times10=90\), इसलिए ((x-9)(x-10)) सही है। परीक्षा में ऋणात्मक मध्य पद के लिए दोनों ऋणात्मक चिन्ह लें।

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Question Easy Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 36

\(4x^2+13x+3=0\) में मध्य पद का सही विभाजन कौनसा है?

Which is the correct splitting of the middle term in \(4x^2+13x+3=0\)?

Explanation opens after your attempt

Correct Answer

A. \(4x^2+12x+x+3=0\)

Step 1

Concept

(12+1=13) and \(12\times1=12=ac\), so (13x) is split as (12x+x). In exams, keep both sum and product correct.

Step 2

Why this answer is correct

The correct answer is A. \(4x^2+12x+x+3=0\). (12+1=13) and \(12\times1=12=ac\), so (13x) is split as (12x+x). In exams, keep both sum and product correct.

Step 3

Exam Tip

(12+1=13) और \(12\times1=12=ac\), इसलिए (13x) को (12x+x) में तोड़ते हैं। परीक्षा में योग और गुणनफल दोनों सही रखें।

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Question Easy Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 36

मध्य पद विभाजन में \(4x^2+13x+3=0\) के लिए (ac) का मान क्या है?

In middle term splitting for \(4x^2+13x+3=0\), what is the value of (ac)?

Explanation opens after your attempt

Correct Answer

A. (12)

Step 1

Concept

Here (a=4) and (c=3), so (ac=12). In exams, finding (ac) first helps.

Step 2

Why this answer is correct

The correct answer is A. (12). Here (a=4) and (c=3), so (ac=12). In exams, finding (ac) first helps.

Step 3

Exam Tip

यहां (a=4) और (c=3), इसलिए (ac=12) है। परीक्षा में पहले (ac) निकालना मदद करता है।

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Question Easy Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 36

\(x^2+3x-40=0\) में मध्य पद बनाने के लिए कौनसी संख्या जोड़ी सही है?

Which number pair is correct for making the middle term in \(x^2+3x-40=0\)?

Explanation opens after your attempt

Correct Answer

A. (8) और (-5)(8) and (-5)

Step 1

Concept

(8+(-5)=3) and \(8\times(-5)=-40\), so this pair is correct. In exams, match the sum with (b) and product with (c).

Step 2

Why this answer is correct

The correct answer is A. (8) और (-5) / (8) and (-5). (8+(-5)=3) and \(8\times(-5)=-40\), so this pair is correct. In exams, match the sum with (b) and product with (c).

Step 3

Exam Tip

(8+(-5)=3) और \(8\times(-5)=-40\), इसलिए यह जोड़ी सही है। परीक्षा में योग (b) और गुणनफल (c) से मिलाएं।

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Question Easy Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 35

\(2x^2-7x+5=0\) के गुणनखंड कौनसे हैं?

What are the factors of \(2x^2-7x+5=0\)?

Explanation opens after your attempt

Correct Answer

A. ((2x-5)(x-1))

Step 1

Concept

(2x^-2-7x+5=(2x-5)(x-1)). In exams, expand back to check (-7x).

Step 2

Why this answer is correct

The correct answer is A. ((2x-5)(x-1)). (2x^-2-7x+5=(2x-5)(x-1)). In exams, expand back to check (-7x).

Step 3

Exam Tip

(2x^-2-7x+5=(2x-5)(x-1)) है। परीक्षा में विस्तार करके (-7x) वापस जांचें।

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Question Easy Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 35

\(2x^2-7x+5=0\) में मध्य पद का सही विभाजन क्या है?

What is the correct splitting of the middle term in \(2x^2-7x+5=0\)?

Explanation opens after your attempt

Correct Answer

A. \(2x^2-2x-5x+5=0\)

Step 1

Concept

((-2)+(-5)=-7) and ((-2)(-5)=10=ac), so (-2x-5x) is correct. In exams, checking (ac) is important while splitting the middle term.

Step 2

Why this answer is correct

The correct answer is A. \(2x^2-2x-5x+5=0\). ((-2)+(-5)=-7) and ((-2)(-5)=10=ac), so (-2x-5x) is correct. In exams, checking (ac) is important while splitting the middle term.

Step 3

Exam Tip

((-2)+(-5)=-7) और ((-2)(-5)=10=ac), इसलिए (-2x-5x) सही है। परीक्षा में मध्य पद तोड़ते समय (ac) देखना जरूरी है।

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Question Easy Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 35

\(x^2-13x+40=0\) के गुणनखंड कौनसे होंगे?

What will be the factors of \(x^2-13x+40=0\)?

Explanation opens after your attempt

Correct Answer

A. ((x-5)(x-8))

Step 1

Concept

(5+8=13) and \(5\times8=40\), so ((x-5)(x-8)) is correct. In exams, take both negative signs for a negative middle term.

Step 2

Why this answer is correct

The correct answer is A. ((x-5)(x-8)). (5+8=13) and \(5\times8=40\), so ((x-5)(x-8)) is correct. In exams, take both negative signs for a negative middle term.

Step 3

Exam Tip

(5+8=13) और \(5\times8=40\), इसलिए ((x-5)(x-8)) सही है। परीक्षा में ऋणात्मक मध्य पद के लिए दोनों ऋणात्मक चिन्ह लें।

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Question Easy Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 35

\(3x^2+10x+3=0\) में मध्य पद का सही विभाजन कौनसा है?

Which is the correct splitting of the middle term in \(3x^2+10x+3=0\)?

Explanation opens after your attempt

Correct Answer

A. \(3x^2+9x+x+3=0\)

Step 1

Concept

(9+1=10) and \(9\times1=9=ac\), so (10x) is split as (9x+x). In exams, keep both sum and product correct.

Step 2

Why this answer is correct

The correct answer is A. \(3x^2+9x+x+3=0\). (9+1=10) and \(9\times1=9=ac\), so (10x) is split as (9x+x). In exams, keep both sum and product correct.

Step 3

Exam Tip

(9+1=10) और \(9\times1=9=ac\), इसलिए (10x) को (9x+x) में तोड़ते हैं। परीक्षा में योग और गुणनफल दोनों सही रखें।

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Question Easy Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 35

मध्य पद विभाजन में \(3x^2+10x+3=0\) के लिए (ac) का मान क्या है?

In middle term splitting for \(3x^2+10x+3=0\), what is the value of (ac)?

Explanation opens after your attempt

Correct Answer

A. (9)

Step 1

Concept

Here (a=3) and (c=3), so (ac=9). In exams, finding (ac) first helps.

Step 2

Why this answer is correct

The correct answer is A. (9). Here (a=3) and (c=3), so (ac=9). In exams, finding (ac) first helps.

Step 3

Exam Tip

यहां (a=3) और (c=3), इसलिए (ac=9) है। परीक्षा में पहले (ac) निकालना मदद करता है।

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Question Easy Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 35

\(x^2+2x-24=0\) में मध्य पद बनाने के लिए कौनसी संख्या जोड़ी सही है?

Which number pair is correct for making the middle term in \(x^2+2x-24=0\)?

Explanation opens after your attempt

Correct Answer

A. (6) और (-4)(6) and (-4)

Step 1

Concept

(6+(-4)=2) and \(6\times(-4)=-24\), so this pair is correct. In exams, match the sum with (b) and product with (c).

Step 2

Why this answer is correct

The correct answer is A. (6) और (-4) / (6) and (-4). (6+(-4)=2) and \(6\times(-4)=-24\), so this pair is correct. In exams, match the sum with (b) and product with (c).

Step 3

Exam Tip

(6+(-4)=2) और \(6\times(-4)=-24\), इसलिए यह जोड़ी सही है। परीक्षा में योग (b) और गुणनफल (c) से मिलाएं।

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Question Easy Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 34

\(2x^2-5x+3=0\) के गुणनखंड कौनसे हैं?

What are the factors of \(2x^2-5x+3=0\)?

Explanation opens after your attempt

Correct Answer

A. ((2x-3)(x-1))

Step 1

Concept

(2x^-2-5x+3=(2x-3)(x-1)). In exams, multiply back to check the middle term (-5x).

Step 2

Why this answer is correct

The correct answer is A. ((2x-3)(x-1)). (2x^-2-5x+3=(2x-3)(x-1)). In exams, multiply back to check the middle term (-5x).

Step 3

Exam Tip

(2x^-2-5x+3=(2x-3)(x-1)) है। परीक्षा में गुणा करके मध्य पद (-5x) वापस जांचें।

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Question Easy Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 34

\(2x^2-5x+3=0\) में मध्य पद का सही विभाजन क्या है?

What is the correct splitting of the middle term in \(2x^2-5x+3=0\)?

Explanation opens after your attempt

Correct Answer

A. \(2x^2-2x-3x+3=0\)

Step 1

Concept

((-2)+(-3)=-5) and ((-2)(-3)=6=ac), so the correct split is (-2x-3x). In exams, the product of the two numbers must be (ac).

Step 2

Why this answer is correct

The correct answer is A. \(2x^2-2x-3x+3=0\). ((-2)+(-3)=-5) and ((-2)(-3)=6=ac), so the correct split is (-2x-3x). In exams, the product of the two numbers must be (ac).

Step 3

Exam Tip

((-2)+(-3)=-5) और ((-2)(-3)=6=ac), इसलिए सही विभाजन (-2x-3x) है। परीक्षा में दोनों संख्याओं का गुणनफल (ac) होना चाहिए।

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Question Easy Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 34

\(x^2-8x+15=0\) के गुणनखंड कौनसे होंगे?

What will be the factors of \(x^2-8x+15=0\)?

Explanation opens after your attempt

Correct Answer

A. ((x-3)(x-5))

Step 1

Concept

(3+5=8) and \(3\times5=15\), so with signs we get ((x-3)(x-5)). In exams, for a negative middle term, look for both negative factors.

Step 2

Why this answer is correct

The correct answer is A. ((x-3)(x-5)). (3+5=8) and \(3\times5=15\), so with signs we get ((x-3)(x-5)). In exams, for a negative middle term, look for both negative factors.

Step 3

Exam Tip

(3+5=8) और \(3\times5=15\), इसलिए संकेतों के साथ ((x-3)(x-5)) मिलता है। परीक्षा में ऋणात्मक मध्य पद के लिए दोनों ऋणात्मक गुणनखंड देखें।

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Question Easy Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 34

\(2x^2+7x+3=0\) के लिए मध्य पद का सही विभाजन कौनसा है?

For \(2x^2+7x+3=0\), which is the correct splitting of the middle term?

Explanation opens after your attempt

Correct Answer

A. \(2x^2+6x+x+3=0\)

Step 1

Concept

Since (6+1=7) and \(6\times1=6\), split (7x) as (6x+x). In exams, keep the sum (b) and product (ac).

Step 2

Why this answer is correct

The correct answer is A. \(2x^2+6x+x+3=0\). Since (6+1=7) and \(6\times1=6\), split (7x) as (6x+x). In exams, keep the sum (b) and product (ac).

Step 3

Exam Tip

(6+1=7) और \(6\times1=6\), इसलिए (7x) को (6x+x) में तोड़ते हैं। परीक्षा में योग (b) और गुणनफल (ac) रखें।

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Question Easy Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 34

मध्य पद विभाजन विधि में \(2x^2+7x+3=0\) के लिए (ac) का मान क्या है?

In middle term splitting method for \(2x^2+7x+3=0\), what is the value of (ac)?

Explanation opens after your attempt

Correct Answer

A. (6)

Step 1

Concept

Here (a=2) and (c=3), so (ac=6). In exams, finding (ac) makes middle term splitting easier.

Step 2

Why this answer is correct

The correct answer is A. (6). Here (a=2) and (c=3), so (ac=6). In exams, finding (ac) makes middle term splitting easier.

Step 3

Exam Tip

यहां (a=2) और (c=3), इसलिए (ac=6) है। परीक्षा में (ac) निकालकर मध्य पद तोड़ना आसान होता है।

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Question Easy Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 34

\(x^2+2x-15=0\) में कौनसी संख्या जोड़ी गुणनखंड बनाने में मदद करेगी?

Which number pair helps in factoring \(x^2+2x-15=0\)?

Explanation opens after your attempt

Correct Answer

A. (5) और (-3)(5) and (-3)

Step 1

Concept

(5+(-3)=2) and \(5\times(-3)=-15\), so this pair is correct. In exams, split the middle term using such a pair.

Step 2

Why this answer is correct

The correct answer is A. (5) और (-3) / (5) and (-3). (5+(-3)=2) and \(5\times(-3)=-15\), so this pair is correct. In exams, split the middle term using such a pair.

Step 3

Exam Tip

(5+(-3)=2) और \(5\times(-3)=-15\), इसलिए यह जोड़ी सही है। परीक्षा में मध्य पद को इसी जोड़ी से तोड़ें।

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