middle-term-splitting se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.
Here (ac=900) and (-36+(-25)=-61), so the correct split is (-36x-25x). In exams, even for large (ac), match both sum and product.
Step 2
Why this answer is correct
The correct answer is A. \(30x^2-36x-25x+30=0\). Here (ac=900) and (-36+(-25)=-61), so the correct split is (-36x-25x). In exams, even for large (ac), match both sum and product.
Step 3
Exam Tip
यहां (ac=900) और (-36+(-25)=-61), इसलिए सही विभाजन (-36x-25x) है। परीक्षा में बड़ा (ac) हो तो भी योग और गुणनफल दोनों मिलाएं।
Here (ac=600) and (-30+(-20)=-50), so the correct split is (-30x-20x). In exams, even for large (ac), match both sum and product.
Step 2
Why this answer is correct
The correct answer is A. \(24x^2-30x-20x+25=0\). Here (ac=600) and (-30+(-20)=-50), so the correct split is (-30x-20x). In exams, even for large (ac), match both sum and product.
Step 3
Exam Tip
यहां (ac=600) और (-30+(-20)=-50), इसलिए सही विभाजन (-30x-20x) है। परीक्षा में बड़ा (ac) हो तो भी योग और गुणनफल दोनों मिलाएं।
Here (ac=420) and (-28+(-15)=-43), so the correct split is (-28x-15x). In exams, even when (ac) is large, match both sum and product.
Step 2
Why this answer is correct
The correct answer is A. \(20x^2-28x-15x+21=0\). Here (ac=420) and (-28+(-15)=-43), so the correct split is (-28x-15x). In exams, even when (ac) is large, match both sum and product.
Step 3
Exam Tip
यहां (ac=420) और (-28+(-15)=-43), इसलिए सही विभाजन (-28x-15x) है। परीक्षा में (ac) बड़ा हो तो भी योग और गुणनफल दोनों मिलाएं।
Here (ac=180) and (-15+(-12)=-27), so the correct split is (-15x-12x). In exams, match both sum (b) and product (ac).
Step 2
Why this answer is correct
The correct answer is A. \(18x^2-15x-12x+10=0\). Here (ac=180) and (-15+(-12)=-27), so the correct split is (-15x-12x). In exams, match both sum (b) and product (ac).
Step 3
Exam Tip
यहां (ac=180) और (-15+(-12)=-27), इसलिए सही विभाजन (-15x-12x) है। परीक्षा में योग (b) और गुणनफल (ac) दोनों मिलाएं।
Here (ac=60) and (10+6=16), so (16x) is split as (10x+6x). In exams, check both sum (b) and product (ac).
Step 2
Why this answer is correct
The correct answer is A. \(15x^2+10x+6x+4=0\). Here (ac=60) and (10+6=16), so (16x) is split as (10x+6x). In exams, check both sum (b) and product (ac).
Step 3
Exam Tip
यहां (ac=60) और (10+6=16), इसलिए (16x) को (10x+6x) में तोड़ते हैं। परीक्षा में योग (b) और गुणनफल (ac) दोनों जांचें।
Here (ac=72) and (-9+(-8)=-17), so the correct split is (-9x-8x). In exams, check both sum (b) and product (ac).
Step 2
Why this answer is correct
The correct answer is A. \(12x^2-9x-8x+6=0\). Here (ac=72) and (-9+(-8)=-17), so the correct split is (-9x-8x). In exams, check both sum (b) and product (ac).
Step 3
Exam Tip
यहां (ac=72) और (-9+(-8)=-17), इसलिए सही विभाजन (-9x-8x) है। परीक्षा में योग (b) और गुणनफल (ac) दोनों जांचें।
(-8+(-12)=-20) and ((-8)(-12)=96), so this pair is correct. In exams, when (c) is positive and (b) is negative, both numbers are negative.
Step 2
Why this answer is correct
The correct answer is A. (-8) और (-12) / (-8) and (-12). (-8+(-12)=-20) and ((-8)(-12)=96), so this pair is correct. In exams, when (c) is positive and (b) is negative, both numbers are negative.
Step 3
Exam Tip
(-8+(-12)=-20) और ((-8)(-12)=96), इसलिए यह जोड़ी सही है। परीक्षा में (c) धनात्मक और (b) ऋणात्मक हो तो दोनों संख्याएं ऋणात्मक होती हैं।
Here (ac=-20) and (-20+1=-19), so the middle term is (-20x+x). In exams, check the sign of (ac) carefully.
Step 2
Why this answer is correct
The correct answer is A. \(4x^2-20x+x-5=0\). Here (ac=-20) and (-20+1=-19), so the middle term is (-20x+x). In exams, check the sign of (ac) carefully.
Step 3
Exam Tip
यहां (ac=-20) और (-20+1=-19), इसलिए मध्य पद (-20x+x) होगा। परीक्षा में (ac) का संकेत ध्यान से देखें।
(-8+(-10)=-18) and ((-8)(-10)=80), so this pair is correct. In exams, when (c) is positive and (b) is negative, both numbers are negative.
Step 2
Why this answer is correct
The correct answer is A. (-8) और (-10) / (-8) and (-10). (-8+(-10)=-18) and ((-8)(-10)=80), so this pair is correct. In exams, when (c) is positive and (b) is negative, both numbers are negative.
Step 3
Exam Tip
(-8+(-10)=-18) और ((-8)(-10)=80), इसलिए यह जोड़ी सही है। परीक्षा में (c) धनात्मक और (b) ऋणात्मक हो तो दोनों संख्याएं ऋणात्मक होती हैं।
Here (ac=-30) and (-15+2=-13), so the middle term is (-15x+2x). In exams, check the sign of (ac) carefully.
Step 2
Why this answer is correct
The correct answer is A. \(5x^2-15x+2x-6=0\). Here (ac=-30) and (-15+2=-13), so the middle term is (-15x+2x). In exams, check the sign of (ac) carefully.
Step 3
Exam Tip
यहां (ac=-30) और (-15+2=-13), इसलिए मध्य पद (-15x+2x) होगा। परीक्षा में (ac) का संकेत ध्यान से देखें।
(-5+(-9)=-14) and ((-5)(-9)=45), so this pair is correct. In exams, if (c) is positive and (b) is negative, both numbers may be negative.
Step 2
Why this answer is correct
The correct answer is A. (-5) और (-9) / (-5) and (-9). (-5+(-9)=-14) and ((-5)(-9)=45), so this pair is correct. In exams, if (c) is positive and (b) is negative, both numbers may be negative.
Step 3
Exam Tip
(-5+(-9)=-14) और ((-5)(-9)=45), इसलिए यह जोड़ी सही है। परीक्षा में (c) धनात्मक और (b) ऋणात्मक हो तो दोनों संख्याएं ऋणात्मक हो सकती हैं।
((-9)+(-2)=-11) and ((-9)(-2)=18=ac), so (-9x-2x) is correct. In exams, split the middle term by checking (ac).
Step 2
Why this answer is correct
The correct answer is A. \(3x^2-9x-2x+6=0\). ((-9)+(-2)=-11) and ((-9)(-2)=18=ac), so (-9x-2x) is correct. In exams, split the middle term by checking (ac).
Step 3
Exam Tip
((-9)+(-2)=-11) और ((-9)(-2)=18=ac), इसलिए (-9x-2x) सही है। परीक्षा में (ac) देखकर मध्य पद तोड़ें।
(12+1=13) and \(12\times1=12=ac\), so (13x) is split as (12x+x). In exams, keep both sum and product correct.
Step 2
Why this answer is correct
The correct answer is A. \(4x^2+12x+x+3=0\). (12+1=13) and \(12\times1=12=ac\), so (13x) is split as (12x+x). In exams, keep both sum and product correct.
Step 3
Exam Tip
(12+1=13) और \(12\times1=12=ac\), इसलिए (13x) को (12x+x) में तोड़ते हैं। परीक्षा में योग और गुणनफल दोनों सही रखें।
(8+(-5)=3) and \(8\times(-5)=-40\), so this pair is correct. In exams, match the sum with (b) and product with (c).
Step 2
Why this answer is correct
The correct answer is A. (8) और (-5) / (8) and (-5). (8+(-5)=3) and \(8\times(-5)=-40\), so this pair is correct. In exams, match the sum with (b) and product with (c).
Step 3
Exam Tip
(8+(-5)=3) और \(8\times(-5)=-40\), इसलिए यह जोड़ी सही है। परीक्षा में योग (b) और गुणनफल (c) से मिलाएं।
((-2)+(-5)=-7) and ((-2)(-5)=10=ac), so (-2x-5x) is correct. In exams, checking (ac) is important while splitting the middle term.
Step 2
Why this answer is correct
The correct answer is A. \(2x^2-2x-5x+5=0\). ((-2)+(-5)=-7) and ((-2)(-5)=10=ac), so (-2x-5x) is correct. In exams, checking (ac) is important while splitting the middle term.
Step 3
Exam Tip
((-2)+(-5)=-7) और ((-2)(-5)=10=ac), इसलिए (-2x-5x) सही है। परीक्षा में मध्य पद तोड़ते समय (ac) देखना जरूरी है।
(6+(-4)=2) and \(6\times(-4)=-24\), so this pair is correct. In exams, match the sum with (b) and product with (c).
Step 2
Why this answer is correct
The correct answer is A. (6) और (-4) / (6) and (-4). (6+(-4)=2) and \(6\times(-4)=-24\), so this pair is correct. In exams, match the sum with (b) and product with (c).
Step 3
Exam Tip
(6+(-4)=2) और \(6\times(-4)=-24\), इसलिए यह जोड़ी सही है। परीक्षा में योग (b) और गुणनफल (c) से मिलाएं।
((-2)+(-3)=-5) and ((-2)(-3)=6=ac), so the correct split is (-2x-3x). In exams, the product of the two numbers must be (ac).
Step 2
Why this answer is correct
The correct answer is A. \(2x^2-2x-3x+3=0\). ((-2)+(-3)=-5) and ((-2)(-3)=6=ac), so the correct split is (-2x-3x). In exams, the product of the two numbers must be (ac).
Step 3
Exam Tip
((-2)+(-3)=-5) और ((-2)(-3)=6=ac), इसलिए सही विभाजन (-2x-3x) है। परीक्षा में दोनों संख्याओं का गुणनफल (ac) होना चाहिए।
(5+(-3)=2) and \(5\times(-3)=-15\), so this pair is correct. In exams, split the middle term using such a pair.
Step 2
Why this answer is correct
The correct answer is A. (5) और (-3) / (5) and (-3). (5+(-3)=2) and \(5\times(-3)=-15\), so this pair is correct. In exams, split the middle term using such a pair.
Step 3
Exam Tip
(5+(-3)=2) और \(5\times(-3)=-15\), इसलिए यह जोड़ी सही है। परीक्षा में मध्य पद को इसी जोड़ी से तोड़ें।
