\(4x^2-19x-5=0\) में मध्य पद का सही विभाजन कौनसा है?
What is the correct splitting of the middle term in \(4x^2-19x-5=0\)?
Explanation opens after your attempt
A. \(4x^2-20x+x-5=0\)
Concept
Here (ac=-20) and (-20+1=-19), so the middle term is (-20x+x). In exams, check the sign of (ac) carefully.
Why this answer is correct
The correct answer is A. \(4x^2-20x+x-5=0\). Here (ac=-20) and (-20+1=-19), so the middle term is (-20x+x). In exams, check the sign of (ac) carefully.
Exam Tip
यहां (ac=-20) और (-20+1=-19), इसलिए मध्य पद (-20x+x) होगा। परीक्षा में (ac) का संकेत ध्यान से देखें।
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